Added(A)/Deleted(D) following books

 A  sample_notebooks/MohitChauhan/Chapter_5.ipynb

1 files changed, 284 insertions, 0 deletions

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+{
+ "metadata": {
+  "name": "",
+  "signature": "sha256:40246af5736342db0b706a17990458bf898d0d1dfd632473c65bf3a52df25d34"
+ },
+ "nbformat": 3,
+ "nbformat_minor": 0,
+ "worksheets": [
+  {
+   "cells": [
+    {
+     "cell_type": "heading",
+     "level": 1,
+     "metadata": {},
+     "source": [
+      "Chapter 05 - Bipolar Junction Transistors"
+     ]
+    },
+    {
+     "cell_type": "heading",
+     "level": 2,
+     "metadata": {},
+     "source": [
+      "Example No -5.1 : Page No - 243"
+     ]
+    },
+    {
+     "cell_type": "code",
+     "collapsed": false,
+     "input": [
+      "# Given data\n",
+      "I_C= 5.10;# in mA\n",
+      "I_E= 5.5;# in mA\n",
+      "alpha= I_C/I_E;\n",
+      "alpha_dc= alpha;\n",
+      "print \"The common-base d.c. current gain = %0.2f \" %alpha_dc\n"
+     ],
+     "language": "python",
+     "metadata": {},
+     "outputs": [
+      {
+       "output_type": "stream",
+       "stream": "stdout",
+       "text": [
+        "The common-base d.c. current gain = 0.93 \n"
+       ]
+      }
+     ],
+     "prompt_number": 1
+    },
+    {
+     "cell_type": "heading",
+     "level": 2,
+     "metadata": {},
+     "source": [
+      "Example No -5.2 : Page No - 243"
+     ]
+    },
+    {
+     "cell_type": "code",
+     "collapsed": false,
+     "input": [
+      "import math \n",
+      "# Given data\n",
+      "alpha= 0.987;\n",
+      "I_E= 10.;# in mA\n",
+      "# Formula alpha= I_C/I_E;\n",
+      "I_C= alpha*I_E;# in mA\n",
+      "I_B= I_E-I_C;# in mA\n",
+      "print \"The base current = %0.2f mA \" %I_B\n"
+     ],
+     "language": "python",
+     "metadata": {},
+     "outputs": [
+      {
+       "output_type": "stream",
+       "stream": "stdout",
+       "text": [
+        "The base current = 0.13 mA \n"
+       ]
+      }
+     ],
+     "prompt_number": 2
+    },
+    {
+     "cell_type": "heading",
+     "level": 2,
+     "metadata": {},
+     "source": [
+      "Example No -5.4 : Page No - 249"
+     ]
+    },
+    {
+     "cell_type": "code",
+     "collapsed": false,
+     "input": [
+      "# Given data\n",
+      "alpha= 0.967;\n",
+      "I_E= 10.;# in mA\n",
+      "# Formula alpha= I_C/I_E;\n",
+      "I_C= alpha*I_E;# in mA\n",
+      "I_B= I_E-I_C;# in mA\n",
+      "print \"The collector current = %0.2f mA\" %I_C\n",
+      "print \"The base current = %0.2f mA \" %I_B\n"
+     ],
+     "language": "python",
+     "metadata": {},
+     "outputs": [
+      {
+       "output_type": "stream",
+       "stream": "stdout",
+       "text": [
+        "The collector current = 9.67 mA\n",
+        "The base current = 0.33 mA \n"
+       ]
+      }
+     ],
+     "prompt_number": 3
+    },
+    {
+     "cell_type": "heading",
+     "level": 2,
+     "metadata": {},
+     "source": [
+      "Example No -5.5 : Page No - 250"
+     ]
+    },
+    {
+     "cell_type": "code",
+     "collapsed": false,
+     "input": [
+      "# Given data\n",
+      "Beta= 100.;\n",
+      "I_E= 10.;# in mA\n",
+      "alpha= Beta/(1+Beta);\n",
+      "print \"The value of alpha = %0.2f\" %alpha\n",
+      "# Formula alpha= I_C/I_E;\n",
+      "I_C= alpha*I_E;# in mA\n",
+      "I_B= I_E-I_C;# in mA\n",
+      "print \"The collector current = %0.1f mA  \" %I_C\n",
+      "print \"The base current = %0.1f mA\" %I_B"
+     ],
+     "language": "python",
+     "metadata": {},
+     "outputs": [
+      {
+       "output_type": "stream",
+       "stream": "stdout",
+       "text": [
+        "The value of alpha = 0.99\n",
+        "The collector current = 9.9 mA  \n",
+        "The base current = 0.1 mA\n"
+       ]
+      }
+     ],
+     "prompt_number": 4
+    },
+    {
+     "cell_type": "heading",
+     "level": 2,
+     "metadata": {},
+     "source": [
+      "Example No -5.6 : Page No - 258"
+     ]
+    },
+    {
+     "cell_type": "code",
+     "collapsed": false,
+     "input": [
+      "# Given data\n",
+      "alpha= 0.950;\n",
+      "Beta= alpha/(1.-alpha);\n",
+      "print \"For alpha = 0.950, the value of beta = %0.f\" %Beta\n",
+      "Beta= 100.;\n",
+      "alpha= Beta/(1.+Beta);\n",
+      "print \"For beta = 100, the value of alpha = %0.2f\" %alpha\n"
+     ],
+     "language": "python",
+     "metadata": {},
+     "outputs": [
+      {
+       "output_type": "stream",
+       "stream": "stdout",
+       "text": [
+        "For alpha = 0.950, the value of beta = 19\n",
+        "For beta = 100, the value of alpha = 0.99\n"
+       ]
+      }
+     ],
+     "prompt_number": 5
+    },
+    {
+     "cell_type": "heading",
+     "level": 2,
+     "metadata": {},
+     "source": [
+      "Example No -5.7 : Page No - 259"
+     ]
+    },
+    {
+     "cell_type": "code",
+     "collapsed": false,
+     "input": [
+      "# Given data\n",
+      "I_E= 10.;# in mA\n",
+      "Beta= 100.;\n",
+      "alpha= Beta/(1.+Beta);\n",
+      "# Formula alpha= I_C/I_E;\n",
+      "I_C= alpha*I_E;# in mA\n",
+      "I_B= I_E-I_C;# in mA\n",
+      "print \"The base current = %0.3f mA \" %I_B\n",
+      "print \"The collector current = %0.3f mA\" %I_C"
+     ],
+     "language": "python",
+     "metadata": {},
+     "outputs": [
+      {
+       "output_type": "stream",
+       "stream": "stdout",
+       "text": [
+        "The base current = 0.099 mA \n",
+        "The collector current = 9.901 mA\n"
+       ]
+      }
+     ],
+     "prompt_number": 6
+    },
+    {
+     "cell_type": "heading",
+     "level": 2,
+     "metadata": {},
+     "source": [
+      "Example No -5.8 : Page No - 263"
+     ]
+    },
+    {
+     "cell_type": "code",
+     "collapsed": false,
+     "input": [
+      "# Given data\n",
+      "%matplotlib inline\n",
+      "import math\n",
+      "import numpy as np\n",
+      "import matplotlib.pyplot as plt\n",
+      "V_CC= 12.;# in V\n",
+      "R_C= 3.;# in kohm\n",
+      "V_CE= np.linspace(0,12,num=120);# in V\n",
+      "I_C= np.zeros(120)\n",
+      "for i in range(0,120):\n",
+      "\tI_C[i]= (V_CC-V_CE[i])/R_C;# in mA\n",
+      "\n",
+      "plt.plot(V_CE,I_C);\n",
+      "plt.xlabel(\"V_CE in volts\")\n",
+      "plt.ylabel(\"I_C in mA\")\n",
+      "plt.title(\"DC load line\")\n",
+      "plt.show()\n",
+      "print \"DC load line shown in figure.\"\n"
+     ],
+     "language": "python",
+     "metadata": {},
+     "outputs": [
+      {
+       "metadata": {},
+       "output_type": "display_data",
+       "png": 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VoUBEZIE8PICPPwZWrTLv/RoYCkREFkqOuQaGAhGRhWs91yDlzqsMBSIiK6Db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\n",
+       "text": [
+        "<matplotlib.figure.Figure at 0x7f6d25333a90>"
+       ]
+      },
+      {
+       "output_type": "stream",
+       "stream": "stdout",
+       "text": [
+        "DC load line shown in figure.\n"
+       ]
+      }
+     ],
+     "prompt_number": 22
+    }
+   ],
+   "metadata": {}
+  }
+ ]
+}
\ No newline at end of file