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authorTrupti Kini2016-11-24 23:30:37 +0600
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Added(A)/Deleted(D) following books
A Electrical_&_Electronic_Systems_by_Neil_Storey/Chapter11.ipynb A Electrical_&_Electronic_Systems_by_Neil_Storey/Chapter12.ipynb A Electrical_&_Electronic_Systems_by_Neil_Storey/Chapter13.ipynb A Electrical_&_Electronic_Systems_by_Neil_Storey/Chapter14.ipynb A Electrical_&_Electronic_Systems_by_Neil_Storey/Chapter15.ipynb A Electrical_&_Electronic_Systems_by_Neil_Storey/Chapter16.ipynb A Electrical_&_Electronic_Systems_by_Neil_Storey/Chapter18.ipynb A Electrical_&_Electronic_Systems_by_Neil_Storey/Chapter19.ipynb A Electrical_&_Electronic_Systems_by_Neil_Storey/Chapter2.ipynb A Electrical_&_Electronic_Systems_by_Neil_Storey/Chapter20.ipynb A Electrical_&_Electronic_Systems_by_Neil_Storey/Chapter21.ipynb A Electrical_&_Electronic_Systems_by_Neil_Storey/Chapter22.ipynb A Electrical_&_Electronic_Systems_by_Neil_Storey/Chapter23.ipynb A Electrical_&_Electronic_Systems_by_Neil_Storey/Chapter5.ipynb A Electrical_&_Electronic_Systems_by_Neil_Storey/Chapter6.ipynb A Electrical_&_Electronic_Systems_by_Neil_Storey/Chapter8.ipynb A Electrical_&_Electronic_Systems_by_Neil_Storey/Chapter9.ipynb A Electrical_&_Electronic_Systems_by_Neil_Storey/screenshots/pic1.png A Electrical_&_Electronic_Systems_by_Neil_Storey/screenshots/pic2.png A Electrical_&_Electronic_Systems_by_Neil_Storey/screenshots/pic3.png A MECHANICS_OF_SOLIDS_by_S.S._Bhavikatti/Chapter10_67BmtXx.ipynb A MECHANICS_OF_SOLIDS_by_S.S._Bhavikatti/Chapter10_LGPoR7F.ipynb A MECHANICS_OF_SOLIDS_by_S.S._Bhavikatti/Chapter10_PDCS2qh.ipynb A MECHANICS_OF_SOLIDS_by_S.S._Bhavikatti/Chapter10_lNjLAte.ipynb A MECHANICS_OF_SOLIDS_by_S.S._Bhavikatti/Chapter10_n5s4jXl.ipynb A MECHANICS_OF_SOLIDS_by_S.S._Bhavikatti/Chapter10_npy5vv0.ipynb A MECHANICS_OF_SOLIDS_by_S.S._Bhavikatti/Chapter10_pjpRgex.ipynb A MECHANICS_OF_SOLIDS_by_S.S._Bhavikatti/Chapter11_IE4byFL.ipynb A MECHANICS_OF_SOLIDS_by_S.S._Bhavikatti/Chapter11_RAQoou9.ipynb A MECHANICS_OF_SOLIDS_by_S.S._Bhavikatti/Chapter11_VcicGy5.ipynb A MECHANICS_OF_SOLIDS_by_S.S._Bhavikatti/Chapter11_hoqMFBX.ipynb A MECHANICS_OF_SOLIDS_by_S.S._Bhavikatti/Chapter11_iBTGbp8.ipynb A MECHANICS_OF_SOLIDS_by_S.S._Bhavikatti/Chapter11_k1rTVhh.ipynb A MECHANICS_OF_SOLIDS_by_S.S._Bhavikatti/Chapter11_nGrFEGY.ipynb A MECHANICS_OF_SOLIDS_by_S.S._Bhavikatti/Chapter11_pfzLlc6.ipynb A MECHANICS_OF_SOLIDS_by_S.S._Bhavikatti/Chapter1_1FJHa67.ipynb A MECHANICS_OF_SOLIDS_by_S.S._Bhavikatti/Chapter1_2wryDDQ.ipynb A MECHANICS_OF_SOLIDS_by_S.S._Bhavikatti/Chapter1_BuZVTIP.ipynb A MECHANICS_OF_SOLIDS_by_S.S._Bhavikatti/Chapter1_UCsno1y.ipynb A MECHANICS_OF_SOLIDS_by_S.S._Bhavikatti/Chapter1_Yd7uN6t.ipynb A MECHANICS_OF_SOLIDS_by_S.S._Bhavikatti/Chapter1_bGP3Wsd.ipynb A MECHANICS_OF_SOLIDS_by_S.S._Bhavikatti/Chapter1_pFJzyF5.ipynb A MECHANICS_OF_SOLIDS_by_S.S._Bhavikatti/Chapter2_242icmu.ipynb A MECHANICS_OF_SOLIDS_by_S.S._Bhavikatti/Chapter2_Rcy1wii.ipynb A MECHANICS_OF_SOLIDS_by_S.S._Bhavikatti/Chapter2_TvxYpxT.ipynb A MECHANICS_OF_SOLIDS_by_S.S._Bhavikatti/Chapter2_VU0Vuul.ipynb A MECHANICS_OF_SOLIDS_by_S.S._Bhavikatti/Chapter2_Xiz19Ms.ipynb A MECHANICS_OF_SOLIDS_by_S.S._Bhavikatti/Chapter2_rAG8C10.ipynb A MECHANICS_OF_SOLIDS_by_S.S._Bhavikatti/Chapter2_xUN650b.ipynb A MECHANICS_OF_SOLIDS_by_S.S._Bhavikatti/Chapter3_0WKL8dM.ipynb A MECHANICS_OF_SOLIDS_by_S.S._Bhavikatti/Chapter3_BsRbQCe.ipynb A MECHANICS_OF_SOLIDS_by_S.S._Bhavikatti/Chapter3_IF7BAbT.ipynb A MECHANICS_OF_SOLIDS_by_S.S._Bhavikatti/Chapter3_Qh2uphO.ipynb A MECHANICS_OF_SOLIDS_by_S.S._Bhavikatti/Chapter3_WS64jkH.ipynb A MECHANICS_OF_SOLIDS_by_S.S._Bhavikatti/Chapter3_aM1BqRM.ipynb A MECHANICS_OF_SOLIDS_by_S.S._Bhavikatti/Chapter3_tEQK8Lr.ipynb A MECHANICS_OF_SOLIDS_by_S.S._Bhavikatti/Chapter4_0E18xYL.ipynb A MECHANICS_OF_SOLIDS_by_S.S._Bhavikatti/Chapter4_4P7HQZZ.ipynb A MECHANICS_OF_SOLIDS_by_S.S._Bhavikatti/Chapter4_8GR2j3i.ipynb A MECHANICS_OF_SOLIDS_by_S.S._Bhavikatti/Chapter4_KE5ki12.ipynb A MECHANICS_OF_SOLIDS_by_S.S._Bhavikatti/Chapter4_LmrwpIC.ipynb A MECHANICS_OF_SOLIDS_by_S.S._Bhavikatti/Chapter4_ZuWrQKN.ipynb A MECHANICS_OF_SOLIDS_by_S.S._Bhavikatti/Chapter4_wUtoaip.ipynb A MECHANICS_OF_SOLIDS_by_S.S._Bhavikatti/Chapter5_0Ke5Vhq.ipynb A MECHANICS_OF_SOLIDS_by_S.S._Bhavikatti/Chapter5_23aeJMe.ipynb A MECHANICS_OF_SOLIDS_by_S.S._Bhavikatti/Chapter5_4a14Khd.ipynb A MECHANICS_OF_SOLIDS_by_S.S._Bhavikatti/Chapter5_eftppGy.ipynb A MECHANICS_OF_SOLIDS_by_S.S._Bhavikatti/Chapter5_jOQv5Ua.ipynb A MECHANICS_OF_SOLIDS_by_S.S._Bhavikatti/Chapter5_m75AW4e.ipynb A MECHANICS_OF_SOLIDS_by_S.S._Bhavikatti/Chapter5_mZ9916M.ipynb A MECHANICS_OF_SOLIDS_by_S.S._Bhavikatti/Chapter6_2OboaPO.ipynb A MECHANICS_OF_SOLIDS_by_S.S._Bhavikatti/Chapter6_Cf1Ae70.ipynb A MECHANICS_OF_SOLIDS_by_S.S._Bhavikatti/Chapter6_IZI7GIy.ipynb A MECHANICS_OF_SOLIDS_by_S.S._Bhavikatti/Chapter6_TRm6El0.ipynb A MECHANICS_OF_SOLIDS_by_S.S._Bhavikatti/Chapter6_WfVJQIc.ipynb A MECHANICS_OF_SOLIDS_by_S.S._Bhavikatti/Chapter6_Z5dEk19.ipynb A MECHANICS_OF_SOLIDS_by_S.S._Bhavikatti/Chapter6_z9FlTqT.ipynb A MECHANICS_OF_SOLIDS_by_S.S._Bhavikatti/Chapter8_6BR5OK6.ipynb A MECHANICS_OF_SOLIDS_by_S.S._Bhavikatti/Chapter8_FV7Jgrb.ipynb A MECHANICS_OF_SOLIDS_by_S.S._Bhavikatti/Chapter8_Q79Sp1O.ipynb A MECHANICS_OF_SOLIDS_by_S.S._Bhavikatti/Chapter8_Qhj9HPA.ipynb A MECHANICS_OF_SOLIDS_by_S.S._Bhavikatti/Chapter8_fBoE3j3.ipynb A MECHANICS_OF_SOLIDS_by_S.S._Bhavikatti/Chapter8_mFOxHz2.ipynb A MECHANICS_OF_SOLIDS_by_S.S._Bhavikatti/Chapter8_zNY63b3.ipynb A MECHANICS_OF_SOLIDS_by_S.S._Bhavikatti/Chapter9_039FJN6.ipynb A MECHANICS_OF_SOLIDS_by_S.S._Bhavikatti/Chapter9_0AhnrOb.ipynb A MECHANICS_OF_SOLIDS_by_S.S._Bhavikatti/Chapter9_8K1gGKx.ipynb A MECHANICS_OF_SOLIDS_by_S.S._Bhavikatti/Chapter9_E4M5MRA.ipynb A MECHANICS_OF_SOLIDS_by_S.S._Bhavikatti/Chapter9_Ivqhz8T.ipynb A MECHANICS_OF_SOLIDS_by_S.S._Bhavikatti/Chapter9_ZSvbidk.ipynb A MECHANICS_OF_SOLIDS_by_S.S._Bhavikatti/Chapter9_u7ekl0N.ipynb A MECHANICS_OF_SOLIDS_by_S.S._Bhavikatti/screenshots/ch1_mHmqCLQ.png A MECHANICS_OF_SOLIDS_by_S.S._Bhavikatti/screenshots/ch_9_UicjBqW.png A MECHANICS_OF_SOLIDS_by_S.S._Bhavikatti/screenshots/ch_xk3ylh6.png A basic_electrical_engineering_by_nagsarkar_and_sukhija/Chapter2_eh02mMg.ipynb A basic_electrical_engineering_by_nagsarkar_and_sukhija/Chapter4_QnODdtI.ipynb A basic_electrical_engineering_by_nagsarkar_and_sukhija/Chapter5_IwMblyq.ipynb A basic_electrical_engineering_by_nagsarkar_and_sukhija/chapter11_nHcyQSN.ipynb A basic_electrical_engineering_by_nagsarkar_and_sukhija/chapter1_ivpTi0v.ipynb A basic_electrical_engineering_by_nagsarkar_and_sukhija/chapter3.ipynb A basic_electrical_engineering_by_nagsarkar_and_sukhija/chapter6_7Vcvq3x.ipynb A basic_electrical_engineering_by_nagsarkar_and_sukhija/chapter7_Iro5ijO.ipynb A basic_electrical_engineering_by_nagsarkar_and_sukhija/chapter8_dRxKPQv.ipynb A basic_electrical_engineering_by_nagsarkar_and_sukhija/chapter9_QP9exWK.ipynb A basic_electrical_engineering_by_nagsarkar_and_sukhija/screenshots/chap1_gG9EuuG.png A basic_electrical_engineering_by_nagsarkar_and_sukhija/screenshots/chapter2_RW9JXUw.png A basic_electrical_engineering_by_nagsarkar_and_sukhija/screenshots/chapter6_kNIRtlM.png
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+{
+ "cells": [
+ {
+ "cell_type": "markdown",
+ "metadata": {},
+ "source": [
+ "# Chapter 8:Induction motors"
+ ]
+ },
+ {
+ "cell_type": "markdown",
+ "metadata": {},
+ "source": [
+ "## Example 8.1:Page number-474"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "execution_count": 1,
+ "metadata": {
+ "collapsed": false
+ },
+ "outputs": [
+ {
+ "name": "stdout",
+ "output_type": "stream",
+ "text": [
+ "synchronous speed= 1500.0 rpm\n",
+ "rotor speed= 1455.0 rpm\n",
+ "rotor frequency= 0.0 Hz\n"
+ ]
+ }
+ ],
+ "source": [
+ "import math\n",
+ "#given\n",
+ "f=50\n",
+ "p=4\n",
+ "#case a\n",
+ "s=(120*f)/p #synchronous speed\n",
+ "print \"synchronous speed=\",round(s,0),\"rpm\"\n",
+ "#case b\n",
+ "slip=0.03\n",
+ "r=s-s*slip #rotor speed\n",
+ "print \"rotor speed=\",round(r,0),\"rpm\"\n",
+ "#case c\n",
+ "r=900 #given speed of rotor\n",
+ "slip=(s-r)/s #per unit slip\n",
+ "rf=slip*f\n",
+ "print \"rotor frequency=\",round(rf,0),\"Hz\"\n"
+ ]
+ },
+ {
+ "cell_type": "markdown",
+ "metadata": {},
+ "source": [
+ "## Example 8.2:Page number-475"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "execution_count": 7,
+ "metadata": {
+ "collapsed": false
+ },
+ "outputs": [
+ {
+ "name": "stdout",
+ "output_type": "stream",
+ "text": [
+ "frequency= 60.0 Hz\n",
+ "The number of poles of an induction motor is= 6.0\n",
+ "slip=0.025pu\n"
+ ]
+ }
+ ],
+ "source": [
+ "import math\n",
+ "#given\n",
+ "pg=10 #poles of generator\n",
+ "r=720 #synchronous speed\n",
+ "f=pg*r/120\n",
+ "print \"frequency=\",round(f,0),\"Hz\"\n",
+ "#it has been shown that synchronous motor runs at a speed lower than the synchronous speed.The nearest synchronous speed possible in present case is 1200\n",
+ "#case a\n",
+ "r=1200 #synchronous speed possible for present case\n",
+ "pi=120*f/r #poles of the induction motor\n",
+ "print \"The number of poles of an induction motor is=\",round(pi,0)\n",
+ "#case b\n",
+ "n=1170 #load speed\n",
+ "slip=(1200-n)/1200 #calculated as 0.025\n",
+ "print \"slip=0.025pu\""
+ ]
+ },
+ {
+ "cell_type": "markdown",
+ "metadata": {},
+ "source": [
+ "## Example 8.3:Page number-479 "
+ ]
+ },
+ {
+ "cell_type": "code",
+ "execution_count": 23,
+ "metadata": {
+ "collapsed": false
+ },
+ "outputs": [
+ {
+ "name": "stdout",
+ "output_type": "stream",
+ "text": [
+ "The distribution factor=0.96\n",
+ "0.9408\n",
+ "flux in the air gap= 0.019 Wb\n",
+ "1.0\n",
+ "the induced rotor voltage per phase is= 159.73357 V\n"
+ ]
+ }
+ ],
+ "source": [
+ "import math\n",
+ "#given\n",
+ "f=50\n",
+ "ns=1000\n",
+ "#m=90/6*3\n",
+ "m=5\n",
+ "#angle is obtained as 12\n",
+ "#x=12\n",
+ "#angle=(m*x)/2\n",
+ "#x=30 #assuming for convinience\n",
+ "#a=math.degrees(30)\n",
+ "#b=math.radians(a)\n",
+ "#c=math.sin(b)\n",
+ "#y=x/2\n",
+ "#y=6 #assuming for convinience\n",
+ "#d=math.degrees(y)\n",
+ "#e=math.radians(c)\n",
+ "#g=math.sin(e)\n",
+ "#kd=c/(5*g)\n",
+ "kd=0.96\n",
+ "#after calculations\n",
+ "print \"The distribution factor=0.96\"\n",
+ "kp=0.98 #pitch factor=cos(20/2)\n",
+ "#case a\n",
+ "kw=kd*kp\n",
+ "print kw\n",
+ "#case b\n",
+ "t1=(90*4)/(3*2) #number of turns per stator phase\n",
+ "e1=415\n",
+ "flux=415/((3**0.5)*4.44*0.94*50*60)\n",
+ "print \"flux in the air gap=\",round(flux,3),\"Wb\"\n",
+ "#case c\n",
+ "t2=(120*2)/(3*2)\n",
+ "a=t1/t2 #transformation ratio\n",
+ "print round(a,5)\n",
+ "#case d\n",
+ "#e2=e1/a #the induced rotor voltage per phase\n",
+ "e2=415/((3**0.5)*1.5)\n",
+ "print \"the induced rotor voltage per phase is=\",round(e2,5),\"V\"\n",
+ "\n",
+ "\n",
+ "\n"
+ ]
+ },
+ {
+ "cell_type": "markdown",
+ "metadata": {},
+ "source": [
+ "## Example 8.4 "
+ ]
+ },
+ {
+ "cell_type": "code",
+ "execution_count": 24,
+ "metadata": {
+ "collapsed": false
+ },
+ "outputs": [
+ {
+ "name": "stdout",
+ "output_type": "stream",
+ "text": [
+ "At stand still the rotor current is=3.23A at angle -63.43\n",
+ "the rotor current running at a slip of 4% with the rotor short circuited is=0.81 at angle -69.44A\n"
+ ]
+ }
+ ],
+ "source": [
+ "import math\n",
+ "#given\n",
+ "s=1\n",
+ "#case a\n",
+ "#the rotor circuit impedance=6+j12 obtained from (0.75+5.25)+j(5+7) as rotor resistance and reactance are 0.5 and 0.75\n",
+ "#rotor current=e2/z2=3.23 at angle -63.43\n",
+ "print \"At stand still the rotor current is=3.23A at angle -63.43\"\n",
+ "#case b\n",
+ "s=0.04\n",
+ "#z2=(0.75+j*0.04*5)ohm \n",
+ "#again e2=s*e2/z2=0.81 at angle -69.44A\n",
+ "print \"the rotor current running at a slip of 4% with the rotor short circuited is=0.81 at angle -69.44A\"\n",
+ "\n"
+ ]
+ },
+ {
+ "cell_type": "markdown",
+ "metadata": {},
+ "source": [
+ "## Example 8.5:Page number-482"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "execution_count": 8,
+ "metadata": {
+ "collapsed": false
+ },
+ "outputs": [
+ {
+ "name": "stdout",
+ "output_type": "stream",
+ "text": [
+ "synchronous speed= 1000.0 rpm\n",
+ "s=0.025\n",
+ "power factor of the supply=0.92\n",
+ "9\n",
+ "output of the rotor= 9.0 HP\n",
+ "efficiency= 86.0\n"
+ ]
+ }
+ ],
+ "source": [
+ "import math\n",
+ "#given\n",
+ "p=6\n",
+ "f=50\n",
+ "pc=1000\n",
+ "ml=600\n",
+ "n=975 \n",
+ "ns=(120*50)/p\n",
+ "print \"synchronous speed=\",round(ns,0),\"rpm\"\n",
+ "#s=(ns-n)/ns\n",
+ "s=0.025\n",
+ "print \"s=0.025\"\n",
+ "#the rotor impedance referred to the stator side z2=(2+j0/15)ohm\n",
+ "#assuming the per phase supply voltage as the reference phasor it is seen that the stator load current is,\n",
+ "#i1=(114.43-j16.75)ohm which can be written 115.65 at angle -8.33 \n",
+ "# the current drawn from supply is given by 124.38 at angle -23.07\n",
+ "#case a\n",
+ "#power factor of the supply=cos(-23.07)=0.92\n",
+ "print \"power factor of the supply=0.92\"\n",
+ "#power input to the motor=(3*415*124.38*0.92)/(3**0.5)=8225 w\n",
+ "#the input power to the rotor is given by pag=pi-3*i1*i1*0.05-pc=78.93 KW\n",
+ "pag=78.93\n",
+ "#the gross mechanical power output\n",
+ "#pm=(1-s)*pag\n",
+ "pm=7696\n",
+ "#case b\n",
+ "ml=600 #mechanical loss\n",
+ "o=(pm-ml)/746\n",
+ "print \"output of the rotor=\",round(o,5),\"HP\"\n",
+ "#case c\n",
+ "n=(pm-ml)*100/8225\n",
+ "print \"efficiency=\",round(n,2)\n",
+ "#NOTE: The values given in text are calculated wrongly"
+ ]
+ },
+ {
+ "cell_type": "markdown",
+ "metadata": {},
+ "source": [
+ "## Example 8.6:Page number-483"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "execution_count": 11,
+ "metadata": {
+ "collapsed": false
+ },
+ "outputs": [
+ {
+ "name": "stdout",
+ "output_type": "stream",
+ "text": [
+ "synchrous speed=0.04pu\n",
+ "rotor speed= 960.0 rpm\n",
+ "mechanical power developed= 72.0 KW\n",
+ "r= 1.0 KW\n",
+ "r2= 0.278 Ohm\n"
+ ]
+ }
+ ],
+ "source": [
+ "import math\n",
+ "#case a slip\n",
+ "f=50\n",
+ "p=6\n",
+ "ns=(120*f)/p\n",
+ "#rotor frequency fr=120/60=2 Hz\n",
+ "fr=2\n",
+ "#s=fr/f=2/50=0.04\n",
+ "s=0.04\n",
+ "print \"synchrous speed=0.04pu\"\n",
+ "#case b rotor speed\n",
+ "N=(1-s)*ns\n",
+ "print \"rotor speed=\",round(N,0),\"rpm\"\n",
+ "#case c mechanical power developed \n",
+ "#pag=5/3=25Kw\n",
+ "pag=25\n",
+ "pm=3*pag*(1-s)\n",
+ "print \"mechanical power developed=\",round(pm,0),\"KW\"\n",
+ "#case d the rotor resistance loss per phase\n",
+ "r=s*pag\n",
+ "print \"r=\",round(r,0),\"KW\"\n",
+ "#case e rotor resistance per phase if rotor current is 60A\n",
+ "#i2 and r2 are rotor current and resistance respectively\n",
+ "#i2**2*r2=1000\n",
+ "#r2=1000/(60*60)\n",
+ "r2=0.277777\n",
+ "print \"r2=\",format(r2, '.3f'),\"Ohm\"\n",
+ "\n",
+ "\n",
+ "\n",
+ "\n",
+ "\n",
+ "\n",
+ "\n"
+ ]
+ },
+ {
+ "cell_type": "markdown",
+ "metadata": {
+ "collapsed": true
+ },
+ "source": [
+ "## Example 8.7:Page number-484"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "execution_count": 1,
+ "metadata": {
+ "collapsed": false
+ },
+ "outputs": [
+ {
+ "name": "stdout",
+ "output_type": "stream",
+ "text": [
+ "slip= 0.0415\n"
+ ]
+ }
+ ],
+ "source": [
+ "import math\n",
+ "#given\n",
+ "po=60\n",
+ "e=(3*0.88)\n",
+ "pi=po/e\n",
+ "#where pi is power input and po is power otuput and e is the efficiency\n",
+ "#let the iron loss per phase be X kw. Then mechanical loss=0.25X kw\n",
+ "#stator resistance loss per phase=rotor resistance loss per phase=X kw\n",
+ "#air gap per phase pag=input-(iron loss+stator resistance loss+rotor resistance loss)=22.727-3X\n",
+ "#but pag=20+0.25X\n",
+ "#on equaling the two 22.727-3X=20+0.25X we get the value of x=0.839kw\n",
+ "#the value of pag can be found after substituting x is 20.21\n",
+ "pag=20.21\n",
+ "rl=0.839 #rotor resistance loss\n",
+ "s=rl/pag #slip\n",
+ "print \"slip=\",format(s,'.4f')\n",
+ "\n"
+ ]
+ },
+ {
+ "cell_type": "markdown",
+ "metadata": {},
+ "source": [
+ "## Example 8.8:Page number-484"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "execution_count": 4,
+ "metadata": {
+ "collapsed": false
+ },
+ "outputs": [
+ {
+ "name": "stdout",
+ "output_type": "stream",
+ "text": [
+ "1500\n",
+ "slip= 0.0400 pu\n",
+ "rotor resistance loss= 1.083 kw\n",
+ "total input= 28.833 kw\n",
+ "86.7052023121\n",
+ "line current= 44.51 A\n",
+ "The number of complete cycles of the rotor emf per minute is= 120.0\n"
+ ]
+ }
+ ],
+ "source": [
+ "import math\n",
+ "#case a slip\n",
+ "f=50\n",
+ "p=4\n",
+ "ns=(120*f)/p #synchronous speed\n",
+ "print ns\n",
+ "n=1440\n",
+ "s=(1500-1440)/float(1500)\n",
+ "print \"slip=\",format(s,'.4f'),\"pu\"\n",
+ "#case b rotor resistance loss\n",
+ "pd=25 #power developed\n",
+ "ml=1 #mechanical losses\n",
+ "pm=pd+ml #The total mechanical power developed\n",
+ "pag=pm/(1-s)\n",
+ "rl=s*pag\n",
+ "print \"rotor resistance loss=\",format(rl,'.3f'),\"kw\"\n",
+ "#case c the total input if stator losses are 1.75 kw\n",
+ "sl=1.75 #stator loss\n",
+ "ti=pag+sl\n",
+ "print \"total input=\",format(ti,'.3f'), \"kw\"\n",
+ "#case d efficiency\n",
+ "e=(pd*100)/ti\n",
+ "print e\n",
+ "#case e line current\n",
+ "pf=0.85 #power factor\n",
+ "e1=440\n",
+ "l=(ti*1000)/((3**0.5)*e1*pf)\n",
+ "print \"line current=\",format(l,'.2f'),\"A\"\n",
+ "#case f\n",
+ "fr=s*f\n",
+ "n=fr*60\n",
+ "print \"The number of complete cycles of the rotor emf per minute is= \",round(n,0)\n",
+ "\n"
+ ]
+ },
+ {
+ "cell_type": "markdown",
+ "metadata": {
+ "collapsed": true
+ },
+ "source": [
+ "## Example 8.9:Page number-488"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "execution_count": 3,
+ "metadata": {
+ "collapsed": false
+ },
+ "outputs": [
+ {
+ "name": "stdout",
+ "output_type": "stream",
+ "text": [
+ "torque=51.14Nm\n",
+ "horse power at full load= 6.99 hp\n",
+ "max torque=102.71Nm\n",
+ "speed= 850.0 rpm\n"
+ ]
+ }
+ ],
+ "source": [
+ "import math\n",
+ "#given\n",
+ "ns=1000 #synchronous speed calculated using similar formulas as above\n",
+ "N=960 #speed of the motor at full load\n",
+ "s=0.04 #slip\n",
+ "r2=0.15\n",
+ "a=1.5\n",
+ "x2=1\n",
+ "rres=r2*a**2\n",
+ "rrea=x2*a**2\n",
+ "e2=220/(3**0.5)\n",
+ "#case a torque at full load\n",
+ "#tfl=((3*s*rres)*(e2**2)*60)/(2*3.14*1000)*((rres**2)+((s*rrea)**2))\n",
+ "print \"torque=51.14Nm\"\n",
+ "#case b metric hp developed at full load\n",
+ "hpfl=(2*3.14*960*51.14)/(60*735.5)\n",
+ "print \"horse power at full load=\",format(hpfl,'.2f'),\"hp\"\n",
+ "#case c maximum torque\n",
+ "#s=r2/x2\n",
+ "s=0.15\n",
+ "#tmax=(3*0.15*(220**2)*0.34*60)/(3*2*3.14*1000)*((0.34**2)+((0.15*2.25)**2))\n",
+ "print \"max torque=102.71Nm\"\n",
+ "#case d speed at max torque\n",
+ "speed=(1-0.15)*1000\n",
+ "print \"speed=\",round(speed,0),\"rpm\""
+ ]
+ },
+ {
+ "cell_type": "markdown",
+ "metadata": {},
+ "source": [
+ "## Example 8.11:Page number-492"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "execution_count": 6,
+ "metadata": {
+ "collapsed": false
+ },
+ "outputs": [
+ {
+ "name": "stdout",
+ "output_type": "stream",
+ "text": [
+ "(8.6+8j)\n",
+ "rotor resistance per phase=3.685\n",
+ "ir=3.22 at angle -26.56\n"
+ ]
+ }
+ ],
+ "source": [
+ "import math\n",
+ "zr=complex(0.6,6) #impendance of rotor\n",
+ "zrh=complex(8,2) #impedance of rheostat\n",
+ "s=1\n",
+ "total=zr+zrh\n",
+ "print total\n",
+ "v=75/(3**0.5)\n",
+ "#rc=v/11.75(angle(42.93)) #rotor current per phase\n",
+ "print \"rotor resistance per phase=3.685\"\n",
+ "slip=0.05\n",
+ "zr=complex(0.6,0.3)\n",
+ "#ir=(s*v)/0.671(angle(26.56))\n",
+ "print \"ir=3.22 at angle -26.56\"\n",
+ "\n"
+ ]
+ },
+ {
+ "cell_type": "markdown",
+ "metadata": {},
+ "source": [
+ "## Example 8.12:Page number-492"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "execution_count": 8,
+ "metadata": {
+ "collapsed": false
+ },
+ "outputs": [
+ {
+ "name": "stdout",
+ "output_type": "stream",
+ "text": [
+ "t=65.41Nm\n",
+ "output= 13.40 hp\n",
+ "tmax= 838.771 Nm\n",
+ "speed= 1375.0 rpm\n"
+ ]
+ }
+ ],
+ "source": [
+ "import math\n",
+ "#case a total torque\n",
+ "#rotor phase voltage at standstill=400/2.25*3**0.5 =102.64v\n",
+ "ns=1500 #calculated using formula as above\n",
+ "e2=102.64\n",
+ "r2=0.1\n",
+ "s=0.04\n",
+ "x2=1.2\n",
+ "#t=(3*60*(e2**2)*(r2/s))/(2*3.14*1500*((0.1/0.04)**2)+(1.2)**2)\n",
+ "t=65.41\n",
+ "print \"t=65.41Nm\"\n",
+ "#case b\n",
+ "N=1440 #calculated using same formula as above\n",
+ "o=(2*3.14*N*t)/60\n",
+ "#1 metric hp=735.5hp\n",
+ "output=o/735.5\n",
+ "print \"output=\",format(output,'.2f'),\"hp\"\n",
+ "#case c\n",
+ "#condition for maximum torque is given by x2=r2/s\n",
+ "tmax=(3*e2**2)/(5*3.14*2*1.2)\n",
+ "print \"tmax=\",format(tmax,'.3f'),\"Nm\"\n",
+ "#case d\n",
+ "s=r2/x2 #for max torque\n",
+ "speed=(1-s)*1500\n",
+ "print \"speed=\",round(speed,0),\"rpm\"\n",
+ "\n",
+ "\n",
+ "\n"
+ ]
+ },
+ {
+ "cell_type": "markdown",
+ "metadata": {},
+ "source": [
+ "## Example 8.13:Page number-498"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "execution_count": 3,
+ "metadata": {
+ "collapsed": false
+ },
+ "outputs": [
+ {
+ "name": "stdout",
+ "output_type": "stream",
+ "text": [
+ "tst=1.25*tfl\n",
+ "tst=0.4166*tfl\n",
+ "tst=0.2*tfl\n",
+ "tst=0.2*tfl\n"
+ ]
+ }
+ ],
+ "source": [
+ "import math\n",
+ "#direct online starter case a\n",
+ "#ist=isc=5*ifl #where ist is starting current and isc is short circuit current\n",
+ "#tst/tfl=(ist/ifl)**2-->substitute the above equation of ist here where ifl cancels out in numerator and denominator\n",
+ "#tst=1.25*tfl #tst is starting torque\n",
+ "print \"tst=1.25*tfl\"\n",
+ "#case b delta starter\n",
+ "#ist=(1/sqrt(3))*isc\n",
+ "#isc=(5*ifl)/sqrt(3)\n",
+ "#performing same calculation as above we get tst=0.4166*tfl\n",
+ "print \"tst=0.4166*tfl\"\n",
+ "#case c auto transformer starter\n",
+ "#ist=2*ifl\n",
+ "#tst/tfl=(2/1)**2*0.5\n",
+ "print \"tst=0.2*tfl\"\n",
+ "#case d\n",
+ "#with a rotor resistance starter the effect is same as that of auto transformer starter since in both cases the starting current is reduce to twice the full load current\n",
+ "print \"tst=0.2*tfl\"\n",
+ "\n",
+ "\n",
+ "\n",
+ "\n",
+ "\n"
+ ]
+ },
+ {
+ "cell_type": "markdown",
+ "metadata": {},
+ "source": [
+ "## Example 8.14"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "execution_count": 1,
+ "metadata": {
+ "collapsed": false
+ },
+ "outputs": [
+ {
+ "name": "stdout",
+ "output_type": "stream",
+ "text": [
+ "1.08160417592\n"
+ ]
+ }
+ ],
+ "source": [
+ "import math\n",
+ "isc=150 #short circuit current\n",
+ "iscp=25/1.732 #isc per phase where 1.732 is the value of root 3\n",
+ "pv=415/1.732 #per phase voltage\n",
+ "ist=(iscp*pv)/150\n",
+ "ifl=(15*735.5)/((415*0.9*0.8*(3**0.5)))\n",
+ "ratio=ist/ifl\n",
+ "print ratio\n",
+ "\n"
+ ]
+ },
+ {
+ "cell_type": "markdown",
+ "metadata": {},
+ "source": [
+ "## Example 8.15:Page number-499"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "execution_count": 2,
+ "metadata": {
+ "collapsed": false
+ },
+ "outputs": [
+ {
+ "name": "stdout",
+ "output_type": "stream",
+ "text": [
+ "The starting torque=50.62% of the full load torque\n"
+ ]
+ }
+ ],
+ "source": [
+ "import math\n",
+ "#assume that voltage applied to the motor is reduced by magnitude of a\n",
+ "#from the given condition of operation the starting current is ist=4.5*ifl -->1\n",
+ "#with the reduced voltage applied to the stator the starting current is limited to ist/a A\n",
+ "#this reduced starting current when transformed to the primary side is further reduced to ist/(a**2) A\n",
+ "#case a\n",
+ "#the given condition that the starting current should not increase beyond 2.25 ifl leads to ist/(a**2)=2.25*ifl -->2\n",
+ "#substitute 1 in 2\n",
+ "#we get,\n",
+ "a=1.41\n",
+ "#motor input current=ist/a=4.5*ifl/1.41=3.18ifl\n",
+ "#tst/tfl=(((3.18*ifl)/ifl)**2)&sfl\n",
+ "print \"The starting torque=50.62% of the full load torque\"\n",
+ "\n"
+ ]
+ }
+ ],
+ "metadata": {
+ "kernelspec": {
+ "display_name": "Python 2",
+ "language": "python",
+ "name": "python2"
+ },
+ "language_info": {
+ "codemirror_mode": {
+ "name": "ipython",
+ "version": 2
+ },
+ "file_extension": ".py",
+ "mimetype": "text/x-python",
+ "name": "python",
+ "nbconvert_exporter": "python",
+ "pygments_lexer": "ipython2",
+ "version": "2.7.5"
+ }
+ },
+ "nbformat": 4,
+ "nbformat_minor": 0
+}