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author | hardythe1 | 2015-06-03 15:27:17 +0530 |
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committer | hardythe1 | 2015-06-03 15:27:17 +0530 |
commit | df60071cf1d1c18822d34f943ab8f412a8946b69 (patch) | |
tree | ab059cf19bad4a1233a464ccf5d72cf8b3fb323c /_A_Textbook_Of_Engineering_Physics/Chapter19.ipynb | |
parent | fba055ce5aa0955e22bac2413c33493b10ae6532 (diff) | |
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diff --git a/_A_Textbook_Of_Engineering_Physics/Chapter19.ipynb b/_A_Textbook_Of_Engineering_Physics/Chapter19.ipynb new file mode 100755 index 00000000..9cd6b0d3 --- /dev/null +++ b/_A_Textbook_Of_Engineering_Physics/Chapter19.ipynb @@ -0,0 +1,103 @@ +{
+ "metadata": {
+ "name": "",
+ "signature": "sha256:e62a104ff81010a41974070c37970149915a1689606735dc017583e29241aaa5"
+ },
+ "nbformat": 3,
+ "nbformat_minor": 0,
+ "worksheets": [
+ {
+ "cells": [
+ {
+ "cell_type": "heading",
+ "level": 1,
+ "metadata": {},
+ "source": [
+ "Chapter19-PN-Junction Diode"
+ ]
+ },
+ {
+ "cell_type": "heading",
+ "level": 2,
+ "metadata": {},
+ "source": [
+ "Ex1-pg571"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "import math\n",
+ "##Example 19.1\n",
+ "##calculation of potential barrier\n",
+ "\n",
+ "##given values\n",
+ "e=1.6*10**-19.;\n",
+ "n=4.4*10**28.;##no of atoms per m**3\n",
+ "kT=.026*e;##temp eqvlnt at room temp\n",
+ "ni=2.4*10**19.;##no of intrinsic carriers per m**3\n",
+ "NA=n/10**6.;##no of acceptors\n",
+ "ND=n/10**6.;##no of donors\n",
+ "\n",
+ "##calculation\n",
+ "V=(kT/e)*math.log(NA*ND/ni**2);\n",
+ "print'%s %.2f %s'%('potential barrier in volts is',V,'');\n"
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "potential barrier in volts is 0.39 \n"
+ ]
+ }
+ ],
+ "prompt_number": 1
+ },
+ {
+ "cell_type": "heading",
+ "level": 2,
+ "metadata": {},
+ "source": [
+ "Ex2-pg578"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "import math\n",
+ "##Example 19.2\n",
+ "##calculation of current\n",
+ "\n",
+ "##given values\n",
+ "e=1.6*10**-19.;\n",
+ "kT=.026*e;##temp eqvlnt at room temp\n",
+ "Io=2*10**-7;##current flowing at room temp in A\n",
+ "V=.1;##forward bias voltage in volts\n",
+ "\n",
+ "##calculation\n",
+ "I=Io*(math.e**(e*V/kT)-1);##in Ampere\n",
+ "print'%s %.2f %s'%('current flowing when forward bias applied(in microampere)is',I*10**6,'');\n"
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "current flowing when forward bias applied(in microampere)is 9.16 \n"
+ ]
+ }
+ ],
+ "prompt_number": 2
+ }
+ ],
+ "metadata": {}
+ }
+ ]
+}
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