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| author | Trupti Kini | 2016-08-07 23:30:22 +0600 |
|---|---|---|
| committer | Trupti Kini | 2016-08-07 23:30:22 +0600 |
| commit | bdf084e95a05a5846fb9f27447964707560609ac (patch) | |
| tree | 1eb8a594e55c10820fb964959f6f1a39ecfeb018 /modern_physics_by_Satish_K._Gupta/chap12_1.ipynb | |
| parent | 08c1e09738ed693ca1413d5fca75e586e8af727f (diff) | |
| download | Python-Textbook-Companions-bdf084e95a05a5846fb9f27447964707560609ac.tar.gz Python-Textbook-Companions-bdf084e95a05a5846fb9f27447964707560609ac.tar.bz2 Python-Textbook-Companions-bdf084e95a05a5846fb9f27447964707560609ac.zip | |
Added(A)/Deleted(D) following books
A Solutions_to_Problems_in_Applied_Mechanics_by_A._N._Gobby/Chapter1.ipynb
A Solutions_to_Problems_in_Applied_Mechanics_by_A._N._Gobby/Chapter10.ipynb
A Solutions_to_Problems_in_Applied_Mechanics_by_A._N._Gobby/Chapter11.ipynb
A Solutions_to_Problems_in_Applied_Mechanics_by_A._N._Gobby/Chapter12.ipynb
A Solutions_to_Problems_in_Applied_Mechanics_by_A._N._Gobby/Chapter2.ipynb
A Solutions_to_Problems_in_Applied_Mechanics_by_A._N._Gobby/Chapter3.ipynb
A Solutions_to_Problems_in_Applied_Mechanics_by_A._N._Gobby/Chapter4.ipynb
A Solutions_to_Problems_in_Applied_Mechanics_by_A._N._Gobby/Chapter5.ipynb
A Solutions_to_Problems_in_Applied_Mechanics_by_A._N._Gobby/Chapter6.ipynb
A Solutions_to_Problems_in_Applied_Mechanics_by_A._N._Gobby/Chapter7.ipynb
A Solutions_to_Problems_in_Applied_Mechanics_by_A._N._Gobby/Chapter8.ipynb
A Solutions_to_Problems_in_Applied_Mechanics_by_A._N._Gobby/Chapter9.ipynb
A Solutions_to_Problems_in_Applied_Mechanics_by_A._N._Gobby/screenshots/chapter1.png
A Solutions_to_Problems_in_Applied_Mechanics_by_A._N._Gobby/screenshots/chapter2.png
A Solutions_to_Problems_in_Applied_Mechanics_by_A._N._Gobby/screenshots/chapter3.png
A Theory_of_Alternating_Current_Machinery_by_A._S._Langsdorf/Chapter1.ipynb
A Theory_of_Alternating_Current_Machinery_by_A._S._Langsdorf/Chapter10.ipynb
A Theory_of_Alternating_Current_Machinery_by_A._S._Langsdorf/Chapter16.ipynb
A Theory_of_Alternating_Current_Machinery_by_A._S._Langsdorf/Chapter2.ipynb
A Theory_of_Alternating_Current_Machinery_by_A._S._Langsdorf/Chapter3.ipynb
A Theory_of_Alternating_Current_Machinery_by_A._S._Langsdorf/screenshots/chapter1.png
A Theory_of_Alternating_Current_Machinery_by_A._S._Langsdorf/screenshots/chapter2.png
A Theory_of_Alternating_Current_Machinery_by_A._S._Langsdorf/screenshots/chapter3.png
A modern_physics_by_Satish_K._Gupta/chap10_1.ipynb
A modern_physics_by_Satish_K._Gupta/chap11_1.ipynb
A modern_physics_by_Satish_K._Gupta/chap12_1.ipynb
A modern_physics_by_Satish_K._Gupta/chap13_1.ipynb
A modern_physics_by_Satish_K._Gupta/chap14_1.ipynb
A modern_physics_by_Satish_K._Gupta/chap15_1.ipynb
A modern_physics_by_Satish_K._Gupta/chap16_1.ipynb
A modern_physics_by_Satish_K._Gupta/chap17_1.ipynb
A modern_physics_by_Satish_K._Gupta/chap18_1.ipynb
A modern_physics_by_Satish_K._Gupta/chap19_1.ipynb
A modern_physics_by_Satish_K._Gupta/chap1_1.ipynb
A modern_physics_by_Satish_K._Gupta/chap20_1.ipynb
A modern_physics_by_Satish_K._Gupta/chap21_1.ipynb
A modern_physics_by_Satish_K._Gupta/chap22_1.ipynb
A modern_physics_by_Satish_K._Gupta/chap23_1.ipynb
A modern_physics_by_Satish_K._Gupta/chap25_1.ipynb
A modern_physics_by_Satish_K._Gupta/chap26_1.ipynb
A modern_physics_by_Satish_K._Gupta/chap27_1.ipynb
A modern_physics_by_Satish_K._Gupta/chap28_1.ipynb
A modern_physics_by_Satish_K._Gupta/chap2_1.ipynb
A modern_physics_by_Satish_K._Gupta/chap30_1.ipynb
A modern_physics_by_Satish_K._Gupta/chap31_1.ipynb
A modern_physics_by_Satish_K._Gupta/chap32_1.ipynb
A modern_physics_by_Satish_K._Gupta/chap33_1.ipynb
A modern_physics_by_Satish_K._Gupta/chap34_1.ipynb
A modern_physics_by_Satish_K._Gupta/chap35_1.ipynb
A modern_physics_by_Satish_K._Gupta/chap36_1.ipynb
A modern_physics_by_Satish_K._Gupta/chap37_1.ipynb
A modern_physics_by_Satish_K._Gupta/chap3_1.ipynb
A modern_physics_by_Satish_K._Gupta/chap4_1.ipynb
A modern_physics_by_Satish_K._Gupta/chap5_1.ipynb
A modern_physics_by_Satish_K._Gupta/chap6_1.ipynb
A modern_physics_by_Satish_K._Gupta/chap7_1.ipynb
A modern_physics_by_Satish_K._Gupta/chap8_1.ipynb
A modern_physics_by_Satish_K._Gupta/chap9_1.ipynb
A modern_physics_by_Satish_K._Gupta/chap_29_1.ipynb
A modern_physics_by_Satish_K._Gupta/screenshots/image1_1.png
A modern_physics_by_Satish_K._Gupta/screenshots/image22_1.png
A modern_physics_by_Satish_K._Gupta/screenshots/image33_1.png
A sample_notebooks/RuchiMittal/chpater3.ipynb
Diffstat (limited to 'modern_physics_by_Satish_K._Gupta/chap12_1.ipynb')
| -rw-r--r-- | modern_physics_by_Satish_K._Gupta/chap12_1.ipynb | 1435 |
1 files changed, 1435 insertions, 0 deletions
diff --git a/modern_physics_by_Satish_K._Gupta/chap12_1.ipynb b/modern_physics_by_Satish_K._Gupta/chap12_1.ipynb new file mode 100644 index 00000000..30e711a0 --- /dev/null +++ b/modern_physics_by_Satish_K._Gupta/chap12_1.ipynb @@ -0,0 +1,1435 @@ +{
+ "metadata": {
+ "name": "",
+ "signature": "sha256:48ced6bcb2294321844f4027bedbd6f874bf0da0aa33534190457acb1015aba8"
+ },
+ "nbformat": 3,
+ "nbformat_minor": 0,
+ "worksheets": [
+ {
+ "cells": [
+ {
+ "cell_type": "heading",
+ "level": 1,
+ "metadata": {},
+ "source": [
+ "Chapter 12 Motion of charged particle"
+ ]
+ },
+ {
+ "cell_type": "heading",
+ "level": 2,
+ "metadata": {},
+ "source": [
+ "Example 12.1 Page no 379"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "#Given\n",
+ "m=1.6*10**-27 #Kg\n",
+ "e=1.6*10**-19\n",
+ "Ey=2*10**4 #V/m\n",
+ "x=0.1 #m\n",
+ "vx=5*10**6 #m/s\n",
+ "\n",
+ "#Calculation\n",
+ "t=x/vx\n",
+ "Fy=e*Ey\n",
+ "a=Fy/m\n",
+ "y=a*t**2/2.0\n",
+ "\n",
+ "#Result\n",
+ "print\"Transverse deflection is\", y*10**3,\"mm\""
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "Transverse deflection is 0.4 mm\n"
+ ]
+ }
+ ],
+ "prompt_number": 7
+ },
+ {
+ "cell_type": "heading",
+ "level": 2,
+ "metadata": {},
+ "source": [
+ "Example 12.2 Page no 379"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "#Given\n",
+ "n=8*10**28 #/m**2\n",
+ "l=1 #m\n",
+ "A=8*10**-6 #m**2\n",
+ "B=5*10**-3 #T\n",
+ "F=8*10**-2 #N\n",
+ "e=1.6*10**-19 #C\n",
+ "\n",
+ "#Calculation\n",
+ "vd=F/(B*n*A*l*e)\n",
+ "\n",
+ "#Result\n",
+ "print\"Drift velocity is\", vd*10**4,\"*10**-4 m/s\""
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "Drift velocity is 1.5625 *10**-4 m/s\n"
+ ]
+ }
+ ],
+ "prompt_number": 11
+ },
+ {
+ "cell_type": "heading",
+ "level": 2,
+ "metadata": {},
+ "source": [
+ "Example 12.3 Page no 379"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "#Given\n",
+ "q=1.6*10**-19 #C\n",
+ "v=10**7 #m/s\n",
+ "B=3 #T\n",
+ "\n",
+ "#Calculation\n",
+ "F=q*v*B\n",
+ "\n",
+ "#Result\n",
+ "print\"Instantaneous force is\", F,\"N\""
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "Instantaneous force is 4.8e-12 N\n"
+ ]
+ }
+ ],
+ "prompt_number": 14
+ },
+ {
+ "cell_type": "heading",
+ "level": 2,
+ "metadata": {},
+ "source": [
+ "Example 12.4 Page no 379"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "#Given\n",
+ "I=2 #A\n",
+ "a=0.1 #m\n",
+ "u=10**-7\n",
+ "q=1.6*10**-19\n",
+ "v=4*10**4 #m/s\n",
+ "\n",
+ "#Calculation\n",
+ "import math\n",
+ "B=(u*2*I)/a\n",
+ "F=B*q*v\n",
+ "\n",
+ "#Result\n",
+ "print\"Force of magnetic field is\", F,\"N\""
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "Force of magnetic field is 2.56e-20 N\n"
+ ]
+ }
+ ],
+ "prompt_number": 6
+ },
+ {
+ "cell_type": "heading",
+ "level": 2,
+ "metadata": {},
+ "source": [
+ "Example 12.6 Page no 380"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "#Given\n",
+ "v=10**5 #m/s\n",
+ "e=1.6*10**-19 #C\n",
+ "m=9.1*10**-31 #Kg\n",
+ "B=0.019*10**-4 #T\n",
+ "\n",
+ "#Calculation\n",
+ "r=m*v/(B*e)\n",
+ "\n",
+ "#Result\n",
+ "print\"Radius of the circular path is\", round(r,3),\"m\""
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "Radius of the circular path is 0.299 m\n"
+ ]
+ }
+ ],
+ "prompt_number": 10
+ },
+ {
+ "cell_type": "heading",
+ "level": 2,
+ "metadata": {},
+ "source": [
+ "Example 12.7 Page no 380"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "#Given\n",
+ "e=1.6*10**-19\n",
+ "m=9*10**-31 #Kg\n",
+ "T=10**-6 #S\n",
+ "\n",
+ "#Calculation\n",
+ "import math\n",
+ "B=2*math.pi*m/(e*T)\n",
+ "\n",
+ "#Result\n",
+ "print\"Magnetic field is\", round(B*10**5,3)*10**-5 ,\"T\""
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "Magnetic field is 3.534e-05 T\n"
+ ]
+ }
+ ],
+ "prompt_number": 16
+ },
+ {
+ "cell_type": "heading",
+ "level": 2,
+ "metadata": {},
+ "source": [
+ "Example 12.9 Page no 381"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "#Given\n",
+ "m=1.67*10**-27 #Kg\n",
+ "e=1.60*10**-19\n",
+ "V=10**7 #Hz\n",
+ "R=0.6 #m\n",
+ "\n",
+ "#Calculation\n",
+ "import math\n",
+ "B=2*math.pi*m*V/e\n",
+ "Emax=(B**2*e**2*R**2/(2*m))/1.6*10**13\n",
+ "\n",
+ "#Result\n",
+ "print\"Kinetic energy of the proton is\",round(Emax,3),\"Mev\""
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "Kinetic energy of the proton is 7.417 Mev\n"
+ ]
+ }
+ ],
+ "prompt_number": 25
+ },
+ {
+ "cell_type": "heading",
+ "level": 2,
+ "metadata": {},
+ "source": [
+ "Example 12.10 Page no 381"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "#Given\n",
+ "I=5 #A\n",
+ "l=0.1 #m\n",
+ "m=3*10**-3\n",
+ "g=9.8\n",
+ "a=0.5\n",
+ "\n",
+ "#Calculation\n",
+ "w=m*g*l\n",
+ "B=w/a\n",
+ "\n",
+ "#Result\n",
+ "print\"Magnitude of the magnetic field is\", B*10**3,\"*10**-3 tesla\""
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "Magnitude of the magnetic field is 5.88 *10**-3 tesla\n"
+ ]
+ }
+ ],
+ "prompt_number": 29
+ },
+ {
+ "cell_type": "heading",
+ "level": 2,
+ "metadata": {},
+ "source": [
+ "Example 12.11 Page no 381"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "#given\n",
+ "I1=4 #A\n",
+ "I2=6\n",
+ "r=0.03 #m\n",
+ "u=10**-7\n",
+ "\n",
+ "#Calculation\n",
+ "F=u*2*I1*I2/r\n",
+ "\n",
+ "#Result\n",
+ "print\"Force per unit length is\", F*10**4,\"*10**-4 N/m\""
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "Force per unit length is 1.6 *10**-4 N/m\n"
+ ]
+ }
+ ],
+ "prompt_number": 33
+ },
+ {
+ "cell_type": "heading",
+ "level": 2,
+ "metadata": {},
+ "source": [
+ "Example 12.12 Page no 381"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "#Given\n",
+ "I1=5 #A\n",
+ "I2=12\n",
+ "r=0.4 #m\n",
+ "u=10**-7\n",
+ "\n",
+ "#Calculation\n",
+ "F=u*2*I1*I2/r\n",
+ "F1=u*2*I1*I2/r\n",
+ "\n",
+ "#Result\n",
+ "print\"(i) Force when current flows in same direction is\", F,\"N/m\"\n",
+ "print\"(ii) Force when current flows in opposite direction is\",F1,\"N/m\""
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "(i) Force when current flows in same direction is 3e-05 N/m\n",
+ "(ii) Force when current flows in opposite direction is 3e-05 N/m\n"
+ ]
+ }
+ ],
+ "prompt_number": 38
+ },
+ {
+ "cell_type": "heading",
+ "level": 2,
+ "metadata": {},
+ "source": [
+ "Example 12.13 Page no 381"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "#Given\n",
+ "I1=300 #A\n",
+ "r=1.5*10**-2 #m\n",
+ "u=10**-7\n",
+ "\n",
+ "#Calculation\n",
+ "F=u*2*I1*I1/r\n",
+ "\n",
+ "#Result\n",
+ "print\"Force per unit length is\",F,\"N/m\""
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "Force per unit length is 1.2 N/m\n"
+ ]
+ }
+ ],
+ "prompt_number": 40
+ },
+ {
+ "cell_type": "heading",
+ "level": 2,
+ "metadata": {},
+ "source": [
+ "Example 12.14 Page no 381"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "#Given\n",
+ "I=10 #A\n",
+ "n=100\n",
+ "A=8*10**-2 #m**2\n",
+ "B=5 #T\n",
+ "\n",
+ "#Calculation\n",
+ "import math\n",
+ "t=n*B*I*A*math.cos(60*3.14/180.0)\n",
+ "\n",
+ "#Result\n",
+ "print\"Torque is\", round(t,0),\"Nm\""
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "Torque is 200.0 Nm\n"
+ ]
+ }
+ ],
+ "prompt_number": 44
+ },
+ {
+ "cell_type": "heading",
+ "level": 2,
+ "metadata": {},
+ "source": [
+ "Example 12.15 Page no 381"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "#Given\n",
+ "n=30\n",
+ "I=6 #A\n",
+ "B=1 #T\n",
+ "r=8*10**-2 #m\n",
+ "\n",
+ "#Calculation\n",
+ "import math\n",
+ "A=math.pi*r**2\n",
+ "t=n*B*I*A*math.sin(60*3.14/180.0)\n",
+ "\n",
+ "#Result\n",
+ "print\"(a) Magnitude of the counter torque is\", round(t,3),\"Nm\"\n",
+ "print\"(b) Torque on the planar loop is independent of its shape, the torque will remain unchanged.\""
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "(a) Magnitude of the counter torque is 3.133 Nm\n",
+ "(b) Torque on the planar loop is independent of its shape, the torque will remain unchanged.\n"
+ ]
+ }
+ ],
+ "prompt_number": 50
+ },
+ {
+ "cell_type": "heading",
+ "level": 2,
+ "metadata": {},
+ "source": [
+ "Example 12.16 Page no 382"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "#Given\n",
+ "B=100*10**-4 #T\n",
+ "I=10 #A\n",
+ "l=44\n",
+ "\n",
+ "#Calculation\n",
+ "import math\n",
+ "r=l/(2.0*math.pi)\n",
+ "A=math.pi*r**2\n",
+ "t=B*I*A\n",
+ "\n",
+ "#Result\n",
+ "print\"Maximum torque is\", round(t*10**-1,2),\"*10**-3 Nm\""
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "Maximum torque is 1.54 *10**-3 Nm\n"
+ ]
+ }
+ ],
+ "prompt_number": 62
+ },
+ {
+ "cell_type": "heading",
+ "level": 2,
+ "metadata": {},
+ "source": [
+ "Example 12.17 Page no 382"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "#Given\n",
+ "n=20\n",
+ "r=10*10**-2 #m\n",
+ "B=0.10 #T\n",
+ "I=5 #A\n",
+ "n1=10**29 #/m**3\n",
+ "A1=10**-5 #m**2\n",
+ "\n",
+ "#Calculation\n",
+ "import math\n",
+ "A=math.pi*r**2\n",
+ "t=n*B*I*A*math.sin(0*3.14/180.0)\n",
+ "F=B*I/(n1*A1)\n",
+ "\n",
+ "#Result\n",
+ "print\"(a) Total torque on the coil is\", t\n",
+ "print\"(b) Net force on a planar loop in a magnetic field is always zero\"\n",
+ "print\"(c) Average force is\",F,\"N\""
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "(a) Total torque on the coil is 0.0\n",
+ "(b) Net force on a planar loop in a magnetic field is always zero\n",
+ "(c) Average force is 5e-25 N\n"
+ ]
+ }
+ ],
+ "prompt_number": 68
+ },
+ {
+ "cell_type": "heading",
+ "level": 2,
+ "metadata": {},
+ "source": [
+ "Example 12.18 Page no 382"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "#Given\n",
+ "A=5*10**-4 #m**2\n",
+ "n=60\n",
+ "a=18 #degree\n",
+ "B=90*10**-4 #T\n",
+ "I=0.20*10**-3 #A\n",
+ "\n",
+ "#calculation\n",
+ "k=n*B*I*A/a\n",
+ "\n",
+ "#Result\n",
+ "print\"Torsional constant is\",k,\"N m per degree\""
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "Torsional constant is 3e-09 N m per degree\n"
+ ]
+ }
+ ],
+ "prompt_number": 70
+ },
+ {
+ "cell_type": "heading",
+ "level": 2,
+ "metadata": {},
+ "source": [
+ "Example 12.21 Page no 383"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "#Given\n",
+ "G=15 #ohm\n",
+ "Ig=2*10**-3 #A\n",
+ "I=5 #A\n",
+ "\n",
+ "#Calculation\n",
+ "S=Ig*G/(I-Ig)\n",
+ "\n",
+ "#Result\n",
+ "print\"Shunt resistance is\",round(S,3),\"Ohm\""
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "Shunt resistance is 0.006 Ohm\n"
+ ]
+ }
+ ],
+ "prompt_number": 74
+ },
+ {
+ "cell_type": "heading",
+ "level": 2,
+ "metadata": {},
+ "source": [
+ "Example 12.22 Page no 383"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "#Given\n",
+ "V=50*10**-3 #V\n",
+ "G=100.0 #ohm\n",
+ "\n",
+ "#Calculation\n",
+ "Ig=V/G\n",
+ "S=Ig*G/(I-Ig)\n",
+ "\n",
+ "#Result\n",
+ "print\"Shunt resistance is\", round(S,2),\"ohm\""
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "Shunt resistance is 0.01 ohm\n"
+ ]
+ }
+ ],
+ "prompt_number": 79
+ },
+ {
+ "cell_type": "heading",
+ "level": 2,
+ "metadata": {},
+ "source": [
+ "Example 12.23 Page no 383"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "#Given\n",
+ "G=100 #ohm\n",
+ "Ig=5*10**-3 #A\n",
+ "I=5 #A\n",
+ "\n",
+ "#Calculation\n",
+ "S=Ig*G/(I-Ig)\n",
+ "\n",
+ "#Result\n",
+ "print\"Shunt resistance is\",S"
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "Shunt resistance is 0.1001001001\n"
+ ]
+ }
+ ],
+ "prompt_number": 80
+ },
+ {
+ "cell_type": "heading",
+ "level": 2,
+ "metadata": {},
+ "source": [
+ "Example 12.24 Page no 383"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "#Given\n",
+ "G=5 #ohm\n",
+ "Ig=15.0*10**-3 #A\n",
+ "I=1.5\n",
+ "V=1.5 #V\n",
+ "\n",
+ "#Calculation\n",
+ "S=Ig*G/(I-Ig)\n",
+ "R=(V/Ig)-G\n",
+ "\n",
+ "#Result\n",
+ "print\"(a) To enable galvanometer to read 1.5 A is\", round(S,2),\"ohm\"\n",
+ "print\"(b) To enable galvanometer to read 1.5 V is\",R,\"ohm\""
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "(a) To enable galvanometer to read 1.5 A is 0.05 ohm\n",
+ "(b) To enable galvanometer to read 1.5 V is 95.0 ohm\n"
+ ]
+ }
+ ],
+ "prompt_number": 88
+ },
+ {
+ "cell_type": "heading",
+ "level": 2,
+ "metadata": {},
+ "source": [
+ "Example 12.25 Page no 383"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "#Given\n",
+ "G=10 #ohm\n",
+ "Ig=25.0*10**-3 #A\n",
+ "V=120 #V\n",
+ "I=20 #A\n",
+ "\n",
+ "#Calculation\n",
+ "R=(V/Ig)-G\n",
+ "S=Ig*G/(I-Ig)\n",
+ "\n",
+ "#Result\n",
+ "print\"(a) To convert the galvanometer into the voltmeter reading is\" ,R,\"ohm\"\n",
+ "print\"(b) To convert the galvanometer into the ammeter reading is\",round(S,4),\"ohm\""
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "(a) To convert the galvanometer into the voltmeter reading is 4790.0 ohm\n",
+ "(b) To convert the galvanometer into the ammeter reading is 0.0125 ohm\n"
+ ]
+ }
+ ],
+ "prompt_number": 95
+ },
+ {
+ "cell_type": "heading",
+ "level": 2,
+ "metadata": {},
+ "source": [
+ "Example 12.26 Page no 383"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "#Given\n",
+ "E=3 #v\n",
+ "R=55 #ohm\n",
+ "Ra=1\n",
+ "I=50*10**-3 #A\n",
+ "\n",
+ "#Calculation\n",
+ "r=(E/I)-(R+Ra)\n",
+ "\n",
+ "#Result\n",
+ "print\"Value of r is\", r,\"ohm\""
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "Value of r is 4.0 ohm\n"
+ ]
+ }
+ ],
+ "prompt_number": 98
+ },
+ {
+ "cell_type": "heading",
+ "level": 2,
+ "metadata": {},
+ "source": [
+ "Example 12.27 Page no 384"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "#Given\n",
+ "E=60 #V\n",
+ "R1=400 #ohm\n",
+ "R2=300\n",
+ "V1=30.0\n",
+ "a=120000\n",
+ "\n",
+ "#Calculation\n",
+ "Rv=(-V1*a)/(V1*(R1+R2)-E*R1)\n",
+ "R=Rv*R2/(Rv+R2)\n",
+ "I1=E/(R+R1)\n",
+ "V=I1*R\n",
+ "\n",
+ "#Result\n",
+ "print\"Voltmeter reads\", V,\"V\""
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "Voltmeter reads 22.5 V\n"
+ ]
+ }
+ ],
+ "prompt_number": 108
+ },
+ {
+ "cell_type": "heading",
+ "level": 2,
+ "metadata": {},
+ "source": [
+ "Example 12.28 Page no 384"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "#Given\n",
+ "Rv=400.0\n",
+ "E=84 #V\n",
+ "r=100.0\n",
+ "r1=200\n",
+ "\n",
+ "#Calculation\n",
+ "R=1/(1/Rv+1/100.0)\n",
+ "R1=R+200\n",
+ "I=E/R1\n",
+ "I1=I/5.0\n",
+ "V=I1*Rv\n",
+ "R2=r+r1\n",
+ "I2=E/R2\n",
+ "V2=I2*r\n",
+ "\n",
+ "#Result\n",
+ "print\"(a) Reading on voltmeter is\", V,\"V\"\n",
+ "print\"(b) Potential difference is\",V2,\"V\""
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "(a) Reading on voltmeter is 24.0 V\n",
+ "(b) Potential difference is 28.0 V\n"
+ ]
+ }
+ ],
+ "prompt_number": 122
+ },
+ {
+ "cell_type": "heading",
+ "level": 2,
+ "metadata": {},
+ "source": [
+ "Example 12.29 Page no 385"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "#Given\n",
+ "E=120 #v\n",
+ "Rv=10**4 #ohm\n",
+ "a=4.0\n",
+ "\n",
+ "#Calculation\n",
+ "x=(Rv*(E-a))/a\n",
+ "\n",
+ "#Result\n",
+ "print\"Large resistance is\", x*10**-3,\"K ohm\""
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "Large resistance is 290.0 K ohm\n"
+ ]
+ }
+ ],
+ "prompt_number": 131
+ },
+ {
+ "cell_type": "heading",
+ "level": 2,
+ "metadata": {},
+ "source": [
+ "Example 12.30 Page no 385"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "#Given\n",
+ "B=0.75 #T\n",
+ "E=9*10**5 #V/m\n",
+ "V=15*10**3\n",
+ "\n",
+ "#Calculation\n",
+ "v=E/B\n",
+ "a=v**2/(2.0*V)\n",
+ "\n",
+ "#Result\n",
+ "print\"The value of e/m is\", a*10**-7,\"*10**7 C/Kg\""
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "The value of e/m is 4.8 *10**7 C/Kg\n"
+ ]
+ }
+ ],
+ "prompt_number": 127
+ },
+ {
+ "cell_type": "heading",
+ "level": 2,
+ "metadata": {},
+ "source": [
+ "Example 12.31 Page no 385"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "#Given\n",
+ "m=9.11*10**-31 #Kg\n",
+ "e=1.60*10**-19 #C\n",
+ "B=0.40*10**-4 #T\n",
+ "a=18*1.6*10**-16\n",
+ "PQ=0.30\n",
+ "a2=1.52 #degree\n",
+ "\n",
+ "#calculation\n",
+ "import math\n",
+ "r=math.sqrt(2*m*a)/(B*e)\n",
+ "a1=(PQ/r)\n",
+ "PA=r*(1-math.cos(a2*3.14/180.0))\n",
+ "\n",
+ "#Result\n",
+ "print\"up and down deflection of the beam is\", round(PA*10**3,0),\"mm\""
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "up and down deflection of the beam is 4.0 mm\n"
+ ]
+ }
+ ],
+ "prompt_number": 153
+ },
+ {
+ "cell_type": "heading",
+ "level": 2,
+ "metadata": {},
+ "source": [
+ "Example 12.32 Page no 386"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "#Given\n",
+ "m=60*10**-3\n",
+ "g=9.8\n",
+ "I=5\n",
+ "l=0.45\n",
+ "\n",
+ "#Calculation\n",
+ "B=m*g/(I*l)\n",
+ "T=2*m*g\n",
+ "\n",
+ "#Result\n",
+ "print\"(i) Magnetic field is\", round(B,3),\"T\"\n",
+ "print\"(ii) Total tension in the wire is\",T,\"N\""
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "(i) Magnetic field is 0.261 T\n",
+ "(ii) Total tension in the wire is 1.176 N\n"
+ ]
+ }
+ ],
+ "prompt_number": 161
+ },
+ {
+ "cell_type": "heading",
+ "level": 2,
+ "metadata": {},
+ "source": [
+ "Example 12.33 Page no 386"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "#Given\n",
+ "B=0.15 #T\n",
+ "m=0.30 #Kg/m\n",
+ "a=30 #degree\n",
+ "g=9.8 #m/s**2\n",
+ "\n",
+ "#Calculation\n",
+ "import math\n",
+ "I=m*g*math.tan(a*3.14/180.0)/B\n",
+ "\n",
+ "#Result\n",
+ "print\"Value of current is\", round(I,2),\"A\""
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "Value of current is 11.31 A\n"
+ ]
+ }
+ ],
+ "prompt_number": 165
+ },
+ {
+ "cell_type": "heading",
+ "level": 2,
+ "metadata": {},
+ "source": [
+ "Example 12.34 Page no 386"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "#Given\n",
+ "I1=4 #A\n",
+ "I2=3\n",
+ "r=3.0*10**-2 #m\n",
+ "u=10**-7\n",
+ "l=5*10**-2\n",
+ "\n",
+ "#Calculation\n",
+ "F=u*2*I1*I2/r\n",
+ "F1=F*l\n",
+ "\n",
+ "#Result\n",
+ "print\"Total force is\", F1,\"N (attractive force)\""
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "Total force is 4e-06 N (attractive force)\n"
+ ]
+ }
+ ],
+ "prompt_number": 171
+ },
+ {
+ "cell_type": "heading",
+ "level": 2,
+ "metadata": {},
+ "source": [
+ "Example 12.35 Page no 386"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "#Given\n",
+ "AB=25*10**-2 #m\n",
+ "BC=10*10**-2\n",
+ "r1=2.0*10**-2 #m\n",
+ "I1=15 #A\n",
+ "I2=25 #A\n",
+ "u=10**-7\n",
+ "\n",
+ "#Calculation\n",
+ "r2=BC+r1\n",
+ "F1=u*2*I1*I2*AB/r1\n",
+ "F2=u*2*I1*I2*AB/r2\n",
+ "F=F1-F2\n",
+ "\n",
+ "#Result\n",
+ "print\"Net force on the loop is\", F*10**4,\"*10**-4 N (towards XY)\""
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "Net force on the loop is 7.8125 *10**-4 N (towards XY)\n"
+ ]
+ }
+ ],
+ "prompt_number": 182
+ },
+ {
+ "cell_type": "heading",
+ "level": 2,
+ "metadata": {},
+ "source": [
+ "Example 12.36 Page no 387"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "#Given\n",
+ "M=30*10**-3 #Kg\n",
+ "g=9.8 #m/s**2\n",
+ "l=0.5 #m\n",
+ "r=10**-2\n",
+ "u=10**-7\n",
+ "\n",
+ "#Calculation\n",
+ "import math\n",
+ "I=math.sqrt((M*g*r)/(u*2*l))\n",
+ "\n",
+ "#Result\n",
+ "print\"Value of current is\", round(I,2),\"A\""
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "Value of current is 171.46 A\n"
+ ]
+ }
+ ],
+ "prompt_number": 186
+ },
+ {
+ "cell_type": "heading",
+ "level": 2,
+ "metadata": {},
+ "source": [
+ "Example 12.37 Page no 387"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "#Given\n",
+ "n=900\n",
+ "l=0.6\n",
+ "u=10**-7\n",
+ "l2=0.02 #m\n",
+ "l1=6\n",
+ "m=2.5*10**-3 #Kg\n",
+ "g=9.8\n",
+ "\n",
+ "#Calculation\n",
+ "import math\n",
+ "n1=n/l\n",
+ "B=4*math.pi*n1\n",
+ "F=B*l1*l2\n",
+ "I=m*g/F\n",
+ "\n",
+ "#Result\n",
+ "print\"Current in the winding of the secondary is\", round(I*10**7,1),\"A\""
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "Current in the winding of the secondary is 108.3 A\n"
+ ]
+ }
+ ],
+ "prompt_number": 197
+ },
+ {
+ "cell_type": "heading",
+ "level": 2,
+ "metadata": {},
+ "source": [
+ "Example 12.38 Page no 387"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "#Given\n",
+ "A=1.6*10**-3 #m**2\n",
+ "n=200\n",
+ "B=0.2 #T\n",
+ "a=30 #degree\n",
+ "K=10**-6 #N m /degree\n",
+ "a1=0.1\n",
+ "\n",
+ "#Calculation\n",
+ "Imax=K*a/(n*B*A)\n",
+ "Imin=K*a1/(n*B*A)\n",
+ "\n",
+ "#Result\n",
+ "print\"(i) Minimum current is\",round(Imax*10**4,2),\"*10**-4 A\"\n",
+ "print\"(ii) Smallest current that can be detected is\",Imin,\"A\""
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "(i) Minimum current is 4.69 *10**-4 A\n",
+ "(ii) Smallest current that can be detected is 1.5625e-06 A\n"
+ ]
+ }
+ ],
+ "prompt_number": 204
+ },
+ {
+ "cell_type": "heading",
+ "level": 2,
+ "metadata": {},
+ "source": [
+ "Example 12.39 Page no 388 "
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "#Given\n",
+ "R=5000.0 #ohm/V\n",
+ "V=5\n",
+ "V1=20.0\n",
+ "\n",
+ "#Calculation\n",
+ "Ig=1/R\n",
+ "G=V/Ig\n",
+ "R1=(V1/Ig)-G\n",
+ "Rn=R1+G\n",
+ "Rv=Rn/V1\n",
+ "\n",
+ "#Result\n",
+ "print\"New voltmeter will be still graded as\", Rv,\"ohm/V\""
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "New voltmeter will be still graded as 5000.0 ohm/V\n"
+ ]
+ }
+ ],
+ "prompt_number": 212
+ },
+ {
+ "cell_type": "heading",
+ "level": 2,
+ "metadata": {},
+ "source": [
+ "Example 12.40 Page no 388"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "#Given\n",
+ "V1=100 #V\n",
+ "Rv=400.0 \n",
+ "\n",
+ "#Calculation\n",
+ "I1=V1/Rv\n",
+ "V=I1*20\n",
+ "V2=V1+V\n",
+ "V3=V2-V1\n",
+ "\n",
+ "#Result\n",
+ "print\"Error in the reading of the voltmeter is\",V3,\"V\""
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "Error in the reading of the voltmeter is 5.0 V\n"
+ ]
+ }
+ ],
+ "prompt_number": 215
+ }
+ ],
+ "metadata": {}
+ }
+ ]
+}
\ No newline at end of file |