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authorkinitrupti2017-05-12 18:53:46 +0530
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-{
- "cells": [
- {
- "cell_type": "markdown",
- "metadata": {},
- "source": [
- "# Chapter 19:Electromagnetic Induction"
- ]
- },
- {
- "cell_type": "markdown",
- "metadata": {},
- "source": [
- "## Ex19.1:pg-938"
- ]
- },
- {
- "cell_type": "code",
- "execution_count": 0,
- "metadata": {
- "collapsed": false
- },
- "outputs": [],
- "source": [
- " #Example 19_1\n",
- " \n",
- " \n",
- " #To find the flux in the room\n",
- "l=4 #Units in meters\n",
- "b=0.8 #Units in meters\n",
- "theta=20 #Units in degrees\n",
- "a=l*b #Units in meters**2\n",
- "b=4*10**-5 #Units in T\n",
- "thetaa=math.cos(theta*math.pi/180) #Units in radians\n",
- "phi=b*thetaa*a #Units in T meters**2\n",
- "print \"The flux in the room is Phi=\",round( ,5),\" T meters**2\",phi)\n"
- ]
- },
- {
- "cell_type": "markdown",
- "metadata": {},
- "source": [
- "## Ex19.2:pg-939"
- ]
- },
- {
- "cell_type": "code",
- "execution_count": 0,
- "metadata": {
- "collapsed": false
- },
- "outputs": [],
- "source": [
- " #Example 19_2\n",
- " \n",
- " \n",
- " #To find how large is the average EMF induced\n",
- "b=0.5 #Units in T\n",
- "a=4*10**-4 #Units in meters**2\n",
- "phi2=b*a #Units in Wb\n",
- "phi1=0 #Units in Wb\n",
- "deltaPHI=phi2-phi1 #Units in Wb\n",
- "n=100 #Units in Constant\n",
- "deltaT=2*10**-2 #Units in sec\n",
- "emf=(n*deltaPHI)/deltaT #Units in V\n",
- "print \"The average emf Induced is emf=\",round( ),\" V\",emf)\n"
- ]
- },
- {
- "cell_type": "markdown",
- "metadata": {},
- "source": [
- "## Ex19.3:pg-939"
- ]
- },
- {
- "cell_type": "code",
- "execution_count": 0,
- "metadata": {
- "collapsed": false
- },
- "outputs": [],
- "source": [
- " #Example 19_3\n",
- " \n",
- " \n",
- " #To findout how large an emf is generated\n",
- "m=0.5 #Units in H\n",
- "i=1 #Units in A\n",
- "t=0.01 #Units in sec\n",
- "emf=m*(i/t) #Units in V\n",
- "print \"The emf generated is emf=\",round( ),\" V\",emf)\n"
- ]
- },
- {
- "cell_type": "markdown",
- "metadata": {},
- "source": [
- "## Ex19.4:pg-939"
- ]
- },
- {
- "cell_type": "code",
- "execution_count": 0,
- "metadata": {
- "collapsed": false
- },
- "outputs": [],
- "source": [
- " #Example 19_4\n",
- " \n",
- " \n",
- " #To Calculate the value of selfinductance\n",
- "print \"The Self Inductance is L=Uo*n**2*D*A\")\n"
- ]
- },
- {
- "cell_type": "markdown",
- "metadata": {},
- "source": [
- "## Ex19.5:pg-939"
- ]
- },
- {
- "cell_type": "code",
- "execution_count": 0,
- "metadata": {
- "collapsed": false
- },
- "outputs": [],
- "source": [
- " #Example 19_5\n",
- " \n",
- " \n",
- " #To find the time constant of the circuit and the final energy stored\n",
- "l=0.5 #Units in H\n",
- "r1=2 #Units in Ohms\n",
- "r2=4 #Units in Ohms\n",
- "r=r1+r2 #Units in Ohms\n",
- "l_r=l/r #Units in sec\n",
- "i=2 #Units in A\n",
- "ene=0.5*l*i**2\n",
- "print \"The time constant is L/R=\",round( ,4),\" Sec\\n The energy stored is=\",round( ),\" J\",l_r,ene)\n"
- ]
- },
- {
- "cell_type": "markdown",
- "metadata": {},
- "source": [
- "## Ex19.6:pg-940"
- ]
- },
- {
- "cell_type": "code",
- "execution_count": 2,
- "metadata": {
- "collapsed": false
- },
- "outputs": [
- {
- "name": "stdout",
- "output_type": "stream",
- "text": [
- "The emf induced in the rod is emf= 0.000542 V\n"
- ]
- }
- ],
- "source": [
- " #Example 19_6\n",
- "import math \n",
- "#To find the emf induced in the rod\n",
- "b=0.6*10**-4 #Units in T\n",
- "v=3 #Units in meters/sec\n",
- "d=5 #Units in meters\n",
- "theta=53 #Units in degrees\n",
- "thetaa=math.cos(theta*math.pi/180) #Units in radians\n",
- "emf=b*v*d*thetaa #Units in V\n",
- "print \"The emf induced in the rod is emf=\",round(emf,6),\" V\"\n"
- ]
- },
- {
- "cell_type": "markdown",
- "metadata": {},
- "source": [
- "## Ex19.7:pg-940"
- ]
- },
- {
- "cell_type": "code",
- "execution_count": 3,
- "metadata": {
- "collapsed": false
- },
- "outputs": [
- {
- "name": "stdout",
- "output_type": "stream",
- "text": [
- "The back emf developed is EMF= 104.0 V\n"
- ]
- }
- ],
- "source": [
- " #Example 19_7\n",
- " \n",
- " \n",
- "#To calculate the Back emf developed\n",
- "i=3 #Units in A\n",
- "r=2.0 #Units in Ohms\n",
- "v=110.0 #Units in Ohms\n",
- "e=v-(i*r) #Units in V\n",
- "print \"The back emf developed is EMF=\",round(e),\" V\"\n"
- ]
- }
- ],
- "metadata": {
- "kernelspec": {
- "display_name": "Python 2",
- "language": "python",
- "name": "python2"
- },
- "language_info": {
- "codemirror_mode": {
- "name": "ipython",
- "version": 2
- },
- "file_extension": ".py",
- "mimetype": "text/x-python",
- "name": "python",
- "nbconvert_exporter": "python",
- "pygments_lexer": "ipython2",
- "version": "2.7.11"
- }
- },
- "nbformat": 4,
- "nbformat_minor": 0
-}