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| author | hardythe1 | 2015-06-17 11:14:34 +0530 |
|---|---|---|
| committer | hardythe1 | 2015-06-17 11:14:34 +0530 |
| commit | 37d315828bbfc0f5cabee669d2b9dd8cd17b5154 (patch) | |
| tree | 18b9d2929b329e112462bca900e9ae25c4c03006 /sample_notebooks/nemichand /Chapter1_1.ipynb | |
| parent | 79c59acc7af08ede23167b8455de4b716f77601f (diff) | |
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diff --git a/sample_notebooks/nemichand /Chapter1_1.ipynb b/sample_notebooks/nemichand /Chapter1_1.ipynb new file mode 100755 index 00000000..43f5bce4 --- /dev/null +++ b/sample_notebooks/nemichand /Chapter1_1.ipynb @@ -0,0 +1,227 @@ +{
+ "metadata": {
+ "name": "",
+ "signature": "sha256:60b1203d60983bbbb28528cd720bc31b7ac71ec9fc83b7d2e5e78e90b9f2b472"
+ },
+ "nbformat": 3,
+ "nbformat_minor": 0,
+ "worksheets": [
+ {
+ "cells": [
+ {
+ "cell_type": "heading",
+ "level": 1,
+ "metadata": {},
+ "source": [
+ "Chapter1-Introduction"
+ ]
+ },
+ {
+ "cell_type": "heading",
+ "level": 2,
+ "metadata": {},
+ "source": [
+ "Ex1-pg32"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "\n",
+ "import math\n",
+ "\n",
+ "#calculate the steady state\n",
+ "\n",
+ "\n",
+ "##The thickness of the slab(L) is 80mm or .08m\n",
+ "##The thermal conductivity(k)of the material is .20 W/(m*K)\n",
+ "T1=40.;\n",
+ "T2=20.;\n",
+ "L=.08;\n",
+ "k=.20;\n",
+ "##The steady state heat transfer rate per unit area through the thick slab is given by q=k(T1-T2)/L\n",
+ "print(\"The steady state heat transfer rate per unit area through the thick slab is given by q=k(T1-T2)/L in W/m^2 \")\n",
+ "q=k*(T1-T2)/L\n",
+ "print(q)"
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "The steady state heat transfer rate per unit area through the thick slab is given by q=k(T1-T2)/L in W/m^2 \n",
+ "50.0\n"
+ ]
+ }
+ ],
+ "prompt_number": 1
+ },
+ {
+ "cell_type": "heading",
+ "level": 2,
+ "metadata": {},
+ "source": [
+ "Ex2-pg32"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "\n",
+ "import math\n",
+ "#calculate the thickness of masonry wall\n",
+ "print(\"Introduction to heat transfer by S.K.Som, Chapter 1, Example 2\")\n",
+ "##The thermal conductivity(km)of masonry wall is .8 W/(mK)\n",
+ "##The thermal conductivity(kc)of composite wall is .2 W/(mK)\n",
+ "##The thickness of composite wall(Lc) is 100 mm or .1 m\n",
+ "km=.8;\n",
+ "kc=.2;\n",
+ "Lc=.1;\n",
+ "##The thickness of masonry wall(Lm) is to be found. \n",
+ "##The steady state heat flow(qm)through masonry wall is km(T1-T2)/L\n",
+ "## The steady state heat flow(qc)through composite wall is kc(T1-T2)/L\n",
+ "##As the steady rate of heat flow through masonry wall is 80% that through composite wall and both the wall have same surface area and same temp. difference so qm/qc=0.8=(km/kc)*(Lc/Lm)\n",
+ "##The thickness of masonry wall is Lm.\n",
+ "print (\"The thickness of masonry wall is Lm in m\")\n",
+ "Lm=(km/kc)*(Lc/(0.8))\n",
+ "print(Lm)"
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "Introduction to heat transfer by S.K.Som, Chapter 1, Example 2\n",
+ "The thickness of masonry wall is Lm in m\n",
+ "0.5\n"
+ ]
+ }
+ ],
+ "prompt_number": 3
+ },
+ {
+ "cell_type": "heading",
+ "level": 2,
+ "metadata": {},
+ "source": [
+ "Ex4-pg36"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "\n",
+ "## printlay warning for floating point exception\n",
+ "print(\"Introduction to heat transfer by S.K.Som Chapter 1 Example 4\")\n",
+ "hbr=200.;\n",
+ "Tinf=100.;\n",
+ "Ts=20.;\n",
+ "##The rate of heat transfer per unit area is q\n",
+ "print (\"The rate of heat transfer per unit area q=hbr*(Tinf-Ts) in W/m^2\")\n",
+ "q=hbr*(Tinf-Ts)\n",
+ "print(q)"
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "Introduction to heat transfer by S.K.Som Chapter 1 Example 4\n",
+ "The rate of heat transfer per unit area q=hbr*(Tinf-Ts) in W/m^2\n",
+ "16000.0\n"
+ ]
+ }
+ ],
+ "prompt_number": 5
+ },
+ {
+ "cell_type": "heading",
+ "level": 2,
+ "metadata": {},
+ "source": [
+ "Ex5-pg36"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "\n",
+ "import math\n",
+ "#calculat e surface area\n",
+ "print(\"Introduction to heat transfer by S.K.Som, Chapter 1, Example 5\")\n",
+ "\n",
+ "hbr=800.;\n",
+ "deltaT=(75.-25.);\n",
+ "Q=20.;\n",
+ "print(\"The heat exchanger surface area(A)in m^2 required for 20 MJ/h of heating is \")\n",
+ "A = (Q*10**6.)/(3600.*hbr*deltaT)\n",
+ "print round(A,2)"
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "Introduction to heat transfer by S.K.Som, Chapter 1, Example 5\n",
+ "The heat exchanger surface area(A)in m^2 required for 20 MJ/h of heating is \n",
+ "0.14\n"
+ ]
+ }
+ ],
+ "prompt_number": 6
+ },
+ {
+ "cell_type": "heading",
+ "level": 2,
+ "metadata": {},
+ "source": [
+ "Ex6-pg37"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "##The ambient temprature (Tinf) \n",
+ "print(\"Introduction to heat transfer by S.K.Som, Chapter 1, Example 6\")\n",
+ "Ts=225.;\n",
+ "Tinf=25.;\n",
+ "## |because it is modulus function and it converts negative values to positive value.\n",
+ "X=0.02;\n",
+ "A=.1;\n",
+ "m=4;\n",
+ "cp=2.8;\n",
+ "hbr=(m*cp*10**3*X)/(A*(Ts-Tinf))\n",
+ "print round(hbr,2)"
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "Introduction to heat transfer by S.K.Som, Chapter 1, Example 6\n",
+ "11.2\n"
+ ]
+ }
+ ],
+ "prompt_number": 8
+ }
+ ],
+ "metadata": {}
+ }
+ ]
+}
\ No newline at end of file |