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-{

- "metadata": {

-  "name": ""

- },

- "nbformat": 3,

- "nbformat_minor": 0,

- "worksheets": [

-  {

-   "cells": [

-    {

-     "cell_type": "heading",

-     "level": 1,

-     "metadata": {},

-     "source": [

-      "Chapter 12: Thermodynamic Property Relations"

-     ]

-    },

-    {

-     "cell_type": "heading",

-     "level": 2,

-     "metadata": {},

-     "source": [

-      "Example 12-1 ,Page No.652"

-     ]

-    },

-    {

-     "cell_type": "code",

-     "collapsed": false,

-     "input": [

-      "#from Table A-17\n",

-      "#cp value approximately by replacing the differentials\n",

-      "h1=305.22;#in kJ/kg\n",

-      "T1=305;#in K\n",

-      "h2=295.17;#in kJ/kg\n",

-      "T2=295;#in K\n",

-      "\n",

-      "#calculations\n",

-      "#from the given equation we can calculate\n",

-      "cp=(h1-h2)/(T1-T2);\n",

-      "print'the cp of air at 300 K %f kJ/ kg - K'%round(cp,3)"

-     ],

-     "language": "python",

-     "metadata": {},

-     "outputs": [

-      {

-       "output_type": "stream",

-       "stream": "stdout",

-       "text": [

-        "the cp of air at 300 K 1.005000 kJ/ kg - K\n"

-       ]

-      }

-     ],

-     "prompt_number": 2

-    },

-    {

-     "cell_type": "heading",

-     "level": 2,

-     "metadata": {},

-     "source": [

-      "Example 12-2 ,Page No.654"

-     ]

-    },

-    {

-     "cell_type": "code",

-     "collapsed": false,

-     "input": [

-      "#given data\n",

-      "dT=302-300;#differnce in final and intial temperatures of air in K\n",

-      "dv=0.87-0.86;#differnce in final and intial volumnes of air in m^3/kg\n",

-      "T=(302+300)/2;#average temp in K\n",

-      "v=(0.87+0.86)/2;#average volumne in m^3/kg\n",

-      "\n",

-      "#constants used\n",

-      "R=0.287;#in kJ/kg-K\n",

-      "\n",

-      "#calculations\n",

-      "#using eq 12-3 by diffrentiating P= R*T/v\n",

-      "dP= R*dT/v - R*T*dv/v**2;\n",

-      "print'the change in the pressure of air %f kPa'%round(dP,3)"

-     ],

-     "language": "python",

-     "metadata": {},

-     "outputs": [

-      {

-       "output_type": "stream",

-       "stream": "stdout",

-       "text": [

-        "the change in the pressure of air -0.491000 kPa\n"

-       ]

-      }

-     ],

-     "prompt_number": 4

-    },

-    {

-     "cell_type": "heading",

-     "level": 2,

-     "metadata": {},

-     "source": [

-      "Example 12-5 ,Page No.659"

-     ]

-    },

-    {

-     "cell_type": "code",

-     "collapsed": false,

-     "input": [

-      "#given data\n",

-      "T=20+273.15;#temperature of refrigerant in K\n",

-      "\n",

-      "#from Table A\u201311\n",

-      "vf=0.0008161;#in m^3/kg\n",

-      "vg=0.035969;#in m^3/kg\n",

-      "\n",

-      "#calculations\n",

-      "#using Eq 12-22\n",

-      "# hfg= T*vfg*(dP/dT)sat\n",

-      "#(dP/dT)sat b/w 24 C - 16 C \n",

-      "dPT=(646.18-504.58)/(24-16);#dP/dT ; values from Table A\u201311\n",

-      "vfg=vg-vf;\n",

-      "hfg=T*vfg*dPT;\n",

-      "print'the value of the enthalpy of vaporization of refrigerant-134a %f kJ/kg'%round(hfg,2)"

-     ],

-     "language": "python",

-     "metadata": {},

-     "outputs": [

-      {

-       "output_type": "stream",

-       "stream": "stdout",

-       "text": [

-        "the value of the enthalpy of vaporization of refrigerant-134a 182.400000 kJ/kg\n"

-       ]

-      }

-     ],

-     "prompt_number": 5

-    },

-    {

-     "cell_type": "heading",

-     "level": 2,

-     "metadata": {},

-     "source": [

-      "Example 12-6 ,Page No.660"

-     ]

-    },

-    {

-     "cell_type": "code",

-     "collapsed": false,

-     "input": [

-      "from math import exp\n",

-      "\n",

-      "#given data\n",

-      "T2=-50+460.0;#temperature of refrigerant-134a on R \n",

-      "\n",

-      "#constants\n",

-      "R=0.01946;#in Btu/lbm\n",

-      "\n",

-      "#from Table A-11E\n",

-      "T1=-40+460.0;#converted into R from F\n",

-      "P1=7.432;\n",

-      "hfg=97.100;\n",

-      "\n",

-      "#calcualation\\\n",

-      "#using Equation 12\u201324\n",

-      "#ln(P2/P1)= hfg/R *(1/T1 - 1/T2)\n",

-      "P2=P1*exp(hfg/R *(1/T1 - 1/T2));\n",

-      "print'the saturation pressure of refrigerant-134a %f psia'%round(P2,2)"

-     ],

-     "language": "python",

-     "metadata": {},

-     "outputs": [

-      {

-       "output_type": "stream",

-       "stream": "stdout",

-       "text": [

-        "the saturation pressure of refrigerant-134a 5.560000 psia\n"

-       ]

-      }

-     ],

-     "prompt_number": 7

-    },

-    {

-     "cell_type": "heading",

-     "level": 2,

-     "metadata": {},

-     "source": [

-      "Example 12-11 ,Page No.373"

-     ]

-    },

-    {

-     "cell_type": "code",

-     "collapsed": false,

-     "input": [

-      "from math import log\n",

-      "\n",

-      "#given data\n",

-      "T1=220;#intial temperature in K\n",

-      "P1=5;#intial pressure in MPa\n",

-      "T2=300;#final temperature in K\n",

-      "P2=10;#final pressure in MPa\n",

-      "\n",

-      "#constants used\n",

-      "Ru=8.314;#on kJ/kmol- K\n",

-      "\n",

-      "#from Table A\u20131\n",

-      "Tcr=154.8;\n",

-      "Pcr=5.08;\n",

-      "\n",

-      "#calculations\n",

-      "\n",

-      "#part - a\n",

-      "print('part - a');\n",

-      "#by assuming ideal-gas behavior\n",

-      "#from Table A\u201319\n",

-      "h1=6404;\n",

-      "h2=8736;\n",

-      "s2=205.213;\n",

-      "s1=196.171;\n",

-      "h21i=h2-h1;#h2 - h1 ideal\n",

-      "s21i=(s2-s1)-Ru*log(P2/P1);#s2 - s1 ideal\n",

-      "print'the enthalpy change %i kJ/kmol'%round(h21i);\n",

-      "print'the entropy change %f kJ/kmol-K'%round(s21i,2);\n",

-      "\n",

-      "#part - b\n",

-      "print('part - b');\n",

-      "#by accounting for the deviation from ideal-gas behavior\n",

-      "TR1=T1/Tcr;\n",

-      "Pr1=P1/Pcr;\n",

-      "#from the generalized charts at each state\n",

-      "Zh1=0.53;\n",

-      "Zs1=0.25;\n",

-      "TR2=T2/Tcr;\n",

-      "Pr2=P2/Pcr;\n",

-      "#from the generalized charts at each state\n",

-      "Zh2=0.48;\n",

-      "Zs2=0.20;\n",

-      "h21=h21i-Ru*Tcr*(Zh2-Zh1);\n",

-      "s21=s21i-Ru*(Zs2-Zs1);\n",

-      "print'the enthalpy change %i in kJ/kmol'%round(h21);\n",

-      "print'the entropy change %f kJ/kmol-K'%round(s21,2);\n",

-      "\n"

-     ],

-     "language": "python",

-     "metadata": {},

-     "outputs": [

-      {

-       "output_type": "stream",

-       "stream": "stdout",

-       "text": [

-        "part - a\n",

-        "the enthalpy change 2332 kJ/kmol\n",

-        "the entropy change 3.280000 kJ/kmol-K\n",

-        "part - b\n",

-        "the enthalpy change 2396 in kJ/kmol\n",

-        "the entropy change 3.690000 kJ/kmol-K\n"

-       ]

-      }

-     ],

-     "prompt_number": 1

-    }

-   ],

-   "metadata": {}

-  }

- ]

-}
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