removing problem statements

1 files changed, 327 insertions, 39 deletions

diff --git a/_Programming_With_C/chapter10.ipynb b/_Programming_With_C/chapter10.ipynb
index 083baffa..ea2e1985 100644
--- a/_Programming_With_C/chapter10.ipynb
+++ b/_Programming_With_C/chapter10.ipynb
@@ -1,6 +1,7 @@
 {
  "metadata": {
-  "name": "chapter10"
+  "name": "",
+  "signature": "sha256:3323f7a9a077b84fffdd30478d4b0d0b7f4032b86670a58b5b333d42bee04f15"
  },
  "nbformat": 3,
  "nbformat_minor": 0,
@@ -10,24 +11,33 @@
     {
      "cell_type": "markdown",
      "metadata": {},
-     "source": "<h1>Chapter 10: Strings<h1> "
+     "source": [
+      "<h1>Chapter 10: Strings<h1> "
+     ]
     },
     {
      "cell_type": "markdown",
      "metadata": {},
-     "source": "<h3>Example 10.3, Page Number: 10.3<h3>"
+     "source": [
+      "<h3>Example 10.3, Page Number: 10.3<h3>"
+     ]
     },
     {
      "cell_type": "code",
      "collapsed": false,
-     "input": "st='Programming'\nprint 'The string is %s' %st",
+     "input": [
+      "st='Programming'\n",
+      "print 'The string is %s' %st"
+     ],
      "language": "python",
      "metadata": {},
      "outputs": [
       {
        "output_type": "stream",
        "stream": "stdout",
-       "text": "The string is Programming\n"
+       "text": [
+        "The string is Programming\n"
+       ]
       }
      ],
      "prompt_number": 4
@@ -35,19 +45,28 @@
     {
      "cell_type": "markdown",
      "metadata": {},
-     "source": "<h3>Example 10.4, Page Number: 10.4<h3>"
+     "source": [
+      "<h3>Example 10.4, Page Number: 10.4<h3>"
+     ]
     },
     {
      "cell_type": "code",
      "collapsed": false,
-     "input": "st='Hello World'\nprint 'The line is :'\nprint st",
+     "input": [
+      "st='Hello World'\n",
+      "print 'The line is :'\n",
+      "print st"
+     ],
      "language": "python",
      "metadata": {},
      "outputs": [
       {
        "output_type": "stream",
        "stream": "stdout",
-       "text": "The line is :\nHello World\n"
+       "text": [
+        "The line is :\n",
+        "Hello World\n"
+       ]
       }
      ],
      "prompt_number": 5
@@ -55,19 +74,29 @@
     {
      "cell_type": "markdown",
      "metadata": {},
-     "source": "<h3>Example 10.6, Page Number: 10.5<h3>"
+     "source": [
+      "<h3>Example 10.6, Page Number: 10.5<h3>"
+     ]
     },
     {
      "cell_type": "code",
      "collapsed": false,
-     "input": "#display the string character by character\n\nstrin='Welcome to python'\nfor i in strin:\n    print i,",
+     "input": [
+      "\n",
+      "\n",
+      "strin='Welcome to python'\n",
+      "for i in strin:\n",
+      "    print i,"
+     ],
      "language": "python",
      "metadata": {},
      "outputs": [
       {
        "output_type": "stream",
        "stream": "stdout",
-       "text": "W e l c o m e   t o   p y t h o n\n"
+       "text": [
+        "W e l c o m e   t o   p y t h o n\n"
+       ]
       }
      ],
      "prompt_number": 6
@@ -75,19 +104,48 @@
     {
      "cell_type": "markdown",
      "metadata": {},
-     "source": "<h3>Example 10.7, Page Number: 10.6<h3>"
+     "source": [
+      "<h3>Example 10.7, Page Number: 10.6<h3>"
+     ]
     },
     {
      "cell_type": "code",
      "collapsed": false,
-     "input": "# to demonstrate the use of operators related function\n\nstr1='Programming'\nlen1=len(str1)\nprint 'The length of the string is ',len1\n\nstr2=str1\nprint 'First string is %s and copied string is %s' %(str1,str2)\n\nstr3='Computer'\n\nif str1==str3:\n    print 'Both strings are equal'\nelif str1<str2:\n    print 'First string is lesser than second string'\nelse:\n    print 'First string is greater than second string'\n    \ntempstr=' with C'\nstr1=str1+tempstr\nprint 'The concated string is ',str1\n",
+     "input": [
+      "\n",
+      "\n",
+      "str1='Programming'\n",
+      "len1=len(str1)\n",
+      "print 'The length of the string is ',len1\n",
+      "\n",
+      "str2=str1\n",
+      "print 'First string is %s and copied string is %s' %(str1,str2)\n",
+      "\n",
+      "str3='Computer'\n",
+      "\n",
+      "if str1==str3:\n",
+      "    print 'Both strings are equal'\n",
+      "elif str1<str2:\n",
+      "    print 'First string is lesser than second string'\n",
+      "else:\n",
+      "    print 'First string is greater than second string'\n",
+      "    \n",
+      "tempstr=' with C'\n",
+      "str1=str1+tempstr\n",
+      "print 'The concated string is ',str1\n"
+     ],
      "language": "python",
      "metadata": {},
      "outputs": [
       {
        "output_type": "stream",
        "stream": "stdout",
-       "text": "The length of the string is  11\nFirst string is Programming and copied string is Programming\nFirst string is greater than second string\nThe concated string is  Programming with C\n"
+       "text": [
+        "The length of the string is  11\n",
+        "First string is Programming and copied string is Programming\n",
+        "First string is greater than second string\n",
+        "The concated string is  Programming with C\n"
+       ]
       }
      ],
      "prompt_number": 7
@@ -95,19 +153,48 @@
     {
      "cell_type": "markdown",
      "metadata": {},
-     "source": "<h3>Example 10.8,Page Number: 10.7<h3>"
+     "source": [
+      "<h3>Example 10.8,Page Number: 10.7<h3>"
+     ]
     },
     {
      "cell_type": "code",
      "collapsed": false,
-     "input": "# user defined function for string length and string copy\n\ndef strlength(str1):\n    count=0\n    for i in str1:\n        count+=1\n    \n    return count\ndef strcopy(src):\n    dst=[]\n    for i in src:\n        dst.append(i)\n        \n    dst=''.join(dst)\n        \n    return dst\n\n\nstr1='New Delhi'\nlen1=strlength(str1)\nprint 'The length of the string is ',len1\n\nstr2=strcopy(str1)\nprint 'First string is %s and copied string is %s' %(str1,str2)\n",
+     "input": [
+      "\n",
+      "def strlength(str1):\n",
+      "    count=0\n",
+      "    for i in str1:\n",
+      "        count+=1\n",
+      "    \n",
+      "    return count\n",
+      "def strcopy(src):\n",
+      "    dst=[]\n",
+      "    for i in src:\n",
+      "        dst.append(i)\n",
+      "        \n",
+      "    dst=''.join(dst)\n",
+      "        \n",
+      "    return dst\n",
+      "\n",
+      "\n",
+      "str1='New Delhi'\n",
+      "len1=strlength(str1)\n",
+      "print 'The length of the string is ',len1\n",
+      "\n",
+      "str2=strcopy(str1)\n",
+      "print 'First string is %s and copied string is %s' %(str1,str2)\n"
+     ],
      "language": "python",
      "metadata": {},
      "outputs": [
       {
        "output_type": "stream",
        "stream": "stdout",
-       "text": "The length of the string is  9\nFirst string is New Delhi and copied string is New Delhi\n"
+       "text": [
+        "The length of the string is  9\n",
+        "First string is New Delhi and copied string is New Delhi\n"
+       ]
       }
      ],
      "prompt_number": 8
@@ -115,19 +202,53 @@
     {
      "cell_type": "markdown",
      "metadata": {},
-     "source": "<h3>Example 10.9,Page Number: 10.9<h3>"
+     "source": [
+      "<h3>Example 10.9,Page Number: 10.9<h3>"
+     ]
     },
     {
      "cell_type": "code",
      "collapsed": false,
-     "input": "# A user defined implementation of comparison of two strings\n\ndef strcompare(str1,str2):\n    \n    len1=len(str1)\n    len2=len(str2)\n    \n    if len1<len2:\n        length=len1\n    else:\n        length=len2\n        \n    for i in xrange(0,length):\n        if str1[i]<str2[i]:\n            return -1\n        elif str1[i]>str2[i]:\n            return 1\n    \n    return 0\n\nstr1='Programming'\nstr2='Computer'\nstatus=strcompare(str1,str2)\nif status==-1:\n    print 'First string is lesser than second string'\nelif status==1:\n    print 'First string is greater than second string'\nelse:\n    print 'Both strings ae equal'\n",
+     "input": [
+      "\n",
+      "\n",
+      "def strcompare(str1,str2):\n",
+      "    \n",
+      "    len1=len(str1)\n",
+      "    len2=len(str2)\n",
+      "    \n",
+      "    if len1<len2:\n",
+      "        length=len1\n",
+      "    else:\n",
+      "        length=len2\n",
+      "        \n",
+      "    for i in xrange(0,length):\n",
+      "        if str1[i]<str2[i]:\n",
+      "            return -1\n",
+      "        elif str1[i]>str2[i]:\n",
+      "            return 1\n",
+      "    \n",
+      "    return 0\n",
+      "\n",
+      "str1='Programming'\n",
+      "str2='Computer'\n",
+      "status=strcompare(str1,str2)\n",
+      "if status==-1:\n",
+      "    print 'First string is lesser than second string'\n",
+      "elif status==1:\n",
+      "    print 'First string is greater than second string'\n",
+      "else:\n",
+      "    print 'Both strings ae equal'\n"
+     ],
      "language": "python",
      "metadata": {},
      "outputs": [
       {
        "output_type": "stream",
        "stream": "stdout",
-       "text": "First string is greater than second string\n"
+       "text": [
+        "First string is greater than second string\n"
+       ]
       }
      ],
      "prompt_number": 9
@@ -135,19 +256,42 @@
     {
      "cell_type": "markdown",
      "metadata": {},
-     "source": "<h3>Example 10.10, Page Number: 10.10<h3>"
+     "source": [
+      "<h3>Example 10.10, Page Number: 10.10<h3>"
+     ]
     },
     {
      "cell_type": "code",
      "collapsed": false,
-     "input": "# Left as well as right concatenation of two strings\n\ndef leftconcat(dst,src):\n    dst=src+dst\n    return dst\n\ndef rightconcat(dst,src):\n    dst=dst+src\n    return dst\n\nstr1='Hello'\nstr2='Friends'\n\ntempstr=leftconcat(str2,str1)\nprint 'The first string after left concatenation becomes ', tempstr\n\ntempstr=rightconcat(str2,str1)\nprint 'The first string after right concatenation becomes', tempstr\n",
+     "input": [
+      "\n",
+      "def leftconcat(dst,src):\n",
+      "    dst=src+dst\n",
+      "    return dst\n",
+      "\n",
+      "def rightconcat(dst,src):\n",
+      "    dst=dst+src\n",
+      "    return dst\n",
+      "\n",
+      "str1='Hello'\n",
+      "str2='Friends'\n",
+      "\n",
+      "tempstr=leftconcat(str2,str1)\n",
+      "print 'The first string after left concatenation becomes ', tempstr\n",
+      "\n",
+      "tempstr=rightconcat(str2,str1)\n",
+      "print 'The first string after right concatenation becomes', tempstr\n"
+     ],
      "language": "python",
      "metadata": {},
      "outputs": [
       {
        "output_type": "stream",
        "stream": "stdout",
-       "text": "The first string after left concatenation becomes  HelloFriends\nThe first string after right concatenation becomes FriendsHello\n"
+       "text": [
+        "The first string after left concatenation becomes  HelloFriends\n",
+        "The first string after right concatenation becomes FriendsHello\n"
+       ]
       }
      ],
      "prompt_number": 10
@@ -155,19 +299,34 @@
     {
      "cell_type": "markdown",
      "metadata": {},
-     "source": "<h3>Example 10.11,Page Numbr: 10.12<h3>"
+     "source": [
+      "<h3>Example 10.11,Page Numbr: 10.12<h3>"
+     ]
     },
     {
      "cell_type": "code",
      "collapsed": false,
-     "input": "# program to count total number of vowel in a given text\n\nstr1='All good boys have bread'\ncount=0\n\nfor i in str1:\n    if i=='a' or i=='e'or i=='i' or i=='o' or i=='u' or i=='A' or i=='E' or i=='I' or i=='O' or i=='U' :\n        count+=1\n        \nprint 'Total number of vowels in a given text are ',count",
+     "input": [
+      "\n",
+      "\n",
+      "str1='All good boys have bread'\n",
+      "count=0\n",
+      "\n",
+      "for i in str1:\n",
+      "    if i=='a' or i=='e'or i=='i' or i=='o' or i=='u' or i=='A' or i=='E' or i=='I' or i=='O' or i=='U' :\n",
+      "        count+=1\n",
+      "        \n",
+      "print 'Total number of vowels in a given text are ',count"
+     ],
      "language": "python",
      "metadata": {},
      "outputs": [
       {
        "output_type": "stream",
        "stream": "stdout",
-       "text": "Total number of vowels in a given text are  8\n"
+       "text": [
+        "Total number of vowels in a given text are  8\n"
+       ]
       }
      ],
      "prompt_number": 11
@@ -175,19 +334,44 @@
     {
      "cell_type": "markdown",
      "metadata": {},
-     "source": "<h3>Example 10.12, Page Number: 10.13<h3>"
+     "source": [
+      "<h3>Example 10.12, Page Number: 10.13<h3>"
+     ]
     },
     {
      "cell_type": "code",
      "collapsed": false,
-     "input": "# Character arithmetic examples\n\nch1='A'\nch2=ord(ch1)+3\nprint chr(ch2)\n\nch1=chr(ord(ch1)+1)\nprint ch1\n\nprint ord('a')\nprint ord('l')\n\nval=ord(ch1)*ch2\nprint val\n\nprint chr(100)",
+     "input": [
+      "\n",
+      "ch1='A'\n",
+      "ch2=ord(ch1)+3\n",
+      "print chr(ch2)\n",
+      "\n",
+      "ch1=chr(ord(ch1)+1)\n",
+      "print ch1\n",
+      "\n",
+      "print ord('a')\n",
+      "print ord('l')\n",
+      "\n",
+      "val=ord(ch1)*ch2\n",
+      "print val\n",
+      "\n",
+      "print chr(100)"
+     ],
      "language": "python",
      "metadata": {},
      "outputs": [
       {
        "output_type": "stream",
        "stream": "stdout",
-       "text": "D\nB\n97\n108\n4488\nd\n"
+       "text": [
+        "D\n",
+        "B\n",
+        "97\n",
+        "108\n",
+        "4488\n",
+        "d\n"
+       ]
       }
      ],
      "prompt_number": 12
@@ -195,19 +379,39 @@
     {
      "cell_type": "markdown",
      "metadata": {},
-     "source": "<h3>Example 10.13, Page Number: 10.13<h3>"
+     "source": [
+      "<h3>Example 10.13, Page Number: 10.13<h3>"
+     ]
     },
     {
      "cell_type": "code",
      "collapsed": false,
-     "input": "# Program to convert lowercase alphabets to uppercase in a given text\n\ntext='I am studying 6 Theory Papers & 4 practicals'\n\nlen1=len(text)\ntext=list(text)\nfor i in xrange(0,len1):\n    if text[i]>='a' and text[i]<='z':\n        text[i]=chr(ord(text[i])+ord('A')-ord('a'))\n        \n    \ntext=''.join(text)\n\nprint 'The text after converting lowercase alphabets to uppercase is '\nprint text",
+     "input": [
+      "\n",
+      "text='I am studying 6 Theory Papers & 4 practicals'\n",
+      "\n",
+      "len1=len(text)\n",
+      "text=list(text)\n",
+      "for i in xrange(0,len1):\n",
+      "    if text[i]>='a' and text[i]<='z':\n",
+      "        text[i]=chr(ord(text[i])+ord('A')-ord('a'))\n",
+      "        \n",
+      "    \n",
+      "text=''.join(text)\n",
+      "\n",
+      "print 'The text after converting lowercase alphabets to uppercase is '\n",
+      "print text"
+     ],
      "language": "python",
      "metadata": {},
      "outputs": [
       {
        "output_type": "stream",
        "stream": "stdout",
-       "text": "The text after converting lowercase alphabets to uppercase is \nI AM STUDYING 6 THEORY PAPERS & 4 PRACTICALS\n"
+       "text": [
+        "The text after converting lowercase alphabets to uppercase is \n",
+        "I AM STUDYING 6 THEORY PAPERS & 4 PRACTICALS\n"
+       ]
       }
      ],
      "prompt_number": 13
@@ -215,19 +419,45 @@
     {
      "cell_type": "markdown",
      "metadata": {},
-     "source": "<h3>Example 10.14, Page Number: 10.14<h3>"
+     "source": [
+      "<h3>Example 10.14, Page Number: 10.14<h3>"
+     ]
     },
     {
      "cell_type": "code",
      "collapsed": false,
-     "input": "# Program to search for a substring in a given string\n\ntext='The programming is a systematic process'\nsubstr='pro'\ntext_len=len(text)\nsub_len=len(substr)\ntext=list(text)\nsubstr=list(substr)\n\nfor i in xrange(0,text_len-sub_len+1):\n    \n    for j in xrange(0,sub_len):\n        \n        if text[i+j]==substr[j]:\n            continue\n        else:\n            break\n        \n    if j==sub_len-1:\n        print 'The substring is present from subscript %d onwards' %i\n            \n",
+     "input": [
+      "\n",
+      "text='The programming is a systematic process'\n",
+      "substr='pro'\n",
+      "text_len=len(text)\n",
+      "sub_len=len(substr)\n",
+      "text=list(text)\n",
+      "substr=list(substr)\n",
+      "\n",
+      "for i in xrange(0,text_len-sub_len+1):\n",
+      "    \n",
+      "    for j in xrange(0,sub_len):\n",
+      "        \n",
+      "        if text[i+j]==substr[j]:\n",
+      "            continue\n",
+      "        else:\n",
+      "            break\n",
+      "        \n",
+      "    if j==sub_len-1:\n",
+      "        print 'The substring is present from subscript %d onwards' %i\n",
+      "            \n"
+     ],
      "language": "python",
      "metadata": {},
      "outputs": [
       {
        "output_type": "stream",
        "stream": "stdout",
-       "text": "The substring is present from subscript 4 onwards\nThe substring is present from subscript 32 onwards\n"
+       "text": [
+        "The substring is present from subscript 4 onwards\n",
+        "The substring is present from subscript 32 onwards\n"
+       ]
       }
      ],
      "prompt_number": 14
@@ -235,19 +465,77 @@
     {
      "cell_type": "markdown",
      "metadata": {},
-     "source": "<h3>Example 10.15,Page number: 10.15<h3>"
+     "source": [
+      "<h3>Example 10.15,Page number: 10.15<h3>"
+     ]
     },
     {
      "cell_type": "code",
      "collapsed": false,
-     "input": "# Reordering a list of strings\n\n\ndef reorder(x):\n\n    n=len(x)\n    for item in range(0,n-1):\n        for i in range(item+1,n):\n            if x[item]>x[i]:\n                temp=x[item]\n                x[item]=x[i]\n                x[i]=temp\n\n\n    return\n\nx=['PACIFIC','ATLANTIC','INDIAN','CARIBBEAN','BERING','BLACK','RED','NORTH','BALTIC','CASPIAN']\nprint 'Original list of strings :\\n\\n'\n\nfor i in x:\n    print \"String : \",i\n\nreorder(x)\n\nprint \"\\nReodered list of strings : \\n\\n\"\n\nfor i in x:\n    print \"String : \",i\n",
+     "input": [
+      "\n",
+      "\n",
+      "def reorder(x):\n",
+      "\n",
+      "    n=len(x)\n",
+      "    for item in range(0,n-1):\n",
+      "        for i in range(item+1,n):\n",
+      "            if x[item]>x[i]:\n",
+      "                temp=x[item]\n",
+      "                x[item]=x[i]\n",
+      "                x[i]=temp\n",
+      "\n",
+      "\n",
+      "    return\n",
+      "\n",
+      "x=['PACIFIC','ATLANTIC','INDIAN','CARIBBEAN','BERING','BLACK','RED','NORTH','BALTIC','CASPIAN']\n",
+      "print 'Original list of strings :\\n\\n'\n",
+      "\n",
+      "for i in x:\n",
+      "    print \"String : \",i\n",
+      "\n",
+      "reorder(x)\n",
+      "\n",
+      "print \"\\nReodered list of strings : \\n\\n\"\n",
+      "\n",
+      "for i in x:\n",
+      "    print \"String : \",i\n"
+     ],
      "language": "python",
      "metadata": {},
      "outputs": [
       {
        "output_type": "stream",
        "stream": "stdout",
-       "text": "Original list of strings :\n\n\nString :  PACIFIC\nString :  ATLANTIC\nString :  INDIAN\nString :  CARIBBEAN\nString :  BERING\nString :  BLACK\nString :  RED\nString :  NORTH\nString :  BALTIC\nString :  CASPIAN\n\nReodered list of strings : \n\n\nString :  ATLANTIC\nString :  BALTIC\nString :  BERING\nString :  BLACK\nString :  CARIBBEAN\nString :  CASPIAN\nString :  INDIAN\nString :  NORTH\nString :  PACIFIC\nString :  RED\n"
+       "text": [
+        "Original list of strings :\n",
+        "\n",
+        "\n",
+        "String :  PACIFIC\n",
+        "String :  ATLANTIC\n",
+        "String :  INDIAN\n",
+        "String :  CARIBBEAN\n",
+        "String :  BERING\n",
+        "String :  BLACK\n",
+        "String :  RED\n",
+        "String :  NORTH\n",
+        "String :  BALTIC\n",
+        "String :  CASPIAN\n",
+        "\n",
+        "Reodered list of strings : \n",
+        "\n",
+        "\n",
+        "String :  ATLANTIC\n",
+        "String :  BALTIC\n",
+        "String :  BERING\n",
+        "String :  BLACK\n",
+        "String :  CARIBBEAN\n",
+        "String :  CASPIAN\n",
+        "String :  INDIAN\n",
+        "String :  NORTH\n",
+        "String :  PACIFIC\n",
+        "String :  RED\n"
+       ]
       }
      ],
      "prompt_number": 15
@@ -255,7 +543,7 @@
     {
      "cell_type": "code",
      "collapsed": false,
-     "input": "",
+     "input": [],
      "language": "python",
      "metadata": {},
      "outputs": [],