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+{
+ "metadata": {
+  "name": ""
+ },
+ "nbformat": 3,
+ "nbformat_minor": 0,
+ "worksheets": [
+  {
+   "cells": [
+    {
+     "cell_type": "heading",
+     "level": 1,
+     "metadata": {},
+     "source": [
+      "Chapter 1: Tension Comprssion and Shear"
+     ]
+    },
+    {
+     "cell_type": "heading",
+     "level": 2,
+     "metadata": {},
+     "source": [
+      "Example 1.1, page no. 9"
+     ]
+    },
+    {
+     "cell_type": "code",
+     "collapsed": false,
+     "input": [
+      "\"\"\"\n",
+      "Find compressive stress and strain in the post\n",
+      "\"\"\"\n",
+      "\n",
+      "import math\n",
+      "\n",
+      "#initialisation\n",
+      "\n",
+      "d_1 = 4                 # inner diameter (inch)\n",
+      "d_2 = 4.5               #outer diameter (inch)\n",
+      "P = 26000               # pressure in pound\n",
+      "L = 16                  # Length of cylinder (inch)\n",
+      "my_del = 0.012             # shortening of post (inch)\n",
+      "\n",
+      "#calculation\n",
+      "A = (math.pi/4)*((d_2**2)-(d_1**2))     #Area (inch^2)\n",
+      "s = P/A                                 # stress\n",
+      "\n",
+      "print \"compressive stress in the post is \", round(s), \"psi\"\n",
+      "\n",
+      "e = my_del/L                            # strain\n",
+      "\n",
+      "print \"compressive strain in the post is %e\" %e"
+     ],
+     "language": "python",
+     "metadata": {},
+     "outputs": [
+      {
+       "output_type": "stream",
+       "stream": "stdout",
+       "text": [
+        "compressive stress in the post is  7789.0 psi\n",
+        "compressive strain in the post is 7.500000e-04\n"
+       ]
+      }
+     ],
+     "prompt_number": 5
+    },
+    {
+     "cell_type": "heading",
+     "level": 2,
+     "metadata": {},
+     "source": [
+      "Example 1.2, page no. 10"
+     ]
+    },
+    {
+     "cell_type": "code",
+     "collapsed": false,
+     "input": [
+      "\"\"\"\n",
+      "formula for maximum stress & calculating maximum stress\n",
+      "\"\"\"\n",
+      "\n",
+      "import math \n",
+      "\n",
+      "#initialisation\n",
+      "W = 1500                    # weight (Newton)\n",
+      "d = 0.008                   #diameter(meter) \n",
+      "g = 77000                   # Weight density of steel\n",
+      "L = 40                      # Length of bar (m)\n",
+      "\n",
+      "#calculation\n",
+      "\n",
+      "A = (math.pi/4)*(d**2)      # Area\n",
+      "s_max = (1500/A) + (g*L)    # maximum stress\n",
+      "\n",
+      "#result\n",
+      "print \"Therefore the maximum stress in the rod is \", round(s_max,1), \"Pa\""
+     ],
+     "language": "python",
+     "metadata": {},
+     "outputs": [
+      {
+       "output_type": "stream",
+       "stream": "stdout",
+       "text": [
+        "Therefore the maximum stress in the rod is  32921551.8 Pa\n"
+       ]
+      }
+     ],
+     "prompt_number": 16
+    },
+    {
+     "cell_type": "heading",
+     "level": 2,
+     "metadata": {},
+     "source": [
+      "Example 1.3. page no. 26"
+     ]
+    },
+    {
+     "cell_type": "code",
+     "collapsed": false,
+     "input": [
+      "\"\"\"\n",
+      "calculating change in lenght of pipe, strain in pipe, increase in diameter & increase in wall thickness\n",
+      "\"\"\"\n",
+      "\n",
+      "import math \n",
+      "\n",
+      "#initialisation\n",
+      "d1 = 4.5                            # diameter in inch\n",
+      "d2 = 6                              # diameter in inch\n",
+      "A = (math.pi/4)*((d2**2)-(d1**2))   # Area\n",
+      "P = 140                             # pressure in K\n",
+      "s = -P/A                            # stress (compression)\n",
+      "E = 30000                           # young's modulus in Ksi\n",
+      "e = s/E                             # strain\n",
+      "\n",
+      "#calculation\n",
+      "\n",
+      "# Part (a)\n",
+      "my_del = e*4*12                        # del = e*L \n",
+      "print \"Change in length of the pipe is\", round(my_del,3), \"inch\"\n",
+      "\n",
+      "# Part (b)\n",
+      "v = 0.30                            # Poissio's ratio\n",
+      "e_ = -(v*e)\n",
+      "print \"Lateral strain in the pipe is %e\" %e_\n",
+      "\n",
+      "# Part (c)\n",
+      "del_d2 = e_*d2 \n",
+      "del_d1 = e_*d1\n",
+      "print \"Increase in the inner diameter is \", round(del_d1,6), \"inch\"\n",
+      "\n",
+      "# Part (d)\n",
+      "t = 0.75\n",
+      "del_t = e_*t\n",
+      "print \"Increase in the wall thicness is %f\" %del_t, \"inch\"\n",
+      "del_t1 = (del_d2-del_d1)/2 \n",
+      "print \"del_t1 = del_t\""
+     ],
+     "language": "python",
+     "metadata": {},
+     "outputs": [
+      {
+       "output_type": "stream",
+       "stream": "stdout",
+       "text": [
+        "Change in length of the pipe is -0.018 inch\n",
+        "Lateral strain in the pipe is 1.131768e-04\n",
+        "Increase in the inner diameter is  0.000509 inch\n",
+        "Increase in the wall thicness is 0.000085 inch\n",
+        "del_t1 = del_t\n"
+       ]
+      }
+     ],
+     "prompt_number": 7
+    },
+    {
+     "cell_type": "heading",
+     "level": 2,
+     "metadata": {},
+     "source": [
+      "Example 1.4, page no. 35"
+     ]
+    },
+    {
+     "cell_type": "code",
+     "collapsed": false,
+     "input": [
+      "\"\"\"\n",
+      "calculate average shear stress and compressive stress\n",
+      "\"\"\"\n",
+      "\n",
+      "import math \n",
+      "\n",
+      "#initialisation\n",
+      "d = 0.02                            # diameter in m\n",
+      "t = 0.008                           # thickness in m\n",
+      "A = math.pi*d*t                     # shear area\n",
+      "P = 110000                          # prassure in Newton\n",
+      "\n",
+      "#calculation\n",
+      "A1 = (math.pi/4)*(d**2)             # Punch area\n",
+      "t_aver = P/A                        # Average shear stress \n",
+      "\n",
+      "\n",
+      "print \"Average shear stress in the plate is \", t_aver, \"Pa\"\n",
+      "s_c = P/A1  # compressive stress\n",
+      "print \"Average compressive stress in the plate is \", s_c, \"Pa\""
+     ],
+     "language": "python",
+     "metadata": {},
+     "outputs": [
+      {
+       "output_type": "stream",
+       "stream": "stdout",
+       "text": [
+        "Average shear stress in the plate is  218838046.751 Pa\n",
+        "Average compressive stress in the plate is  350140874.802 Pa\n"
+       ]
+      }
+     ],
+     "prompt_number": 37
+    },
+    {
+     "cell_type": "heading",
+     "level": 2,
+     "metadata": {},
+     "source": [
+      "Eample 1.5, page no. 36"
+     ]
+    },
+    {
+     "cell_type": "code",
+     "collapsed": false,
+     "input": [
+      "\"\"\"\n",
+      "calculate bearing stress, shear stress in pin,\n",
+      "bearing stress between pin and gussets,\n",
+      "shear stress in anchor bolts\n",
+      "\"\"\"\n",
+      "\n",
+      "import math \n",
+      "\n",
+      "#initialisation\n",
+      "\n",
+      "P = 12.0                              # Pressure in K\n",
+      "t = 0.375                           # thickness of wall in inch\n",
+      "theta = 40.0                          # angle in degree\n",
+      "d_pin = 0.75                        # diameter of pin in inch\n",
+      "t_G = 0.625                         # thickness of gusset in inch\n",
+      "t_B = 0.375                         #thickness of base plate in inch\n",
+      "d_b = 0.50                          # diameter of bolt in inch\n",
+      "\n",
+      "#calculation\n",
+      "\n",
+      "#Part (a)\n",
+      "s_b1 = P/(2*t*d_pin)                  # bearing stress\n",
+      "print \"Bearing stress between strut and pin\", round(s_b1,1), \"ksi\"\n",
+      "\n",
+      "#Part (b)\n",
+      "t_pin = (4*P)/(2*math.pi*(d_pin**2))  # average shear stress in the \n",
+      "print \"Shear stress in pin is \", round(t_pin,1), \"ksi\"\n",
+      "\n",
+      "# Part (c)\n",
+      "s_b2 = P/(2*t_G*d_pin)                # bearing stress between pin and gusset\n",
+      "print \"Bearing stress between pin and gussets is\", s_b2, \"ksi\"\n",
+      "\n",
+      "# Part (d)\n",
+      "s_b3 = (P*math.cos(math.radians(40))/(4*t_B*d_b)) # bearing stress between anchor bolt and base plate\n",
+      "print \"Bearing stress between anchor bolts & base plate\", round(s_b3,1), \"ksi\"\n",
+      "\n",
+      "# Part (e)\n",
+      "t_bolt = (4*math.cos(math.radians(40))*P)/(4*math.pi*(d_b**2))  # shear stress in anchor bolt\n",
+      "print \"Shear stress in anchor bolts is\", round(t_bolt,1), \"ksi\""
+     ],
+     "language": "python",
+     "metadata": {},
+     "outputs": [
+      {
+       "output_type": "stream",
+       "stream": "stdout",
+       "text": [
+        "Bearing stress between strut and pin 21.3 ksi\n",
+        "Shear stress in pin is  13.6 ksi\n",
+        "Bearing stress between pin and gussets is 12.8 ksi\n",
+        "Bearing stress between anchor bolts & base plate 12.3 ksi\n",
+        "Shear stress in anchor bolts is 11.7 ksi\n"
+       ]
+      }
+     ],
+     "prompt_number": 39
+    },
+    {
+     "cell_type": "heading",
+     "level": 2,
+     "metadata": {},
+     "source": [
+      "Example 1.7, page no. 42"
+     ]
+    },
+    {
+     "cell_type": "code",
+     "collapsed": false,
+     "input": [
+      "\"\"\"\n",
+      "determine stress at various parts\n",
+      "\"\"\"\n",
+      "\n",
+      "import math\n",
+      "\n",
+      "#initialisation\n",
+      "b1 = 1.5                            # width of recmath.tangular crosssection in inch\n",
+      "t = 0.5                             # thickness of recmath.tangular crosssection in inch\n",
+      "b2 = 3.0                            # width  of enlarged recmath.tangular crosssection in inch\n",
+      "d = 1.0                             # diameter in inch\n",
+      "\n",
+      "#calculation\n",
+      "\n",
+      "# Part (a)\n",
+      "s_1 = 16000 # maximum allowable tensile stress in Psi\n",
+      "P_1 = s_1*t*b1 \n",
+      "print \"The allowable load  P1 is\", P_1, \"lb\"\n",
+      "\n",
+      "# Part (b)\n",
+      "s_2 = 11000 # maximum allowable tensile stress in Psi\n",
+      "P_2 = s_2*t*(b2-d) \n",
+      "print \"allowable load P2 at this section is\", P_2, \"lb\"\n",
+      "\n",
+      "#Part (c)\n",
+      "s_3 = 26000 # maximum allowable tensile stress in Psi\n",
+      "P_3 = s_3*t*d \n",
+      "print \"The allowable load based upon bearing between the hanger and the bolt is\", P_3, \"lb\"\n",
+      "\n",
+      "# Part (d)\n",
+      "s_4 = 6500 # maximum allowable tensile stress in Psi\n",
+      "P_4 = (math.pi/4)*(d**2)*2*s_4 \n",
+      "print \"the allowable load  P4 based upon shear in the bolt is\", round(P_4), \"lb\"\n"
+     ],
+     "language": "python",
+     "metadata": {},
+     "outputs": [
+      {
+       "output_type": "stream",
+       "stream": "stdout",
+       "text": [
+        "The allowable load  P1 is 12000.0 lb\n",
+        "allowable load P2 at this section is 11000.0 lb\n",
+        "The allowable load based upon bearing between the hanger and the bolt is 13000.0 lb\n",
+        "the allowable load  P4 based upon shear in the bolt is 10210.0 lb\n"
+       ]
+      }
+     ],
+     "prompt_number": 42
+    },
+    {
+     "cell_type": "heading",
+     "level": 2,
+     "metadata": {},
+     "source": [
+      "Example 1.8, page no. 46"
+     ]
+    },
+    {
+     "cell_type": "code",
+     "collapsed": false,
+     "input": [
+      "\"\"\"\n",
+      "calculating the cross sectional area \n",
+      "\"\"\"\n",
+      "\n",
+      "import math \n",
+      "\n",
+      "#initialisation\n",
+      "R_ah = (2700*0.8 + 2700*2.6)/2                  # Horizontal component at A in N\n",
+      "R_ch = R_ah                                     # Horizontal component at C in N\n",
+      "R_cv = (2700*2.2 + 2700*0.4)/3                  # vertical component at C in N\n",
+      "R_av = 2700 + 2700 - R_cv                       # vertical component at A in N\n",
+      "R_a = math.sqrt((R_ah**2)+(R_av**2))\n",
+      "R_c = math.sqrt((R_ch**2)+(R_cv**2))\n",
+      "Fab = R_a                                       # Tensile force in bar AB\n",
+      "Vc = R_c                                        # Shear force acting on the pin at C\n",
+      "s_allow = 125000000                             # allowable stress in tension \n",
+      "t_allow = 45000000                              # allowable stress in shear\n",
+      "\n",
+      "#calculation\n",
+      "Aab = Fab / s_allow                             # required area of bar \n",
+      "Apin = Vc / (2*t_allow)                         # required area of pin\n",
+      "\n",
+      "\n",
+      "print \"Required area of bar is %f\" %Apin, \"m^2\"\n",
+      "d = math.sqrt((4*Apin)/math.pi)                 # diameter in meter\n",
+      "print \"Required diameter of pin is %f\" %d, \"m\""
+     ],
+     "language": "python",
+     "metadata": {},
+     "outputs": [
+      {
+       "output_type": "stream",
+       "stream": "stdout",
+       "text": [
+        "Required area of bar is 0.000057 m^2\n",
+        "Required diameter of pin is 0.008537 m\n"
+       ]
+      }
+     ],
+     "prompt_number": 9
+    },
+    {
+     "cell_type": "code",
+     "collapsed": false,
+     "input": [],
+     "language": "python",
+     "metadata": {},
+     "outputs": []
+    }
+   ],
+   "metadata": {}
+  }
+ ]
+}
\ No newline at end of file