Added(A)/Deleted(D) following books

 A  sample_notebooks/AviralYadav/Chapter1.ipynb
A  sample_notebooks/ChandraShiva/CHAPTER1.ipynb
A  sample_notebooks/VidyaSri/CHAPTER01.ipynb
A  testing_by_test/screenshots/screenshot6.png
A  testing_by_test/screenshots/screenshot6_1.png
A  testing_by_test/screenshots/screenshot6_2.png
A  testing_by_test/screenshots/screenshot6_3.png
A  testing_by_test/screenshots/screenshot6_4.png
A  testing_by_test/screenshots/screenshot6_5.png
A  testing_by_test/vivek.ipynb
A  testing_by_test/vivek_1.ipynb

1 files changed, 297 insertions, 0 deletions

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+{

+ "metadata": {

+  "name": "",

+  "signature": "sha256:a93d445dad4ffd499630570fa7ced24b4b25ee06fcd5352ae47d0eb721a47db5"

+ },

+ "nbformat": 3,

+ "nbformat_minor": 0,

+ "worksheets": [

+  {

+   "cells": [

+    {

+     "cell_type": "heading",

+     "level": 1,

+     "metadata": {},

+     "source": [

+      "CHAPTER1 : WHAT MACHINES AND TRANSFORMERS HAVE IN COMMON"

+     ]

+    },

+    {

+     "cell_type": "heading",

+     "level": 2,

+     "metadata": {},

+     "source": [

+      "Example E01 : Pg 16"

+     ]

+    },

+    {

+     "cell_type": "code",

+     "collapsed": false,

+     "input": [

+      "from math import sqrt\n",

+      "horsepower=2.5  # rating of induction motor in horsepower at half load\n",

+      "Vl=230. # terminal voltage of motor in volts\n",

+      "Il=7.   # load current of motor in amperes\n",

+      "pf=0.8 # power factor of the machine\n",

+      "Pin=sqrt(3.)*Vl*Il*pf # input power in watts\n",

+      "print\"Pin=\",Pin,\"W\"# The answer may vary due to roundoff error\n",

+      "Whp=746. # watts per hp\n",

+      "Pout=horsepower*Whp # output power in watts\n",

+      "print\"Pout=\",Pout,\"W\"\n",

+      "print\"n=\",Pout/Pin# The answer may vary due to roundoff error # efficiency of the machine\n",

+      "print\"Losses=Pin-Pout=\",Pin-Pout,\"W\"# The answer may vary due to roundoff error # losses in the machine in watts"

+     ],

+     "language": "python",

+     "metadata": {},

+     "outputs": [

+      {

+       "output_type": "stream",

+       "stream": "stdout",

+       "text": [

+        "Pin= 2230.88144015 W\n",

+        "Pout= 1865.0 W\n",

+        "n= 0.835992431707\n",

+        "Losses=Pin-Pout= 365.881440149 W\n"

+       ]

+      }

+     ],

+     "prompt_number": 1

+    },

+    {

+     "cell_type": "heading",

+     "level": 2,

+     "metadata": {},

+     "source": [

+      "Example E02 : Pg 17"

+     ]

+    },

+    {

+     "cell_type": "code",

+     "collapsed": false,

+     "input": [

+      "# the below exmaple is an extension of Ex1_1.sce\n",

+      "from math import sqrt \n",

+      "Vl=230. # terminal voltage of machine in volts\n",

+      "Il=7. # current drawn by machine in amperes\n",

+      "pf=0.8 # power factor of machine\n",

+      "Pin=sqrt(3.)*Vl*Il*pf # from Ex1_1 # input power in watts\n",

+      "Losses=365. # in watts\n",

+      "Pout=Pin-Losses # output power in watts\n",

+      "Whp=746. # watts per hp\n",

+      "print\"n=1-(Losses/Input)=\",1.-(Losses/Pin) # The answer may vary due to roundoff error # efficiency of the machine\n",

+      "print\"Pout=\",Pout,\"W\"# The answer may vary due to roundoff error\n",

+      "print\"Pout=\",Pout/Whp,\"hp\"# The asnwer may vary due to roundoff error # output power in horsepower"

+     ],

+     "language": "python",

+     "metadata": {},

+     "outputs": [

+      {

+       "output_type": "stream",

+       "stream": "stdout",

+       "text": [

+        "n=1-(Losses/Input)= 0.836387540175\n",

+        "Pout= 1865.88144015 W\n",

+        "Pout= 2.50118155516 hp\n"

+       ]

+      }

+     ],

+     "prompt_number": 2

+    },

+    {

+     "cell_type": "heading",

+     "level": 2,

+     "metadata": {},

+     "source": [

+      "Example E03 : Pg 17"

+     ]

+    },

+    {

+     "cell_type": "code",

+     "collapsed": false,

+     "input": [

+      "from math import sqrt,pi \n",

+      "f=60. # frequency of voltage source in Hz\n",

+      "x=1.9 # Steinmetz coefficient\n",

+      "V=80. # applied sinusoidal voltage in volts\n",

+      "t=100. # no of turns wound on a coil\n",

+      "hc=500. # hysteresis coefficient \n",

+      "w=2.*pi*f # angular frequency in rads/sec\n",

+      "phimax=(sqrt(2.)*V)/(t*w)# maximum value of flux in the core in webers\n",

+      "print\"phimax=\",phimax,\"Wb\"# the answer may vary due to roundoff error\n",

+      "A1=0.0025 # cross-sectional area of core in metre square\n",

+      "Bmax1=phimax/A1 # flux density in core A in tesla\n",

+      "print\"Bmax=\",Bmax1,\"T\"# the answer may vary due to roundoff error\n",

+      "lfe1=0.5 # mean flux path length of core A in meters\n",

+      "VolA=A1*lfe1 # volume of core A in metre cube\n",

+      "print\"VolA=\",VolA,\"metre cube\"\n",

+      "# for core A\n",

+      "Ph1=VolA*f*hc*(Bmax1**x) # hysteresis loss in core A in watts\n",

+      "print\"Ph=\",Ph1,\"W\"# the answer may vary due to roundoff error\n",

+      "# for core B\n",

+      "A2=A1*3. # cross sectional area of core B in metre square\n",

+      "lfe2=0.866 # mean flux path length of core B in metres\n",

+      "Bmax2=phimax/A2 # flux density in core B in tesla\n",

+      "VolB=A2*lfe2 # volume of core B in metre cubes\n",

+      "Ph2=VolB*f*hc*(Bmax2**x) # hysteresis loss of core B in watts\n",

+      "print\"Ph=\",Ph2,\"W\"# the answer may vary due to roundoff error"

+     ],

+     "language": "python",

+     "metadata": {},

+     "outputs": [

+      {

+       "output_type": "stream",

+       "stream": "stdout",

+       "text": [

+        "phimax= 0.00300105438719 Wb\n",

+        "Bmax= 1.20042175488 T\n",

+        "VolA= 0.00125 metre cube\n",

+        "Ph= 53.0597985532 W\n",

+        "Ph= 34.1904136606 W\n"

+       ]

+      }

+     ],

+     "prompt_number": 3

+    },

+    {

+     "cell_type": "heading",

+     "level": 2,

+     "metadata": {},

+     "source": [

+      "Example E04 : Pg 18"

+     ]

+    },

+    {

+     "cell_type": "code",

+     "collapsed": false,

+     "input": [

+      "V1=240. # voltage applied to a winding of transformer(three phase) in volts\n",

+      "f1=60. # initial applied frequency in Hz\n",

+      "f2=30. # reduced frequency in Hz\n",

+      "Phe1=400. # core loss in watts at f1 frequency\n",

+      "Phe2=169. # core losses in watts at f2 frequency\n",

+      "print\"V2=\",(f2*V1)/f1,\"V\"# voltage at 30 Hz frequency\n",

+      "print\"Ph+e/f=Ch+Ce*f\"# equation for claculating  hysteresis and eddy current loss coefficients\n",

+      "#a=[1 f1;1 f2] # left hand side matix for the equation above\n",

+      "#b=[Phe1/f1;Phe2/f2] # right hand side matrix for the equation above\n",

+      "#c=inv(a)*b\n",

+      "Ch=4.6#c(1,:)# hysteresis loss coefficient in W/Hz\n",

+      "Ce=0.0344#c(2,:)# eddy current loss coefficient in W/(Hz*Hz)\n",

+      "print\"Ph=\",Ch*f1,\"W\"# ans may vary due to roundoff error # hysteresis loss in watts at 60 Hz\n",

+      "print\"Pe=\",round(Ce*f1*f1),\"W\"# ans may vary due to roundoff error # eddy current loss at 60 Hz in watts"

+     ],

+     "language": "python",

+     "metadata": {},

+     "outputs": [

+      {

+       "output_type": "stream",

+       "stream": "stdout",

+       "text": [

+        "V2= 120.0 V\n",

+        "Ph+e/f=Ch+Ce*f\n",

+        "Ph= 276.0 W\n",

+        "Pe= 124.0 W\n"

+       ]

+      }

+     ],

+     "prompt_number": 4

+    },

+    {

+     "cell_type": "heading",

+     "level": 2,

+     "metadata": {},

+     "source": [

+      "Example E05 : Pg 20"

+     ]

+    },

+    {

+     "cell_type": "code",

+     "collapsed": false,

+     "input": [

+      "from math import sqrt \n",

+      "Pk=75. # core loss of transfomer in watts\n",

+      "R=0.048 # internal resistance in ohms\n",

+      "V2=240.#  secondary voltage in volts\n",

+      "I2=sqrt(Pk/R)# secondary current in amperes\n",

+      "print\"I2=\",round(I2),\"A\"# ans may vary due to roundoff error\n",

+      "print\"|S|=V2*I2=\",round(V2*I2),\"VA\"# The answer in the textbook is wrong # output volt ampere of transformer"

+     ],

+     "language": "python",

+     "metadata": {},

+     "outputs": [

+      {

+       "output_type": "stream",

+       "stream": "stdout",

+       "text": [

+        "I2= 40.0 A\n",

+        "|S|=V2*I2= 9487.0 VA\n"

+       ]

+      }

+     ],

+     "prompt_number": 5

+    },

+    {

+     "cell_type": "heading",

+     "level": 2,

+     "metadata": {},

+     "source": [

+      "Example E06 : Pg 22"

+     ]

+    },

+    {

+     "cell_type": "code",

+     "collapsed": false,

+     "input": [

+      "sfl=1746 # speed at full load in rev/min\n",

+      "snl=1799.5 # speed at no load in rev/min\n",

+      "print\"Voltage Regulation=\",round((snl-sfl)/sfl,5) # the ans may vary due to round of error"

+     ],

+     "language": "python",

+     "metadata": {},

+     "outputs": [

+      {

+       "output_type": "stream",

+       "stream": "stdout",

+       "text": [

+        "Voltage Regulation= 0.03064\n"

+       ]

+      }

+     ],

+     "prompt_number": 6

+    },

+    {

+     "cell_type": "heading",

+     "level": 2,

+     "metadata": {},

+     "source": [

+      "Example E07 : Pg 22"

+     ]

+    },

+    {

+     "cell_type": "code",

+     "collapsed": false,

+     "input": [

+      "Vnl=27.3 # no load voltage in volts\n",

+      "Vfl1=24.   # full load voltage at power factor 1 in volts\n",

+      "print\"(Vnl-Vfl/Vfl)=\",(Vnl-Vfl1)/Vfl1# ans may vary due to roundoff error\n",

+      "Vfl2=22.1 # full load voltage at power factor 0.7 in volts\n",

+      "print\"Voltage Regulation=\",round((Vnl-Vfl2)/Vfl1,4)"

+     ],

+     "language": "python",

+     "metadata": {},

+     "outputs": [

+      {

+       "output_type": "stream",

+       "stream": "stdout",

+       "text": [

+        "(Vnl-Vfl/Vfl)= 0.1375\n",

+        "Voltage Regulation= 0.2167\n"

+       ]

+      }

+     ],

+     "prompt_number": 7

+    }

+   ],

+   "metadata": {}

+  }

+ ]

+}
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