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authorTrupti Kini2016-06-09 23:30:30 +0600
committerTrupti Kini2016-06-09 23:30:30 +0600
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Added(A)/Deleted(D) following books
A sample_notebooks/Haseen/Chapter3.ipynb A sample_notebooks/MohdRizwan/Chapter2.ipynb
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+{
+ "cells": [
+ {
+ "cell_type": "markdown",
+ "metadata": {},
+ "source": [
+ "# Chapter 3 Elementry Operations in Algebra"
+ ]
+ },
+ {
+ "cell_type": "markdown",
+ "metadata": {},
+ "source": [
+ "## Example 3_5 pgno:33"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "execution_count": 1,
+ "metadata": {
+ "collapsed": false
+ },
+ "outputs": [
+ {
+ "name": "stdout",
+ "output_type": "stream",
+ "text": [
+ "3x**4/6x**6\n"
+ ]
+ }
+ ],
+ "source": [
+ "#3x**4/6x**6\n",
+ "\n",
+ "x=('x')#is polynomial function of degree zero poly(0,'x');#for this I assume it to be 1 for my convince poly(0,'a');poly(0,'x');\n",
+ "p1='3*x**4';\n",
+ "p2='6*x**6';\n",
+ "#p=p1/p2\n",
+ "print '3x**4/6x**6'"
+ ]
+ },
+ {
+ "cell_type": "markdown",
+ "metadata": {},
+ "source": [
+ "## Example 3_6 pgno:34"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "execution_count": 2,
+ "metadata": {
+ "collapsed": false
+ },
+ "outputs": [
+ {
+ "name": "stdout",
+ "output_type": "stream",
+ "text": [
+ "val=8*x/15\n"
+ ]
+ }
+ ],
+ "source": [
+ "#x/3 + x/5\n",
+ "\n",
+ "x=('x')#is polynomial function of degree zero poly(0,'x');#for this I assume it to be 1 for my convince poly(0,'a');poly(0,'x');poly(0,'x');\n",
+ "p1='x/3';\n",
+ "p2='x/5';\n",
+ "p=p1+p2;\n",
+ "q='8*x/15';\n",
+ "if(p==q):\n",
+ " print\"val=8*x/15 \\n\"\n",
+ "print\"val=8*x/15\""
+ ]
+ },
+ {
+ "cell_type": "markdown",
+ "metadata": {},
+ "source": [
+ "## Example 3_9 pgno:35"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "execution_count": 3,
+ "metadata": {
+ "collapsed": false
+ },
+ "outputs": [
+ {
+ "name": "stdout",
+ "output_type": "stream",
+ "text": [
+ "ans=\n",
+ "(a+b)/k 8 25 60\n"
+ ]
+ }
+ ],
+ "source": [
+ "#2a/15 + 5b/12\n",
+ "\n",
+ "\n",
+ "d=60#\"L.C.M of denominators\"\n",
+ "k=d;\n",
+ "a_coeff=60/15*2;\n",
+ "b_coeff=60/12*5;\n",
+ "print'ans='\n",
+ "print\"(a+b)/k\",a_coeff,b_coeff,k"
+ ]
+ },
+ {
+ "cell_type": "markdown",
+ "metadata": {},
+ "source": [
+ "## Example 3_10 pgno:35"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "execution_count": 4,
+ "metadata": {
+ "collapsed": false
+ },
+ "outputs": [
+ {
+ "name": "stdout",
+ "output_type": "stream",
+ "text": [
+ "ans=\n",
+ "(bx-ay)/a**2b**2 3 2 36\n"
+ ]
+ }
+ ],
+ "source": [
+ "#x/12a**2b - y/18ab**2\n",
+ "\n",
+ "k=36#lcm(d);#L.C.M of denominators\n",
+ "\n",
+ "#\"L.C.M of a**2*b and a*b**2 is a**2*b**2\"\n",
+ "x_coeff=36/12;\n",
+ "y_coeff=36/18;\n",
+ "print'ans='\n",
+ "print\"(bx-ay)/a**2b**2\",x_coeff,y_coeff,k"
+ ]
+ },
+ {
+ "cell_type": "markdown",
+ "metadata": {},
+ "source": [
+ "## Example 3_11 pgno:36"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "execution_count": 5,
+ "metadata": {
+ "collapsed": false
+ },
+ "outputs": [
+ {
+ "name": "stdout",
+ "output_type": "stream",
+ "text": [
+ "val=\n",
+ "/*x**2/y**2 2 3\n"
+ ]
+ }
+ ],
+ "source": [
+ "#4*x**3*y/(6*x*y**3)\n",
+ "\n",
+ "gcd_d=1#GCD of 4 and 6 is 2\n",
+ "m=4/gcd_d\n",
+ "n=6/gcd_d\n",
+ "x=1#is polynomial function of degree zero poly(0,'x');#for this I assume it to be 1 for my convincepoly(0,'x');\n",
+ "y=1#is polynomial function of degree zero poly(0,'x');#for this I assume it to be 1 for my convincepoly(0,'y');\n",
+ "p1=x**3;p2=x;p=p1/p2;\n",
+ "q1=y;q2=y**3;q=q1/q2;\n",
+ "#val=m/n*p*q \n",
+ "print'val='\n",
+ "print\"/*x**2/y**2\",m/2,n/2"
+ ]
+ },
+ {
+ "cell_type": "markdown",
+ "metadata": {},
+ "source": [
+ "## Example 3_12 pgno:36"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "execution_count": 6,
+ "metadata": {
+ "collapsed": false
+ },
+ "outputs": [
+ {
+ "name": "stdout",
+ "output_type": "stream",
+ "text": [
+ "val=\n",
+ "*x**2*y/a**3 0.285714285714\n"
+ ]
+ }
+ ],
+ "source": [
+ "#6*a*x**4*2*y**3/(14*x**2*y**2*3*a**4)\n",
+ "\n",
+ "\n",
+ "x=('x')#is polynomial function of degree zero poly(0,'x');#for this I assume it to be 1 for my convincepoly(0,'x');poly(0,'x');\n",
+ "y=('y')#is polynomial function of degree zero poly(0,'x');#for this I assume it to be 1 for my convincepoly(0,'x');poly(0,'y');\n",
+ "a=('a')#is polynomial function of degree zero poly(0,'x');#for this I assume it to be 1 for my convincepoly(0,'x');poly(0,'a');\n",
+ "num=6.*2./(14.*3.);\n",
+ "p1='x**4';p2='x**2';p='p1/p2';\n",
+ "q1='y**3';q2='y**2';q='q1/q2';\n",
+ "r1='a';r2='a**4';r='r1/r2';\n",
+ "#val=num*p*q*r\n",
+ "print'val='\n",
+ "print\"*x**2*y/a**3\",num"
+ ]
+ },
+ {
+ "cell_type": "markdown",
+ "metadata": {},
+ "source": [
+ "## Example 3_13 pgno:36"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "execution_count": 7,
+ "metadata": {
+ "collapsed": false
+ },
+ "outputs": [
+ {
+ "name": "stdout",
+ "output_type": "stream",
+ "text": [
+ "val=\n",
+ "*x/(a*y) 1.2\n"
+ ]
+ }
+ ],
+ "source": [
+ "#(8x**3)/(5a**2y) *(3a)/(4x**2)\n",
+ "\n",
+ "\n",
+ "x=('x')#is polynomial function of degree zero poly(0,'x');#for this I assume it to be 1 for my convincepoly(0,'x');poly(0,'x');\n",
+ "y=('y')#is polynomial function of degree zero poly(0,'x');#for this I assume it to be 1 for my convincepoly(0,'x');poly(0,'y');\n",
+ "a=('a')#is polynomial function of degree zero poly(0,'x');#for this I assume it to be 1 for my convincepoly(0,'x');poly(0,'a');\n",
+ "p1='x**3';p2='x**2';p='p1/p2';\n",
+ "q='1/y';\n",
+ "r1='a';r2='a**2';r='r1/r2';\n",
+ "num=8.*3./(5.*4.);\n",
+ "#val=num*p*q*r\n",
+ "print('val=')\n",
+ "print\"*x/(a*y)\",num"
+ ]
+ }
+ ],
+ "metadata": {
+ "kernelspec": {
+ "display_name": "Python 2",
+ "language": "python",
+ "name": "python2"
+ },
+ "language_info": {
+ "codemirror_mode": {
+ "name": "ipython",
+ "version": 2
+ },
+ "file_extension": ".py",
+ "mimetype": "text/x-python",
+ "name": "python",
+ "nbconvert_exporter": "python",
+ "pygments_lexer": "ipython2",
+ "version": "2.7.9"
+ }
+ },
+ "nbformat": 4,
+ "nbformat_minor": 0
+}