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author | Thomas Stephen Lee | 2015-08-28 16:53:23 +0530 |
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committer | Thomas Stephen Lee | 2015-08-28 16:53:23 +0530 |
commit | 4a1f703f1c1808d390ebf80e80659fe161f69fab (patch) | |
tree | 31b43ae8895599f2d13cf19395d84164463615d9 /sample_notebooks/JayDadlani/SAMPLE_NB_KI_KAPOOR.ipynb | |
parent | 9d260e6fae7328d816a514130b691fbd0e9ef81d (diff) | |
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diff --git a/sample_notebooks/JayDadlani/SAMPLE_NB_KI_KAPOOR.ipynb b/sample_notebooks/JayDadlani/SAMPLE_NB_KI_KAPOOR.ipynb new file mode 100755 index 00000000..7ccc9697 --- /dev/null +++ b/sample_notebooks/JayDadlani/SAMPLE_NB_KI_KAPOOR.ipynb @@ -0,0 +1,220 @@ +{ + "metadata": { + "celltoolbar": "Raw Cell Format", + "name": "", + "signature": "sha256:58e66a1486b17622aacd34bb93b225c18134442ddc1f2fbedecd0abdd0c9b88e" + }, + "nbformat": 3, + "nbformat_minor": 0, + "worksheets": [ + { + "cells": [ + { + "cell_type": "heading", + "level": 1, + "metadata": {}, + "source": [ + "A TEXTBOOK OF PHYSICAL CHEMISTRY BY K.I. KAPOOR" + ] + }, + { + "cell_type": "heading", + "level": 1, + "metadata": {}, + "source": [ + "CHAPTER NUMBER 1 : EQUILIBRIUM BETWEEN PHASES" + ] + }, + { + "cell_type": "heading", + "level": 2, + "metadata": {}, + "source": [ + "EXAMPLE NUMBER 1.5.1 : PAGE NUMBER 10" + ] + }, + { + "cell_type": "code", + "collapsed": false, + "input": [ + "import math \n", + "T1 = 234.5 # Temperature in K\n", + "P = 1 # Pressure in atm\n", + "rho1 = 14.19 # Density of solid Hg in g/(cm**3)\n", + "rho2 = 13.70 # Density of liquid Hg in g/(cm**3)\n", + "V = 200.59 # volume of liquid and solid in g/mol\n", + "delV = ((V/rho2)-(V/rho1))*(10**-3)# in dm**3/mol\n", + "delTdelP = 0.0051 # K/atm\n", + "R1 = 8.314 # in J\n", + "R2 = 0.082 # in (dm)**3/atm\n", + "delH = ((delV*T1)/(delTdelP))*(R1/R2)*10**-3;#molar heat of fusion in kJ/mol\n", + "print \" delH = \",round(delH,4),\"(KJ)/mol \"\n", + "T2 = 273# in K\n", + "delP = (delH*(R2/R1)*(T2-T1))/(delV*T1)*10**3;#pressure required to raise melting point to T2 in atm\n", + "print \" delP = \",round(delP,4),\"atm\"" + ], + "language": "python", + "metadata": {}, + "outputs": [ + { + "output_type": "stream", + "stream": "stdout", + "text": [ + " delH = 2.3571 (KJ)/mol \n", + " delP = 7549.0196 atm\n" + ] + } + ], + "prompt_number": 3 + }, + { + "cell_type": "heading", + "level": 2, + "metadata": {}, + "source": [ + "EXAMPLE NUMBER 1.5.2 : PAGE NUMBER 15" + ] + }, + { + "cell_type": "code", + "collapsed": false, + "input": [ + "import math;\n", + "T1=373.15;#in K\n", + "P=1;#atm\n", + "Vv=1674;#in cm**3/gm\n", + "delPdelT=27.12;#in torr/K\n", + "R1=8.314;#in J\n", + "R2=0.082;#in atm/(dm)**3\n", + "delH=((delPdelT)/760)*T1*((Vv*10**-3)*18)*(R1/R2)\n", + "print \" delH = \",round(delH,4),\" J/mol \"" + ], + "language": "python", + "metadata": {}, + "outputs": [ + { + "output_type": "stream", + "stream": "stdout", + "text": [ + " delH = 40680.2549 J/mol \n" + ] + } + ], + "prompt_number": 5 + }, + { + "cell_type": "heading", + "level": 2, + "metadata": {}, + "source": [ + "EXAMPLE NUMBER 1.5.3 : PAGE NUMBER 16" + ] + }, + { + "cell_type": "code", + "collapsed": false, + "input": [ + "import math;\n", + "T1=313.75;#in K\n", + "P1=59.1;#in torr\n", + "T2=353.15;#in K\n", + "P2=298.7;#in torr\n", + "R=2.303*8.314;#in J/(K*mol)\n", + "delH=R*math.log10(P2/P1)*((T2*T1)/(T2-T1))\n", + "print \" delH= \",round(delH,4),\" J/mol \"" + ], + "language": "python", + "metadata": {}, + "outputs": [ + { + "output_type": "stream", + "stream": "stdout", + "text": [ + " delH= 37888.375 J/mol \n" + ] + } + ], + "prompt_number": 9 + }, + { + "cell_type": "heading", + "level": 2, + "metadata": {}, + "source": [ + "EXAMPLE NUMBER 1.5.4 : PAGE NUMBER 16" + ] + }, + { + "cell_type": "code", + "collapsed": false, + "input": [ + "import math\n", + "T1=325.15;#in K\n", + "T2=338.15;#in K\n", + "P2=760;#in torr\n", + "DelHm_v=10.5;#\n", + "P1=P2/(10**((DelHm_v/2.303)*((T2/T1)-1)));#in torr\n", + "print \" P1= \",round(P1,4),\"torr \"\n", + "P=200;#in torr\n", + "T=T2/(1+((2.303/10.5)*math.log10(P2/P)));#in K\n", + "print \" T =\",round(T,4),\" K \"\n", + "I=math.log10(P2)-(((DelHm_v*T2)/2.303)*(-1/T2));#\n", + "print \" I = \",round(I,4)" + ], + "language": "python", + "metadata": {}, + "outputs": [ + { + "output_type": "stream", + "stream": "stdout", + "text": [ + " P1= 499.4901 torr \n", + " T = 306.1154 K \n", + " I = 7.4401\n" + ] + } + ], + "prompt_number": 13 + }, + { + "cell_type": "heading", + "level": 2, + "metadata": {}, + "source": [ + "EXAMPLE NUMBER 1.5.5 : PAGE NUMBER 17" + ] + }, + { + "cell_type": "code", + "collapsed": false, + "input": [ + "import math;\n", + "P=760;#in torr\n", + "dP=52;#in torr\n", + "dT=2;#in K\n", + "DelH_RTb=10.5;#Trouton rule\n", + "Tb=(DelH_RTb*P)/(dP/dT)\n", + "print \" Tb = \",round(Tb,4),\" K\"\n", + "R=8.314;#in J/Kmol\n", + "DelH_v=(DelH_RTb*R*Tb)\n", + "print \" DelH_v = \",round(DelH_v,4),\"J/mol \"" + ], + "language": "python", + "metadata": {}, + "outputs": [ + { + "output_type": "stream", + "stream": "stdout", + "text": [ + " Tb = 306.9231 K\n", + " DelH_v = 26793.4638 J/mol \n" + ] + } + ], + "prompt_number": 16 + } + ], + "metadata": {} + } + ] +}
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