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+{
+ "metadata": {
+ "name": "",
+ "signature": "sha256:85e9fe66492d8e2bf21b397989dbba9327240cd1300820fe26869c1390e3cf15"
+ },
+ "nbformat": 3,
+ "nbformat_minor": 0,
+ "worksheets": [
+ {
+ "cells": [
+ {
+ "cell_type": "heading",
+ "level": 1,
+ "metadata": {},
+ "source": [
+ "Chapter1-Introduction fluid mechanics"
+ ]
+ },
+ {
+ "cell_type": "heading",
+ "level": 2,
+ "metadata": {},
+ "source": [
+ "Ex1-pg13"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "import math\n",
+ "##initialization of new variables\n",
+ "#calculate density \n",
+ "M=29. ## Molecular weight of air\n",
+ "R=8314.3 ## J/mol K Gas constant\n",
+ "T=300. ##K Temperature\n",
+ "P=1. ##kg/cm^2 Pressure\n",
+ "g=9.8 ##m/s^2 Acceleration due to gravity\n",
+ "##calculations\n",
+ "R=R/M\n",
+ "P=P*g*10**4\n",
+ "rho=P/(R*T)\n",
+ "##result\n",
+ "print'%s %.2f %s'%(' Density = ',rho,' kg/m^3 ')\n"
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ " Density = 1.14 kg/m^3 \n"
+ ]
+ }
+ ],
+ "prompt_number": 1
+ },
+ {
+ "cell_type": "heading",
+ "level": 2,
+ "metadata": {},
+ "source": [
+ "Ex2-pg13"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "import math\n",
+ "##initialization of new variables\n",
+ "#calculate shear stress\n",
+ "t=2. ##cm thickness\n",
+ "U=3. ##m/s Velocity\n",
+ "mu=0.29 ##kg/m s Coefficient of Viscocity\n",
+ "##calculations\n",
+ "tau=mu*U/(t*10**-2)\n",
+ "##results\n",
+ "print'%s %.2f %s'%(' Shear = ',tau,' N/m^2')\n"
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ " Shear = 43.50 N/m^2\n"
+ ]
+ }
+ ],
+ "prompt_number": 2
+ },
+ {
+ "cell_type": "heading",
+ "level": 2,
+ "metadata": {},
+ "source": [
+ "Ex3-pg13"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "import math\n",
+ "##initialization of new variables\n",
+ "#calculate pressure differnce\n",
+ "sigma=2.5*10**-2 ##N/m\n",
+ "D=10 ##cm\n",
+ "##calculations\n",
+ "R=D/2.\n",
+ "dP=2.*sigma/(R*10**-2)\n",
+ "##result\n",
+ "print'%s %.2f %s'%('The pressure difference is = ',dP,' N/m^2')\n"
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "The pressure difference is = 1.00 N/m^2\n"
+ ]
+ }
+ ],
+ "prompt_number": 3
+ },
+ {
+ "cell_type": "heading",
+ "level": 2,
+ "metadata": {},
+ "source": [
+ "Ex4-pg15"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "import math\n",
+ "##initialization of new variables\n",
+ "#calculate rise of water and rise of mercury\n",
+ "R=1. ##mm\n",
+ "sigma=0.073 ##N/m\n",
+ "theta=0. ##degrees\n",
+ "rho=1000. ##kg/m^3\n",
+ "g=9.8 ##m/s^2\n",
+ "##calculations\n",
+ "theta=theta*math.pi/180 ##radians\n",
+ "h=2*sigma*math.cos(theta)/(rho*g*R*10**-3)\n",
+ "##result\n",
+ "print'%s %.2f %s'%('The rise of water = ',h,' m')\n",
+ "R=1. ##mm\n",
+ "sigma=0.48 ##N/m\n",
+ "theta=130. ##degrees\n",
+ "rho=13600. ##kg/m^3\n",
+ "g=9.8 ##m/s^2\n",
+ "##calculations\n",
+ "theta=theta*math.pi/180 ##radians\n",
+ "h=2*sigma*math.cos(theta)/(rho*g*R*10**-3)\n",
+ "##result\n",
+ "print'%s %.2e %s'%('\\n The rise of mercury = ',h,' m')\n",
+ "\n"
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "The rise of water = 0.01 m\n",
+ "\n",
+ " The rise of mercury = -4.63e-03 m\n"
+ ]
+ }
+ ],
+ "prompt_number": 4
+ },
+ {
+ "cell_type": "heading",
+ "level": 2,
+ "metadata": {},
+ "source": [
+ "Ex5-pg15"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "import math\n",
+ "##initialization of new variables\n",
+ "#calculate chenge in pressure and change in volume\n",
+ "E=2.34*10**9 ##N/m^2 Modulus of Elasticity\n",
+ "d=1 ##km depth\n",
+ "rho=1000. ##kg/m^3 density\n",
+ "g=9.8 ##m/s^2 Acceleration due to gravity\n",
+ "##calculations\n",
+ "d=d*1000. \n",
+ "dp=rho*g*d\n",
+ "dVV=dp/E\n",
+ "##result\n",
+ "print'%s %.2e %s'%('The change in pressure is ',dp,' N/m^2 ')\n",
+ "print'%s %.3e %s'%('\\n Change in volume is ',dVV,'')\n"
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "The change in pressure is 9.80e+06 N/m^2 \n",
+ "\n",
+ " Change in volume is 4.188e-03 \n"
+ ]
+ }
+ ],
+ "prompt_number": 5
+ },
+ {
+ "cell_type": "heading",
+ "level": 2,
+ "metadata": {},
+ "source": [
+ "Ex6-pg16"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "import math\n",
+ "##initialization of new variables\n",
+ "#calculate speed of sound in air and speed of sound in sea water\n",
+ "T=300. ##K\n",
+ "gama=1.4\n",
+ "R=286.6\n",
+ "##calculation\n",
+ "## for air\n",
+ "a=math.sqrt(gama*R*T)\n",
+ "##result\n",
+ "print'%s %.2f %s'%('The speed of sound in air is ',a,' m/s ')\n",
+ "## for sea water\n",
+ "E=2.34*10**9 ## N/m^2\n",
+ "rho=1000. ##kg/cm^2\n",
+ "a=math.sqrt(E/rho)\n",
+ "##result\n",
+ "print'%s %.2f %s'%(' \\n The speed of sound in sea waer is ',a,' m/s ')\n"
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "The speed of sound in air is 346.95 m/s \n",
+ " \n",
+ " The speed of sound in sea waer is 1529.71 m/s \n"
+ ]
+ }
+ ],
+ "prompt_number": 6
+ }
+ ],
+ "metadata": {}
+ }
+ ]
+} \ No newline at end of file