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| author | hardythe1 | 2015-06-11 17:31:11 +0530 |
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| committer | hardythe1 | 2015-06-11 17:31:11 +0530 |
| commit | 251a07c4cbed1a5a960f5ed416ce6ac13c8152b7 (patch) | |
| tree | cb7f084fad6d7ee6ae89e586fad0e909b5408319 /sample_notebooks/yashwanth kumarmada/sample_notes_1.ipynb | |
| parent | 47d7279a724246ef7aa0f5359cf417992ed04449 (diff) | |
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diff --git a/sample_notebooks/yashwanth kumarmada/sample_notes_1.ipynb b/sample_notebooks/yashwanth kumarmada/sample_notes_1.ipynb new file mode 100755 index 00000000..faacb548 --- /dev/null +++ b/sample_notebooks/yashwanth kumarmada/sample_notes_1.ipynb @@ -0,0 +1,480 @@ +{
+ "cells": [
+ {
+ "cell_type": "markdown",
+ "metadata": {
+ "collapsed": true
+ },
+ "source": [
+ "# CHAPTER 2 :Physical Properties of Hydraulic Fluids"
+ ]
+ },
+ {
+ "cell_type": "markdown",
+ "metadata": {
+ "collapsed": false
+ },
+ "source": [
+ "##Example2_1"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "execution_count": 6,
+ "metadata": {
+ "collapsed": false
+ },
+ "outputs": [
+ {
+ "name": "stdout",
+ "output_type": "stream",
+ "text": [
+ "the weight is 129.0\n"
+ ]
+ }
+ ],
+ "source": [
+ "# Aim:To Find Weight of Body\n",
+ "# Given:\n",
+ "# Mass of the Body:\n",
+ "m=4; #slugs\n",
+ "\n",
+ "# Solutions:\n",
+ "# we know acceleration due to gravity,\n",
+ "g=32.2; #ft/s**2\n",
+ "W=(m*g);\n",
+ "\n",
+ "# Results:\n",
+ "print \"the weight(lbs) is\",round(W,0)\n"
+ ]
+ },
+ {
+ "cell_type": "markdown",
+ "metadata": {},
+ "source": [
+ "## Example2_2"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "execution_count": 2,
+ "metadata": {
+ "collapsed": false
+ },
+ "outputs": [
+ {
+ "name": "stdout",
+ "output_type": "stream",
+ "text": [
+ " Results: \n",
+ " The specific weight of Body is lb/ft**3. 71.7\n"
+ ]
+ }
+ ],
+ "source": [
+ "# Aim:To find the specific weight of a body\n",
+ "# Given:\n",
+ "# Weigth of the Body:\n",
+ "W=129; #lb\n",
+ "# Volume of the Body:\n",
+ "V=1.8; #ft**3\n",
+ "\n",
+ "# Solution:\n",
+ "# we know specific weight,\n",
+ "# gamma=(Weigth of the Body/Volume of the Body)\n",
+ "gamma1=(W/V); #lb/ft^3\n",
+ "# rounding off the above answer\n",
+ "gamma1=round(gamma1)+(round((gamma1-round(gamma1))*10)/10); #lb/ft^3\n",
+ " \n",
+ "# Results:\n",
+ "print \" Results: \"\n",
+ "print \" The specific weight of Body is lb/ft**3.\",gamma1\n"
+ ]
+ },
+ {
+ "cell_type": "markdown",
+ "metadata": {},
+ "source": [
+ "## Example2_3"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "execution_count": 2,
+ "metadata": {
+ "collapsed": false
+ },
+ "outputs": [
+ {
+ "name": "stdout",
+ "output_type": "stream",
+ "text": [
+ "Results: \n",
+ "The specific gravity of air 0.00121\n"
+ ]
+ }
+ ],
+ "source": [
+ "# Aim:To find the specific gravity of air at 68 degF\n",
+ "# Given:\n",
+ "# specific weight of air at 68 degF:\n",
+ "gamma_air=0.0752; #lb/ft**3\n",
+ "\n",
+ "\n",
+ "# Solution:\n",
+ "# we know,\n",
+ "# specific gravity of air=(specific weight of air/specific weight of water)\n",
+ "# also we know,specific weight of water at 68 degF,\n",
+ "gamma_water=62.4; #lb/ft**3\n",
+ "SG_air=gamma_air/gamma_water;\n",
+ "\n",
+ "# Results:\n",
+ "print \"Results: \"\n",
+ "print \"The specific gravity of air \",round(SG_air,5) \n",
+ "\n"
+ ]
+ },
+ {
+ "cell_type": "markdown",
+ "metadata": {},
+ "source": [
+ "## Example2_4"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "execution_count": 3,
+ "metadata": {
+ "collapsed": false
+ },
+ "outputs": [
+ {
+ "name": "stdout",
+ "output_type": "stream",
+ "text": [
+ "Results: \n",
+ "The Density of Body is slugs/ft**3. 2.2222\n",
+ "The Density of Body is slugs/ft**3. 2.2236\n"
+ ]
+ }
+ ],
+ "source": [
+ "\n",
+ "# Aim:To find Density of body of Example 2-1 and 2-2\n",
+ "# Given:\n",
+ "# mass of the Body:\n",
+ "m=4; #slugs\n",
+ "# Volume of the Body:\n",
+ "V=1.8; #ft**3\n",
+ "\n",
+ "# Solution:\n",
+ "# we know density,\n",
+ "# rho1=(mass of the Body/Volume of the Body)\n",
+ "rho1=(m/V); #slugs/ft**3\n",
+ "# also density,rho2=(specific weight/acceleration due to gravity)\n",
+ "g=32.2; #ft/s**2\n",
+ "gamma1=71.6; #lb/ft**3\n",
+ "rho2=(gamma1/g); #slugs/ft**3\n",
+ "\n",
+ "# Results:\n",
+ "print \"Results: \"\n",
+ "print \"The Density of Body is slugs/ft**3.\",round(rho1,4)\n",
+ "print \"The Density of Body is slugs/ft**3.\",round(rho2,4)\n"
+ ]
+ },
+ {
+ "cell_type": "markdown",
+ "metadata": {},
+ "source": [
+ "## Example2_5"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "execution_count": 7,
+ "metadata": {
+ "collapsed": false
+ },
+ "outputs": [
+ {
+ "name": "stdout",
+ "output_type": "stream",
+ "text": [
+ " Results: \n",
+ " The pressure on skin diver is psi. 26.0\n"
+ ]
+ }
+ ],
+ "source": [
+ "# Aim:To find pressure on the skin diver\n",
+ "# Given:\n",
+ "# Depth of Water Body:\n",
+ "H=60; #ft\n",
+ "\n",
+ "# Solution:\n",
+ "# specific Weight of water,\n",
+ "gamma1=0.0361; #lb/in**3 \n",
+ "# Conversion: \n",
+ "# 1 feet = 12 inches\n",
+ "# 1 lb/in**2 = 1 psi \n",
+ "# we know pressure,\n",
+ "# p=(specific weight of liquid * liquid column height)\n",
+ "p=(gamma1*H*12); #psi\n",
+ "\n",
+ "# Results:\n",
+ "print \" Results: \"\n",
+ "print \" The pressure on skin diver is psi.\",round(p,1)\n",
+ "\n",
+ "\n"
+ ]
+ },
+ {
+ "cell_type": "markdown",
+ "metadata": {},
+ "source": [
+ "## Example2_6"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "execution_count": 5,
+ "metadata": {
+ "collapsed": false
+ },
+ "outputs": [
+ {
+ "name": "stdout",
+ "output_type": "stream",
+ "text": [
+ " Results: \n",
+ " The Height of water column is ft. 33.8\n"
+ ]
+ }
+ ],
+ "source": [
+ "\n",
+ "# Aim:To find tube height of a Barometer\n",
+ "# Given:\n",
+ "# liquid used is Water instead of Mercury.\n",
+ "\n",
+ "# Solution:\n",
+ "# specific Weight of water,\n",
+ "gamma1=0.0361; #lb/in**3 \n",
+ "# We also knows Atmospheric Pressure,\n",
+ "p=14.7; #psi\n",
+ "# Conversion: \n",
+ "# 1 feet = 12 inches\n",
+ "# 1 lb/in**2 = 1 psi \n",
+ "# we know pressure,\n",
+ "# p=(specific weight of liquid * liquid column height)\n",
+ "# Therefore,\n",
+ "H=(p/gamma1); #in\n",
+ "# He=Height in Feet.\n",
+ "He=H*0.083; #ft\n",
+ "\n",
+ "# Results:\n",
+ "print \" Results: \"\n",
+ "print \" The Height of water column is ft.\",round(He,1)\n"
+ ]
+ },
+ {
+ "cell_type": "markdown",
+ "metadata": {},
+ "source": [
+ "## Example2_7"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "execution_count": 13,
+ "metadata": {
+ "collapsed": false
+ },
+ "outputs": [
+ {
+ "name": "stdout",
+ "output_type": "stream",
+ "text": [
+ " Results: \n",
+ " The Absolute Pressure is psi. 9.7\n"
+ ]
+ }
+ ],
+ "source": [
+ "\n",
+ "# Aim:To convert given pressure into absolute pressure\n",
+ "# Given:\n",
+ "# Gage Pressure:\n",
+ "Pg=-5; #psi\n",
+ "\n",
+ "# Solution:\n",
+ "# Atmospheric Pressure,\n",
+ "Po=14.7; #psi \n",
+ "# Absolute Pressure(Pa) =Gage Pressure + Atmospheric Pressure\n",
+ "Pa=Pg+Po;\n",
+ "\n",
+ "# Results:\n",
+ "print \" Results: \"\n",
+ "print \" The Absolute Pressure is psi.\",Pa\n"
+ ]
+ },
+ {
+ "cell_type": "markdown",
+ "metadata": {},
+ "source": [
+ "## Example2_8"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "execution_count": 14,
+ "metadata": {
+ "collapsed": false
+ },
+ "outputs": [
+ {
+ "name": "stdout",
+ "output_type": "stream",
+ "text": [
+ " Results: \n",
+ "The Absolute Pressure is psi. 40.7\n"
+ ]
+ }
+ ],
+ "source": [
+ "\n",
+ "# Aim:To find absolute pressure on skin diver of Example 2-5\n",
+ "# Given:\n",
+ "# Gage Pressure:\n",
+ "Pg=26; #psi\n",
+ "\n",
+ "# Solution:\n",
+ "# Atmospheric Pressure,\n",
+ "Po=14.7; #psi \n",
+ "# Absolute Pressure(Pa) =Gage Pressure + Atmospheric Pressure\n",
+ "Pa=Pg+Po; #psi\n",
+ "\n",
+ "# Results:\n",
+ "print \" Results: \"\n",
+ "print \"The Absolute Pressure is psi.\",Pa\n"
+ ]
+ },
+ {
+ "cell_type": "markdown",
+ "metadata": {},
+ "source": [
+ "## Example2_9"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "execution_count": 15,
+ "metadata": {
+ "collapsed": false
+ },
+ "outputs": [
+ {
+ "name": "stdout",
+ "output_type": "stream",
+ "text": [
+ " Results: \n",
+ "The specific weights is N/m**3. 8792\n",
+ " The answer in the program is different than that in textbook. It may be due to no.s of significant digit in data and calculation\n"
+ ]
+ }
+ ],
+ "source": [
+ "\n",
+ "# Aim:To Determine specific weights in N/m**3\n",
+ "# Given:\n",
+ "# specific weight:\n",
+ "gamma1=56; #lb/ft**3\n",
+ "\n",
+ "\n",
+ "# Solution:\n",
+ "# We know,\n",
+ "# 1 N/m**3 = 157 lb/ft**3\n",
+ "gamma2=157*gamma1; #N/m**3\n",
+ "\n",
+ "# Results:\n",
+ "print \" Results: \"\n",
+ "print \"The specific weights is N/m**3.\",gamma2\n",
+ "print \" The answer in the program is different than that in textbook. It may be due to no.s of significant digit in data and calculation\"\n",
+ "\n"
+ ]
+ },
+ {
+ "cell_type": "markdown",
+ "metadata": {},
+ "source": [
+ "## Example2_10"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "execution_count": 16,
+ "metadata": {
+ "collapsed": false
+ },
+ "outputs": [
+ {
+ "name": "stdout",
+ "output_type": "stream",
+ "text": [
+ " Results: \n",
+ " The temp at which Fahrenheit and Celsius values are equal is deg. -40.0\n"
+ ]
+ }
+ ],
+ "source": [
+ "\n",
+ "# Aim:To find Temperature at which Fahrenheit and Celsius values are equal \n",
+ "# Given:\n",
+ "# T(degF) = T(degC) #Eqn - 1\n",
+ "\n",
+ "# Solution:\n",
+ "# We know that,\n",
+ "# T(degF)=((1.8*T(degC))+32) #Eqn - 2 \n",
+ "# From Eqn 1 and 2\n",
+ "# ((1.8*T(degC))+32)= T(degC)\n",
+ "# (1-1.8)*T(degC)=32\n",
+ "# -0.8*T(degC)=32\n",
+ "TdegC=-32/0.8;\n",
+ "\n",
+ "# Results:\n",
+ "print \" Results: \"\n",
+ "print \" The temp at which Fahrenheit and Celsius values are equal is deg.\",TdegC\n"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "execution_count": null,
+ "metadata": {
+ "collapsed": true
+ },
+ "outputs": [],
+ "source": []
+ }
+ ],
+ "metadata": {
+ "kernelspec": {
+ "display_name": "Python 2",
+ "language": "python",
+ "name": "python2"
+ },
+ "language_info": {
+ "codemirror_mode": {
+ "name": "ipython",
+ "version": 2
+ },
+ "file_extension": ".py",
+ "mimetype": "text/x-python",
+ "name": "python",
+ "nbconvert_exporter": "python",
+ "pygments_lexer": "ipython2",
+ "version": "2.7.9"
+ }
+ },
+ "nbformat": 4,
+ "nbformat_minor": 0
+}
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