Added(A)/Deleted(D) following books

 A  1000_solved_Problems_in_Fluid_Mechanics_includes_Hydraulic_machines_by_K.Subramanya/README.txt
A  Fundamentals_Of_Aerodynamics_by_J._D._Anderson_Jr./README.txt
A  Introductory_Methods_Of_Numerical_Analysis__by_S._S._Sastry/README.txt
A  SURVYNG_AND_LEVELLING__by_N.N.BASAK/README.txt
A  sample_notebooks/Harshitgarg/Chapter_1-INTRODUCTION_TO_MECHANICS_OF_SOLIDS__2.ipynb
A  "sample_notebooks/KARTHIKEYAN S/CHAPTER_1.ipynb"
A  sample_notebooks/NityaL/Sample-Chapter_26.ipynb

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+{
+ "cells": [
+  {
+   "cell_type": "markdown",
+   "metadata": {},
+   "source": [
+    "# Chapter 26:CHARGE AND MATTER"
+   ]
+  },
+  {
+   "cell_type": "markdown",
+   "metadata": {
+    "collapsed": true
+   },
+   "source": [
+    "# Example 26.1 Magnitude of total charges in a copper penny"
+   ]
+  },
+  {
+   "cell_type": "code",
+   "execution_count": 5,
+   "metadata": {
+    "collapsed": false
+   },
+   "outputs": [
+    {
+     "name": "stdout",
+     "output_type": "stream",
+     "text": [
+      " Magnitude of the charges in coulombs is  133687.50000000003\n"
+     ]
+    }
+   ],
+   "source": [
+    "#Example 1.1\n",
+    "\n",
+    "m =3.1 #mass of copper penny in grams\n",
+    "e =4.6*10** -18 #charge in coulombs\n",
+    "N0 =6*10**23 #avogadro’s number atoms / mole\n",
+    "M =64  #molecular weight of copper in gm/ mole\n",
+    "\n",
+    "#Calculation\n",
+    "N =( N0 * m ) / M  #No. of copper atoms in penny\n",
+    "q = N * e  # magnitude of the charges in coulombs\n",
+    "print (\" Magnitude of the charges in coulomb is \",q )"
+   ]
+  },
+  {
+   "cell_type": "markdown",
+   "metadata": {
+    "collapsed": true
+   },
+   "source": [
+    "# Example 26.2 Separation between total positive and negative charges"
+   ]
+  },
+  {
+   "cell_type": "code",
+   "execution_count": 1,
+   "metadata": {
+    "collapsed": false
+   },
+   "outputs": [
+    {
+     "name": "stdout",
+     "output_type": "stream",
+     "text": [
+      " Separation between total positive and negative charges in meters is  5813776741.499454\n"
+     ]
+    }
+   ],
+   "source": [
+    "#Example 2\n",
+    "\n",
+    "import math\n",
+    "\n",
+    "F =4.5 #Force of attraction in nt\n",
+    "q =1.3*10**5 #total charge in coulomb\n",
+    "r = q * math.sqrt ((9*10**9) / F ) ;\n",
+    "print(\" Separation between total positive and negative charges in meters is \",r )"
+   ]
+  },
+  {
+   "cell_type": "markdown",
+   "metadata": {
+    "collapsed": true
+   },
+   "source": [
+    "# Example 26.3 Force acting on charge q1"
+   ]
+  },
+  {
+   "cell_type": "code",
+   "execution_count": 8,
+   "metadata": {
+    "collapsed": false
+   },
+   "outputs": [
+    {
+     "name": "stdout",
+     "output_type": "stream",
+     "text": [
+      "X component of resultant force acting on q1 in nt is 2.0999999999999996\n",
+      "Y component of resultant force acting on q1 in nt is -1.5588457268119893\n"
+     ]
+    }
+   ],
+   "source": [
+    "#Example 3\n",
+    "\n",
+    "import math\n",
+    "\n",
+    "#given three charges q1,q2,q3\n",
+    "q1=-1.0*10**-6 #charge in coul\n",
+    "q2=+3.0*10**-6 #charge in coul\n",
+    "q3=-2.0*10**-6 #charge in coul\n",
+    "r12=15*10**-2 #separation between q1 and q2 in m\n",
+    "r13=10*10**-2 # separation between q1 and q3 in m\n",
+    "angle=math.pi/6 #in degrees\n",
+    "F12=(9.0*10**9)*q1*q2/(r12**2) #in nt\n",
+    "F13=(9.0*10**9)*q1*q3/(r13**2) #in nt\n",
+    "F12x=-F12  #ignoring signs of charges\n",
+    "F13x=F13*math.sin(angle);\n",
+    "F1x=F12x+F13x\n",
+    "F12y=0 #from fig.263\n",
+    "F13y=-F13*math.cos(angle);\n",
+    "F1y=F12y+F13y #in nt\n",
+    "print(\"X component of resultant force acting on q1 in nt is\",F1x)\n",
+    "print(\"Y component of resultant force acting on q1 in nt is\",F1y)"
+   ]
+  },
+  {
+   "cell_type": "markdown",
+   "metadata": {
+    "collapsed": true
+   },
+   "source": [
+    "# Example 26.4 Electrical and Gravitational force between two particles"
+   ]
+  },
+  {
+   "cell_type": "code",
+   "execution_count": 9,
+   "metadata": {
+    "collapsed": false
+   },
+   "outputs": [
+    {
+     "name": "stdout",
+     "output_type": "stream",
+     "text": [
+      "Coulomb force in nt is 8.202207191171238e-08\n",
+      "Gravitational force in nt is 3.689889640441438e-47\n"
+     ]
+    }
+   ],
+   "source": [
+    "#Example 4\n",
+    "\n",
+    "r=5.3*10**-11 #distance between electron and proton in the hydrogen atom in meter\n",
+    "e=1.6*10**-19 #charge in coul\n",
+    "G=6.7*10**-11 #gravitatinal constant in nt-m2/kg2\n",
+    "m1=9.1*10**-31 #mass of electron in kg\n",
+    "m2=1.7*10**-27 #mass of proton in kg\n",
+    "F1=(9*10**9)*e*e/(r**2) #coulomb's law\n",
+    "F2=G*m1*m2/(r**2) #gravitational force\n",
+    "print(\"Coulomb force in nt is\",F1)\n",
+    "print(\"Gravitational force in nt is\",F2)"
+   ]
+  },
+  {
+   "cell_type": "markdown",
+   "metadata": {
+    "collapsed": true
+   },
+   "source": [
+    "# Example 26.5 Repulsive force between two protons in a nucleus of iron"
+   ]
+  },
+  {
+   "cell_type": "code",
+   "execution_count": 2,
+   "metadata": {
+    "collapsed": false
+   },
+   "outputs": [
+    {
+     "name": "stdout",
+     "output_type": "stream",
+     "text": [
+      "Repulsive coulomb force F  14.4 nt\n"
+     ]
+    }
+   ],
+   "source": [
+    "#Example 5\n",
+    "\n",
+    "r=4*10**-15 #separation between proton annd nucleus in iron in meters\n",
+    "q=1.6*10**-19 #charge in coul\n",
+    "F=(9*10**9)*(q**2)/(r**2) #coulomb's law\n",
+    "print(\"Repulsive coulomb force F \",F,'nt')"
+   ]
+  }
+ ],
+ "metadata": {
+  "kernelspec": {
+   "display_name": "Python [Root]",
+   "language": "python",
+   "name": "Python [Root]"
+  },
+  "language_info": {
+   "codemirror_mode": {
+    "name": "ipython",
+    "version": 2
+   },
+   "file_extension": ".py",
+   "mimetype": "text/x-python",
+   "name": "python",
+   "nbconvert_exporter": "python",
+   "pygments_lexer": "ipython2",
+   "version": "2.7.12"
+  }
+ },
+ "nbformat": 4,
+ "nbformat_minor": 0
+}