Added(A)/Deleted(D) following books

 A  A_textbook_of_Internal_Combustion_Engines_by_R._K._Rajput/CHAPTER11.ipynb
A  A_textbook_of_Internal_Combustion_Engines_by_R._K._Rajput/CHAPTER12.ipynb
A  A_textbook_of_Internal_Combustion_Engines_by_R._K._Rajput/CHAPTER15.ipynb
A  A_textbook_of_Internal_Combustion_Engines_by_R._K._Rajput/CHAPTER16.ipynb
A  A_textbook_of_Internal_Combustion_Engines_by_R._K._Rajput/CHAPTER17.ipynb
A  A_textbook_of_Internal_Combustion_Engines_by_R._K._Rajput/CHAPTER20.ipynb
A  A_textbook_of_Internal_Combustion_Engines_by_R._K._Rajput/CHAPTER21.ipynb
A  A_textbook_of_Internal_Combustion_Engines_by_R._K._Rajput/CHAPTER3.ipynb
A  A_textbook_of_Internal_Combustion_Engines_by_R._K._Rajput/CHAPTER4.ipynb
A  A_textbook_of_Internal_Combustion_Engines_by_R._K._Rajput/CHAPTER5.ipynb
A  A_textbook_of_Internal_Combustion_Engines_by_R._K._Rajput/CHAPTER7.ipynb
A  A_textbook_of_Internal_Combustion_Engines_by_R._K._Rajput/screenshots/HeatTransfer(3).png
A  A_textbook_of_Internal_Combustion_Engines_by_R._K._Rajput/screenshots/cycleWorkEff(4).png
A  A_textbook_of_Internal_Combustion_Engines_by_R._K._Rajput/screenshots/volumetric_Eff(7).png
A  Engineering_Thermodynamics_by_Dr._S._S._Khandare/chapter_no_1.ipynb
A  Engineering_Thermodynamics_by_Dr._S._S._Khandare/chapter_no_2.ipynb
A  Engineering_Thermodynamics_by_Dr._S._S._Khandare/chapter_no_3.ipynb
A  Engineering_Thermodynamics_by_Dr._S._S._Khandare/chapter_no_4.ipynb
A  Engineering_Thermodynamics_by_Dr._S._S._Khandare/chapter_no_5.ipynb
A  Engineering_Thermodynamics_by_Dr._S._S._Khandare/chapter_no_6.ipynb
A  Engineering_Thermodynamics_by_Dr._S._S._Khandare/chapter_no_7.ipynb
A  Engineering_Thermodynamics_by_Dr._S._S._Khandare/chapter_no_8.ipynb
A  Engineering_Thermodynamics_by_Dr._S._S._Khandare/screenshots/file1.png
A  Engineering_Thermodynamics_by_Dr._S._S._Khandare/screenshots/file2.png
A  Engineering_Thermodynamics_by_Dr._S._S._Khandare/screenshots/file3.png
A  sample_notebooks/MohdGufran/chapter_10.ipynb

1 files changed, 355 insertions, 0 deletions

diff --git a/sample_notebooks/MohdGufran/chapter_10.ipynb b/sample_notebooks/MohdGufran/chapter_10.ipynb
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+{
+ "metadata": {
+  "name": ""
+ },
+ "nbformat": 3,
+ "nbformat_minor": 0,
+ "worksheets": [
+  {
+   "cells": [
+    {
+     "cell_type": "heading",
+     "level": 1,
+     "metadata": {},
+     "source": [
+      "Chapter No - 10 : Mass Transfer\n",
+      "    "
+     ]
+    },
+    {
+     "cell_type": "heading",
+     "level": 2,
+     "metadata": {},
+     "source": [
+      "Example No :  10.1 - Page No. : 318"
+     ]
+    },
+    {
+     "cell_type": "code",
+     "collapsed": false,
+     "input": [
+      "from __future__ import division\n",
+      "# Given data\n",
+      "P1=4     # in bar\n",
+      "P2=2     # in bar\n",
+      "T=25     # in degree C\n",
+      "Dhp=9*10**-8     # in m**2/s\n",
+      "S=3*10**-3     # in kg mole/m**3 bar\n",
+      "del_x=0.5*10**-3     # thickness in m\n",
+      "#(a) The molar concentration of a gas in terms of solubility\n",
+      "CH1=S*P1     # in kg mole/m**3\n",
+      "CH2=S*P2     # in kg mole/m**3\n",
+      "#(b) Molar diffusion flux of hydrogen through plastic memberence is given by Fick's law of diffision\n",
+      "#N_H= N_h/A = Dhp*(CH1-CH2)/del_x#\n",
+      "N_H= Dhp*(CH1-CH2)/del_x     # in kg mole/s-m**2\n",
+      "print \"Molar diffusion flux of hydrogen through the membrane = %0.2e kg mole/s-m**2\" %N_H\n",
+      "#Mass_d_Flux= N_H*Molecular_Weight \n",
+      "Molecular_Weight=2#\n",
+      "Mass_d_Flux= N_H*Molecular_Weight \n",
+      "print \"Molar diffusion flux = %0.3e kg/s-m**2\" %Mass_d_Flux"
+     ],
+     "language": "python",
+     "metadata": {},
+     "outputs": [
+      {
+       "output_type": "stream",
+       "stream": "stdout",
+       "text": [
+        "Molar diffusion flux of hydrogen through the membrane = 1.08e-06 kg mole/s-m**2\n",
+        "Molar diffusion flux = 2.160e-06 kg/s-m**2\n"
+       ]
+      }
+     ],
+     "prompt_number": 5
+    },
+    {
+     "cell_type": "heading",
+     "level": 2,
+     "metadata": {},
+     "source": [
+      "Example No :  10.2 - Page No. : 322"
+     ]
+    },
+    {
+     "cell_type": "code",
+     "collapsed": false,
+     "input": [
+      "# Given data\n",
+      "T=25     # in degree C\n",
+      "T=T+273     # in K\n",
+      "P=1#\n",
+      "V1=12     #Molecular volume of H2 in cm**3/gm mole\n",
+      "V2=30     #Molecular volume of Air in cm**3/gm mole\n",
+      "M1=2     # Molecular weight of H2\n",
+      "M2=29     # Molecular weight of Air\n",
+      "#The diffusion coefficient for gases in terms of molecular volumes may be express as\n",
+      "D_AB= .0043*T**(3/2)/(P*(V1**(1/3)+V2**(1/3)))*(1/M1+1/M2)**(1/2)#\n",
+      "print \"The diffusion coefficient for gases in terms of molecular volumes = %0.3f cm**2/sec\" %D_AB"
+     ],
+     "language": "python",
+     "metadata": {},
+     "outputs": [
+      {
+       "output_type": "stream",
+       "stream": "stdout",
+       "text": [
+        "The diffusion coefficient for gases in terms of molecular volumes = 2.997 cm**2/sec\n"
+       ]
+      }
+     ],
+     "prompt_number": 7
+    },
+    {
+     "cell_type": "heading",
+     "level": 2,
+     "metadata": {},
+     "source": [
+      "Example No :  10.3 - Page No. : 322"
+     ]
+    },
+    {
+     "cell_type": "code",
+     "collapsed": false,
+     "input": [
+      "# Given data\n",
+      "T=300     # temp of gas mixture in K\n",
+      "D_HN2=18*10**-6     # in m**2/s at 300 K, 1 bar\n",
+      "T1=300     # in K\n",
+      "D_HO2=16*10**-6     # in m**2/s at 273 K, 1 bar\n",
+      "T2=273     # in K\n",
+      "O_2=0.2#\n",
+      "N_2=0.7#\n",
+      "H_2=0.1#\n",
+      "#The diffusivity at the mixture temperature and pressure are calculated as \n",
+      "# D1/D2 = (T1/T2)**(3/2)*(P2/P1)\n",
+      "D_HO2= (T/T2)**(3/2)*1/4*D_HO2#\n",
+      "D_HN2= (T/T1)**(3/2)*1/4*D_HN2#\n",
+      "#The composition of oxygen and nitrogen on a H2 free basis is \n",
+      "x_O= O_2/(1-H_2)#\n",
+      "x_N= N_2/(1-H_2)#\n",
+      "\n",
+      "# The effective diffusivity for the gas mixture at given temperature and pressure is\n",
+      "D= 1/(x_O/D_HO2+x_N/D_HN2)     # in m**2/s\n",
+      "print \"Effective diffusivity = %0.3e m**2/s\" %D"
+     ],
+     "language": "python",
+     "metadata": {},
+     "outputs": [
+      {
+       "output_type": "stream",
+       "stream": "stdout",
+       "text": [
+        "Effective diffusivity = 4.524e-06 m**2/s\n"
+       ]
+      }
+     ],
+     "prompt_number": 12
+    },
+    {
+     "cell_type": "heading",
+     "level": 2,
+     "metadata": {},
+     "source": [
+      "Example No :  10.4 - Page No. : 323"
+     ]
+    },
+    {
+     "cell_type": "code",
+     "collapsed": false,
+     "input": [
+      "from numpy import pi\n",
+      "# Given data\n",
+      "d=3     # in mm\n",
+      "d=d*10**-3     # in meter\n",
+      "T=25     # in \u00b0C\n",
+      "T=T+273     # in K\n",
+      "D= 0.4*10**-4     # in m**2/s\n",
+      "R= 8314#\n",
+      "P_A1=1     # in atm\n",
+      "P_A1=P_A1*10**5     # in w/m**2\n",
+      "P_A2=0#\n",
+      "C_A2=0#\n",
+      "x2= 15     # in meter\n",
+      "x1= 0#\n",
+      "A= pi/4*d**2#\n",
+      "M_A= D*A/(R*T)*(P_A1-P_A2)/(x2-x1)     # in kg mole/sec\n",
+      "N_B= M_A#\n",
+      "M_B= M_A*29     # in kg/sec\n",
+      "print \"Value of N_B = %0.3e kg mole/sec\" %N_B\n",
+      "print \"Value of M_B = %0.3e kg /sec\" %M_B"
+     ],
+     "language": "python",
+     "metadata": {},
+     "outputs": [
+      {
+       "output_type": "stream",
+       "stream": "stdout",
+       "text": [
+        "Value of N_B = 7.608e-13 kg mole/sec\n",
+        "Value of M_B = 2.206e-11 kg /sec\n"
+       ]
+      }
+     ],
+     "prompt_number": 15
+    },
+    {
+     "cell_type": "heading",
+     "level": 2,
+     "metadata": {},
+     "source": [
+      "Example No :  10.5 - Page No. : 325"
+     ]
+    },
+    {
+     "cell_type": "code",
+     "collapsed": false,
+     "input": [
+      "from math import log\n",
+      "# Given data\n",
+      "P=3     # in atm\n",
+      "P=P*10**5     # in N/m**2\n",
+      "r1=10     # in mm\n",
+      "r1=r1*10**-3     # in m\n",
+      "r2=20     # in mm\n",
+      "r2=r2*10**-3     # in m\n",
+      "R=4160     # in J/kg-K\n",
+      "T=303     # in K\n",
+      "D=3*10**-8     # in m**2/s\n",
+      "S=3*0.05# # Solubility of hydrogen at a pressure of 3 atm in m**3/m**3 of rubber tubing\n",
+      "del_x=r2-r1     # in m\n",
+      "L=1     # in m\n",
+      "Am=2*pi*L*del_x/log(r2/r1)#\n",
+      "#Formula P*V= m*R*T\n",
+      "V=S#\n",
+      "m=P*V/(R*T)     # in kg/m**3 of rubber tubing at the inner surface of the pipe\n",
+      "C_A1=m#\n",
+      "C_A2=0#\n",
+      "#Diffusion flux through the cylinder is given\n",
+      "M=D*(C_A1-C_A2)*Am/del_x#\n",
+      "print \"Diffusion flux through the cylinder = %0.2e kg/sm\" %M"
+     ],
+     "language": "python",
+     "metadata": {},
+     "outputs": [
+      {
+       "output_type": "stream",
+       "stream": "stdout",
+       "text": [
+        "Diffusion flux through the cylinder = 9.71e-09 kg/sm\n"
+       ]
+      }
+     ],
+     "prompt_number": 18
+    },
+    {
+     "cell_type": "heading",
+     "level": 2,
+     "metadata": {},
+     "source": [
+      "Example No :  10.6 - Page No. :  329"
+     ]
+    },
+    {
+     "cell_type": "code",
+     "collapsed": false,
+     "input": [
+      "# Given data\n",
+      "R=4160     # in J/kg-K\n",
+      "M=2#\n",
+      "D_AB=1.944*10**-8     # in m**2/s\n",
+      "R_H2=R/M#\n",
+      "S=2*0.0532# # Solubility of hydrogen at a pressure of 2 atm in cm**3/cm**3 of pipe\n",
+      "P=2     # in atm\n",
+      "P=P*1.03*10**5     # N/m**2\n",
+      "T=25     # in degree C\n",
+      "T=T+273     # in K\n",
+      "r1=2.5     # in mm\n",
+      "r1=r1*10**-3     # in m\n",
+      "r2=5     # in mm\n",
+      "r2=r2*10**-3     # in m\n",
+      "del_x=r2-r1     # in m\n",
+      "L=1     # in m\n",
+      "#Formula P*V= m*R*T\n",
+      "V=S#\n",
+      "m=P*V/(R*T)     # in kg/m**3 of pipe\n",
+      "# So, Concentration of H2 at inner surface of the pipe\n",
+      "C_A1=0.0176     # in kg/m**3\n",
+      "# The resistance of diffusion of H2 away from the outer surface is negligible i.e.\n",
+      "C_A2=0#\n",
+      "Am=2*pi*L*del_x/log(r2/r1)#\n",
+      "# Loss of H2 by diffusion \n",
+      "M_A= D_AB*(C_A1-C_A2)*Am/del_x#\n",
+      "print \"Loss of H2 by diffusion = %0.2ef kg/s\" %M_A"
+     ],
+     "language": "python",
+     "metadata": {},
+     "outputs": [
+      {
+       "output_type": "stream",
+       "stream": "stdout",
+       "text": [
+        "Loss of H2 by diffusion = 3.10e-09f kg/s\n"
+       ]
+      }
+     ],
+     "prompt_number": 23
+    },
+    {
+     "cell_type": "heading",
+     "level": 2,
+     "metadata": {},
+     "source": [
+      "Example No :  10.7 - Page No. : 330"
+     ]
+    },
+    {
+     "cell_type": "code",
+     "collapsed": false,
+     "input": [
+      "# Given data\n",
+      "Px1= 0.14     # in bar\n",
+      "Px2= 0#\n",
+      "P=1.013     # in bar\n",
+      "Py1=P-Px1# # in bar\n",
+      "Py2=P-Px2# # in bar\n",
+      "D=8.5*10**-6     # in m**2/s\n",
+      "d=5     # diameter in meter\n",
+      "L=1     # in mm\n",
+      "L=L*10**-3     #in meter\n",
+      "M=78     # molecular weight\n",
+      "Am_x= 1/4*pi*d**2*M#\n",
+      "R=8314#\n",
+      "del_x=3     # thickness in mm\n",
+      "del_x=del_x*10**-3     # in m\n",
+      "T=20     # in degree C\n",
+      "T=T+273     # in K\n",
+      "P=P*10**5     # in N/m**2\n",
+      "m_x= D*Am_x*P*log(Py2/Py1)/(R*T*del_x)#\n",
+      "# The mass of the benzene to be evaporated\n",
+      "mass= 1/4*pi*d**2*L#\n",
+      "density=880     # in kg/m**3\n",
+      "m_b= mass*density#\n",
+      "toh=m_b/m_x     # in sec\n",
+      "print \"Time taken for the entire organic compound to evaporate = %0.0f seconds\" %toh\n",
+      "\n",
+      "\n",
+      "# Note: Answer in the book is wrong"
+     ],
+     "language": "python",
+     "metadata": {},
+     "outputs": [
+      {
+       "output_type": "stream",
+       "stream": "stdout",
+       "text": [
+        "Time taken for the entire organic compound to evaporate = 644 seconds\n"
+       ]
+      }
+     ],
+     "prompt_number": 25
+    }
+   ],
+   "metadata": {}
+  }
+ ]
+}
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