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authorThomas Stephen Lee2015-08-28 16:53:23 +0530
committerThomas Stephen Lee2015-08-28 16:53:23 +0530
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+{
+ "metadata": {
+ "name": "",
+ "signature": "sha256:a87b776675d5bac90b6fac25c1a236bc0e485ed79b01767e8b8d1e2b69104021"
+ },
+ "nbformat": 3,
+ "nbformat_minor": 0,
+ "worksheets": [
+ {
+ "cells": [
+ {
+ "cell_type": "heading",
+ "level": 1,
+ "metadata": {},
+ "source": [
+ "CHAPTER 2- Mechanical Behavior, Testing, and Manufacturing Properties of Materials"
+ ]
+ },
+ {
+ "cell_type": "heading",
+ "level": 2,
+ "metadata": {},
+ "source": [
+ "EXAMPLE 2.1 - PG NO. 63"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "#example 2.1,chapter 2, page 63\n",
+ "\n",
+ "# Given that\n",
+ "#True stress=100000*(True strain)**0.5\n",
+ "\n",
+ "# Sample Problem on page no. 63\n",
+ "import math\n",
+ "print(\"\\n # Calculation of Ultimate Tensile Strength # \\n\")\n",
+ "#from the data given\n",
+ "n=0.5\n",
+ "E=0.5\n",
+ "K=690.\n",
+ "Truestress=K*((E)**n)\n",
+ "#let An(area of neck)/Ao=t\n",
+ "#from math.log(Ao/An)=n\n",
+ "print'%s %d %s' %(\"true Ultimate Tensile Strength =\",round(Truestress),\"MPa \\n\")\n",
+ "t=math.exp(-n)\n",
+ "UTS=Truestress*math.exp(-n)#from the math.expression UTS= P/Ao where P(Maximum Load)=Truestress*An\n",
+ "print'%s %d %s' %(\"Ultimate Tensile Strength =\",round(UTS),\"MPa\")\n",
+ "#answer in the book is approximated to 42850 psi \n"
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "\n",
+ " # Calculation of Ultimate Tensile Strength # \n",
+ "\n",
+ "true Ultimate Tensile Strength = 488 MPa \n",
+ "\n",
+ "Ultimate Tensile Strength = 296 MPa\n"
+ ]
+ }
+ ],
+ "prompt_number": 1
+ },
+ {
+ "cell_type": "heading",
+ "level": 2,
+ "metadata": {},
+ "source": [
+ "EXAMPLE 2.2 - PG NO. 72"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "#example 2.1,chapter 2, page 72\n",
+ "\n",
+ "print(\"## Calculation of Modulus of Resilience from Hardness ##\\n\")\n",
+ "#given data\n",
+ "Hardness=300.\n",
+ "Y=100.#\n",
+ "E=210000.\n",
+ "a=100.*100.\n",
+ "b=2.*210000.\n",
+ "Modulus=a/b\n",
+ "print(\"The area under the stress-strain curve is :\\n\")\n",
+ "print'%s %.4f %s' %(\"Modulus of Resilience =\",Modulus*9.81,\"mm-kg/mm^3\")"
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "## Calculation of Modulus of Resilience from Hardness ##\n",
+ "\n",
+ "The area under the stress-strain curve is :\n",
+ "\n",
+ "Modulus of Resilience = 0.2336 mm-kg/mm^3\n"
+ ]
+ }
+ ],
+ "prompt_number": 2
+ }
+ ],
+ "metadata": {}
+ }
+ ]
+} \ No newline at end of file