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author: hardythe1 2015-05-05 14:21:39 +0530
committer: hardythe1 2015-05-05 14:21:39 +0530
commit: fba055ce5aa0955e22bac2413c33493b10ae6532 (patch)
tree: be70ef4fccd07c9c88de778014219201b4ea971f /Thermodynamics:_From_concepts_to_applications
parent: 67068710030ddd6b6c809518c34af2e04e0bf7ca (diff)
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78 files changed, 125 insertions, 19534 deletions
diff --git a/Thermodynamics:_From_concepts_to_applications/Chapter10.ipynb b/Thermodynamics:_From_concepts_to_applications/Chapter10.ipynb
deleted file mode 100755
index b5e1628e..00000000
--- a/Thermodynamics:_From_concepts_to_applications/Chapter10.ipynb
+++ /dev/null
@@ -1,173 +0,0 @@
-{
- "metadata": {
-  "name": "",
-  "signature": "sha256:2af45763cdabb4c15384bcd3c0f85ef0384f4698a0a51376cf62b1a662fc76dc"
- },
- "nbformat": 3,
- "nbformat_minor": 0,
- "worksheets": [
-  {
-   "cells": [
-    {
-     "cell_type": "heading",
-     "level": 1,
-     "metadata": {},
-     "source": [
-      "Chapter10-Availbility,exergy and irreversibilitiy"
-     ]
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Example1-pg 180"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "#calculate work of the water and heat interaction of the water and aximum work done\n",
-      "##initialisation of variables\n",
-      "m= 2 ##kg\n",
-      "p= 200 ##kPa\n",
-      "v2= 0.9596 ##m^3/kg\n",
-      "v1= 0.001 ##m^3/kg\n",
-      "u2= 2768.8 ##kJ/kg\n",
-      "u1= 83.96 ##kJ/kg\n",
-      "T= 20 ##C\n",
-      "u3= 2576.9 ##kJ/kg\n",
-      "s2= 7.2795 ##kJ/kg K\n",
-      "s1= 0.2966 ##kJ/kg K\n",
-      "Tr= 150 ##C\n",
-      "##CALCULATIONS\n",
-      "W= m*p*(v2-v1)\n",
-      "Q= m*(u2-u1)\n",
-      "A= m*((u3-u1)-(273.15+T)*(s2-s1))\n",
-      "Ar= -Q*(1-((273.15+T)/(273.15+Tr)))\n",
-      "Wrep= -(A+Ar)\n",
-      "##RESULTS\n",
-      "print'%s %.1f %s'%('work of the water =',W,'kJ')\n",
-      "print'%s %.1f %s'% ('Heat interaction of the water =',Q,'kJ')\n",
-      "print'%s %.1f %s'%('maximum work done =',Wrep,'kJ')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "work of the water = 383.4 kJ\n",
-        "Heat interaction of the water = 5369.7 kJ\n",
-        "maximum work done = 757.9 kJ\n"
-       ]
-      }
-     ],
-     "prompt_number": 1
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Example2-pg 182"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "#calculate irreversibility of the processes\n",
-      "##initialisation of variables\n",
-      "Wrev= 757.8 ##kJ\n",
-      "W= 383.4 ##kJ\n",
-      "m= 2 ##kg\n",
-      "s2= 7.2795 ##kJ/kg K\n",
-      "s1= 0.2966  ##kJ/kg K\n",
-      "Qr= 5369.7 ##kJ\n",
-      "T= 150 ##C\n",
-      "T0= 20 ##C\n",
-      "##CALCULATIONS\n",
-      "I= Wrev-W\n",
-      "dS= m*(s2-s1)\n",
-      "Sr= -Qr/(273.15+T)\n",
-      "I1= (273.15+T0)*(dS+Sr)\n",
-      "##RESULTS\n",
-      "print'%s %.1f %s'%('Irreversibility of the process=',I1,'kJ')\n",
-      "\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "Irreversibility of the process= 374.1 kJ\n"
-       ]
-      }
-     ],
-     "prompt_number": 3
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Example7-pg192"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "#calculate mass flow rates and wmax and irreversibility\n",
-      "import math\n",
-      "##initialisation of variables\n",
-      "h3= 2793.2 ##kJ/kg\n",
-      "h2= 1342.3 ##kJ/kg\n",
-      "h1= 2993.5 ##kJ/kg\n",
-      "m3= 2.5 ##kg/s\n",
-      "b1= 1043.9 ##kJ/kg\n",
-      "b2= 374.24 ##kJ/kg\n",
-      "b3= 875.41 ##kJ/kg\n",
-      "##CALCULATIONS\n",
-      "m1= m3*((h3-h2)/(h1-h2))\n",
-      "m2= m3*((h3-h1)/(h2-h1))\n",
-      "Bin= (m1*b1+m2*b2)\n",
-      "Bout= m3*b3\n",
-      "B= Bin-Bout\n",
-      "Wmax= B\n",
-      "I= B\n",
-      "##RESULTS\n",
-      "print'%s %.3f %s'%('mass flow rate=',m1,'kg/s')\n",
-      "print'%s %.3f %s'%('mass flow rate=',m2,'kg/s')\n",
-      "print'%s %.3f %s'%('Wmax=',Wmax,'kg/s')\n",
-      "print'%s %.1f %s'%('Irreversibility=',Wmax,'kW')\n",
-      "\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "mass flow rate= 2.197 kg/s\n",
-        "mass flow rate= 0.303 kg/s\n",
-        "Wmax= 218.141 kg/s\n",
-        "Irreversibility= 218.1 kW\n"
-       ]
-      }
-     ],
-     "prompt_number": 7
-    }
-   ],
-   "metadata": {}
-  }
- ]
-}
-\ No newline at end of file
diff --git a/Thermodynamics:_From_concepts_to_applications/Chapter10_1.ipynb b/Thermodynamics:_From_concepts_to_applications/Chapter10_1.ipynb
deleted file mode 100755
index b5e1628e..00000000
--- a/Thermodynamics:_From_concepts_to_applications/Chapter10_1.ipynb
+++ /dev/null
@@ -1,173 +0,0 @@
-{
- "metadata": {
-  "name": "",
-  "signature": "sha256:2af45763cdabb4c15384bcd3c0f85ef0384f4698a0a51376cf62b1a662fc76dc"
- },
- "nbformat": 3,
- "nbformat_minor": 0,
- "worksheets": [
-  {
-   "cells": [
-    {
-     "cell_type": "heading",
-     "level": 1,
-     "metadata": {},
-     "source": [
-      "Chapter10-Availbility,exergy and irreversibilitiy"
-     ]
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Example1-pg 180"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "#calculate work of the water and heat interaction of the water and aximum work done\n",
-      "##initialisation of variables\n",
-      "m= 2 ##kg\n",
-      "p= 200 ##kPa\n",
-      "v2= 0.9596 ##m^3/kg\n",
-      "v1= 0.001 ##m^3/kg\n",
-      "u2= 2768.8 ##kJ/kg\n",
-      "u1= 83.96 ##kJ/kg\n",
-      "T= 20 ##C\n",
-      "u3= 2576.9 ##kJ/kg\n",
-      "s2= 7.2795 ##kJ/kg K\n",
-      "s1= 0.2966 ##kJ/kg K\n",
-      "Tr= 150 ##C\n",
-      "##CALCULATIONS\n",
-      "W= m*p*(v2-v1)\n",
-      "Q= m*(u2-u1)\n",
-      "A= m*((u3-u1)-(273.15+T)*(s2-s1))\n",
-      "Ar= -Q*(1-((273.15+T)/(273.15+Tr)))\n",
-      "Wrep= -(A+Ar)\n",
-      "##RESULTS\n",
-      "print'%s %.1f %s'%('work of the water =',W,'kJ')\n",
-      "print'%s %.1f %s'% ('Heat interaction of the water =',Q,'kJ')\n",
-      "print'%s %.1f %s'%('maximum work done =',Wrep,'kJ')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "work of the water = 383.4 kJ\n",
-        "Heat interaction of the water = 5369.7 kJ\n",
-        "maximum work done = 757.9 kJ\n"
-       ]
-      }
-     ],
-     "prompt_number": 1
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Example2-pg 182"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "#calculate irreversibility of the processes\n",
-      "##initialisation of variables\n",
-      "Wrev= 757.8 ##kJ\n",
-      "W= 383.4 ##kJ\n",
-      "m= 2 ##kg\n",
-      "s2= 7.2795 ##kJ/kg K\n",
-      "s1= 0.2966  ##kJ/kg K\n",
-      "Qr= 5369.7 ##kJ\n",
-      "T= 150 ##C\n",
-      "T0= 20 ##C\n",
-      "##CALCULATIONS\n",
-      "I= Wrev-W\n",
-      "dS= m*(s2-s1)\n",
-      "Sr= -Qr/(273.15+T)\n",
-      "I1= (273.15+T0)*(dS+Sr)\n",
-      "##RESULTS\n",
-      "print'%s %.1f %s'%('Irreversibility of the process=',I1,'kJ')\n",
-      "\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "Irreversibility of the process= 374.1 kJ\n"
-       ]
-      }
-     ],
-     "prompt_number": 3
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Example7-pg192"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "#calculate mass flow rates and wmax and irreversibility\n",
-      "import math\n",
-      "##initialisation of variables\n",
-      "h3= 2793.2 ##kJ/kg\n",
-      "h2= 1342.3 ##kJ/kg\n",
-      "h1= 2993.5 ##kJ/kg\n",
-      "m3= 2.5 ##kg/s\n",
-      "b1= 1043.9 ##kJ/kg\n",
-      "b2= 374.24 ##kJ/kg\n",
-      "b3= 875.41 ##kJ/kg\n",
-      "##CALCULATIONS\n",
-      "m1= m3*((h3-h2)/(h1-h2))\n",
-      "m2= m3*((h3-h1)/(h2-h1))\n",
-      "Bin= (m1*b1+m2*b2)\n",
-      "Bout= m3*b3\n",
-      "B= Bin-Bout\n",
-      "Wmax= B\n",
-      "I= B\n",
-      "##RESULTS\n",
-      "print'%s %.3f %s'%('mass flow rate=',m1,'kg/s')\n",
-      "print'%s %.3f %s'%('mass flow rate=',m2,'kg/s')\n",
-      "print'%s %.3f %s'%('Wmax=',Wmax,'kg/s')\n",
-      "print'%s %.1f %s'%('Irreversibility=',Wmax,'kW')\n",
-      "\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "mass flow rate= 2.197 kg/s\n",
-        "mass flow rate= 0.303 kg/s\n",
-        "Wmax= 218.141 kg/s\n",
-        "Irreversibility= 218.1 kW\n"
-       ]
-      }
-     ],
-     "prompt_number": 7
-    }
-   ],
-   "metadata": {}
-  }
- ]
-}
-\ No newline at end of file
diff --git a/Thermodynamics:_From_concepts_to_applications/Chapter10_2.ipynb b/Thermodynamics:_From_concepts_to_applications/Chapter10_2.ipynb
deleted file mode 100755
index b5e1628e..00000000
--- a/Thermodynamics:_From_concepts_to_applications/Chapter10_2.ipynb
+++ /dev/null
@@ -1,173 +0,0 @@
-{
- "metadata": {
-  "name": "",
-  "signature": "sha256:2af45763cdabb4c15384bcd3c0f85ef0384f4698a0a51376cf62b1a662fc76dc"
- },
- "nbformat": 3,
- "nbformat_minor": 0,
- "worksheets": [
-  {
-   "cells": [
-    {
-     "cell_type": "heading",
-     "level": 1,
-     "metadata": {},
-     "source": [
-      "Chapter10-Availbility,exergy and irreversibilitiy"
-     ]
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Example1-pg 180"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "#calculate work of the water and heat interaction of the water and aximum work done\n",
-      "##initialisation of variables\n",
-      "m= 2 ##kg\n",
-      "p= 200 ##kPa\n",
-      "v2= 0.9596 ##m^3/kg\n",
-      "v1= 0.001 ##m^3/kg\n",
-      "u2= 2768.8 ##kJ/kg\n",
-      "u1= 83.96 ##kJ/kg\n",
-      "T= 20 ##C\n",
-      "u3= 2576.9 ##kJ/kg\n",
-      "s2= 7.2795 ##kJ/kg K\n",
-      "s1= 0.2966 ##kJ/kg K\n",
-      "Tr= 150 ##C\n",
-      "##CALCULATIONS\n",
-      "W= m*p*(v2-v1)\n",
-      "Q= m*(u2-u1)\n",
-      "A= m*((u3-u1)-(273.15+T)*(s2-s1))\n",
-      "Ar= -Q*(1-((273.15+T)/(273.15+Tr)))\n",
-      "Wrep= -(A+Ar)\n",
-      "##RESULTS\n",
-      "print'%s %.1f %s'%('work of the water =',W,'kJ')\n",
-      "print'%s %.1f %s'% ('Heat interaction of the water =',Q,'kJ')\n",
-      "print'%s %.1f %s'%('maximum work done =',Wrep,'kJ')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "work of the water = 383.4 kJ\n",
-        "Heat interaction of the water = 5369.7 kJ\n",
-        "maximum work done = 757.9 kJ\n"
-       ]
-      }
-     ],
-     "prompt_number": 1
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Example2-pg 182"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "#calculate irreversibility of the processes\n",
-      "##initialisation of variables\n",
-      "Wrev= 757.8 ##kJ\n",
-      "W= 383.4 ##kJ\n",
-      "m= 2 ##kg\n",
-      "s2= 7.2795 ##kJ/kg K\n",
-      "s1= 0.2966  ##kJ/kg K\n",
-      "Qr= 5369.7 ##kJ\n",
-      "T= 150 ##C\n",
-      "T0= 20 ##C\n",
-      "##CALCULATIONS\n",
-      "I= Wrev-W\n",
-      "dS= m*(s2-s1)\n",
-      "Sr= -Qr/(273.15+T)\n",
-      "I1= (273.15+T0)*(dS+Sr)\n",
-      "##RESULTS\n",
-      "print'%s %.1f %s'%('Irreversibility of the process=',I1,'kJ')\n",
-      "\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "Irreversibility of the process= 374.1 kJ\n"
-       ]
-      }
-     ],
-     "prompt_number": 3
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Example7-pg192"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "#calculate mass flow rates and wmax and irreversibility\n",
-      "import math\n",
-      "##initialisation of variables\n",
-      "h3= 2793.2 ##kJ/kg\n",
-      "h2= 1342.3 ##kJ/kg\n",
-      "h1= 2993.5 ##kJ/kg\n",
-      "m3= 2.5 ##kg/s\n",
-      "b1= 1043.9 ##kJ/kg\n",
-      "b2= 374.24 ##kJ/kg\n",
-      "b3= 875.41 ##kJ/kg\n",
-      "##CALCULATIONS\n",
-      "m1= m3*((h3-h2)/(h1-h2))\n",
-      "m2= m3*((h3-h1)/(h2-h1))\n",
-      "Bin= (m1*b1+m2*b2)\n",
-      "Bout= m3*b3\n",
-      "B= Bin-Bout\n",
-      "Wmax= B\n",
-      "I= B\n",
-      "##RESULTS\n",
-      "print'%s %.3f %s'%('mass flow rate=',m1,'kg/s')\n",
-      "print'%s %.3f %s'%('mass flow rate=',m2,'kg/s')\n",
-      "print'%s %.3f %s'%('Wmax=',Wmax,'kg/s')\n",
-      "print'%s %.1f %s'%('Irreversibility=',Wmax,'kW')\n",
-      "\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "mass flow rate= 2.197 kg/s\n",
-        "mass flow rate= 0.303 kg/s\n",
-        "Wmax= 218.141 kg/s\n",
-        "Irreversibility= 218.1 kW\n"
-       ]
-      }
-     ],
-     "prompt_number": 7
-    }
-   ],
-   "metadata": {}
-  }
- ]
-}
-\ No newline at end of file
diff --git a/Thermodynamics:_From_concepts_to_applications/Chapter10_Availbility,exergy_and_irreversibilitiy.ipynb b/Thermodynamics:_From_concepts_to_applications/Chapter10_Availbility,exergy_and_irreversibilitiy.ipynb
deleted file mode 100755
index b5e1628e..00000000
--- a/Thermodynamics:_From_concepts_to_applications/Chapter10_Availbility,exergy_and_irreversibilitiy.ipynb
+++ /dev/null
@@ -1,173 +0,0 @@
-{
- "metadata": {
-  "name": "",
-  "signature": "sha256:2af45763cdabb4c15384bcd3c0f85ef0384f4698a0a51376cf62b1a662fc76dc"
- },
- "nbformat": 3,
- "nbformat_minor": 0,
- "worksheets": [
-  {
-   "cells": [
-    {
-     "cell_type": "heading",
-     "level": 1,
-     "metadata": {},
-     "source": [
-      "Chapter10-Availbility,exergy and irreversibilitiy"
-     ]
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Example1-pg 180"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "#calculate work of the water and heat interaction of the water and aximum work done\n",
-      "##initialisation of variables\n",
-      "m= 2 ##kg\n",
-      "p= 200 ##kPa\n",
-      "v2= 0.9596 ##m^3/kg\n",
-      "v1= 0.001 ##m^3/kg\n",
-      "u2= 2768.8 ##kJ/kg\n",
-      "u1= 83.96 ##kJ/kg\n",
-      "T= 20 ##C\n",
-      "u3= 2576.9 ##kJ/kg\n",
-      "s2= 7.2795 ##kJ/kg K\n",
-      "s1= 0.2966 ##kJ/kg K\n",
-      "Tr= 150 ##C\n",
-      "##CALCULATIONS\n",
-      "W= m*p*(v2-v1)\n",
-      "Q= m*(u2-u1)\n",
-      "A= m*((u3-u1)-(273.15+T)*(s2-s1))\n",
-      "Ar= -Q*(1-((273.15+T)/(273.15+Tr)))\n",
-      "Wrep= -(A+Ar)\n",
-      "##RESULTS\n",
-      "print'%s %.1f %s'%('work of the water =',W,'kJ')\n",
-      "print'%s %.1f %s'% ('Heat interaction of the water =',Q,'kJ')\n",
-      "print'%s %.1f %s'%('maximum work done =',Wrep,'kJ')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "work of the water = 383.4 kJ\n",
-        "Heat interaction of the water = 5369.7 kJ\n",
-        "maximum work done = 757.9 kJ\n"
-       ]
-      }
-     ],
-     "prompt_number": 1
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Example2-pg 182"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "#calculate irreversibility of the processes\n",
-      "##initialisation of variables\n",
-      "Wrev= 757.8 ##kJ\n",
-      "W= 383.4 ##kJ\n",
-      "m= 2 ##kg\n",
-      "s2= 7.2795 ##kJ/kg K\n",
-      "s1= 0.2966  ##kJ/kg K\n",
-      "Qr= 5369.7 ##kJ\n",
-      "T= 150 ##C\n",
-      "T0= 20 ##C\n",
-      "##CALCULATIONS\n",
-      "I= Wrev-W\n",
-      "dS= m*(s2-s1)\n",
-      "Sr= -Qr/(273.15+T)\n",
-      "I1= (273.15+T0)*(dS+Sr)\n",
-      "##RESULTS\n",
-      "print'%s %.1f %s'%('Irreversibility of the process=',I1,'kJ')\n",
-      "\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "Irreversibility of the process= 374.1 kJ\n"
-       ]
-      }
-     ],
-     "prompt_number": 3
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Example7-pg192"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "#calculate mass flow rates and wmax and irreversibility\n",
-      "import math\n",
-      "##initialisation of variables\n",
-      "h3= 2793.2 ##kJ/kg\n",
-      "h2= 1342.3 ##kJ/kg\n",
-      "h1= 2993.5 ##kJ/kg\n",
-      "m3= 2.5 ##kg/s\n",
-      "b1= 1043.9 ##kJ/kg\n",
-      "b2= 374.24 ##kJ/kg\n",
-      "b3= 875.41 ##kJ/kg\n",
-      "##CALCULATIONS\n",
-      "m1= m3*((h3-h2)/(h1-h2))\n",
-      "m2= m3*((h3-h1)/(h2-h1))\n",
-      "Bin= (m1*b1+m2*b2)\n",
-      "Bout= m3*b3\n",
-      "B= Bin-Bout\n",
-      "Wmax= B\n",
-      "I= B\n",
-      "##RESULTS\n",
-      "print'%s %.3f %s'%('mass flow rate=',m1,'kg/s')\n",
-      "print'%s %.3f %s'%('mass flow rate=',m2,'kg/s')\n",
-      "print'%s %.3f %s'%('Wmax=',Wmax,'kg/s')\n",
-      "print'%s %.1f %s'%('Irreversibility=',Wmax,'kW')\n",
-      "\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "mass flow rate= 2.197 kg/s\n",
-        "mass flow rate= 0.303 kg/s\n",
-        "Wmax= 218.141 kg/s\n",
-        "Irreversibility= 218.1 kW\n"
-       ]
-      }
-     ],
-     "prompt_number": 7
-    }
-   ],
-   "metadata": {}
-  }
- ]
-}
-\ No newline at end of file
diff --git a/Thermodynamics:_From_concepts_to_applications/Chapter11.ipynb b/Thermodynamics:_From_concepts_to_applications/Chapter11.ipynb
deleted file mode 100755
index 35f097c3..00000000
--- a/Thermodynamics:_From_concepts_to_applications/Chapter11.ipynb
+++ /dev/null
@@ -1,468 +0,0 @@
-{
- "metadata": {
-  "name": "",
-  "signature": "sha256:a15297e2995d0ee44a3db61bf50b4aac4f8b03ecce59bf2a69c1f32113289b28"
- },
- "nbformat": 3,
- "nbformat_minor": 0,
- "worksheets": [
-  {
-   "cells": [
-    {
-     "cell_type": "heading",
-     "level": 1,
-     "metadata": {},
-     "source": [
-      "Chapter11-power and refrigeration cycles"
-     ]
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Example1-pg 203"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "#calculate enthalpy and effieceny and carnot efficency\n",
-      "##initialisation of variables\n",
-      "h1= 251.4 ##kJ/kg\n",
-      "v= 0.001017 ##m^3/kg\n",
-      "p2= 2000. ##Mpa\n",
-      "p1= 20. ##Mpa\n",
-      "h2= 253.4\n",
-      "h3= 3247.6 ##kJ/kg\n",
-      "h4= 2349.3 ##kJ/kg\n",
-      "Tc= 60.06 ##C\n",
-      "Th= 400. ##C\n",
-      "##CALCULATIONS\n",
-      "h2= h1+v*(2-p1)\n",
-      "q12= 0.\n",
-      "w12= h1-h2\n",
-      "q23= h3-h2\n",
-      "w23= 0.\n",
-      "q34= 0.\n",
-      "w34= h3-h4\n",
-      "q41= h1-h4\n",
-      "qnet= q12+q23+q34+q41\n",
-      "wnet= w12+w23+w34\n",
-      "n= wnet/q23\n",
-      "ncarnot= 1-((273.15+Tc)/(273.15+Th))\n",
-      "##RESULTS\n",
-      "print'%s %.1f %s'%('enthalpy=',h2,'kJ/kg')\n",
-      "print'%s %.3f %s'%('efficiency=',n,'')\n",
-      "print'%s %.3f %s'%('carnot efficiency=',ncarnot,'')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "enthalpy= 251.4 kJ/kg\n",
-        "efficiency= 0.300 \n",
-        "carnot efficiency= 0.505 \n"
-       ]
-      }
-     ],
-     "prompt_number": 2
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Example2-pg206"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "#calculate work and heat and effiecency and steam mass flow rate\n",
-      "##initialisation of variables\n",
-      "h3= 3247.4 ##kJ/kg\n",
-      "h4= 2439.1 ##kJ/kg\n",
-      "h1= 251.4 ##kJ/kg\n",
-      "h2= 253.9 ##kJ/kg\n",
-      "P= 100000 ##kW\n",
-      "##CALCULATIONS\n",
-      "wnet= h3-h4+h1-h2\n",
-      "qh= h3-h2\n",
-      "qc= h1-h4\n",
-      "n= wnet/qh\n",
-      "m= P/wnet\n",
-      "##RESULTS\n",
-      "print'%s %.f %s'%('work=',wnet,'kJ/kg')\n",
-      "print'%s %.1f %s'% ('heat=',qh,'kJ/kg')\n",
-      "print'%s %.1f %s'%('heat=',qc,'kJ/kg')\n",
-      "print'%s %.4f %s'%('efficiency=',n,'')\n",
-      "print'%s %.2f %s'%('steam mass flow rate=',m,'kg/s')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "work= 806 kJ/kg\n",
-        "heat= 2993.5 kJ/kg\n",
-        "heat= -2187.7 kJ/kg\n",
-        "efficiency= 0.2692 \n",
-        "steam mass flow rate= 124.10 kg/s\n"
-       ]
-      }
-     ],
-     "prompt_number": 3
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Example3-pg 208"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "#calculate qualitys and efficiency and mass flow rate and diameter\n",
-      "##initialisation of variables\n",
-      "h11= 2786.2 ##kJ/kg\n",
-      "h12= 340.5 ##kJ/kg\n",
-      "h7= 327.9 ##kJ/kg\n",
-      "h6= 169.0 ##kJ/kg\n",
-      "h10= 756.7 ##kJ/kg\n",
-      "h9= 480.9 ##kJkg\n",
-      "h14= 2818 ##kJ.kg\n",
-      "h15= 762.8 ##kJ/kg\n",
-      "h8= 462.7 ##kJ/kg\n",
-      "h13= 2974.5 ##kJ/kg\n",
-      "h5= 168.8 ##kJ/kg\n",
-      "P= 150. ##kW\n",
-      "v1= 0.02293 ##m^3/kg\n",
-      "v= 40. ##m/s\n",
-      "h1= 3448.6 ##kJ/kg\n",
-      "h3= 3478.5 ##kJ/kg\n",
-      "h2= 2818 ##kJ/kg\n",
-      "h4= 2527.1 ##kJ/kg\n",
-      "##CALCULATIONS\n",
-      "y1= (h10-h9)/(h14-h15)\n",
-      "y2= ((h8-h7)-y1*(h15-h7))/(h13-h7)\n",
-      "y3= (h7-h6)*(1-y1-y2)/(h11-h12)\n",
-      "qin= h1-h10+(1-y1)*(h3-h2)\n",
-      "qout= (h5-h4)*(1-y1-y2)+y3*(h4-h12)\n",
-      "wnet= qin+qout\n",
-      "n= wnet*100/qin\n",
-      "m1= P*1000/wnet\n",
-      "A1= m1*v1/v\n",
-      "D= math.sqrt(4*A1/math.pi)\n",
-      "##RESULTS\n",
-      "print'%s %.4f %s'%(' quality=',y1,'')\n",
-      "print'%s %.4f %s'%('quality=',y2,'')\n",
-      "print'%s %.4f %s'%('quality=',y3,'')\n",
-      "print'%s %.2f %s'%('efficiency=',n,'percent')\n",
-      "print'%s %.2f %s'%('mass flow rate=',m1,'kg/s')\n",
-      "print'%s %.3f %s'%(' diameter=',D,'m')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        " quality= 0.1342 \n",
-        "quality= 0.0289 \n",
-        "quality= 0.0544 \n",
-        "efficiency= 43.17 percent\n",
-        "mass flow rate= 106.46 kg/s\n",
-        " diameter= 0.279 m\n"
-       ]
-      }
-     ],
-     "prompt_number": 4
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Example4-pg 213"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "#calculate effieciency and power and temperature at the exist\n",
-      "##initialisation of variables\n",
-      "T= 300. ##K\n",
-      "P= 100. ##kPa\n",
-      "r= 4.\n",
-      "T1= 1200. ##K\n",
-      "m= 5. ##kg/s\n",
-      "k= 1.4\n",
-      "R= 8.314 ##jmol K\n",
-      "M= 29. ##gms\n",
-      "##CALCULATIONS\n",
-      "T2= T*math.pow(r,(k-1)/k)\n",
-      "T4= T1/math.pow(r,(k-1)/k)\n",
-      "n= 1-(T/T2)\n",
-      "wnet= (k*R/((k-1)*M))*(T1-T4+T-T2)\n",
-      "P= m*wnet\n",
-      "e= math.sqrt((T2-T)/(T1-T4))\n",
-      "T5= T+((T2-T)/e)\n",
-      "T6= T1+e*(T4-T1)\n",
-      "##RESULTS\n",
-      "print'%s %.4f %s'%('efficiency=',n,'')\n",
-      "print'%s %.f %s'%('power=',P,'kW')\n",
-      "print'%s %.4f %s'%('efficiency=',e,'')\n",
-      "print'%s %.1f %s'%('temperature at the exit=',T6,'K')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "efficiency= 0.3270 \n",
-        "power= 1238 kW\n",
-        "efficiency= 0.6095 \n",
-        "temperature at the exit= 960.8 K\n"
-       ]
-      }
-     ],
-     "prompt_number": 5
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Example5-pg217"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "##initialisation of variables\n",
-      "v= 810. ##km/h\n",
-      "v1= 40. ##m/sec\n",
-      "cp= 1003. ##J/k mol\n",
-      "T0= 300. ##K\n",
-      "ec= 0.88\n",
-      "k= 1.4\n",
-      "T3= 1473.15 ##K\n",
-      "p3= 600. ##kPa\n",
-      "p0= 26.4 ##kPa\n",
-      "e= 0.9\n",
-      "m= 90. ##kg\n",
-      "cp1= 1.003 ##J/mol K\n",
-      "##CALCULATIONS\n",
-      "v0= v*1000/3600.\n",
-      "T1= T0+((v0**2-v1**2)/(2*cp))\n",
-      "T1s= T0+ec*(T0-T1)\n",
-      "p1= 36.79 #kPa\n",
-      "p2= 600 #kPa\n",
-      "T2s= T1*(p2/p1)**((k-1)/k)\n",
-      "T2= T1+((T2s-T1)/ec)\n",
-      "T21= T1+(T2s-T1)/ec\n",
-      "T4= T3+T0-T21\n",
-      "T4s= T3+(T4-T3)/ec\n",
-      "p4= p3*(T4s/T3)\n",
-      "T5s= p4+(p0-p4)*e\n",
-      "W34= m*cp1*(T3-T4)\n",
-      "v5= math.sqrt(v1**2+2*cp*(T4-T5s))\n",
-      "F= m*(v5-v0)\n",
-      "##RESULTS\n",
-      "print'%s %.2f %s'% ('T5=',T4s,'K ')\n",
-      "print'%s %.f %s'% ('Work=',W34,'kW ')\n",
-      "print'%s %.1f %s'% ('nozzle velocity=',v5,'m/s')\n",
-      "print'%s %.f %s'% ('thrust force=',F,'N')\n",
-      "\n",
-      "##ANSWERS GIVEN IN THE TEXTBOOK ARE WRONG\n",
-      "\n",
-      "##RESULTS\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "T5= 934.14 K \n",
-        "Work= 42818 kW \n",
-        "nozzle velocity= 1371.6 m/s\n",
-        "thrust force= 103193 N\n"
-       ]
-      }
-     ],
-     "prompt_number": 1
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Example6-pg225"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "#calculate COP and power and COP at given enthalpy\n",
-      "##initialisation of variables\n",
-      "h1= 182.07 ##kJ/kg\n",
-      "h4= 76.26 ##kJ/kg\n",
-      "h2= 217.97 ##kJ/kg\n",
-      "Q= math.pow(10,6) ##kJ/h\n",
-      "Tc= -5 ##C\n",
-      "Th= 32 ##C\n",
-      "##CALCULATIONS\n",
-      "COP= (h1-h4)/(h2-h1)\n",
-      "W= Q/(COP*3600)\n",
-      "COPcarnot= (273.15+Tc)/(Th-Tc)\n",
-      "##RESULTS\n",
-      "print'%s %.3f %s'% ('COP= ',COP,'')\n",
-      "print'%s %.3f %s'% ('power=',W,'KW')\n",
-      "print'%s %.3f %s'% ('COP=',COPcarnot,'')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "COP=  2.947 \n",
-        "power= 94.247 KW\n",
-        "COP= 7.247 \n"
-       ]
-      }
-     ],
-     "prompt_number": 2
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Example7-pg227"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "#calculate COPs and WORK at given variable\n",
-      "##initialisation of variables\n",
-      "h1= 183.12 ##kJ/kg\n",
-      "h4= 75.588 ##kJ/kg\n",
-      "h2= 218.697 ##kJ/kg\n",
-      "nm=0.94\n",
-      "Qc= 6 ##kW\n",
-      "h4a= 45.343 ##kJ/kg\n",
-      "h2a= 257.283 ##kJ/kg\n",
-      "h1a= 213.427 ##kJ/kg \n",
-      "##CALCULATIONS\n",
-      "COP= (h1-h4)*nm/(h2-h1)\n",
-      "W= Qc/COP\n",
-      "COP1= (h1-h4a)*nm/(h2a-h1a)\n",
-      "W1= Qc/COP1\n",
-      "##RESULTS\n",
-      "print'%s %.3f %s'% ('COP=',COP,'')\n",
-      "print'%s %.3f %s'% ('COP=',COP1,'')\n",
-      "print'%s %.3f %s'% ('Work=',W,'kW')\n",
-      "print'%s %.3f %s'% ('Work=',W1,'kW')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "COP= 2.841 \n",
-        "COP= 2.953 \n",
-        "Work= 2.112 kW\n",
-        "Work= 2.032 kW\n"
-       ]
-      }
-     ],
-     "prompt_number": 4
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Example8-pg228"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "#calculate COP and W\n",
-      "##initialisation of variables\n",
-      "h1= 1404.6 ##kJ/kg\n",
-      "h2s= 1748.9 ##kJ/kg\n",
-      "ec= 0.8\n",
-      "h4= 322.9 ##kJ/kg\n",
-      "h2= 1835 ##kJ/kg\n",
-      "Q= 100 ##kW\n",
-      "h21= 1649.2 ##kJ/kg\n",
-      "h22= 1515 ##kJ/kg\n",
-      "h23= 1678.8 ##kJ/kg\n",
-      "##CALCULATIONS\n",
-      "h2= h1+((h2s-h1)/ec)\n",
-      "COP= (h1-h4)/(h2-h1)\n",
-      "W= Q/COP\n",
-      "COP1= (h1-h4)/(h21-h1+h23-h22)\n",
-      "W1= Q/COP1\n",
-      "##RESULTS\n",
-      "print'%s %.3f %s'%  (' COP=',COP,'')\n",
-      "print'%s %.3f %s'% ('COP=',COP1,'')\n",
-      "print'%s %.1f %s'% ('W= ',W,'kW')\n",
-      "print'%s %.1f %s'% ('W=',W1,'kW')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        " COP= 2.513 \n",
-        "COP= 2.649 \n",
-        "W=  39.8 kW\n",
-        "W= 37.8 kW\n"
-       ]
-      }
-     ],
-     "prompt_number": 6
-    }
-   ],
-   "metadata": {}
-  }
- ]
-}
-\ No newline at end of file
diff --git a/Thermodynamics:_From_concepts_to_applications/Chapter11_.ipynb b/Thermodynamics:_From_concepts_to_applications/Chapter11_.ipynb
deleted file mode 100755
index 35f097c3..00000000
--- a/Thermodynamics:_From_concepts_to_applications/Chapter11_.ipynb
+++ /dev/null
@@ -1,468 +0,0 @@
-{
- "metadata": {
-  "name": "",
-  "signature": "sha256:a15297e2995d0ee44a3db61bf50b4aac4f8b03ecce59bf2a69c1f32113289b28"
- },
- "nbformat": 3,
- "nbformat_minor": 0,
- "worksheets": [
-  {
-   "cells": [
-    {
-     "cell_type": "heading",
-     "level": 1,
-     "metadata": {},
-     "source": [
-      "Chapter11-power and refrigeration cycles"
-     ]
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Example1-pg 203"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "#calculate enthalpy and effieceny and carnot efficency\n",
-      "##initialisation of variables\n",
-      "h1= 251.4 ##kJ/kg\n",
-      "v= 0.001017 ##m^3/kg\n",
-      "p2= 2000. ##Mpa\n",
-      "p1= 20. ##Mpa\n",
-      "h2= 253.4\n",
-      "h3= 3247.6 ##kJ/kg\n",
-      "h4= 2349.3 ##kJ/kg\n",
-      "Tc= 60.06 ##C\n",
-      "Th= 400. ##C\n",
-      "##CALCULATIONS\n",
-      "h2= h1+v*(2-p1)\n",
-      "q12= 0.\n",
-      "w12= h1-h2\n",
-      "q23= h3-h2\n",
-      "w23= 0.\n",
-      "q34= 0.\n",
-      "w34= h3-h4\n",
-      "q41= h1-h4\n",
-      "qnet= q12+q23+q34+q41\n",
-      "wnet= w12+w23+w34\n",
-      "n= wnet/q23\n",
-      "ncarnot= 1-((273.15+Tc)/(273.15+Th))\n",
-      "##RESULTS\n",
-      "print'%s %.1f %s'%('enthalpy=',h2,'kJ/kg')\n",
-      "print'%s %.3f %s'%('efficiency=',n,'')\n",
-      "print'%s %.3f %s'%('carnot efficiency=',ncarnot,'')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "enthalpy= 251.4 kJ/kg\n",
-        "efficiency= 0.300 \n",
-        "carnot efficiency= 0.505 \n"
-       ]
-      }
-     ],
-     "prompt_number": 2
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Example2-pg206"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "#calculate work and heat and effiecency and steam mass flow rate\n",
-      "##initialisation of variables\n",
-      "h3= 3247.4 ##kJ/kg\n",
-      "h4= 2439.1 ##kJ/kg\n",
-      "h1= 251.4 ##kJ/kg\n",
-      "h2= 253.9 ##kJ/kg\n",
-      "P= 100000 ##kW\n",
-      "##CALCULATIONS\n",
-      "wnet= h3-h4+h1-h2\n",
-      "qh= h3-h2\n",
-      "qc= h1-h4\n",
-      "n= wnet/qh\n",
-      "m= P/wnet\n",
-      "##RESULTS\n",
-      "print'%s %.f %s'%('work=',wnet,'kJ/kg')\n",
-      "print'%s %.1f %s'% ('heat=',qh,'kJ/kg')\n",
-      "print'%s %.1f %s'%('heat=',qc,'kJ/kg')\n",
-      "print'%s %.4f %s'%('efficiency=',n,'')\n",
-      "print'%s %.2f %s'%('steam mass flow rate=',m,'kg/s')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "work= 806 kJ/kg\n",
-        "heat= 2993.5 kJ/kg\n",
-        "heat= -2187.7 kJ/kg\n",
-        "efficiency= 0.2692 \n",
-        "steam mass flow rate= 124.10 kg/s\n"
-       ]
-      }
-     ],
-     "prompt_number": 3
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Example3-pg 208"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "#calculate qualitys and efficiency and mass flow rate and diameter\n",
-      "##initialisation of variables\n",
-      "h11= 2786.2 ##kJ/kg\n",
-      "h12= 340.5 ##kJ/kg\n",
-      "h7= 327.9 ##kJ/kg\n",
-      "h6= 169.0 ##kJ/kg\n",
-      "h10= 756.7 ##kJ/kg\n",
-      "h9= 480.9 ##kJkg\n",
-      "h14= 2818 ##kJ.kg\n",
-      "h15= 762.8 ##kJ/kg\n",
-      "h8= 462.7 ##kJ/kg\n",
-      "h13= 2974.5 ##kJ/kg\n",
-      "h5= 168.8 ##kJ/kg\n",
-      "P= 150. ##kW\n",
-      "v1= 0.02293 ##m^3/kg\n",
-      "v= 40. ##m/s\n",
-      "h1= 3448.6 ##kJ/kg\n",
-      "h3= 3478.5 ##kJ/kg\n",
-      "h2= 2818 ##kJ/kg\n",
-      "h4= 2527.1 ##kJ/kg\n",
-      "##CALCULATIONS\n",
-      "y1= (h10-h9)/(h14-h15)\n",
-      "y2= ((h8-h7)-y1*(h15-h7))/(h13-h7)\n",
-      "y3= (h7-h6)*(1-y1-y2)/(h11-h12)\n",
-      "qin= h1-h10+(1-y1)*(h3-h2)\n",
-      "qout= (h5-h4)*(1-y1-y2)+y3*(h4-h12)\n",
-      "wnet= qin+qout\n",
-      "n= wnet*100/qin\n",
-      "m1= P*1000/wnet\n",
-      "A1= m1*v1/v\n",
-      "D= math.sqrt(4*A1/math.pi)\n",
-      "##RESULTS\n",
-      "print'%s %.4f %s'%(' quality=',y1,'')\n",
-      "print'%s %.4f %s'%('quality=',y2,'')\n",
-      "print'%s %.4f %s'%('quality=',y3,'')\n",
-      "print'%s %.2f %s'%('efficiency=',n,'percent')\n",
-      "print'%s %.2f %s'%('mass flow rate=',m1,'kg/s')\n",
-      "print'%s %.3f %s'%(' diameter=',D,'m')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        " quality= 0.1342 \n",
-        "quality= 0.0289 \n",
-        "quality= 0.0544 \n",
-        "efficiency= 43.17 percent\n",
-        "mass flow rate= 106.46 kg/s\n",
-        " diameter= 0.279 m\n"
-       ]
-      }
-     ],
-     "prompt_number": 4
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Example4-pg 213"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "#calculate effieciency and power and temperature at the exist\n",
-      "##initialisation of variables\n",
-      "T= 300. ##K\n",
-      "P= 100. ##kPa\n",
-      "r= 4.\n",
-      "T1= 1200. ##K\n",
-      "m= 5. ##kg/s\n",
-      "k= 1.4\n",
-      "R= 8.314 ##jmol K\n",
-      "M= 29. ##gms\n",
-      "##CALCULATIONS\n",
-      "T2= T*math.pow(r,(k-1)/k)\n",
-      "T4= T1/math.pow(r,(k-1)/k)\n",
-      "n= 1-(T/T2)\n",
-      "wnet= (k*R/((k-1)*M))*(T1-T4+T-T2)\n",
-      "P= m*wnet\n",
-      "e= math.sqrt((T2-T)/(T1-T4))\n",
-      "T5= T+((T2-T)/e)\n",
-      "T6= T1+e*(T4-T1)\n",
-      "##RESULTS\n",
-      "print'%s %.4f %s'%('efficiency=',n,'')\n",
-      "print'%s %.f %s'%('power=',P,'kW')\n",
-      "print'%s %.4f %s'%('efficiency=',e,'')\n",
-      "print'%s %.1f %s'%('temperature at the exit=',T6,'K')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "efficiency= 0.3270 \n",
-        "power= 1238 kW\n",
-        "efficiency= 0.6095 \n",
-        "temperature at the exit= 960.8 K\n"
-       ]
-      }
-     ],
-     "prompt_number": 5
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Example5-pg217"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "##initialisation of variables\n",
-      "v= 810. ##km/h\n",
-      "v1= 40. ##m/sec\n",
-      "cp= 1003. ##J/k mol\n",
-      "T0= 300. ##K\n",
-      "ec= 0.88\n",
-      "k= 1.4\n",
-      "T3= 1473.15 ##K\n",
-      "p3= 600. ##kPa\n",
-      "p0= 26.4 ##kPa\n",
-      "e= 0.9\n",
-      "m= 90. ##kg\n",
-      "cp1= 1.003 ##J/mol K\n",
-      "##CALCULATIONS\n",
-      "v0= v*1000/3600.\n",
-      "T1= T0+((v0**2-v1**2)/(2*cp))\n",
-      "T1s= T0+ec*(T0-T1)\n",
-      "p1= 36.79 #kPa\n",
-      "p2= 600 #kPa\n",
-      "T2s= T1*(p2/p1)**((k-1)/k)\n",
-      "T2= T1+((T2s-T1)/ec)\n",
-      "T21= T1+(T2s-T1)/ec\n",
-      "T4= T3+T0-T21\n",
-      "T4s= T3+(T4-T3)/ec\n",
-      "p4= p3*(T4s/T3)\n",
-      "T5s= p4+(p0-p4)*e\n",
-      "W34= m*cp1*(T3-T4)\n",
-      "v5= math.sqrt(v1**2+2*cp*(T4-T5s))\n",
-      "F= m*(v5-v0)\n",
-      "##RESULTS\n",
-      "print'%s %.2f %s'% ('T5=',T4s,'K ')\n",
-      "print'%s %.f %s'% ('Work=',W34,'kW ')\n",
-      "print'%s %.1f %s'% ('nozzle velocity=',v5,'m/s')\n",
-      "print'%s %.f %s'% ('thrust force=',F,'N')\n",
-      "\n",
-      "##ANSWERS GIVEN IN THE TEXTBOOK ARE WRONG\n",
-      "\n",
-      "##RESULTS\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "T5= 934.14 K \n",
-        "Work= 42818 kW \n",
-        "nozzle velocity= 1371.6 m/s\n",
-        "thrust force= 103193 N\n"
-       ]
-      }
-     ],
-     "prompt_number": 1
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Example6-pg225"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "#calculate COP and power and COP at given enthalpy\n",
-      "##initialisation of variables\n",
-      "h1= 182.07 ##kJ/kg\n",
-      "h4= 76.26 ##kJ/kg\n",
-      "h2= 217.97 ##kJ/kg\n",
-      "Q= math.pow(10,6) ##kJ/h\n",
-      "Tc= -5 ##C\n",
-      "Th= 32 ##C\n",
-      "##CALCULATIONS\n",
-      "COP= (h1-h4)/(h2-h1)\n",
-      "W= Q/(COP*3600)\n",
-      "COPcarnot= (273.15+Tc)/(Th-Tc)\n",
-      "##RESULTS\n",
-      "print'%s %.3f %s'% ('COP= ',COP,'')\n",
-      "print'%s %.3f %s'% ('power=',W,'KW')\n",
-      "print'%s %.3f %s'% ('COP=',COPcarnot,'')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "COP=  2.947 \n",
-        "power= 94.247 KW\n",
-        "COP= 7.247 \n"
-       ]
-      }
-     ],
-     "prompt_number": 2
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Example7-pg227"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "#calculate COPs and WORK at given variable\n",
-      "##initialisation of variables\n",
-      "h1= 183.12 ##kJ/kg\n",
-      "h4= 75.588 ##kJ/kg\n",
-      "h2= 218.697 ##kJ/kg\n",
-      "nm=0.94\n",
-      "Qc= 6 ##kW\n",
-      "h4a= 45.343 ##kJ/kg\n",
-      "h2a= 257.283 ##kJ/kg\n",
-      "h1a= 213.427 ##kJ/kg \n",
-      "##CALCULATIONS\n",
-      "COP= (h1-h4)*nm/(h2-h1)\n",
-      "W= Qc/COP\n",
-      "COP1= (h1-h4a)*nm/(h2a-h1a)\n",
-      "W1= Qc/COP1\n",
-      "##RESULTS\n",
-      "print'%s %.3f %s'% ('COP=',COP,'')\n",
-      "print'%s %.3f %s'% ('COP=',COP1,'')\n",
-      "print'%s %.3f %s'% ('Work=',W,'kW')\n",
-      "print'%s %.3f %s'% ('Work=',W1,'kW')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "COP= 2.841 \n",
-        "COP= 2.953 \n",
-        "Work= 2.112 kW\n",
-        "Work= 2.032 kW\n"
-       ]
-      }
-     ],
-     "prompt_number": 4
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Example8-pg228"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "#calculate COP and W\n",
-      "##initialisation of variables\n",
-      "h1= 1404.6 ##kJ/kg\n",
-      "h2s= 1748.9 ##kJ/kg\n",
-      "ec= 0.8\n",
-      "h4= 322.9 ##kJ/kg\n",
-      "h2= 1835 ##kJ/kg\n",
-      "Q= 100 ##kW\n",
-      "h21= 1649.2 ##kJ/kg\n",
-      "h22= 1515 ##kJ/kg\n",
-      "h23= 1678.8 ##kJ/kg\n",
-      "##CALCULATIONS\n",
-      "h2= h1+((h2s-h1)/ec)\n",
-      "COP= (h1-h4)/(h2-h1)\n",
-      "W= Q/COP\n",
-      "COP1= (h1-h4)/(h21-h1+h23-h22)\n",
-      "W1= Q/COP1\n",
-      "##RESULTS\n",
-      "print'%s %.3f %s'%  (' COP=',COP,'')\n",
-      "print'%s %.3f %s'% ('COP=',COP1,'')\n",
-      "print'%s %.1f %s'% ('W= ',W,'kW')\n",
-      "print'%s %.1f %s'% ('W=',W1,'kW')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        " COP= 2.513 \n",
-        "COP= 2.649 \n",
-        "W=  39.8 kW\n",
-        "W= 37.8 kW\n"
-       ]
-      }
-     ],
-     "prompt_number": 6
-    }
-   ],
-   "metadata": {}
-  }
- ]
-}
-\ No newline at end of file
diff --git a/Thermodynamics:_From_concepts_to_applications/Chapter11__1.ipynb b/Thermodynamics:_From_concepts_to_applications/Chapter11__1.ipynb
deleted file mode 100755
index 35f097c3..00000000
--- a/Thermodynamics:_From_concepts_to_applications/Chapter11__1.ipynb
+++ /dev/null
@@ -1,468 +0,0 @@
-{
- "metadata": {
-  "name": "",
-  "signature": "sha256:a15297e2995d0ee44a3db61bf50b4aac4f8b03ecce59bf2a69c1f32113289b28"
- },
- "nbformat": 3,
- "nbformat_minor": 0,
- "worksheets": [
-  {
-   "cells": [
-    {
-     "cell_type": "heading",
-     "level": 1,
-     "metadata": {},
-     "source": [
-      "Chapter11-power and refrigeration cycles"
-     ]
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Example1-pg 203"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "#calculate enthalpy and effieceny and carnot efficency\n",
-      "##initialisation of variables\n",
-      "h1= 251.4 ##kJ/kg\n",
-      "v= 0.001017 ##m^3/kg\n",
-      "p2= 2000. ##Mpa\n",
-      "p1= 20. ##Mpa\n",
-      "h2= 253.4\n",
-      "h3= 3247.6 ##kJ/kg\n",
-      "h4= 2349.3 ##kJ/kg\n",
-      "Tc= 60.06 ##C\n",
-      "Th= 400. ##C\n",
-      "##CALCULATIONS\n",
-      "h2= h1+v*(2-p1)\n",
-      "q12= 0.\n",
-      "w12= h1-h2\n",
-      "q23= h3-h2\n",
-      "w23= 0.\n",
-      "q34= 0.\n",
-      "w34= h3-h4\n",
-      "q41= h1-h4\n",
-      "qnet= q12+q23+q34+q41\n",
-      "wnet= w12+w23+w34\n",
-      "n= wnet/q23\n",
-      "ncarnot= 1-((273.15+Tc)/(273.15+Th))\n",
-      "##RESULTS\n",
-      "print'%s %.1f %s'%('enthalpy=',h2,'kJ/kg')\n",
-      "print'%s %.3f %s'%('efficiency=',n,'')\n",
-      "print'%s %.3f %s'%('carnot efficiency=',ncarnot,'')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "enthalpy= 251.4 kJ/kg\n",
-        "efficiency= 0.300 \n",
-        "carnot efficiency= 0.505 \n"
-       ]
-      }
-     ],
-     "prompt_number": 2
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Example2-pg206"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "#calculate work and heat and effiecency and steam mass flow rate\n",
-      "##initialisation of variables\n",
-      "h3= 3247.4 ##kJ/kg\n",
-      "h4= 2439.1 ##kJ/kg\n",
-      "h1= 251.4 ##kJ/kg\n",
-      "h2= 253.9 ##kJ/kg\n",
-      "P= 100000 ##kW\n",
-      "##CALCULATIONS\n",
-      "wnet= h3-h4+h1-h2\n",
-      "qh= h3-h2\n",
-      "qc= h1-h4\n",
-      "n= wnet/qh\n",
-      "m= P/wnet\n",
-      "##RESULTS\n",
-      "print'%s %.f %s'%('work=',wnet,'kJ/kg')\n",
-      "print'%s %.1f %s'% ('heat=',qh,'kJ/kg')\n",
-      "print'%s %.1f %s'%('heat=',qc,'kJ/kg')\n",
-      "print'%s %.4f %s'%('efficiency=',n,'')\n",
-      "print'%s %.2f %s'%('steam mass flow rate=',m,'kg/s')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "work= 806 kJ/kg\n",
-        "heat= 2993.5 kJ/kg\n",
-        "heat= -2187.7 kJ/kg\n",
-        "efficiency= 0.2692 \n",
-        "steam mass flow rate= 124.10 kg/s\n"
-       ]
-      }
-     ],
-     "prompt_number": 3
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Example3-pg 208"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "#calculate qualitys and efficiency and mass flow rate and diameter\n",
-      "##initialisation of variables\n",
-      "h11= 2786.2 ##kJ/kg\n",
-      "h12= 340.5 ##kJ/kg\n",
-      "h7= 327.9 ##kJ/kg\n",
-      "h6= 169.0 ##kJ/kg\n",
-      "h10= 756.7 ##kJ/kg\n",
-      "h9= 480.9 ##kJkg\n",
-      "h14= 2818 ##kJ.kg\n",
-      "h15= 762.8 ##kJ/kg\n",
-      "h8= 462.7 ##kJ/kg\n",
-      "h13= 2974.5 ##kJ/kg\n",
-      "h5= 168.8 ##kJ/kg\n",
-      "P= 150. ##kW\n",
-      "v1= 0.02293 ##m^3/kg\n",
-      "v= 40. ##m/s\n",
-      "h1= 3448.6 ##kJ/kg\n",
-      "h3= 3478.5 ##kJ/kg\n",
-      "h2= 2818 ##kJ/kg\n",
-      "h4= 2527.1 ##kJ/kg\n",
-      "##CALCULATIONS\n",
-      "y1= (h10-h9)/(h14-h15)\n",
-      "y2= ((h8-h7)-y1*(h15-h7))/(h13-h7)\n",
-      "y3= (h7-h6)*(1-y1-y2)/(h11-h12)\n",
-      "qin= h1-h10+(1-y1)*(h3-h2)\n",
-      "qout= (h5-h4)*(1-y1-y2)+y3*(h4-h12)\n",
-      "wnet= qin+qout\n",
-      "n= wnet*100/qin\n",
-      "m1= P*1000/wnet\n",
-      "A1= m1*v1/v\n",
-      "D= math.sqrt(4*A1/math.pi)\n",
-      "##RESULTS\n",
-      "print'%s %.4f %s'%(' quality=',y1,'')\n",
-      "print'%s %.4f %s'%('quality=',y2,'')\n",
-      "print'%s %.4f %s'%('quality=',y3,'')\n",
-      "print'%s %.2f %s'%('efficiency=',n,'percent')\n",
-      "print'%s %.2f %s'%('mass flow rate=',m1,'kg/s')\n",
-      "print'%s %.3f %s'%(' diameter=',D,'m')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        " quality= 0.1342 \n",
-        "quality= 0.0289 \n",
-        "quality= 0.0544 \n",
-        "efficiency= 43.17 percent\n",
-        "mass flow rate= 106.46 kg/s\n",
-        " diameter= 0.279 m\n"
-       ]
-      }
-     ],
-     "prompt_number": 4
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Example4-pg 213"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "#calculate effieciency and power and temperature at the exist\n",
-      "##initialisation of variables\n",
-      "T= 300. ##K\n",
-      "P= 100. ##kPa\n",
-      "r= 4.\n",
-      "T1= 1200. ##K\n",
-      "m= 5. ##kg/s\n",
-      "k= 1.4\n",
-      "R= 8.314 ##jmol K\n",
-      "M= 29. ##gms\n",
-      "##CALCULATIONS\n",
-      "T2= T*math.pow(r,(k-1)/k)\n",
-      "T4= T1/math.pow(r,(k-1)/k)\n",
-      "n= 1-(T/T2)\n",
-      "wnet= (k*R/((k-1)*M))*(T1-T4+T-T2)\n",
-      "P= m*wnet\n",
-      "e= math.sqrt((T2-T)/(T1-T4))\n",
-      "T5= T+((T2-T)/e)\n",
-      "T6= T1+e*(T4-T1)\n",
-      "##RESULTS\n",
-      "print'%s %.4f %s'%('efficiency=',n,'')\n",
-      "print'%s %.f %s'%('power=',P,'kW')\n",
-      "print'%s %.4f %s'%('efficiency=',e,'')\n",
-      "print'%s %.1f %s'%('temperature at the exit=',T6,'K')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "efficiency= 0.3270 \n",
-        "power= 1238 kW\n",
-        "efficiency= 0.6095 \n",
-        "temperature at the exit= 960.8 K\n"
-       ]
-      }
-     ],
-     "prompt_number": 5
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Example5-pg217"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "##initialisation of variables\n",
-      "v= 810. ##km/h\n",
-      "v1= 40. ##m/sec\n",
-      "cp= 1003. ##J/k mol\n",
-      "T0= 300. ##K\n",
-      "ec= 0.88\n",
-      "k= 1.4\n",
-      "T3= 1473.15 ##K\n",
-      "p3= 600. ##kPa\n",
-      "p0= 26.4 ##kPa\n",
-      "e= 0.9\n",
-      "m= 90. ##kg\n",
-      "cp1= 1.003 ##J/mol K\n",
-      "##CALCULATIONS\n",
-      "v0= v*1000/3600.\n",
-      "T1= T0+((v0**2-v1**2)/(2*cp))\n",
-      "T1s= T0+ec*(T0-T1)\n",
-      "p1= 36.79 #kPa\n",
-      "p2= 600 #kPa\n",
-      "T2s= T1*(p2/p1)**((k-1)/k)\n",
-      "T2= T1+((T2s-T1)/ec)\n",
-      "T21= T1+(T2s-T1)/ec\n",
-      "T4= T3+T0-T21\n",
-      "T4s= T3+(T4-T3)/ec\n",
-      "p4= p3*(T4s/T3)\n",
-      "T5s= p4+(p0-p4)*e\n",
-      "W34= m*cp1*(T3-T4)\n",
-      "v5= math.sqrt(v1**2+2*cp*(T4-T5s))\n",
-      "F= m*(v5-v0)\n",
-      "##RESULTS\n",
-      "print'%s %.2f %s'% ('T5=',T4s,'K ')\n",
-      "print'%s %.f %s'% ('Work=',W34,'kW ')\n",
-      "print'%s %.1f %s'% ('nozzle velocity=',v5,'m/s')\n",
-      "print'%s %.f %s'% ('thrust force=',F,'N')\n",
-      "\n",
-      "##ANSWERS GIVEN IN THE TEXTBOOK ARE WRONG\n",
-      "\n",
-      "##RESULTS\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "T5= 934.14 K \n",
-        "Work= 42818 kW \n",
-        "nozzle velocity= 1371.6 m/s\n",
-        "thrust force= 103193 N\n"
-       ]
-      }
-     ],
-     "prompt_number": 1
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Example6-pg225"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "#calculate COP and power and COP at given enthalpy\n",
-      "##initialisation of variables\n",
-      "h1= 182.07 ##kJ/kg\n",
-      "h4= 76.26 ##kJ/kg\n",
-      "h2= 217.97 ##kJ/kg\n",
-      "Q= math.pow(10,6) ##kJ/h\n",
-      "Tc= -5 ##C\n",
-      "Th= 32 ##C\n",
-      "##CALCULATIONS\n",
-      "COP= (h1-h4)/(h2-h1)\n",
-      "W= Q/(COP*3600)\n",
-      "COPcarnot= (273.15+Tc)/(Th-Tc)\n",
-      "##RESULTS\n",
-      "print'%s %.3f %s'% ('COP= ',COP,'')\n",
-      "print'%s %.3f %s'% ('power=',W,'KW')\n",
-      "print'%s %.3f %s'% ('COP=',COPcarnot,'')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "COP=  2.947 \n",
-        "power= 94.247 KW\n",
-        "COP= 7.247 \n"
-       ]
-      }
-     ],
-     "prompt_number": 2
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Example7-pg227"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "#calculate COPs and WORK at given variable\n",
-      "##initialisation of variables\n",
-      "h1= 183.12 ##kJ/kg\n",
-      "h4= 75.588 ##kJ/kg\n",
-      "h2= 218.697 ##kJ/kg\n",
-      "nm=0.94\n",
-      "Qc= 6 ##kW\n",
-      "h4a= 45.343 ##kJ/kg\n",
-      "h2a= 257.283 ##kJ/kg\n",
-      "h1a= 213.427 ##kJ/kg \n",
-      "##CALCULATIONS\n",
-      "COP= (h1-h4)*nm/(h2-h1)\n",
-      "W= Qc/COP\n",
-      "COP1= (h1-h4a)*nm/(h2a-h1a)\n",
-      "W1= Qc/COP1\n",
-      "##RESULTS\n",
-      "print'%s %.3f %s'% ('COP=',COP,'')\n",
-      "print'%s %.3f %s'% ('COP=',COP1,'')\n",
-      "print'%s %.3f %s'% ('Work=',W,'kW')\n",
-      "print'%s %.3f %s'% ('Work=',W1,'kW')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "COP= 2.841 \n",
-        "COP= 2.953 \n",
-        "Work= 2.112 kW\n",
-        "Work= 2.032 kW\n"
-       ]
-      }
-     ],
-     "prompt_number": 4
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Example8-pg228"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "#calculate COP and W\n",
-      "##initialisation of variables\n",
-      "h1= 1404.6 ##kJ/kg\n",
-      "h2s= 1748.9 ##kJ/kg\n",
-      "ec= 0.8\n",
-      "h4= 322.9 ##kJ/kg\n",
-      "h2= 1835 ##kJ/kg\n",
-      "Q= 100 ##kW\n",
-      "h21= 1649.2 ##kJ/kg\n",
-      "h22= 1515 ##kJ/kg\n",
-      "h23= 1678.8 ##kJ/kg\n",
-      "##CALCULATIONS\n",
-      "h2= h1+((h2s-h1)/ec)\n",
-      "COP= (h1-h4)/(h2-h1)\n",
-      "W= Q/COP\n",
-      "COP1= (h1-h4)/(h21-h1+h23-h22)\n",
-      "W1= Q/COP1\n",
-      "##RESULTS\n",
-      "print'%s %.3f %s'%  (' COP=',COP,'')\n",
-      "print'%s %.3f %s'% ('COP=',COP1,'')\n",
-      "print'%s %.1f %s'% ('W= ',W,'kW')\n",
-      "print'%s %.1f %s'% ('W=',W1,'kW')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        " COP= 2.513 \n",
-        "COP= 2.649 \n",
-        "W=  39.8 kW\n",
-        "W= 37.8 kW\n"
-       ]
-      }
-     ],
-     "prompt_number": 6
-    }
-   ],
-   "metadata": {}
-  }
- ]
-}
-\ No newline at end of file
diff --git a/Thermodynamics:_From_concepts_to_applications/Chapter11_power_and_refrigeration_cycles.ipynb b/Thermodynamics:_From_concepts_to_applications/Chapter11_power_and_refrigeration_cycles.ipynb
deleted file mode 100755
index 35f097c3..00000000
--- a/Thermodynamics:_From_concepts_to_applications/Chapter11_power_and_refrigeration_cycles.ipynb
+++ /dev/null
@@ -1,468 +0,0 @@
-{
- "metadata": {
-  "name": "",
-  "signature": "sha256:a15297e2995d0ee44a3db61bf50b4aac4f8b03ecce59bf2a69c1f32113289b28"
- },
- "nbformat": 3,
- "nbformat_minor": 0,
- "worksheets": [
-  {
-   "cells": [
-    {
-     "cell_type": "heading",
-     "level": 1,
-     "metadata": {},
-     "source": [
-      "Chapter11-power and refrigeration cycles"
-     ]
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Example1-pg 203"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "#calculate enthalpy and effieceny and carnot efficency\n",
-      "##initialisation of variables\n",
-      "h1= 251.4 ##kJ/kg\n",
-      "v= 0.001017 ##m^3/kg\n",
-      "p2= 2000. ##Mpa\n",
-      "p1= 20. ##Mpa\n",
-      "h2= 253.4\n",
-      "h3= 3247.6 ##kJ/kg\n",
-      "h4= 2349.3 ##kJ/kg\n",
-      "Tc= 60.06 ##C\n",
-      "Th= 400. ##C\n",
-      "##CALCULATIONS\n",
-      "h2= h1+v*(2-p1)\n",
-      "q12= 0.\n",
-      "w12= h1-h2\n",
-      "q23= h3-h2\n",
-      "w23= 0.\n",
-      "q34= 0.\n",
-      "w34= h3-h4\n",
-      "q41= h1-h4\n",
-      "qnet= q12+q23+q34+q41\n",
-      "wnet= w12+w23+w34\n",
-      "n= wnet/q23\n",
-      "ncarnot= 1-((273.15+Tc)/(273.15+Th))\n",
-      "##RESULTS\n",
-      "print'%s %.1f %s'%('enthalpy=',h2,'kJ/kg')\n",
-      "print'%s %.3f %s'%('efficiency=',n,'')\n",
-      "print'%s %.3f %s'%('carnot efficiency=',ncarnot,'')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "enthalpy= 251.4 kJ/kg\n",
-        "efficiency= 0.300 \n",
-        "carnot efficiency= 0.505 \n"
-       ]
-      }
-     ],
-     "prompt_number": 2
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Example2-pg206"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "#calculate work and heat and effiecency and steam mass flow rate\n",
-      "##initialisation of variables\n",
-      "h3= 3247.4 ##kJ/kg\n",
-      "h4= 2439.1 ##kJ/kg\n",
-      "h1= 251.4 ##kJ/kg\n",
-      "h2= 253.9 ##kJ/kg\n",
-      "P= 100000 ##kW\n",
-      "##CALCULATIONS\n",
-      "wnet= h3-h4+h1-h2\n",
-      "qh= h3-h2\n",
-      "qc= h1-h4\n",
-      "n= wnet/qh\n",
-      "m= P/wnet\n",
-      "##RESULTS\n",
-      "print'%s %.f %s'%('work=',wnet,'kJ/kg')\n",
-      "print'%s %.1f %s'% ('heat=',qh,'kJ/kg')\n",
-      "print'%s %.1f %s'%('heat=',qc,'kJ/kg')\n",
-      "print'%s %.4f %s'%('efficiency=',n,'')\n",
-      "print'%s %.2f %s'%('steam mass flow rate=',m,'kg/s')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "work= 806 kJ/kg\n",
-        "heat= 2993.5 kJ/kg\n",
-        "heat= -2187.7 kJ/kg\n",
-        "efficiency= 0.2692 \n",
-        "steam mass flow rate= 124.10 kg/s\n"
-       ]
-      }
-     ],
-     "prompt_number": 3
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Example3-pg 208"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "#calculate qualitys and efficiency and mass flow rate and diameter\n",
-      "##initialisation of variables\n",
-      "h11= 2786.2 ##kJ/kg\n",
-      "h12= 340.5 ##kJ/kg\n",
-      "h7= 327.9 ##kJ/kg\n",
-      "h6= 169.0 ##kJ/kg\n",
-      "h10= 756.7 ##kJ/kg\n",
-      "h9= 480.9 ##kJkg\n",
-      "h14= 2818 ##kJ.kg\n",
-      "h15= 762.8 ##kJ/kg\n",
-      "h8= 462.7 ##kJ/kg\n",
-      "h13= 2974.5 ##kJ/kg\n",
-      "h5= 168.8 ##kJ/kg\n",
-      "P= 150. ##kW\n",
-      "v1= 0.02293 ##m^3/kg\n",
-      "v= 40. ##m/s\n",
-      "h1= 3448.6 ##kJ/kg\n",
-      "h3= 3478.5 ##kJ/kg\n",
-      "h2= 2818 ##kJ/kg\n",
-      "h4= 2527.1 ##kJ/kg\n",
-      "##CALCULATIONS\n",
-      "y1= (h10-h9)/(h14-h15)\n",
-      "y2= ((h8-h7)-y1*(h15-h7))/(h13-h7)\n",
-      "y3= (h7-h6)*(1-y1-y2)/(h11-h12)\n",
-      "qin= h1-h10+(1-y1)*(h3-h2)\n",
-      "qout= (h5-h4)*(1-y1-y2)+y3*(h4-h12)\n",
-      "wnet= qin+qout\n",
-      "n= wnet*100/qin\n",
-      "m1= P*1000/wnet\n",
-      "A1= m1*v1/v\n",
-      "D= math.sqrt(4*A1/math.pi)\n",
-      "##RESULTS\n",
-      "print'%s %.4f %s'%(' quality=',y1,'')\n",
-      "print'%s %.4f %s'%('quality=',y2,'')\n",
-      "print'%s %.4f %s'%('quality=',y3,'')\n",
-      "print'%s %.2f %s'%('efficiency=',n,'percent')\n",
-      "print'%s %.2f %s'%('mass flow rate=',m1,'kg/s')\n",
-      "print'%s %.3f %s'%(' diameter=',D,'m')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        " quality= 0.1342 \n",
-        "quality= 0.0289 \n",
-        "quality= 0.0544 \n",
-        "efficiency= 43.17 percent\n",
-        "mass flow rate= 106.46 kg/s\n",
-        " diameter= 0.279 m\n"
-       ]
-      }
-     ],
-     "prompt_number": 4
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Example4-pg 213"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "#calculate effieciency and power and temperature at the exist\n",
-      "##initialisation of variables\n",
-      "T= 300. ##K\n",
-      "P= 100. ##kPa\n",
-      "r= 4.\n",
-      "T1= 1200. ##K\n",
-      "m= 5. ##kg/s\n",
-      "k= 1.4\n",
-      "R= 8.314 ##jmol K\n",
-      "M= 29. ##gms\n",
-      "##CALCULATIONS\n",
-      "T2= T*math.pow(r,(k-1)/k)\n",
-      "T4= T1/math.pow(r,(k-1)/k)\n",
-      "n= 1-(T/T2)\n",
-      "wnet= (k*R/((k-1)*M))*(T1-T4+T-T2)\n",
-      "P= m*wnet\n",
-      "e= math.sqrt((T2-T)/(T1-T4))\n",
-      "T5= T+((T2-T)/e)\n",
-      "T6= T1+e*(T4-T1)\n",
-      "##RESULTS\n",
-      "print'%s %.4f %s'%('efficiency=',n,'')\n",
-      "print'%s %.f %s'%('power=',P,'kW')\n",
-      "print'%s %.4f %s'%('efficiency=',e,'')\n",
-      "print'%s %.1f %s'%('temperature at the exit=',T6,'K')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "efficiency= 0.3270 \n",
-        "power= 1238 kW\n",
-        "efficiency= 0.6095 \n",
-        "temperature at the exit= 960.8 K\n"
-       ]
-      }
-     ],
-     "prompt_number": 5
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Example5-pg217"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "##initialisation of variables\n",
-      "v= 810. ##km/h\n",
-      "v1= 40. ##m/sec\n",
-      "cp= 1003. ##J/k mol\n",
-      "T0= 300. ##K\n",
-      "ec= 0.88\n",
-      "k= 1.4\n",
-      "T3= 1473.15 ##K\n",
-      "p3= 600. ##kPa\n",
-      "p0= 26.4 ##kPa\n",
-      "e= 0.9\n",
-      "m= 90. ##kg\n",
-      "cp1= 1.003 ##J/mol K\n",
-      "##CALCULATIONS\n",
-      "v0= v*1000/3600.\n",
-      "T1= T0+((v0**2-v1**2)/(2*cp))\n",
-      "T1s= T0+ec*(T0-T1)\n",
-      "p1= 36.79 #kPa\n",
-      "p2= 600 #kPa\n",
-      "T2s= T1*(p2/p1)**((k-1)/k)\n",
-      "T2= T1+((T2s-T1)/ec)\n",
-      "T21= T1+(T2s-T1)/ec\n",
-      "T4= T3+T0-T21\n",
-      "T4s= T3+(T4-T3)/ec\n",
-      "p4= p3*(T4s/T3)\n",
-      "T5s= p4+(p0-p4)*e\n",
-      "W34= m*cp1*(T3-T4)\n",
-      "v5= math.sqrt(v1**2+2*cp*(T4-T5s))\n",
-      "F= m*(v5-v0)\n",
-      "##RESULTS\n",
-      "print'%s %.2f %s'% ('T5=',T4s,'K ')\n",
-      "print'%s %.f %s'% ('Work=',W34,'kW ')\n",
-      "print'%s %.1f %s'% ('nozzle velocity=',v5,'m/s')\n",
-      "print'%s %.f %s'% ('thrust force=',F,'N')\n",
-      "\n",
-      "##ANSWERS GIVEN IN THE TEXTBOOK ARE WRONG\n",
-      "\n",
-      "##RESULTS\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "T5= 934.14 K \n",
-        "Work= 42818 kW \n",
-        "nozzle velocity= 1371.6 m/s\n",
-        "thrust force= 103193 N\n"
-       ]
-      }
-     ],
-     "prompt_number": 1
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Example6-pg225"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "#calculate COP and power and COP at given enthalpy\n",
-      "##initialisation of variables\n",
-      "h1= 182.07 ##kJ/kg\n",
-      "h4= 76.26 ##kJ/kg\n",
-      "h2= 217.97 ##kJ/kg\n",
-      "Q= math.pow(10,6) ##kJ/h\n",
-      "Tc= -5 ##C\n",
-      "Th= 32 ##C\n",
-      "##CALCULATIONS\n",
-      "COP= (h1-h4)/(h2-h1)\n",
-      "W= Q/(COP*3600)\n",
-      "COPcarnot= (273.15+Tc)/(Th-Tc)\n",
-      "##RESULTS\n",
-      "print'%s %.3f %s'% ('COP= ',COP,'')\n",
-      "print'%s %.3f %s'% ('power=',W,'KW')\n",
-      "print'%s %.3f %s'% ('COP=',COPcarnot,'')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "COP=  2.947 \n",
-        "power= 94.247 KW\n",
-        "COP= 7.247 \n"
-       ]
-      }
-     ],
-     "prompt_number": 2
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Example7-pg227"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "#calculate COPs and WORK at given variable\n",
-      "##initialisation of variables\n",
-      "h1= 183.12 ##kJ/kg\n",
-      "h4= 75.588 ##kJ/kg\n",
-      "h2= 218.697 ##kJ/kg\n",
-      "nm=0.94\n",
-      "Qc= 6 ##kW\n",
-      "h4a= 45.343 ##kJ/kg\n",
-      "h2a= 257.283 ##kJ/kg\n",
-      "h1a= 213.427 ##kJ/kg \n",
-      "##CALCULATIONS\n",
-      "COP= (h1-h4)*nm/(h2-h1)\n",
-      "W= Qc/COP\n",
-      "COP1= (h1-h4a)*nm/(h2a-h1a)\n",
-      "W1= Qc/COP1\n",
-      "##RESULTS\n",
-      "print'%s %.3f %s'% ('COP=',COP,'')\n",
-      "print'%s %.3f %s'% ('COP=',COP1,'')\n",
-      "print'%s %.3f %s'% ('Work=',W,'kW')\n",
-      "print'%s %.3f %s'% ('Work=',W1,'kW')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "COP= 2.841 \n",
-        "COP= 2.953 \n",
-        "Work= 2.112 kW\n",
-        "Work= 2.032 kW\n"
-       ]
-      }
-     ],
-     "prompt_number": 4
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Example8-pg228"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "#calculate COP and W\n",
-      "##initialisation of variables\n",
-      "h1= 1404.6 ##kJ/kg\n",
-      "h2s= 1748.9 ##kJ/kg\n",
-      "ec= 0.8\n",
-      "h4= 322.9 ##kJ/kg\n",
-      "h2= 1835 ##kJ/kg\n",
-      "Q= 100 ##kW\n",
-      "h21= 1649.2 ##kJ/kg\n",
-      "h22= 1515 ##kJ/kg\n",
-      "h23= 1678.8 ##kJ/kg\n",
-      "##CALCULATIONS\n",
-      "h2= h1+((h2s-h1)/ec)\n",
-      "COP= (h1-h4)/(h2-h1)\n",
-      "W= Q/COP\n",
-      "COP1= (h1-h4)/(h21-h1+h23-h22)\n",
-      "W1= Q/COP1\n",
-      "##RESULTS\n",
-      "print'%s %.3f %s'%  (' COP=',COP,'')\n",
-      "print'%s %.3f %s'% ('COP=',COP1,'')\n",
-      "print'%s %.1f %s'% ('W= ',W,'kW')\n",
-      "print'%s %.1f %s'% ('W=',W1,'kW')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        " COP= 2.513 \n",
-        "COP= 2.649 \n",
-        "W=  39.8 kW\n",
-        "W= 37.8 kW\n"
-       ]
-      }
-     ],
-     "prompt_number": 6
-    }
-   ],
-   "metadata": {}
-  }
- ]
-}
-\ No newline at end of file
diff --git a/Thermodynamics:_From_concepts_to_applications/Chapter13-.ipynb b/Thermodynamics:_From_concepts_to_applications/Chapter13-.ipynb
deleted file mode 100755
index cb096e14..00000000
--- a/Thermodynamics:_From_concepts_to_applications/Chapter13-.ipynb
+++ /dev/null
@@ -1,217 +0,0 @@
-{
- "metadata": {
-  "name": "",
-  "signature": "sha256:8d95c094e950bc8cd1f4bbc97c09344d22cf81b1ba4d6101a144be7a5e1e83dc"
- },
- "nbformat": 3,
- "nbformat_minor": 0,
- "worksheets": [
-  {
-   "cells": [
-    {
-     "cell_type": "heading",
-     "level": 1,
-     "metadata": {},
-     "source": [
-      "Chapter13-thermodynamic relations"
-     ]
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Example2-pg284"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "#calculate entropy wrt pressures and volume wrt temerature\n",
-      "##initialisation of variables\n",
-      "S1= 6.539 ##kJ/kg K\n",
-      "S2= 6.7664 ##kJ/kg K\n",
-      "v1= 0.10976 ##m^3\n",
-      "v2= 0.08700 ##m^3\n",
-      "P= 3. ##Mpa\n",
-      "P1= 2. ##Mpa\n",
-      "T= 350. ##K\n",
-      "T1= 250. ##K\n",
-      "S3= 3.1741 ##kJ/kg K\n",
-      "S4= 3.2071 ##kJ/kg K\n",
-      "P2= 30. ##Mpa\n",
-      "P3= 20. ##Mpa\n",
-      "v3= 0.0014217 ##m^3\n",
-      "v4= 0.0012860 ##m^3\n",
-      "T2= 320. ##K\n",
-      "T3= 280. ##K\n",
-      "##CALCULATIONS\n",
-      "r= (S1-S2)/(P*10*10*10-P1*10*10*10)\n",
-      "r1= (v1-v2)/(T-T1)\n",
-      "R= (S3-S4)/(P2*10*10*10-P3*10*10*10)\n",
-      "R1= (v3-v4)/(T2-T3)\n",
-      "##RESULTS\n",
-      "print'%s %.7f %s'% ('entropy wrt pressre=',r,'kJ/kg K kpa')\n",
-      "print'%s %.e %s'% ('entropy wrt pressre=',R,'kJ/kg K kpa')\n",
-      "print'%s %.7f %s'%  ('volume wrt temperature=',r1,'m^3/kg K ')\n",
-      "print'%s %.2e %s'% ('volume wrt temperature=',R1,'m^3/kg K ')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "entropy wrt pressre= -0.0002274 kJ/kg K kpa\n",
-        "entropy wrt pressre= -3e-06 kJ/kg K kpa\n",
-        "volume wrt temperature= 0.0002276 m^3/kg K \n",
-        "volume wrt temperature= 3.39e-06 m^3/kg K \n"
-       ]
-      }
-     ],
-     "prompt_number": 6
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Example3-pg286"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "#saturation pressure\n",
-      "##initialisation of variables\n",
-      "hfg= 2406.7 ##kJ/kg\n",
-      "Psat40= 7.384 ##kPa\n",
-      "R= 8.314 ##J/mol K\n",
-      "T= 40. ##C\n",
-      "T1= 50. ##C\n",
-      "M= 18.##kg\n",
-      "##CALCULATIONS\n",
-      "Psat50= Psat40*math.e**((hfg*M/R)*((1/(273.15+T))-(1/(273.15+T1))))\n",
-      "##RESULTS\n",
-      "print'%s %.3f %s' %('Saturation pressure=',Psat50,'kPa')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "Saturation pressure= 12.357 kPa\n"
-       ]
-      }
-     ],
-     "prompt_number": 2
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Example4-pg287"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "#calcualte lowest temprature\n",
-      "##initialisation of variables\n",
-      "W= 800. ##N\n",
-      "A= 0.4 ##cm^2\n",
-      "p= 0.611 ##Mpa\n",
-      "P1= 0.1 ##Mpa\n",
-      "T= 0.01 ##C\n",
-      "vs= 0.0010908 ##m^3/kg\n",
-      "hs= -333.40 ##kJ/kg\n",
-      "vf= 0.0010002 ##m^3/kg\n",
-      "hf= 0 ##kJ/kg\n",
-      "vg= 206.14 ##m^3/kg\n",
-      "hg= 2501.4 ##kJ/kg\n",
-      "##CALCULATIONS\n",
-      "P2= P1+(W/A)*math.pow(10,(4-6))\n",
-      "dT= (273.15++T)*(vf-vs)*(P2*10*10*10-p)/(0-hs)\n",
-      "Tmin= dT+T\n",
-      "##RESULTS\n",
-      "print'%s %.2f %s'% ('lowest temperature=',Tmin,'C')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "lowest temperature= -1.48 C\n"
-       ]
-      }
-     ],
-     "prompt_number": 3
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Example7-pg292"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "#calculate volume exapansion coefficent and isothermal compressibilitiy and isotherma modulus of elasticity\n",
-      "##initialisation of variables\n",
-      "vi= 0.0009992 ##m^3\n",
-      "T= 60. ##C\n",
-      "T1= 20. ##C\n",
-      "T2= 40. ##C\n",
-      "vi1= 0.0010042 ##m^3\n",
-      "vi2= 0.0009886 ##m^3\n",
-      "v= 0.000951 ##m^3\n",
-      "v1= 0.0009992 ##m^3\n",
-      "v2= 0.0009956 ##m^3\n",
-      "##CALCULATIONS\n",
-      "B= (vi1-vi2)/(vi*(T-T1))\n",
-      "Kt= (v1-v2)/(v*(T2-T1))\n",
-      "Et= 1/Kt\n",
-      "##RESULTS\n",
-      "print'%s %.2e %s'% ('volume exapansion coefficient=',B,'L/s')\n",
-      "print'%s %.3e %s'% ('isothermal compressibility=',Kt,'Mpa')\n",
-      "print'%s %.f %s'% ('isothermal modulus of elasticity=',Et,'Mpa')\n",
-      "\n",
-      "\n",
-      "##ANSWER FOR Et GIVEN IN THE TEXTBOOK IS WRONG\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "volume exapansion coefficient= 3.90e-04 L/s\n",
-        "isothermal compressibility= 1.893e-04 Mpa\n",
-        "isothermal modulus of elasticity= 5283 Mpa\n"
-       ]
-      }
-     ],
-     "prompt_number": 4
-    }
-   ],
-   "metadata": {}
-  }
- ]
-}
-\ No newline at end of file
diff --git a/Thermodynamics:_From_concepts_to_applications/Chapter13-_thermodynamic_relations.ipynb b/Thermodynamics:_From_concepts_to_applications/Chapter13-_thermodynamic_relations.ipynb
deleted file mode 100755
index cb096e14..00000000
--- a/Thermodynamics:_From_concepts_to_applications/Chapter13-_thermodynamic_relations.ipynb
+++ /dev/null
@@ -1,217 +0,0 @@
-{
- "metadata": {
-  "name": "",
-  "signature": "sha256:8d95c094e950bc8cd1f4bbc97c09344d22cf81b1ba4d6101a144be7a5e1e83dc"
- },
- "nbformat": 3,
- "nbformat_minor": 0,
- "worksheets": [
-  {
-   "cells": [
-    {
-     "cell_type": "heading",
-     "level": 1,
-     "metadata": {},
-     "source": [
-      "Chapter13-thermodynamic relations"
-     ]
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Example2-pg284"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "#calculate entropy wrt pressures and volume wrt temerature\n",
-      "##initialisation of variables\n",
-      "S1= 6.539 ##kJ/kg K\n",
-      "S2= 6.7664 ##kJ/kg K\n",
-      "v1= 0.10976 ##m^3\n",
-      "v2= 0.08700 ##m^3\n",
-      "P= 3. ##Mpa\n",
-      "P1= 2. ##Mpa\n",
-      "T= 350. ##K\n",
-      "T1= 250. ##K\n",
-      "S3= 3.1741 ##kJ/kg K\n",
-      "S4= 3.2071 ##kJ/kg K\n",
-      "P2= 30. ##Mpa\n",
-      "P3= 20. ##Mpa\n",
-      "v3= 0.0014217 ##m^3\n",
-      "v4= 0.0012860 ##m^3\n",
-      "T2= 320. ##K\n",
-      "T3= 280. ##K\n",
-      "##CALCULATIONS\n",
-      "r= (S1-S2)/(P*10*10*10-P1*10*10*10)\n",
-      "r1= (v1-v2)/(T-T1)\n",
-      "R= (S3-S4)/(P2*10*10*10-P3*10*10*10)\n",
-      "R1= (v3-v4)/(T2-T3)\n",
-      "##RESULTS\n",
-      "print'%s %.7f %s'% ('entropy wrt pressre=',r,'kJ/kg K kpa')\n",
-      "print'%s %.e %s'% ('entropy wrt pressre=',R,'kJ/kg K kpa')\n",
-      "print'%s %.7f %s'%  ('volume wrt temperature=',r1,'m^3/kg K ')\n",
-      "print'%s %.2e %s'% ('volume wrt temperature=',R1,'m^3/kg K ')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "entropy wrt pressre= -0.0002274 kJ/kg K kpa\n",
-        "entropy wrt pressre= -3e-06 kJ/kg K kpa\n",
-        "volume wrt temperature= 0.0002276 m^3/kg K \n",
-        "volume wrt temperature= 3.39e-06 m^3/kg K \n"
-       ]
-      }
-     ],
-     "prompt_number": 6
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Example3-pg286"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "#saturation pressure\n",
-      "##initialisation of variables\n",
-      "hfg= 2406.7 ##kJ/kg\n",
-      "Psat40= 7.384 ##kPa\n",
-      "R= 8.314 ##J/mol K\n",
-      "T= 40. ##C\n",
-      "T1= 50. ##C\n",
-      "M= 18.##kg\n",
-      "##CALCULATIONS\n",
-      "Psat50= Psat40*math.e**((hfg*M/R)*((1/(273.15+T))-(1/(273.15+T1))))\n",
-      "##RESULTS\n",
-      "print'%s %.3f %s' %('Saturation pressure=',Psat50,'kPa')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "Saturation pressure= 12.357 kPa\n"
-       ]
-      }
-     ],
-     "prompt_number": 2
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Example4-pg287"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "#calcualte lowest temprature\n",
-      "##initialisation of variables\n",
-      "W= 800. ##N\n",
-      "A= 0.4 ##cm^2\n",
-      "p= 0.611 ##Mpa\n",
-      "P1= 0.1 ##Mpa\n",
-      "T= 0.01 ##C\n",
-      "vs= 0.0010908 ##m^3/kg\n",
-      "hs= -333.40 ##kJ/kg\n",
-      "vf= 0.0010002 ##m^3/kg\n",
-      "hf= 0 ##kJ/kg\n",
-      "vg= 206.14 ##m^3/kg\n",
-      "hg= 2501.4 ##kJ/kg\n",
-      "##CALCULATIONS\n",
-      "P2= P1+(W/A)*math.pow(10,(4-6))\n",
-      "dT= (273.15++T)*(vf-vs)*(P2*10*10*10-p)/(0-hs)\n",
-      "Tmin= dT+T\n",
-      "##RESULTS\n",
-      "print'%s %.2f %s'% ('lowest temperature=',Tmin,'C')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "lowest temperature= -1.48 C\n"
-       ]
-      }
-     ],
-     "prompt_number": 3
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Example7-pg292"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "#calculate volume exapansion coefficent and isothermal compressibilitiy and isotherma modulus of elasticity\n",
-      "##initialisation of variables\n",
-      "vi= 0.0009992 ##m^3\n",
-      "T= 60. ##C\n",
-      "T1= 20. ##C\n",
-      "T2= 40. ##C\n",
-      "vi1= 0.0010042 ##m^3\n",
-      "vi2= 0.0009886 ##m^3\n",
-      "v= 0.000951 ##m^3\n",
-      "v1= 0.0009992 ##m^3\n",
-      "v2= 0.0009956 ##m^3\n",
-      "##CALCULATIONS\n",
-      "B= (vi1-vi2)/(vi*(T-T1))\n",
-      "Kt= (v1-v2)/(v*(T2-T1))\n",
-      "Et= 1/Kt\n",
-      "##RESULTS\n",
-      "print'%s %.2e %s'% ('volume exapansion coefficient=',B,'L/s')\n",
-      "print'%s %.3e %s'% ('isothermal compressibility=',Kt,'Mpa')\n",
-      "print'%s %.f %s'% ('isothermal modulus of elasticity=',Et,'Mpa')\n",
-      "\n",
-      "\n",
-      "##ANSWER FOR Et GIVEN IN THE TEXTBOOK IS WRONG\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "volume exapansion coefficient= 3.90e-04 L/s\n",
-        "isothermal compressibility= 1.893e-04 Mpa\n",
-        "isothermal modulus of elasticity= 5283 Mpa\n"
-       ]
-      }
-     ],
-     "prompt_number": 4
-    }
-   ],
-   "metadata": {}
-  }
- ]
-}
-\ No newline at end of file
diff --git a/Thermodynamics:_From_concepts_to_applications/Chapter13.ipynb b/Thermodynamics:_From_concepts_to_applications/Chapter13.ipynb
deleted file mode 100755
index cb096e14..00000000
--- a/Thermodynamics:_From_concepts_to_applications/Chapter13.ipynb
+++ /dev/null
@@ -1,217 +0,0 @@
-{
- "metadata": {
-  "name": "",
-  "signature": "sha256:8d95c094e950bc8cd1f4bbc97c09344d22cf81b1ba4d6101a144be7a5e1e83dc"
- },
- "nbformat": 3,
- "nbformat_minor": 0,
- "worksheets": [
-  {
-   "cells": [
-    {
-     "cell_type": "heading",
-     "level": 1,
-     "metadata": {},
-     "source": [
-      "Chapter13-thermodynamic relations"
-     ]
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Example2-pg284"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "#calculate entropy wrt pressures and volume wrt temerature\n",
-      "##initialisation of variables\n",
-      "S1= 6.539 ##kJ/kg K\n",
-      "S2= 6.7664 ##kJ/kg K\n",
-      "v1= 0.10976 ##m^3\n",
-      "v2= 0.08700 ##m^3\n",
-      "P= 3. ##Mpa\n",
-      "P1= 2. ##Mpa\n",
-      "T= 350. ##K\n",
-      "T1= 250. ##K\n",
-      "S3= 3.1741 ##kJ/kg K\n",
-      "S4= 3.2071 ##kJ/kg K\n",
-      "P2= 30. ##Mpa\n",
-      "P3= 20. ##Mpa\n",
-      "v3= 0.0014217 ##m^3\n",
-      "v4= 0.0012860 ##m^3\n",
-      "T2= 320. ##K\n",
-      "T3= 280. ##K\n",
-      "##CALCULATIONS\n",
-      "r= (S1-S2)/(P*10*10*10-P1*10*10*10)\n",
-      "r1= (v1-v2)/(T-T1)\n",
-      "R= (S3-S4)/(P2*10*10*10-P3*10*10*10)\n",
-      "R1= (v3-v4)/(T2-T3)\n",
-      "##RESULTS\n",
-      "print'%s %.7f %s'% ('entropy wrt pressre=',r,'kJ/kg K kpa')\n",
-      "print'%s %.e %s'% ('entropy wrt pressre=',R,'kJ/kg K kpa')\n",
-      "print'%s %.7f %s'%  ('volume wrt temperature=',r1,'m^3/kg K ')\n",
-      "print'%s %.2e %s'% ('volume wrt temperature=',R1,'m^3/kg K ')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "entropy wrt pressre= -0.0002274 kJ/kg K kpa\n",
-        "entropy wrt pressre= -3e-06 kJ/kg K kpa\n",
-        "volume wrt temperature= 0.0002276 m^3/kg K \n",
-        "volume wrt temperature= 3.39e-06 m^3/kg K \n"
-       ]
-      }
-     ],
-     "prompt_number": 6
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Example3-pg286"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "#saturation pressure\n",
-      "##initialisation of variables\n",
-      "hfg= 2406.7 ##kJ/kg\n",
-      "Psat40= 7.384 ##kPa\n",
-      "R= 8.314 ##J/mol K\n",
-      "T= 40. ##C\n",
-      "T1= 50. ##C\n",
-      "M= 18.##kg\n",
-      "##CALCULATIONS\n",
-      "Psat50= Psat40*math.e**((hfg*M/R)*((1/(273.15+T))-(1/(273.15+T1))))\n",
-      "##RESULTS\n",
-      "print'%s %.3f %s' %('Saturation pressure=',Psat50,'kPa')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "Saturation pressure= 12.357 kPa\n"
-       ]
-      }
-     ],
-     "prompt_number": 2
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Example4-pg287"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "#calcualte lowest temprature\n",
-      "##initialisation of variables\n",
-      "W= 800. ##N\n",
-      "A= 0.4 ##cm^2\n",
-      "p= 0.611 ##Mpa\n",
-      "P1= 0.1 ##Mpa\n",
-      "T= 0.01 ##C\n",
-      "vs= 0.0010908 ##m^3/kg\n",
-      "hs= -333.40 ##kJ/kg\n",
-      "vf= 0.0010002 ##m^3/kg\n",
-      "hf= 0 ##kJ/kg\n",
-      "vg= 206.14 ##m^3/kg\n",
-      "hg= 2501.4 ##kJ/kg\n",
-      "##CALCULATIONS\n",
-      "P2= P1+(W/A)*math.pow(10,(4-6))\n",
-      "dT= (273.15++T)*(vf-vs)*(P2*10*10*10-p)/(0-hs)\n",
-      "Tmin= dT+T\n",
-      "##RESULTS\n",
-      "print'%s %.2f %s'% ('lowest temperature=',Tmin,'C')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "lowest temperature= -1.48 C\n"
-       ]
-      }
-     ],
-     "prompt_number": 3
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Example7-pg292"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "#calculate volume exapansion coefficent and isothermal compressibilitiy and isotherma modulus of elasticity\n",
-      "##initialisation of variables\n",
-      "vi= 0.0009992 ##m^3\n",
-      "T= 60. ##C\n",
-      "T1= 20. ##C\n",
-      "T2= 40. ##C\n",
-      "vi1= 0.0010042 ##m^3\n",
-      "vi2= 0.0009886 ##m^3\n",
-      "v= 0.000951 ##m^3\n",
-      "v1= 0.0009992 ##m^3\n",
-      "v2= 0.0009956 ##m^3\n",
-      "##CALCULATIONS\n",
-      "B= (vi1-vi2)/(vi*(T-T1))\n",
-      "Kt= (v1-v2)/(v*(T2-T1))\n",
-      "Et= 1/Kt\n",
-      "##RESULTS\n",
-      "print'%s %.2e %s'% ('volume exapansion coefficient=',B,'L/s')\n",
-      "print'%s %.3e %s'% ('isothermal compressibility=',Kt,'Mpa')\n",
-      "print'%s %.f %s'% ('isothermal modulus of elasticity=',Et,'Mpa')\n",
-      "\n",
-      "\n",
-      "##ANSWER FOR Et GIVEN IN THE TEXTBOOK IS WRONG\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "volume exapansion coefficient= 3.90e-04 L/s\n",
-        "isothermal compressibility= 1.893e-04 Mpa\n",
-        "isothermal modulus of elasticity= 5283 Mpa\n"
-       ]
-      }
-     ],
-     "prompt_number": 4
-    }
-   ],
-   "metadata": {}
-  }
- ]
-}
-\ No newline at end of file
diff --git a/Thermodynamics:_From_concepts_to_applications/Chapter13_1.ipynb b/Thermodynamics:_From_concepts_to_applications/Chapter13_1.ipynb
deleted file mode 100755
index cb096e14..00000000
--- a/Thermodynamics:_From_concepts_to_applications/Chapter13_1.ipynb
+++ /dev/null
@@ -1,217 +0,0 @@
-{
- "metadata": {
-  "name": "",
-  "signature": "sha256:8d95c094e950bc8cd1f4bbc97c09344d22cf81b1ba4d6101a144be7a5e1e83dc"
- },
- "nbformat": 3,
- "nbformat_minor": 0,
- "worksheets": [
-  {
-   "cells": [
-    {
-     "cell_type": "heading",
-     "level": 1,
-     "metadata": {},
-     "source": [
-      "Chapter13-thermodynamic relations"
-     ]
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Example2-pg284"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "#calculate entropy wrt pressures and volume wrt temerature\n",
-      "##initialisation of variables\n",
-      "S1= 6.539 ##kJ/kg K\n",
-      "S2= 6.7664 ##kJ/kg K\n",
-      "v1= 0.10976 ##m^3\n",
-      "v2= 0.08700 ##m^3\n",
-      "P= 3. ##Mpa\n",
-      "P1= 2. ##Mpa\n",
-      "T= 350. ##K\n",
-      "T1= 250. ##K\n",
-      "S3= 3.1741 ##kJ/kg K\n",
-      "S4= 3.2071 ##kJ/kg K\n",
-      "P2= 30. ##Mpa\n",
-      "P3= 20. ##Mpa\n",
-      "v3= 0.0014217 ##m^3\n",
-      "v4= 0.0012860 ##m^3\n",
-      "T2= 320. ##K\n",
-      "T3= 280. ##K\n",
-      "##CALCULATIONS\n",
-      "r= (S1-S2)/(P*10*10*10-P1*10*10*10)\n",
-      "r1= (v1-v2)/(T-T1)\n",
-      "R= (S3-S4)/(P2*10*10*10-P3*10*10*10)\n",
-      "R1= (v3-v4)/(T2-T3)\n",
-      "##RESULTS\n",
-      "print'%s %.7f %s'% ('entropy wrt pressre=',r,'kJ/kg K kpa')\n",
-      "print'%s %.e %s'% ('entropy wrt pressre=',R,'kJ/kg K kpa')\n",
-      "print'%s %.7f %s'%  ('volume wrt temperature=',r1,'m^3/kg K ')\n",
-      "print'%s %.2e %s'% ('volume wrt temperature=',R1,'m^3/kg K ')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "entropy wrt pressre= -0.0002274 kJ/kg K kpa\n",
-        "entropy wrt pressre= -3e-06 kJ/kg K kpa\n",
-        "volume wrt temperature= 0.0002276 m^3/kg K \n",
-        "volume wrt temperature= 3.39e-06 m^3/kg K \n"
-       ]
-      }
-     ],
-     "prompt_number": 6
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Example3-pg286"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "#saturation pressure\n",
-      "##initialisation of variables\n",
-      "hfg= 2406.7 ##kJ/kg\n",
-      "Psat40= 7.384 ##kPa\n",
-      "R= 8.314 ##J/mol K\n",
-      "T= 40. ##C\n",
-      "T1= 50. ##C\n",
-      "M= 18.##kg\n",
-      "##CALCULATIONS\n",
-      "Psat50= Psat40*math.e**((hfg*M/R)*((1/(273.15+T))-(1/(273.15+T1))))\n",
-      "##RESULTS\n",
-      "print'%s %.3f %s' %('Saturation pressure=',Psat50,'kPa')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "Saturation pressure= 12.357 kPa\n"
-       ]
-      }
-     ],
-     "prompt_number": 2
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Example4-pg287"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "#calcualte lowest temprature\n",
-      "##initialisation of variables\n",
-      "W= 800. ##N\n",
-      "A= 0.4 ##cm^2\n",
-      "p= 0.611 ##Mpa\n",
-      "P1= 0.1 ##Mpa\n",
-      "T= 0.01 ##C\n",
-      "vs= 0.0010908 ##m^3/kg\n",
-      "hs= -333.40 ##kJ/kg\n",
-      "vf= 0.0010002 ##m^3/kg\n",
-      "hf= 0 ##kJ/kg\n",
-      "vg= 206.14 ##m^3/kg\n",
-      "hg= 2501.4 ##kJ/kg\n",
-      "##CALCULATIONS\n",
-      "P2= P1+(W/A)*math.pow(10,(4-6))\n",
-      "dT= (273.15++T)*(vf-vs)*(P2*10*10*10-p)/(0-hs)\n",
-      "Tmin= dT+T\n",
-      "##RESULTS\n",
-      "print'%s %.2f %s'% ('lowest temperature=',Tmin,'C')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "lowest temperature= -1.48 C\n"
-       ]
-      }
-     ],
-     "prompt_number": 3
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Example7-pg292"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "#calculate volume exapansion coefficent and isothermal compressibilitiy and isotherma modulus of elasticity\n",
-      "##initialisation of variables\n",
-      "vi= 0.0009992 ##m^3\n",
-      "T= 60. ##C\n",
-      "T1= 20. ##C\n",
-      "T2= 40. ##C\n",
-      "vi1= 0.0010042 ##m^3\n",
-      "vi2= 0.0009886 ##m^3\n",
-      "v= 0.000951 ##m^3\n",
-      "v1= 0.0009992 ##m^3\n",
-      "v2= 0.0009956 ##m^3\n",
-      "##CALCULATIONS\n",
-      "B= (vi1-vi2)/(vi*(T-T1))\n",
-      "Kt= (v1-v2)/(v*(T2-T1))\n",
-      "Et= 1/Kt\n",
-      "##RESULTS\n",
-      "print'%s %.2e %s'% ('volume exapansion coefficient=',B,'L/s')\n",
-      "print'%s %.3e %s'% ('isothermal compressibility=',Kt,'Mpa')\n",
-      "print'%s %.f %s'% ('isothermal modulus of elasticity=',Et,'Mpa')\n",
-      "\n",
-      "\n",
-      "##ANSWER FOR Et GIVEN IN THE TEXTBOOK IS WRONG\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "volume exapansion coefficient= 3.90e-04 L/s\n",
-        "isothermal compressibility= 1.893e-04 Mpa\n",
-        "isothermal modulus of elasticity= 5283 Mpa\n"
-       ]
-      }
-     ],
-     "prompt_number": 4
-    }
-   ],
-   "metadata": {}
-  }
- ]
-}
-\ No newline at end of file
diff --git a/Thermodynamics:_From_concepts_to_applications/Chapter14.ipynb b/Thermodynamics:_From_concepts_to_applications/Chapter14.ipynb
deleted file mode 100755
index 5bcffb75..00000000
--- a/Thermodynamics:_From_concepts_to_applications/Chapter14.ipynb
+++ /dev/null
@@ -1,313 +0,0 @@
-{
- "metadata": {
-  "name": "",
-  "signature": "sha256:dceed5d123e7adb1d73db762a18a52615a5b487342c94704535d968cf751d6c0"
- },
- "nbformat": 3,
- "nbformat_minor": 0,
- "worksheets": [
-  {
-   "cells": [
-    {
-     "cell_type": "heading",
-     "level": 1,
-     "metadata": {},
-     "source": [
-      "chapter14-equations of state and generlized charts"
-     ]
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Example2-pg"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "import numpy\n",
-      "#calcualte isotherm\n",
-      "##initialisation of variables\n",
-      "a=552.6 ##kPa m^6/kmol^2\n",
-      "b= 0.03402 ##m^3/kmol\n",
-      "p= 100. ##kPa\n",
-      "R= 8.314 ##J/mol K\n",
-      "##CALCULATIONS\n",
-      "vec=([p,-a,2*a*b])\n",
-      "vector= numpy.roots(vec)\n",
-      "x=vec[0]\n",
-      "T= 2*a*(x-b)*(x-b)/(R*x*x*x)\n",
-      "##RESULTS\n",
-      "print'%s %.1f %s'% (' isotherm=',T,'K')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        " isotherm= 1.3 K\n"
-       ]
-      }
-     ],
-     "prompt_number": 5
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Example1-pg307"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "#calculate volumes of given temperatures\n",
-      "##initialisation of variables\n",
-      "R= 8.314 ##J/mol K\n",
-      "T= 400. ##C\n",
-      "T1= 500. ##C\n",
-      "M= 18.015 ##kg/k mol\n",
-      "p1= 30. ##Mpa\n",
-      "##CALCULATIONS\n",
-      "v1= R*(273.15+T)/(M*p1*10*10*10)\n",
-      "v2= R*(273.15+T1)/(M*p1*10*10*10)\n",
-      "##RESULTS\n",
-      "print'%s %.5f %s'% ('volume=',v1,'m^3/kg')\n",
-      "print'%s %.5f %s'% ('volume=',v2,'m^3/kg')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "volume= 0.01036 m^3/kg\n",
-        "volume= 0.01189 m^3/kg\n"
-       ]
-      }
-     ],
-     "prompt_number": 2
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Example2-pg310"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "#calculate specific enthalpy at each and every point their differences\n",
-      "##initialisation of variables\n",
-      "h1= 3892.2 ##kJ/kg\n",
-      "h2= 4102.2 ##kJ/kg\n",
-      "dh= 1015.4 ##kJ/kg\n",
-      "dh1= 448. ##kJ/kg\n",
-      "h3= 2151.1 ##kJ/kg\n",
-      "h4= 3081.1 ##kJ/kg\n",
-      "##RESULTS\n",
-      "print'%s %.1f %s'% ('Specific Enthalpy=',h1,'kJ/kg')\n",
-      "print'%s %.1f %s'% ('Specific Enthalpy=',h2,'kJ/kg')\n",
-      "print'%s %.1f %s'% ('Specific Enthalpy=',h3,'kJ/kg')\n",
-      "print'%s %.1f %s'% ('Specific Enthalpy=',h4,'kJ/kg')\n",
-      "print'%s %.f %s'% ('Enthalpy difference=',dh,'kJ/kg')\n",
-      "print'%s %.f %s'% ('Enthalpy difference=',dh1,'kJ/kg')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "Specific Enthalpy= 3892.2 kJ/kg\n",
-        "Specific Enthalpy= 4102.2 kJ/kg\n",
-        "Specific Enthalpy= 2151.1 kJ/kg\n",
-        "Specific Enthalpy= 3081.1 kJ/kg\n",
-        "Enthalpy difference= 1015 kJ/kg\n",
-        "Enthalpy difference= 448 kJ/kg\n"
-       ]
-      }
-     ],
-     "prompt_number": 4
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Example3-pg313"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "#calculate entropy at every point\n",
-      "##initialisation of variables\n",
-      "s2= 5.7905 ##kJ/kg K\n",
-      "s1= 4.4728 ##kJ/kg K\n",
-      "s3= 4.64437 ##kJ/kg K\n",
-      "s4= 5.7883 ##kJ/kg K\n",
-      "s5= 6.2036 ##kJ/kg K\n",
-      "s6= 5.9128 ##kJ/kg K\n",
-      "##CALCULATIONS\n",
-      "S1= s2-s1\n",
-      "S2= s4-s3\n",
-      "S3= s5-s6\n",
-      "##RESULTS\n",
-      "print'%s %.4f %s'% ('Entropy=',S1,'kJ/kg K')\n",
-      "print'%s %.4f %s'%  ('Entropy=',S2,'kJ/kg K')\n",
-      "print'%s %.4f %s'% ('Entropy=',S3,'kJ/kg K')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "Entropy= 1.3177 kJ/kg K\n",
-        "Entropy= 1.1439 kJ/kg K\n",
-        "Entropy= 0.2908 kJ/kg K\n"
-       ]
-      }
-     ],
-     "prompt_number": 5
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Example4-pg315"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "#calculate entrance velocity and exit velocity heat and maximum power and irreversibility\n",
-      "##initialisation of variables\n",
-      "m= 100. ##kg/s\n",
-      "M= 58. ##kg/kmol\n",
-      "v1= 0.164 ##m^3/kmol\n",
-      "r= 0.1 ##m\n",
-      "v2= 2.675 ##m^3/kmol \n",
-      "T= 175. ##C\n",
-      "T1= 80. ##C\n",
-      "cp= 1.75 ##kJ/kg\n",
-      "R= 8.314 ##J/mol K\n",
-      "dh= 3.6 ##kJ/kg\n",
-      "dh1= 0.5 ##kJ/kg\n",
-      "T2= 425 ##K\n",
-      "p2= 0.9 ##Mpa\n",
-      "p1= 7.5 ##Mpa\n",
-      "ds= 2.7*R \n",
-      "ds1= 0.4*R\n",
-      "##CAULATIONS\n",
-      "A= math.pi*r*r\n",
-      "n= m/M\n",
-      "V1= v1*n/A\n",
-      "V2= v2*n/A\n",
-      "Cp= M*cp\n",
-      "H= -(Cp*(T1-T)+(dh-dh1)*R*T2)\n",
-      "Q= n*(H+((M/1000)*((V2*V2-V1*V1)/2)))\n",
-      "dS= Cp*math.log((273.51+T1)/(273.15+T))+R*(-math.log(p2/p1)+((ds/R)-(ds1/R)))\n",
-      "Wmax= (Q-12)-n*(273.15+27)*(-dS)\n",
-      "I= Wmax\n",
-      "##RESULTS\n",
-      "print'%s %.f %s'% ('entrance velocity=',V1,'m/s')\n",
-      "print'%s %.1f %s'% ('exit velocity=',V2,'m/s')\n",
-      "print'%s %.1f %s'% ('Heat=',Q-12,'kW')\n",
-      "print'%s %.1f %s'% ('maximum power=',Wmax-54,'kW')\n",
-      "print'%s %.1f %s'% ('irreversiblity=',I-54,'kW')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "entrance velocity= 9 m/s\n",
-        "exit velocity= 146.8 m/s\n",
-        "Heat= -1199.1 kW\n",
-        "maximum power= 5305.0 kW\n",
-        "irreversiblity= 5305.0 kW\n"
-       ]
-      }
-     ],
-     "prompt_number": 6
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Example5-pg319"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "#calcualate work of compession and work of reversible isthoremal process and work\n",
-      "##initialisation of variables\n",
-      "R= 8.314 ##J/mol K\n",
-      "T= 400. ##C\n",
-      "M= 18.015 ##kg/s\n",
-      "p2= 30. ##Mpa\n",
-      "p1= 5. ##Mpa\n",
-      "f2= 17.7\n",
-      "f1=4.85\n",
-      "s1= 6.6459 ##kJ/kg K\n",
-      "s2= 4.4728 ##kJ/kg K\n",
-      "h1= 3195.7 ##kJ/kg\n",
-      "h2= 2151.1 ##kJ/kg\n",
-      "##CALCULATIONS\n",
-      "W= -R*(273.15+T)*math.log(p2/p1)/M\n",
-      "W1= -R*(273.15+T)*math.log(f2/f1)/M\n",
-      "W2= h1-h2-(273.15+T)*(s1-s2)\n",
-      "##RESULTS\n",
-      "print'%s %.1f %s'% ('Work of compression=',W,'kJ/kg')\n",
-      "print'%s %.1f %s'% ('Work of reversible isothermal process=',W1,'kJ/kg')\n",
-      "print'%s %.1f %s'% ('Work =',W2,'kJ/kg')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "Work of compression= -556.6 kJ/kg\n",
-        "Work of reversible isothermal process= -402.2 kJ/kg\n",
-        "Work = -418.2 kJ/kg\n"
-       ]
-      }
-     ],
-     "prompt_number": 7
-    }
-   ],
-   "metadata": {}
-  }
- ]
-}
-\ No newline at end of file
diff --git a/Thermodynamics:_From_concepts_to_applications/Chapter14_1.ipynb b/Thermodynamics:_From_concepts_to_applications/Chapter14_1.ipynb
deleted file mode 100755
index 5bcffb75..00000000
--- a/Thermodynamics:_From_concepts_to_applications/Chapter14_1.ipynb
+++ /dev/null
@@ -1,313 +0,0 @@
-{
- "metadata": {
-  "name": "",
-  "signature": "sha256:dceed5d123e7adb1d73db762a18a52615a5b487342c94704535d968cf751d6c0"
- },
- "nbformat": 3,
- "nbformat_minor": 0,
- "worksheets": [
-  {
-   "cells": [
-    {
-     "cell_type": "heading",
-     "level": 1,
-     "metadata": {},
-     "source": [
-      "chapter14-equations of state and generlized charts"
-     ]
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Example2-pg"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "import numpy\n",
-      "#calcualte isotherm\n",
-      "##initialisation of variables\n",
-      "a=552.6 ##kPa m^6/kmol^2\n",
-      "b= 0.03402 ##m^3/kmol\n",
-      "p= 100. ##kPa\n",
-      "R= 8.314 ##J/mol K\n",
-      "##CALCULATIONS\n",
-      "vec=([p,-a,2*a*b])\n",
-      "vector= numpy.roots(vec)\n",
-      "x=vec[0]\n",
-      "T= 2*a*(x-b)*(x-b)/(R*x*x*x)\n",
-      "##RESULTS\n",
-      "print'%s %.1f %s'% (' isotherm=',T,'K')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        " isotherm= 1.3 K\n"
-       ]
-      }
-     ],
-     "prompt_number": 5
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Example1-pg307"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "#calculate volumes of given temperatures\n",
-      "##initialisation of variables\n",
-      "R= 8.314 ##J/mol K\n",
-      "T= 400. ##C\n",
-      "T1= 500. ##C\n",
-      "M= 18.015 ##kg/k mol\n",
-      "p1= 30. ##Mpa\n",
-      "##CALCULATIONS\n",
-      "v1= R*(273.15+T)/(M*p1*10*10*10)\n",
-      "v2= R*(273.15+T1)/(M*p1*10*10*10)\n",
-      "##RESULTS\n",
-      "print'%s %.5f %s'% ('volume=',v1,'m^3/kg')\n",
-      "print'%s %.5f %s'% ('volume=',v2,'m^3/kg')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "volume= 0.01036 m^3/kg\n",
-        "volume= 0.01189 m^3/kg\n"
-       ]
-      }
-     ],
-     "prompt_number": 2
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Example2-pg310"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "#calculate specific enthalpy at each and every point their differences\n",
-      "##initialisation of variables\n",
-      "h1= 3892.2 ##kJ/kg\n",
-      "h2= 4102.2 ##kJ/kg\n",
-      "dh= 1015.4 ##kJ/kg\n",
-      "dh1= 448. ##kJ/kg\n",
-      "h3= 2151.1 ##kJ/kg\n",
-      "h4= 3081.1 ##kJ/kg\n",
-      "##RESULTS\n",
-      "print'%s %.1f %s'% ('Specific Enthalpy=',h1,'kJ/kg')\n",
-      "print'%s %.1f %s'% ('Specific Enthalpy=',h2,'kJ/kg')\n",
-      "print'%s %.1f %s'% ('Specific Enthalpy=',h3,'kJ/kg')\n",
-      "print'%s %.1f %s'% ('Specific Enthalpy=',h4,'kJ/kg')\n",
-      "print'%s %.f %s'% ('Enthalpy difference=',dh,'kJ/kg')\n",
-      "print'%s %.f %s'% ('Enthalpy difference=',dh1,'kJ/kg')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "Specific Enthalpy= 3892.2 kJ/kg\n",
-        "Specific Enthalpy= 4102.2 kJ/kg\n",
-        "Specific Enthalpy= 2151.1 kJ/kg\n",
-        "Specific Enthalpy= 3081.1 kJ/kg\n",
-        "Enthalpy difference= 1015 kJ/kg\n",
-        "Enthalpy difference= 448 kJ/kg\n"
-       ]
-      }
-     ],
-     "prompt_number": 4
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Example3-pg313"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "#calculate entropy at every point\n",
-      "##initialisation of variables\n",
-      "s2= 5.7905 ##kJ/kg K\n",
-      "s1= 4.4728 ##kJ/kg K\n",
-      "s3= 4.64437 ##kJ/kg K\n",
-      "s4= 5.7883 ##kJ/kg K\n",
-      "s5= 6.2036 ##kJ/kg K\n",
-      "s6= 5.9128 ##kJ/kg K\n",
-      "##CALCULATIONS\n",
-      "S1= s2-s1\n",
-      "S2= s4-s3\n",
-      "S3= s5-s6\n",
-      "##RESULTS\n",
-      "print'%s %.4f %s'% ('Entropy=',S1,'kJ/kg K')\n",
-      "print'%s %.4f %s'%  ('Entropy=',S2,'kJ/kg K')\n",
-      "print'%s %.4f %s'% ('Entropy=',S3,'kJ/kg K')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "Entropy= 1.3177 kJ/kg K\n",
-        "Entropy= 1.1439 kJ/kg K\n",
-        "Entropy= 0.2908 kJ/kg K\n"
-       ]
-      }
-     ],
-     "prompt_number": 5
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Example4-pg315"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "#calculate entrance velocity and exit velocity heat and maximum power and irreversibility\n",
-      "##initialisation of variables\n",
-      "m= 100. ##kg/s\n",
-      "M= 58. ##kg/kmol\n",
-      "v1= 0.164 ##m^3/kmol\n",
-      "r= 0.1 ##m\n",
-      "v2= 2.675 ##m^3/kmol \n",
-      "T= 175. ##C\n",
-      "T1= 80. ##C\n",
-      "cp= 1.75 ##kJ/kg\n",
-      "R= 8.314 ##J/mol K\n",
-      "dh= 3.6 ##kJ/kg\n",
-      "dh1= 0.5 ##kJ/kg\n",
-      "T2= 425 ##K\n",
-      "p2= 0.9 ##Mpa\n",
-      "p1= 7.5 ##Mpa\n",
-      "ds= 2.7*R \n",
-      "ds1= 0.4*R\n",
-      "##CAULATIONS\n",
-      "A= math.pi*r*r\n",
-      "n= m/M\n",
-      "V1= v1*n/A\n",
-      "V2= v2*n/A\n",
-      "Cp= M*cp\n",
-      "H= -(Cp*(T1-T)+(dh-dh1)*R*T2)\n",
-      "Q= n*(H+((M/1000)*((V2*V2-V1*V1)/2)))\n",
-      "dS= Cp*math.log((273.51+T1)/(273.15+T))+R*(-math.log(p2/p1)+((ds/R)-(ds1/R)))\n",
-      "Wmax= (Q-12)-n*(273.15+27)*(-dS)\n",
-      "I= Wmax\n",
-      "##RESULTS\n",
-      "print'%s %.f %s'% ('entrance velocity=',V1,'m/s')\n",
-      "print'%s %.1f %s'% ('exit velocity=',V2,'m/s')\n",
-      "print'%s %.1f %s'% ('Heat=',Q-12,'kW')\n",
-      "print'%s %.1f %s'% ('maximum power=',Wmax-54,'kW')\n",
-      "print'%s %.1f %s'% ('irreversiblity=',I-54,'kW')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "entrance velocity= 9 m/s\n",
-        "exit velocity= 146.8 m/s\n",
-        "Heat= -1199.1 kW\n",
-        "maximum power= 5305.0 kW\n",
-        "irreversiblity= 5305.0 kW\n"
-       ]
-      }
-     ],
-     "prompt_number": 6
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Example5-pg319"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "#calcualate work of compession and work of reversible isthoremal process and work\n",
-      "##initialisation of variables\n",
-      "R= 8.314 ##J/mol K\n",
-      "T= 400. ##C\n",
-      "M= 18.015 ##kg/s\n",
-      "p2= 30. ##Mpa\n",
-      "p1= 5. ##Mpa\n",
-      "f2= 17.7\n",
-      "f1=4.85\n",
-      "s1= 6.6459 ##kJ/kg K\n",
-      "s2= 4.4728 ##kJ/kg K\n",
-      "h1= 3195.7 ##kJ/kg\n",
-      "h2= 2151.1 ##kJ/kg\n",
-      "##CALCULATIONS\n",
-      "W= -R*(273.15+T)*math.log(p2/p1)/M\n",
-      "W1= -R*(273.15+T)*math.log(f2/f1)/M\n",
-      "W2= h1-h2-(273.15+T)*(s1-s2)\n",
-      "##RESULTS\n",
-      "print'%s %.1f %s'% ('Work of compression=',W,'kJ/kg')\n",
-      "print'%s %.1f %s'% ('Work of reversible isothermal process=',W1,'kJ/kg')\n",
-      "print'%s %.1f %s'% ('Work =',W2,'kJ/kg')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "Work of compression= -556.6 kJ/kg\n",
-        "Work of reversible isothermal process= -402.2 kJ/kg\n",
-        "Work = -418.2 kJ/kg\n"
-       ]
-      }
-     ],
-     "prompt_number": 7
-    }
-   ],
-   "metadata": {}
-  }
- ]
-}
-\ No newline at end of file
diff --git a/Thermodynamics:_From_concepts_to_applications/Chapter14_2.ipynb b/Thermodynamics:_From_concepts_to_applications/Chapter14_2.ipynb
deleted file mode 100755
index 5bcffb75..00000000
--- a/Thermodynamics:_From_concepts_to_applications/Chapter14_2.ipynb
+++ /dev/null
@@ -1,313 +0,0 @@
-{
- "metadata": {
-  "name": "",
-  "signature": "sha256:dceed5d123e7adb1d73db762a18a52615a5b487342c94704535d968cf751d6c0"
- },
- "nbformat": 3,
- "nbformat_minor": 0,
- "worksheets": [
-  {
-   "cells": [
-    {
-     "cell_type": "heading",
-     "level": 1,
-     "metadata": {},
-     "source": [
-      "chapter14-equations of state and generlized charts"
-     ]
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Example2-pg"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "import numpy\n",
-      "#calcualte isotherm\n",
-      "##initialisation of variables\n",
-      "a=552.6 ##kPa m^6/kmol^2\n",
-      "b= 0.03402 ##m^3/kmol\n",
-      "p= 100. ##kPa\n",
-      "R= 8.314 ##J/mol K\n",
-      "##CALCULATIONS\n",
-      "vec=([p,-a,2*a*b])\n",
-      "vector= numpy.roots(vec)\n",
-      "x=vec[0]\n",
-      "T= 2*a*(x-b)*(x-b)/(R*x*x*x)\n",
-      "##RESULTS\n",
-      "print'%s %.1f %s'% (' isotherm=',T,'K')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        " isotherm= 1.3 K\n"
-       ]
-      }
-     ],
-     "prompt_number": 5
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Example1-pg307"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "#calculate volumes of given temperatures\n",
-      "##initialisation of variables\n",
-      "R= 8.314 ##J/mol K\n",
-      "T= 400. ##C\n",
-      "T1= 500. ##C\n",
-      "M= 18.015 ##kg/k mol\n",
-      "p1= 30. ##Mpa\n",
-      "##CALCULATIONS\n",
-      "v1= R*(273.15+T)/(M*p1*10*10*10)\n",
-      "v2= R*(273.15+T1)/(M*p1*10*10*10)\n",
-      "##RESULTS\n",
-      "print'%s %.5f %s'% ('volume=',v1,'m^3/kg')\n",
-      "print'%s %.5f %s'% ('volume=',v2,'m^3/kg')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "volume= 0.01036 m^3/kg\n",
-        "volume= 0.01189 m^3/kg\n"
-       ]
-      }
-     ],
-     "prompt_number": 2
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Example2-pg310"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "#calculate specific enthalpy at each and every point their differences\n",
-      "##initialisation of variables\n",
-      "h1= 3892.2 ##kJ/kg\n",
-      "h2= 4102.2 ##kJ/kg\n",
-      "dh= 1015.4 ##kJ/kg\n",
-      "dh1= 448. ##kJ/kg\n",
-      "h3= 2151.1 ##kJ/kg\n",
-      "h4= 3081.1 ##kJ/kg\n",
-      "##RESULTS\n",
-      "print'%s %.1f %s'% ('Specific Enthalpy=',h1,'kJ/kg')\n",
-      "print'%s %.1f %s'% ('Specific Enthalpy=',h2,'kJ/kg')\n",
-      "print'%s %.1f %s'% ('Specific Enthalpy=',h3,'kJ/kg')\n",
-      "print'%s %.1f %s'% ('Specific Enthalpy=',h4,'kJ/kg')\n",
-      "print'%s %.f %s'% ('Enthalpy difference=',dh,'kJ/kg')\n",
-      "print'%s %.f %s'% ('Enthalpy difference=',dh1,'kJ/kg')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "Specific Enthalpy= 3892.2 kJ/kg\n",
-        "Specific Enthalpy= 4102.2 kJ/kg\n",
-        "Specific Enthalpy= 2151.1 kJ/kg\n",
-        "Specific Enthalpy= 3081.1 kJ/kg\n",
-        "Enthalpy difference= 1015 kJ/kg\n",
-        "Enthalpy difference= 448 kJ/kg\n"
-       ]
-      }
-     ],
-     "prompt_number": 4
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Example3-pg313"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "#calculate entropy at every point\n",
-      "##initialisation of variables\n",
-      "s2= 5.7905 ##kJ/kg K\n",
-      "s1= 4.4728 ##kJ/kg K\n",
-      "s3= 4.64437 ##kJ/kg K\n",
-      "s4= 5.7883 ##kJ/kg K\n",
-      "s5= 6.2036 ##kJ/kg K\n",
-      "s6= 5.9128 ##kJ/kg K\n",
-      "##CALCULATIONS\n",
-      "S1= s2-s1\n",
-      "S2= s4-s3\n",
-      "S3= s5-s6\n",
-      "##RESULTS\n",
-      "print'%s %.4f %s'% ('Entropy=',S1,'kJ/kg K')\n",
-      "print'%s %.4f %s'%  ('Entropy=',S2,'kJ/kg K')\n",
-      "print'%s %.4f %s'% ('Entropy=',S3,'kJ/kg K')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "Entropy= 1.3177 kJ/kg K\n",
-        "Entropy= 1.1439 kJ/kg K\n",
-        "Entropy= 0.2908 kJ/kg K\n"
-       ]
-      }
-     ],
-     "prompt_number": 5
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Example4-pg315"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "#calculate entrance velocity and exit velocity heat and maximum power and irreversibility\n",
-      "##initialisation of variables\n",
-      "m= 100. ##kg/s\n",
-      "M= 58. ##kg/kmol\n",
-      "v1= 0.164 ##m^3/kmol\n",
-      "r= 0.1 ##m\n",
-      "v2= 2.675 ##m^3/kmol \n",
-      "T= 175. ##C\n",
-      "T1= 80. ##C\n",
-      "cp= 1.75 ##kJ/kg\n",
-      "R= 8.314 ##J/mol K\n",
-      "dh= 3.6 ##kJ/kg\n",
-      "dh1= 0.5 ##kJ/kg\n",
-      "T2= 425 ##K\n",
-      "p2= 0.9 ##Mpa\n",
-      "p1= 7.5 ##Mpa\n",
-      "ds= 2.7*R \n",
-      "ds1= 0.4*R\n",
-      "##CAULATIONS\n",
-      "A= math.pi*r*r\n",
-      "n= m/M\n",
-      "V1= v1*n/A\n",
-      "V2= v2*n/A\n",
-      "Cp= M*cp\n",
-      "H= -(Cp*(T1-T)+(dh-dh1)*R*T2)\n",
-      "Q= n*(H+((M/1000)*((V2*V2-V1*V1)/2)))\n",
-      "dS= Cp*math.log((273.51+T1)/(273.15+T))+R*(-math.log(p2/p1)+((ds/R)-(ds1/R)))\n",
-      "Wmax= (Q-12)-n*(273.15+27)*(-dS)\n",
-      "I= Wmax\n",
-      "##RESULTS\n",
-      "print'%s %.f %s'% ('entrance velocity=',V1,'m/s')\n",
-      "print'%s %.1f %s'% ('exit velocity=',V2,'m/s')\n",
-      "print'%s %.1f %s'% ('Heat=',Q-12,'kW')\n",
-      "print'%s %.1f %s'% ('maximum power=',Wmax-54,'kW')\n",
-      "print'%s %.1f %s'% ('irreversiblity=',I-54,'kW')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "entrance velocity= 9 m/s\n",
-        "exit velocity= 146.8 m/s\n",
-        "Heat= -1199.1 kW\n",
-        "maximum power= 5305.0 kW\n",
-        "irreversiblity= 5305.0 kW\n"
-       ]
-      }
-     ],
-     "prompt_number": 6
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Example5-pg319"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "#calcualate work of compession and work of reversible isthoremal process and work\n",
-      "##initialisation of variables\n",
-      "R= 8.314 ##J/mol K\n",
-      "T= 400. ##C\n",
-      "M= 18.015 ##kg/s\n",
-      "p2= 30. ##Mpa\n",
-      "p1= 5. ##Mpa\n",
-      "f2= 17.7\n",
-      "f1=4.85\n",
-      "s1= 6.6459 ##kJ/kg K\n",
-      "s2= 4.4728 ##kJ/kg K\n",
-      "h1= 3195.7 ##kJ/kg\n",
-      "h2= 2151.1 ##kJ/kg\n",
-      "##CALCULATIONS\n",
-      "W= -R*(273.15+T)*math.log(p2/p1)/M\n",
-      "W1= -R*(273.15+T)*math.log(f2/f1)/M\n",
-      "W2= h1-h2-(273.15+T)*(s1-s2)\n",
-      "##RESULTS\n",
-      "print'%s %.1f %s'% ('Work of compression=',W,'kJ/kg')\n",
-      "print'%s %.1f %s'% ('Work of reversible isothermal process=',W1,'kJ/kg')\n",
-      "print'%s %.1f %s'% ('Work =',W2,'kJ/kg')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "Work of compression= -556.6 kJ/kg\n",
-        "Work of reversible isothermal process= -402.2 kJ/kg\n",
-        "Work = -418.2 kJ/kg\n"
-       ]
-      }
-     ],
-     "prompt_number": 7
-    }
-   ],
-   "metadata": {}
-  }
- ]
-}
-\ No newline at end of file
diff --git a/Thermodynamics:_From_concepts_to_applications/Chapter14_Equations_of_state_and_generlized_charts.ipynb b/Thermodynamics:_From_concepts_to_applications/Chapter14_Equations_of_state_and_generlized_charts.ipynb
deleted file mode 100755
index 5bcffb75..00000000
--- a/Thermodynamics:_From_concepts_to_applications/Chapter14_Equations_of_state_and_generlized_charts.ipynb
+++ /dev/null
@@ -1,313 +0,0 @@
-{
- "metadata": {
-  "name": "",
-  "signature": "sha256:dceed5d123e7adb1d73db762a18a52615a5b487342c94704535d968cf751d6c0"
- },
- "nbformat": 3,
- "nbformat_minor": 0,
- "worksheets": [
-  {
-   "cells": [
-    {
-     "cell_type": "heading",
-     "level": 1,
-     "metadata": {},
-     "source": [
-      "chapter14-equations of state and generlized charts"
-     ]
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Example2-pg"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "import numpy\n",
-      "#calcualte isotherm\n",
-      "##initialisation of variables\n",
-      "a=552.6 ##kPa m^6/kmol^2\n",
-      "b= 0.03402 ##m^3/kmol\n",
-      "p= 100. ##kPa\n",
-      "R= 8.314 ##J/mol K\n",
-      "##CALCULATIONS\n",
-      "vec=([p,-a,2*a*b])\n",
-      "vector= numpy.roots(vec)\n",
-      "x=vec[0]\n",
-      "T= 2*a*(x-b)*(x-b)/(R*x*x*x)\n",
-      "##RESULTS\n",
-      "print'%s %.1f %s'% (' isotherm=',T,'K')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        " isotherm= 1.3 K\n"
-       ]
-      }
-     ],
-     "prompt_number": 5
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Example1-pg307"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "#calculate volumes of given temperatures\n",
-      "##initialisation of variables\n",
-      "R= 8.314 ##J/mol K\n",
-      "T= 400. ##C\n",
-      "T1= 500. ##C\n",
-      "M= 18.015 ##kg/k mol\n",
-      "p1= 30. ##Mpa\n",
-      "##CALCULATIONS\n",
-      "v1= R*(273.15+T)/(M*p1*10*10*10)\n",
-      "v2= R*(273.15+T1)/(M*p1*10*10*10)\n",
-      "##RESULTS\n",
-      "print'%s %.5f %s'% ('volume=',v1,'m^3/kg')\n",
-      "print'%s %.5f %s'% ('volume=',v2,'m^3/kg')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "volume= 0.01036 m^3/kg\n",
-        "volume= 0.01189 m^3/kg\n"
-       ]
-      }
-     ],
-     "prompt_number": 2
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Example2-pg310"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "#calculate specific enthalpy at each and every point their differences\n",
-      "##initialisation of variables\n",
-      "h1= 3892.2 ##kJ/kg\n",
-      "h2= 4102.2 ##kJ/kg\n",
-      "dh= 1015.4 ##kJ/kg\n",
-      "dh1= 448. ##kJ/kg\n",
-      "h3= 2151.1 ##kJ/kg\n",
-      "h4= 3081.1 ##kJ/kg\n",
-      "##RESULTS\n",
-      "print'%s %.1f %s'% ('Specific Enthalpy=',h1,'kJ/kg')\n",
-      "print'%s %.1f %s'% ('Specific Enthalpy=',h2,'kJ/kg')\n",
-      "print'%s %.1f %s'% ('Specific Enthalpy=',h3,'kJ/kg')\n",
-      "print'%s %.1f %s'% ('Specific Enthalpy=',h4,'kJ/kg')\n",
-      "print'%s %.f %s'% ('Enthalpy difference=',dh,'kJ/kg')\n",
-      "print'%s %.f %s'% ('Enthalpy difference=',dh1,'kJ/kg')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "Specific Enthalpy= 3892.2 kJ/kg\n",
-        "Specific Enthalpy= 4102.2 kJ/kg\n",
-        "Specific Enthalpy= 2151.1 kJ/kg\n",
-        "Specific Enthalpy= 3081.1 kJ/kg\n",
-        "Enthalpy difference= 1015 kJ/kg\n",
-        "Enthalpy difference= 448 kJ/kg\n"
-       ]
-      }
-     ],
-     "prompt_number": 4
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Example3-pg313"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "#calculate entropy at every point\n",
-      "##initialisation of variables\n",
-      "s2= 5.7905 ##kJ/kg K\n",
-      "s1= 4.4728 ##kJ/kg K\n",
-      "s3= 4.64437 ##kJ/kg K\n",
-      "s4= 5.7883 ##kJ/kg K\n",
-      "s5= 6.2036 ##kJ/kg K\n",
-      "s6= 5.9128 ##kJ/kg K\n",
-      "##CALCULATIONS\n",
-      "S1= s2-s1\n",
-      "S2= s4-s3\n",
-      "S3= s5-s6\n",
-      "##RESULTS\n",
-      "print'%s %.4f %s'% ('Entropy=',S1,'kJ/kg K')\n",
-      "print'%s %.4f %s'%  ('Entropy=',S2,'kJ/kg K')\n",
-      "print'%s %.4f %s'% ('Entropy=',S3,'kJ/kg K')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "Entropy= 1.3177 kJ/kg K\n",
-        "Entropy= 1.1439 kJ/kg K\n",
-        "Entropy= 0.2908 kJ/kg K\n"
-       ]
-      }
-     ],
-     "prompt_number": 5
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Example4-pg315"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "#calculate entrance velocity and exit velocity heat and maximum power and irreversibility\n",
-      "##initialisation of variables\n",
-      "m= 100. ##kg/s\n",
-      "M= 58. ##kg/kmol\n",
-      "v1= 0.164 ##m^3/kmol\n",
-      "r= 0.1 ##m\n",
-      "v2= 2.675 ##m^3/kmol \n",
-      "T= 175. ##C\n",
-      "T1= 80. ##C\n",
-      "cp= 1.75 ##kJ/kg\n",
-      "R= 8.314 ##J/mol K\n",
-      "dh= 3.6 ##kJ/kg\n",
-      "dh1= 0.5 ##kJ/kg\n",
-      "T2= 425 ##K\n",
-      "p2= 0.9 ##Mpa\n",
-      "p1= 7.5 ##Mpa\n",
-      "ds= 2.7*R \n",
-      "ds1= 0.4*R\n",
-      "##CAULATIONS\n",
-      "A= math.pi*r*r\n",
-      "n= m/M\n",
-      "V1= v1*n/A\n",
-      "V2= v2*n/A\n",
-      "Cp= M*cp\n",
-      "H= -(Cp*(T1-T)+(dh-dh1)*R*T2)\n",
-      "Q= n*(H+((M/1000)*((V2*V2-V1*V1)/2)))\n",
-      "dS= Cp*math.log((273.51+T1)/(273.15+T))+R*(-math.log(p2/p1)+((ds/R)-(ds1/R)))\n",
-      "Wmax= (Q-12)-n*(273.15+27)*(-dS)\n",
-      "I= Wmax\n",
-      "##RESULTS\n",
-      "print'%s %.f %s'% ('entrance velocity=',V1,'m/s')\n",
-      "print'%s %.1f %s'% ('exit velocity=',V2,'m/s')\n",
-      "print'%s %.1f %s'% ('Heat=',Q-12,'kW')\n",
-      "print'%s %.1f %s'% ('maximum power=',Wmax-54,'kW')\n",
-      "print'%s %.1f %s'% ('irreversiblity=',I-54,'kW')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "entrance velocity= 9 m/s\n",
-        "exit velocity= 146.8 m/s\n",
-        "Heat= -1199.1 kW\n",
-        "maximum power= 5305.0 kW\n",
-        "irreversiblity= 5305.0 kW\n"
-       ]
-      }
-     ],
-     "prompt_number": 6
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Example5-pg319"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "#calcualate work of compession and work of reversible isthoremal process and work\n",
-      "##initialisation of variables\n",
-      "R= 8.314 ##J/mol K\n",
-      "T= 400. ##C\n",
-      "M= 18.015 ##kg/s\n",
-      "p2= 30. ##Mpa\n",
-      "p1= 5. ##Mpa\n",
-      "f2= 17.7\n",
-      "f1=4.85\n",
-      "s1= 6.6459 ##kJ/kg K\n",
-      "s2= 4.4728 ##kJ/kg K\n",
-      "h1= 3195.7 ##kJ/kg\n",
-      "h2= 2151.1 ##kJ/kg\n",
-      "##CALCULATIONS\n",
-      "W= -R*(273.15+T)*math.log(p2/p1)/M\n",
-      "W1= -R*(273.15+T)*math.log(f2/f1)/M\n",
-      "W2= h1-h2-(273.15+T)*(s1-s2)\n",
-      "##RESULTS\n",
-      "print'%s %.1f %s'% ('Work of compression=',W,'kJ/kg')\n",
-      "print'%s %.1f %s'% ('Work of reversible isothermal process=',W1,'kJ/kg')\n",
-      "print'%s %.1f %s'% ('Work =',W2,'kJ/kg')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "Work of compression= -556.6 kJ/kg\n",
-        "Work of reversible isothermal process= -402.2 kJ/kg\n",
-        "Work = -418.2 kJ/kg\n"
-       ]
-      }
-     ],
-     "prompt_number": 7
-    }
-   ],
-   "metadata": {}
-  }
- ]
-}
-\ No newline at end of file
diff --git a/Thermodynamics:_From_concepts_to_applications/Chapter15-.ipynb b/Thermodynamics:_From_concepts_to_applications/Chapter15-.ipynb
deleted file mode 100755
index 7474279a..00000000
--- a/Thermodynamics:_From_concepts_to_applications/Chapter15-.ipynb
+++ /dev/null
@@ -1,101 +0,0 @@
-{
- "metadata": {
-  "name": "",
-  "signature": "sha256:80d64855fab39260827744b179bb4ae70aaba7b386517244e3cbca404875a81d"
- },
- "nbformat": 3,
- "nbformat_minor": 0,
- "worksheets": [
-  {
-   "cells": [
-    {
-     "cell_type": "heading",
-     "level": 1,
-     "metadata": {},
-     "source": [
-      "Chapter15-multicomponet systems"
-     ]
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Example1-pg332"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "#calculate volume of the phase\n",
-      "##initialisation of variables\n",
-      "m2= 50. ##gms\n",
-      "M= 46. ##gms\n",
-      "m1= 50. ##gms\n",
-      "M1= 18. ##gms\n",
-      "v1= 17402. ##cm^3/kmol\n",
-      "v2= 56090. ##cm^3/kmol\n",
-      "##CALCULATIONS\n",
-      "x2= (m2/M)/((m2/M)+(m1/M1))\n",
-      "V= (v1*(m1/M1)+v2*(m2/M))*math.pow(10,-3)\n",
-      "##RESULTS\n",
-      "print'%s %.1f %s'% ('volume of the phase=',V,'cm^3')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "volume of the phase= 109.3 cm^3\n"
-       ]
-      }
-     ],
-     "prompt_number": 2
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Example2-337"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "#calcualte difference in enthalpy and amount of heat removed\n",
-      "##initialisation of variables\n",
-      "nw= 9 ##kmol\n",
-      "na= 1 ##kmol\n",
-      "##CALCULATIONS\n",
-      "dh= 75*nw*nw/math.pow(na+1.8*nw,2)\n",
-      "Q= -75*na*nw/(nw+1.8*na)\n",
-      "##RESULTS\n",
-      "print'%s %.2f %s'%  ('difference in enthalpy=',dh,'kJ/kg')\n",
-      "print'%s %.1f %s'% ('amount of heat removed=',Q,'kJ')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "difference in enthalpy= 20.53 kJ/kg\n",
-        "amount of heat removed= -62.5 kJ\n"
-       ]
-      }
-     ],
-     "prompt_number": 2
-    }
-   ],
-   "metadata": {}
-  }
- ]
-}
-\ No newline at end of file
diff --git a/Thermodynamics:_From_concepts_to_applications/Chapter15-multicomponet_systems.ipynb b/Thermodynamics:_From_concepts_to_applications/Chapter15-multicomponet_systems.ipynb
deleted file mode 100755
index 7474279a..00000000
--- a/Thermodynamics:_From_concepts_to_applications/Chapter15-multicomponet_systems.ipynb
+++ /dev/null
@@ -1,101 +0,0 @@
-{
- "metadata": {
-  "name": "",
-  "signature": "sha256:80d64855fab39260827744b179bb4ae70aaba7b386517244e3cbca404875a81d"
- },
- "nbformat": 3,
- "nbformat_minor": 0,
- "worksheets": [
-  {
-   "cells": [
-    {
-     "cell_type": "heading",
-     "level": 1,
-     "metadata": {},
-     "source": [
-      "Chapter15-multicomponet systems"
-     ]
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Example1-pg332"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "#calculate volume of the phase\n",
-      "##initialisation of variables\n",
-      "m2= 50. ##gms\n",
-      "M= 46. ##gms\n",
-      "m1= 50. ##gms\n",
-      "M1= 18. ##gms\n",
-      "v1= 17402. ##cm^3/kmol\n",
-      "v2= 56090. ##cm^3/kmol\n",
-      "##CALCULATIONS\n",
-      "x2= (m2/M)/((m2/M)+(m1/M1))\n",
-      "V= (v1*(m1/M1)+v2*(m2/M))*math.pow(10,-3)\n",
-      "##RESULTS\n",
-      "print'%s %.1f %s'% ('volume of the phase=',V,'cm^3')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "volume of the phase= 109.3 cm^3\n"
-       ]
-      }
-     ],
-     "prompt_number": 2
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Example2-337"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "#calcualte difference in enthalpy and amount of heat removed\n",
-      "##initialisation of variables\n",
-      "nw= 9 ##kmol\n",
-      "na= 1 ##kmol\n",
-      "##CALCULATIONS\n",
-      "dh= 75*nw*nw/math.pow(na+1.8*nw,2)\n",
-      "Q= -75*na*nw/(nw+1.8*na)\n",
-      "##RESULTS\n",
-      "print'%s %.2f %s'%  ('difference in enthalpy=',dh,'kJ/kg')\n",
-      "print'%s %.1f %s'% ('amount of heat removed=',Q,'kJ')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "difference in enthalpy= 20.53 kJ/kg\n",
-        "amount of heat removed= -62.5 kJ\n"
-       ]
-      }
-     ],
-     "prompt_number": 2
-    }
-   ],
-   "metadata": {}
-  }
- ]
-}
-\ No newline at end of file
diff --git a/Thermodynamics:_From_concepts_to_applications/Chapter15.ipynb b/Thermodynamics:_From_concepts_to_applications/Chapter15.ipynb
deleted file mode 100755
index 7474279a..00000000
--- a/Thermodynamics:_From_concepts_to_applications/Chapter15.ipynb
+++ /dev/null
@@ -1,101 +0,0 @@
-{
- "metadata": {
-  "name": "",
-  "signature": "sha256:80d64855fab39260827744b179bb4ae70aaba7b386517244e3cbca404875a81d"
- },
- "nbformat": 3,
- "nbformat_minor": 0,
- "worksheets": [
-  {
-   "cells": [
-    {
-     "cell_type": "heading",
-     "level": 1,
-     "metadata": {},
-     "source": [
-      "Chapter15-multicomponet systems"
-     ]
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Example1-pg332"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "#calculate volume of the phase\n",
-      "##initialisation of variables\n",
-      "m2= 50. ##gms\n",
-      "M= 46. ##gms\n",
-      "m1= 50. ##gms\n",
-      "M1= 18. ##gms\n",
-      "v1= 17402. ##cm^3/kmol\n",
-      "v2= 56090. ##cm^3/kmol\n",
-      "##CALCULATIONS\n",
-      "x2= (m2/M)/((m2/M)+(m1/M1))\n",
-      "V= (v1*(m1/M1)+v2*(m2/M))*math.pow(10,-3)\n",
-      "##RESULTS\n",
-      "print'%s %.1f %s'% ('volume of the phase=',V,'cm^3')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "volume of the phase= 109.3 cm^3\n"
-       ]
-      }
-     ],
-     "prompt_number": 2
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Example2-337"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "#calcualte difference in enthalpy and amount of heat removed\n",
-      "##initialisation of variables\n",
-      "nw= 9 ##kmol\n",
-      "na= 1 ##kmol\n",
-      "##CALCULATIONS\n",
-      "dh= 75*nw*nw/math.pow(na+1.8*nw,2)\n",
-      "Q= -75*na*nw/(nw+1.8*na)\n",
-      "##RESULTS\n",
-      "print'%s %.2f %s'%  ('difference in enthalpy=',dh,'kJ/kg')\n",
-      "print'%s %.1f %s'% ('amount of heat removed=',Q,'kJ')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "difference in enthalpy= 20.53 kJ/kg\n",
-        "amount of heat removed= -62.5 kJ\n"
-       ]
-      }
-     ],
-     "prompt_number": 2
-    }
-   ],
-   "metadata": {}
-  }
- ]
-}
-\ No newline at end of file
diff --git a/Thermodynamics:_From_concepts_to_applications/Chapter15_1.ipynb b/Thermodynamics:_From_concepts_to_applications/Chapter15_1.ipynb
deleted file mode 100755
index 7474279a..00000000
--- a/Thermodynamics:_From_concepts_to_applications/Chapter15_1.ipynb
+++ /dev/null
@@ -1,101 +0,0 @@
-{
- "metadata": {
-  "name": "",
-  "signature": "sha256:80d64855fab39260827744b179bb4ae70aaba7b386517244e3cbca404875a81d"
- },
- "nbformat": 3,
- "nbformat_minor": 0,
- "worksheets": [
-  {
-   "cells": [
-    {
-     "cell_type": "heading",
-     "level": 1,
-     "metadata": {},
-     "source": [
-      "Chapter15-multicomponet systems"
-     ]
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Example1-pg332"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "#calculate volume of the phase\n",
-      "##initialisation of variables\n",
-      "m2= 50. ##gms\n",
-      "M= 46. ##gms\n",
-      "m1= 50. ##gms\n",
-      "M1= 18. ##gms\n",
-      "v1= 17402. ##cm^3/kmol\n",
-      "v2= 56090. ##cm^3/kmol\n",
-      "##CALCULATIONS\n",
-      "x2= (m2/M)/((m2/M)+(m1/M1))\n",
-      "V= (v1*(m1/M1)+v2*(m2/M))*math.pow(10,-3)\n",
-      "##RESULTS\n",
-      "print'%s %.1f %s'% ('volume of the phase=',V,'cm^3')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "volume of the phase= 109.3 cm^3\n"
-       ]
-      }
-     ],
-     "prompt_number": 2
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Example2-337"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "#calcualte difference in enthalpy and amount of heat removed\n",
-      "##initialisation of variables\n",
-      "nw= 9 ##kmol\n",
-      "na= 1 ##kmol\n",
-      "##CALCULATIONS\n",
-      "dh= 75*nw*nw/math.pow(na+1.8*nw,2)\n",
-      "Q= -75*na*nw/(nw+1.8*na)\n",
-      "##RESULTS\n",
-      "print'%s %.2f %s'%  ('difference in enthalpy=',dh,'kJ/kg')\n",
-      "print'%s %.1f %s'% ('amount of heat removed=',Q,'kJ')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "difference in enthalpy= 20.53 kJ/kg\n",
-        "amount of heat removed= -62.5 kJ\n"
-       ]
-      }
-     ],
-     "prompt_number": 2
-    }
-   ],
-   "metadata": {}
-  }
- ]
-}
-\ No newline at end of file
diff --git a/Thermodynamics:_From_concepts_to_applications/Chapter16-.ipynb b/Thermodynamics:_From_concepts_to_applications/Chapter16-.ipynb
deleted file mode 100755
index b1fb1e8a..00000000
--- a/Thermodynamics:_From_concepts_to_applications/Chapter16-.ipynb
+++ /dev/null
@@ -1,109 +0,0 @@
-{
- "metadata": {
-  "name": "",
-  "signature": "sha256:e59b2fd71b4552cea44cac8d6a7db5757cb1bae32cfc202beb06aefa6735b63c"
- },
- "nbformat": 3,
- "nbformat_minor": 0,
- "worksheets": [
-  {
-   "cells": [
-    {
-     "cell_type": "heading",
-     "level": 1,
-     "metadata": {},
-     "source": [
-      "Chapter16-equlibrium"
-     ]
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Example1-pg349"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "#calculate entropy at the equllibrium state\n",
-      "##initialisation of variables\n",
-      "m= 10. ##kg\n",
-      "R= 8.314 ##J/mol K\n",
-      "k= 1.4\n",
-      "M= 29. ##kg\n",
-      "TA= 20. ##C\n",
-      "TB= 200. ##C\n",
-      "##CALCULATIONS\n",
-      "T= (TA+TB)/2\n",
-      "dS= 0.5*m*R*(math.log(273.15+T)*math.log(273.15+T))/((273.15+TA)*(273.15+TB))/((k-1)*M)\n",
-      "##RESULTS\n",
-      "print'%s %.4f %s'% ('entropy at the equillibrium state=',dS,'kJ/K')\n",
-      "\n",
-      "\n",
-      "##answer GIVEN IN THE TEXTBOOK IS WRONG\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "entropy at the equillibrium state= 0.0009 kJ/K\n"
-       ]
-      }
-     ],
-     "prompt_number": 2
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Example2-pg357"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "#calcualte equlibrium pressure and diameter of droplet\n",
-      "##initialisation of variables\n",
-      "psat= 143.3 ##kPa\n",
-      "R= 8.314 ##J/mol K\n",
-      "T= 110. ##C\n",
-      "m= 18.02 ##gms\n",
-      "pv= 150. ##kPa\n",
-      "v= 0.001052 ##m^3/kg\n",
-      "s= math.pow(10,-3)\n",
-      "##CALCULATIONS\n",
-      "PL= psat+((R*(273.15+T)/(m*0.0010502))*math.log(pv/psat))\n",
-      "D= (4*s/(PL-pv))*(75.64-13.91*(T/100)-3*(T/100)*(T/100))*10*10*10\n",
-      "##RESULTS\n",
-      "print'%s %.f %s'% ('equilibrium pressure=',PL-13,'kPa')\n",
-      "print'%s %.4f %s'% ('diameter of droplet=',D,'mm')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "equilibrium pressure= 7822 kPa\n",
-        "diameter of droplet= 0.0295 mm\n"
-       ]
-      }
-     ],
-     "prompt_number": 3
-    }
-   ],
-   "metadata": {}
-  }
- ]
-}
-\ No newline at end of file
diff --git a/Thermodynamics:_From_concepts_to_applications/Chapter16-Equlibrium.ipynb b/Thermodynamics:_From_concepts_to_applications/Chapter16-Equlibrium.ipynb
deleted file mode 100755
index b1fb1e8a..00000000
--- a/Thermodynamics:_From_concepts_to_applications/Chapter16-Equlibrium.ipynb
+++ /dev/null
@@ -1,109 +0,0 @@
-{
- "metadata": {
-  "name": "",
-  "signature": "sha256:e59b2fd71b4552cea44cac8d6a7db5757cb1bae32cfc202beb06aefa6735b63c"
- },
- "nbformat": 3,
- "nbformat_minor": 0,
- "worksheets": [
-  {
-   "cells": [
-    {
-     "cell_type": "heading",
-     "level": 1,
-     "metadata": {},
-     "source": [
-      "Chapter16-equlibrium"
-     ]
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Example1-pg349"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "#calculate entropy at the equllibrium state\n",
-      "##initialisation of variables\n",
-      "m= 10. ##kg\n",
-      "R= 8.314 ##J/mol K\n",
-      "k= 1.4\n",
-      "M= 29. ##kg\n",
-      "TA= 20. ##C\n",
-      "TB= 200. ##C\n",
-      "##CALCULATIONS\n",
-      "T= (TA+TB)/2\n",
-      "dS= 0.5*m*R*(math.log(273.15+T)*math.log(273.15+T))/((273.15+TA)*(273.15+TB))/((k-1)*M)\n",
-      "##RESULTS\n",
-      "print'%s %.4f %s'% ('entropy at the equillibrium state=',dS,'kJ/K')\n",
-      "\n",
-      "\n",
-      "##answer GIVEN IN THE TEXTBOOK IS WRONG\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "entropy at the equillibrium state= 0.0009 kJ/K\n"
-       ]
-      }
-     ],
-     "prompt_number": 2
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Example2-pg357"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "#calcualte equlibrium pressure and diameter of droplet\n",
-      "##initialisation of variables\n",
-      "psat= 143.3 ##kPa\n",
-      "R= 8.314 ##J/mol K\n",
-      "T= 110. ##C\n",
-      "m= 18.02 ##gms\n",
-      "pv= 150. ##kPa\n",
-      "v= 0.001052 ##m^3/kg\n",
-      "s= math.pow(10,-3)\n",
-      "##CALCULATIONS\n",
-      "PL= psat+((R*(273.15+T)/(m*0.0010502))*math.log(pv/psat))\n",
-      "D= (4*s/(PL-pv))*(75.64-13.91*(T/100)-3*(T/100)*(T/100))*10*10*10\n",
-      "##RESULTS\n",
-      "print'%s %.f %s'% ('equilibrium pressure=',PL-13,'kPa')\n",
-      "print'%s %.4f %s'% ('diameter of droplet=',D,'mm')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "equilibrium pressure= 7822 kPa\n",
-        "diameter of droplet= 0.0295 mm\n"
-       ]
-      }
-     ],
-     "prompt_number": 3
-    }
-   ],
-   "metadata": {}
-  }
- ]
-}
-\ No newline at end of file
diff --git a/Thermodynamics:_From_concepts_to_applications/Chapter16.ipynb b/Thermodynamics:_From_concepts_to_applications/Chapter16.ipynb
deleted file mode 100755
index b1fb1e8a..00000000
--- a/Thermodynamics:_From_concepts_to_applications/Chapter16.ipynb
+++ /dev/null
@@ -1,109 +0,0 @@
-{
- "metadata": {
-  "name": "",
-  "signature": "sha256:e59b2fd71b4552cea44cac8d6a7db5757cb1bae32cfc202beb06aefa6735b63c"
- },
- "nbformat": 3,
- "nbformat_minor": 0,
- "worksheets": [
-  {
-   "cells": [
-    {
-     "cell_type": "heading",
-     "level": 1,
-     "metadata": {},
-     "source": [
-      "Chapter16-equlibrium"
-     ]
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Example1-pg349"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "#calculate entropy at the equllibrium state\n",
-      "##initialisation of variables\n",
-      "m= 10. ##kg\n",
-      "R= 8.314 ##J/mol K\n",
-      "k= 1.4\n",
-      "M= 29. ##kg\n",
-      "TA= 20. ##C\n",
-      "TB= 200. ##C\n",
-      "##CALCULATIONS\n",
-      "T= (TA+TB)/2\n",
-      "dS= 0.5*m*R*(math.log(273.15+T)*math.log(273.15+T))/((273.15+TA)*(273.15+TB))/((k-1)*M)\n",
-      "##RESULTS\n",
-      "print'%s %.4f %s'% ('entropy at the equillibrium state=',dS,'kJ/K')\n",
-      "\n",
-      "\n",
-      "##answer GIVEN IN THE TEXTBOOK IS WRONG\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "entropy at the equillibrium state= 0.0009 kJ/K\n"
-       ]
-      }
-     ],
-     "prompt_number": 2
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Example2-pg357"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "#calcualte equlibrium pressure and diameter of droplet\n",
-      "##initialisation of variables\n",
-      "psat= 143.3 ##kPa\n",
-      "R= 8.314 ##J/mol K\n",
-      "T= 110. ##C\n",
-      "m= 18.02 ##gms\n",
-      "pv= 150. ##kPa\n",
-      "v= 0.001052 ##m^3/kg\n",
-      "s= math.pow(10,-3)\n",
-      "##CALCULATIONS\n",
-      "PL= psat+((R*(273.15+T)/(m*0.0010502))*math.log(pv/psat))\n",
-      "D= (4*s/(PL-pv))*(75.64-13.91*(T/100)-3*(T/100)*(T/100))*10*10*10\n",
-      "##RESULTS\n",
-      "print'%s %.f %s'% ('equilibrium pressure=',PL-13,'kPa')\n",
-      "print'%s %.4f %s'% ('diameter of droplet=',D,'mm')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "equilibrium pressure= 7822 kPa\n",
-        "diameter of droplet= 0.0295 mm\n"
-       ]
-      }
-     ],
-     "prompt_number": 3
-    }
-   ],
-   "metadata": {}
-  }
- ]
-}
-\ No newline at end of file
diff --git a/Thermodynamics:_From_concepts_to_applications/Chapter16_1.ipynb b/Thermodynamics:_From_concepts_to_applications/Chapter16_1.ipynb
deleted file mode 100755
index b1fb1e8a..00000000
--- a/Thermodynamics:_From_concepts_to_applications/Chapter16_1.ipynb
+++ /dev/null
@@ -1,109 +0,0 @@
-{
- "metadata": {
-  "name": "",
-  "signature": "sha256:e59b2fd71b4552cea44cac8d6a7db5757cb1bae32cfc202beb06aefa6735b63c"
- },
- "nbformat": 3,
- "nbformat_minor": 0,
- "worksheets": [
-  {
-   "cells": [
-    {
-     "cell_type": "heading",
-     "level": 1,
-     "metadata": {},
-     "source": [
-      "Chapter16-equlibrium"
-     ]
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Example1-pg349"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "#calculate entropy at the equllibrium state\n",
-      "##initialisation of variables\n",
-      "m= 10. ##kg\n",
-      "R= 8.314 ##J/mol K\n",
-      "k= 1.4\n",
-      "M= 29. ##kg\n",
-      "TA= 20. ##C\n",
-      "TB= 200. ##C\n",
-      "##CALCULATIONS\n",
-      "T= (TA+TB)/2\n",
-      "dS= 0.5*m*R*(math.log(273.15+T)*math.log(273.15+T))/((273.15+TA)*(273.15+TB))/((k-1)*M)\n",
-      "##RESULTS\n",
-      "print'%s %.4f %s'% ('entropy at the equillibrium state=',dS,'kJ/K')\n",
-      "\n",
-      "\n",
-      "##answer GIVEN IN THE TEXTBOOK IS WRONG\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "entropy at the equillibrium state= 0.0009 kJ/K\n"
-       ]
-      }
-     ],
-     "prompt_number": 2
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Example2-pg357"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "#calcualte equlibrium pressure and diameter of droplet\n",
-      "##initialisation of variables\n",
-      "psat= 143.3 ##kPa\n",
-      "R= 8.314 ##J/mol K\n",
-      "T= 110. ##C\n",
-      "m= 18.02 ##gms\n",
-      "pv= 150. ##kPa\n",
-      "v= 0.001052 ##m^3/kg\n",
-      "s= math.pow(10,-3)\n",
-      "##CALCULATIONS\n",
-      "PL= psat+((R*(273.15+T)/(m*0.0010502))*math.log(pv/psat))\n",
-      "D= (4*s/(PL-pv))*(75.64-13.91*(T/100)-3*(T/100)*(T/100))*10*10*10\n",
-      "##RESULTS\n",
-      "print'%s %.f %s'% ('equilibrium pressure=',PL-13,'kPa')\n",
-      "print'%s %.4f %s'% ('diameter of droplet=',D,'mm')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "equilibrium pressure= 7822 kPa\n",
-        "diameter of droplet= 0.0295 mm\n"
-       ]
-      }
-     ],
-     "prompt_number": 3
-    }
-   ],
-   "metadata": {}
-  }
- ]
-}
-\ No newline at end of file
diff --git a/Thermodynamics:_From_concepts_to_applications/Chapter17-.ipynb b/Thermodynamics:_From_concepts_to_applications/Chapter17-.ipynb
deleted file mode 100755
index 2d6dc101..00000000
--- a/Thermodynamics:_From_concepts_to_applications/Chapter17-.ipynb
+++ /dev/null
@@ -1,250 +0,0 @@
-{
- "metadata": {
-  "name": "",
-  "signature": "sha256:0bd1584504a5182c99f46d576a77cfaa07f83a047faf3b55eaafd0cea74518f2"
- },
- "nbformat": 3,
- "nbformat_minor": 0,
- "worksheets": [
-  {
-   "cells": [
-    {
-     "cell_type": "heading",
-     "level": 1,
-     "metadata": {},
-     "source": [
-      "Chapter17-Ideal solutions"
-     ]
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Example1-pg367"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "#calculate Total pressure and composition of vapour phases and composition of last drop liquids\n",
-      "##initialisation of variables\n",
-      "Pa= 40. ##kPa\n",
-      "Pb= 50. ##kPa\n",
-      "na= 2. ##moles\n",
-      "nb= 6. ##moles\n",
-      "##CALCULATIONS\n",
-      "a= Pb/Pa\n",
-      "xa= na/(na+nb)\n",
-      "xb= 1.-xa\n",
-      "p= xa*Pa+xb*Pb\n",
-      "y= (xa*Pa)/p\n",
-      "ya= 1.-y\n",
-      "Xa= a*xa/(1+(a-1)*xa)\n",
-      "Xb= 1.-Xa\n",
-      "##RESULTS\n",
-      "print'%s %.1f %s'%('Total pressure=',p,'kPa')\n",
-      "print'%s %.4f %s'%('composition of vapour phase=',y,'')\n",
-      "print'%s %.4f %s'%('composition of vapour phase=',ya,'')\n",
-      "print'%s %.4f %s'%('composition of last drop of liquid=',Xa,'')\n",
-      "print'%s %.4f %s'%('composition of last drop of liquid=',Xb,'')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "Total pressure= 47.5 kPa\n",
-        "composition of vapour phase= 0.2105 \n",
-        "composition of vapour phase= 0.7895 \n",
-        "composition of last drop of liquid= 0.2941 \n",
-        "composition of last drop of liquid= 0.7059 \n"
-       ]
-      }
-     ],
-     "prompt_number": 1
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Example2-pg371"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\t\n",
-      "#calculate pressure of the phase of pure A\n",
-      "##initialisation of variables\n",
-      "p0= 10. ##Mpa\n",
-      "R= 8.314 ##J/mol K\n",
-      "T= 30. ##C\n",
-      "va= 0.02 ##m^3/kmol\n",
-      "xa= 0.98\n",
-      "##CALCULATIONS\n",
-      "p= p0+(R*(273.15+T)*math.log(xa)/(va*1000.))\n",
-      "##RESULTS\n",
-      "print'%s %.2f %s'%('Pressure of the phase of pure A=',p,'Mpa')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "Pressure of the phase of pure A= 7.45 Mpa\n"
-       ]
-      }
-     ],
-     "prompt_number": 3
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Example3-pg373"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "#calculate the boiling point elevation\n",
-      "##initialisation of variables\n",
-      "hfg= 2257.0 ##kJ/kg\n",
-      "Tb= 100 ##C\n",
-      "R= 8.314 ##J/mol K\n",
-      "m2= 10 ##gms\n",
-      "M2= 58.5 ##gms\n",
-      "m1= 90. ##gms\n",
-      "M1= 18. ##gms\n",
-      "##CALCULATIONS\n",
-      "x2= (m2/M2)/((m2/M2)+(m1/M1))\n",
-      "dT= R*math.pow(273.15+Tb,2)*x2/(M1*hfg)\n",
-      "##RESULTS\n",
-      "print'%s %.3f %s'%(' Boiling point elevation=',dT,'C')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        " Boiling point elevation= 0.942 C\n"
-       ]
-      }
-     ],
-     "prompt_number": 4
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Example4-pg376"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "#calculate Osomatic pressures\n",
-      "##initialisation of variables\n",
-      "M1= 18.02 ##gms\n",
-      "m1= 0.965 ##gms\n",
-      "m2= 0.035 ##gms\n",
-      "M2= 58.5 ##gms\n",
-      "R= 8.314 ##J/mol K\n",
-      "M= 18.02 ##kg\n",
-      "T= 20. ##C\n",
-      "vf= 0.001002 ##m^3\n",
-      "x21= 0.021856 ##m^3\n",
-      "##CALCULATIONS\n",
-      "n1= m1/M1\n",
-      "n2= m2/M2\n",
-      "x1= n1/(n1+n2)\n",
-      "x2= n2/(n2+n1)\n",
-      "P= R*(273.15+T)*x2/(M*vf)\n",
-      "P1=  R*(273.15+T)*x21/(M*vf)\n",
-      "##RESULTS\n",
-      "print'%s %.1f %s'%('Osmotic pressure=',P,'kpa')\n",
-      "print'%s %.1f %s'%('Osmotic pressure=',P1,'kpa')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "Osmotic pressure= 1491.4 kpa\n",
-        "Osmotic pressure= 2950.2 kpa\n"
-       ]
-      }
-     ],
-     "prompt_number": 5
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Example5-pg377"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "#what is useful work in the process and heat interaction and maximum work and irreversibility\n",
-      "##initialisation of variables\n",
-      "W= 0.\n",
-      "Q= 0.\n",
-      "R= 8.314 ##J/mol K\n",
-      "T0= 300. ##K\n",
-      "x= 5./13.\n",
-      "n1= 0.5 ##kmol/s\n",
-      "n2= 0.8 ##kmol/s\n",
-      "##CALCULATIONS\n",
-      "W1= (n1+n2)*R*T0*(x*math.log(1/x)+(1-x)*math.log(1/(1-x)))\n",
-      "I= W1\n",
-      "##RESULTS\n",
-      "print'%s %.f %s'%('useful work of the process=',W,'kW') \n",
-      "print'%s %.f %s'%('heat interaction=',Q,'kW') \n",
-      "print'%s %.1f %s'%('maximum work=',W1,'kW') \n",
-      "print'%s %.1f %s'%('irreversibility=',I,'kW')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "useful work of the process= 0 kW\n",
-        "heat interaction= 0 kW\n",
-        "maximum work= 2160.4 kW\n",
-        "irreversibility= 2160.4 kW\n"
-       ]
-      }
-     ],
-     "prompt_number": 7
-    }
-   ],
-   "metadata": {}
-  }
- ]
-}
-\ No newline at end of file
diff --git a/Thermodynamics:_From_concepts_to_applications/Chapter17-Ideal_solutions.ipynb b/Thermodynamics:_From_concepts_to_applications/Chapter17-Ideal_solutions.ipynb
deleted file mode 100755
index 2d6dc101..00000000
--- a/Thermodynamics:_From_concepts_to_applications/Chapter17-Ideal_solutions.ipynb
+++ /dev/null
@@ -1,250 +0,0 @@
-{
- "metadata": {
-  "name": "",
-  "signature": "sha256:0bd1584504a5182c99f46d576a77cfaa07f83a047faf3b55eaafd0cea74518f2"
- },
- "nbformat": 3,
- "nbformat_minor": 0,
- "worksheets": [
-  {
-   "cells": [
-    {
-     "cell_type": "heading",
-     "level": 1,
-     "metadata": {},
-     "source": [
-      "Chapter17-Ideal solutions"
-     ]
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Example1-pg367"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "#calculate Total pressure and composition of vapour phases and composition of last drop liquids\n",
-      "##initialisation of variables\n",
-      "Pa= 40. ##kPa\n",
-      "Pb= 50. ##kPa\n",
-      "na= 2. ##moles\n",
-      "nb= 6. ##moles\n",
-      "##CALCULATIONS\n",
-      "a= Pb/Pa\n",
-      "xa= na/(na+nb)\n",
-      "xb= 1.-xa\n",
-      "p= xa*Pa+xb*Pb\n",
-      "y= (xa*Pa)/p\n",
-      "ya= 1.-y\n",
-      "Xa= a*xa/(1+(a-1)*xa)\n",
-      "Xb= 1.-Xa\n",
-      "##RESULTS\n",
-      "print'%s %.1f %s'%('Total pressure=',p,'kPa')\n",
-      "print'%s %.4f %s'%('composition of vapour phase=',y,'')\n",
-      "print'%s %.4f %s'%('composition of vapour phase=',ya,'')\n",
-      "print'%s %.4f %s'%('composition of last drop of liquid=',Xa,'')\n",
-      "print'%s %.4f %s'%('composition of last drop of liquid=',Xb,'')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "Total pressure= 47.5 kPa\n",
-        "composition of vapour phase= 0.2105 \n",
-        "composition of vapour phase= 0.7895 \n",
-        "composition of last drop of liquid= 0.2941 \n",
-        "composition of last drop of liquid= 0.7059 \n"
-       ]
-      }
-     ],
-     "prompt_number": 1
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Example2-pg371"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\t\n",
-      "#calculate pressure of the phase of pure A\n",
-      "##initialisation of variables\n",
-      "p0= 10. ##Mpa\n",
-      "R= 8.314 ##J/mol K\n",
-      "T= 30. ##C\n",
-      "va= 0.02 ##m^3/kmol\n",
-      "xa= 0.98\n",
-      "##CALCULATIONS\n",
-      "p= p0+(R*(273.15+T)*math.log(xa)/(va*1000.))\n",
-      "##RESULTS\n",
-      "print'%s %.2f %s'%('Pressure of the phase of pure A=',p,'Mpa')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "Pressure of the phase of pure A= 7.45 Mpa\n"
-       ]
-      }
-     ],
-     "prompt_number": 3
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Example3-pg373"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "#calculate the boiling point elevation\n",
-      "##initialisation of variables\n",
-      "hfg= 2257.0 ##kJ/kg\n",
-      "Tb= 100 ##C\n",
-      "R= 8.314 ##J/mol K\n",
-      "m2= 10 ##gms\n",
-      "M2= 58.5 ##gms\n",
-      "m1= 90. ##gms\n",
-      "M1= 18. ##gms\n",
-      "##CALCULATIONS\n",
-      "x2= (m2/M2)/((m2/M2)+(m1/M1))\n",
-      "dT= R*math.pow(273.15+Tb,2)*x2/(M1*hfg)\n",
-      "##RESULTS\n",
-      "print'%s %.3f %s'%(' Boiling point elevation=',dT,'C')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        " Boiling point elevation= 0.942 C\n"
-       ]
-      }
-     ],
-     "prompt_number": 4
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Example4-pg376"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "#calculate Osomatic pressures\n",
-      "##initialisation of variables\n",
-      "M1= 18.02 ##gms\n",
-      "m1= 0.965 ##gms\n",
-      "m2= 0.035 ##gms\n",
-      "M2= 58.5 ##gms\n",
-      "R= 8.314 ##J/mol K\n",
-      "M= 18.02 ##kg\n",
-      "T= 20. ##C\n",
-      "vf= 0.001002 ##m^3\n",
-      "x21= 0.021856 ##m^3\n",
-      "##CALCULATIONS\n",
-      "n1= m1/M1\n",
-      "n2= m2/M2\n",
-      "x1= n1/(n1+n2)\n",
-      "x2= n2/(n2+n1)\n",
-      "P= R*(273.15+T)*x2/(M*vf)\n",
-      "P1=  R*(273.15+T)*x21/(M*vf)\n",
-      "##RESULTS\n",
-      "print'%s %.1f %s'%('Osmotic pressure=',P,'kpa')\n",
-      "print'%s %.1f %s'%('Osmotic pressure=',P1,'kpa')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "Osmotic pressure= 1491.4 kpa\n",
-        "Osmotic pressure= 2950.2 kpa\n"
-       ]
-      }
-     ],
-     "prompt_number": 5
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Example5-pg377"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "#what is useful work in the process and heat interaction and maximum work and irreversibility\n",
-      "##initialisation of variables\n",
-      "W= 0.\n",
-      "Q= 0.\n",
-      "R= 8.314 ##J/mol K\n",
-      "T0= 300. ##K\n",
-      "x= 5./13.\n",
-      "n1= 0.5 ##kmol/s\n",
-      "n2= 0.8 ##kmol/s\n",
-      "##CALCULATIONS\n",
-      "W1= (n1+n2)*R*T0*(x*math.log(1/x)+(1-x)*math.log(1/(1-x)))\n",
-      "I= W1\n",
-      "##RESULTS\n",
-      "print'%s %.f %s'%('useful work of the process=',W,'kW') \n",
-      "print'%s %.f %s'%('heat interaction=',Q,'kW') \n",
-      "print'%s %.1f %s'%('maximum work=',W1,'kW') \n",
-      "print'%s %.1f %s'%('irreversibility=',I,'kW')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "useful work of the process= 0 kW\n",
-        "heat interaction= 0 kW\n",
-        "maximum work= 2160.4 kW\n",
-        "irreversibility= 2160.4 kW\n"
-       ]
-      }
-     ],
-     "prompt_number": 7
-    }
-   ],
-   "metadata": {}
-  }
- ]
-}
-\ No newline at end of file
diff --git a/Thermodynamics:_From_concepts_to_applications/Chapter17.ipynb b/Thermodynamics:_From_concepts_to_applications/Chapter17.ipynb
deleted file mode 100755
index 2d6dc101..00000000
--- a/Thermodynamics:_From_concepts_to_applications/Chapter17.ipynb
+++ /dev/null
@@ -1,250 +0,0 @@
-{
- "metadata": {
-  "name": "",
-  "signature": "sha256:0bd1584504a5182c99f46d576a77cfaa07f83a047faf3b55eaafd0cea74518f2"
- },
- "nbformat": 3,
- "nbformat_minor": 0,
- "worksheets": [
-  {
-   "cells": [
-    {
-     "cell_type": "heading",
-     "level": 1,
-     "metadata": {},
-     "source": [
-      "Chapter17-Ideal solutions"
-     ]
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Example1-pg367"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "#calculate Total pressure and composition of vapour phases and composition of last drop liquids\n",
-      "##initialisation of variables\n",
-      "Pa= 40. ##kPa\n",
-      "Pb= 50. ##kPa\n",
-      "na= 2. ##moles\n",
-      "nb= 6. ##moles\n",
-      "##CALCULATIONS\n",
-      "a= Pb/Pa\n",
-      "xa= na/(na+nb)\n",
-      "xb= 1.-xa\n",
-      "p= xa*Pa+xb*Pb\n",
-      "y= (xa*Pa)/p\n",
-      "ya= 1.-y\n",
-      "Xa= a*xa/(1+(a-1)*xa)\n",
-      "Xb= 1.-Xa\n",
-      "##RESULTS\n",
-      "print'%s %.1f %s'%('Total pressure=',p,'kPa')\n",
-      "print'%s %.4f %s'%('composition of vapour phase=',y,'')\n",
-      "print'%s %.4f %s'%('composition of vapour phase=',ya,'')\n",
-      "print'%s %.4f %s'%('composition of last drop of liquid=',Xa,'')\n",
-      "print'%s %.4f %s'%('composition of last drop of liquid=',Xb,'')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "Total pressure= 47.5 kPa\n",
-        "composition of vapour phase= 0.2105 \n",
-        "composition of vapour phase= 0.7895 \n",
-        "composition of last drop of liquid= 0.2941 \n",
-        "composition of last drop of liquid= 0.7059 \n"
-       ]
-      }
-     ],
-     "prompt_number": 1
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Example2-pg371"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\t\n",
-      "#calculate pressure of the phase of pure A\n",
-      "##initialisation of variables\n",
-      "p0= 10. ##Mpa\n",
-      "R= 8.314 ##J/mol K\n",
-      "T= 30. ##C\n",
-      "va= 0.02 ##m^3/kmol\n",
-      "xa= 0.98\n",
-      "##CALCULATIONS\n",
-      "p= p0+(R*(273.15+T)*math.log(xa)/(va*1000.))\n",
-      "##RESULTS\n",
-      "print'%s %.2f %s'%('Pressure of the phase of pure A=',p,'Mpa')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "Pressure of the phase of pure A= 7.45 Mpa\n"
-       ]
-      }
-     ],
-     "prompt_number": 3
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Example3-pg373"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "#calculate the boiling point elevation\n",
-      "##initialisation of variables\n",
-      "hfg= 2257.0 ##kJ/kg\n",
-      "Tb= 100 ##C\n",
-      "R= 8.314 ##J/mol K\n",
-      "m2= 10 ##gms\n",
-      "M2= 58.5 ##gms\n",
-      "m1= 90. ##gms\n",
-      "M1= 18. ##gms\n",
-      "##CALCULATIONS\n",
-      "x2= (m2/M2)/((m2/M2)+(m1/M1))\n",
-      "dT= R*math.pow(273.15+Tb,2)*x2/(M1*hfg)\n",
-      "##RESULTS\n",
-      "print'%s %.3f %s'%(' Boiling point elevation=',dT,'C')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        " Boiling point elevation= 0.942 C\n"
-       ]
-      }
-     ],
-     "prompt_number": 4
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Example4-pg376"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "#calculate Osomatic pressures\n",
-      "##initialisation of variables\n",
-      "M1= 18.02 ##gms\n",
-      "m1= 0.965 ##gms\n",
-      "m2= 0.035 ##gms\n",
-      "M2= 58.5 ##gms\n",
-      "R= 8.314 ##J/mol K\n",
-      "M= 18.02 ##kg\n",
-      "T= 20. ##C\n",
-      "vf= 0.001002 ##m^3\n",
-      "x21= 0.021856 ##m^3\n",
-      "##CALCULATIONS\n",
-      "n1= m1/M1\n",
-      "n2= m2/M2\n",
-      "x1= n1/(n1+n2)\n",
-      "x2= n2/(n2+n1)\n",
-      "P= R*(273.15+T)*x2/(M*vf)\n",
-      "P1=  R*(273.15+T)*x21/(M*vf)\n",
-      "##RESULTS\n",
-      "print'%s %.1f %s'%('Osmotic pressure=',P,'kpa')\n",
-      "print'%s %.1f %s'%('Osmotic pressure=',P1,'kpa')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "Osmotic pressure= 1491.4 kpa\n",
-        "Osmotic pressure= 2950.2 kpa\n"
-       ]
-      }
-     ],
-     "prompt_number": 5
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Example5-pg377"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "#what is useful work in the process and heat interaction and maximum work and irreversibility\n",
-      "##initialisation of variables\n",
-      "W= 0.\n",
-      "Q= 0.\n",
-      "R= 8.314 ##J/mol K\n",
-      "T0= 300. ##K\n",
-      "x= 5./13.\n",
-      "n1= 0.5 ##kmol/s\n",
-      "n2= 0.8 ##kmol/s\n",
-      "##CALCULATIONS\n",
-      "W1= (n1+n2)*R*T0*(x*math.log(1/x)+(1-x)*math.log(1/(1-x)))\n",
-      "I= W1\n",
-      "##RESULTS\n",
-      "print'%s %.f %s'%('useful work of the process=',W,'kW') \n",
-      "print'%s %.f %s'%('heat interaction=',Q,'kW') \n",
-      "print'%s %.1f %s'%('maximum work=',W1,'kW') \n",
-      "print'%s %.1f %s'%('irreversibility=',I,'kW')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "useful work of the process= 0 kW\n",
-        "heat interaction= 0 kW\n",
-        "maximum work= 2160.4 kW\n",
-        "irreversibility= 2160.4 kW\n"
-       ]
-      }
-     ],
-     "prompt_number": 7
-    }
-   ],
-   "metadata": {}
-  }
- ]
-}
-\ No newline at end of file
diff --git a/Thermodynamics:_From_concepts_to_applications/Chapter17_1.ipynb b/Thermodynamics:_From_concepts_to_applications/Chapter17_1.ipynb
deleted file mode 100755
index 2d6dc101..00000000
--- a/Thermodynamics:_From_concepts_to_applications/Chapter17_1.ipynb
+++ /dev/null
@@ -1,250 +0,0 @@
-{
- "metadata": {
-  "name": "",
-  "signature": "sha256:0bd1584504a5182c99f46d576a77cfaa07f83a047faf3b55eaafd0cea74518f2"
- },
- "nbformat": 3,
- "nbformat_minor": 0,
- "worksheets": [
-  {
-   "cells": [
-    {
-     "cell_type": "heading",
-     "level": 1,
-     "metadata": {},
-     "source": [
-      "Chapter17-Ideal solutions"
-     ]
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Example1-pg367"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "#calculate Total pressure and composition of vapour phases and composition of last drop liquids\n",
-      "##initialisation of variables\n",
-      "Pa= 40. ##kPa\n",
-      "Pb= 50. ##kPa\n",
-      "na= 2. ##moles\n",
-      "nb= 6. ##moles\n",
-      "##CALCULATIONS\n",
-      "a= Pb/Pa\n",
-      "xa= na/(na+nb)\n",
-      "xb= 1.-xa\n",
-      "p= xa*Pa+xb*Pb\n",
-      "y= (xa*Pa)/p\n",
-      "ya= 1.-y\n",
-      "Xa= a*xa/(1+(a-1)*xa)\n",
-      "Xb= 1.-Xa\n",
-      "##RESULTS\n",
-      "print'%s %.1f %s'%('Total pressure=',p,'kPa')\n",
-      "print'%s %.4f %s'%('composition of vapour phase=',y,'')\n",
-      "print'%s %.4f %s'%('composition of vapour phase=',ya,'')\n",
-      "print'%s %.4f %s'%('composition of last drop of liquid=',Xa,'')\n",
-      "print'%s %.4f %s'%('composition of last drop of liquid=',Xb,'')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "Total pressure= 47.5 kPa\n",
-        "composition of vapour phase= 0.2105 \n",
-        "composition of vapour phase= 0.7895 \n",
-        "composition of last drop of liquid= 0.2941 \n",
-        "composition of last drop of liquid= 0.7059 \n"
-       ]
-      }
-     ],
-     "prompt_number": 1
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Example2-pg371"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\t\n",
-      "#calculate pressure of the phase of pure A\n",
-      "##initialisation of variables\n",
-      "p0= 10. ##Mpa\n",
-      "R= 8.314 ##J/mol K\n",
-      "T= 30. ##C\n",
-      "va= 0.02 ##m^3/kmol\n",
-      "xa= 0.98\n",
-      "##CALCULATIONS\n",
-      "p= p0+(R*(273.15+T)*math.log(xa)/(va*1000.))\n",
-      "##RESULTS\n",
-      "print'%s %.2f %s'%('Pressure of the phase of pure A=',p,'Mpa')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "Pressure of the phase of pure A= 7.45 Mpa\n"
-       ]
-      }
-     ],
-     "prompt_number": 3
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Example3-pg373"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "#calculate the boiling point elevation\n",
-      "##initialisation of variables\n",
-      "hfg= 2257.0 ##kJ/kg\n",
-      "Tb= 100 ##C\n",
-      "R= 8.314 ##J/mol K\n",
-      "m2= 10 ##gms\n",
-      "M2= 58.5 ##gms\n",
-      "m1= 90. ##gms\n",
-      "M1= 18. ##gms\n",
-      "##CALCULATIONS\n",
-      "x2= (m2/M2)/((m2/M2)+(m1/M1))\n",
-      "dT= R*math.pow(273.15+Tb,2)*x2/(M1*hfg)\n",
-      "##RESULTS\n",
-      "print'%s %.3f %s'%(' Boiling point elevation=',dT,'C')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        " Boiling point elevation= 0.942 C\n"
-       ]
-      }
-     ],
-     "prompt_number": 4
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Example4-pg376"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "#calculate Osomatic pressures\n",
-      "##initialisation of variables\n",
-      "M1= 18.02 ##gms\n",
-      "m1= 0.965 ##gms\n",
-      "m2= 0.035 ##gms\n",
-      "M2= 58.5 ##gms\n",
-      "R= 8.314 ##J/mol K\n",
-      "M= 18.02 ##kg\n",
-      "T= 20. ##C\n",
-      "vf= 0.001002 ##m^3\n",
-      "x21= 0.021856 ##m^3\n",
-      "##CALCULATIONS\n",
-      "n1= m1/M1\n",
-      "n2= m2/M2\n",
-      "x1= n1/(n1+n2)\n",
-      "x2= n2/(n2+n1)\n",
-      "P= R*(273.15+T)*x2/(M*vf)\n",
-      "P1=  R*(273.15+T)*x21/(M*vf)\n",
-      "##RESULTS\n",
-      "print'%s %.1f %s'%('Osmotic pressure=',P,'kpa')\n",
-      "print'%s %.1f %s'%('Osmotic pressure=',P1,'kpa')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "Osmotic pressure= 1491.4 kpa\n",
-        "Osmotic pressure= 2950.2 kpa\n"
-       ]
-      }
-     ],
-     "prompt_number": 5
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Example5-pg377"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "#what is useful work in the process and heat interaction and maximum work and irreversibility\n",
-      "##initialisation of variables\n",
-      "W= 0.\n",
-      "Q= 0.\n",
-      "R= 8.314 ##J/mol K\n",
-      "T0= 300. ##K\n",
-      "x= 5./13.\n",
-      "n1= 0.5 ##kmol/s\n",
-      "n2= 0.8 ##kmol/s\n",
-      "##CALCULATIONS\n",
-      "W1= (n1+n2)*R*T0*(x*math.log(1/x)+(1-x)*math.log(1/(1-x)))\n",
-      "I= W1\n",
-      "##RESULTS\n",
-      "print'%s %.f %s'%('useful work of the process=',W,'kW') \n",
-      "print'%s %.f %s'%('heat interaction=',Q,'kW') \n",
-      "print'%s %.1f %s'%('maximum work=',W1,'kW') \n",
-      "print'%s %.1f %s'%('irreversibility=',I,'kW')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "useful work of the process= 0 kW\n",
-        "heat interaction= 0 kW\n",
-        "maximum work= 2160.4 kW\n",
-        "irreversibility= 2160.4 kW\n"
-       ]
-      }
-     ],
-     "prompt_number": 7
-    }
-   ],
-   "metadata": {}
-  }
- ]
-}
-\ No newline at end of file
diff --git a/Thermodynamics:_From_concepts_to_applications/Chapter18-.ipynb b/Thermodynamics:_From_concepts_to_applications/Chapter18-.ipynb
deleted file mode 100755
index 86e6ded4..00000000
--- a/Thermodynamics:_From_concepts_to_applications/Chapter18-.ipynb
+++ /dev/null
@@ -1,208 +0,0 @@
-{
- "metadata": {
-  "name": "",
-  "signature": "sha256:388411b55217b773ab745745bb0334d4f921763a66e2059d0e5fb20a6dddb702"
- },
- "nbformat": 3,
- "nbformat_minor": 0,
- "worksheets": [
-  {
-   "cells": [
-    {
-     "cell_type": "heading",
-     "level": 1,
-     "metadata": {},
-     "source": [
-      "Chapter18-Non-ideal solutions"
-     ]
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Example2-pg 385"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "#what is saturation pressure\n",
-      "##initialisation of variables\n",
-      "T= 80. ##C\n",
-      "p= 30. ##percent\n",
-      "pw= 47.39 ##kPa\n",
-      "psat= 36 ##kPa\n",
-      "##RESULTS\n",
-      "print'%s %.1f %s'%(' Saturation pressure=',psat,'kPa')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        " Saturation pressure= 36.0 kPa\n"
-       ]
-      }
-     ],
-     "prompt_number": 3
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Example3-pg 385"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "#what is temperature of pure water and saturation pressure\n",
-      "##initialisation of variables\n",
-      "T= 120. ##C\n",
-      "p= 30. ##percent\n",
-      "T2= 80. ##C\n",
-      "psat= 36. ##kPa\n",
-      "Tw= 73. ##C\n",
-      "##RESULTS\n",
-      "print'%s %.1f %s'% ('Temperature of pure water=',Tw,'C')\n",
-      "print'%s %.1f %s'% ('Saturation pressure=',psat,'kPa')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "Temperature of pure water= 73.0 C\n",
-        "Saturation pressure= 36.0 kPa\n"
-       ]
-      }
-     ],
-     "prompt_number": 4
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Example5-pg 395"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "#calculate enthalpys at 4 point and maximum temperature and new enthalpy\n",
-      "##initialisation of variables\n",
-      "p= 10. ##bar\n",
-      "P= 40. ##percent\n",
-      "x= 0.4\n",
-      "H1= 16. ##kcal/kg\n",
-      "H2= 31. ##kcal/kg\n",
-      "H3= 64. ##kcal/kg\n",
-      "H4= 140. ##kcal/kg\n",
-      "T= 157. ##C\n",
-      "He= 580. ##kcal/kg\n",
-      "##RESULTS\n",
-      "print'%s %.f %s'% ('Enthalpy=',H1,'kcal/kg')\n",
-      "print'%s %.f %s'% ('Enthalpy=',H2,'kcal/kg')\n",
-      "print'%s %.f %s'%  ('Enthalpy=',H3,'kcal/kg')\n",
-      "print'%s %.f %s'% ('Enthalpy=',H4,'kcal/kg')\n",
-      "print'%s %.f %s'% ('Maximum temperature=',T,'C')\n",
-      "print'%s %.f %s'% ('Enthalpy =',He,'kcal/kg')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "Enthalpy= 16 kcal/kg\n",
-        "Enthalpy= 31 kcal/kg\n",
-        "Enthalpy= 64 kcal/kg\n",
-        "Enthalpy= 140 kcal/kg\n",
-        "Maximum temperature= 157 C\n",
-        "Enthalpy = 580 kcal/kg\n"
-       ]
-      }
-     ],
-     "prompt_number": 6
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Example6-pg 397"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "#what is enthalpy and circulation ratio and COP and COPcarnot\n",
-      "##initialisation of variables\n",
-      "v= 0.0011 ##m^3\n",
-      "P1= 1200 ##Mpa\n",
-      "P2= 140 ##Mpa\n",
-      "h5= -103 ##kJ/kg\n",
-      "x4= 0.860\n",
-      "x7= 0.253\n",
-      "x5= 0.337\n",
-      "h1= 1658.1 ##kJ/kg\n",
-      "h7= 343.7 ##kJ/kg\n",
-      "h6= -1008 ##kJ/kg\n",
-      "h4= 639. ##kJ/kg\n",
-      "h3= 40. ##kJ/kg\n",
-      "Tc= -10. ##C\n",
-      "Th= 125. ##C\n",
-      "Ta= 25. ##C\n",
-      "m1= 1. ##kg/s\n",
-      "m7= 6.23 ##kg/s\n",
-      "m6= 7.23 ##kg/s\n",
-      "##CALCULATIONS\n",
-      "h6= h5+v*(P1-P2)\n",
-      "cr= (x4-x7)/(x5-x7)\n",
-      "Qhbym= h1+(m7/m1)*h7-(m6/m1)*h6\n",
-      "Qcbym= h4-h3\n",
-      "COP= Qcbym/Qhbym\n",
-      "COPcarnot= ((273.15+Tc)/(273.15+Th))*((Th-Ta)/(Ta-Tc))\n",
-      "##RESULTS\n",
-      "print'%s %.1f %s'% (' Enthalpy=',h6,'kJ/kg')\n",
-      "print'%s %.3f %s'% (' circulation ratio=',cr,'')\n",
-      "print'%s %.3f %s'% (' COP=',COP,'')\n",
-      "print'%s %.3f %s'%  (' COP carnot=',COPcarnot,'')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        " Enthalpy= -101.8 kJ/kg\n",
-        " circulation ratio= 7.226 \n",
-        " COP= 0.132 \n",
-        " COP carnot= 1.888 \n"
-       ]
-      }
-     ],
-     "prompt_number": 7
-    }
-   ],
-   "metadata": {}
-  }
- ]
-}
-\ No newline at end of file
diff --git a/Thermodynamics:_From_concepts_to_applications/Chapter18-Non-ideal_solutions.ipynb b/Thermodynamics:_From_concepts_to_applications/Chapter18-Non-ideal_solutions.ipynb
deleted file mode 100755
index 86e6ded4..00000000
--- a/Thermodynamics:_From_concepts_to_applications/Chapter18-Non-ideal_solutions.ipynb
+++ /dev/null
@@ -1,208 +0,0 @@
-{
- "metadata": {
-  "name": "",
-  "signature": "sha256:388411b55217b773ab745745bb0334d4f921763a66e2059d0e5fb20a6dddb702"
- },
- "nbformat": 3,
- "nbformat_minor": 0,
- "worksheets": [
-  {
-   "cells": [
-    {
-     "cell_type": "heading",
-     "level": 1,
-     "metadata": {},
-     "source": [
-      "Chapter18-Non-ideal solutions"
-     ]
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Example2-pg 385"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "#what is saturation pressure\n",
-      "##initialisation of variables\n",
-      "T= 80. ##C\n",
-      "p= 30. ##percent\n",
-      "pw= 47.39 ##kPa\n",
-      "psat= 36 ##kPa\n",
-      "##RESULTS\n",
-      "print'%s %.1f %s'%(' Saturation pressure=',psat,'kPa')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        " Saturation pressure= 36.0 kPa\n"
-       ]
-      }
-     ],
-     "prompt_number": 3
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Example3-pg 385"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "#what is temperature of pure water and saturation pressure\n",
-      "##initialisation of variables\n",
-      "T= 120. ##C\n",
-      "p= 30. ##percent\n",
-      "T2= 80. ##C\n",
-      "psat= 36. ##kPa\n",
-      "Tw= 73. ##C\n",
-      "##RESULTS\n",
-      "print'%s %.1f %s'% ('Temperature of pure water=',Tw,'C')\n",
-      "print'%s %.1f %s'% ('Saturation pressure=',psat,'kPa')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "Temperature of pure water= 73.0 C\n",
-        "Saturation pressure= 36.0 kPa\n"
-       ]
-      }
-     ],
-     "prompt_number": 4
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Example5-pg 395"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "#calculate enthalpys at 4 point and maximum temperature and new enthalpy\n",
-      "##initialisation of variables\n",
-      "p= 10. ##bar\n",
-      "P= 40. ##percent\n",
-      "x= 0.4\n",
-      "H1= 16. ##kcal/kg\n",
-      "H2= 31. ##kcal/kg\n",
-      "H3= 64. ##kcal/kg\n",
-      "H4= 140. ##kcal/kg\n",
-      "T= 157. ##C\n",
-      "He= 580. ##kcal/kg\n",
-      "##RESULTS\n",
-      "print'%s %.f %s'% ('Enthalpy=',H1,'kcal/kg')\n",
-      "print'%s %.f %s'% ('Enthalpy=',H2,'kcal/kg')\n",
-      "print'%s %.f %s'%  ('Enthalpy=',H3,'kcal/kg')\n",
-      "print'%s %.f %s'% ('Enthalpy=',H4,'kcal/kg')\n",
-      "print'%s %.f %s'% ('Maximum temperature=',T,'C')\n",
-      "print'%s %.f %s'% ('Enthalpy =',He,'kcal/kg')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "Enthalpy= 16 kcal/kg\n",
-        "Enthalpy= 31 kcal/kg\n",
-        "Enthalpy= 64 kcal/kg\n",
-        "Enthalpy= 140 kcal/kg\n",
-        "Maximum temperature= 157 C\n",
-        "Enthalpy = 580 kcal/kg\n"
-       ]
-      }
-     ],
-     "prompt_number": 6
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Example6-pg 397"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "#what is enthalpy and circulation ratio and COP and COPcarnot\n",
-      "##initialisation of variables\n",
-      "v= 0.0011 ##m^3\n",
-      "P1= 1200 ##Mpa\n",
-      "P2= 140 ##Mpa\n",
-      "h5= -103 ##kJ/kg\n",
-      "x4= 0.860\n",
-      "x7= 0.253\n",
-      "x5= 0.337\n",
-      "h1= 1658.1 ##kJ/kg\n",
-      "h7= 343.7 ##kJ/kg\n",
-      "h6= -1008 ##kJ/kg\n",
-      "h4= 639. ##kJ/kg\n",
-      "h3= 40. ##kJ/kg\n",
-      "Tc= -10. ##C\n",
-      "Th= 125. ##C\n",
-      "Ta= 25. ##C\n",
-      "m1= 1. ##kg/s\n",
-      "m7= 6.23 ##kg/s\n",
-      "m6= 7.23 ##kg/s\n",
-      "##CALCULATIONS\n",
-      "h6= h5+v*(P1-P2)\n",
-      "cr= (x4-x7)/(x5-x7)\n",
-      "Qhbym= h1+(m7/m1)*h7-(m6/m1)*h6\n",
-      "Qcbym= h4-h3\n",
-      "COP= Qcbym/Qhbym\n",
-      "COPcarnot= ((273.15+Tc)/(273.15+Th))*((Th-Ta)/(Ta-Tc))\n",
-      "##RESULTS\n",
-      "print'%s %.1f %s'% (' Enthalpy=',h6,'kJ/kg')\n",
-      "print'%s %.3f %s'% (' circulation ratio=',cr,'')\n",
-      "print'%s %.3f %s'% (' COP=',COP,'')\n",
-      "print'%s %.3f %s'%  (' COP carnot=',COPcarnot,'')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        " Enthalpy= -101.8 kJ/kg\n",
-        " circulation ratio= 7.226 \n",
-        " COP= 0.132 \n",
-        " COP carnot= 1.888 \n"
-       ]
-      }
-     ],
-     "prompt_number": 7
-    }
-   ],
-   "metadata": {}
-  }
- ]
-}
-\ No newline at end of file
diff --git a/Thermodynamics:_From_concepts_to_applications/Chapter18.ipynb b/Thermodynamics:_From_concepts_to_applications/Chapter18.ipynb
deleted file mode 100755
index 86e6ded4..00000000
--- a/Thermodynamics:_From_concepts_to_applications/Chapter18.ipynb
+++ /dev/null
@@ -1,208 +0,0 @@
-{
- "metadata": {
-  "name": "",
-  "signature": "sha256:388411b55217b773ab745745bb0334d4f921763a66e2059d0e5fb20a6dddb702"
- },
- "nbformat": 3,
- "nbformat_minor": 0,
- "worksheets": [
-  {
-   "cells": [
-    {
-     "cell_type": "heading",
-     "level": 1,
-     "metadata": {},
-     "source": [
-      "Chapter18-Non-ideal solutions"
-     ]
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Example2-pg 385"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "#what is saturation pressure\n",
-      "##initialisation of variables\n",
-      "T= 80. ##C\n",
-      "p= 30. ##percent\n",
-      "pw= 47.39 ##kPa\n",
-      "psat= 36 ##kPa\n",
-      "##RESULTS\n",
-      "print'%s %.1f %s'%(' Saturation pressure=',psat,'kPa')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        " Saturation pressure= 36.0 kPa\n"
-       ]
-      }
-     ],
-     "prompt_number": 3
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Example3-pg 385"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "#what is temperature of pure water and saturation pressure\n",
-      "##initialisation of variables\n",
-      "T= 120. ##C\n",
-      "p= 30. ##percent\n",
-      "T2= 80. ##C\n",
-      "psat= 36. ##kPa\n",
-      "Tw= 73. ##C\n",
-      "##RESULTS\n",
-      "print'%s %.1f %s'% ('Temperature of pure water=',Tw,'C')\n",
-      "print'%s %.1f %s'% ('Saturation pressure=',psat,'kPa')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "Temperature of pure water= 73.0 C\n",
-        "Saturation pressure= 36.0 kPa\n"
-       ]
-      }
-     ],
-     "prompt_number": 4
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Example5-pg 395"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "#calculate enthalpys at 4 point and maximum temperature and new enthalpy\n",
-      "##initialisation of variables\n",
-      "p= 10. ##bar\n",
-      "P= 40. ##percent\n",
-      "x= 0.4\n",
-      "H1= 16. ##kcal/kg\n",
-      "H2= 31. ##kcal/kg\n",
-      "H3= 64. ##kcal/kg\n",
-      "H4= 140. ##kcal/kg\n",
-      "T= 157. ##C\n",
-      "He= 580. ##kcal/kg\n",
-      "##RESULTS\n",
-      "print'%s %.f %s'% ('Enthalpy=',H1,'kcal/kg')\n",
-      "print'%s %.f %s'% ('Enthalpy=',H2,'kcal/kg')\n",
-      "print'%s %.f %s'%  ('Enthalpy=',H3,'kcal/kg')\n",
-      "print'%s %.f %s'% ('Enthalpy=',H4,'kcal/kg')\n",
-      "print'%s %.f %s'% ('Maximum temperature=',T,'C')\n",
-      "print'%s %.f %s'% ('Enthalpy =',He,'kcal/kg')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "Enthalpy= 16 kcal/kg\n",
-        "Enthalpy= 31 kcal/kg\n",
-        "Enthalpy= 64 kcal/kg\n",
-        "Enthalpy= 140 kcal/kg\n",
-        "Maximum temperature= 157 C\n",
-        "Enthalpy = 580 kcal/kg\n"
-       ]
-      }
-     ],
-     "prompt_number": 6
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Example6-pg 397"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "#what is enthalpy and circulation ratio and COP and COPcarnot\n",
-      "##initialisation of variables\n",
-      "v= 0.0011 ##m^3\n",
-      "P1= 1200 ##Mpa\n",
-      "P2= 140 ##Mpa\n",
-      "h5= -103 ##kJ/kg\n",
-      "x4= 0.860\n",
-      "x7= 0.253\n",
-      "x5= 0.337\n",
-      "h1= 1658.1 ##kJ/kg\n",
-      "h7= 343.7 ##kJ/kg\n",
-      "h6= -1008 ##kJ/kg\n",
-      "h4= 639. ##kJ/kg\n",
-      "h3= 40. ##kJ/kg\n",
-      "Tc= -10. ##C\n",
-      "Th= 125. ##C\n",
-      "Ta= 25. ##C\n",
-      "m1= 1. ##kg/s\n",
-      "m7= 6.23 ##kg/s\n",
-      "m6= 7.23 ##kg/s\n",
-      "##CALCULATIONS\n",
-      "h6= h5+v*(P1-P2)\n",
-      "cr= (x4-x7)/(x5-x7)\n",
-      "Qhbym= h1+(m7/m1)*h7-(m6/m1)*h6\n",
-      "Qcbym= h4-h3\n",
-      "COP= Qcbym/Qhbym\n",
-      "COPcarnot= ((273.15+Tc)/(273.15+Th))*((Th-Ta)/(Ta-Tc))\n",
-      "##RESULTS\n",
-      "print'%s %.1f %s'% (' Enthalpy=',h6,'kJ/kg')\n",
-      "print'%s %.3f %s'% (' circulation ratio=',cr,'')\n",
-      "print'%s %.3f %s'% (' COP=',COP,'')\n",
-      "print'%s %.3f %s'%  (' COP carnot=',COPcarnot,'')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        " Enthalpy= -101.8 kJ/kg\n",
-        " circulation ratio= 7.226 \n",
-        " COP= 0.132 \n",
-        " COP carnot= 1.888 \n"
-       ]
-      }
-     ],
-     "prompt_number": 7
-    }
-   ],
-   "metadata": {}
-  }
- ]
-}
-\ No newline at end of file
diff --git a/Thermodynamics:_From_concepts_to_applications/Chapter18_1.ipynb b/Thermodynamics:_From_concepts_to_applications/Chapter18_1.ipynb
deleted file mode 100755
index 86e6ded4..00000000
--- a/Thermodynamics:_From_concepts_to_applications/Chapter18_1.ipynb
+++ /dev/null
@@ -1,208 +0,0 @@
-{
- "metadata": {
-  "name": "",
-  "signature": "sha256:388411b55217b773ab745745bb0334d4f921763a66e2059d0e5fb20a6dddb702"
- },
- "nbformat": 3,
- "nbformat_minor": 0,
- "worksheets": [
-  {
-   "cells": [
-    {
-     "cell_type": "heading",
-     "level": 1,
-     "metadata": {},
-     "source": [
-      "Chapter18-Non-ideal solutions"
-     ]
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Example2-pg 385"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "#what is saturation pressure\n",
-      "##initialisation of variables\n",
-      "T= 80. ##C\n",
-      "p= 30. ##percent\n",
-      "pw= 47.39 ##kPa\n",
-      "psat= 36 ##kPa\n",
-      "##RESULTS\n",
-      "print'%s %.1f %s'%(' Saturation pressure=',psat,'kPa')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        " Saturation pressure= 36.0 kPa\n"
-       ]
-      }
-     ],
-     "prompt_number": 3
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Example3-pg 385"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "#what is temperature of pure water and saturation pressure\n",
-      "##initialisation of variables\n",
-      "T= 120. ##C\n",
-      "p= 30. ##percent\n",
-      "T2= 80. ##C\n",
-      "psat= 36. ##kPa\n",
-      "Tw= 73. ##C\n",
-      "##RESULTS\n",
-      "print'%s %.1f %s'% ('Temperature of pure water=',Tw,'C')\n",
-      "print'%s %.1f %s'% ('Saturation pressure=',psat,'kPa')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "Temperature of pure water= 73.0 C\n",
-        "Saturation pressure= 36.0 kPa\n"
-       ]
-      }
-     ],
-     "prompt_number": 4
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Example5-pg 395"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "#calculate enthalpys at 4 point and maximum temperature and new enthalpy\n",
-      "##initialisation of variables\n",
-      "p= 10. ##bar\n",
-      "P= 40. ##percent\n",
-      "x= 0.4\n",
-      "H1= 16. ##kcal/kg\n",
-      "H2= 31. ##kcal/kg\n",
-      "H3= 64. ##kcal/kg\n",
-      "H4= 140. ##kcal/kg\n",
-      "T= 157. ##C\n",
-      "He= 580. ##kcal/kg\n",
-      "##RESULTS\n",
-      "print'%s %.f %s'% ('Enthalpy=',H1,'kcal/kg')\n",
-      "print'%s %.f %s'% ('Enthalpy=',H2,'kcal/kg')\n",
-      "print'%s %.f %s'%  ('Enthalpy=',H3,'kcal/kg')\n",
-      "print'%s %.f %s'% ('Enthalpy=',H4,'kcal/kg')\n",
-      "print'%s %.f %s'% ('Maximum temperature=',T,'C')\n",
-      "print'%s %.f %s'% ('Enthalpy =',He,'kcal/kg')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "Enthalpy= 16 kcal/kg\n",
-        "Enthalpy= 31 kcal/kg\n",
-        "Enthalpy= 64 kcal/kg\n",
-        "Enthalpy= 140 kcal/kg\n",
-        "Maximum temperature= 157 C\n",
-        "Enthalpy = 580 kcal/kg\n"
-       ]
-      }
-     ],
-     "prompt_number": 6
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Example6-pg 397"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "#what is enthalpy and circulation ratio and COP and COPcarnot\n",
-      "##initialisation of variables\n",
-      "v= 0.0011 ##m^3\n",
-      "P1= 1200 ##Mpa\n",
-      "P2= 140 ##Mpa\n",
-      "h5= -103 ##kJ/kg\n",
-      "x4= 0.860\n",
-      "x7= 0.253\n",
-      "x5= 0.337\n",
-      "h1= 1658.1 ##kJ/kg\n",
-      "h7= 343.7 ##kJ/kg\n",
-      "h6= -1008 ##kJ/kg\n",
-      "h4= 639. ##kJ/kg\n",
-      "h3= 40. ##kJ/kg\n",
-      "Tc= -10. ##C\n",
-      "Th= 125. ##C\n",
-      "Ta= 25. ##C\n",
-      "m1= 1. ##kg/s\n",
-      "m7= 6.23 ##kg/s\n",
-      "m6= 7.23 ##kg/s\n",
-      "##CALCULATIONS\n",
-      "h6= h5+v*(P1-P2)\n",
-      "cr= (x4-x7)/(x5-x7)\n",
-      "Qhbym= h1+(m7/m1)*h7-(m6/m1)*h6\n",
-      "Qcbym= h4-h3\n",
-      "COP= Qcbym/Qhbym\n",
-      "COPcarnot= ((273.15+Tc)/(273.15+Th))*((Th-Ta)/(Ta-Tc))\n",
-      "##RESULTS\n",
-      "print'%s %.1f %s'% (' Enthalpy=',h6,'kJ/kg')\n",
-      "print'%s %.3f %s'% (' circulation ratio=',cr,'')\n",
-      "print'%s %.3f %s'% (' COP=',COP,'')\n",
-      "print'%s %.3f %s'%  (' COP carnot=',COPcarnot,'')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        " Enthalpy= -101.8 kJ/kg\n",
-        " circulation ratio= 7.226 \n",
-        " COP= 0.132 \n",
-        " COP carnot= 1.888 \n"
-       ]
-      }
-     ],
-     "prompt_number": 7
-    }
-   ],
-   "metadata": {}
-  }
- ]
-}
-\ No newline at end of file
diff --git a/Thermodynamics:_From_concepts_to_applications/Chapter19-Chemical_reactions.ipynb b/Thermodynamics:_From_concepts_to_applications/Chapter19-Chemical_reactions.ipynb
deleted file mode 100755
index fd5d0f72..00000000
--- a/Thermodynamics:_From_concepts_to_applications/Chapter19-Chemical_reactions.ipynb
+++ /dev/null
@@ -1,472 +0,0 @@
-{
- "metadata": {
-  "name": "",
-  "signature": "sha256:62da0bbd390eac5357f5f997103c8800ba34f828bad9afe3f011ec1444ac1334"
- },
- "nbformat": 3,
- "nbformat_minor": 0,
- "worksheets": [
-  {
-   "cells": [
-    {
-     "cell_type": "heading",
-     "level": 1,
-     "metadata": {},
-     "source": [
-      "Chapter19-Chemical reactions"
-     ]
-    },
-    {
-     "cell_type": "heading",
-     "level": 1,
-     "metadata": {},
-     "source": [
-      "Example1-pg 404"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "#caluclate fuel ratio and excess air and emass air-fuel ratio\n",
-      "##initialisation of variables\n",
-      "pN2= 79. ##percent\n",
-      "VN2= 82.3 ##m^3\n",
-      "VCO2= 8. ##m^3\n",
-      "VCO= 0.9 ##m^3\n",
-      "M= 32. ##gms\n",
-      "M1= 28. ##gms\n",
-      "##CALCULATIONS\n",
-      "P= (pN2/(100-pN2))\n",
-      "z= VN2/P\n",
-      "x= VCO2+VCO\n",
-      "w= VCO2+(VCO/2)+(VCO2/10)\n",
-      "y= 2*w\n",
-      "r= y/x\n",
-      "TO= x+(y/4)\n",
-      "X= (z/TO)-1\n",
-      "AF= z*(M+P*M1)/(12*x+y)\n",
-      "##RESULTS\n",
-      "print'%s %.3f %s'%('fuel ratio=',r,'')\n",
-      "print'%s %.3f %s'%('excess air=',X,'')\n",
-      "print'%s %.2f %s'%('emass air-fuel ratio=',AF,'')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "fuel ratio= 2.079 \n",
-        "excess air= 0.618 \n",
-        "emass air-fuel ratio= 23.98 \n"
-       ]
-      }
-     ],
-     "prompt_number": 2
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Example2-pg 410"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "#calculate heat interaction\n",
-      "##initialisation of variables\n",
-      "m1= 24. ##kg\n",
-      "M1= 32. ##kg\n",
-      "m2= 28. ##kg\n",
-      "M2= 28. ##kg\n",
-      "e= 0.5\n",
-      "T3= 1800. ##C\n",
-      "T0= 25. ##C\n",
-      "T1= 25. ##C\n",
-      "T2= 100. ##C\n",
-      "R= 8.314 ##Jmol K\n",
-      "cp= 4.57 ##J/mol K\n",
-      "cp1= 3.5 ##J/mol K\n",
-      "cp2= 3.5 ##J/mol K\n",
-      "hCO2= -393522. ##J\n",
-      "hCO= -110529. ##J\n",
-      "##CALCULATIONS\n",
-      "n1= m1/M1\n",
-      "n2= m2/M2\n",
-      "N= n1-0.5*e\n",
-      "N1= n2-e\n",
-      "N2= e\n",
-      "N3= N+N1+N2\n",
-      "y1= N/N3\n",
-      "Q= ((N*cp+N1*cp1+N2*cp2)*R*(T3-T0)-(n1*cp*(T1-T0)+n2*cp2*(T2-T1))+N*(hCO2-hCO))/60.\n",
-      "##RESULTS\n",
-      "print'%s %.f %s'%(' Heat interaction=',Q,'kW ')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        " Heat interaction= -940 kW \n"
-       ]
-      }
-     ],
-     "prompt_number": 4
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Example3-pg 412"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "#calculate adiabatic flame temperature\n",
-      "##initialisation of variables\n",
-      "T0= 25. ##C\n",
-      "T1= 220. ##C\n",
-      "hCO2= -393520 ##kJ/kg\n",
-      "hH2O= -241830 ##kJ/kg\n",
-      "hC3H8= -103850 ##kJ/kg= 1.4\n",
-      "R= 8.314 ##Jmol K\n",
-      "k= 1.4\n",
-      "k1= 1.29\n",
-      "##CALCULATIONS\n",
-      "T= T0+((15*(R*(k/(k-1)))*4.762*(T1-T0)-(3*hCO2+4*hH2O-hC3H8))/(R*((3+4)*(k1/(k1-1))+(10+56.43)*(k/(k-1)))))\n",
-      "##RESULTS\n",
-      "print'%s %.1f %s'%('adiabatic flame temperature=',T,'C ')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "adiabatic flame temperature= 1142.4 C \n"
-       ]
-      }
-     ],
-     "prompt_number": 1
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Example5-pg 415"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "#calculate enthalpy formation\n",
-      "##initialisation of variables\n",
-      "T= 25. ##C\n",
-      "hfT= -241820 ##kJ/kmol\n",
-      "R= 8.314 ##J/mol K\n",
-      "k= 1.4\n",
-      "cpH2O= 4.45\n",
-      "cpO2= 3.5\n",
-      "T1= 1000. ##C\n",
-      "##CALCULATIONS\n",
-      "S= (cpH2O-k*cpO2)\n",
-      "hfT1= hfT+S*(T1-T)\n",
-      "##RESULTS\n",
-      "print'%s %.f %s'%('enthalpy formation=',hfT1,'kJ/kmol ')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "enthalpy formation= -242259 kJ/kmol \n"
-       ]
-      }
-     ],
-     "prompt_number": 8
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Example6-pg 418"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "#calculate equlibrium constant at K and KT1\n",
-      "##initialisation of variables\n",
-      "R= 8.314 ##J/mol K\n",
-      "T= 25. ##C\n",
-      "gf= 16590. ##kJ/kmol\n",
-      "T1= 500. ##C\n",
-      "Cp= 4.157 ##J/mol K\n",
-      "hf= -46190 ##kJ/kmol\n",
-      "e=0.5\n",
-      "##CALCULATIONS\n",
-      "K=math.pow(math.e,gf/(R*(273.15+T)))\n",
-      "r= (1-((273.15+T)/(273.15+T1)))*((hf/(R*(273.15+T)))+(R/Cp))-2*math.log((273.15+T1)/(273.15+T))+0.6\n",
-      "KT1= K*math.pow(math.e,r)\n",
-      "##RESULTS\n",
-      "print'%s %.1f %s'%('equilibrium constant=',K,'bar^-1 ')\n",
-      "print'%s %.5f %s'%('equilibrium constant=',KT1,'bar^-1 ')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "equilibrium constant= 806.5 bar^-1 \n",
-        "equilibrium constant= 0.00797 bar^-1 \n"
-       ]
-      }
-     ],
-     "prompt_number": 9
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Example7-pg 419"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "#what equilibrium constant at T1 and T2\n",
-      "##initialisation of variables\n",
-      "uCO2= -394374 ##J/mol\n",
-      "uCO= -137150 ##J/mol\n",
-      "uO2= 0.\n",
-      "R= 8.314 ##J/mol K\n",
-      "T= 25. ##C\n",
-      "cpCO2= 4.57 ##J/mol K\n",
-      "cpCO= 3.5 ##J/mol K\n",
-      "cpO2= 3.5 ##J/mol K\n",
-      "T1= 1500. ##C\n",
-      "hf= -393522 ##kJ/kmol\n",
-      "gf= -110529 ##kJ/kmol\n",
-      "T2= 2500. ##C\n",
-      "##CALCULATIONS\n",
-      "r= -(uCO2-uCO-0.5*uO2)/(R*(273.15+T))\n",
-      "s= (cpCO2-cpCO-0.5*cpO2)\n",
-      "r1= (1-((273.15+T)/(273.15+T1)))*((hf-gf)/(R*(273.15+T))-s)+s*math.log((273.15+T1)/(273.15+T))\n",
-      "KT1= math.pow(math.e,r+r1)\n",
-      "r2= (1-((273.15+T)/(273.15+T2)))*((hf-gf)/(R*(273.15+T))-s)+s*math.log((273.15+T2)/(273.15+T))\n",
-      "KT2= math.pow(math.e,r+r2)\n",
-      "##RESULTS\n",
-      "print'%s %.f %s'%('equilibrium constant at T1=',KT1,'C ')\n",
-      "print'%s %.3f %s'%('equilibrium constant at T2=',KT2,'C ')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "equilibrium constant at T1= 3477 C \n",
-        "equilibrium constant at T2= 2.635 C \n"
-       ]
-      }
-     ],
-     "prompt_number": 10
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Example8-pg422"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "#what is maximum work of given variable \n",
-      "##initialisation of variables\n",
-      "Wc= 12. ##kg\n",
-      "hf= -393520 ##kJ/kmol\n",
-      "gf= -394360 ##kJ/kmol\n",
-      "##CALCULATIONS\n",
-      "Wmax= -gf/Wc\n",
-      "##RESULTS\n",
-      "print'%s %.f %s'%('maximum work=',Wmax,'kJ/kg of carbon ')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "maximum work= 32863 kJ/kg of carbon \n"
-       ]
-      }
-     ],
-     "prompt_number": 11
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Example9-pg423"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "#calculate the outlet temperature and energy of formation and energy out let and energy of the products\n",
-      "##initialisation of variables\n",
-      "T= 25 ##C\n",
-      "R= 8.314 ##Jmol K\n",
-      "k= 1.27\n",
-      "k1= 1.34\n",
-      "hf= -393520 ##kJ/kmol\n",
-      "M= 28 ##gms\n",
-      "gf= -394360 ##kJ/kmol\n",
-      "M= 12 ##gms\n",
-      "##CALCULATIONS\n",
-      "T1= T+(-hf/((R)*((k/(k-1))+(0.2+4.5144)*(k1/(k1-1)))))\n",
-      "Bin= 0\n",
-      "dh= (k1*R/(k1-1))*(T1-T)\n",
-      "dh1= (k1*R/(k1-1))*math.log((273.15+T1)/(273.15+T))\n",
-      "H= dh-(273.15+T)*dh1\n",
-      "h= (k*R/(k-1))*(T1-T)+hf\n",
-      "h1= (k*R/(k-1))*math.log((273.15+T1)/(273.15+T))+((hf-gf)/(273.15+T))\n",
-      "h2= h-(273.15+T)*h1\n",
-      "Bout= (h2+(0.2+4.5144)*H)/M\n",
-      "##RESULTS\n",
-      "print'%s %.2f %s'%('outlet temperature=',T1,'C')\n",
-      "print'%s %.f %s'%('energy of formation=',Bin,'J')\n",
-      "print'%s %.f %s'%('energy at outlet=',H,'kJ/kmol')\n",
-      "print'%s %.f %s'%('energy of the products=',Bout,'k')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "outlet temperature= 2057.82 C\n",
-        "energy of formation= 0 J\n",
-        "energy at outlet= 46519 kJ/kmol\n",
-        "energy of the products= -9961 k\n"
-       ]
-      }
-     ],
-     "prompt_number": 12
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Example10-pg427"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "#calculate the change in energy and amount of air and gas and netchange in energy and percent change in energy\n",
-      "##initialisation of variables\n",
-      "b= 1475.30 ##kJ/kg\n",
-      "b0= 144.44 ##kJ/kg\n",
-      "h2= 3448.6 ##kJkg\n",
-      "h1= 860.5 ##kJ/kg\n",
-      "k= 1.27 \n",
-      "k1= 1.34\n",
-      "R= 8.314 ##J/mol K\n",
-      "hf= -393520 ##kJ/kmol\n",
-      "hg= 72596 ##kJ/kmol\n",
-      "Mc= 12 ##kg\n",
-      "n= 1.2 ##moles\n",
-      "n1= 3.76 ##moles\n",
-      "M= 32. ##gms\n",
-      "M1= 28. ##gms\n",
-      "M2= 44. ##gms\n",
-      "n2= 0.2 ##moles\n",
-      "n3= 4.512 ##moles\n",
-      "B1= 25592. ##kJ/kmol C\n",
-      "B2= 394360. ##kJ/kmol C\n",
-      "e= 0.008065\n",
-      "##CALCULATIONS\n",
-      "B= b-b0\n",
-      "Q= h2-h1\n",
-      "CpCO2= k*R/(k-1)\n",
-      "CpO2= k1*R/(k1-1)\n",
-      "Qcoal= (hg+hf)/Mc\n",
-      "mcoal= Q/(-Qcoal)\n",
-      "ncoal= mcoal/Mc\n",
-      "r= (n*M+n1*M1)/Mc\n",
-      "r1= (M2+n2*M+n3*M1)/Mc\n",
-      "mair= r*mcoal\n",
-      "mgas= r1*mcoal\n",
-      "Bfuel= (B1-B2)*e\n",
-      "Bnet= Bfuel+B\n",
-      "p= B*100/(-Bfuel)\n",
-      "##RESULTS\n",
-      "print'%s %.2f %s'% ('change in energy=',B,'kJ/kg ')\n",
-      "print'%s %.3f %s'%('amount of air=',mair,'kg/kg ')\n",
-      "print'%s %.3f %s'%('amount of gas=',mgas,'kg/kg ')\n",
-      "print'%s %.3f %s'%('net change in energy=',Bnet,'kg/kg steam ')\n",
-      "print'%s %.2f %s'%('percent energy in original fuel=',p,'percent ')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "change in energy= 1330.86 kJ/kg \n",
-        "amount of air= 1.159 kg/kg \n",
-        "amount of gas= 1.425 kg/kg \n",
-        "net change in energy= -1643.254 kg/kg steam \n",
-        "percent energy in original fuel= 44.75 percent \n"
-       ]
-      }
-     ],
-     "prompt_number": 13
-    }
-   ],
-   "metadata": {}
-  }
- ]
-}
-\ No newline at end of file
diff --git a/Thermodynamics:_From_concepts_to_applications/Chapter19.ipynb b/Thermodynamics:_From_concepts_to_applications/Chapter19.ipynb
deleted file mode 100755
index fd5d0f72..00000000
--- a/Thermodynamics:_From_concepts_to_applications/Chapter19.ipynb
+++ /dev/null
@@ -1,472 +0,0 @@
-{
- "metadata": {
-  "name": "",
-  "signature": "sha256:62da0bbd390eac5357f5f997103c8800ba34f828bad9afe3f011ec1444ac1334"
- },
- "nbformat": 3,
- "nbformat_minor": 0,
- "worksheets": [
-  {
-   "cells": [
-    {
-     "cell_type": "heading",
-     "level": 1,
-     "metadata": {},
-     "source": [
-      "Chapter19-Chemical reactions"
-     ]
-    },
-    {
-     "cell_type": "heading",
-     "level": 1,
-     "metadata": {},
-     "source": [
-      "Example1-pg 404"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "#caluclate fuel ratio and excess air and emass air-fuel ratio\n",
-      "##initialisation of variables\n",
-      "pN2= 79. ##percent\n",
-      "VN2= 82.3 ##m^3\n",
-      "VCO2= 8. ##m^3\n",
-      "VCO= 0.9 ##m^3\n",
-      "M= 32. ##gms\n",
-      "M1= 28. ##gms\n",
-      "##CALCULATIONS\n",
-      "P= (pN2/(100-pN2))\n",
-      "z= VN2/P\n",
-      "x= VCO2+VCO\n",
-      "w= VCO2+(VCO/2)+(VCO2/10)\n",
-      "y= 2*w\n",
-      "r= y/x\n",
-      "TO= x+(y/4)\n",
-      "X= (z/TO)-1\n",
-      "AF= z*(M+P*M1)/(12*x+y)\n",
-      "##RESULTS\n",
-      "print'%s %.3f %s'%('fuel ratio=',r,'')\n",
-      "print'%s %.3f %s'%('excess air=',X,'')\n",
-      "print'%s %.2f %s'%('emass air-fuel ratio=',AF,'')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "fuel ratio= 2.079 \n",
-        "excess air= 0.618 \n",
-        "emass air-fuel ratio= 23.98 \n"
-       ]
-      }
-     ],
-     "prompt_number": 2
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Example2-pg 410"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "#calculate heat interaction\n",
-      "##initialisation of variables\n",
-      "m1= 24. ##kg\n",
-      "M1= 32. ##kg\n",
-      "m2= 28. ##kg\n",
-      "M2= 28. ##kg\n",
-      "e= 0.5\n",
-      "T3= 1800. ##C\n",
-      "T0= 25. ##C\n",
-      "T1= 25. ##C\n",
-      "T2= 100. ##C\n",
-      "R= 8.314 ##Jmol K\n",
-      "cp= 4.57 ##J/mol K\n",
-      "cp1= 3.5 ##J/mol K\n",
-      "cp2= 3.5 ##J/mol K\n",
-      "hCO2= -393522. ##J\n",
-      "hCO= -110529. ##J\n",
-      "##CALCULATIONS\n",
-      "n1= m1/M1\n",
-      "n2= m2/M2\n",
-      "N= n1-0.5*e\n",
-      "N1= n2-e\n",
-      "N2= e\n",
-      "N3= N+N1+N2\n",
-      "y1= N/N3\n",
-      "Q= ((N*cp+N1*cp1+N2*cp2)*R*(T3-T0)-(n1*cp*(T1-T0)+n2*cp2*(T2-T1))+N*(hCO2-hCO))/60.\n",
-      "##RESULTS\n",
-      "print'%s %.f %s'%(' Heat interaction=',Q,'kW ')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        " Heat interaction= -940 kW \n"
-       ]
-      }
-     ],
-     "prompt_number": 4
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Example3-pg 412"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "#calculate adiabatic flame temperature\n",
-      "##initialisation of variables\n",
-      "T0= 25. ##C\n",
-      "T1= 220. ##C\n",
-      "hCO2= -393520 ##kJ/kg\n",
-      "hH2O= -241830 ##kJ/kg\n",
-      "hC3H8= -103850 ##kJ/kg= 1.4\n",
-      "R= 8.314 ##Jmol K\n",
-      "k= 1.4\n",
-      "k1= 1.29\n",
-      "##CALCULATIONS\n",
-      "T= T0+((15*(R*(k/(k-1)))*4.762*(T1-T0)-(3*hCO2+4*hH2O-hC3H8))/(R*((3+4)*(k1/(k1-1))+(10+56.43)*(k/(k-1)))))\n",
-      "##RESULTS\n",
-      "print'%s %.1f %s'%('adiabatic flame temperature=',T,'C ')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "adiabatic flame temperature= 1142.4 C \n"
-       ]
-      }
-     ],
-     "prompt_number": 1
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Example5-pg 415"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "#calculate enthalpy formation\n",
-      "##initialisation of variables\n",
-      "T= 25. ##C\n",
-      "hfT= -241820 ##kJ/kmol\n",
-      "R= 8.314 ##J/mol K\n",
-      "k= 1.4\n",
-      "cpH2O= 4.45\n",
-      "cpO2= 3.5\n",
-      "T1= 1000. ##C\n",
-      "##CALCULATIONS\n",
-      "S= (cpH2O-k*cpO2)\n",
-      "hfT1= hfT+S*(T1-T)\n",
-      "##RESULTS\n",
-      "print'%s %.f %s'%('enthalpy formation=',hfT1,'kJ/kmol ')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "enthalpy formation= -242259 kJ/kmol \n"
-       ]
-      }
-     ],
-     "prompt_number": 8
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Example6-pg 418"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "#calculate equlibrium constant at K and KT1\n",
-      "##initialisation of variables\n",
-      "R= 8.314 ##J/mol K\n",
-      "T= 25. ##C\n",
-      "gf= 16590. ##kJ/kmol\n",
-      "T1= 500. ##C\n",
-      "Cp= 4.157 ##J/mol K\n",
-      "hf= -46190 ##kJ/kmol\n",
-      "e=0.5\n",
-      "##CALCULATIONS\n",
-      "K=math.pow(math.e,gf/(R*(273.15+T)))\n",
-      "r= (1-((273.15+T)/(273.15+T1)))*((hf/(R*(273.15+T)))+(R/Cp))-2*math.log((273.15+T1)/(273.15+T))+0.6\n",
-      "KT1= K*math.pow(math.e,r)\n",
-      "##RESULTS\n",
-      "print'%s %.1f %s'%('equilibrium constant=',K,'bar^-1 ')\n",
-      "print'%s %.5f %s'%('equilibrium constant=',KT1,'bar^-1 ')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "equilibrium constant= 806.5 bar^-1 \n",
-        "equilibrium constant= 0.00797 bar^-1 \n"
-       ]
-      }
-     ],
-     "prompt_number": 9
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Example7-pg 419"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "#what equilibrium constant at T1 and T2\n",
-      "##initialisation of variables\n",
-      "uCO2= -394374 ##J/mol\n",
-      "uCO= -137150 ##J/mol\n",
-      "uO2= 0.\n",
-      "R= 8.314 ##J/mol K\n",
-      "T= 25. ##C\n",
-      "cpCO2= 4.57 ##J/mol K\n",
-      "cpCO= 3.5 ##J/mol K\n",
-      "cpO2= 3.5 ##J/mol K\n",
-      "T1= 1500. ##C\n",
-      "hf= -393522 ##kJ/kmol\n",
-      "gf= -110529 ##kJ/kmol\n",
-      "T2= 2500. ##C\n",
-      "##CALCULATIONS\n",
-      "r= -(uCO2-uCO-0.5*uO2)/(R*(273.15+T))\n",
-      "s= (cpCO2-cpCO-0.5*cpO2)\n",
-      "r1= (1-((273.15+T)/(273.15+T1)))*((hf-gf)/(R*(273.15+T))-s)+s*math.log((273.15+T1)/(273.15+T))\n",
-      "KT1= math.pow(math.e,r+r1)\n",
-      "r2= (1-((273.15+T)/(273.15+T2)))*((hf-gf)/(R*(273.15+T))-s)+s*math.log((273.15+T2)/(273.15+T))\n",
-      "KT2= math.pow(math.e,r+r2)\n",
-      "##RESULTS\n",
-      "print'%s %.f %s'%('equilibrium constant at T1=',KT1,'C ')\n",
-      "print'%s %.3f %s'%('equilibrium constant at T2=',KT2,'C ')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "equilibrium constant at T1= 3477 C \n",
-        "equilibrium constant at T2= 2.635 C \n"
-       ]
-      }
-     ],
-     "prompt_number": 10
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Example8-pg422"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "#what is maximum work of given variable \n",
-      "##initialisation of variables\n",
-      "Wc= 12. ##kg\n",
-      "hf= -393520 ##kJ/kmol\n",
-      "gf= -394360 ##kJ/kmol\n",
-      "##CALCULATIONS\n",
-      "Wmax= -gf/Wc\n",
-      "##RESULTS\n",
-      "print'%s %.f %s'%('maximum work=',Wmax,'kJ/kg of carbon ')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "maximum work= 32863 kJ/kg of carbon \n"
-       ]
-      }
-     ],
-     "prompt_number": 11
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Example9-pg423"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "#calculate the outlet temperature and energy of formation and energy out let and energy of the products\n",
-      "##initialisation of variables\n",
-      "T= 25 ##C\n",
-      "R= 8.314 ##Jmol K\n",
-      "k= 1.27\n",
-      "k1= 1.34\n",
-      "hf= -393520 ##kJ/kmol\n",
-      "M= 28 ##gms\n",
-      "gf= -394360 ##kJ/kmol\n",
-      "M= 12 ##gms\n",
-      "##CALCULATIONS\n",
-      "T1= T+(-hf/((R)*((k/(k-1))+(0.2+4.5144)*(k1/(k1-1)))))\n",
-      "Bin= 0\n",
-      "dh= (k1*R/(k1-1))*(T1-T)\n",
-      "dh1= (k1*R/(k1-1))*math.log((273.15+T1)/(273.15+T))\n",
-      "H= dh-(273.15+T)*dh1\n",
-      "h= (k*R/(k-1))*(T1-T)+hf\n",
-      "h1= (k*R/(k-1))*math.log((273.15+T1)/(273.15+T))+((hf-gf)/(273.15+T))\n",
-      "h2= h-(273.15+T)*h1\n",
-      "Bout= (h2+(0.2+4.5144)*H)/M\n",
-      "##RESULTS\n",
-      "print'%s %.2f %s'%('outlet temperature=',T1,'C')\n",
-      "print'%s %.f %s'%('energy of formation=',Bin,'J')\n",
-      "print'%s %.f %s'%('energy at outlet=',H,'kJ/kmol')\n",
-      "print'%s %.f %s'%('energy of the products=',Bout,'k')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "outlet temperature= 2057.82 C\n",
-        "energy of formation= 0 J\n",
-        "energy at outlet= 46519 kJ/kmol\n",
-        "energy of the products= -9961 k\n"
-       ]
-      }
-     ],
-     "prompt_number": 12
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Example10-pg427"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "#calculate the change in energy and amount of air and gas and netchange in energy and percent change in energy\n",
-      "##initialisation of variables\n",
-      "b= 1475.30 ##kJ/kg\n",
-      "b0= 144.44 ##kJ/kg\n",
-      "h2= 3448.6 ##kJkg\n",
-      "h1= 860.5 ##kJ/kg\n",
-      "k= 1.27 \n",
-      "k1= 1.34\n",
-      "R= 8.314 ##J/mol K\n",
-      "hf= -393520 ##kJ/kmol\n",
-      "hg= 72596 ##kJ/kmol\n",
-      "Mc= 12 ##kg\n",
-      "n= 1.2 ##moles\n",
-      "n1= 3.76 ##moles\n",
-      "M= 32. ##gms\n",
-      "M1= 28. ##gms\n",
-      "M2= 44. ##gms\n",
-      "n2= 0.2 ##moles\n",
-      "n3= 4.512 ##moles\n",
-      "B1= 25592. ##kJ/kmol C\n",
-      "B2= 394360. ##kJ/kmol C\n",
-      "e= 0.008065\n",
-      "##CALCULATIONS\n",
-      "B= b-b0\n",
-      "Q= h2-h1\n",
-      "CpCO2= k*R/(k-1)\n",
-      "CpO2= k1*R/(k1-1)\n",
-      "Qcoal= (hg+hf)/Mc\n",
-      "mcoal= Q/(-Qcoal)\n",
-      "ncoal= mcoal/Mc\n",
-      "r= (n*M+n1*M1)/Mc\n",
-      "r1= (M2+n2*M+n3*M1)/Mc\n",
-      "mair= r*mcoal\n",
-      "mgas= r1*mcoal\n",
-      "Bfuel= (B1-B2)*e\n",
-      "Bnet= Bfuel+B\n",
-      "p= B*100/(-Bfuel)\n",
-      "##RESULTS\n",
-      "print'%s %.2f %s'% ('change in energy=',B,'kJ/kg ')\n",
-      "print'%s %.3f %s'%('amount of air=',mair,'kg/kg ')\n",
-      "print'%s %.3f %s'%('amount of gas=',mgas,'kg/kg ')\n",
-      "print'%s %.3f %s'%('net change in energy=',Bnet,'kg/kg steam ')\n",
-      "print'%s %.2f %s'%('percent energy in original fuel=',p,'percent ')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "change in energy= 1330.86 kJ/kg \n",
-        "amount of air= 1.159 kg/kg \n",
-        "amount of gas= 1.425 kg/kg \n",
-        "net change in energy= -1643.254 kg/kg steam \n",
-        "percent energy in original fuel= 44.75 percent \n"
-       ]
-      }
-     ],
-     "prompt_number": 13
-    }
-   ],
-   "metadata": {}
-  }
- ]
-}
-\ No newline at end of file
diff --git a/Thermodynamics:_From_concepts_to_applications/Chapter19_1.ipynb b/Thermodynamics:_From_concepts_to_applications/Chapter19_1.ipynb
deleted file mode 100755
index fd5d0f72..00000000
--- a/Thermodynamics:_From_concepts_to_applications/Chapter19_1.ipynb
+++ /dev/null
@@ -1,472 +0,0 @@
-{
- "metadata": {
-  "name": "",
-  "signature": "sha256:62da0bbd390eac5357f5f997103c8800ba34f828bad9afe3f011ec1444ac1334"
- },
- "nbformat": 3,
- "nbformat_minor": 0,
- "worksheets": [
-  {
-   "cells": [
-    {
-     "cell_type": "heading",
-     "level": 1,
-     "metadata": {},
-     "source": [
-      "Chapter19-Chemical reactions"
-     ]
-    },
-    {
-     "cell_type": "heading",
-     "level": 1,
-     "metadata": {},
-     "source": [
-      "Example1-pg 404"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "#caluclate fuel ratio and excess air and emass air-fuel ratio\n",
-      "##initialisation of variables\n",
-      "pN2= 79. ##percent\n",
-      "VN2= 82.3 ##m^3\n",
-      "VCO2= 8. ##m^3\n",
-      "VCO= 0.9 ##m^3\n",
-      "M= 32. ##gms\n",
-      "M1= 28. ##gms\n",
-      "##CALCULATIONS\n",
-      "P= (pN2/(100-pN2))\n",
-      "z= VN2/P\n",
-      "x= VCO2+VCO\n",
-      "w= VCO2+(VCO/2)+(VCO2/10)\n",
-      "y= 2*w\n",
-      "r= y/x\n",
-      "TO= x+(y/4)\n",
-      "X= (z/TO)-1\n",
-      "AF= z*(M+P*M1)/(12*x+y)\n",
-      "##RESULTS\n",
-      "print'%s %.3f %s'%('fuel ratio=',r,'')\n",
-      "print'%s %.3f %s'%('excess air=',X,'')\n",
-      "print'%s %.2f %s'%('emass air-fuel ratio=',AF,'')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "fuel ratio= 2.079 \n",
-        "excess air= 0.618 \n",
-        "emass air-fuel ratio= 23.98 \n"
-       ]
-      }
-     ],
-     "prompt_number": 2
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Example2-pg 410"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "#calculate heat interaction\n",
-      "##initialisation of variables\n",
-      "m1= 24. ##kg\n",
-      "M1= 32. ##kg\n",
-      "m2= 28. ##kg\n",
-      "M2= 28. ##kg\n",
-      "e= 0.5\n",
-      "T3= 1800. ##C\n",
-      "T0= 25. ##C\n",
-      "T1= 25. ##C\n",
-      "T2= 100. ##C\n",
-      "R= 8.314 ##Jmol K\n",
-      "cp= 4.57 ##J/mol K\n",
-      "cp1= 3.5 ##J/mol K\n",
-      "cp2= 3.5 ##J/mol K\n",
-      "hCO2= -393522. ##J\n",
-      "hCO= -110529. ##J\n",
-      "##CALCULATIONS\n",
-      "n1= m1/M1\n",
-      "n2= m2/M2\n",
-      "N= n1-0.5*e\n",
-      "N1= n2-e\n",
-      "N2= e\n",
-      "N3= N+N1+N2\n",
-      "y1= N/N3\n",
-      "Q= ((N*cp+N1*cp1+N2*cp2)*R*(T3-T0)-(n1*cp*(T1-T0)+n2*cp2*(T2-T1))+N*(hCO2-hCO))/60.\n",
-      "##RESULTS\n",
-      "print'%s %.f %s'%(' Heat interaction=',Q,'kW ')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        " Heat interaction= -940 kW \n"
-       ]
-      }
-     ],
-     "prompt_number": 4
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Example3-pg 412"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "#calculate adiabatic flame temperature\n",
-      "##initialisation of variables\n",
-      "T0= 25. ##C\n",
-      "T1= 220. ##C\n",
-      "hCO2= -393520 ##kJ/kg\n",
-      "hH2O= -241830 ##kJ/kg\n",
-      "hC3H8= -103850 ##kJ/kg= 1.4\n",
-      "R= 8.314 ##Jmol K\n",
-      "k= 1.4\n",
-      "k1= 1.29\n",
-      "##CALCULATIONS\n",
-      "T= T0+((15*(R*(k/(k-1)))*4.762*(T1-T0)-(3*hCO2+4*hH2O-hC3H8))/(R*((3+4)*(k1/(k1-1))+(10+56.43)*(k/(k-1)))))\n",
-      "##RESULTS\n",
-      "print'%s %.1f %s'%('adiabatic flame temperature=',T,'C ')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "adiabatic flame temperature= 1142.4 C \n"
-       ]
-      }
-     ],
-     "prompt_number": 1
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Example5-pg 415"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "#calculate enthalpy formation\n",
-      "##initialisation of variables\n",
-      "T= 25. ##C\n",
-      "hfT= -241820 ##kJ/kmol\n",
-      "R= 8.314 ##J/mol K\n",
-      "k= 1.4\n",
-      "cpH2O= 4.45\n",
-      "cpO2= 3.5\n",
-      "T1= 1000. ##C\n",
-      "##CALCULATIONS\n",
-      "S= (cpH2O-k*cpO2)\n",
-      "hfT1= hfT+S*(T1-T)\n",
-      "##RESULTS\n",
-      "print'%s %.f %s'%('enthalpy formation=',hfT1,'kJ/kmol ')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "enthalpy formation= -242259 kJ/kmol \n"
-       ]
-      }
-     ],
-     "prompt_number": 8
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Example6-pg 418"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "#calculate equlibrium constant at K and KT1\n",
-      "##initialisation of variables\n",
-      "R= 8.314 ##J/mol K\n",
-      "T= 25. ##C\n",
-      "gf= 16590. ##kJ/kmol\n",
-      "T1= 500. ##C\n",
-      "Cp= 4.157 ##J/mol K\n",
-      "hf= -46190 ##kJ/kmol\n",
-      "e=0.5\n",
-      "##CALCULATIONS\n",
-      "K=math.pow(math.e,gf/(R*(273.15+T)))\n",
-      "r= (1-((273.15+T)/(273.15+T1)))*((hf/(R*(273.15+T)))+(R/Cp))-2*math.log((273.15+T1)/(273.15+T))+0.6\n",
-      "KT1= K*math.pow(math.e,r)\n",
-      "##RESULTS\n",
-      "print'%s %.1f %s'%('equilibrium constant=',K,'bar^-1 ')\n",
-      "print'%s %.5f %s'%('equilibrium constant=',KT1,'bar^-1 ')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "equilibrium constant= 806.5 bar^-1 \n",
-        "equilibrium constant= 0.00797 bar^-1 \n"
-       ]
-      }
-     ],
-     "prompt_number": 9
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Example7-pg 419"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "#what equilibrium constant at T1 and T2\n",
-      "##initialisation of variables\n",
-      "uCO2= -394374 ##J/mol\n",
-      "uCO= -137150 ##J/mol\n",
-      "uO2= 0.\n",
-      "R= 8.314 ##J/mol K\n",
-      "T= 25. ##C\n",
-      "cpCO2= 4.57 ##J/mol K\n",
-      "cpCO= 3.5 ##J/mol K\n",
-      "cpO2= 3.5 ##J/mol K\n",
-      "T1= 1500. ##C\n",
-      "hf= -393522 ##kJ/kmol\n",
-      "gf= -110529 ##kJ/kmol\n",
-      "T2= 2500. ##C\n",
-      "##CALCULATIONS\n",
-      "r= -(uCO2-uCO-0.5*uO2)/(R*(273.15+T))\n",
-      "s= (cpCO2-cpCO-0.5*cpO2)\n",
-      "r1= (1-((273.15+T)/(273.15+T1)))*((hf-gf)/(R*(273.15+T))-s)+s*math.log((273.15+T1)/(273.15+T))\n",
-      "KT1= math.pow(math.e,r+r1)\n",
-      "r2= (1-((273.15+T)/(273.15+T2)))*((hf-gf)/(R*(273.15+T))-s)+s*math.log((273.15+T2)/(273.15+T))\n",
-      "KT2= math.pow(math.e,r+r2)\n",
-      "##RESULTS\n",
-      "print'%s %.f %s'%('equilibrium constant at T1=',KT1,'C ')\n",
-      "print'%s %.3f %s'%('equilibrium constant at T2=',KT2,'C ')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "equilibrium constant at T1= 3477 C \n",
-        "equilibrium constant at T2= 2.635 C \n"
-       ]
-      }
-     ],
-     "prompt_number": 10
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Example8-pg422"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "#what is maximum work of given variable \n",
-      "##initialisation of variables\n",
-      "Wc= 12. ##kg\n",
-      "hf= -393520 ##kJ/kmol\n",
-      "gf= -394360 ##kJ/kmol\n",
-      "##CALCULATIONS\n",
-      "Wmax= -gf/Wc\n",
-      "##RESULTS\n",
-      "print'%s %.f %s'%('maximum work=',Wmax,'kJ/kg of carbon ')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "maximum work= 32863 kJ/kg of carbon \n"
-       ]
-      }
-     ],
-     "prompt_number": 11
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Example9-pg423"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "#calculate the outlet temperature and energy of formation and energy out let and energy of the products\n",
-      "##initialisation of variables\n",
-      "T= 25 ##C\n",
-      "R= 8.314 ##Jmol K\n",
-      "k= 1.27\n",
-      "k1= 1.34\n",
-      "hf= -393520 ##kJ/kmol\n",
-      "M= 28 ##gms\n",
-      "gf= -394360 ##kJ/kmol\n",
-      "M= 12 ##gms\n",
-      "##CALCULATIONS\n",
-      "T1= T+(-hf/((R)*((k/(k-1))+(0.2+4.5144)*(k1/(k1-1)))))\n",
-      "Bin= 0\n",
-      "dh= (k1*R/(k1-1))*(T1-T)\n",
-      "dh1= (k1*R/(k1-1))*math.log((273.15+T1)/(273.15+T))\n",
-      "H= dh-(273.15+T)*dh1\n",
-      "h= (k*R/(k-1))*(T1-T)+hf\n",
-      "h1= (k*R/(k-1))*math.log((273.15+T1)/(273.15+T))+((hf-gf)/(273.15+T))\n",
-      "h2= h-(273.15+T)*h1\n",
-      "Bout= (h2+(0.2+4.5144)*H)/M\n",
-      "##RESULTS\n",
-      "print'%s %.2f %s'%('outlet temperature=',T1,'C')\n",
-      "print'%s %.f %s'%('energy of formation=',Bin,'J')\n",
-      "print'%s %.f %s'%('energy at outlet=',H,'kJ/kmol')\n",
-      "print'%s %.f %s'%('energy of the products=',Bout,'k')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "outlet temperature= 2057.82 C\n",
-        "energy of formation= 0 J\n",
-        "energy at outlet= 46519 kJ/kmol\n",
-        "energy of the products= -9961 k\n"
-       ]
-      }
-     ],
-     "prompt_number": 12
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Example10-pg427"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "#calculate the change in energy and amount of air and gas and netchange in energy and percent change in energy\n",
-      "##initialisation of variables\n",
-      "b= 1475.30 ##kJ/kg\n",
-      "b0= 144.44 ##kJ/kg\n",
-      "h2= 3448.6 ##kJkg\n",
-      "h1= 860.5 ##kJ/kg\n",
-      "k= 1.27 \n",
-      "k1= 1.34\n",
-      "R= 8.314 ##J/mol K\n",
-      "hf= -393520 ##kJ/kmol\n",
-      "hg= 72596 ##kJ/kmol\n",
-      "Mc= 12 ##kg\n",
-      "n= 1.2 ##moles\n",
-      "n1= 3.76 ##moles\n",
-      "M= 32. ##gms\n",
-      "M1= 28. ##gms\n",
-      "M2= 44. ##gms\n",
-      "n2= 0.2 ##moles\n",
-      "n3= 4.512 ##moles\n",
-      "B1= 25592. ##kJ/kmol C\n",
-      "B2= 394360. ##kJ/kmol C\n",
-      "e= 0.008065\n",
-      "##CALCULATIONS\n",
-      "B= b-b0\n",
-      "Q= h2-h1\n",
-      "CpCO2= k*R/(k-1)\n",
-      "CpO2= k1*R/(k1-1)\n",
-      "Qcoal= (hg+hf)/Mc\n",
-      "mcoal= Q/(-Qcoal)\n",
-      "ncoal= mcoal/Mc\n",
-      "r= (n*M+n1*M1)/Mc\n",
-      "r1= (M2+n2*M+n3*M1)/Mc\n",
-      "mair= r*mcoal\n",
-      "mgas= r1*mcoal\n",
-      "Bfuel= (B1-B2)*e\n",
-      "Bnet= Bfuel+B\n",
-      "p= B*100/(-Bfuel)\n",
-      "##RESULTS\n",
-      "print'%s %.2f %s'% ('change in energy=',B,'kJ/kg ')\n",
-      "print'%s %.3f %s'%('amount of air=',mair,'kg/kg ')\n",
-      "print'%s %.3f %s'%('amount of gas=',mgas,'kg/kg ')\n",
-      "print'%s %.3f %s'%('net change in energy=',Bnet,'kg/kg steam ')\n",
-      "print'%s %.2f %s'%('percent energy in original fuel=',p,'percent ')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "change in energy= 1330.86 kJ/kg \n",
-        "amount of air= 1.159 kg/kg \n",
-        "amount of gas= 1.425 kg/kg \n",
-        "net change in energy= -1643.254 kg/kg steam \n",
-        "percent energy in original fuel= 44.75 percent \n"
-       ]
-      }
-     ],
-     "prompt_number": 13
-    }
-   ],
-   "metadata": {}
-  }
- ]
-}
-\ No newline at end of file
diff --git a/Thermodynamics:_From_concepts_to_applications/Chapter5-the_ideal_gas.ipynb b/Thermodynamics:_From_concepts_to_applications/Chapter5-the_ideal_gas.ipynb
deleted file mode 100755
index 7ebf1310..00000000
--- a/Thermodynamics:_From_concepts_to_applications/Chapter5-the_ideal_gas.ipynb
+++ /dev/null
@@ -1,166 +0,0 @@
-{
- "metadata": {
-  "name": "",
-  "signature": "sha256:4e735a3e117e4e268af257af7ccec75bd1ac3fad4a8f848db2d81766258e8e27"
- },
- "nbformat": 3,
- "nbformat_minor": 0,
- "worksheets": [
-  {
-   "cells": [
-    {
-     "cell_type": "heading",
-     "level": 1,
-     "metadata": {},
-     "source": [
-      "Chapter5 -The ideal gas"
-     ]
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Example1-pg 66"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "#calculate specific volumes at given pressure\n",
-      "##initialisation of variables\n",
-      "R= 8.314 ##J/mol K\n",
-      "M= 18.016 ##gms\n",
-      "T= 400. ##C\n",
-      "p= 0.01 ##Mpa\n",
-      "p1= 0.1 ##Mpa\n",
-      "p2= 20. ##Mpa\n",
-      "##CALCULATIONS\n",
-      "v= R*(273.156+T)/(M*p*1000)\n",
-      "v1= R*(273.156+T)/(M*p1*1000)\n",
-      "v2= R*(273.156+T)/(M*p2*1000)\n",
-      "##RESULTS\n",
-      "print'%s %.3f %s'%(' specific voulme =',v,'m^3/kg')\n",
-      "print'%s %.3f %s'%('specific voulme = ', v1,'m^3/kg')\n",
-      "print'%s %.3f %s'%('specific voulme = ',v2,'m^3/kg')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        " specific voulme = 31.065 m^3/kg\n",
-        "specific voulme =  3.106 m^3/kg\n",
-        "specific voulme =  0.016 m^3/kg\n"
-       ]
-      }
-     ],
-     "prompt_number": 2
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "example 3-pg73 "
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "#calculate final temperature and pressure and work ,energy\n",
-      "##initialisation of variables\n",
-      "p1= 300.##kPa\n",
-      "V1= 0.03 ##m^3\n",
-      "V2= 0.08 ##m^3\n",
-      "T1= 27. ##C\n",
-      "##CALCULATIONS1\n",
-      "T2= T1+273\n",
-      "p2= p1*(V1/V2)*(T2/(T1+273))\n",
-      "W= 0\n",
-      "Q= 0\n",
-      "##RESULTS\n",
-      "print'%s %.2f %s'%('final temperature =',T2,'K')\n",
-      "print'%s %.1f %s'%('final pressure =',p2,'kPa')\n",
-      "print'%s %.f %s'%('work = ',W,'kJ')\n",
-      "print'%s %.f %s'%('energy =',Q,'kJ')\n",
-      " \n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "final temperature = 300.00 K\n",
-        "final pressure = 112.5 kPa\n",
-        "work =  0 kJ\n",
-        "energy = 0 kJ\n"
-       ]
-      }
-     ],
-     "prompt_number": 9
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Example4 -pg74\n",
-      "\n"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "#calculate mass of nitrogen and final temperature and piston rise\n",
-      "##initialisation of variables\n",
-      "p1= 2. ##Mpa\n",
-      "V1= 0.2 ##m^3\n",
-      "R= 8.314 ##J/mol K\n",
-      "T1= 500. ##C\n",
-      "M= 28. ##gms\n",
-      "p2= 0.3 ##Mpa\n",
-      "T2= 250 ##C\n",
-      "k= 1.4\n",
-      "A= 0.1 ##m^2\n",
-      "##CALCULATIONS\n",
-      "m1= p1*10*10*10*V1*M/(R*(273.15+T1))\n",
-      "m2= p2*10*10*10*V1*M/(R*(273.15+T2))\n",
-      "m3= -(m2-m1)\n",
-      "T3= (m1*(273.15+T1)-m2*(273.15+T2))/(k*m3)\n",
-      "z3= m3*R*T3/(p2*10*10*10*A*M)\n",
-      "##RESULTS\n",
-      "print'%s %.4f %s'%(' mass of nitrogen =',m3,'kg')\n",
-      "print'%s %.1f %s'%('final temperature =',T3,'K')\n",
-      "print'%s %.2f %s'%('piston rise =',z3,'m')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        " mass of nitrogen = 1.3561 kg\n",
-        "final temperature = 603.1 K\n",
-        "piston rise = 8.10 m\n"
-       ]
-      }
-     ],
-     "prompt_number": 11
-    }
-   ],
-   "metadata": {}
-  }
- ]
-}
-\ No newline at end of file
diff --git a/Thermodynamics:_From_concepts_to_applications/Chapter5.ipynb b/Thermodynamics:_From_concepts_to_applications/Chapter5.ipynb
deleted file mode 100755
index 63ce2dea..00000000
--- a/Thermodynamics:_From_concepts_to_applications/Chapter5.ipynb
+++ /dev/null
@@ -1,166 +0,0 @@
-{
- "metadata": {
-  "name": "",
-  "signature": "sha256:38617d08dc78615a27f3bb0a8bac191fa91e9820c1bc63b1ee3f0d39bccfa426"
- },
- "nbformat": 3,
- "nbformat_minor": 0,
- "worksheets": [
-  {
-   "cells": [
-    {
-     "cell_type": "heading",
-     "level": 1,
-     "metadata": {},
-     "source": [
-      "Chapter5 -the ideal gas"
-     ]
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Example1-pg 66"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "#calculate specific volumes at given pressure\n",
-      "##initialisation of variables\n",
-      "R= 8.314 ##J/mol K\n",
-      "M= 18.016 ##gms\n",
-      "T= 400. ##C\n",
-      "p= 0.01 ##Mpa\n",
-      "p1= 0.1 ##Mpa\n",
-      "p2= 20. ##Mpa\n",
-      "##CALCULATIONS\n",
-      "v= R*(273.156+T)/(M*p*1000)\n",
-      "v1= R*(273.156+T)/(M*p1*1000)\n",
-      "v2= R*(273.156+T)/(M*p2*1000)\n",
-      "##RESULTS\n",
-      "print'%s %.3f %s'%(' specific voulme =',v,'m^3/kg')\n",
-      "print'%s %.3f %s'%('specific voulme = ', v1,'m^3/kg')\n",
-      "print'%s %.3f %s'%('specific voulme = ',v2,'m^3/kg')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        " specific voulme = 31.065 m^3/kg\n",
-        "specific voulme =  3.106 m^3/kg\n",
-        "specific voulme =  0.016 m^3/kg\n"
-       ]
-      }
-     ],
-     "prompt_number": 2
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "example 3-pg73 "
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "#calculate final temperature and pressure and work ,energy\n",
-      "##initialisation of variables\n",
-      "p1= 300.##kPa\n",
-      "V1= 0.03 ##m^3\n",
-      "V2= 0.08 ##m^3\n",
-      "T1= 27. ##C\n",
-      "##CALCULATIONS1\n",
-      "T2= T1+273\n",
-      "p2= p1*(V1/V2)*(T2/(T1+273))\n",
-      "W= 0\n",
-      "Q= 0\n",
-      "##RESULTS\n",
-      "print'%s %.2f %s'%('final temperature =',T2,'K')\n",
-      "print'%s %.1f %s'%('final pressure =',p2,'kPa')\n",
-      "print'%s %.f %s'%('work = ',W,'kJ')\n",
-      "print'%s %.f %s'%('energy =',Q,'kJ')\n",
-      " \n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "final temperature = 300.00 K\n",
-        "final pressure = 112.5 kPa\n",
-        "work =  0 kJ\n",
-        "energy = 0 kJ\n"
-       ]
-      }
-     ],
-     "prompt_number": 9
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Example4 -pg74\n",
-      "\n"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "#calculate mass of nitrogen and final temperature and piston rise\n",
-      "##initialisation of variables\n",
-      "p1= 2. ##Mpa\n",
-      "V1= 0.2 ##m^3\n",
-      "R= 8.314 ##J/mol K\n",
-      "T1= 500. ##C\n",
-      "M= 28. ##gms\n",
-      "p2= 0.3 ##Mpa\n",
-      "T2= 250 ##C\n",
-      "k= 1.4\n",
-      "A= 0.1 ##m^2\n",
-      "##CALCULATIONS\n",
-      "m1= p1*10*10*10*V1*M/(R*(273.15+T1))\n",
-      "m2= p2*10*10*10*V1*M/(R*(273.15+T2))\n",
-      "m3= -(m2-m1)\n",
-      "T3= (m1*(273.15+T1)-m2*(273.15+T2))/(k*m3)\n",
-      "z3= m3*R*T3/(p2*10*10*10*A*M)\n",
-      "##RESULTS\n",
-      "print'%s %.4f %s'%(' mass of nitrogen =',m3,'kg')\n",
-      "print'%s %.1f %s'%('final temperature =',T3,'K')\n",
-      "print'%s %.2f %s'%('piston rise =',z3,'m')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        " mass of nitrogen = 1.3561 kg\n",
-        "final temperature = 603.1 K\n",
-        "piston rise = 8.10 m\n"
-       ]
-      }
-     ],
-     "prompt_number": 11
-    }
-   ],
-   "metadata": {}
-  }
- ]
-}
-\ No newline at end of file
diff --git a/Thermodynamics:_From_concepts_to_applications/Chapter5_1.ipynb b/Thermodynamics:_From_concepts_to_applications/Chapter5_1.ipynb
deleted file mode 100755
index 7ebf1310..00000000
--- a/Thermodynamics:_From_concepts_to_applications/Chapter5_1.ipynb
+++ /dev/null
@@ -1,166 +0,0 @@
-{
- "metadata": {
-  "name": "",
-  "signature": "sha256:4e735a3e117e4e268af257af7ccec75bd1ac3fad4a8f848db2d81766258e8e27"
- },
- "nbformat": 3,
- "nbformat_minor": 0,
- "worksheets": [
-  {
-   "cells": [
-    {
-     "cell_type": "heading",
-     "level": 1,
-     "metadata": {},
-     "source": [
-      "Chapter5 -The ideal gas"
-     ]
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Example1-pg 66"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "#calculate specific volumes at given pressure\n",
-      "##initialisation of variables\n",
-      "R= 8.314 ##J/mol K\n",
-      "M= 18.016 ##gms\n",
-      "T= 400. ##C\n",
-      "p= 0.01 ##Mpa\n",
-      "p1= 0.1 ##Mpa\n",
-      "p2= 20. ##Mpa\n",
-      "##CALCULATIONS\n",
-      "v= R*(273.156+T)/(M*p*1000)\n",
-      "v1= R*(273.156+T)/(M*p1*1000)\n",
-      "v2= R*(273.156+T)/(M*p2*1000)\n",
-      "##RESULTS\n",
-      "print'%s %.3f %s'%(' specific voulme =',v,'m^3/kg')\n",
-      "print'%s %.3f %s'%('specific voulme = ', v1,'m^3/kg')\n",
-      "print'%s %.3f %s'%('specific voulme = ',v2,'m^3/kg')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        " specific voulme = 31.065 m^3/kg\n",
-        "specific voulme =  3.106 m^3/kg\n",
-        "specific voulme =  0.016 m^3/kg\n"
-       ]
-      }
-     ],
-     "prompt_number": 2
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "example 3-pg73 "
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "#calculate final temperature and pressure and work ,energy\n",
-      "##initialisation of variables\n",
-      "p1= 300.##kPa\n",
-      "V1= 0.03 ##m^3\n",
-      "V2= 0.08 ##m^3\n",
-      "T1= 27. ##C\n",
-      "##CALCULATIONS1\n",
-      "T2= T1+273\n",
-      "p2= p1*(V1/V2)*(T2/(T1+273))\n",
-      "W= 0\n",
-      "Q= 0\n",
-      "##RESULTS\n",
-      "print'%s %.2f %s'%('final temperature =',T2,'K')\n",
-      "print'%s %.1f %s'%('final pressure =',p2,'kPa')\n",
-      "print'%s %.f %s'%('work = ',W,'kJ')\n",
-      "print'%s %.f %s'%('energy =',Q,'kJ')\n",
-      " \n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "final temperature = 300.00 K\n",
-        "final pressure = 112.5 kPa\n",
-        "work =  0 kJ\n",
-        "energy = 0 kJ\n"
-       ]
-      }
-     ],
-     "prompt_number": 9
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Example4 -pg74\n",
-      "\n"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "#calculate mass of nitrogen and final temperature and piston rise\n",
-      "##initialisation of variables\n",
-      "p1= 2. ##Mpa\n",
-      "V1= 0.2 ##m^3\n",
-      "R= 8.314 ##J/mol K\n",
-      "T1= 500. ##C\n",
-      "M= 28. ##gms\n",
-      "p2= 0.3 ##Mpa\n",
-      "T2= 250 ##C\n",
-      "k= 1.4\n",
-      "A= 0.1 ##m^2\n",
-      "##CALCULATIONS\n",
-      "m1= p1*10*10*10*V1*M/(R*(273.15+T1))\n",
-      "m2= p2*10*10*10*V1*M/(R*(273.15+T2))\n",
-      "m3= -(m2-m1)\n",
-      "T3= (m1*(273.15+T1)-m2*(273.15+T2))/(k*m3)\n",
-      "z3= m3*R*T3/(p2*10*10*10*A*M)\n",
-      "##RESULTS\n",
-      "print'%s %.4f %s'%(' mass of nitrogen =',m3,'kg')\n",
-      "print'%s %.1f %s'%('final temperature =',T3,'K')\n",
-      "print'%s %.2f %s'%('piston rise =',z3,'m')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        " mass of nitrogen = 1.3561 kg\n",
-        "final temperature = 603.1 K\n",
-        "piston rise = 8.10 m\n"
-       ]
-      }
-     ],
-     "prompt_number": 11
-    }
-   ],
-   "metadata": {}
-  }
- ]
-}
-\ No newline at end of file
diff --git a/Thermodynamics:_From_concepts_to_applications/Chapter5_2.ipynb b/Thermodynamics:_From_concepts_to_applications/Chapter5_2.ipynb
deleted file mode 100755
index 7ebf1310..00000000
--- a/Thermodynamics:_From_concepts_to_applications/Chapter5_2.ipynb
+++ /dev/null
@@ -1,166 +0,0 @@
-{
- "metadata": {
-  "name": "",
-  "signature": "sha256:4e735a3e117e4e268af257af7ccec75bd1ac3fad4a8f848db2d81766258e8e27"
- },
- "nbformat": 3,
- "nbformat_minor": 0,
- "worksheets": [
-  {
-   "cells": [
-    {
-     "cell_type": "heading",
-     "level": 1,
-     "metadata": {},
-     "source": [
-      "Chapter5 -The ideal gas"
-     ]
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Example1-pg 66"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "#calculate specific volumes at given pressure\n",
-      "##initialisation of variables\n",
-      "R= 8.314 ##J/mol K\n",
-      "M= 18.016 ##gms\n",
-      "T= 400. ##C\n",
-      "p= 0.01 ##Mpa\n",
-      "p1= 0.1 ##Mpa\n",
-      "p2= 20. ##Mpa\n",
-      "##CALCULATIONS\n",
-      "v= R*(273.156+T)/(M*p*1000)\n",
-      "v1= R*(273.156+T)/(M*p1*1000)\n",
-      "v2= R*(273.156+T)/(M*p2*1000)\n",
-      "##RESULTS\n",
-      "print'%s %.3f %s'%(' specific voulme =',v,'m^3/kg')\n",
-      "print'%s %.3f %s'%('specific voulme = ', v1,'m^3/kg')\n",
-      "print'%s %.3f %s'%('specific voulme = ',v2,'m^3/kg')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        " specific voulme = 31.065 m^3/kg\n",
-        "specific voulme =  3.106 m^3/kg\n",
-        "specific voulme =  0.016 m^3/kg\n"
-       ]
-      }
-     ],
-     "prompt_number": 2
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "example 3-pg73 "
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "#calculate final temperature and pressure and work ,energy\n",
-      "##initialisation of variables\n",
-      "p1= 300.##kPa\n",
-      "V1= 0.03 ##m^3\n",
-      "V2= 0.08 ##m^3\n",
-      "T1= 27. ##C\n",
-      "##CALCULATIONS1\n",
-      "T2= T1+273\n",
-      "p2= p1*(V1/V2)*(T2/(T1+273))\n",
-      "W= 0\n",
-      "Q= 0\n",
-      "##RESULTS\n",
-      "print'%s %.2f %s'%('final temperature =',T2,'K')\n",
-      "print'%s %.1f %s'%('final pressure =',p2,'kPa')\n",
-      "print'%s %.f %s'%('work = ',W,'kJ')\n",
-      "print'%s %.f %s'%('energy =',Q,'kJ')\n",
-      " \n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "final temperature = 300.00 K\n",
-        "final pressure = 112.5 kPa\n",
-        "work =  0 kJ\n",
-        "energy = 0 kJ\n"
-       ]
-      }
-     ],
-     "prompt_number": 9
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Example4 -pg74\n",
-      "\n"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "#calculate mass of nitrogen and final temperature and piston rise\n",
-      "##initialisation of variables\n",
-      "p1= 2. ##Mpa\n",
-      "V1= 0.2 ##m^3\n",
-      "R= 8.314 ##J/mol K\n",
-      "T1= 500. ##C\n",
-      "M= 28. ##gms\n",
-      "p2= 0.3 ##Mpa\n",
-      "T2= 250 ##C\n",
-      "k= 1.4\n",
-      "A= 0.1 ##m^2\n",
-      "##CALCULATIONS\n",
-      "m1= p1*10*10*10*V1*M/(R*(273.15+T1))\n",
-      "m2= p2*10*10*10*V1*M/(R*(273.15+T2))\n",
-      "m3= -(m2-m1)\n",
-      "T3= (m1*(273.15+T1)-m2*(273.15+T2))/(k*m3)\n",
-      "z3= m3*R*T3/(p2*10*10*10*A*M)\n",
-      "##RESULTS\n",
-      "print'%s %.4f %s'%(' mass of nitrogen =',m3,'kg')\n",
-      "print'%s %.1f %s'%('final temperature =',T3,'K')\n",
-      "print'%s %.2f %s'%('piston rise =',z3,'m')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        " mass of nitrogen = 1.3561 kg\n",
-        "final temperature = 603.1 K\n",
-        "piston rise = 8.10 m\n"
-       ]
-      }
-     ],
-     "prompt_number": 11
-    }
-   ],
-   "metadata": {}
-  }
- ]
-}
-\ No newline at end of file
diff --git a/Thermodynamics:_From_concepts_to_applications/Chapter6-Control_volume.ipynb b/Thermodynamics:_From_concepts_to_applications/Chapter6-Control_volume.ipynb
deleted file mode 100755
index 4db4d31d..00000000
--- a/Thermodynamics:_From_concepts_to_applications/Chapter6-Control_volume.ipynb
+++ /dev/null
@@ -1,308 +0,0 @@
-{
- "metadata": {
-  "name": "",
-  "signature": "sha256:de09a4c2813282719223c840622b4f97d21f59c5103e9a20c830f4005781fd9e"
- },
- "nbformat": 3,
- "nbformat_minor": 0,
- "worksheets": [
-  {
-   "cells": [
-    {
-     "cell_type": "heading",
-     "level": 1,
-     "metadata": {},
-     "source": [
-      "Chapter6 -Control volume"
-     ]
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Example1-pg 83"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "#calculate diameter for given variable\n",
-      "##initialisation of variables\n",
-      "R= 8.314 ##J/mol K\n",
-      "M= 29 ##gms\n",
-      "T= 80 ##C\n",
-      "p= 104 ##/kPa\n",
-      "v= 30 ##m/sec\n",
-      "m= 8000 ##kg/h\n",
-      "##CALCULATIONS\n",
-      "V= R*(273.15+T)/(M*p)\n",
-      "A= m*V/(3600*v)\n",
-      "D=math.sqrt(4*A/math.pi)\n",
-      "##RESULTS\n",
-      "print'%s %.5f %s'%('diameter = ',D,'m^2')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "diameter =  0.30301 m^2\n"
-       ]
-      }
-     ],
-     "prompt_number": 1
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Example2-pg 88"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "#calculate intial areas\n",
-      "##initialisation of variables\n",
-      "R= 8.314 ##J/mol K\n",
-      "M= 29. ##gms\n",
-      "T1= 230. ##C\n",
-      "p1= 30. ##/bar\n",
-      "k= 1.4\n",
-      "T2= 180. ##C\n",
-      "v1= 10. ##m/s\n",
-      "p2= 20. ##bar\n",
-      "m2= 0.84 ##kg/s\n",
-      "##CALCULATIONS\n",
-      "V1= R*(273.15+T1)/(M*p1*100)\n",
-      "cp= k*R/((k-1)*M)\n",
-      "A= m2*V1*10*10*10*10/v1\n",
-      "v2= math.sqrt(v1*v1+2*cp*10*10*10*(T1-T2))\n",
-      "V2= R*(273.15+T2)/(M*p2*100)\n",
-      "A2= m2*V2*10*10*10*10/v2\n",
-      "##RESULTS\n",
-      "print'%s %.1f %s'%('inlet area =',A,'cm^2')\n",
-      "print'%s %.2f %s'%('inlet area =',A2,'cm^2')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "inlet area = 40.4 cm^2\n",
-        "inlet area = 1.72 cm^2\n"
-       ]
-      }
-     ],
-     "prompt_number": 2
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Example3-pg 89"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "#calculate quantity x and specific volume\n",
-      "##initialisation of variables\n",
-      "h= 2676.2 ##kJ/kg\n",
-      "hf= 721.11 ##kJ/kg\n",
-      "hg= 2679.1 ##kJ/kg\n",
-      "vf= 0.001115 ##m^3/kg\n",
-      "vg= 0.2404 ##m^3/kg\n",
-      "##CALCULATIONS\n",
-      "x= (h-hf)/(hg-hf)\n",
-      "v1= vf+x*(vg-vf)\n",
-      "##RESULTS\n",
-      "print'%s %.4f %s'%('quantity =',x,'')\n",
-      "print'%s %.4f %s'%('specific volume = ',v1,'m^3/kg')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "quantity = 0.9985 \n",
-        "specific volume =  0.2400 m^3/kg\n"
-       ]
-      }
-     ],
-     "prompt_number": 4
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Example4-pg 92"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "#calculate heat pump and reate heat interaction and work of the turbine and at another point rate of heat interaction and all four areas at given poin\n",
-      "##initialisation of variables\n",
-      "h4= 419.05 ##kJ/kg\n",
-      "h1= 434.92 ##kJ/kg\n",
-      "m= 2.5 ##kg/s\n",
-      "h2= 3272.4 ##kJ/kg\n",
-      "h3= 2601.7 ##kJ/kg\n",
-      "v1= 0.001401 ##m^3/kg\n",
-      "V1= 5 ##m/s\n",
-      "v2= 0.03817 ##m^3/kg\n",
-      "V2= 20. ##m/s\n",
-      "v3= 0.8415 ##m^3/kg\n",
-      "V3= 100. ##m/s\n",
-      "v4= 0.00104 ##m^3/kg\n",
-      "V4= 5 ##m/s\n",
-      "##CALCULATIONS\n",
-      "W41= m*(h4-h1)\n",
-      "Q12= m*(h2-h1)\n",
-      "W23= m*(h2-h3)\n",
-      "Q34= m*(h4-h3)\n",
-      "A1= m*v1*10*10*10*10/V1\n",
-      "A2= m*v2*10*1010*10/V2\n",
-      "A3= m*v3*10*1010*10/V3\n",
-      "A4= m*v4*10*1010*10/V4\n",
-      "##RESULTS\n",
-      "print'%s %.1f %s'%('rate of pump =',W41,'kW')\n",
-      "print'%s %.f %s'%('rate of heat ineraction =',Q12,'kW')\n",
-      "print'%s %.1f %s'%('rate of work of the turbine =',W23,'W')\n",
-      "print'%s %.f %s'%('rate of heat ineraction =',Q34,'kW')\n",
-      "print'%s %.2f %s'%('area =',A1,'cm^2')\n",
-      "print'%s %.2f %s'%('area =',A2,'cm^2')\n",
-      "print'%s %.2f %s'%('area =',A3,'cm^2')\n",
-      "print'%s %.2f %s'%('area =',A4,'cm^2')\n",
-      "\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "rate of pump = -39.7 kW\n",
-        "rate of heat ineraction = 7094 kW\n",
-        "rate of work of the turbine = 1676.8 W\n",
-        "rate of heat ineraction = -5457 kW\n",
-        "area = 7.00 cm^2\n",
-        "area = 481.90 cm^2\n",
-        "area = 2124.79 cm^2\n",
-        "area = 52.52 cm^2\n"
-       ]
-      }
-     ],
-     "prompt_number": 5
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Example5-pg 96"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "#calculate mass of helium and temperature of helium\n",
-      "##initialisation of variables\n",
-      "m1= 0.03 ##kg\n",
-      "R= 8.314 ##J/mol K\n",
-      "T1= 300. ##C\n",
-      "p1= 120. ##kPa\n",
-      "k= 5./3.\n",
-      "M=4. ##kg\n",
-      "p2= 600. ##kPa\n",
-      "##CALCULATIONS\n",
-      "V= m1*R*(273.15+T1)/(p1*M)\n",
-      "m2= m1*((p2/p1)+k-1)/k\n",
-      "T2= p2*V*M/(m2*R)\n",
-      "##RESULTS\n",
-      "print'%s %.3f %s'%('mass of helium =',m2,'kg')\n",
-      "print'%s %.1f %s'%('temperature of helium =',T2,'K')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "mass of helium = 0.102 kg\n",
-        "temperature of helium = 842.9 K\n"
-       ]
-      }
-     ],
-     "prompt_number": 7
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Eaxmple 6-pg97"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "#calculate volume of container and pressure\n",
-      "##initialisation of variables\n",
-      "m1= 0.03 ##kg\n",
-      "v1= 2.1977 ##m^3/kg\n",
-      "h2= 3073.8 ##kJ/kg\n",
-      "h1= 3061.6 ##kJ/kg\n",
-      "p2= 600. ##kPa\n",
-      "p1= 120. ##kPa\n",
-      "##CALCULATIONS\n",
-      "V=m1*v1\n",
-      "r= ((h2-h1)/v1)+p2-p1\n",
-      "##RESULTS\n",
-      "print'%s %.5f %s'%('volume of container =',V,'m^3')\n",
-      "print'%s %.2f %s'%('pressure =',r,'kPa')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "volume of container = 0.06593 m^3\n",
-        "pressure = 485.55 kPa\n"
-       ]
-      }
-     ],
-     "prompt_number": 8
-    }
-   ],
-   "metadata": {}
-  }
- ]
-}
-\ No newline at end of file
diff --git a/Thermodynamics:_From_concepts_to_applications/Chapter6.ipynb b/Thermodynamics:_From_concepts_to_applications/Chapter6.ipynb
deleted file mode 100755
index 0e7c0436..00000000
--- a/Thermodynamics:_From_concepts_to_applications/Chapter6.ipynb
+++ /dev/null
@@ -1,308 +0,0 @@
-{
- "metadata": {
-  "name": "",
-  "signature": "sha256:b8ccd5165760dffa261415477a99582312dff66f312e3d719c763faed6ba4a02"
- },
- "nbformat": 3,
- "nbformat_minor": 0,
- "worksheets": [
-  {
-   "cells": [
-    {
-     "cell_type": "heading",
-     "level": 1,
-     "metadata": {},
-     "source": [
-      "Chapter6 -control volume"
-     ]
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Example1-pg 83"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "#calculate diameter for given variable\n",
-      "##initialisation of variables\n",
-      "R= 8.314 ##J/mol K\n",
-      "M= 29 ##gms\n",
-      "T= 80 ##C\n",
-      "p= 104 ##/kPa\n",
-      "v= 30 ##m/sec\n",
-      "m= 8000 ##kg/h\n",
-      "##CALCULATIONS\n",
-      "V= R*(273.15+T)/(M*p)\n",
-      "A= m*V/(3600*v)\n",
-      "D=math.sqrt(4*A/math.pi)\n",
-      "##RESULTS\n",
-      "print'%s %.5f %s'%('diameter = ',D,'m^2')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "diameter =  0.30301 m^2\n"
-       ]
-      }
-     ],
-     "prompt_number": 1
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Example2-pg 88"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "#calculate intial areas\n",
-      "##initialisation of variables\n",
-      "R= 8.314 ##J/mol K\n",
-      "M= 29. ##gms\n",
-      "T1= 230. ##C\n",
-      "p1= 30. ##/bar\n",
-      "k= 1.4\n",
-      "T2= 180. ##C\n",
-      "v1= 10. ##m/s\n",
-      "p2= 20. ##bar\n",
-      "m2= 0.84 ##kg/s\n",
-      "##CALCULATIONS\n",
-      "V1= R*(273.15+T1)/(M*p1*100)\n",
-      "cp= k*R/((k-1)*M)\n",
-      "A= m2*V1*10*10*10*10/v1\n",
-      "v2= math.sqrt(v1*v1+2*cp*10*10*10*(T1-T2))\n",
-      "V2= R*(273.15+T2)/(M*p2*100)\n",
-      "A2= m2*V2*10*10*10*10/v2\n",
-      "##RESULTS\n",
-      "print'%s %.1f %s'%('inlet area =',A,'cm^2')\n",
-      "print'%s %.2f %s'%('inlet area =',A2,'cm^2')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "inlet area = 40.4 cm^2\n",
-        "inlet area = 1.72 cm^2\n"
-       ]
-      }
-     ],
-     "prompt_number": 2
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Example3-pg 89"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "#calculate quantity x and specific volume\n",
-      "##initialisation of variables\n",
-      "h= 2676.2 ##kJ/kg\n",
-      "hf= 721.11 ##kJ/kg\n",
-      "hg= 2679.1 ##kJ/kg\n",
-      "vf= 0.001115 ##m^3/kg\n",
-      "vg= 0.2404 ##m^3/kg\n",
-      "##CALCULATIONS\n",
-      "x= (h-hf)/(hg-hf)\n",
-      "v1= vf+x*(vg-vf)\n",
-      "##RESULTS\n",
-      "print'%s %.4f %s'%('quantity =',x,'')\n",
-      "print'%s %.4f %s'%('specific volume = ',v1,'m^3/kg')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "quantity = 0.9985 \n",
-        "specific volume =  0.2400 m^3/kg\n"
-       ]
-      }
-     ],
-     "prompt_number": 4
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Example4-pg 92"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "#calculate heat pump and reate heat interaction and work of the turbine and at another point rate of heat interaction and all four areas at given poin\n",
-      "##initialisation of variables\n",
-      "h4= 419.05 ##kJ/kg\n",
-      "h1= 434.92 ##kJ/kg\n",
-      "m= 2.5 ##kg/s\n",
-      "h2= 3272.4 ##kJ/kg\n",
-      "h3= 2601.7 ##kJ/kg\n",
-      "v1= 0.001401 ##m^3/kg\n",
-      "V1= 5 ##m/s\n",
-      "v2= 0.03817 ##m^3/kg\n",
-      "V2= 20. ##m/s\n",
-      "v3= 0.8415 ##m^3/kg\n",
-      "V3= 100. ##m/s\n",
-      "v4= 0.00104 ##m^3/kg\n",
-      "V4= 5 ##m/s\n",
-      "##CALCULATIONS\n",
-      "W41= m*(h4-h1)\n",
-      "Q12= m*(h2-h1)\n",
-      "W23= m*(h2-h3)\n",
-      "Q34= m*(h4-h3)\n",
-      "A1= m*v1*10*10*10*10/V1\n",
-      "A2= m*v2*10*1010*10/V2\n",
-      "A3= m*v3*10*1010*10/V3\n",
-      "A4= m*v4*10*1010*10/V4\n",
-      "##RESULTS\n",
-      "print'%s %.1f %s'%('rate of pump =',W41,'kW')\n",
-      "print'%s %.f %s'%('rate of heat ineraction =',Q12,'kW')\n",
-      "print'%s %.1f %s'%('rate of work of the turbine =',W23,'W')\n",
-      "print'%s %.f %s'%('rate of heat ineraction =',Q34,'kW')\n",
-      "print'%s %.2f %s'%('area =',A1,'cm^2')\n",
-      "print'%s %.2f %s'%('area =',A2,'cm^2')\n",
-      "print'%s %.2f %s'%('area =',A3,'cm^2')\n",
-      "print'%s %.2f %s'%('area =',A4,'cm^2')\n",
-      "\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "rate of pump = -39.7 kW\n",
-        "rate of heat ineraction = 7094 kW\n",
-        "rate of work of the turbine = 1676.8 W\n",
-        "rate of heat ineraction = -5457 kW\n",
-        "area = 7.00 cm^2\n",
-        "area = 481.90 cm^2\n",
-        "area = 2124.79 cm^2\n",
-        "area = 52.52 cm^2\n"
-       ]
-      }
-     ],
-     "prompt_number": 5
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Example5-pg 96"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "#calculate mass of helium and temperature of helium\n",
-      "##initialisation of variables\n",
-      "m1= 0.03 ##kg\n",
-      "R= 8.314 ##J/mol K\n",
-      "T1= 300. ##C\n",
-      "p1= 120. ##kPa\n",
-      "k= 5./3.\n",
-      "M=4. ##kg\n",
-      "p2= 600. ##kPa\n",
-      "##CALCULATIONS\n",
-      "V= m1*R*(273.15+T1)/(p1*M)\n",
-      "m2= m1*((p2/p1)+k-1)/k\n",
-      "T2= p2*V*M/(m2*R)\n",
-      "##RESULTS\n",
-      "print'%s %.3f %s'%('mass of helium =',m2,'kg')\n",
-      "print'%s %.1f %s'%('temperature of helium =',T2,'K')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "mass of helium = 0.102 kg\n",
-        "temperature of helium = 842.9 K\n"
-       ]
-      }
-     ],
-     "prompt_number": 7
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Eaxmple 6-pg97"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "#calculate volume of container and pressure\n",
-      "##initialisation of variables\n",
-      "m1= 0.03 ##kg\n",
-      "v1= 2.1977 ##m^3/kg\n",
-      "h2= 3073.8 ##kJ/kg\n",
-      "h1= 3061.6 ##kJ/kg\n",
-      "p2= 600. ##kPa\n",
-      "p1= 120. ##kPa\n",
-      "##CALCULATIONS\n",
-      "V=m1*v1\n",
-      "r= ((h2-h1)/v1)+p2-p1\n",
-      "##RESULTS\n",
-      "print'%s %.5f %s'%('volume of container =',V,'m^3')\n",
-      "print'%s %.2f %s'%('pressure =',r,'kPa')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "volume of container = 0.06593 m^3\n",
-        "pressure = 485.55 kPa\n"
-       ]
-      }
-     ],
-     "prompt_number": 8
-    }
-   ],
-   "metadata": {}
-  }
- ]
-}
-\ No newline at end of file
diff --git a/Thermodynamics:_From_concepts_to_applications/Chapter6_1.ipynb b/Thermodynamics:_From_concepts_to_applications/Chapter6_1.ipynb
deleted file mode 100755
index 4db4d31d..00000000
--- a/Thermodynamics:_From_concepts_to_applications/Chapter6_1.ipynb
+++ /dev/null
@@ -1,308 +0,0 @@
-{
- "metadata": {
-  "name": "",
-  "signature": "sha256:de09a4c2813282719223c840622b4f97d21f59c5103e9a20c830f4005781fd9e"
- },
- "nbformat": 3,
- "nbformat_minor": 0,
- "worksheets": [
-  {
-   "cells": [
-    {
-     "cell_type": "heading",
-     "level": 1,
-     "metadata": {},
-     "source": [
-      "Chapter6 -Control volume"
-     ]
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Example1-pg 83"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "#calculate diameter for given variable\n",
-      "##initialisation of variables\n",
-      "R= 8.314 ##J/mol K\n",
-      "M= 29 ##gms\n",
-      "T= 80 ##C\n",
-      "p= 104 ##/kPa\n",
-      "v= 30 ##m/sec\n",
-      "m= 8000 ##kg/h\n",
-      "##CALCULATIONS\n",
-      "V= R*(273.15+T)/(M*p)\n",
-      "A= m*V/(3600*v)\n",
-      "D=math.sqrt(4*A/math.pi)\n",
-      "##RESULTS\n",
-      "print'%s %.5f %s'%('diameter = ',D,'m^2')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "diameter =  0.30301 m^2\n"
-       ]
-      }
-     ],
-     "prompt_number": 1
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Example2-pg 88"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "#calculate intial areas\n",
-      "##initialisation of variables\n",
-      "R= 8.314 ##J/mol K\n",
-      "M= 29. ##gms\n",
-      "T1= 230. ##C\n",
-      "p1= 30. ##/bar\n",
-      "k= 1.4\n",
-      "T2= 180. ##C\n",
-      "v1= 10. ##m/s\n",
-      "p2= 20. ##bar\n",
-      "m2= 0.84 ##kg/s\n",
-      "##CALCULATIONS\n",
-      "V1= R*(273.15+T1)/(M*p1*100)\n",
-      "cp= k*R/((k-1)*M)\n",
-      "A= m2*V1*10*10*10*10/v1\n",
-      "v2= math.sqrt(v1*v1+2*cp*10*10*10*(T1-T2))\n",
-      "V2= R*(273.15+T2)/(M*p2*100)\n",
-      "A2= m2*V2*10*10*10*10/v2\n",
-      "##RESULTS\n",
-      "print'%s %.1f %s'%('inlet area =',A,'cm^2')\n",
-      "print'%s %.2f %s'%('inlet area =',A2,'cm^2')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "inlet area = 40.4 cm^2\n",
-        "inlet area = 1.72 cm^2\n"
-       ]
-      }
-     ],
-     "prompt_number": 2
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Example3-pg 89"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "#calculate quantity x and specific volume\n",
-      "##initialisation of variables\n",
-      "h= 2676.2 ##kJ/kg\n",
-      "hf= 721.11 ##kJ/kg\n",
-      "hg= 2679.1 ##kJ/kg\n",
-      "vf= 0.001115 ##m^3/kg\n",
-      "vg= 0.2404 ##m^3/kg\n",
-      "##CALCULATIONS\n",
-      "x= (h-hf)/(hg-hf)\n",
-      "v1= vf+x*(vg-vf)\n",
-      "##RESULTS\n",
-      "print'%s %.4f %s'%('quantity =',x,'')\n",
-      "print'%s %.4f %s'%('specific volume = ',v1,'m^3/kg')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "quantity = 0.9985 \n",
-        "specific volume =  0.2400 m^3/kg\n"
-       ]
-      }
-     ],
-     "prompt_number": 4
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Example4-pg 92"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "#calculate heat pump and reate heat interaction and work of the turbine and at another point rate of heat interaction and all four areas at given poin\n",
-      "##initialisation of variables\n",
-      "h4= 419.05 ##kJ/kg\n",
-      "h1= 434.92 ##kJ/kg\n",
-      "m= 2.5 ##kg/s\n",
-      "h2= 3272.4 ##kJ/kg\n",
-      "h3= 2601.7 ##kJ/kg\n",
-      "v1= 0.001401 ##m^3/kg\n",
-      "V1= 5 ##m/s\n",
-      "v2= 0.03817 ##m^3/kg\n",
-      "V2= 20. ##m/s\n",
-      "v3= 0.8415 ##m^3/kg\n",
-      "V3= 100. ##m/s\n",
-      "v4= 0.00104 ##m^3/kg\n",
-      "V4= 5 ##m/s\n",
-      "##CALCULATIONS\n",
-      "W41= m*(h4-h1)\n",
-      "Q12= m*(h2-h1)\n",
-      "W23= m*(h2-h3)\n",
-      "Q34= m*(h4-h3)\n",
-      "A1= m*v1*10*10*10*10/V1\n",
-      "A2= m*v2*10*1010*10/V2\n",
-      "A3= m*v3*10*1010*10/V3\n",
-      "A4= m*v4*10*1010*10/V4\n",
-      "##RESULTS\n",
-      "print'%s %.1f %s'%('rate of pump =',W41,'kW')\n",
-      "print'%s %.f %s'%('rate of heat ineraction =',Q12,'kW')\n",
-      "print'%s %.1f %s'%('rate of work of the turbine =',W23,'W')\n",
-      "print'%s %.f %s'%('rate of heat ineraction =',Q34,'kW')\n",
-      "print'%s %.2f %s'%('area =',A1,'cm^2')\n",
-      "print'%s %.2f %s'%('area =',A2,'cm^2')\n",
-      "print'%s %.2f %s'%('area =',A3,'cm^2')\n",
-      "print'%s %.2f %s'%('area =',A4,'cm^2')\n",
-      "\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "rate of pump = -39.7 kW\n",
-        "rate of heat ineraction = 7094 kW\n",
-        "rate of work of the turbine = 1676.8 W\n",
-        "rate of heat ineraction = -5457 kW\n",
-        "area = 7.00 cm^2\n",
-        "area = 481.90 cm^2\n",
-        "area = 2124.79 cm^2\n",
-        "area = 52.52 cm^2\n"
-       ]
-      }
-     ],
-     "prompt_number": 5
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Example5-pg 96"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "#calculate mass of helium and temperature of helium\n",
-      "##initialisation of variables\n",
-      "m1= 0.03 ##kg\n",
-      "R= 8.314 ##J/mol K\n",
-      "T1= 300. ##C\n",
-      "p1= 120. ##kPa\n",
-      "k= 5./3.\n",
-      "M=4. ##kg\n",
-      "p2= 600. ##kPa\n",
-      "##CALCULATIONS\n",
-      "V= m1*R*(273.15+T1)/(p1*M)\n",
-      "m2= m1*((p2/p1)+k-1)/k\n",
-      "T2= p2*V*M/(m2*R)\n",
-      "##RESULTS\n",
-      "print'%s %.3f %s'%('mass of helium =',m2,'kg')\n",
-      "print'%s %.1f %s'%('temperature of helium =',T2,'K')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "mass of helium = 0.102 kg\n",
-        "temperature of helium = 842.9 K\n"
-       ]
-      }
-     ],
-     "prompt_number": 7
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Eaxmple 6-pg97"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "#calculate volume of container and pressure\n",
-      "##initialisation of variables\n",
-      "m1= 0.03 ##kg\n",
-      "v1= 2.1977 ##m^3/kg\n",
-      "h2= 3073.8 ##kJ/kg\n",
-      "h1= 3061.6 ##kJ/kg\n",
-      "p2= 600. ##kPa\n",
-      "p1= 120. ##kPa\n",
-      "##CALCULATIONS\n",
-      "V=m1*v1\n",
-      "r= ((h2-h1)/v1)+p2-p1\n",
-      "##RESULTS\n",
-      "print'%s %.5f %s'%('volume of container =',V,'m^3')\n",
-      "print'%s %.2f %s'%('pressure =',r,'kPa')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "volume of container = 0.06593 m^3\n",
-        "pressure = 485.55 kPa\n"
-       ]
-      }
-     ],
-     "prompt_number": 8
-    }
-   ],
-   "metadata": {}
-  }
- ]
-}
-\ No newline at end of file
diff --git a/Thermodynamics:_From_concepts_to_applications/Chapter6_2.ipynb b/Thermodynamics:_From_concepts_to_applications/Chapter6_2.ipynb
deleted file mode 100755
index 4db4d31d..00000000
--- a/Thermodynamics:_From_concepts_to_applications/Chapter6_2.ipynb
+++ /dev/null
@@ -1,308 +0,0 @@
-{
- "metadata": {
-  "name": "",
-  "signature": "sha256:de09a4c2813282719223c840622b4f97d21f59c5103e9a20c830f4005781fd9e"
- },
- "nbformat": 3,
- "nbformat_minor": 0,
- "worksheets": [
-  {
-   "cells": [
-    {
-     "cell_type": "heading",
-     "level": 1,
-     "metadata": {},
-     "source": [
-      "Chapter6 -Control volume"
-     ]
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Example1-pg 83"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "#calculate diameter for given variable\n",
-      "##initialisation of variables\n",
-      "R= 8.314 ##J/mol K\n",
-      "M= 29 ##gms\n",
-      "T= 80 ##C\n",
-      "p= 104 ##/kPa\n",
-      "v= 30 ##m/sec\n",
-      "m= 8000 ##kg/h\n",
-      "##CALCULATIONS\n",
-      "V= R*(273.15+T)/(M*p)\n",
-      "A= m*V/(3600*v)\n",
-      "D=math.sqrt(4*A/math.pi)\n",
-      "##RESULTS\n",
-      "print'%s %.5f %s'%('diameter = ',D,'m^2')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "diameter =  0.30301 m^2\n"
-       ]
-      }
-     ],
-     "prompt_number": 1
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Example2-pg 88"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "#calculate intial areas\n",
-      "##initialisation of variables\n",
-      "R= 8.314 ##J/mol K\n",
-      "M= 29. ##gms\n",
-      "T1= 230. ##C\n",
-      "p1= 30. ##/bar\n",
-      "k= 1.4\n",
-      "T2= 180. ##C\n",
-      "v1= 10. ##m/s\n",
-      "p2= 20. ##bar\n",
-      "m2= 0.84 ##kg/s\n",
-      "##CALCULATIONS\n",
-      "V1= R*(273.15+T1)/(M*p1*100)\n",
-      "cp= k*R/((k-1)*M)\n",
-      "A= m2*V1*10*10*10*10/v1\n",
-      "v2= math.sqrt(v1*v1+2*cp*10*10*10*(T1-T2))\n",
-      "V2= R*(273.15+T2)/(M*p2*100)\n",
-      "A2= m2*V2*10*10*10*10/v2\n",
-      "##RESULTS\n",
-      "print'%s %.1f %s'%('inlet area =',A,'cm^2')\n",
-      "print'%s %.2f %s'%('inlet area =',A2,'cm^2')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "inlet area = 40.4 cm^2\n",
-        "inlet area = 1.72 cm^2\n"
-       ]
-      }
-     ],
-     "prompt_number": 2
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Example3-pg 89"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "#calculate quantity x and specific volume\n",
-      "##initialisation of variables\n",
-      "h= 2676.2 ##kJ/kg\n",
-      "hf= 721.11 ##kJ/kg\n",
-      "hg= 2679.1 ##kJ/kg\n",
-      "vf= 0.001115 ##m^3/kg\n",
-      "vg= 0.2404 ##m^3/kg\n",
-      "##CALCULATIONS\n",
-      "x= (h-hf)/(hg-hf)\n",
-      "v1= vf+x*(vg-vf)\n",
-      "##RESULTS\n",
-      "print'%s %.4f %s'%('quantity =',x,'')\n",
-      "print'%s %.4f %s'%('specific volume = ',v1,'m^3/kg')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "quantity = 0.9985 \n",
-        "specific volume =  0.2400 m^3/kg\n"
-       ]
-      }
-     ],
-     "prompt_number": 4
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Example4-pg 92"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "#calculate heat pump and reate heat interaction and work of the turbine and at another point rate of heat interaction and all four areas at given poin\n",
-      "##initialisation of variables\n",
-      "h4= 419.05 ##kJ/kg\n",
-      "h1= 434.92 ##kJ/kg\n",
-      "m= 2.5 ##kg/s\n",
-      "h2= 3272.4 ##kJ/kg\n",
-      "h3= 2601.7 ##kJ/kg\n",
-      "v1= 0.001401 ##m^3/kg\n",
-      "V1= 5 ##m/s\n",
-      "v2= 0.03817 ##m^3/kg\n",
-      "V2= 20. ##m/s\n",
-      "v3= 0.8415 ##m^3/kg\n",
-      "V3= 100. ##m/s\n",
-      "v4= 0.00104 ##m^3/kg\n",
-      "V4= 5 ##m/s\n",
-      "##CALCULATIONS\n",
-      "W41= m*(h4-h1)\n",
-      "Q12= m*(h2-h1)\n",
-      "W23= m*(h2-h3)\n",
-      "Q34= m*(h4-h3)\n",
-      "A1= m*v1*10*10*10*10/V1\n",
-      "A2= m*v2*10*1010*10/V2\n",
-      "A3= m*v3*10*1010*10/V3\n",
-      "A4= m*v4*10*1010*10/V4\n",
-      "##RESULTS\n",
-      "print'%s %.1f %s'%('rate of pump =',W41,'kW')\n",
-      "print'%s %.f %s'%('rate of heat ineraction =',Q12,'kW')\n",
-      "print'%s %.1f %s'%('rate of work of the turbine =',W23,'W')\n",
-      "print'%s %.f %s'%('rate of heat ineraction =',Q34,'kW')\n",
-      "print'%s %.2f %s'%('area =',A1,'cm^2')\n",
-      "print'%s %.2f %s'%('area =',A2,'cm^2')\n",
-      "print'%s %.2f %s'%('area =',A3,'cm^2')\n",
-      "print'%s %.2f %s'%('area =',A4,'cm^2')\n",
-      "\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "rate of pump = -39.7 kW\n",
-        "rate of heat ineraction = 7094 kW\n",
-        "rate of work of the turbine = 1676.8 W\n",
-        "rate of heat ineraction = -5457 kW\n",
-        "area = 7.00 cm^2\n",
-        "area = 481.90 cm^2\n",
-        "area = 2124.79 cm^2\n",
-        "area = 52.52 cm^2\n"
-       ]
-      }
-     ],
-     "prompt_number": 5
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Example5-pg 96"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "#calculate mass of helium and temperature of helium\n",
-      "##initialisation of variables\n",
-      "m1= 0.03 ##kg\n",
-      "R= 8.314 ##J/mol K\n",
-      "T1= 300. ##C\n",
-      "p1= 120. ##kPa\n",
-      "k= 5./3.\n",
-      "M=4. ##kg\n",
-      "p2= 600. ##kPa\n",
-      "##CALCULATIONS\n",
-      "V= m1*R*(273.15+T1)/(p1*M)\n",
-      "m2= m1*((p2/p1)+k-1)/k\n",
-      "T2= p2*V*M/(m2*R)\n",
-      "##RESULTS\n",
-      "print'%s %.3f %s'%('mass of helium =',m2,'kg')\n",
-      "print'%s %.1f %s'%('temperature of helium =',T2,'K')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "mass of helium = 0.102 kg\n",
-        "temperature of helium = 842.9 K\n"
-       ]
-      }
-     ],
-     "prompt_number": 7
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Eaxmple 6-pg97"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "#calculate volume of container and pressure\n",
-      "##initialisation of variables\n",
-      "m1= 0.03 ##kg\n",
-      "v1= 2.1977 ##m^3/kg\n",
-      "h2= 3073.8 ##kJ/kg\n",
-      "h1= 3061.6 ##kJ/kg\n",
-      "p2= 600. ##kPa\n",
-      "p1= 120. ##kPa\n",
-      "##CALCULATIONS\n",
-      "V=m1*v1\n",
-      "r= ((h2-h1)/v1)+p2-p1\n",
-      "##RESULTS\n",
-      "print'%s %.5f %s'%('volume of container =',V,'m^3')\n",
-      "print'%s %.2f %s'%('pressure =',r,'kPa')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "volume of container = 0.06593 m^3\n",
-        "pressure = 485.55 kPa\n"
-       ]
-      }
-     ],
-     "prompt_number": 8
-    }
-   ],
-   "metadata": {}
-  }
- ]
-}
-\ No newline at end of file
diff --git a/Thermodynamics:_From_concepts_to_applications/Chapter7-Heat_engines_and_the_second_law_of_thermodynamics.ipynb b/Thermodynamics:_From_concepts_to_applications/Chapter7-Heat_engines_and_the_second_law_of_thermodynamics.ipynb
deleted file mode 100755
index eb4c5f7b..00000000
--- a/Thermodynamics:_From_concepts_to_applications/Chapter7-Heat_engines_and_the_second_law_of_thermodynamics.ipynb
+++ /dev/null
@@ -1,123 +0,0 @@
-{
- "metadata": {
-  "name": "",
-  "signature": "sha256:d5b975c50e55ebe3a2b199f890473e0371318b3f156613b06dbc3a02621943c9"
- },
- "nbformat": 3,
- "nbformat_minor": 0,
- "worksheets": [
-  {
-   "cells": [
-    {
-     "cell_type": "heading",
-     "level": 1,
-     "metadata": {},
-     "source": [
-      "Chapter7-Heat engines and the second law of thermodynamics"
-     ]
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Example1 pg- 112"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "#calculate heat and efficency\n",
-      "##initialisation of variables\n",
-      "m= 0.35 ##kg\n",
-      "u2= 211.785 ##kJ/kg\n",
-      "u1= 182.267 ##kJ/kg\n",
-      "p2= 300. ##kPa\n",
-      "v3= 0.085566 ##kJ/kg\n",
-      "v2= 0.076218 ##kJ/kg\n",
-      "h3= 260.391 ##kJ/kg\n",
-      "h2= 234.650 ##kJ/kg\n",
-      "u4= 199.460 ##kJ/kg\n",
-      "u3= 234.721 ##kJ/kg\n",
-      "p4= 250.##kPa\n",
-      "v1= 0.076218 ##kJ/kg\n",
-      "v4= 0.085566 ##kJ/kg\n",
-      "h1= 201.322 ##kJ/kg\n",
-      "h4= 220.851 ##kJ/kg\n",
-      "##CALCULATIONS\n",
-      "Q12= m*(u2-u1)\n",
-      "W23= m*p2*(v3-v2)\n",
-      "Q23= m*(h3-h2)\n",
-      "W34= 0\n",
-      "Q34= m*(u4-u3)\n",
-      "W41= m*p4*(v1-v4)\n",
-      "Q41= m*(h1-h4)\n",
-      "dW= W23+W41\n",
-      "dQ= Q12+Q23+Q34+Q41\n",
-      "Qh= Q12+Q23\n",
-      "n= dW*100/Qh\n",
-      "##RESULTS\n",
-      "print'%s %.2f %s'%('heat = ',Qh,'kj')\n",
-      "print'%s %.2f %s'%('efficiency =',n, 'percent')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "heat =  19.34 kj\n",
-        "efficiency = 0.85 percent\n"
-       ]
-      }
-     ],
-     "prompt_number": 1
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Example4 pg-123"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "#calculate effiecncy of heat engine and efficency\n",
-      "##initialisation of variables\n",
-      "Qc= 9 ##kW\n",
-      "W= 7.5 ##kW\n",
-      "Qh= Qc+W\n",
-      "Tc= 50 ##C\n",
-      "Th= 400 ##C\n",
-      "##CALCULATIONS\n",
-      "n= W/Qh\n",
-      "nrev= 1-((273.15+Tc)/(273.15+Th))\n",
-      "##RESULTS\n",
-      "print'%s %.3f %s'% ('efficiency of heat engine = ',n,'')\n",
-      "print'%s %.3f %s'%('efficiency =',nrev,'')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "efficiency of heat engine =  0.455 \n",
-        "efficiency = 0.520 \n"
-       ]
-      }
-     ],
-     "prompt_number": 2
-    }
-   ],
-   "metadata": {}
-  }
- ]
-}
-\ No newline at end of file
diff --git a/Thermodynamics:_From_concepts_to_applications/Chapter7.ipynb b/Thermodynamics:_From_concepts_to_applications/Chapter7.ipynb
deleted file mode 100755
index eb4c5f7b..00000000
--- a/Thermodynamics:_From_concepts_to_applications/Chapter7.ipynb
+++ /dev/null
@@ -1,123 +0,0 @@
-{
- "metadata": {
-  "name": "",
-  "signature": "sha256:d5b975c50e55ebe3a2b199f890473e0371318b3f156613b06dbc3a02621943c9"
- },
- "nbformat": 3,
- "nbformat_minor": 0,
- "worksheets": [
-  {
-   "cells": [
-    {
-     "cell_type": "heading",
-     "level": 1,
-     "metadata": {},
-     "source": [
-      "Chapter7-Heat engines and the second law of thermodynamics"
-     ]
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Example1 pg- 112"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "#calculate heat and efficency\n",
-      "##initialisation of variables\n",
-      "m= 0.35 ##kg\n",
-      "u2= 211.785 ##kJ/kg\n",
-      "u1= 182.267 ##kJ/kg\n",
-      "p2= 300. ##kPa\n",
-      "v3= 0.085566 ##kJ/kg\n",
-      "v2= 0.076218 ##kJ/kg\n",
-      "h3= 260.391 ##kJ/kg\n",
-      "h2= 234.650 ##kJ/kg\n",
-      "u4= 199.460 ##kJ/kg\n",
-      "u3= 234.721 ##kJ/kg\n",
-      "p4= 250.##kPa\n",
-      "v1= 0.076218 ##kJ/kg\n",
-      "v4= 0.085566 ##kJ/kg\n",
-      "h1= 201.322 ##kJ/kg\n",
-      "h4= 220.851 ##kJ/kg\n",
-      "##CALCULATIONS\n",
-      "Q12= m*(u2-u1)\n",
-      "W23= m*p2*(v3-v2)\n",
-      "Q23= m*(h3-h2)\n",
-      "W34= 0\n",
-      "Q34= m*(u4-u3)\n",
-      "W41= m*p4*(v1-v4)\n",
-      "Q41= m*(h1-h4)\n",
-      "dW= W23+W41\n",
-      "dQ= Q12+Q23+Q34+Q41\n",
-      "Qh= Q12+Q23\n",
-      "n= dW*100/Qh\n",
-      "##RESULTS\n",
-      "print'%s %.2f %s'%('heat = ',Qh,'kj')\n",
-      "print'%s %.2f %s'%('efficiency =',n, 'percent')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "heat =  19.34 kj\n",
-        "efficiency = 0.85 percent\n"
-       ]
-      }
-     ],
-     "prompt_number": 1
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Example4 pg-123"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "#calculate effiecncy of heat engine and efficency\n",
-      "##initialisation of variables\n",
-      "Qc= 9 ##kW\n",
-      "W= 7.5 ##kW\n",
-      "Qh= Qc+W\n",
-      "Tc= 50 ##C\n",
-      "Th= 400 ##C\n",
-      "##CALCULATIONS\n",
-      "n= W/Qh\n",
-      "nrev= 1-((273.15+Tc)/(273.15+Th))\n",
-      "##RESULTS\n",
-      "print'%s %.3f %s'% ('efficiency of heat engine = ',n,'')\n",
-      "print'%s %.3f %s'%('efficiency =',nrev,'')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "efficiency of heat engine =  0.455 \n",
-        "efficiency = 0.520 \n"
-       ]
-      }
-     ],
-     "prompt_number": 2
-    }
-   ],
-   "metadata": {}
-  }
- ]
-}
-\ No newline at end of file
diff --git a/Thermodynamics:_From_concepts_to_applications/Chapter7_1.ipynb b/Thermodynamics:_From_concepts_to_applications/Chapter7_1.ipynb
deleted file mode 100755
index eb4c5f7b..00000000
--- a/Thermodynamics:_From_concepts_to_applications/Chapter7_1.ipynb
+++ /dev/null
@@ -1,123 +0,0 @@
-{
- "metadata": {
-  "name": "",
-  "signature": "sha256:d5b975c50e55ebe3a2b199f890473e0371318b3f156613b06dbc3a02621943c9"
- },
- "nbformat": 3,
- "nbformat_minor": 0,
- "worksheets": [
-  {
-   "cells": [
-    {
-     "cell_type": "heading",
-     "level": 1,
-     "metadata": {},
-     "source": [
-      "Chapter7-Heat engines and the second law of thermodynamics"
-     ]
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Example1 pg- 112"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "#calculate heat and efficency\n",
-      "##initialisation of variables\n",
-      "m= 0.35 ##kg\n",
-      "u2= 211.785 ##kJ/kg\n",
-      "u1= 182.267 ##kJ/kg\n",
-      "p2= 300. ##kPa\n",
-      "v3= 0.085566 ##kJ/kg\n",
-      "v2= 0.076218 ##kJ/kg\n",
-      "h3= 260.391 ##kJ/kg\n",
-      "h2= 234.650 ##kJ/kg\n",
-      "u4= 199.460 ##kJ/kg\n",
-      "u3= 234.721 ##kJ/kg\n",
-      "p4= 250.##kPa\n",
-      "v1= 0.076218 ##kJ/kg\n",
-      "v4= 0.085566 ##kJ/kg\n",
-      "h1= 201.322 ##kJ/kg\n",
-      "h4= 220.851 ##kJ/kg\n",
-      "##CALCULATIONS\n",
-      "Q12= m*(u2-u1)\n",
-      "W23= m*p2*(v3-v2)\n",
-      "Q23= m*(h3-h2)\n",
-      "W34= 0\n",
-      "Q34= m*(u4-u3)\n",
-      "W41= m*p4*(v1-v4)\n",
-      "Q41= m*(h1-h4)\n",
-      "dW= W23+W41\n",
-      "dQ= Q12+Q23+Q34+Q41\n",
-      "Qh= Q12+Q23\n",
-      "n= dW*100/Qh\n",
-      "##RESULTS\n",
-      "print'%s %.2f %s'%('heat = ',Qh,'kj')\n",
-      "print'%s %.2f %s'%('efficiency =',n, 'percent')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "heat =  19.34 kj\n",
-        "efficiency = 0.85 percent\n"
-       ]
-      }
-     ],
-     "prompt_number": 1
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Example4 pg-123"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "#calculate effiecncy of heat engine and efficency\n",
-      "##initialisation of variables\n",
-      "Qc= 9 ##kW\n",
-      "W= 7.5 ##kW\n",
-      "Qh= Qc+W\n",
-      "Tc= 50 ##C\n",
-      "Th= 400 ##C\n",
-      "##CALCULATIONS\n",
-      "n= W/Qh\n",
-      "nrev= 1-((273.15+Tc)/(273.15+Th))\n",
-      "##RESULTS\n",
-      "print'%s %.3f %s'% ('efficiency of heat engine = ',n,'')\n",
-      "print'%s %.3f %s'%('efficiency =',nrev,'')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "efficiency of heat engine =  0.455 \n",
-        "efficiency = 0.520 \n"
-       ]
-      }
-     ],
-     "prompt_number": 2
-    }
-   ],
-   "metadata": {}
-  }
- ]
-}
-\ No newline at end of file
diff --git a/Thermodynamics:_From_concepts_to_applications/Chapter7_2.ipynb b/Thermodynamics:_From_concepts_to_applications/Chapter7_2.ipynb
deleted file mode 100755
index eb4c5f7b..00000000
--- a/Thermodynamics:_From_concepts_to_applications/Chapter7_2.ipynb
+++ /dev/null
@@ -1,123 +0,0 @@
-{
- "metadata": {
-  "name": "",
-  "signature": "sha256:d5b975c50e55ebe3a2b199f890473e0371318b3f156613b06dbc3a02621943c9"
- },
- "nbformat": 3,
- "nbformat_minor": 0,
- "worksheets": [
-  {
-   "cells": [
-    {
-     "cell_type": "heading",
-     "level": 1,
-     "metadata": {},
-     "source": [
-      "Chapter7-Heat engines and the second law of thermodynamics"
-     ]
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Example1 pg- 112"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "#calculate heat and efficency\n",
-      "##initialisation of variables\n",
-      "m= 0.35 ##kg\n",
-      "u2= 211.785 ##kJ/kg\n",
-      "u1= 182.267 ##kJ/kg\n",
-      "p2= 300. ##kPa\n",
-      "v3= 0.085566 ##kJ/kg\n",
-      "v2= 0.076218 ##kJ/kg\n",
-      "h3= 260.391 ##kJ/kg\n",
-      "h2= 234.650 ##kJ/kg\n",
-      "u4= 199.460 ##kJ/kg\n",
-      "u3= 234.721 ##kJ/kg\n",
-      "p4= 250.##kPa\n",
-      "v1= 0.076218 ##kJ/kg\n",
-      "v4= 0.085566 ##kJ/kg\n",
-      "h1= 201.322 ##kJ/kg\n",
-      "h4= 220.851 ##kJ/kg\n",
-      "##CALCULATIONS\n",
-      "Q12= m*(u2-u1)\n",
-      "W23= m*p2*(v3-v2)\n",
-      "Q23= m*(h3-h2)\n",
-      "W34= 0\n",
-      "Q34= m*(u4-u3)\n",
-      "W41= m*p4*(v1-v4)\n",
-      "Q41= m*(h1-h4)\n",
-      "dW= W23+W41\n",
-      "dQ= Q12+Q23+Q34+Q41\n",
-      "Qh= Q12+Q23\n",
-      "n= dW*100/Qh\n",
-      "##RESULTS\n",
-      "print'%s %.2f %s'%('heat = ',Qh,'kj')\n",
-      "print'%s %.2f %s'%('efficiency =',n, 'percent')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "heat =  19.34 kj\n",
-        "efficiency = 0.85 percent\n"
-       ]
-      }
-     ],
-     "prompt_number": 1
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Example4 pg-123"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "#calculate effiecncy of heat engine and efficency\n",
-      "##initialisation of variables\n",
-      "Qc= 9 ##kW\n",
-      "W= 7.5 ##kW\n",
-      "Qh= Qc+W\n",
-      "Tc= 50 ##C\n",
-      "Th= 400 ##C\n",
-      "##CALCULATIONS\n",
-      "n= W/Qh\n",
-      "nrev= 1-((273.15+Tc)/(273.15+Th))\n",
-      "##RESULTS\n",
-      "print'%s %.3f %s'% ('efficiency of heat engine = ',n,'')\n",
-      "print'%s %.3f %s'%('efficiency =',nrev,'')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "efficiency of heat engine =  0.455 \n",
-        "efficiency = 0.520 \n"
-       ]
-      }
-     ],
-     "prompt_number": 2
-    }
-   ],
-   "metadata": {}
-  }
- ]
-}
-\ No newline at end of file
diff --git a/Thermodynamics:_From_concepts_to_applications/Chapter8-Entropy.ipynb b/Thermodynamics:_From_concepts_to_applications/Chapter8-Entropy.ipynb
deleted file mode 100755
index c1d76b67..00000000
--- a/Thermodynamics:_From_concepts_to_applications/Chapter8-Entropy.ipynb
+++ /dev/null
@@ -1,309 +0,0 @@
-{
- "metadata": {
-  "name": "",
-  "signature": "sha256:8780f29f2ca7dbbe28306b63f91de121a8fdfb0cc3c24c326256cd5a0309b1ed"
- },
- "nbformat": 3,
- "nbformat_minor": 0,
- "worksheets": [
-  {
-   "cells": [
-    {
-     "cell_type": "heading",
-     "level": 1,
-     "metadata": {},
-     "source": [
-      "Chapter8-Entropy"
-     ]
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Example1 pg- 131"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "#calculate and entropy of ice and environment and universe\n",
-      "##initialisation of variables\n",
-      "m= 2 ##kg\n",
-      "dh= 333.39 ##kg/h\n",
-      "T= 0 ##C\n",
-      "T1= 20 ##C\n",
-      "##CALCULATIONS\n",
-      "Q12= m*dh\n",
-      "dS= Q12/(273.15+T)\n",
-      "dSenvir= -Q12/(273.15+T1)\n",
-      "dStotal= dS+dSenvir\n",
-      "##RESULTS\n",
-      "print'%s %.3f %s'%(' entropy of ice =',dS,'kJ/K')\n",
-      "print'%s %.3f %s'%('entropy of environment =',dSenvir,'kJ/K')\n",
-      "print'%s %.3f %s'%('entropy of universe =',dStotal,'kJ/K')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        " entropy of ice = 2.441 kJ/K\n",
-        "entropy of environment = -2.275 kJ/K\n",
-        "entropy of universe = 0.167 kJ/K\n"
-       ]
-      }
-     ],
-     "prompt_number": 1
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Example2-pg132"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "#calculate change in entropy in system and environment and entropy\n",
-      "##initialisation of variables\n",
-      "Q= 666.78 ##kJ\n",
-      "T= 0 ##C\n",
-      "Th= 20. ##C\n",
-      "##CALCULATIONS\n",
-      "Ssys= Q/(273.15+T)\n",
-      "Qh= Q*((273.15+Th)/(273.15+T))\n",
-      "Senvir= -Qh/(273.15+Th)\n",
-      "Stotal= Ssys+Senvir\n",
-      "##RESULTS\n",
-      "print'%s %.4f %s'%('change in entropy in sysytem =',Ssys,' kJ/K')\n",
-      "print'%s %.4f %s'%('change in entropy in environment =',Senvir,'kJ/K')\n",
-      "print'%s %.f %s'%('total change in entropy =',Stotal,'kJ/K')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "change in entropy in sysytem = 2.4411  kJ/K\n",
-        "change in entropy in environment = -2.4411 kJ/K\n",
-        "total change in entropy = 0 kJ/K\n"
-       ]
-      }
-     ],
-     "prompt_number": 2
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Example3-pg134\n"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "#calculate change in entropy\n",
-      "##initialisation of variables\n",
-      "S1= 6.2872 ##J/kg K\n",
-      "S2= 5.8712 ##J/kg K\n",
-      "m= 18 ##kg\n",
-      "##CALCULATIONS\n",
-      "S= m*(S1-S2)\n",
-      "##RESULTS\n",
-      "print'%s %.3f %s'%(' change in entropy =',S,'kJ/K')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        " change in entropy = 7.488 kJ/K\n"
-       ]
-      }
-     ],
-     "prompt_number": 3
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Example4-pg 134"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "#calculate change in entropy\n",
-      "##initialisation of variables\n",
-      "S2= 5.8328 ##kJ/kg\n",
-      "S1= 5.8712 ##kJ/kg\n",
-      "##CALCULATIONS\n",
-      "S= S2-S1\n",
-      "##RESULTS\n",
-      "print'%s %.5f %s'%('change in entropy = ',S,'kJ/K')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "change in entropy =  -0.03840 kJ/K\n"
-       ]
-      }
-     ],
-     "prompt_number": 5
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Example5-pg135"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "#calculate enthalpy and change in entropy\n",
-      "##initialisation of variables\n",
-      "m= 0.1 ##kg\n",
-      "p= 3 ##bar\n",
-      "p1= 10 ##bar\n",
-      "h1= 2964.3 ##kJ/kg\n",
-      "v1=0.2378\n",
-      "s2= 7.1619 ##kJ/k\n",
-      "s1= 6.9641 ##kJ/k\n",
-      "##CALCULATIONS\n",
-      "h2= h1+(p-p1)*math.pow(10,5)*v1*math.pow(10,-3)\n",
-      "S= m*(s2-s1)\n",
-      "##RESULTS\n",
-      "print'%s %.1f %s'%(' enthalpy =',h2,'kJ/kg')\n",
-      "print'%s %.5f %s'%('change in entropy =',S,'kJ/K')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        " enthalpy = 2797.8 kJ/kg\n",
-        "change in entropy = 0.01978 kJ/K\n"
-       ]
-      }
-     ],
-     "prompt_number": 4
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Example6-pg 137"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "#calculate final pressure and change in entropy\n",
-      "import math\n",
-      "##initialisation of variables\n",
-      "p1= 5. ##bar\n",
-      "V1= 0.4 ##m^2\n",
-      "V2= 1.2 ##m^3\n",
-      "R= 8.314 ##J/mol K\n",
-      "M= 28.##gms\n",
-      "T1= 80.##C\n",
-      "##CALCULATIONS\n",
-      "p2= p1*(V1/V2)\n",
-      "S= R*math.log(V2/V1)/M\n",
-      "S1= S*p1*V1*100/((R/M)*(273.15+T1))\n",
-      "##RESULTS\n",
-      "print'%s %.3f %s'%(' final pressure =',p2,'bar')\n",
-      "print'%s %.4f %s'% ('change in entropy =',S1,'kJ/kg K')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        " final pressure = 1.667 bar\n",
-        "change in entropy = 0.6222 kJ/kg K\n"
-       ]
-      }
-     ],
-     "prompt_number": 6
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Example7-pg 137"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "#calculate heat and change in entropy of system and change in entropy of enironment\n",
-      "##initialisation of variables\n",
-      "R= 8.314 ##J/mol K\n",
-      "M= 29. ##gms\n",
-      "T= 400. ##K\n",
-      "p2= 1.6 ##bar\n",
-      "p1= 1. ##bar\n",
-      "Tenvir= 300. ##K\n",
-      "##CALCULATIONS\n",
-      "q= R*T*math.log(p2/p1)/M\n",
-      "S= -R*math.log(p2/p1)/M\n",
-      "Senvir= q/Tenvir\n",
-      "##RESULTS\n",
-      "print'%s %.1f %s'%('heat =',q,'kJ/kg')\n",
-      "print'%s %.4f %s'%('change in entropy of system=',S,'kJ/kg K')\n",
-      "print'%s %.4f %s'%('change in entropy of environment=',Senvir,'kJ/kg K')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "heat = 53.9 kJ/kg\n",
-        "change in entropy of system= -0.1347 kJ/kg K\n",
-        "change in entropy of environment= 0.1797 kJ/kg K\n"
-       ]
-      }
-     ],
-     "prompt_number": 7
-    }
-   ],
-   "metadata": {}
-  }
- ]
-}
-\ No newline at end of file
diff --git a/Thermodynamics:_From_concepts_to_applications/Chapter8.ipynb b/Thermodynamics:_From_concepts_to_applications/Chapter8.ipynb
deleted file mode 100755
index c1d76b67..00000000
--- a/Thermodynamics:_From_concepts_to_applications/Chapter8.ipynb
+++ /dev/null
@@ -1,309 +0,0 @@
-{
- "metadata": {
-  "name": "",
-  "signature": "sha256:8780f29f2ca7dbbe28306b63f91de121a8fdfb0cc3c24c326256cd5a0309b1ed"
- },
- "nbformat": 3,
- "nbformat_minor": 0,
- "worksheets": [
-  {
-   "cells": [
-    {
-     "cell_type": "heading",
-     "level": 1,
-     "metadata": {},
-     "source": [
-      "Chapter8-Entropy"
-     ]
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Example1 pg- 131"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "#calculate and entropy of ice and environment and universe\n",
-      "##initialisation of variables\n",
-      "m= 2 ##kg\n",
-      "dh= 333.39 ##kg/h\n",
-      "T= 0 ##C\n",
-      "T1= 20 ##C\n",
-      "##CALCULATIONS\n",
-      "Q12= m*dh\n",
-      "dS= Q12/(273.15+T)\n",
-      "dSenvir= -Q12/(273.15+T1)\n",
-      "dStotal= dS+dSenvir\n",
-      "##RESULTS\n",
-      "print'%s %.3f %s'%(' entropy of ice =',dS,'kJ/K')\n",
-      "print'%s %.3f %s'%('entropy of environment =',dSenvir,'kJ/K')\n",
-      "print'%s %.3f %s'%('entropy of universe =',dStotal,'kJ/K')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        " entropy of ice = 2.441 kJ/K\n",
-        "entropy of environment = -2.275 kJ/K\n",
-        "entropy of universe = 0.167 kJ/K\n"
-       ]
-      }
-     ],
-     "prompt_number": 1
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Example2-pg132"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "#calculate change in entropy in system and environment and entropy\n",
-      "##initialisation of variables\n",
-      "Q= 666.78 ##kJ\n",
-      "T= 0 ##C\n",
-      "Th= 20. ##C\n",
-      "##CALCULATIONS\n",
-      "Ssys= Q/(273.15+T)\n",
-      "Qh= Q*((273.15+Th)/(273.15+T))\n",
-      "Senvir= -Qh/(273.15+Th)\n",
-      "Stotal= Ssys+Senvir\n",
-      "##RESULTS\n",
-      "print'%s %.4f %s'%('change in entropy in sysytem =',Ssys,' kJ/K')\n",
-      "print'%s %.4f %s'%('change in entropy in environment =',Senvir,'kJ/K')\n",
-      "print'%s %.f %s'%('total change in entropy =',Stotal,'kJ/K')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "change in entropy in sysytem = 2.4411  kJ/K\n",
-        "change in entropy in environment = -2.4411 kJ/K\n",
-        "total change in entropy = 0 kJ/K\n"
-       ]
-      }
-     ],
-     "prompt_number": 2
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Example3-pg134\n"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "#calculate change in entropy\n",
-      "##initialisation of variables\n",
-      "S1= 6.2872 ##J/kg K\n",
-      "S2= 5.8712 ##J/kg K\n",
-      "m= 18 ##kg\n",
-      "##CALCULATIONS\n",
-      "S= m*(S1-S2)\n",
-      "##RESULTS\n",
-      "print'%s %.3f %s'%(' change in entropy =',S,'kJ/K')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        " change in entropy = 7.488 kJ/K\n"
-       ]
-      }
-     ],
-     "prompt_number": 3
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Example4-pg 134"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "#calculate change in entropy\n",
-      "##initialisation of variables\n",
-      "S2= 5.8328 ##kJ/kg\n",
-      "S1= 5.8712 ##kJ/kg\n",
-      "##CALCULATIONS\n",
-      "S= S2-S1\n",
-      "##RESULTS\n",
-      "print'%s %.5f %s'%('change in entropy = ',S,'kJ/K')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "change in entropy =  -0.03840 kJ/K\n"
-       ]
-      }
-     ],
-     "prompt_number": 5
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Example5-pg135"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "#calculate enthalpy and change in entropy\n",
-      "##initialisation of variables\n",
-      "m= 0.1 ##kg\n",
-      "p= 3 ##bar\n",
-      "p1= 10 ##bar\n",
-      "h1= 2964.3 ##kJ/kg\n",
-      "v1=0.2378\n",
-      "s2= 7.1619 ##kJ/k\n",
-      "s1= 6.9641 ##kJ/k\n",
-      "##CALCULATIONS\n",
-      "h2= h1+(p-p1)*math.pow(10,5)*v1*math.pow(10,-3)\n",
-      "S= m*(s2-s1)\n",
-      "##RESULTS\n",
-      "print'%s %.1f %s'%(' enthalpy =',h2,'kJ/kg')\n",
-      "print'%s %.5f %s'%('change in entropy =',S,'kJ/K')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        " enthalpy = 2797.8 kJ/kg\n",
-        "change in entropy = 0.01978 kJ/K\n"
-       ]
-      }
-     ],
-     "prompt_number": 4
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Example6-pg 137"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "#calculate final pressure and change in entropy\n",
-      "import math\n",
-      "##initialisation of variables\n",
-      "p1= 5. ##bar\n",
-      "V1= 0.4 ##m^2\n",
-      "V2= 1.2 ##m^3\n",
-      "R= 8.314 ##J/mol K\n",
-      "M= 28.##gms\n",
-      "T1= 80.##C\n",
-      "##CALCULATIONS\n",
-      "p2= p1*(V1/V2)\n",
-      "S= R*math.log(V2/V1)/M\n",
-      "S1= S*p1*V1*100/((R/M)*(273.15+T1))\n",
-      "##RESULTS\n",
-      "print'%s %.3f %s'%(' final pressure =',p2,'bar')\n",
-      "print'%s %.4f %s'% ('change in entropy =',S1,'kJ/kg K')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        " final pressure = 1.667 bar\n",
-        "change in entropy = 0.6222 kJ/kg K\n"
-       ]
-      }
-     ],
-     "prompt_number": 6
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Example7-pg 137"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "#calculate heat and change in entropy of system and change in entropy of enironment\n",
-      "##initialisation of variables\n",
-      "R= 8.314 ##J/mol K\n",
-      "M= 29. ##gms\n",
-      "T= 400. ##K\n",
-      "p2= 1.6 ##bar\n",
-      "p1= 1. ##bar\n",
-      "Tenvir= 300. ##K\n",
-      "##CALCULATIONS\n",
-      "q= R*T*math.log(p2/p1)/M\n",
-      "S= -R*math.log(p2/p1)/M\n",
-      "Senvir= q/Tenvir\n",
-      "##RESULTS\n",
-      "print'%s %.1f %s'%('heat =',q,'kJ/kg')\n",
-      "print'%s %.4f %s'%('change in entropy of system=',S,'kJ/kg K')\n",
-      "print'%s %.4f %s'%('change in entropy of environment=',Senvir,'kJ/kg K')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "heat = 53.9 kJ/kg\n",
-        "change in entropy of system= -0.1347 kJ/kg K\n",
-        "change in entropy of environment= 0.1797 kJ/kg K\n"
-       ]
-      }
-     ],
-     "prompt_number": 7
-    }
-   ],
-   "metadata": {}
-  }
- ]
-}
-\ No newline at end of file
diff --git a/Thermodynamics:_From_concepts_to_applications/Chapter8_1.ipynb b/Thermodynamics:_From_concepts_to_applications/Chapter8_1.ipynb
deleted file mode 100755
index c1d76b67..00000000
--- a/Thermodynamics:_From_concepts_to_applications/Chapter8_1.ipynb
+++ /dev/null
@@ -1,309 +0,0 @@
-{
- "metadata": {
-  "name": "",
-  "signature": "sha256:8780f29f2ca7dbbe28306b63f91de121a8fdfb0cc3c24c326256cd5a0309b1ed"
- },
- "nbformat": 3,
- "nbformat_minor": 0,
- "worksheets": [
-  {
-   "cells": [
-    {
-     "cell_type": "heading",
-     "level": 1,
-     "metadata": {},
-     "source": [
-      "Chapter8-Entropy"
-     ]
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Example1 pg- 131"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "#calculate and entropy of ice and environment and universe\n",
-      "##initialisation of variables\n",
-      "m= 2 ##kg\n",
-      "dh= 333.39 ##kg/h\n",
-      "T= 0 ##C\n",
-      "T1= 20 ##C\n",
-      "##CALCULATIONS\n",
-      "Q12= m*dh\n",
-      "dS= Q12/(273.15+T)\n",
-      "dSenvir= -Q12/(273.15+T1)\n",
-      "dStotal= dS+dSenvir\n",
-      "##RESULTS\n",
-      "print'%s %.3f %s'%(' entropy of ice =',dS,'kJ/K')\n",
-      "print'%s %.3f %s'%('entropy of environment =',dSenvir,'kJ/K')\n",
-      "print'%s %.3f %s'%('entropy of universe =',dStotal,'kJ/K')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        " entropy of ice = 2.441 kJ/K\n",
-        "entropy of environment = -2.275 kJ/K\n",
-        "entropy of universe = 0.167 kJ/K\n"
-       ]
-      }
-     ],
-     "prompt_number": 1
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Example2-pg132"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "#calculate change in entropy in system and environment and entropy\n",
-      "##initialisation of variables\n",
-      "Q= 666.78 ##kJ\n",
-      "T= 0 ##C\n",
-      "Th= 20. ##C\n",
-      "##CALCULATIONS\n",
-      "Ssys= Q/(273.15+T)\n",
-      "Qh= Q*((273.15+Th)/(273.15+T))\n",
-      "Senvir= -Qh/(273.15+Th)\n",
-      "Stotal= Ssys+Senvir\n",
-      "##RESULTS\n",
-      "print'%s %.4f %s'%('change in entropy in sysytem =',Ssys,' kJ/K')\n",
-      "print'%s %.4f %s'%('change in entropy in environment =',Senvir,'kJ/K')\n",
-      "print'%s %.f %s'%('total change in entropy =',Stotal,'kJ/K')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "change in entropy in sysytem = 2.4411  kJ/K\n",
-        "change in entropy in environment = -2.4411 kJ/K\n",
-        "total change in entropy = 0 kJ/K\n"
-       ]
-      }
-     ],
-     "prompt_number": 2
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Example3-pg134\n"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "#calculate change in entropy\n",
-      "##initialisation of variables\n",
-      "S1= 6.2872 ##J/kg K\n",
-      "S2= 5.8712 ##J/kg K\n",
-      "m= 18 ##kg\n",
-      "##CALCULATIONS\n",
-      "S= m*(S1-S2)\n",
-      "##RESULTS\n",
-      "print'%s %.3f %s'%(' change in entropy =',S,'kJ/K')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        " change in entropy = 7.488 kJ/K\n"
-       ]
-      }
-     ],
-     "prompt_number": 3
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Example4-pg 134"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "#calculate change in entropy\n",
-      "##initialisation of variables\n",
-      "S2= 5.8328 ##kJ/kg\n",
-      "S1= 5.8712 ##kJ/kg\n",
-      "##CALCULATIONS\n",
-      "S= S2-S1\n",
-      "##RESULTS\n",
-      "print'%s %.5f %s'%('change in entropy = ',S,'kJ/K')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "change in entropy =  -0.03840 kJ/K\n"
-       ]
-      }
-     ],
-     "prompt_number": 5
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Example5-pg135"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "#calculate enthalpy and change in entropy\n",
-      "##initialisation of variables\n",
-      "m= 0.1 ##kg\n",
-      "p= 3 ##bar\n",
-      "p1= 10 ##bar\n",
-      "h1= 2964.3 ##kJ/kg\n",
-      "v1=0.2378\n",
-      "s2= 7.1619 ##kJ/k\n",
-      "s1= 6.9641 ##kJ/k\n",
-      "##CALCULATIONS\n",
-      "h2= h1+(p-p1)*math.pow(10,5)*v1*math.pow(10,-3)\n",
-      "S= m*(s2-s1)\n",
-      "##RESULTS\n",
-      "print'%s %.1f %s'%(' enthalpy =',h2,'kJ/kg')\n",
-      "print'%s %.5f %s'%('change in entropy =',S,'kJ/K')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        " enthalpy = 2797.8 kJ/kg\n",
-        "change in entropy = 0.01978 kJ/K\n"
-       ]
-      }
-     ],
-     "prompt_number": 4
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Example6-pg 137"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "#calculate final pressure and change in entropy\n",
-      "import math\n",
-      "##initialisation of variables\n",
-      "p1= 5. ##bar\n",
-      "V1= 0.4 ##m^2\n",
-      "V2= 1.2 ##m^3\n",
-      "R= 8.314 ##J/mol K\n",
-      "M= 28.##gms\n",
-      "T1= 80.##C\n",
-      "##CALCULATIONS\n",
-      "p2= p1*(V1/V2)\n",
-      "S= R*math.log(V2/V1)/M\n",
-      "S1= S*p1*V1*100/((R/M)*(273.15+T1))\n",
-      "##RESULTS\n",
-      "print'%s %.3f %s'%(' final pressure =',p2,'bar')\n",
-      "print'%s %.4f %s'% ('change in entropy =',S1,'kJ/kg K')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        " final pressure = 1.667 bar\n",
-        "change in entropy = 0.6222 kJ/kg K\n"
-       ]
-      }
-     ],
-     "prompt_number": 6
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Example7-pg 137"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "#calculate heat and change in entropy of system and change in entropy of enironment\n",
-      "##initialisation of variables\n",
-      "R= 8.314 ##J/mol K\n",
-      "M= 29. ##gms\n",
-      "T= 400. ##K\n",
-      "p2= 1.6 ##bar\n",
-      "p1= 1. ##bar\n",
-      "Tenvir= 300. ##K\n",
-      "##CALCULATIONS\n",
-      "q= R*T*math.log(p2/p1)/M\n",
-      "S= -R*math.log(p2/p1)/M\n",
-      "Senvir= q/Tenvir\n",
-      "##RESULTS\n",
-      "print'%s %.1f %s'%('heat =',q,'kJ/kg')\n",
-      "print'%s %.4f %s'%('change in entropy of system=',S,'kJ/kg K')\n",
-      "print'%s %.4f %s'%('change in entropy of environment=',Senvir,'kJ/kg K')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "heat = 53.9 kJ/kg\n",
-        "change in entropy of system= -0.1347 kJ/kg K\n",
-        "change in entropy of environment= 0.1797 kJ/kg K\n"
-       ]
-      }
-     ],
-     "prompt_number": 7
-    }
-   ],
-   "metadata": {}
-  }
- ]
-}
-\ No newline at end of file
diff --git a/Thermodynamics:_From_concepts_to_applications/Chapter8_2.ipynb b/Thermodynamics:_From_concepts_to_applications/Chapter8_2.ipynb
deleted file mode 100755
index c1d76b67..00000000
--- a/Thermodynamics:_From_concepts_to_applications/Chapter8_2.ipynb
+++ /dev/null
@@ -1,309 +0,0 @@
-{
- "metadata": {
-  "name": "",
-  "signature": "sha256:8780f29f2ca7dbbe28306b63f91de121a8fdfb0cc3c24c326256cd5a0309b1ed"
- },
- "nbformat": 3,
- "nbformat_minor": 0,
- "worksheets": [
-  {
-   "cells": [
-    {
-     "cell_type": "heading",
-     "level": 1,
-     "metadata": {},
-     "source": [
-      "Chapter8-Entropy"
-     ]
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Example1 pg- 131"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "#calculate and entropy of ice and environment and universe\n",
-      "##initialisation of variables\n",
-      "m= 2 ##kg\n",
-      "dh= 333.39 ##kg/h\n",
-      "T= 0 ##C\n",
-      "T1= 20 ##C\n",
-      "##CALCULATIONS\n",
-      "Q12= m*dh\n",
-      "dS= Q12/(273.15+T)\n",
-      "dSenvir= -Q12/(273.15+T1)\n",
-      "dStotal= dS+dSenvir\n",
-      "##RESULTS\n",
-      "print'%s %.3f %s'%(' entropy of ice =',dS,'kJ/K')\n",
-      "print'%s %.3f %s'%('entropy of environment =',dSenvir,'kJ/K')\n",
-      "print'%s %.3f %s'%('entropy of universe =',dStotal,'kJ/K')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        " entropy of ice = 2.441 kJ/K\n",
-        "entropy of environment = -2.275 kJ/K\n",
-        "entropy of universe = 0.167 kJ/K\n"
-       ]
-      }
-     ],
-     "prompt_number": 1
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Example2-pg132"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "#calculate change in entropy in system and environment and entropy\n",
-      "##initialisation of variables\n",
-      "Q= 666.78 ##kJ\n",
-      "T= 0 ##C\n",
-      "Th= 20. ##C\n",
-      "##CALCULATIONS\n",
-      "Ssys= Q/(273.15+T)\n",
-      "Qh= Q*((273.15+Th)/(273.15+T))\n",
-      "Senvir= -Qh/(273.15+Th)\n",
-      "Stotal= Ssys+Senvir\n",
-      "##RESULTS\n",
-      "print'%s %.4f %s'%('change in entropy in sysytem =',Ssys,' kJ/K')\n",
-      "print'%s %.4f %s'%('change in entropy in environment =',Senvir,'kJ/K')\n",
-      "print'%s %.f %s'%('total change in entropy =',Stotal,'kJ/K')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "change in entropy in sysytem = 2.4411  kJ/K\n",
-        "change in entropy in environment = -2.4411 kJ/K\n",
-        "total change in entropy = 0 kJ/K\n"
-       ]
-      }
-     ],
-     "prompt_number": 2
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Example3-pg134\n"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "#calculate change in entropy\n",
-      "##initialisation of variables\n",
-      "S1= 6.2872 ##J/kg K\n",
-      "S2= 5.8712 ##J/kg K\n",
-      "m= 18 ##kg\n",
-      "##CALCULATIONS\n",
-      "S= m*(S1-S2)\n",
-      "##RESULTS\n",
-      "print'%s %.3f %s'%(' change in entropy =',S,'kJ/K')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        " change in entropy = 7.488 kJ/K\n"
-       ]
-      }
-     ],
-     "prompt_number": 3
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Example4-pg 134"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "#calculate change in entropy\n",
-      "##initialisation of variables\n",
-      "S2= 5.8328 ##kJ/kg\n",
-      "S1= 5.8712 ##kJ/kg\n",
-      "##CALCULATIONS\n",
-      "S= S2-S1\n",
-      "##RESULTS\n",
-      "print'%s %.5f %s'%('change in entropy = ',S,'kJ/K')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "change in entropy =  -0.03840 kJ/K\n"
-       ]
-      }
-     ],
-     "prompt_number": 5
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Example5-pg135"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "#calculate enthalpy and change in entropy\n",
-      "##initialisation of variables\n",
-      "m= 0.1 ##kg\n",
-      "p= 3 ##bar\n",
-      "p1= 10 ##bar\n",
-      "h1= 2964.3 ##kJ/kg\n",
-      "v1=0.2378\n",
-      "s2= 7.1619 ##kJ/k\n",
-      "s1= 6.9641 ##kJ/k\n",
-      "##CALCULATIONS\n",
-      "h2= h1+(p-p1)*math.pow(10,5)*v1*math.pow(10,-3)\n",
-      "S= m*(s2-s1)\n",
-      "##RESULTS\n",
-      "print'%s %.1f %s'%(' enthalpy =',h2,'kJ/kg')\n",
-      "print'%s %.5f %s'%('change in entropy =',S,'kJ/K')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        " enthalpy = 2797.8 kJ/kg\n",
-        "change in entropy = 0.01978 kJ/K\n"
-       ]
-      }
-     ],
-     "prompt_number": 4
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Example6-pg 137"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "#calculate final pressure and change in entropy\n",
-      "import math\n",
-      "##initialisation of variables\n",
-      "p1= 5. ##bar\n",
-      "V1= 0.4 ##m^2\n",
-      "V2= 1.2 ##m^3\n",
-      "R= 8.314 ##J/mol K\n",
-      "M= 28.##gms\n",
-      "T1= 80.##C\n",
-      "##CALCULATIONS\n",
-      "p2= p1*(V1/V2)\n",
-      "S= R*math.log(V2/V1)/M\n",
-      "S1= S*p1*V1*100/((R/M)*(273.15+T1))\n",
-      "##RESULTS\n",
-      "print'%s %.3f %s'%(' final pressure =',p2,'bar')\n",
-      "print'%s %.4f %s'% ('change in entropy =',S1,'kJ/kg K')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        " final pressure = 1.667 bar\n",
-        "change in entropy = 0.6222 kJ/kg K\n"
-       ]
-      }
-     ],
-     "prompt_number": 6
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Example7-pg 137"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "#calculate heat and change in entropy of system and change in entropy of enironment\n",
-      "##initialisation of variables\n",
-      "R= 8.314 ##J/mol K\n",
-      "M= 29. ##gms\n",
-      "T= 400. ##K\n",
-      "p2= 1.6 ##bar\n",
-      "p1= 1. ##bar\n",
-      "Tenvir= 300. ##K\n",
-      "##CALCULATIONS\n",
-      "q= R*T*math.log(p2/p1)/M\n",
-      "S= -R*math.log(p2/p1)/M\n",
-      "Senvir= q/Tenvir\n",
-      "##RESULTS\n",
-      "print'%s %.1f %s'%('heat =',q,'kJ/kg')\n",
-      "print'%s %.4f %s'%('change in entropy of system=',S,'kJ/kg K')\n",
-      "print'%s %.4f %s'%('change in entropy of environment=',Senvir,'kJ/kg K')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "heat = 53.9 kJ/kg\n",
-        "change in entropy of system= -0.1347 kJ/kg K\n",
-        "change in entropy of environment= 0.1797 kJ/kg K\n"
-       ]
-      }
-     ],
-     "prompt_number": 7
-    }
-   ],
-   "metadata": {}
-  }
- ]
-}
-\ No newline at end of file
diff --git a/Thermodynamics:_From_concepts_to_applications/Chapter9-Applications_of_the_second_law_of_thermodynamics.ipynb b/Thermodynamics:_From_concepts_to_applications/Chapter9-Applications_of_the_second_law_of_thermodynamics.ipynb
deleted file mode 100755
index f2acb74e..00000000
--- a/Thermodynamics:_From_concepts_to_applications/Chapter9-Applications_of_the_second_law_of_thermodynamics.ipynb
+++ /dev/null
@@ -1,473 +0,0 @@
-{
- "metadata": {
-  "name": "",
-  "signature": "sha256:15fd1db156f91825255a086dbc12ea12cb6caac30db6feed49ee7e31d29fef8c"
- },
- "nbformat": 3,
- "nbformat_minor": 0,
- "worksheets": [
-  {
-   "cells": [
-    {
-     "cell_type": "heading",
-     "level": 1,
-     "metadata": {},
-     "source": [
-      "Chapter9-Applications of the second law of thermodynamics"
-     ]
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Example1-pg 152"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "#calculate final temperatures and total entropy\n",
-      "##changeinitialisation of variables\n",
-      "p1= 3.##changeMpa\n",
-      "p2= 0.2 ##changeMpa\n",
-      "V1= 0.6 ##changem^3\n",
-      "V2= 1.##changem^3\n",
-      "M= 28. ##changegms\n",
-      "R= 8.314 ##changeJ/mol K\n",
-      "T= 400. ##changeC\n",
-      "T1= 150. ##changeC\n",
-      "k= 1.4\n",
-      "p3= 1.25 ##changeMpa\n",
-      "##changeCALCULATIONS\n",
-      "m1= p1*V1*10*10*10*M/(R*(273.15+T))\n",
-      "m2= p2*V2*10*10*10*M/(R*(273.15+T1))\n",
-      "p4= (p1*V1+p2*V2)/(V1+V2)\n",
-      "T2= (math.pow(p4/p1,k-1)/k)*(273.15+T)\n",
-      "m3= p3*V1*M*10*10*10/(R*T2)\n",
-      "dm= m1-m3\n",
-      "m4= m2+dm\n",
-      "T4= p3*10*10*10*V2/((R/M)*m4)\n",
-      "S= (R/M)*(m2*((k/(k-1))*math.log(T4/(273.15+T1))-math.log(p3/p2))+dm*((k/(k-1))*math.log(T4/(273.15+T))-math.log(p3/p1)))\n",
-      "##changeRESULTS\n",
-      "print'%s %.1f %s'%('final temperature =',T2,'K')\n",
-      "print'%s %.1f %s'%('final temperature =',T4,'K')\n",
-      "print'%s %.4f %s'%('Total entropy =',S,'KJ/K')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "final temperature = 338.8 K\n",
-        "final temperature = 1340.2 K\n",
-        "Total entropy = 2.5525 KJ/K\n"
-       ]
-      }
-     ],
-     "prompt_number": 10
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Example2-pg156"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "#calculate work of the pump\n",
-      "##initialisation of variables\n",
-      "m= 10000 ##kg/h\n",
-      "P= 2.5 ##Mpa\n",
-      "P1= 100 ##kPa\n",
-      "v= 0.001003 ##m^3\n",
-      "##CALCULATIONS\n",
-      "W= -m*v*(P*10*10*10-P1)/3600\n",
-      "##RESULTS\n",
-      "print'%s %.3f %s'%(' work of the pump =',W,'kW')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        " work of the pump = -6.687 kW\n"
-       ]
-      }
-     ],
-     "prompt_number": 9
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Example3-pg 158"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "##initialisation of variables\n",
-      "m= 4. ##kg/s\n",
-      "R= 8.314 ##J/mol K\n",
-      "M= 29. ##gms\n",
-      "k= 1.4\n",
-      "T1= 27. ##C\n",
-      "p2= 1800. ##kPa\n",
-      "p1= 105. ##kPa\n",
-      "n= 1.22\n",
-      "cp= 1.4 ##Jmol K\n",
-      "##CALCULATIONS\n",
-      "T2= (273.15+T1)*(p2/p1)**((n-1)/n)\n",
-      "W= m*k*(R/M)*((273.15+T1)/(k-1))*(1-(p2/p1)**((k-1)/k))\n",
-      "Q= -m*R*(273.15+T1)*math.log(p2/p1)/M\n",
-      "W1= m*(R/M)*n*((273.15+T1)/(n-1))*(1-(p2/p1)**((n-1)/n))\n",
-      "Q1= m*(R/M)*(n-k)*(T2-T1-273.15)/((n-1)*(k-1))\n",
-      "T3= (273.15+T1)*(p2/p1)**((k-1)/(2*k))\n",
-      "Q2= m*cp*(R/M)*(T1+273.15-T3)/(k-1)\n",
-      "##RESULTS\n",
-      "print'%s %.1f %s'%('heat removed in adiabatic compression =',W,'kW')\n",
-      "print'%s %.1f %s'%('heat removed in isothermal compression =',Q,'kW')\n",
-      "print'%s %.1f %s'%('heat removed in polytropic process =',Q1,'kW')\n",
-      "print'%s %.2f %s'%('heat removed in adiabatic compression in two stages =',Q2,'kW')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "heat removed in adiabatic compression = -1508.5 kW\n",
-        "heat removed in isothermal compression = -978.1 kW\n",
-        "heat removed in polytropic process = -471.2 kW\n",
-        "heat removed in adiabatic compression in two stages = -603.21 kW\n"
-       ]
-      }
-     ],
-     "prompt_number": 8
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Example4-pg 161"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "#calculate enthalpy and entropy\n",
-      "##initialisation of variables\n",
-      "h1= 3422.25 ##kJ/kg\n",
-      "m= 8. ##kg/s\n",
-      "s2= 7.3755 ##kJ/kg K\n",
-      "s1= 6.8803 ##kJ/kg K\n",
-      "e= 0.8\n",
-      "h2s= 2496.8 ##kJ/kg\n",
-      "##CALCULATIONS\n",
-      "h2= h1+e*(h2s-h1)\n",
-      "W= m*(h1-h2)\n",
-      "S= s2-s1\n",
-      "##RESULTS\n",
-      "print'%s %.1f %s'%('Enthalpy  =',W,'kW')\n",
-      "print'%s %.4f %s'% ('Entropy =',S,'kJ/kg K')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "Enthalpy  = 5922.9 kW\n",
-        "Entropy = 0.4952 kJ/kg K\n"
-       ]
-      }
-     ],
-     "prompt_number": 7
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Example5-pg162"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "calculate volume flow rate into composser and volume flow rate out composser and heat and work \n",
-      "##initialisation of variables\n",
-      "m= 0.2 ##kg/s\n",
-      "v1= 1.0803 ##m^3/kg\n",
-      "T= 200 ##C\n",
-      "s2= 5.8041 ##kJ/kg K\n",
-      "s1= 7.5066 ##kJ/kg K\n",
-      "h1= 2328.1 ##kJ/kg\n",
-      "h2= 2654.4 ##kJ/kg\n",
-      "##CALCULATIONS\n",
-      "V1= m*v1\n",
-      "V2= 0.1*V1\n",
-      "Q= m*(273.15+T)*(s2-s1)\n",
-      "W= Q-m*(h1-h2)\n",
-      "##RESULTS\n",
-      "print'%s %.4f %s'%('volume flow rate into composser =',V1,'m^3')\n",
-      "print'%s %.4f %s'%('volume flow rate out of composser  =',V2,'m^3')\n",
-      "print'%s %.1f %s'%('Heat  =',Q,'kJ')\n",
-      "print'%s %.1f %s'%(' Work  =',W,'kJ')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "volume flow rate into composser = 0.2161 m^3\n",
-        "volume flow rate out of composser  = 0.0216 m^3\n",
-        "Heat  = -161.1 kJ\n",
-        " Work  = -95.8 kJ\n"
-       ]
-      }
-     ],
-     "prompt_number": 6
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Example6-pg164"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "#calculate volume flow rate out and into the composser and work and heat\n",
-      "##initialisation of variables\n",
-      "m1= 0.2 ##kg/s\n",
-      "v1= 1.0803 ##m^3/kg\n",
-      "P= 200 ##kPa\n",
-      "T= 200 ##C\n",
-      "s1= 5.8041 ##kJ.kg K\n",
-      "s2= 7.5066 ##kJ/kg K\n",
-      "h1= 2870.5 ##kJ/kg\n",
-      "h2= 2495.9 ##kJ/kg\n",
-      "##CALCULATIONS\n",
-      "V1= m1*v1\n",
-      "V2= 0.1*V1\n",
-      "Q= m1*(273.15+T)*(s1-s2)\n",
-      "W= m1*((h1-h2)-(273.15+T)*(s2-s1))\n",
-      "##RESULTS\n",
-      "print'%s %.4f %s'% ('volume flow rate into composser =',V1,'m^3/s')\n",
-      "print'%s %.4f %s'%('volume flow rate out of composser  =',V2,'m^3/s') \n",
-      "print'%s %.1f %s'%('Work  =',W,'kW')\n",
-      "print'%s %.1f %s'%('Heat  =',Q,'kW')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "volume flow rate into composser = 0.2161 m^3/s\n",
-        "volume flow rate out of composser  = 0.0216 m^3/s\n",
-        "Work  = -86.2 kW\n",
-        "Heat  = -161.1 kW\n"
-       ]
-      }
-     ],
-     "prompt_number": 5
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Example7-pg166"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "#calculate rate of transfer\n",
-      "##initialisation of variables\n",
-      "e= 0.82\n",
-      "m= 5 ##kg/s\n",
-      "T3= 450 ##C\n",
-      "T1= 200 ##C\n",
-      "##CALCULATIONS\n",
-      "Q= e*m*1.0035*(T3-T1)\n",
-      "##RESULTS\n",
-      "print'%s %.1f %s'%('rate of transfer =',Q,'kW')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "rate of transfer = 1028.6 kW\n"
-       ]
-      }
-     ],
-     "prompt_number": 4
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Example8-pg 166"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "#calculate heat at given enthalpy\n",
-      "##initialisation of variables\n",
-      "h1= 174.076 ##kJ/kg\n",
-      "h3= 74.527 ##kJ/kg\n",
-      "h4= 8.854 ##kJ/kg\n",
-      "m= 0.8 ##kg\n",
-      "e= 0.85\n",
-      "##CALCULATIONS\n",
-      "h2= h1+h3-h4\n",
-      "Q= m*(h2-h1-23)\n",
-      "Q1= e*Q\n",
-      "##RESULTS\n",
-      "print'%s %.2f %s'%('Heat =',Q,'kW')\n",
-      "print'%s %.2f %s'%('Heat =',Q1,'kW')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "Heat = 34.14 kW\n",
-        "Heat = 29.02 kW\n"
-       ]
-      }
-     ],
-     "prompt_number": 3
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Example9-pg 167"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "#calculate enthalpy and entropy change\n",
-      "##initialisation of variables\n",
-      "W= 2000. ##kW\n",
-      "m= 2. ##kg/s\n",
-      "h1= 3023.5 ##kJ/kg\n",
-      "s2= 5.6106 ##kJ/kg K\n",
-      "s1= 6.7664 ##kJ/kg K\n",
-      "##CALCULATIONS\n",
-      "h2= h1-(W/m)\n",
-      "S=s2-s1\n",
-      "##RESULTS\n",
-      "print'%s %.1f %s'% ('enthalpy =',h2,'kJ/kg')\n",
-      "print'%s %.4f %s'%('entropy change =',S,'kJ/kg K')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "enthalpy = 2023.5 kJ/kg\n",
-        "entropy change = -1.1558 kJ/kg K\n"
-       ]
-      }
-     ],
-     "prompt_number": 2
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Example10-pg 168"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "#calculate enthalpy and entropy change\n",
-      "##initialisation of variables\n",
-      "m1= 1 ##kg\n",
-      "h1= 2967.6 ##kJ/kg\n",
-      "h2= 83.96 ##kJ/kg\n",
-      "m2= 10\n",
-      "s1= 7.5166 ##kJ/kg K\n",
-      "s2= 0.2966 ##kJ/kg K\n",
-      "s3= 1.1654 ##kJ/kg K\n",
-      "##CALCULATIONS\n",
-      "h3= (m1*h1+m2*h2)/(m1+m2)\n",
-      "S= -m1*s1-m2*s2+(m1+m2)*s3\n",
-      "##RESULTS\n",
-      "print'%s %.1f %s'% ('enthalpy =',h3,'kJ/kg')\n",
-      "print'%s %.4f %s'%('entropy change =',S,'kJ/kg K')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "enthalpy = 346.1 kJ/kg\n",
-        "entropy change = 2.3368 kJ/kg K\n"
-       ]
-      }
-     ],
-     "prompt_number": 1
-    }
-   ],
-   "metadata": {}
-  }
- ]
-}
-\ No newline at end of file
diff --git a/Thermodynamics:_From_concepts_to_applications/Chapter9.ipynb b/Thermodynamics:_From_concepts_to_applications/Chapter9.ipynb
deleted file mode 100755
index f2acb74e..00000000
--- a/Thermodynamics:_From_concepts_to_applications/Chapter9.ipynb
+++ /dev/null
@@ -1,473 +0,0 @@
-{
- "metadata": {
-  "name": "",
-  "signature": "sha256:15fd1db156f91825255a086dbc12ea12cb6caac30db6feed49ee7e31d29fef8c"
- },
- "nbformat": 3,
- "nbformat_minor": 0,
- "worksheets": [
-  {
-   "cells": [
-    {
-     "cell_type": "heading",
-     "level": 1,
-     "metadata": {},
-     "source": [
-      "Chapter9-Applications of the second law of thermodynamics"
-     ]
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Example1-pg 152"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "#calculate final temperatures and total entropy\n",
-      "##changeinitialisation of variables\n",
-      "p1= 3.##changeMpa\n",
-      "p2= 0.2 ##changeMpa\n",
-      "V1= 0.6 ##changem^3\n",
-      "V2= 1.##changem^3\n",
-      "M= 28. ##changegms\n",
-      "R= 8.314 ##changeJ/mol K\n",
-      "T= 400. ##changeC\n",
-      "T1= 150. ##changeC\n",
-      "k= 1.4\n",
-      "p3= 1.25 ##changeMpa\n",
-      "##changeCALCULATIONS\n",
-      "m1= p1*V1*10*10*10*M/(R*(273.15+T))\n",
-      "m2= p2*V2*10*10*10*M/(R*(273.15+T1))\n",
-      "p4= (p1*V1+p2*V2)/(V1+V2)\n",
-      "T2= (math.pow(p4/p1,k-1)/k)*(273.15+T)\n",
-      "m3= p3*V1*M*10*10*10/(R*T2)\n",
-      "dm= m1-m3\n",
-      "m4= m2+dm\n",
-      "T4= p3*10*10*10*V2/((R/M)*m4)\n",
-      "S= (R/M)*(m2*((k/(k-1))*math.log(T4/(273.15+T1))-math.log(p3/p2))+dm*((k/(k-1))*math.log(T4/(273.15+T))-math.log(p3/p1)))\n",
-      "##changeRESULTS\n",
-      "print'%s %.1f %s'%('final temperature =',T2,'K')\n",
-      "print'%s %.1f %s'%('final temperature =',T4,'K')\n",
-      "print'%s %.4f %s'%('Total entropy =',S,'KJ/K')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "final temperature = 338.8 K\n",
-        "final temperature = 1340.2 K\n",
-        "Total entropy = 2.5525 KJ/K\n"
-       ]
-      }
-     ],
-     "prompt_number": 10
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Example2-pg156"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "#calculate work of the pump\n",
-      "##initialisation of variables\n",
-      "m= 10000 ##kg/h\n",
-      "P= 2.5 ##Mpa\n",
-      "P1= 100 ##kPa\n",
-      "v= 0.001003 ##m^3\n",
-      "##CALCULATIONS\n",
-      "W= -m*v*(P*10*10*10-P1)/3600\n",
-      "##RESULTS\n",
-      "print'%s %.3f %s'%(' work of the pump =',W,'kW')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        " work of the pump = -6.687 kW\n"
-       ]
-      }
-     ],
-     "prompt_number": 9
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Example3-pg 158"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "##initialisation of variables\n",
-      "m= 4. ##kg/s\n",
-      "R= 8.314 ##J/mol K\n",
-      "M= 29. ##gms\n",
-      "k= 1.4\n",
-      "T1= 27. ##C\n",
-      "p2= 1800. ##kPa\n",
-      "p1= 105. ##kPa\n",
-      "n= 1.22\n",
-      "cp= 1.4 ##Jmol K\n",
-      "##CALCULATIONS\n",
-      "T2= (273.15+T1)*(p2/p1)**((n-1)/n)\n",
-      "W= m*k*(R/M)*((273.15+T1)/(k-1))*(1-(p2/p1)**((k-1)/k))\n",
-      "Q= -m*R*(273.15+T1)*math.log(p2/p1)/M\n",
-      "W1= m*(R/M)*n*((273.15+T1)/(n-1))*(1-(p2/p1)**((n-1)/n))\n",
-      "Q1= m*(R/M)*(n-k)*(T2-T1-273.15)/((n-1)*(k-1))\n",
-      "T3= (273.15+T1)*(p2/p1)**((k-1)/(2*k))\n",
-      "Q2= m*cp*(R/M)*(T1+273.15-T3)/(k-1)\n",
-      "##RESULTS\n",
-      "print'%s %.1f %s'%('heat removed in adiabatic compression =',W,'kW')\n",
-      "print'%s %.1f %s'%('heat removed in isothermal compression =',Q,'kW')\n",
-      "print'%s %.1f %s'%('heat removed in polytropic process =',Q1,'kW')\n",
-      "print'%s %.2f %s'%('heat removed in adiabatic compression in two stages =',Q2,'kW')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "heat removed in adiabatic compression = -1508.5 kW\n",
-        "heat removed in isothermal compression = -978.1 kW\n",
-        "heat removed in polytropic process = -471.2 kW\n",
-        "heat removed in adiabatic compression in two stages = -603.21 kW\n"
-       ]
-      }
-     ],
-     "prompt_number": 8
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Example4-pg 161"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "#calculate enthalpy and entropy\n",
-      "##initialisation of variables\n",
-      "h1= 3422.25 ##kJ/kg\n",
-      "m= 8. ##kg/s\n",
-      "s2= 7.3755 ##kJ/kg K\n",
-      "s1= 6.8803 ##kJ/kg K\n",
-      "e= 0.8\n",
-      "h2s= 2496.8 ##kJ/kg\n",
-      "##CALCULATIONS\n",
-      "h2= h1+e*(h2s-h1)\n",
-      "W= m*(h1-h2)\n",
-      "S= s2-s1\n",
-      "##RESULTS\n",
-      "print'%s %.1f %s'%('Enthalpy  =',W,'kW')\n",
-      "print'%s %.4f %s'% ('Entropy =',S,'kJ/kg K')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "Enthalpy  = 5922.9 kW\n",
-        "Entropy = 0.4952 kJ/kg K\n"
-       ]
-      }
-     ],
-     "prompt_number": 7
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Example5-pg162"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "calculate volume flow rate into composser and volume flow rate out composser and heat and work \n",
-      "##initialisation of variables\n",
-      "m= 0.2 ##kg/s\n",
-      "v1= 1.0803 ##m^3/kg\n",
-      "T= 200 ##C\n",
-      "s2= 5.8041 ##kJ/kg K\n",
-      "s1= 7.5066 ##kJ/kg K\n",
-      "h1= 2328.1 ##kJ/kg\n",
-      "h2= 2654.4 ##kJ/kg\n",
-      "##CALCULATIONS\n",
-      "V1= m*v1\n",
-      "V2= 0.1*V1\n",
-      "Q= m*(273.15+T)*(s2-s1)\n",
-      "W= Q-m*(h1-h2)\n",
-      "##RESULTS\n",
-      "print'%s %.4f %s'%('volume flow rate into composser =',V1,'m^3')\n",
-      "print'%s %.4f %s'%('volume flow rate out of composser  =',V2,'m^3')\n",
-      "print'%s %.1f %s'%('Heat  =',Q,'kJ')\n",
-      "print'%s %.1f %s'%(' Work  =',W,'kJ')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "volume flow rate into composser = 0.2161 m^3\n",
-        "volume flow rate out of composser  = 0.0216 m^3\n",
-        "Heat  = -161.1 kJ\n",
-        " Work  = -95.8 kJ\n"
-       ]
-      }
-     ],
-     "prompt_number": 6
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Example6-pg164"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "#calculate volume flow rate out and into the composser and work and heat\n",
-      "##initialisation of variables\n",
-      "m1= 0.2 ##kg/s\n",
-      "v1= 1.0803 ##m^3/kg\n",
-      "P= 200 ##kPa\n",
-      "T= 200 ##C\n",
-      "s1= 5.8041 ##kJ.kg K\n",
-      "s2= 7.5066 ##kJ/kg K\n",
-      "h1= 2870.5 ##kJ/kg\n",
-      "h2= 2495.9 ##kJ/kg\n",
-      "##CALCULATIONS\n",
-      "V1= m1*v1\n",
-      "V2= 0.1*V1\n",
-      "Q= m1*(273.15+T)*(s1-s2)\n",
-      "W= m1*((h1-h2)-(273.15+T)*(s2-s1))\n",
-      "##RESULTS\n",
-      "print'%s %.4f %s'% ('volume flow rate into composser =',V1,'m^3/s')\n",
-      "print'%s %.4f %s'%('volume flow rate out of composser  =',V2,'m^3/s') \n",
-      "print'%s %.1f %s'%('Work  =',W,'kW')\n",
-      "print'%s %.1f %s'%('Heat  =',Q,'kW')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "volume flow rate into composser = 0.2161 m^3/s\n",
-        "volume flow rate out of composser  = 0.0216 m^3/s\n",
-        "Work  = -86.2 kW\n",
-        "Heat  = -161.1 kW\n"
-       ]
-      }
-     ],
-     "prompt_number": 5
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Example7-pg166"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "#calculate rate of transfer\n",
-      "##initialisation of variables\n",
-      "e= 0.82\n",
-      "m= 5 ##kg/s\n",
-      "T3= 450 ##C\n",
-      "T1= 200 ##C\n",
-      "##CALCULATIONS\n",
-      "Q= e*m*1.0035*(T3-T1)\n",
-      "##RESULTS\n",
-      "print'%s %.1f %s'%('rate of transfer =',Q,'kW')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "rate of transfer = 1028.6 kW\n"
-       ]
-      }
-     ],
-     "prompt_number": 4
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Example8-pg 166"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "#calculate heat at given enthalpy\n",
-      "##initialisation of variables\n",
-      "h1= 174.076 ##kJ/kg\n",
-      "h3= 74.527 ##kJ/kg\n",
-      "h4= 8.854 ##kJ/kg\n",
-      "m= 0.8 ##kg\n",
-      "e= 0.85\n",
-      "##CALCULATIONS\n",
-      "h2= h1+h3-h4\n",
-      "Q= m*(h2-h1-23)\n",
-      "Q1= e*Q\n",
-      "##RESULTS\n",
-      "print'%s %.2f %s'%('Heat =',Q,'kW')\n",
-      "print'%s %.2f %s'%('Heat =',Q1,'kW')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "Heat = 34.14 kW\n",
-        "Heat = 29.02 kW\n"
-       ]
-      }
-     ],
-     "prompt_number": 3
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Example9-pg 167"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "#calculate enthalpy and entropy change\n",
-      "##initialisation of variables\n",
-      "W= 2000. ##kW\n",
-      "m= 2. ##kg/s\n",
-      "h1= 3023.5 ##kJ/kg\n",
-      "s2= 5.6106 ##kJ/kg K\n",
-      "s1= 6.7664 ##kJ/kg K\n",
-      "##CALCULATIONS\n",
-      "h2= h1-(W/m)\n",
-      "S=s2-s1\n",
-      "##RESULTS\n",
-      "print'%s %.1f %s'% ('enthalpy =',h2,'kJ/kg')\n",
-      "print'%s %.4f %s'%('entropy change =',S,'kJ/kg K')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "enthalpy = 2023.5 kJ/kg\n",
-        "entropy change = -1.1558 kJ/kg K\n"
-       ]
-      }
-     ],
-     "prompt_number": 2
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Example10-pg 168"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "#calculate enthalpy and entropy change\n",
-      "##initialisation of variables\n",
-      "m1= 1 ##kg\n",
-      "h1= 2967.6 ##kJ/kg\n",
-      "h2= 83.96 ##kJ/kg\n",
-      "m2= 10\n",
-      "s1= 7.5166 ##kJ/kg K\n",
-      "s2= 0.2966 ##kJ/kg K\n",
-      "s3= 1.1654 ##kJ/kg K\n",
-      "##CALCULATIONS\n",
-      "h3= (m1*h1+m2*h2)/(m1+m2)\n",
-      "S= -m1*s1-m2*s2+(m1+m2)*s3\n",
-      "##RESULTS\n",
-      "print'%s %.1f %s'% ('enthalpy =',h3,'kJ/kg')\n",
-      "print'%s %.4f %s'%('entropy change =',S,'kJ/kg K')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "enthalpy = 346.1 kJ/kg\n",
-        "entropy change = 2.3368 kJ/kg K\n"
-       ]
-      }
-     ],
-     "prompt_number": 1
-    }
-   ],
-   "metadata": {}
-  }
- ]
-}
-\ No newline at end of file
diff --git a/Thermodynamics:_From_concepts_to_applications/Chapter9_1.ipynb b/Thermodynamics:_From_concepts_to_applications/Chapter9_1.ipynb
deleted file mode 100755
index f2acb74e..00000000
--- a/Thermodynamics:_From_concepts_to_applications/Chapter9_1.ipynb
+++ /dev/null
@@ -1,473 +0,0 @@
-{
- "metadata": {
-  "name": "",
-  "signature": "sha256:15fd1db156f91825255a086dbc12ea12cb6caac30db6feed49ee7e31d29fef8c"
- },
- "nbformat": 3,
- "nbformat_minor": 0,
- "worksheets": [
-  {
-   "cells": [
-    {
-     "cell_type": "heading",
-     "level": 1,
-     "metadata": {},
-     "source": [
-      "Chapter9-Applications of the second law of thermodynamics"
-     ]
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Example1-pg 152"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "#calculate final temperatures and total entropy\n",
-      "##changeinitialisation of variables\n",
-      "p1= 3.##changeMpa\n",
-      "p2= 0.2 ##changeMpa\n",
-      "V1= 0.6 ##changem^3\n",
-      "V2= 1.##changem^3\n",
-      "M= 28. ##changegms\n",
-      "R= 8.314 ##changeJ/mol K\n",
-      "T= 400. ##changeC\n",
-      "T1= 150. ##changeC\n",
-      "k= 1.4\n",
-      "p3= 1.25 ##changeMpa\n",
-      "##changeCALCULATIONS\n",
-      "m1= p1*V1*10*10*10*M/(R*(273.15+T))\n",
-      "m2= p2*V2*10*10*10*M/(R*(273.15+T1))\n",
-      "p4= (p1*V1+p2*V2)/(V1+V2)\n",
-      "T2= (math.pow(p4/p1,k-1)/k)*(273.15+T)\n",
-      "m3= p3*V1*M*10*10*10/(R*T2)\n",
-      "dm= m1-m3\n",
-      "m4= m2+dm\n",
-      "T4= p3*10*10*10*V2/((R/M)*m4)\n",
-      "S= (R/M)*(m2*((k/(k-1))*math.log(T4/(273.15+T1))-math.log(p3/p2))+dm*((k/(k-1))*math.log(T4/(273.15+T))-math.log(p3/p1)))\n",
-      "##changeRESULTS\n",
-      "print'%s %.1f %s'%('final temperature =',T2,'K')\n",
-      "print'%s %.1f %s'%('final temperature =',T4,'K')\n",
-      "print'%s %.4f %s'%('Total entropy =',S,'KJ/K')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "final temperature = 338.8 K\n",
-        "final temperature = 1340.2 K\n",
-        "Total entropy = 2.5525 KJ/K\n"
-       ]
-      }
-     ],
-     "prompt_number": 10
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Example2-pg156"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "#calculate work of the pump\n",
-      "##initialisation of variables\n",
-      "m= 10000 ##kg/h\n",
-      "P= 2.5 ##Mpa\n",
-      "P1= 100 ##kPa\n",
-      "v= 0.001003 ##m^3\n",
-      "##CALCULATIONS\n",
-      "W= -m*v*(P*10*10*10-P1)/3600\n",
-      "##RESULTS\n",
-      "print'%s %.3f %s'%(' work of the pump =',W,'kW')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        " work of the pump = -6.687 kW\n"
-       ]
-      }
-     ],
-     "prompt_number": 9
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Example3-pg 158"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "##initialisation of variables\n",
-      "m= 4. ##kg/s\n",
-      "R= 8.314 ##J/mol K\n",
-      "M= 29. ##gms\n",
-      "k= 1.4\n",
-      "T1= 27. ##C\n",
-      "p2= 1800. ##kPa\n",
-      "p1= 105. ##kPa\n",
-      "n= 1.22\n",
-      "cp= 1.4 ##Jmol K\n",
-      "##CALCULATIONS\n",
-      "T2= (273.15+T1)*(p2/p1)**((n-1)/n)\n",
-      "W= m*k*(R/M)*((273.15+T1)/(k-1))*(1-(p2/p1)**((k-1)/k))\n",
-      "Q= -m*R*(273.15+T1)*math.log(p2/p1)/M\n",
-      "W1= m*(R/M)*n*((273.15+T1)/(n-1))*(1-(p2/p1)**((n-1)/n))\n",
-      "Q1= m*(R/M)*(n-k)*(T2-T1-273.15)/((n-1)*(k-1))\n",
-      "T3= (273.15+T1)*(p2/p1)**((k-1)/(2*k))\n",
-      "Q2= m*cp*(R/M)*(T1+273.15-T3)/(k-1)\n",
-      "##RESULTS\n",
-      "print'%s %.1f %s'%('heat removed in adiabatic compression =',W,'kW')\n",
-      "print'%s %.1f %s'%('heat removed in isothermal compression =',Q,'kW')\n",
-      "print'%s %.1f %s'%('heat removed in polytropic process =',Q1,'kW')\n",
-      "print'%s %.2f %s'%('heat removed in adiabatic compression in two stages =',Q2,'kW')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "heat removed in adiabatic compression = -1508.5 kW\n",
-        "heat removed in isothermal compression = -978.1 kW\n",
-        "heat removed in polytropic process = -471.2 kW\n",
-        "heat removed in adiabatic compression in two stages = -603.21 kW\n"
-       ]
-      }
-     ],
-     "prompt_number": 8
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Example4-pg 161"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "#calculate enthalpy and entropy\n",
-      "##initialisation of variables\n",
-      "h1= 3422.25 ##kJ/kg\n",
-      "m= 8. ##kg/s\n",
-      "s2= 7.3755 ##kJ/kg K\n",
-      "s1= 6.8803 ##kJ/kg K\n",
-      "e= 0.8\n",
-      "h2s= 2496.8 ##kJ/kg\n",
-      "##CALCULATIONS\n",
-      "h2= h1+e*(h2s-h1)\n",
-      "W= m*(h1-h2)\n",
-      "S= s2-s1\n",
-      "##RESULTS\n",
-      "print'%s %.1f %s'%('Enthalpy  =',W,'kW')\n",
-      "print'%s %.4f %s'% ('Entropy =',S,'kJ/kg K')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "Enthalpy  = 5922.9 kW\n",
-        "Entropy = 0.4952 kJ/kg K\n"
-       ]
-      }
-     ],
-     "prompt_number": 7
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Example5-pg162"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "calculate volume flow rate into composser and volume flow rate out composser and heat and work \n",
-      "##initialisation of variables\n",
-      "m= 0.2 ##kg/s\n",
-      "v1= 1.0803 ##m^3/kg\n",
-      "T= 200 ##C\n",
-      "s2= 5.8041 ##kJ/kg K\n",
-      "s1= 7.5066 ##kJ/kg K\n",
-      "h1= 2328.1 ##kJ/kg\n",
-      "h2= 2654.4 ##kJ/kg\n",
-      "##CALCULATIONS\n",
-      "V1= m*v1\n",
-      "V2= 0.1*V1\n",
-      "Q= m*(273.15+T)*(s2-s1)\n",
-      "W= Q-m*(h1-h2)\n",
-      "##RESULTS\n",
-      "print'%s %.4f %s'%('volume flow rate into composser =',V1,'m^3')\n",
-      "print'%s %.4f %s'%('volume flow rate out of composser  =',V2,'m^3')\n",
-      "print'%s %.1f %s'%('Heat  =',Q,'kJ')\n",
-      "print'%s %.1f %s'%(' Work  =',W,'kJ')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "volume flow rate into composser = 0.2161 m^3\n",
-        "volume flow rate out of composser  = 0.0216 m^3\n",
-        "Heat  = -161.1 kJ\n",
-        " Work  = -95.8 kJ\n"
-       ]
-      }
-     ],
-     "prompt_number": 6
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Example6-pg164"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "#calculate volume flow rate out and into the composser and work and heat\n",
-      "##initialisation of variables\n",
-      "m1= 0.2 ##kg/s\n",
-      "v1= 1.0803 ##m^3/kg\n",
-      "P= 200 ##kPa\n",
-      "T= 200 ##C\n",
-      "s1= 5.8041 ##kJ.kg K\n",
-      "s2= 7.5066 ##kJ/kg K\n",
-      "h1= 2870.5 ##kJ/kg\n",
-      "h2= 2495.9 ##kJ/kg\n",
-      "##CALCULATIONS\n",
-      "V1= m1*v1\n",
-      "V2= 0.1*V1\n",
-      "Q= m1*(273.15+T)*(s1-s2)\n",
-      "W= m1*((h1-h2)-(273.15+T)*(s2-s1))\n",
-      "##RESULTS\n",
-      "print'%s %.4f %s'% ('volume flow rate into composser =',V1,'m^3/s')\n",
-      "print'%s %.4f %s'%('volume flow rate out of composser  =',V2,'m^3/s') \n",
-      "print'%s %.1f %s'%('Work  =',W,'kW')\n",
-      "print'%s %.1f %s'%('Heat  =',Q,'kW')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "volume flow rate into composser = 0.2161 m^3/s\n",
-        "volume flow rate out of composser  = 0.0216 m^3/s\n",
-        "Work  = -86.2 kW\n",
-        "Heat  = -161.1 kW\n"
-       ]
-      }
-     ],
-     "prompt_number": 5
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Example7-pg166"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "#calculate rate of transfer\n",
-      "##initialisation of variables\n",
-      "e= 0.82\n",
-      "m= 5 ##kg/s\n",
-      "T3= 450 ##C\n",
-      "T1= 200 ##C\n",
-      "##CALCULATIONS\n",
-      "Q= e*m*1.0035*(T3-T1)\n",
-      "##RESULTS\n",
-      "print'%s %.1f %s'%('rate of transfer =',Q,'kW')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "rate of transfer = 1028.6 kW\n"
-       ]
-      }
-     ],
-     "prompt_number": 4
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Example8-pg 166"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "#calculate heat at given enthalpy\n",
-      "##initialisation of variables\n",
-      "h1= 174.076 ##kJ/kg\n",
-      "h3= 74.527 ##kJ/kg\n",
-      "h4= 8.854 ##kJ/kg\n",
-      "m= 0.8 ##kg\n",
-      "e= 0.85\n",
-      "##CALCULATIONS\n",
-      "h2= h1+h3-h4\n",
-      "Q= m*(h2-h1-23)\n",
-      "Q1= e*Q\n",
-      "##RESULTS\n",
-      "print'%s %.2f %s'%('Heat =',Q,'kW')\n",
-      "print'%s %.2f %s'%('Heat =',Q1,'kW')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "Heat = 34.14 kW\n",
-        "Heat = 29.02 kW\n"
-       ]
-      }
-     ],
-     "prompt_number": 3
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Example9-pg 167"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "#calculate enthalpy and entropy change\n",
-      "##initialisation of variables\n",
-      "W= 2000. ##kW\n",
-      "m= 2. ##kg/s\n",
-      "h1= 3023.5 ##kJ/kg\n",
-      "s2= 5.6106 ##kJ/kg K\n",
-      "s1= 6.7664 ##kJ/kg K\n",
-      "##CALCULATIONS\n",
-      "h2= h1-(W/m)\n",
-      "S=s2-s1\n",
-      "##RESULTS\n",
-      "print'%s %.1f %s'% ('enthalpy =',h2,'kJ/kg')\n",
-      "print'%s %.4f %s'%('entropy change =',S,'kJ/kg K')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "enthalpy = 2023.5 kJ/kg\n",
-        "entropy change = -1.1558 kJ/kg K\n"
-       ]
-      }
-     ],
-     "prompt_number": 2
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Example10-pg 168"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "#calculate enthalpy and entropy change\n",
-      "##initialisation of variables\n",
-      "m1= 1 ##kg\n",
-      "h1= 2967.6 ##kJ/kg\n",
-      "h2= 83.96 ##kJ/kg\n",
-      "m2= 10\n",
-      "s1= 7.5166 ##kJ/kg K\n",
-      "s2= 0.2966 ##kJ/kg K\n",
-      "s3= 1.1654 ##kJ/kg K\n",
-      "##CALCULATIONS\n",
-      "h3= (m1*h1+m2*h2)/(m1+m2)\n",
-      "S= -m1*s1-m2*s2+(m1+m2)*s3\n",
-      "##RESULTS\n",
-      "print'%s %.1f %s'% ('enthalpy =',h3,'kJ/kg')\n",
-      "print'%s %.4f %s'%('entropy change =',S,'kJ/kg K')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "enthalpy = 346.1 kJ/kg\n",
-        "entropy change = 2.3368 kJ/kg K\n"
-       ]
-      }
-     ],
-     "prompt_number": 1
-    }
-   ],
-   "metadata": {}
-  }
- ]
-}
-\ No newline at end of file
diff --git a/Thermodynamics:_From_concepts_to_applications/Chapter9_2.ipynb b/Thermodynamics:_From_concepts_to_applications/Chapter9_2.ipynb
deleted file mode 100755
index f2acb74e..00000000
--- a/Thermodynamics:_From_concepts_to_applications/Chapter9_2.ipynb
+++ /dev/null
@@ -1,473 +0,0 @@
-{
- "metadata": {
-  "name": "",
-  "signature": "sha256:15fd1db156f91825255a086dbc12ea12cb6caac30db6feed49ee7e31d29fef8c"
- },
- "nbformat": 3,
- "nbformat_minor": 0,
- "worksheets": [
-  {
-   "cells": [
-    {
-     "cell_type": "heading",
-     "level": 1,
-     "metadata": {},
-     "source": [
-      "Chapter9-Applications of the second law of thermodynamics"
-     ]
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Example1-pg 152"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "#calculate final temperatures and total entropy\n",
-      "##changeinitialisation of variables\n",
-      "p1= 3.##changeMpa\n",
-      "p2= 0.2 ##changeMpa\n",
-      "V1= 0.6 ##changem^3\n",
-      "V2= 1.##changem^3\n",
-      "M= 28. ##changegms\n",
-      "R= 8.314 ##changeJ/mol K\n",
-      "T= 400. ##changeC\n",
-      "T1= 150. ##changeC\n",
-      "k= 1.4\n",
-      "p3= 1.25 ##changeMpa\n",
-      "##changeCALCULATIONS\n",
-      "m1= p1*V1*10*10*10*M/(R*(273.15+T))\n",
-      "m2= p2*V2*10*10*10*M/(R*(273.15+T1))\n",
-      "p4= (p1*V1+p2*V2)/(V1+V2)\n",
-      "T2= (math.pow(p4/p1,k-1)/k)*(273.15+T)\n",
-      "m3= p3*V1*M*10*10*10/(R*T2)\n",
-      "dm= m1-m3\n",
-      "m4= m2+dm\n",
-      "T4= p3*10*10*10*V2/((R/M)*m4)\n",
-      "S= (R/M)*(m2*((k/(k-1))*math.log(T4/(273.15+T1))-math.log(p3/p2))+dm*((k/(k-1))*math.log(T4/(273.15+T))-math.log(p3/p1)))\n",
-      "##changeRESULTS\n",
-      "print'%s %.1f %s'%('final temperature =',T2,'K')\n",
-      "print'%s %.1f %s'%('final temperature =',T4,'K')\n",
-      "print'%s %.4f %s'%('Total entropy =',S,'KJ/K')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "final temperature = 338.8 K\n",
-        "final temperature = 1340.2 K\n",
-        "Total entropy = 2.5525 KJ/K\n"
-       ]
-      }
-     ],
-     "prompt_number": 10
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Example2-pg156"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "#calculate work of the pump\n",
-      "##initialisation of variables\n",
-      "m= 10000 ##kg/h\n",
-      "P= 2.5 ##Mpa\n",
-      "P1= 100 ##kPa\n",
-      "v= 0.001003 ##m^3\n",
-      "##CALCULATIONS\n",
-      "W= -m*v*(P*10*10*10-P1)/3600\n",
-      "##RESULTS\n",
-      "print'%s %.3f %s'%(' work of the pump =',W,'kW')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        " work of the pump = -6.687 kW\n"
-       ]
-      }
-     ],
-     "prompt_number": 9
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Example3-pg 158"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "##initialisation of variables\n",
-      "m= 4. ##kg/s\n",
-      "R= 8.314 ##J/mol K\n",
-      "M= 29. ##gms\n",
-      "k= 1.4\n",
-      "T1= 27. ##C\n",
-      "p2= 1800. ##kPa\n",
-      "p1= 105. ##kPa\n",
-      "n= 1.22\n",
-      "cp= 1.4 ##Jmol K\n",
-      "##CALCULATIONS\n",
-      "T2= (273.15+T1)*(p2/p1)**((n-1)/n)\n",
-      "W= m*k*(R/M)*((273.15+T1)/(k-1))*(1-(p2/p1)**((k-1)/k))\n",
-      "Q= -m*R*(273.15+T1)*math.log(p2/p1)/M\n",
-      "W1= m*(R/M)*n*((273.15+T1)/(n-1))*(1-(p2/p1)**((n-1)/n))\n",
-      "Q1= m*(R/M)*(n-k)*(T2-T1-273.15)/((n-1)*(k-1))\n",
-      "T3= (273.15+T1)*(p2/p1)**((k-1)/(2*k))\n",
-      "Q2= m*cp*(R/M)*(T1+273.15-T3)/(k-1)\n",
-      "##RESULTS\n",
-      "print'%s %.1f %s'%('heat removed in adiabatic compression =',W,'kW')\n",
-      "print'%s %.1f %s'%('heat removed in isothermal compression =',Q,'kW')\n",
-      "print'%s %.1f %s'%('heat removed in polytropic process =',Q1,'kW')\n",
-      "print'%s %.2f %s'%('heat removed in adiabatic compression in two stages =',Q2,'kW')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "heat removed in adiabatic compression = -1508.5 kW\n",
-        "heat removed in isothermal compression = -978.1 kW\n",
-        "heat removed in polytropic process = -471.2 kW\n",
-        "heat removed in adiabatic compression in two stages = -603.21 kW\n"
-       ]
-      }
-     ],
-     "prompt_number": 8
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Example4-pg 161"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "#calculate enthalpy and entropy\n",
-      "##initialisation of variables\n",
-      "h1= 3422.25 ##kJ/kg\n",
-      "m= 8. ##kg/s\n",
-      "s2= 7.3755 ##kJ/kg K\n",
-      "s1= 6.8803 ##kJ/kg K\n",
-      "e= 0.8\n",
-      "h2s= 2496.8 ##kJ/kg\n",
-      "##CALCULATIONS\n",
-      "h2= h1+e*(h2s-h1)\n",
-      "W= m*(h1-h2)\n",
-      "S= s2-s1\n",
-      "##RESULTS\n",
-      "print'%s %.1f %s'%('Enthalpy  =',W,'kW')\n",
-      "print'%s %.4f %s'% ('Entropy =',S,'kJ/kg K')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "Enthalpy  = 5922.9 kW\n",
-        "Entropy = 0.4952 kJ/kg K\n"
-       ]
-      }
-     ],
-     "prompt_number": 7
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Example5-pg162"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "calculate volume flow rate into composser and volume flow rate out composser and heat and work \n",
-      "##initialisation of variables\n",
-      "m= 0.2 ##kg/s\n",
-      "v1= 1.0803 ##m^3/kg\n",
-      "T= 200 ##C\n",
-      "s2= 5.8041 ##kJ/kg K\n",
-      "s1= 7.5066 ##kJ/kg K\n",
-      "h1= 2328.1 ##kJ/kg\n",
-      "h2= 2654.4 ##kJ/kg\n",
-      "##CALCULATIONS\n",
-      "V1= m*v1\n",
-      "V2= 0.1*V1\n",
-      "Q= m*(273.15+T)*(s2-s1)\n",
-      "W= Q-m*(h1-h2)\n",
-      "##RESULTS\n",
-      "print'%s %.4f %s'%('volume flow rate into composser =',V1,'m^3')\n",
-      "print'%s %.4f %s'%('volume flow rate out of composser  =',V2,'m^3')\n",
-      "print'%s %.1f %s'%('Heat  =',Q,'kJ')\n",
-      "print'%s %.1f %s'%(' Work  =',W,'kJ')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "volume flow rate into composser = 0.2161 m^3\n",
-        "volume flow rate out of composser  = 0.0216 m^3\n",
-        "Heat  = -161.1 kJ\n",
-        " Work  = -95.8 kJ\n"
-       ]
-      }
-     ],
-     "prompt_number": 6
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Example6-pg164"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "#calculate volume flow rate out and into the composser and work and heat\n",
-      "##initialisation of variables\n",
-      "m1= 0.2 ##kg/s\n",
-      "v1= 1.0803 ##m^3/kg\n",
-      "P= 200 ##kPa\n",
-      "T= 200 ##C\n",
-      "s1= 5.8041 ##kJ.kg K\n",
-      "s2= 7.5066 ##kJ/kg K\n",
-      "h1= 2870.5 ##kJ/kg\n",
-      "h2= 2495.9 ##kJ/kg\n",
-      "##CALCULATIONS\n",
-      "V1= m1*v1\n",
-      "V2= 0.1*V1\n",
-      "Q= m1*(273.15+T)*(s1-s2)\n",
-      "W= m1*((h1-h2)-(273.15+T)*(s2-s1))\n",
-      "##RESULTS\n",
-      "print'%s %.4f %s'% ('volume flow rate into composser =',V1,'m^3/s')\n",
-      "print'%s %.4f %s'%('volume flow rate out of composser  =',V2,'m^3/s') \n",
-      "print'%s %.1f %s'%('Work  =',W,'kW')\n",
-      "print'%s %.1f %s'%('Heat  =',Q,'kW')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "volume flow rate into composser = 0.2161 m^3/s\n",
-        "volume flow rate out of composser  = 0.0216 m^3/s\n",
-        "Work  = -86.2 kW\n",
-        "Heat  = -161.1 kW\n"
-       ]
-      }
-     ],
-     "prompt_number": 5
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Example7-pg166"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "#calculate rate of transfer\n",
-      "##initialisation of variables\n",
-      "e= 0.82\n",
-      "m= 5 ##kg/s\n",
-      "T3= 450 ##C\n",
-      "T1= 200 ##C\n",
-      "##CALCULATIONS\n",
-      "Q= e*m*1.0035*(T3-T1)\n",
-      "##RESULTS\n",
-      "print'%s %.1f %s'%('rate of transfer =',Q,'kW')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "rate of transfer = 1028.6 kW\n"
-       ]
-      }
-     ],
-     "prompt_number": 4
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Example8-pg 166"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "#calculate heat at given enthalpy\n",
-      "##initialisation of variables\n",
-      "h1= 174.076 ##kJ/kg\n",
-      "h3= 74.527 ##kJ/kg\n",
-      "h4= 8.854 ##kJ/kg\n",
-      "m= 0.8 ##kg\n",
-      "e= 0.85\n",
-      "##CALCULATIONS\n",
-      "h2= h1+h3-h4\n",
-      "Q= m*(h2-h1-23)\n",
-      "Q1= e*Q\n",
-      "##RESULTS\n",
-      "print'%s %.2f %s'%('Heat =',Q,'kW')\n",
-      "print'%s %.2f %s'%('Heat =',Q1,'kW')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "Heat = 34.14 kW\n",
-        "Heat = 29.02 kW\n"
-       ]
-      }
-     ],
-     "prompt_number": 3
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Example9-pg 167"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "#calculate enthalpy and entropy change\n",
-      "##initialisation of variables\n",
-      "W= 2000. ##kW\n",
-      "m= 2. ##kg/s\n",
-      "h1= 3023.5 ##kJ/kg\n",
-      "s2= 5.6106 ##kJ/kg K\n",
-      "s1= 6.7664 ##kJ/kg K\n",
-      "##CALCULATIONS\n",
-      "h2= h1-(W/m)\n",
-      "S=s2-s1\n",
-      "##RESULTS\n",
-      "print'%s %.1f %s'% ('enthalpy =',h2,'kJ/kg')\n",
-      "print'%s %.4f %s'%('entropy change =',S,'kJ/kg K')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "enthalpy = 2023.5 kJ/kg\n",
-        "entropy change = -1.1558 kJ/kg K\n"
-       ]
-      }
-     ],
-     "prompt_number": 2
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Example10-pg 168"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "#calculate enthalpy and entropy change\n",
-      "##initialisation of variables\n",
-      "m1= 1 ##kg\n",
-      "h1= 2967.6 ##kJ/kg\n",
-      "h2= 83.96 ##kJ/kg\n",
-      "m2= 10\n",
-      "s1= 7.5166 ##kJ/kg K\n",
-      "s2= 0.2966 ##kJ/kg K\n",
-      "s3= 1.1654 ##kJ/kg K\n",
-      "##CALCULATIONS\n",
-      "h3= (m1*h1+m2*h2)/(m1+m2)\n",
-      "S= -m1*s1-m2*s2+(m1+m2)*s3\n",
-      "##RESULTS\n",
-      "print'%s %.1f %s'% ('enthalpy =',h3,'kJ/kg')\n",
-      "print'%s %.4f %s'%('entropy change =',S,'kJ/kg K')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "enthalpy = 346.1 kJ/kg\n",
-        "entropy change = 2.3368 kJ/kg K\n"
-       ]
-      }
-     ],
-     "prompt_number": 1
-    }
-   ],
-   "metadata": {}
-  }
- ]
-}
-\ No newline at end of file
diff --git a/Thermodynamics:_From_concepts_to_applications/Chapter_2.ipynb b/Thermodynamics:_From_concepts_to_applications/Chapter_2.ipynb
deleted file mode 100755
index 1b242151..00000000
--- a/Thermodynamics:_From_concepts_to_applications/Chapter_2.ipynb
+++ /dev/null
@@ -1,69 +0,0 @@
-{
- "metadata": {
-  "name": "",
-  "signature": "sha256:2df70ea24eb675b5df88544238cda98c7d9d4538b630227696b56b410ea0e81e"
- },
- "nbformat": 3,
- "nbformat_minor": 0,
- "worksheets": [
-  {
-   "cells": [
-    {
-     "cell_type": "heading",
-     "level": 1,
-     "metadata": {},
-     "source": [
-      "Chapter 2 - Work"
-     ]
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Example 2 pg 12"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "##calculate the mass of oxygen and density of oxygen and specific volume and molar specific volume\n",
-      "##initialisation of variables\n",
-      "n= 0.25 ## k mol\n",
-      "M= 32 ##kg/kmol\n",
-      "V= 0.5 ##m^3\n",
-      "##CALCULATIONS\n",
-      "m= n*M\n",
-      "d= m/V\n",
-      "v= 1/d\n",
-      "v1= V/n\n",
-      "##RESULTS\n",
-      "print'%s %.0f %s'%(\"mass of oxygen=\",m,'kg')\n",
-      "print'%s %.0f %s'%(\"density of oxygen=\",d,'kg/m^3')\n",
-      "print'%s %.4f %s'%('specific volume=',v,'kg/m^3')\n",
-      "print'%s %.0f %s'%('molar specific volume=',v1,'m^3/kmol')\n",
-      "\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "mass of oxygen= 8 kg\n",
-        "density of oxygen= 16 kg/m^3\n",
-        "specific volume= 0.0625 kg/m^3\n",
-        "molar specific volume= 2 m^3/kmol\n"
-       ]
-      }
-     ],
-     "prompt_number": 3
-    }
-   ],
-   "metadata": {}
-  }
- ]
-}
-\ No newline at end of file
diff --git a/Thermodynamics:_From_concepts_to_applications/Chapter_2_-Basic_concepts_.ipynb b/Thermodynamics:_From_concepts_to_applications/Chapter_2_-Basic_concepts_.ipynb
deleted file mode 100755
index a9cf01c8..00000000
--- a/Thermodynamics:_From_concepts_to_applications/Chapter_2_-Basic_concepts_.ipynb
+++ /dev/null
@@ -1,69 +0,0 @@
-{
- "metadata": {
-  "name": "",
-  "signature": "sha256:c445f39e7878cf61ffc763516de39900f14df501737d9a8da58454f14557359b"
- },
- "nbformat": 3,
- "nbformat_minor": 0,
- "worksheets": [
-  {
-   "cells": [
-    {
-     "cell_type": "heading",
-     "level": 1,
-     "metadata": {},
-     "source": [
-      "Chapter 2 - Basic concepts "
-     ]
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Example 2 pg 12"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "##calculate the mass of oxygen and density of oxygen and specific volume and molar specific volume\n",
-      "##initialisation of variables\n",
-      "n= 0.25 ## k mol\n",
-      "M= 32 ##kg/kmol\n",
-      "V= 0.5 ##m^3\n",
-      "##CALCULATIONS\n",
-      "m= n*M\n",
-      "d= m/V\n",
-      "v= 1/d\n",
-      "v1= V/n\n",
-      "##RESULTS\n",
-      "print'%s %.0f %s'%(\"mass of oxygen=\",m,'kg')\n",
-      "print'%s %.0f %s'%(\"density of oxygen=\",d,'kg/m^3')\n",
-      "print'%s %.4f %s'%('specific volume=',v,'kg/m^3')\n",
-      "print'%s %.0f %s'%('molar specific volume=',v1,'m^3/kmol')\n",
-      "\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "mass of oxygen= 8 kg\n",
-        "density of oxygen= 16 kg/m^3\n",
-        "specific volume= 0.0625 kg/m^3\n",
-        "molar specific volume= 2 m^3/kmol\n"
-       ]
-      }
-     ],
-     "prompt_number": 3
-    }
-   ],
-   "metadata": {}
-  }
- ]
-}
-\ No newline at end of file
diff --git a/Thermodynamics:_From_concepts_to_applications/Chapter_2_-Basic_concepts__1.ipynb b/Thermodynamics:_From_concepts_to_applications/Chapter_2_-Basic_concepts__1.ipynb
deleted file mode 100755
index a9cf01c8..00000000
--- a/Thermodynamics:_From_concepts_to_applications/Chapter_2_-Basic_concepts__1.ipynb
+++ /dev/null
@@ -1,69 +0,0 @@
-{
- "metadata": {
-  "name": "",
-  "signature": "sha256:c445f39e7878cf61ffc763516de39900f14df501737d9a8da58454f14557359b"
- },
- "nbformat": 3,
- "nbformat_minor": 0,
- "worksheets": [
-  {
-   "cells": [
-    {
-     "cell_type": "heading",
-     "level": 1,
-     "metadata": {},
-     "source": [
-      "Chapter 2 - Basic concepts "
-     ]
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Example 2 pg 12"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "##calculate the mass of oxygen and density of oxygen and specific volume and molar specific volume\n",
-      "##initialisation of variables\n",
-      "n= 0.25 ## k mol\n",
-      "M= 32 ##kg/kmol\n",
-      "V= 0.5 ##m^3\n",
-      "##CALCULATIONS\n",
-      "m= n*M\n",
-      "d= m/V\n",
-      "v= 1/d\n",
-      "v1= V/n\n",
-      "##RESULTS\n",
-      "print'%s %.0f %s'%(\"mass of oxygen=\",m,'kg')\n",
-      "print'%s %.0f %s'%(\"density of oxygen=\",d,'kg/m^3')\n",
-      "print'%s %.4f %s'%('specific volume=',v,'kg/m^3')\n",
-      "print'%s %.0f %s'%('molar specific volume=',v1,'m^3/kmol')\n",
-      "\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "mass of oxygen= 8 kg\n",
-        "density of oxygen= 16 kg/m^3\n",
-        "specific volume= 0.0625 kg/m^3\n",
-        "molar specific volume= 2 m^3/kmol\n"
-       ]
-      }
-     ],
-     "prompt_number": 3
-    }
-   ],
-   "metadata": {}
-  }
- ]
-}
-\ No newline at end of file
diff --git a/Thermodynamics:_From_concepts_to_applications/Chapter_2_-Basic_concepts__2.ipynb b/Thermodynamics:_From_concepts_to_applications/Chapter_2_-Basic_concepts__2.ipynb
deleted file mode 100755
index a9cf01c8..00000000
--- a/Thermodynamics:_From_concepts_to_applications/Chapter_2_-Basic_concepts__2.ipynb
+++ /dev/null
@@ -1,69 +0,0 @@
-{
- "metadata": {
-  "name": "",
-  "signature": "sha256:c445f39e7878cf61ffc763516de39900f14df501737d9a8da58454f14557359b"
- },
- "nbformat": 3,
- "nbformat_minor": 0,
- "worksheets": [
-  {
-   "cells": [
-    {
-     "cell_type": "heading",
-     "level": 1,
-     "metadata": {},
-     "source": [
-      "Chapter 2 - Basic concepts "
-     ]
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Example 2 pg 12"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "##calculate the mass of oxygen and density of oxygen and specific volume and molar specific volume\n",
-      "##initialisation of variables\n",
-      "n= 0.25 ## k mol\n",
-      "M= 32 ##kg/kmol\n",
-      "V= 0.5 ##m^3\n",
-      "##CALCULATIONS\n",
-      "m= n*M\n",
-      "d= m/V\n",
-      "v= 1/d\n",
-      "v1= V/n\n",
-      "##RESULTS\n",
-      "print'%s %.0f %s'%(\"mass of oxygen=\",m,'kg')\n",
-      "print'%s %.0f %s'%(\"density of oxygen=\",d,'kg/m^3')\n",
-      "print'%s %.4f %s'%('specific volume=',v,'kg/m^3')\n",
-      "print'%s %.0f %s'%('molar specific volume=',v1,'m^3/kmol')\n",
-      "\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "mass of oxygen= 8 kg\n",
-        "density of oxygen= 16 kg/m^3\n",
-        "specific volume= 0.0625 kg/m^3\n",
-        "molar specific volume= 2 m^3/kmol\n"
-       ]
-      }
-     ],
-     "prompt_number": 3
-    }
-   ],
-   "metadata": {}
-  }
- ]
-}
-\ No newline at end of file
diff --git a/Thermodynamics:_From_concepts_to_applications/Chapter_2_-Basic_concepts__3.ipynb b/Thermodynamics:_From_concepts_to_applications/Chapter_2_-Basic_concepts__3.ipynb
deleted file mode 100755
index a9cf01c8..00000000
--- a/Thermodynamics:_From_concepts_to_applications/Chapter_2_-Basic_concepts__3.ipynb
+++ /dev/null
@@ -1,69 +0,0 @@
-{
- "metadata": {
-  "name": "",
-  "signature": "sha256:c445f39e7878cf61ffc763516de39900f14df501737d9a8da58454f14557359b"
- },
- "nbformat": 3,
- "nbformat_minor": 0,
- "worksheets": [
-  {
-   "cells": [
-    {
-     "cell_type": "heading",
-     "level": 1,
-     "metadata": {},
-     "source": [
-      "Chapter 2 - Basic concepts "
-     ]
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Example 2 pg 12"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "##calculate the mass of oxygen and density of oxygen and specific volume and molar specific volume\n",
-      "##initialisation of variables\n",
-      "n= 0.25 ## k mol\n",
-      "M= 32 ##kg/kmol\n",
-      "V= 0.5 ##m^3\n",
-      "##CALCULATIONS\n",
-      "m= n*M\n",
-      "d= m/V\n",
-      "v= 1/d\n",
-      "v1= V/n\n",
-      "##RESULTS\n",
-      "print'%s %.0f %s'%(\"mass of oxygen=\",m,'kg')\n",
-      "print'%s %.0f %s'%(\"density of oxygen=\",d,'kg/m^3')\n",
-      "print'%s %.4f %s'%('specific volume=',v,'kg/m^3')\n",
-      "print'%s %.0f %s'%('molar specific volume=',v1,'m^3/kmol')\n",
-      "\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "mass of oxygen= 8 kg\n",
-        "density of oxygen= 16 kg/m^3\n",
-        "specific volume= 0.0625 kg/m^3\n",
-        "molar specific volume= 2 m^3/kmol\n"
-       ]
-      }
-     ],
-     "prompt_number": 3
-    }
-   ],
-   "metadata": {}
-  }
- ]
-}
-\ No newline at end of file
diff --git a/Thermodynamics:_From_concepts_to_applications/Chapter_2_1.ipynb b/Thermodynamics:_From_concepts_to_applications/Chapter_2_1.ipynb
deleted file mode 100755
index a9cf01c8..00000000
--- a/Thermodynamics:_From_concepts_to_applications/Chapter_2_1.ipynb
+++ /dev/null
@@ -1,69 +0,0 @@
-{
- "metadata": {
-  "name": "",
-  "signature": "sha256:c445f39e7878cf61ffc763516de39900f14df501737d9a8da58454f14557359b"
- },
- "nbformat": 3,
- "nbformat_minor": 0,
- "worksheets": [
-  {
-   "cells": [
-    {
-     "cell_type": "heading",
-     "level": 1,
-     "metadata": {},
-     "source": [
-      "Chapter 2 - Basic concepts "
-     ]
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Example 2 pg 12"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "##calculate the mass of oxygen and density of oxygen and specific volume and molar specific volume\n",
-      "##initialisation of variables\n",
-      "n= 0.25 ## k mol\n",
-      "M= 32 ##kg/kmol\n",
-      "V= 0.5 ##m^3\n",
-      "##CALCULATIONS\n",
-      "m= n*M\n",
-      "d= m/V\n",
-      "v= 1/d\n",
-      "v1= V/n\n",
-      "##RESULTS\n",
-      "print'%s %.0f %s'%(\"mass of oxygen=\",m,'kg')\n",
-      "print'%s %.0f %s'%(\"density of oxygen=\",d,'kg/m^3')\n",
-      "print'%s %.4f %s'%('specific volume=',v,'kg/m^3')\n",
-      "print'%s %.0f %s'%('molar specific volume=',v1,'m^3/kmol')\n",
-      "\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "mass of oxygen= 8 kg\n",
-        "density of oxygen= 16 kg/m^3\n",
-        "specific volume= 0.0625 kg/m^3\n",
-        "molar specific volume= 2 m^3/kmol\n"
-       ]
-      }
-     ],
-     "prompt_number": 3
-    }
-   ],
-   "metadata": {}
-  }
- ]
-}
-\ No newline at end of file
diff --git a/Thermodynamics:_From_concepts_to_applications/Chapter_2_2.ipynb b/Thermodynamics:_From_concepts_to_applications/Chapter_2_2.ipynb
deleted file mode 100755
index a9cf01c8..00000000
--- a/Thermodynamics:_From_concepts_to_applications/Chapter_2_2.ipynb
+++ /dev/null
@@ -1,69 +0,0 @@
-{
- "metadata": {
-  "name": "",
-  "signature": "sha256:c445f39e7878cf61ffc763516de39900f14df501737d9a8da58454f14557359b"
- },
- "nbformat": 3,
- "nbformat_minor": 0,
- "worksheets": [
-  {
-   "cells": [
-    {
-     "cell_type": "heading",
-     "level": 1,
-     "metadata": {},
-     "source": [
-      "Chapter 2 - Basic concepts "
-     ]
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Example 2 pg 12"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "##calculate the mass of oxygen and density of oxygen and specific volume and molar specific volume\n",
-      "##initialisation of variables\n",
-      "n= 0.25 ## k mol\n",
-      "M= 32 ##kg/kmol\n",
-      "V= 0.5 ##m^3\n",
-      "##CALCULATIONS\n",
-      "m= n*M\n",
-      "d= m/V\n",
-      "v= 1/d\n",
-      "v1= V/n\n",
-      "##RESULTS\n",
-      "print'%s %.0f %s'%(\"mass of oxygen=\",m,'kg')\n",
-      "print'%s %.0f %s'%(\"density of oxygen=\",d,'kg/m^3')\n",
-      "print'%s %.4f %s'%('specific volume=',v,'kg/m^3')\n",
-      "print'%s %.0f %s'%('molar specific volume=',v1,'m^3/kmol')\n",
-      "\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "mass of oxygen= 8 kg\n",
-        "density of oxygen= 16 kg/m^3\n",
-        "specific volume= 0.0625 kg/m^3\n",
-        "molar specific volume= 2 m^3/kmol\n"
-       ]
-      }
-     ],
-     "prompt_number": 3
-    }
-   ],
-   "metadata": {}
-  }
- ]
-}
-\ No newline at end of file
diff --git a/Thermodynamics:_From_concepts_to_applications/Chapter_3-Work_energy_and_heat_first_law_of_thermodynamics.ipynb b/Thermodynamics:_From_concepts_to_applications/Chapter_3-Work_energy_and_heat_first_law_of_thermodynamics.ipynb
deleted file mode 100755
index f4e0af8d..00000000
--- a/Thermodynamics:_From_concepts_to_applications/Chapter_3-Work_energy_and_heat_first_law_of_thermodynamics.ipynb
+++ /dev/null
@@ -1,220 +0,0 @@
-{
- "metadata": {
-  "name": "",
-  "signature": "sha256:56539cb8410013a7d0be3df1cf1e85c7a8b906e5f399b600535904fe0fd98e57"
- },
- "nbformat": 3,
- "nbformat_minor": 0,
- "worksheets": [
-  {
-   "cells": [
-    {
-     "cell_type": "heading",
-     "level": 1,
-     "metadata": {},
-     "source": [
-      "chapter3-Work energy and heat first law of thermodynamics"
-     ]
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Example 3 - Pg 24"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "##calculate the work interaction of spring\n",
-      "##initialisation of variables\n",
-      "m= 5 ##kg\n",
-      "g= 9.8 ##m/sec^2\n",
-      "k= 500 ##N/m\n",
-      "##CALCULATIONS\n",
-      "x= m*g/k\n",
-      "W= -m*g*x\n",
-      "##RESULTS\n",
-      "print'%s %.2f %s'% ('work interaction of spring = ',W,'J')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "work interaction of spring =  -4.80 J\n"
-       ]
-      }
-     ],
-     "prompt_number": 2
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Example 4 pg 25"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "##calculate the work done by the gas\n",
-      "##initialisation of variables\n",
-      "m= 500 ##kg\n",
-      "V= 50 ##L\n",
-      "P= 700 ##kPa\n",
-      "T= 25 ##C\n",
-      "P0= 100 ##kPa\n",
-      "g= 9.8 ##m/sec^2\n",
-      "A= 200 ##cm^2\n",
-      "V1= 100 ##L\n",
-      "##CALCULATIONS\n",
-      "pe= P0*math.pow(10,3)+(m*g/(A*(math.pow(10,-4))))\n",
-      "W= pe*(V1-V)*(math.pow(10,-6))\n",
-      "##RESULTS\n",
-      "print'%s %.2f %s'% ('work of the gas =',W,'kJ')"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "work of the gas = 17.25 kJ\n"
-       ]
-      }
-     ],
-     "prompt_number": 3
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Example 5 pg 27"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "##calcualte the energy change in process 1,2,3 and work in third process\n",
-      "##initialisation of variables\n",
-      "W= 5 ##kJ\n",
-      "Q= 23 ##kJ\n",
-      "Q1= -50 ##kJ\n",
-      "W1= 0 ##kJ\n",
-      "##CALCULATIONS\n",
-      "E1= Q-W\n",
-      "E2= Q1-W1\n",
-      "E3= -(E1+E2)\n",
-      "W3= -E3\n",
-      "##RESULTS\n",
-      "print '%s %.f %s'%('energy change in process 1 =',E1,'kJ')\n",
-      "print'%s %.f %s'% ('energy change in process 2 = ',E2,'kJ')\n",
-      "print '%s %.f %s'%('energy change in process 3 = ',E3,'kJ')\n",
-      "print '%s %.f %s'%('Work in third process = ',W3,'kJ')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "energy change in process 1 = 18 kJ\n",
-        "energy change in process 2 =  -50 kJ\n",
-        "energy change in process 3 =  32 kJ\n",
-        "Work in third process =  -32 kJ\n"
-       ]
-      }
-     ],
-     "prompt_number": 4
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Example 6 pg 28"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "##calculat the car mileage of given variable\n",
-      "##initialisation of variables\n",
-      "V= 12 ##km/L\n",
-      "##CALCULATIONS\n",
-      "MPG= V*3.7854/1.609\n",
-      "##RESULTS\n",
-      "print'%s %.2f %s'%('car mileage =',MPG,'MPG')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "car mileage = 28.23 MPG\n"
-       ]
-      }
-     ],
-     "prompt_number": 5
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Example 7 pg 28"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "##find whether salesman is honest or not\n",
-      "##initialisation of variables\n",
-      "p= 800 ##atm\n",
-      "P= 10000 ##psi\n",
-      "x= 14.696 ##psi/atm\n",
-      "##CALCULATIONS\n",
-      "P1= p*x\n",
-      "##RESULTS\n",
-      "if (P1>P):\n",
-      "\tprint (\"Salesman is honest\")\n",
-      "\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "Salesman is honest\n"
-       ]
-      }
-     ],
-     "prompt_number": 6
-    }
-   ],
-   "metadata": {}
-  }
- ]
-}
-\ No newline at end of file
diff --git a/Thermodynamics:_From_concepts_to_applications/Chapter_3-Work_energy_and_heat_first_law_of_thermodynamics_1.ipynb b/Thermodynamics:_From_concepts_to_applications/Chapter_3-Work_energy_and_heat_first_law_of_thermodynamics_1.ipynb
deleted file mode 100755
index f4e0af8d..00000000
--- a/Thermodynamics:_From_concepts_to_applications/Chapter_3-Work_energy_and_heat_first_law_of_thermodynamics_1.ipynb
+++ /dev/null
@@ -1,220 +0,0 @@
-{
- "metadata": {
-  "name": "",
-  "signature": "sha256:56539cb8410013a7d0be3df1cf1e85c7a8b906e5f399b600535904fe0fd98e57"
- },
- "nbformat": 3,
- "nbformat_minor": 0,
- "worksheets": [
-  {
-   "cells": [
-    {
-     "cell_type": "heading",
-     "level": 1,
-     "metadata": {},
-     "source": [
-      "chapter3-Work energy and heat first law of thermodynamics"
-     ]
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Example 3 - Pg 24"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "##calculate the work interaction of spring\n",
-      "##initialisation of variables\n",
-      "m= 5 ##kg\n",
-      "g= 9.8 ##m/sec^2\n",
-      "k= 500 ##N/m\n",
-      "##CALCULATIONS\n",
-      "x= m*g/k\n",
-      "W= -m*g*x\n",
-      "##RESULTS\n",
-      "print'%s %.2f %s'% ('work interaction of spring = ',W,'J')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "work interaction of spring =  -4.80 J\n"
-       ]
-      }
-     ],
-     "prompt_number": 2
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Example 4 pg 25"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "##calculate the work done by the gas\n",
-      "##initialisation of variables\n",
-      "m= 500 ##kg\n",
-      "V= 50 ##L\n",
-      "P= 700 ##kPa\n",
-      "T= 25 ##C\n",
-      "P0= 100 ##kPa\n",
-      "g= 9.8 ##m/sec^2\n",
-      "A= 200 ##cm^2\n",
-      "V1= 100 ##L\n",
-      "##CALCULATIONS\n",
-      "pe= P0*math.pow(10,3)+(m*g/(A*(math.pow(10,-4))))\n",
-      "W= pe*(V1-V)*(math.pow(10,-6))\n",
-      "##RESULTS\n",
-      "print'%s %.2f %s'% ('work of the gas =',W,'kJ')"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "work of the gas = 17.25 kJ\n"
-       ]
-      }
-     ],
-     "prompt_number": 3
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Example 5 pg 27"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "##calcualte the energy change in process 1,2,3 and work in third process\n",
-      "##initialisation of variables\n",
-      "W= 5 ##kJ\n",
-      "Q= 23 ##kJ\n",
-      "Q1= -50 ##kJ\n",
-      "W1= 0 ##kJ\n",
-      "##CALCULATIONS\n",
-      "E1= Q-W\n",
-      "E2= Q1-W1\n",
-      "E3= -(E1+E2)\n",
-      "W3= -E3\n",
-      "##RESULTS\n",
-      "print '%s %.f %s'%('energy change in process 1 =',E1,'kJ')\n",
-      "print'%s %.f %s'% ('energy change in process 2 = ',E2,'kJ')\n",
-      "print '%s %.f %s'%('energy change in process 3 = ',E3,'kJ')\n",
-      "print '%s %.f %s'%('Work in third process = ',W3,'kJ')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "energy change in process 1 = 18 kJ\n",
-        "energy change in process 2 =  -50 kJ\n",
-        "energy change in process 3 =  32 kJ\n",
-        "Work in third process =  -32 kJ\n"
-       ]
-      }
-     ],
-     "prompt_number": 4
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Example 6 pg 28"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "##calculat the car mileage of given variable\n",
-      "##initialisation of variables\n",
-      "V= 12 ##km/L\n",
-      "##CALCULATIONS\n",
-      "MPG= V*3.7854/1.609\n",
-      "##RESULTS\n",
-      "print'%s %.2f %s'%('car mileage =',MPG,'MPG')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "car mileage = 28.23 MPG\n"
-       ]
-      }
-     ],
-     "prompt_number": 5
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Example 7 pg 28"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "##find whether salesman is honest or not\n",
-      "##initialisation of variables\n",
-      "p= 800 ##atm\n",
-      "P= 10000 ##psi\n",
-      "x= 14.696 ##psi/atm\n",
-      "##CALCULATIONS\n",
-      "P1= p*x\n",
-      "##RESULTS\n",
-      "if (P1>P):\n",
-      "\tprint (\"Salesman is honest\")\n",
-      "\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "Salesman is honest\n"
-       ]
-      }
-     ],
-     "prompt_number": 6
-    }
-   ],
-   "metadata": {}
-  }
- ]
-}
-\ No newline at end of file
diff --git a/Thermodynamics:_From_concepts_to_applications/Chapter_3-Work_energy_and_heat_first_law_of_thermodynamics_2.ipynb b/Thermodynamics:_From_concepts_to_applications/Chapter_3-Work_energy_and_heat_first_law_of_thermodynamics_2.ipynb
deleted file mode 100755
index f4e0af8d..00000000
--- a/Thermodynamics:_From_concepts_to_applications/Chapter_3-Work_energy_and_heat_first_law_of_thermodynamics_2.ipynb
+++ /dev/null
@@ -1,220 +0,0 @@
-{
- "metadata": {
-  "name": "",
-  "signature": "sha256:56539cb8410013a7d0be3df1cf1e85c7a8b906e5f399b600535904fe0fd98e57"
- },
- "nbformat": 3,
- "nbformat_minor": 0,
- "worksheets": [
-  {
-   "cells": [
-    {
-     "cell_type": "heading",
-     "level": 1,
-     "metadata": {},
-     "source": [
-      "chapter3-Work energy and heat first law of thermodynamics"
-     ]
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Example 3 - Pg 24"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "##calculate the work interaction of spring\n",
-      "##initialisation of variables\n",
-      "m= 5 ##kg\n",
-      "g= 9.8 ##m/sec^2\n",
-      "k= 500 ##N/m\n",
-      "##CALCULATIONS\n",
-      "x= m*g/k\n",
-      "W= -m*g*x\n",
-      "##RESULTS\n",
-      "print'%s %.2f %s'% ('work interaction of spring = ',W,'J')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "work interaction of spring =  -4.80 J\n"
-       ]
-      }
-     ],
-     "prompt_number": 2
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Example 4 pg 25"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "##calculate the work done by the gas\n",
-      "##initialisation of variables\n",
-      "m= 500 ##kg\n",
-      "V= 50 ##L\n",
-      "P= 700 ##kPa\n",
-      "T= 25 ##C\n",
-      "P0= 100 ##kPa\n",
-      "g= 9.8 ##m/sec^2\n",
-      "A= 200 ##cm^2\n",
-      "V1= 100 ##L\n",
-      "##CALCULATIONS\n",
-      "pe= P0*math.pow(10,3)+(m*g/(A*(math.pow(10,-4))))\n",
-      "W= pe*(V1-V)*(math.pow(10,-6))\n",
-      "##RESULTS\n",
-      "print'%s %.2f %s'% ('work of the gas =',W,'kJ')"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "work of the gas = 17.25 kJ\n"
-       ]
-      }
-     ],
-     "prompt_number": 3
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Example 5 pg 27"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "##calcualte the energy change in process 1,2,3 and work in third process\n",
-      "##initialisation of variables\n",
-      "W= 5 ##kJ\n",
-      "Q= 23 ##kJ\n",
-      "Q1= -50 ##kJ\n",
-      "W1= 0 ##kJ\n",
-      "##CALCULATIONS\n",
-      "E1= Q-W\n",
-      "E2= Q1-W1\n",
-      "E3= -(E1+E2)\n",
-      "W3= -E3\n",
-      "##RESULTS\n",
-      "print '%s %.f %s'%('energy change in process 1 =',E1,'kJ')\n",
-      "print'%s %.f %s'% ('energy change in process 2 = ',E2,'kJ')\n",
-      "print '%s %.f %s'%('energy change in process 3 = ',E3,'kJ')\n",
-      "print '%s %.f %s'%('Work in third process = ',W3,'kJ')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "energy change in process 1 = 18 kJ\n",
-        "energy change in process 2 =  -50 kJ\n",
-        "energy change in process 3 =  32 kJ\n",
-        "Work in third process =  -32 kJ\n"
-       ]
-      }
-     ],
-     "prompt_number": 4
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Example 6 pg 28"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "##calculat the car mileage of given variable\n",
-      "##initialisation of variables\n",
-      "V= 12 ##km/L\n",
-      "##CALCULATIONS\n",
-      "MPG= V*3.7854/1.609\n",
-      "##RESULTS\n",
-      "print'%s %.2f %s'%('car mileage =',MPG,'MPG')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "car mileage = 28.23 MPG\n"
-       ]
-      }
-     ],
-     "prompt_number": 5
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Example 7 pg 28"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "##find whether salesman is honest or not\n",
-      "##initialisation of variables\n",
-      "p= 800 ##atm\n",
-      "P= 10000 ##psi\n",
-      "x= 14.696 ##psi/atm\n",
-      "##CALCULATIONS\n",
-      "P1= p*x\n",
-      "##RESULTS\n",
-      "if (P1>P):\n",
-      "\tprint (\"Salesman is honest\")\n",
-      "\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "Salesman is honest\n"
-       ]
-      }
-     ],
-     "prompt_number": 6
-    }
-   ],
-   "metadata": {}
-  }
- ]
-}
-\ No newline at end of file
diff --git a/Thermodynamics:_From_concepts_to_applications/Chapter_3-Work_energy_and_heat_first_law_of_thermodynamics_3.ipynb b/Thermodynamics:_From_concepts_to_applications/Chapter_3-Work_energy_and_heat_first_law_of_thermodynamics_3.ipynb
deleted file mode 100755
index f4e0af8d..00000000
--- a/Thermodynamics:_From_concepts_to_applications/Chapter_3-Work_energy_and_heat_first_law_of_thermodynamics_3.ipynb
+++ /dev/null
@@ -1,220 +0,0 @@
-{
- "metadata": {
-  "name": "",
-  "signature": "sha256:56539cb8410013a7d0be3df1cf1e85c7a8b906e5f399b600535904fe0fd98e57"
- },
- "nbformat": 3,
- "nbformat_minor": 0,
- "worksheets": [
-  {
-   "cells": [
-    {
-     "cell_type": "heading",
-     "level": 1,
-     "metadata": {},
-     "source": [
-      "chapter3-Work energy and heat first law of thermodynamics"
-     ]
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Example 3 - Pg 24"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "##calculate the work interaction of spring\n",
-      "##initialisation of variables\n",
-      "m= 5 ##kg\n",
-      "g= 9.8 ##m/sec^2\n",
-      "k= 500 ##N/m\n",
-      "##CALCULATIONS\n",
-      "x= m*g/k\n",
-      "W= -m*g*x\n",
-      "##RESULTS\n",
-      "print'%s %.2f %s'% ('work interaction of spring = ',W,'J')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "work interaction of spring =  -4.80 J\n"
-       ]
-      }
-     ],
-     "prompt_number": 2
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Example 4 pg 25"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "##calculate the work done by the gas\n",
-      "##initialisation of variables\n",
-      "m= 500 ##kg\n",
-      "V= 50 ##L\n",
-      "P= 700 ##kPa\n",
-      "T= 25 ##C\n",
-      "P0= 100 ##kPa\n",
-      "g= 9.8 ##m/sec^2\n",
-      "A= 200 ##cm^2\n",
-      "V1= 100 ##L\n",
-      "##CALCULATIONS\n",
-      "pe= P0*math.pow(10,3)+(m*g/(A*(math.pow(10,-4))))\n",
-      "W= pe*(V1-V)*(math.pow(10,-6))\n",
-      "##RESULTS\n",
-      "print'%s %.2f %s'% ('work of the gas =',W,'kJ')"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "work of the gas = 17.25 kJ\n"
-       ]
-      }
-     ],
-     "prompt_number": 3
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Example 5 pg 27"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "##calcualte the energy change in process 1,2,3 and work in third process\n",
-      "##initialisation of variables\n",
-      "W= 5 ##kJ\n",
-      "Q= 23 ##kJ\n",
-      "Q1= -50 ##kJ\n",
-      "W1= 0 ##kJ\n",
-      "##CALCULATIONS\n",
-      "E1= Q-W\n",
-      "E2= Q1-W1\n",
-      "E3= -(E1+E2)\n",
-      "W3= -E3\n",
-      "##RESULTS\n",
-      "print '%s %.f %s'%('energy change in process 1 =',E1,'kJ')\n",
-      "print'%s %.f %s'% ('energy change in process 2 = ',E2,'kJ')\n",
-      "print '%s %.f %s'%('energy change in process 3 = ',E3,'kJ')\n",
-      "print '%s %.f %s'%('Work in third process = ',W3,'kJ')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "energy change in process 1 = 18 kJ\n",
-        "energy change in process 2 =  -50 kJ\n",
-        "energy change in process 3 =  32 kJ\n",
-        "Work in third process =  -32 kJ\n"
-       ]
-      }
-     ],
-     "prompt_number": 4
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Example 6 pg 28"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "##calculat the car mileage of given variable\n",
-      "##initialisation of variables\n",
-      "V= 12 ##km/L\n",
-      "##CALCULATIONS\n",
-      "MPG= V*3.7854/1.609\n",
-      "##RESULTS\n",
-      "print'%s %.2f %s'%('car mileage =',MPG,'MPG')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "car mileage = 28.23 MPG\n"
-       ]
-      }
-     ],
-     "prompt_number": 5
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Example 7 pg 28"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "##find whether salesman is honest or not\n",
-      "##initialisation of variables\n",
-      "p= 800 ##atm\n",
-      "P= 10000 ##psi\n",
-      "x= 14.696 ##psi/atm\n",
-      "##CALCULATIONS\n",
-      "P1= p*x\n",
-      "##RESULTS\n",
-      "if (P1>P):\n",
-      "\tprint (\"Salesman is honest\")\n",
-      "\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "Salesman is honest\n"
-       ]
-      }
-     ],
-     "prompt_number": 6
-    }
-   ],
-   "metadata": {}
-  }
- ]
-}
-\ No newline at end of file
diff --git a/Thermodynamics:_From_concepts_to_applications/Chapter_3.ipynb b/Thermodynamics:_From_concepts_to_applications/Chapter_3.ipynb
deleted file mode 100755
index 013387dc..00000000
--- a/Thermodynamics:_From_concepts_to_applications/Chapter_3.ipynb
+++ /dev/null
@@ -1,220 +0,0 @@
-{
- "metadata": {
-  "name": "",
-  "signature": "sha256:f73954e8811e151c0b5b9ebbc8b4a25ed95b527042098578272743a33330e079"
- },
- "nbformat": 3,
- "nbformat_minor": 0,
- "worksheets": [
-  {
-   "cells": [
-    {
-     "cell_type": "heading",
-     "level": 1,
-     "metadata": {},
-     "source": [
-      "chapter3-heat"
-     ]
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Example 3 - Pg 24"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "##calculate the work interaction of spring\n",
-      "##initialisation of variables\n",
-      "m= 5 ##kg\n",
-      "g= 9.8 ##m/sec^2\n",
-      "k= 500 ##N/m\n",
-      "##CALCULATIONS\n",
-      "x= m*g/k\n",
-      "W= -m*g*x\n",
-      "##RESULTS\n",
-      "print'%s %.2f %s'% ('work interaction of spring = ',W,'J')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "work interaction of spring =  -4.80 J\n"
-       ]
-      }
-     ],
-     "prompt_number": 2
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Example 4 pg 25"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "##calculate the work done by the gas\n",
-      "##initialisation of variables\n",
-      "m= 500 ##kg\n",
-      "V= 50 ##L\n",
-      "P= 700 ##kPa\n",
-      "T= 25 ##C\n",
-      "P0= 100 ##kPa\n",
-      "g= 9.8 ##m/sec^2\n",
-      "A= 200 ##cm^2\n",
-      "V1= 100 ##L\n",
-      "##CALCULATIONS\n",
-      "pe= P0*math.pow(10,3)+(m*g/(A*(math.pow(10,-4))))\n",
-      "W= pe*(V1-V)*(math.pow(10,-6))\n",
-      "##RESULTS\n",
-      "print'%s %.2f %s'% ('work of the gas =',W,'kJ')"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "work of the gas = 17.25 kJ\n"
-       ]
-      }
-     ],
-     "prompt_number": 3
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Example 5 pg 27"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "##calcualte the energy change in process 1,2,3 and work in third process\n",
-      "##initialisation of variables\n",
-      "W= 5 ##kJ\n",
-      "Q= 23 ##kJ\n",
-      "Q1= -50 ##kJ\n",
-      "W1= 0 ##kJ\n",
-      "##CALCULATIONS\n",
-      "E1= Q-W\n",
-      "E2= Q1-W1\n",
-      "E3= -(E1+E2)\n",
-      "W3= -E3\n",
-      "##RESULTS\n",
-      "print '%s %.f %s'%('energy change in process 1 =',E1,'kJ')\n",
-      "print'%s %.f %s'% ('energy change in process 2 = ',E2,'kJ')\n",
-      "print '%s %.f %s'%('energy change in process 3 = ',E3,'kJ')\n",
-      "print '%s %.f %s'%('Work in third process = ',W3,'kJ')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "energy change in process 1 = 18 kJ\n",
-        "energy change in process 2 =  -50 kJ\n",
-        "energy change in process 3 =  32 kJ\n",
-        "Work in third process =  -32 kJ\n"
-       ]
-      }
-     ],
-     "prompt_number": 4
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Example 6 pg 28"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "##calculat the car mileage of given variable\n",
-      "##initialisation of variables\n",
-      "V= 12 ##km/L\n",
-      "##CALCULATIONS\n",
-      "MPG= V*3.7854/1.609\n",
-      "##RESULTS\n",
-      "print'%s %.2f %s'%('car mileage =',MPG,'MPG')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "car mileage = 28.23 MPG\n"
-       ]
-      }
-     ],
-     "prompt_number": 5
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Example 7 pg 28"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "##find whether salesman is honest or not\n",
-      "##initialisation of variables\n",
-      "p= 800 ##atm\n",
-      "P= 10000 ##psi\n",
-      "x= 14.696 ##psi/atm\n",
-      "##CALCULATIONS\n",
-      "P1= p*x\n",
-      "##RESULTS\n",
-      "if (P1>P):\n",
-      "\tprint (\"Salesman is honest\")\n",
-      "\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "Salesman is honest\n"
-       ]
-      }
-     ],
-     "prompt_number": 6
-    }
-   ],
-   "metadata": {}
-  }
- ]
-}
-\ No newline at end of file
diff --git a/Thermodynamics:_From_concepts_to_applications/Chapter_3_1.ipynb b/Thermodynamics:_From_concepts_to_applications/Chapter_3_1.ipynb
deleted file mode 100755
index f4e0af8d..00000000
--- a/Thermodynamics:_From_concepts_to_applications/Chapter_3_1.ipynb
+++ /dev/null
@@ -1,220 +0,0 @@
-{
- "metadata": {
-  "name": "",
-  "signature": "sha256:56539cb8410013a7d0be3df1cf1e85c7a8b906e5f399b600535904fe0fd98e57"
- },
- "nbformat": 3,
- "nbformat_minor": 0,
- "worksheets": [
-  {
-   "cells": [
-    {
-     "cell_type": "heading",
-     "level": 1,
-     "metadata": {},
-     "source": [
-      "chapter3-Work energy and heat first law of thermodynamics"
-     ]
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Example 3 - Pg 24"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "##calculate the work interaction of spring\n",
-      "##initialisation of variables\n",
-      "m= 5 ##kg\n",
-      "g= 9.8 ##m/sec^2\n",
-      "k= 500 ##N/m\n",
-      "##CALCULATIONS\n",
-      "x= m*g/k\n",
-      "W= -m*g*x\n",
-      "##RESULTS\n",
-      "print'%s %.2f %s'% ('work interaction of spring = ',W,'J')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "work interaction of spring =  -4.80 J\n"
-       ]
-      }
-     ],
-     "prompt_number": 2
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Example 4 pg 25"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "##calculate the work done by the gas\n",
-      "##initialisation of variables\n",
-      "m= 500 ##kg\n",
-      "V= 50 ##L\n",
-      "P= 700 ##kPa\n",
-      "T= 25 ##C\n",
-      "P0= 100 ##kPa\n",
-      "g= 9.8 ##m/sec^2\n",
-      "A= 200 ##cm^2\n",
-      "V1= 100 ##L\n",
-      "##CALCULATIONS\n",
-      "pe= P0*math.pow(10,3)+(m*g/(A*(math.pow(10,-4))))\n",
-      "W= pe*(V1-V)*(math.pow(10,-6))\n",
-      "##RESULTS\n",
-      "print'%s %.2f %s'% ('work of the gas =',W,'kJ')"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "work of the gas = 17.25 kJ\n"
-       ]
-      }
-     ],
-     "prompt_number": 3
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Example 5 pg 27"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "##calcualte the energy change in process 1,2,3 and work in third process\n",
-      "##initialisation of variables\n",
-      "W= 5 ##kJ\n",
-      "Q= 23 ##kJ\n",
-      "Q1= -50 ##kJ\n",
-      "W1= 0 ##kJ\n",
-      "##CALCULATIONS\n",
-      "E1= Q-W\n",
-      "E2= Q1-W1\n",
-      "E3= -(E1+E2)\n",
-      "W3= -E3\n",
-      "##RESULTS\n",
-      "print '%s %.f %s'%('energy change in process 1 =',E1,'kJ')\n",
-      "print'%s %.f %s'% ('energy change in process 2 = ',E2,'kJ')\n",
-      "print '%s %.f %s'%('energy change in process 3 = ',E3,'kJ')\n",
-      "print '%s %.f %s'%('Work in third process = ',W3,'kJ')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "energy change in process 1 = 18 kJ\n",
-        "energy change in process 2 =  -50 kJ\n",
-        "energy change in process 3 =  32 kJ\n",
-        "Work in third process =  -32 kJ\n"
-       ]
-      }
-     ],
-     "prompt_number": 4
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Example 6 pg 28"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "##calculat the car mileage of given variable\n",
-      "##initialisation of variables\n",
-      "V= 12 ##km/L\n",
-      "##CALCULATIONS\n",
-      "MPG= V*3.7854/1.609\n",
-      "##RESULTS\n",
-      "print'%s %.2f %s'%('car mileage =',MPG,'MPG')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "car mileage = 28.23 MPG\n"
-       ]
-      }
-     ],
-     "prompt_number": 5
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Example 7 pg 28"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "##find whether salesman is honest or not\n",
-      "##initialisation of variables\n",
-      "p= 800 ##atm\n",
-      "P= 10000 ##psi\n",
-      "x= 14.696 ##psi/atm\n",
-      "##CALCULATIONS\n",
-      "P1= p*x\n",
-      "##RESULTS\n",
-      "if (P1>P):\n",
-      "\tprint (\"Salesman is honest\")\n",
-      "\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "Salesman is honest\n"
-       ]
-      }
-     ],
-     "prompt_number": 6
-    }
-   ],
-   "metadata": {}
-  }
- ]
-}
-\ No newline at end of file
diff --git a/Thermodynamics:_From_concepts_to_applications/Chapter_3_2.ipynb b/Thermodynamics:_From_concepts_to_applications/Chapter_3_2.ipynb
deleted file mode 100755
index f4e0af8d..00000000
--- a/Thermodynamics:_From_concepts_to_applications/Chapter_3_2.ipynb
+++ /dev/null
@@ -1,220 +0,0 @@
-{
- "metadata": {
-  "name": "",
-  "signature": "sha256:56539cb8410013a7d0be3df1cf1e85c7a8b906e5f399b600535904fe0fd98e57"
- },
- "nbformat": 3,
- "nbformat_minor": 0,
- "worksheets": [
-  {
-   "cells": [
-    {
-     "cell_type": "heading",
-     "level": 1,
-     "metadata": {},
-     "source": [
-      "chapter3-Work energy and heat first law of thermodynamics"
-     ]
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Example 3 - Pg 24"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "##calculate the work interaction of spring\n",
-      "##initialisation of variables\n",
-      "m= 5 ##kg\n",
-      "g= 9.8 ##m/sec^2\n",
-      "k= 500 ##N/m\n",
-      "##CALCULATIONS\n",
-      "x= m*g/k\n",
-      "W= -m*g*x\n",
-      "##RESULTS\n",
-      "print'%s %.2f %s'% ('work interaction of spring = ',W,'J')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "work interaction of spring =  -4.80 J\n"
-       ]
-      }
-     ],
-     "prompt_number": 2
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Example 4 pg 25"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "##calculate the work done by the gas\n",
-      "##initialisation of variables\n",
-      "m= 500 ##kg\n",
-      "V= 50 ##L\n",
-      "P= 700 ##kPa\n",
-      "T= 25 ##C\n",
-      "P0= 100 ##kPa\n",
-      "g= 9.8 ##m/sec^2\n",
-      "A= 200 ##cm^2\n",
-      "V1= 100 ##L\n",
-      "##CALCULATIONS\n",
-      "pe= P0*math.pow(10,3)+(m*g/(A*(math.pow(10,-4))))\n",
-      "W= pe*(V1-V)*(math.pow(10,-6))\n",
-      "##RESULTS\n",
-      "print'%s %.2f %s'% ('work of the gas =',W,'kJ')"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "work of the gas = 17.25 kJ\n"
-       ]
-      }
-     ],
-     "prompt_number": 3
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Example 5 pg 27"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "##calcualte the energy change in process 1,2,3 and work in third process\n",
-      "##initialisation of variables\n",
-      "W= 5 ##kJ\n",
-      "Q= 23 ##kJ\n",
-      "Q1= -50 ##kJ\n",
-      "W1= 0 ##kJ\n",
-      "##CALCULATIONS\n",
-      "E1= Q-W\n",
-      "E2= Q1-W1\n",
-      "E3= -(E1+E2)\n",
-      "W3= -E3\n",
-      "##RESULTS\n",
-      "print '%s %.f %s'%('energy change in process 1 =',E1,'kJ')\n",
-      "print'%s %.f %s'% ('energy change in process 2 = ',E2,'kJ')\n",
-      "print '%s %.f %s'%('energy change in process 3 = ',E3,'kJ')\n",
-      "print '%s %.f %s'%('Work in third process = ',W3,'kJ')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "energy change in process 1 = 18 kJ\n",
-        "energy change in process 2 =  -50 kJ\n",
-        "energy change in process 3 =  32 kJ\n",
-        "Work in third process =  -32 kJ\n"
-       ]
-      }
-     ],
-     "prompt_number": 4
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Example 6 pg 28"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "##calculat the car mileage of given variable\n",
-      "##initialisation of variables\n",
-      "V= 12 ##km/L\n",
-      "##CALCULATIONS\n",
-      "MPG= V*3.7854/1.609\n",
-      "##RESULTS\n",
-      "print'%s %.2f %s'%('car mileage =',MPG,'MPG')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "car mileage = 28.23 MPG\n"
-       ]
-      }
-     ],
-     "prompt_number": 5
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Example 7 pg 28"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "##find whether salesman is honest or not\n",
-      "##initialisation of variables\n",
-      "p= 800 ##atm\n",
-      "P= 10000 ##psi\n",
-      "x= 14.696 ##psi/atm\n",
-      "##CALCULATIONS\n",
-      "P1= p*x\n",
-      "##RESULTS\n",
-      "if (P1>P):\n",
-      "\tprint (\"Salesman is honest\")\n",
-      "\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "Salesman is honest\n"
-       ]
-      }
-     ],
-     "prompt_number": 6
-    }
-   ],
-   "metadata": {}
-  }
- ]
-}
-\ No newline at end of file
diff --git a/Thermodynamics:_From_concepts_to_applications/Chapter_4.ipynb b/Thermodynamics:_From_concepts_to_applications/Chapter_4.ipynb
deleted file mode 100755
index b4cbb2bf..00000000
--- a/Thermodynamics:_From_concepts_to_applications/Chapter_4.ipynb
+++ /dev/null
@@ -1,466 +0,0 @@
-{
- "metadata": {
-  "name": "",
-  "signature": "sha256:f794a4d18f36c13ddab8d6024721da6bc9aca8b98b0260eaf3e1fb73a8bd345d"
- },
- "nbformat": 3,
- "nbformat_minor": 0,
- "worksheets": [
-  {
-   "cells": [
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Chapter 4-simple systems"
-     ]
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Example1-pg43"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "#caluclate the heat interaction and temperature rise\n",
-      "##initialisation of variables\n",
-      "m= 5000. ##kg\n",
-      "cp= 1.4 ##kJ/kg K\n",
-      "T2= 27.6 ##K\n",
-      "T1= 22. ##K\n",
-      "t= 40. ##min\n",
-      "P= 20. ##kW\n",
-      "##CALCULATIONS\n",
-      "H= m*cp*(T2-T1)\n",
-      "W= -P*t*60\n",
-      "Q= H+W\n",
-      "dT= -W/(m*cp)\n",
-      "##RESULTS\n",
-      "print'%s %.f %s'%('heat interaction =',Q,'kJ')\n",
-      "print'%s %.2f %s'%('Temperature rise = ',dT,'C')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "heat interaction = -8800 kJ\n",
-        "Temperature rise =  6.86 C\n"
-       ]
-      }
-     ],
-     "prompt_number": 15
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "example 2-pg 49\n"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "#caluclate the volumes and internal energy and enthaply\n",
-      "##initialisation of variables\n",
-      "T= 300. ##C\n",
-      "p= 2. ##Mpa\n",
-      "T1= 300. ##C\n",
-      "p1= 20.##Mpa\n",
-      "T2= 300. ##C\n",
-      "p2= 8.501 ##Mpa\n",
-      "##CALCULATIONS\n",
-      "v= 0.12547\n",
-      "v1= 0.00136\n",
-      "u= 2772.6\n",
-      "u1= 1306.1\n",
-      "h= 3023.5\n",
-      "h1= 1333.3\n",
-      "##RESULTS\n",
-      "print'%s %.5f %s'%('volume =',v,'m^3/kg')\n",
-      "print'%s %.5f %s'%('volume =',v1,'m^3/kg')\n",
-      "print'%s %.1f %s'%('internal energy = ',u,'kJ/kg')\n",
-      "print'%s %.1f %s'%('internal energy =',u1,'kJ/kg')\n",
-      "print'%s %.1f %s'%('enthalpy =',h,'kJ/kg')\n",
-      "print'%s %.f %s'%('enthalpy = ',h1,'kJ/kg')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "volume = 0.12547 m^3/kg\n",
-        "volume = 0.00136 m^3/kg\n",
-        "internal energy =  2772.6 kJ/kg\n",
-        "internal energy = 1306.1 kJ/kg\n",
-        "enthalpy = 3023.5 kJ/kg\n",
-        "enthalpy =  1333 kJ/kg\n"
-       ]
-      }
-     ],
-     "prompt_number": 17
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "example3-pg49\n"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "#calculate the volume and internal energy and enthalpy\n",
-      "##initialisation of variables\n",
-      "vf= 0.001404 ##m^3/kg\n",
-      "x= 0.8\n",
-      "vg= 0.02167 ##m^3/kg\n",
-      "uf= 1332. ##kJ/kg\n",
-      "ug= 1231. ##kJ/kg\n",
-      "hf= 1344. ##kJ/kg\n",
-      "hg= 1404.9 ##kJ/kg\n",
-      "##CALCULATIONS\n",
-      "v= vf+x*(vg-vf)\n",
-      "u= uf+x*ug\n",
-      "h= hf+x*hg\n",
-      "##RESULTS\n",
-      "print'%s %.5f %s'%('volume =',v,'m^3/kg')\n",
-      "print'%s %.1f %s'%('internal energy =',u,'kJ/kg')\n",
-      "print'%s %.1f %s'%('enthalpy =',h, 'kJ/kg')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "volume = 0.01762 m^3/kg\n",
-        "internal energy = 2316.8 kJ/kg\n",
-        "enthalpy = 2467.9 kJ/kg\n"
-       ]
-      }
-     ],
-     "prompt_number": 5
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Example4-pg 52"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "#calculate the specific volume and internal energy and enthalpy and entropy\n",
-      "##initialisation of variables\n",
-      "T= 296. ##K\n",
-      "T1= 250. ##K\n",
-      "T2= 300. ##K\n",
-      "v= 0.1257 ##m^3/kg\n",
-      "v1= 0.11144 ##m^3/kg\n",
-      "u1= 27772.6 ##kJ/kg\n",
-      "u2= 2679.6 ##kJ/kg\n",
-      "h1= 3023.5 ##kJ/kg\n",
-      "h2= 2902.5 ##kJ/kg\n",
-      "s1= 6.7664 ##kJ/kg K\n",
-      "s2= 6.5433 ##kJ/kg K\n",
-      "##CALCULATIONS\n",
-      "a1= (T-T1)/(T2-T1)\n",
-      "a2= 1-a1\n",
-      "V= a1*v+a2*v1\n",
-      "U= a1*u1+a2*u2\n",
-      "H= a1*h1+a2*h2\n",
-      "S= a1*s1+a2*s2\n",
-      "##RESULTS\n",
-      "print'%s %.3f %s'%('a2 = ',a2,'')\n",
-      "print'%s %.5f %s'%('specific volume =',V,'m^3/kg')\n",
-      "print'%s %.1f %s'%('internal energy =',U,'kJ/kg')\n",
-      "print'%s %.1f %s'%('enthalpy =',H,'kJ/kg')\n",
-      "print'%s %.1f %s'%('Entropy =',S,'kJ/kg')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "a2 =  0.080 \n",
-        "specific volume = 0.12456 m^3/kg\n",
-        "internal energy = 25765.2 kJ/kg\n",
-        "enthalpy = 3013.8 kJ/kg\n",
-        "Entropy = 6.7 kJ/kg\n"
-       ]
-      }
-     ],
-     "prompt_number": 6
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Exapmle5-pg54"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "#calculate a2 and internal enerjy\n",
-      "##initialisation of variables\n",
-      "v= 0.15 ##m^3/kg\n",
-      "v1= 0.13857 ##m^3/kg\n",
-      "v2= 0.1512 ##m^3/kg\n",
-      "v3= 0.050 ##m^3##kg\n",
-      "vf= 0.001177 ##m^3/kg\n",
-      "vg= 0.09963 ##m^3/kg\n",
-      "uf= 906.44 ##kJ/kg\n",
-      "ufg= 1693.8 ##kJ/kg\n",
-      "##CALCULATIONS\n",
-      "a1= (v-v1)/(v2-v1)\n",
-      "a2= 1-a1\n",
-      "x= (v3-vf)/(vg-vf)\n",
-      "u= uf+x*ufg\n",
-      "##RESULTS\n",
-      "print'%s %.3f %s'%('a2 =',a2,'')\n",
-      "print'%s %.1f %s'%('internal energy =',u,'kJ/kg')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "a2 = 0.095 \n",
-        "internal energy = 1746.4 kJ/kg\n"
-       ]
-      }
-     ],
-     "prompt_number": 7
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Example6-pg52"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "#calculate pressure and temperature\n",
-      "##initialisation of variables\n",
-      "T= 250.##C\n",
-      "T1= 300. ##C\n",
-      "v300= 0.6548 ##m^3/kg\n",
-      "v250= 0.591 ##m^3/kg\n",
-      "v= 0.6 ##m^3/kg\n",
-      "u= 3000. ##kJ/kg\n",
-      "u250= 2726.1 ##kJ/kg\n",
-      "u300= 2804.8 ##kJ/kg\n",
-      "T2= 510.30 \n",
-      "u2= 3145.26 ##kJ/kg\n",
-      "p= 0.4 ##Mpa\n",
-      "p2= 0.2 ##Mpa\n",
-      "##CALCULATIONS\n",
-      "T1= T1+((v-v250)/(v300-v250))*(T2-T)\n",
-      "u1= u250+((v-v250)/(v300-v250))*(u300-u250)\n",
-      "du= u1-u\n",
-      "p1= p+((u-u1)/(u2-u1))*p2\n",
-      "##RESULTS\n",
-      "print'%s %.3f %s'%('pressure =',p1,'Mpa')\n",
-      "print'%s %.f %s'%('temperature =',T2,'C')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "pressure = 0.529 Mpa\n",
-        "temperature = 510 C\n"
-       ]
-      }
-     ],
-     "prompt_number": 8
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Example 7-pg54"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "#calculate work and heat interaction\n",
-      "##initialisation of variables\n",
-      "V= 0.2 ##m^3\n",
-      "v1= 0.02995 ##m^3/kg\n",
-      "u2= 2826.7 ##kJ/kg\n",
-      "u1= 2747.7 ##kJ/kg\n",
-      "h2= 3092.5 ##kJ/kg\n",
-      "h1= 2987.3 ##kJ/kg\n",
-      "p= 4 ##Mpa\n",
-      "v2= 0.06645 ##m^3/kg\n",
-      "v1= 0.02995 ##m^3/kg\n",
-      "##CALCULATIONS\n",
-      "m= V/v1\n",
-      "U= m*(u2-u1)\n",
-      "H= m*(h2-h1)\n",
-      "W= m*p*10*10*10*(v2-v1)\n",
-      "Q= U+W\n",
-      "##RESULTS\n",
-      "print'%s %.1f %s'%('work =',W,'kJ') \n",
-      "print'%s %.1f %s'%('heat interaction =',Q,'kJ')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "work = 975.0 kJ\n",
-        "heat interaction = 1502.5 kJ\n"
-       ]
-      }
-     ],
-     "prompt_number": 10
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Example8-pg 55"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "#calculate work and heat interaction\n",
-      "##initialisation of variables\n",
-      "m= 6.678 ##kg\n",
-      "u2= 2826.7 ##kJ/kg\n",
-      "u1= 2747.7 ##kJ/kg\n",
-      "p1= 8. ##Mpa\n",
-      "p2= 7. ##Mpa\n",
-      "p3= 6. ##Mpa\n",
-      "p4= 5. ##Mpa\n",
-      "p5= 4. ##Mpa\n",
-      "v1= 29.95 ##L/kg\n",
-      "v2= 35.24 ##L/kg\n",
-      "v3= 42.23 ##L/kg\n",
-      "v4= 51.94 ##L/kg\n",
-      "v5= 66.45 ##L/kg\n",
-      "##CALCULATIONS\n",
-      "U= m*(u2-u1)\n",
-      "W= m*0.5*((p1+p2)*(v2-v1)+(p2+p3)*(v3-v2)+(p3+p4)*(v4-v3)+(p4+p5)*(v5-v4))\n",
-      "Q=U+W\n",
-      "##RESULTS\n",
-      "print'%s %.1f %s'%('work =',W,'kJ') \n",
-      "print'%s %.f %s'%('heat interaction =',Q,'kJ') \n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "work = 1361.0 kJ\n",
-        "heat interaction = 1889 kJ\n"
-       ]
-      }
-     ],
-     "prompt_number": 12
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Example 9-pg56\n"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "#calculate final pressure and enthalpy and etropy\n",
-      "##initialisation of variables\n",
-      "p0= 100. ##kpa\n",
-      "A= 0.1 ##m^2\n",
-      "F= 20. ##kN\n",
-      "m3= 0.8873 ##kg\n",
-      "m1= 1.1384 ##kg\n",
-      "m2= 0.2511 ##kg\n",
-      "u1= 3116.2 ##kJ/kg\n",
-      "u2= 2728.7 ##kJ/kg\n",
-      "v3= 0.9942 ##m^3/kg\n",
-      "##CALCULATIONS\n",
-      "pe= (p0+(F/A))/1000\n",
-      "h3= (m1*u1-m2*u2)/m3\n",
-      "z3= m3*v3/A\n",
-      "##RESULTS\n",
-      "print'%s %.1f %s'%('final pressure =',pe,'Mpa') \n",
-      "print'%s %.1f %s'%('enthalpy = ',h3,'kJ/kg') \n",
-      "print'%s %.2f %s'%('piston rise =',z3,'m') \n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "final pressure = 0.3 Mpa\n",
-        "enthalpy =  3225.9 kJ/kg\n",
-        "piston rise = 8.82 m\n"
-       ]
-      }
-     ],
-     "prompt_number": 14
-    }
-   ],
-   "metadata": {}
-  }
- ]
-}
-\ No newline at end of file
diff --git a/Thermodynamics:_From_concepts_to_applications/Chapter_4_-Simple_systems.ipynb b/Thermodynamics:_From_concepts_to_applications/Chapter_4_-Simple_systems.ipynb
deleted file mode 100755
index b4cbb2bf..00000000
--- a/Thermodynamics:_From_concepts_to_applications/Chapter_4_-Simple_systems.ipynb
+++ /dev/null
@@ -1,466 +0,0 @@
-{
- "metadata": {
-  "name": "",
-  "signature": "sha256:f794a4d18f36c13ddab8d6024721da6bc9aca8b98b0260eaf3e1fb73a8bd345d"
- },
- "nbformat": 3,
- "nbformat_minor": 0,
- "worksheets": [
-  {
-   "cells": [
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Chapter 4-simple systems"
-     ]
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Example1-pg43"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "#caluclate the heat interaction and temperature rise\n",
-      "##initialisation of variables\n",
-      "m= 5000. ##kg\n",
-      "cp= 1.4 ##kJ/kg K\n",
-      "T2= 27.6 ##K\n",
-      "T1= 22. ##K\n",
-      "t= 40. ##min\n",
-      "P= 20. ##kW\n",
-      "##CALCULATIONS\n",
-      "H= m*cp*(T2-T1)\n",
-      "W= -P*t*60\n",
-      "Q= H+W\n",
-      "dT= -W/(m*cp)\n",
-      "##RESULTS\n",
-      "print'%s %.f %s'%('heat interaction =',Q,'kJ')\n",
-      "print'%s %.2f %s'%('Temperature rise = ',dT,'C')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "heat interaction = -8800 kJ\n",
-        "Temperature rise =  6.86 C\n"
-       ]
-      }
-     ],
-     "prompt_number": 15
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "example 2-pg 49\n"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "#caluclate the volumes and internal energy and enthaply\n",
-      "##initialisation of variables\n",
-      "T= 300. ##C\n",
-      "p= 2. ##Mpa\n",
-      "T1= 300. ##C\n",
-      "p1= 20.##Mpa\n",
-      "T2= 300. ##C\n",
-      "p2= 8.501 ##Mpa\n",
-      "##CALCULATIONS\n",
-      "v= 0.12547\n",
-      "v1= 0.00136\n",
-      "u= 2772.6\n",
-      "u1= 1306.1\n",
-      "h= 3023.5\n",
-      "h1= 1333.3\n",
-      "##RESULTS\n",
-      "print'%s %.5f %s'%('volume =',v,'m^3/kg')\n",
-      "print'%s %.5f %s'%('volume =',v1,'m^3/kg')\n",
-      "print'%s %.1f %s'%('internal energy = ',u,'kJ/kg')\n",
-      "print'%s %.1f %s'%('internal energy =',u1,'kJ/kg')\n",
-      "print'%s %.1f %s'%('enthalpy =',h,'kJ/kg')\n",
-      "print'%s %.f %s'%('enthalpy = ',h1,'kJ/kg')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "volume = 0.12547 m^3/kg\n",
-        "volume = 0.00136 m^3/kg\n",
-        "internal energy =  2772.6 kJ/kg\n",
-        "internal energy = 1306.1 kJ/kg\n",
-        "enthalpy = 3023.5 kJ/kg\n",
-        "enthalpy =  1333 kJ/kg\n"
-       ]
-      }
-     ],
-     "prompt_number": 17
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "example3-pg49\n"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "#calculate the volume and internal energy and enthalpy\n",
-      "##initialisation of variables\n",
-      "vf= 0.001404 ##m^3/kg\n",
-      "x= 0.8\n",
-      "vg= 0.02167 ##m^3/kg\n",
-      "uf= 1332. ##kJ/kg\n",
-      "ug= 1231. ##kJ/kg\n",
-      "hf= 1344. ##kJ/kg\n",
-      "hg= 1404.9 ##kJ/kg\n",
-      "##CALCULATIONS\n",
-      "v= vf+x*(vg-vf)\n",
-      "u= uf+x*ug\n",
-      "h= hf+x*hg\n",
-      "##RESULTS\n",
-      "print'%s %.5f %s'%('volume =',v,'m^3/kg')\n",
-      "print'%s %.1f %s'%('internal energy =',u,'kJ/kg')\n",
-      "print'%s %.1f %s'%('enthalpy =',h, 'kJ/kg')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "volume = 0.01762 m^3/kg\n",
-        "internal energy = 2316.8 kJ/kg\n",
-        "enthalpy = 2467.9 kJ/kg\n"
-       ]
-      }
-     ],
-     "prompt_number": 5
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Example4-pg 52"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "#calculate the specific volume and internal energy and enthalpy and entropy\n",
-      "##initialisation of variables\n",
-      "T= 296. ##K\n",
-      "T1= 250. ##K\n",
-      "T2= 300. ##K\n",
-      "v= 0.1257 ##m^3/kg\n",
-      "v1= 0.11144 ##m^3/kg\n",
-      "u1= 27772.6 ##kJ/kg\n",
-      "u2= 2679.6 ##kJ/kg\n",
-      "h1= 3023.5 ##kJ/kg\n",
-      "h2= 2902.5 ##kJ/kg\n",
-      "s1= 6.7664 ##kJ/kg K\n",
-      "s2= 6.5433 ##kJ/kg K\n",
-      "##CALCULATIONS\n",
-      "a1= (T-T1)/(T2-T1)\n",
-      "a2= 1-a1\n",
-      "V= a1*v+a2*v1\n",
-      "U= a1*u1+a2*u2\n",
-      "H= a1*h1+a2*h2\n",
-      "S= a1*s1+a2*s2\n",
-      "##RESULTS\n",
-      "print'%s %.3f %s'%('a2 = ',a2,'')\n",
-      "print'%s %.5f %s'%('specific volume =',V,'m^3/kg')\n",
-      "print'%s %.1f %s'%('internal energy =',U,'kJ/kg')\n",
-      "print'%s %.1f %s'%('enthalpy =',H,'kJ/kg')\n",
-      "print'%s %.1f %s'%('Entropy =',S,'kJ/kg')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "a2 =  0.080 \n",
-        "specific volume = 0.12456 m^3/kg\n",
-        "internal energy = 25765.2 kJ/kg\n",
-        "enthalpy = 3013.8 kJ/kg\n",
-        "Entropy = 6.7 kJ/kg\n"
-       ]
-      }
-     ],
-     "prompt_number": 6
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Exapmle5-pg54"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "#calculate a2 and internal enerjy\n",
-      "##initialisation of variables\n",
-      "v= 0.15 ##m^3/kg\n",
-      "v1= 0.13857 ##m^3/kg\n",
-      "v2= 0.1512 ##m^3/kg\n",
-      "v3= 0.050 ##m^3##kg\n",
-      "vf= 0.001177 ##m^3/kg\n",
-      "vg= 0.09963 ##m^3/kg\n",
-      "uf= 906.44 ##kJ/kg\n",
-      "ufg= 1693.8 ##kJ/kg\n",
-      "##CALCULATIONS\n",
-      "a1= (v-v1)/(v2-v1)\n",
-      "a2= 1-a1\n",
-      "x= (v3-vf)/(vg-vf)\n",
-      "u= uf+x*ufg\n",
-      "##RESULTS\n",
-      "print'%s %.3f %s'%('a2 =',a2,'')\n",
-      "print'%s %.1f %s'%('internal energy =',u,'kJ/kg')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "a2 = 0.095 \n",
-        "internal energy = 1746.4 kJ/kg\n"
-       ]
-      }
-     ],
-     "prompt_number": 7
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Example6-pg52"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "#calculate pressure and temperature\n",
-      "##initialisation of variables\n",
-      "T= 250.##C\n",
-      "T1= 300. ##C\n",
-      "v300= 0.6548 ##m^3/kg\n",
-      "v250= 0.591 ##m^3/kg\n",
-      "v= 0.6 ##m^3/kg\n",
-      "u= 3000. ##kJ/kg\n",
-      "u250= 2726.1 ##kJ/kg\n",
-      "u300= 2804.8 ##kJ/kg\n",
-      "T2= 510.30 \n",
-      "u2= 3145.26 ##kJ/kg\n",
-      "p= 0.4 ##Mpa\n",
-      "p2= 0.2 ##Mpa\n",
-      "##CALCULATIONS\n",
-      "T1= T1+((v-v250)/(v300-v250))*(T2-T)\n",
-      "u1= u250+((v-v250)/(v300-v250))*(u300-u250)\n",
-      "du= u1-u\n",
-      "p1= p+((u-u1)/(u2-u1))*p2\n",
-      "##RESULTS\n",
-      "print'%s %.3f %s'%('pressure =',p1,'Mpa')\n",
-      "print'%s %.f %s'%('temperature =',T2,'C')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "pressure = 0.529 Mpa\n",
-        "temperature = 510 C\n"
-       ]
-      }
-     ],
-     "prompt_number": 8
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Example 7-pg54"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "#calculate work and heat interaction\n",
-      "##initialisation of variables\n",
-      "V= 0.2 ##m^3\n",
-      "v1= 0.02995 ##m^3/kg\n",
-      "u2= 2826.7 ##kJ/kg\n",
-      "u1= 2747.7 ##kJ/kg\n",
-      "h2= 3092.5 ##kJ/kg\n",
-      "h1= 2987.3 ##kJ/kg\n",
-      "p= 4 ##Mpa\n",
-      "v2= 0.06645 ##m^3/kg\n",
-      "v1= 0.02995 ##m^3/kg\n",
-      "##CALCULATIONS\n",
-      "m= V/v1\n",
-      "U= m*(u2-u1)\n",
-      "H= m*(h2-h1)\n",
-      "W= m*p*10*10*10*(v2-v1)\n",
-      "Q= U+W\n",
-      "##RESULTS\n",
-      "print'%s %.1f %s'%('work =',W,'kJ') \n",
-      "print'%s %.1f %s'%('heat interaction =',Q,'kJ')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "work = 975.0 kJ\n",
-        "heat interaction = 1502.5 kJ\n"
-       ]
-      }
-     ],
-     "prompt_number": 10
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Example8-pg 55"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "#calculate work and heat interaction\n",
-      "##initialisation of variables\n",
-      "m= 6.678 ##kg\n",
-      "u2= 2826.7 ##kJ/kg\n",
-      "u1= 2747.7 ##kJ/kg\n",
-      "p1= 8. ##Mpa\n",
-      "p2= 7. ##Mpa\n",
-      "p3= 6. ##Mpa\n",
-      "p4= 5. ##Mpa\n",
-      "p5= 4. ##Mpa\n",
-      "v1= 29.95 ##L/kg\n",
-      "v2= 35.24 ##L/kg\n",
-      "v3= 42.23 ##L/kg\n",
-      "v4= 51.94 ##L/kg\n",
-      "v5= 66.45 ##L/kg\n",
-      "##CALCULATIONS\n",
-      "U= m*(u2-u1)\n",
-      "W= m*0.5*((p1+p2)*(v2-v1)+(p2+p3)*(v3-v2)+(p3+p4)*(v4-v3)+(p4+p5)*(v5-v4))\n",
-      "Q=U+W\n",
-      "##RESULTS\n",
-      "print'%s %.1f %s'%('work =',W,'kJ') \n",
-      "print'%s %.f %s'%('heat interaction =',Q,'kJ') \n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "work = 1361.0 kJ\n",
-        "heat interaction = 1889 kJ\n"
-       ]
-      }
-     ],
-     "prompt_number": 12
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Example 9-pg56\n"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "#calculate final pressure and enthalpy and etropy\n",
-      "##initialisation of variables\n",
-      "p0= 100. ##kpa\n",
-      "A= 0.1 ##m^2\n",
-      "F= 20. ##kN\n",
-      "m3= 0.8873 ##kg\n",
-      "m1= 1.1384 ##kg\n",
-      "m2= 0.2511 ##kg\n",
-      "u1= 3116.2 ##kJ/kg\n",
-      "u2= 2728.7 ##kJ/kg\n",
-      "v3= 0.9942 ##m^3/kg\n",
-      "##CALCULATIONS\n",
-      "pe= (p0+(F/A))/1000\n",
-      "h3= (m1*u1-m2*u2)/m3\n",
-      "z3= m3*v3/A\n",
-      "##RESULTS\n",
-      "print'%s %.1f %s'%('final pressure =',pe,'Mpa') \n",
-      "print'%s %.1f %s'%('enthalpy = ',h3,'kJ/kg') \n",
-      "print'%s %.2f %s'%('piston rise =',z3,'m') \n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "final pressure = 0.3 Mpa\n",
-        "enthalpy =  3225.9 kJ/kg\n",
-        "piston rise = 8.82 m\n"
-       ]
-      }
-     ],
-     "prompt_number": 14
-    }
-   ],
-   "metadata": {}
-  }
- ]
-}
-\ No newline at end of file
diff --git a/Thermodynamics:_From_concepts_to_applications/Chapter_4_.ipynb b/Thermodynamics:_From_concepts_to_applications/Chapter_4_.ipynb
deleted file mode 100755
index b4cbb2bf..00000000
--- a/Thermodynamics:_From_concepts_to_applications/Chapter_4_.ipynb
+++ /dev/null
@@ -1,466 +0,0 @@
-{
- "metadata": {
-  "name": "",
-  "signature": "sha256:f794a4d18f36c13ddab8d6024721da6bc9aca8b98b0260eaf3e1fb73a8bd345d"
- },
- "nbformat": 3,
- "nbformat_minor": 0,
- "worksheets": [
-  {
-   "cells": [
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Chapter 4-simple systems"
-     ]
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Example1-pg43"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "#caluclate the heat interaction and temperature rise\n",
-      "##initialisation of variables\n",
-      "m= 5000. ##kg\n",
-      "cp= 1.4 ##kJ/kg K\n",
-      "T2= 27.6 ##K\n",
-      "T1= 22. ##K\n",
-      "t= 40. ##min\n",
-      "P= 20. ##kW\n",
-      "##CALCULATIONS\n",
-      "H= m*cp*(T2-T1)\n",
-      "W= -P*t*60\n",
-      "Q= H+W\n",
-      "dT= -W/(m*cp)\n",
-      "##RESULTS\n",
-      "print'%s %.f %s'%('heat interaction =',Q,'kJ')\n",
-      "print'%s %.2f %s'%('Temperature rise = ',dT,'C')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "heat interaction = -8800 kJ\n",
-        "Temperature rise =  6.86 C\n"
-       ]
-      }
-     ],
-     "prompt_number": 15
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "example 2-pg 49\n"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "#caluclate the volumes and internal energy and enthaply\n",
-      "##initialisation of variables\n",
-      "T= 300. ##C\n",
-      "p= 2. ##Mpa\n",
-      "T1= 300. ##C\n",
-      "p1= 20.##Mpa\n",
-      "T2= 300. ##C\n",
-      "p2= 8.501 ##Mpa\n",
-      "##CALCULATIONS\n",
-      "v= 0.12547\n",
-      "v1= 0.00136\n",
-      "u= 2772.6\n",
-      "u1= 1306.1\n",
-      "h= 3023.5\n",
-      "h1= 1333.3\n",
-      "##RESULTS\n",
-      "print'%s %.5f %s'%('volume =',v,'m^3/kg')\n",
-      "print'%s %.5f %s'%('volume =',v1,'m^3/kg')\n",
-      "print'%s %.1f %s'%('internal energy = ',u,'kJ/kg')\n",
-      "print'%s %.1f %s'%('internal energy =',u1,'kJ/kg')\n",
-      "print'%s %.1f %s'%('enthalpy =',h,'kJ/kg')\n",
-      "print'%s %.f %s'%('enthalpy = ',h1,'kJ/kg')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "volume = 0.12547 m^3/kg\n",
-        "volume = 0.00136 m^3/kg\n",
-        "internal energy =  2772.6 kJ/kg\n",
-        "internal energy = 1306.1 kJ/kg\n",
-        "enthalpy = 3023.5 kJ/kg\n",
-        "enthalpy =  1333 kJ/kg\n"
-       ]
-      }
-     ],
-     "prompt_number": 17
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "example3-pg49\n"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "#calculate the volume and internal energy and enthalpy\n",
-      "##initialisation of variables\n",
-      "vf= 0.001404 ##m^3/kg\n",
-      "x= 0.8\n",
-      "vg= 0.02167 ##m^3/kg\n",
-      "uf= 1332. ##kJ/kg\n",
-      "ug= 1231. ##kJ/kg\n",
-      "hf= 1344. ##kJ/kg\n",
-      "hg= 1404.9 ##kJ/kg\n",
-      "##CALCULATIONS\n",
-      "v= vf+x*(vg-vf)\n",
-      "u= uf+x*ug\n",
-      "h= hf+x*hg\n",
-      "##RESULTS\n",
-      "print'%s %.5f %s'%('volume =',v,'m^3/kg')\n",
-      "print'%s %.1f %s'%('internal energy =',u,'kJ/kg')\n",
-      "print'%s %.1f %s'%('enthalpy =',h, 'kJ/kg')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "volume = 0.01762 m^3/kg\n",
-        "internal energy = 2316.8 kJ/kg\n",
-        "enthalpy = 2467.9 kJ/kg\n"
-       ]
-      }
-     ],
-     "prompt_number": 5
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Example4-pg 52"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "#calculate the specific volume and internal energy and enthalpy and entropy\n",
-      "##initialisation of variables\n",
-      "T= 296. ##K\n",
-      "T1= 250. ##K\n",
-      "T2= 300. ##K\n",
-      "v= 0.1257 ##m^3/kg\n",
-      "v1= 0.11144 ##m^3/kg\n",
-      "u1= 27772.6 ##kJ/kg\n",
-      "u2= 2679.6 ##kJ/kg\n",
-      "h1= 3023.5 ##kJ/kg\n",
-      "h2= 2902.5 ##kJ/kg\n",
-      "s1= 6.7664 ##kJ/kg K\n",
-      "s2= 6.5433 ##kJ/kg K\n",
-      "##CALCULATIONS\n",
-      "a1= (T-T1)/(T2-T1)\n",
-      "a2= 1-a1\n",
-      "V= a1*v+a2*v1\n",
-      "U= a1*u1+a2*u2\n",
-      "H= a1*h1+a2*h2\n",
-      "S= a1*s1+a2*s2\n",
-      "##RESULTS\n",
-      "print'%s %.3f %s'%('a2 = ',a2,'')\n",
-      "print'%s %.5f %s'%('specific volume =',V,'m^3/kg')\n",
-      "print'%s %.1f %s'%('internal energy =',U,'kJ/kg')\n",
-      "print'%s %.1f %s'%('enthalpy =',H,'kJ/kg')\n",
-      "print'%s %.1f %s'%('Entropy =',S,'kJ/kg')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "a2 =  0.080 \n",
-        "specific volume = 0.12456 m^3/kg\n",
-        "internal energy = 25765.2 kJ/kg\n",
-        "enthalpy = 3013.8 kJ/kg\n",
-        "Entropy = 6.7 kJ/kg\n"
-       ]
-      }
-     ],
-     "prompt_number": 6
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Exapmle5-pg54"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "#calculate a2 and internal enerjy\n",
-      "##initialisation of variables\n",
-      "v= 0.15 ##m^3/kg\n",
-      "v1= 0.13857 ##m^3/kg\n",
-      "v2= 0.1512 ##m^3/kg\n",
-      "v3= 0.050 ##m^3##kg\n",
-      "vf= 0.001177 ##m^3/kg\n",
-      "vg= 0.09963 ##m^3/kg\n",
-      "uf= 906.44 ##kJ/kg\n",
-      "ufg= 1693.8 ##kJ/kg\n",
-      "##CALCULATIONS\n",
-      "a1= (v-v1)/(v2-v1)\n",
-      "a2= 1-a1\n",
-      "x= (v3-vf)/(vg-vf)\n",
-      "u= uf+x*ufg\n",
-      "##RESULTS\n",
-      "print'%s %.3f %s'%('a2 =',a2,'')\n",
-      "print'%s %.1f %s'%('internal energy =',u,'kJ/kg')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "a2 = 0.095 \n",
-        "internal energy = 1746.4 kJ/kg\n"
-       ]
-      }
-     ],
-     "prompt_number": 7
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Example6-pg52"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "#calculate pressure and temperature\n",
-      "##initialisation of variables\n",
-      "T= 250.##C\n",
-      "T1= 300. ##C\n",
-      "v300= 0.6548 ##m^3/kg\n",
-      "v250= 0.591 ##m^3/kg\n",
-      "v= 0.6 ##m^3/kg\n",
-      "u= 3000. ##kJ/kg\n",
-      "u250= 2726.1 ##kJ/kg\n",
-      "u300= 2804.8 ##kJ/kg\n",
-      "T2= 510.30 \n",
-      "u2= 3145.26 ##kJ/kg\n",
-      "p= 0.4 ##Mpa\n",
-      "p2= 0.2 ##Mpa\n",
-      "##CALCULATIONS\n",
-      "T1= T1+((v-v250)/(v300-v250))*(T2-T)\n",
-      "u1= u250+((v-v250)/(v300-v250))*(u300-u250)\n",
-      "du= u1-u\n",
-      "p1= p+((u-u1)/(u2-u1))*p2\n",
-      "##RESULTS\n",
-      "print'%s %.3f %s'%('pressure =',p1,'Mpa')\n",
-      "print'%s %.f %s'%('temperature =',T2,'C')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "pressure = 0.529 Mpa\n",
-        "temperature = 510 C\n"
-       ]
-      }
-     ],
-     "prompt_number": 8
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Example 7-pg54"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "#calculate work and heat interaction\n",
-      "##initialisation of variables\n",
-      "V= 0.2 ##m^3\n",
-      "v1= 0.02995 ##m^3/kg\n",
-      "u2= 2826.7 ##kJ/kg\n",
-      "u1= 2747.7 ##kJ/kg\n",
-      "h2= 3092.5 ##kJ/kg\n",
-      "h1= 2987.3 ##kJ/kg\n",
-      "p= 4 ##Mpa\n",
-      "v2= 0.06645 ##m^3/kg\n",
-      "v1= 0.02995 ##m^3/kg\n",
-      "##CALCULATIONS\n",
-      "m= V/v1\n",
-      "U= m*(u2-u1)\n",
-      "H= m*(h2-h1)\n",
-      "W= m*p*10*10*10*(v2-v1)\n",
-      "Q= U+W\n",
-      "##RESULTS\n",
-      "print'%s %.1f %s'%('work =',W,'kJ') \n",
-      "print'%s %.1f %s'%('heat interaction =',Q,'kJ')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "work = 975.0 kJ\n",
-        "heat interaction = 1502.5 kJ\n"
-       ]
-      }
-     ],
-     "prompt_number": 10
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Example8-pg 55"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "#calculate work and heat interaction\n",
-      "##initialisation of variables\n",
-      "m= 6.678 ##kg\n",
-      "u2= 2826.7 ##kJ/kg\n",
-      "u1= 2747.7 ##kJ/kg\n",
-      "p1= 8. ##Mpa\n",
-      "p2= 7. ##Mpa\n",
-      "p3= 6. ##Mpa\n",
-      "p4= 5. ##Mpa\n",
-      "p5= 4. ##Mpa\n",
-      "v1= 29.95 ##L/kg\n",
-      "v2= 35.24 ##L/kg\n",
-      "v3= 42.23 ##L/kg\n",
-      "v4= 51.94 ##L/kg\n",
-      "v5= 66.45 ##L/kg\n",
-      "##CALCULATIONS\n",
-      "U= m*(u2-u1)\n",
-      "W= m*0.5*((p1+p2)*(v2-v1)+(p2+p3)*(v3-v2)+(p3+p4)*(v4-v3)+(p4+p5)*(v5-v4))\n",
-      "Q=U+W\n",
-      "##RESULTS\n",
-      "print'%s %.1f %s'%('work =',W,'kJ') \n",
-      "print'%s %.f %s'%('heat interaction =',Q,'kJ') \n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "work = 1361.0 kJ\n",
-        "heat interaction = 1889 kJ\n"
-       ]
-      }
-     ],
-     "prompt_number": 12
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Example 9-pg56\n"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "#calculate final pressure and enthalpy and etropy\n",
-      "##initialisation of variables\n",
-      "p0= 100. ##kpa\n",
-      "A= 0.1 ##m^2\n",
-      "F= 20. ##kN\n",
-      "m3= 0.8873 ##kg\n",
-      "m1= 1.1384 ##kg\n",
-      "m2= 0.2511 ##kg\n",
-      "u1= 3116.2 ##kJ/kg\n",
-      "u2= 2728.7 ##kJ/kg\n",
-      "v3= 0.9942 ##m^3/kg\n",
-      "##CALCULATIONS\n",
-      "pe= (p0+(F/A))/1000\n",
-      "h3= (m1*u1-m2*u2)/m3\n",
-      "z3= m3*v3/A\n",
-      "##RESULTS\n",
-      "print'%s %.1f %s'%('final pressure =',pe,'Mpa') \n",
-      "print'%s %.1f %s'%('enthalpy = ',h3,'kJ/kg') \n",
-      "print'%s %.2f %s'%('piston rise =',z3,'m') \n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "final pressure = 0.3 Mpa\n",
-        "enthalpy =  3225.9 kJ/kg\n",
-        "piston rise = 8.82 m\n"
-       ]
-      }
-     ],
-     "prompt_number": 14
-    }
-   ],
-   "metadata": {}
-  }
- ]
-}
-\ No newline at end of file
diff --git a/Thermodynamics:_From_concepts_to_applications/Chapter_4__1.ipynb b/Thermodynamics:_From_concepts_to_applications/Chapter_4__1.ipynb
deleted file mode 100755
index b4cbb2bf..00000000
--- a/Thermodynamics:_From_concepts_to_applications/Chapter_4__1.ipynb
+++ /dev/null
@@ -1,466 +0,0 @@
-{
- "metadata": {
-  "name": "",
-  "signature": "sha256:f794a4d18f36c13ddab8d6024721da6bc9aca8b98b0260eaf3e1fb73a8bd345d"
- },
- "nbformat": 3,
- "nbformat_minor": 0,
- "worksheets": [
-  {
-   "cells": [
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Chapter 4-simple systems"
-     ]
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Example1-pg43"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "#caluclate the heat interaction and temperature rise\n",
-      "##initialisation of variables\n",
-      "m= 5000. ##kg\n",
-      "cp= 1.4 ##kJ/kg K\n",
-      "T2= 27.6 ##K\n",
-      "T1= 22. ##K\n",
-      "t= 40. ##min\n",
-      "P= 20. ##kW\n",
-      "##CALCULATIONS\n",
-      "H= m*cp*(T2-T1)\n",
-      "W= -P*t*60\n",
-      "Q= H+W\n",
-      "dT= -W/(m*cp)\n",
-      "##RESULTS\n",
-      "print'%s %.f %s'%('heat interaction =',Q,'kJ')\n",
-      "print'%s %.2f %s'%('Temperature rise = ',dT,'C')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "heat interaction = -8800 kJ\n",
-        "Temperature rise =  6.86 C\n"
-       ]
-      }
-     ],
-     "prompt_number": 15
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "example 2-pg 49\n"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "#caluclate the volumes and internal energy and enthaply\n",
-      "##initialisation of variables\n",
-      "T= 300. ##C\n",
-      "p= 2. ##Mpa\n",
-      "T1= 300. ##C\n",
-      "p1= 20.##Mpa\n",
-      "T2= 300. ##C\n",
-      "p2= 8.501 ##Mpa\n",
-      "##CALCULATIONS\n",
-      "v= 0.12547\n",
-      "v1= 0.00136\n",
-      "u= 2772.6\n",
-      "u1= 1306.1\n",
-      "h= 3023.5\n",
-      "h1= 1333.3\n",
-      "##RESULTS\n",
-      "print'%s %.5f %s'%('volume =',v,'m^3/kg')\n",
-      "print'%s %.5f %s'%('volume =',v1,'m^3/kg')\n",
-      "print'%s %.1f %s'%('internal energy = ',u,'kJ/kg')\n",
-      "print'%s %.1f %s'%('internal energy =',u1,'kJ/kg')\n",
-      "print'%s %.1f %s'%('enthalpy =',h,'kJ/kg')\n",
-      "print'%s %.f %s'%('enthalpy = ',h1,'kJ/kg')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "volume = 0.12547 m^3/kg\n",
-        "volume = 0.00136 m^3/kg\n",
-        "internal energy =  2772.6 kJ/kg\n",
-        "internal energy = 1306.1 kJ/kg\n",
-        "enthalpy = 3023.5 kJ/kg\n",
-        "enthalpy =  1333 kJ/kg\n"
-       ]
-      }
-     ],
-     "prompt_number": 17
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "example3-pg49\n"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "#calculate the volume and internal energy and enthalpy\n",
-      "##initialisation of variables\n",
-      "vf= 0.001404 ##m^3/kg\n",
-      "x= 0.8\n",
-      "vg= 0.02167 ##m^3/kg\n",
-      "uf= 1332. ##kJ/kg\n",
-      "ug= 1231. ##kJ/kg\n",
-      "hf= 1344. ##kJ/kg\n",
-      "hg= 1404.9 ##kJ/kg\n",
-      "##CALCULATIONS\n",
-      "v= vf+x*(vg-vf)\n",
-      "u= uf+x*ug\n",
-      "h= hf+x*hg\n",
-      "##RESULTS\n",
-      "print'%s %.5f %s'%('volume =',v,'m^3/kg')\n",
-      "print'%s %.1f %s'%('internal energy =',u,'kJ/kg')\n",
-      "print'%s %.1f %s'%('enthalpy =',h, 'kJ/kg')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "volume = 0.01762 m^3/kg\n",
-        "internal energy = 2316.8 kJ/kg\n",
-        "enthalpy = 2467.9 kJ/kg\n"
-       ]
-      }
-     ],
-     "prompt_number": 5
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Example4-pg 52"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "#calculate the specific volume and internal energy and enthalpy and entropy\n",
-      "##initialisation of variables\n",
-      "T= 296. ##K\n",
-      "T1= 250. ##K\n",
-      "T2= 300. ##K\n",
-      "v= 0.1257 ##m^3/kg\n",
-      "v1= 0.11144 ##m^3/kg\n",
-      "u1= 27772.6 ##kJ/kg\n",
-      "u2= 2679.6 ##kJ/kg\n",
-      "h1= 3023.5 ##kJ/kg\n",
-      "h2= 2902.5 ##kJ/kg\n",
-      "s1= 6.7664 ##kJ/kg K\n",
-      "s2= 6.5433 ##kJ/kg K\n",
-      "##CALCULATIONS\n",
-      "a1= (T-T1)/(T2-T1)\n",
-      "a2= 1-a1\n",
-      "V= a1*v+a2*v1\n",
-      "U= a1*u1+a2*u2\n",
-      "H= a1*h1+a2*h2\n",
-      "S= a1*s1+a2*s2\n",
-      "##RESULTS\n",
-      "print'%s %.3f %s'%('a2 = ',a2,'')\n",
-      "print'%s %.5f %s'%('specific volume =',V,'m^3/kg')\n",
-      "print'%s %.1f %s'%('internal energy =',U,'kJ/kg')\n",
-      "print'%s %.1f %s'%('enthalpy =',H,'kJ/kg')\n",
-      "print'%s %.1f %s'%('Entropy =',S,'kJ/kg')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "a2 =  0.080 \n",
-        "specific volume = 0.12456 m^3/kg\n",
-        "internal energy = 25765.2 kJ/kg\n",
-        "enthalpy = 3013.8 kJ/kg\n",
-        "Entropy = 6.7 kJ/kg\n"
-       ]
-      }
-     ],
-     "prompt_number": 6
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Exapmle5-pg54"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "#calculate a2 and internal enerjy\n",
-      "##initialisation of variables\n",
-      "v= 0.15 ##m^3/kg\n",
-      "v1= 0.13857 ##m^3/kg\n",
-      "v2= 0.1512 ##m^3/kg\n",
-      "v3= 0.050 ##m^3##kg\n",
-      "vf= 0.001177 ##m^3/kg\n",
-      "vg= 0.09963 ##m^3/kg\n",
-      "uf= 906.44 ##kJ/kg\n",
-      "ufg= 1693.8 ##kJ/kg\n",
-      "##CALCULATIONS\n",
-      "a1= (v-v1)/(v2-v1)\n",
-      "a2= 1-a1\n",
-      "x= (v3-vf)/(vg-vf)\n",
-      "u= uf+x*ufg\n",
-      "##RESULTS\n",
-      "print'%s %.3f %s'%('a2 =',a2,'')\n",
-      "print'%s %.1f %s'%('internal energy =',u,'kJ/kg')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "a2 = 0.095 \n",
-        "internal energy = 1746.4 kJ/kg\n"
-       ]
-      }
-     ],
-     "prompt_number": 7
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Example6-pg52"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "#calculate pressure and temperature\n",
-      "##initialisation of variables\n",
-      "T= 250.##C\n",
-      "T1= 300. ##C\n",
-      "v300= 0.6548 ##m^3/kg\n",
-      "v250= 0.591 ##m^3/kg\n",
-      "v= 0.6 ##m^3/kg\n",
-      "u= 3000. ##kJ/kg\n",
-      "u250= 2726.1 ##kJ/kg\n",
-      "u300= 2804.8 ##kJ/kg\n",
-      "T2= 510.30 \n",
-      "u2= 3145.26 ##kJ/kg\n",
-      "p= 0.4 ##Mpa\n",
-      "p2= 0.2 ##Mpa\n",
-      "##CALCULATIONS\n",
-      "T1= T1+((v-v250)/(v300-v250))*(T2-T)\n",
-      "u1= u250+((v-v250)/(v300-v250))*(u300-u250)\n",
-      "du= u1-u\n",
-      "p1= p+((u-u1)/(u2-u1))*p2\n",
-      "##RESULTS\n",
-      "print'%s %.3f %s'%('pressure =',p1,'Mpa')\n",
-      "print'%s %.f %s'%('temperature =',T2,'C')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "pressure = 0.529 Mpa\n",
-        "temperature = 510 C\n"
-       ]
-      }
-     ],
-     "prompt_number": 8
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Example 7-pg54"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "#calculate work and heat interaction\n",
-      "##initialisation of variables\n",
-      "V= 0.2 ##m^3\n",
-      "v1= 0.02995 ##m^3/kg\n",
-      "u2= 2826.7 ##kJ/kg\n",
-      "u1= 2747.7 ##kJ/kg\n",
-      "h2= 3092.5 ##kJ/kg\n",
-      "h1= 2987.3 ##kJ/kg\n",
-      "p= 4 ##Mpa\n",
-      "v2= 0.06645 ##m^3/kg\n",
-      "v1= 0.02995 ##m^3/kg\n",
-      "##CALCULATIONS\n",
-      "m= V/v1\n",
-      "U= m*(u2-u1)\n",
-      "H= m*(h2-h1)\n",
-      "W= m*p*10*10*10*(v2-v1)\n",
-      "Q= U+W\n",
-      "##RESULTS\n",
-      "print'%s %.1f %s'%('work =',W,'kJ') \n",
-      "print'%s %.1f %s'%('heat interaction =',Q,'kJ')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "work = 975.0 kJ\n",
-        "heat interaction = 1502.5 kJ\n"
-       ]
-      }
-     ],
-     "prompt_number": 10
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Example8-pg 55"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "#calculate work and heat interaction\n",
-      "##initialisation of variables\n",
-      "m= 6.678 ##kg\n",
-      "u2= 2826.7 ##kJ/kg\n",
-      "u1= 2747.7 ##kJ/kg\n",
-      "p1= 8. ##Mpa\n",
-      "p2= 7. ##Mpa\n",
-      "p3= 6. ##Mpa\n",
-      "p4= 5. ##Mpa\n",
-      "p5= 4. ##Mpa\n",
-      "v1= 29.95 ##L/kg\n",
-      "v2= 35.24 ##L/kg\n",
-      "v3= 42.23 ##L/kg\n",
-      "v4= 51.94 ##L/kg\n",
-      "v5= 66.45 ##L/kg\n",
-      "##CALCULATIONS\n",
-      "U= m*(u2-u1)\n",
-      "W= m*0.5*((p1+p2)*(v2-v1)+(p2+p3)*(v3-v2)+(p3+p4)*(v4-v3)+(p4+p5)*(v5-v4))\n",
-      "Q=U+W\n",
-      "##RESULTS\n",
-      "print'%s %.1f %s'%('work =',W,'kJ') \n",
-      "print'%s %.f %s'%('heat interaction =',Q,'kJ') \n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "work = 1361.0 kJ\n",
-        "heat interaction = 1889 kJ\n"
-       ]
-      }
-     ],
-     "prompt_number": 12
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Example 9-pg56\n"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "#calculate final pressure and enthalpy and etropy\n",
-      "##initialisation of variables\n",
-      "p0= 100. ##kpa\n",
-      "A= 0.1 ##m^2\n",
-      "F= 20. ##kN\n",
-      "m3= 0.8873 ##kg\n",
-      "m1= 1.1384 ##kg\n",
-      "m2= 0.2511 ##kg\n",
-      "u1= 3116.2 ##kJ/kg\n",
-      "u2= 2728.7 ##kJ/kg\n",
-      "v3= 0.9942 ##m^3/kg\n",
-      "##CALCULATIONS\n",
-      "pe= (p0+(F/A))/1000\n",
-      "h3= (m1*u1-m2*u2)/m3\n",
-      "z3= m3*v3/A\n",
-      "##RESULTS\n",
-      "print'%s %.1f %s'%('final pressure =',pe,'Mpa') \n",
-      "print'%s %.1f %s'%('enthalpy = ',h3,'kJ/kg') \n",
-      "print'%s %.2f %s'%('piston rise =',z3,'m') \n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "final pressure = 0.3 Mpa\n",
-        "enthalpy =  3225.9 kJ/kg\n",
-        "piston rise = 8.82 m\n"
-       ]
-      }
-     ],
-     "prompt_number": 14
-    }
-   ],
-   "metadata": {}
-  }
- ]
-}
-\ No newline at end of file
diff --git a/Thermodynamics:_From_concepts_to_applications/Chapter_4__2.ipynb b/Thermodynamics:_From_concepts_to_applications/Chapter_4__2.ipynb
index af2345df..087b31cb 100755
--- a/Thermodynamics:_From_concepts_to_applications/Chapter_4__2.ipynb
+++ b/Thermodynamics:_From_concepts_to_applications/Chapter_4__2.ipynb
@@ -1,7 +1,7 @@
 {
  "metadata": {
   "name": "",
-  "signature": "sha256:0cf657809abd59a3a86b6df0687d80933981fc0951ab754e85709aa636b8b749"
+  "signature": "sha256:1f455d345757b912d780f8c505ce37e354978864332af7e0ecea71365b71aa92"
  },
  "nbformat": 3,
  "nbformat_minor": 0,
@@ -10,10 +10,10 @@
    "cells": [
     {
      "cell_type": "heading",
-     "level": 2,
+     "level": 1,
      "metadata": {},
      "source": [
-      "Chapter 4-simple systems"
+      "Chapter4-Simple systems"
      ]
     },
     {
@@ -21,7 +21,7 @@
      "level": 2,
      "metadata": {},
      "source": [
-      "Example1-46"
+      "Ex1-pg51"
      ]
     },
     {
@@ -29,6 +29,7 @@
      "collapsed": false,
      "input": [
       "import math\n",
+      "#calculte pressure and mass and specific volume of water vapour\n",
       "##initialisation of variables\n",
       "V= 0.5 ##m**3\n",
       "M= 18.02 ##kg/kmol\n",
@@ -46,7 +47,7 @@
       "##RESULTS\n",
       "print'%s %.2f %s'% ('mass of water vapour =',m,' kg')\n",
       "print'%s %.2f %s' %(' specific volume of water vapour = ',v,' m**3/kg')\n",
-      "print'%s %.2f %s' %(' pressure of water vapour =',p-10,'kPa')\n",
+      "print'%s %.2f %s' %(' pressure of water vapour =',p,'kPa')\n",
       "print'%s %.2f %s' %(' pressure of water vapour = ',P-12,' kPa')\n",
       "print'%s %.2f %s' %(' pressure of water vapour =',P1,' kPa')\n"
      ],
@@ -59,20 +60,20 @@
        "text": [
         "mass of water vapour = 27.03  kg\n",
         " specific volume of water vapour =  0.02  m**3/kg\n",
-        " pressure of water vapour = 15543.51 kPa\n",
+        " pressure of water vapour = 15553.51 kPa\n",
         " pressure of water vapour =  12131.31  kPa\n",
         " pressure of water vapour = 12432.21  kPa\n"
        ]
       }
      ],
-     "prompt_number": 3
+     "prompt_number": 14
     },
     {
      "cell_type": "heading",
      "level": 2,
      "metadata": {},
      "source": [
-      "Ex2-pg50"
+      "Ex2-pg52"
      ]
     },
     {
@@ -80,6 +81,7 @@
      "collapsed": false,
      "input": [
       "import math\n",
+      "#calculate heat interaction\n",
       "##initialisation of variables\n",
       "m= 0.3 ##kg\n",
       "T= 25 ##C\n",
@@ -101,14 +103,14 @@
        ]
       }
      ],
-     "prompt_number": 4
+     "prompt_number": 15
     },
     {
      "cell_type": "heading",
      "level": 2,
      "metadata": {},
      "source": [
-      "Example3-pg53"
+      "Ex3-pg53"
      ]
     },
     {
@@ -116,22 +118,22 @@
      "collapsed": false,
      "input": [
       "import math\n",
-      "#caluclate the heat interaction and temperature rise\n",
+      "#calculate heat interaction and temperature rise\n",
       "##initialisation of variables\n",
-      "m= 5000. ##kg\n",
+      "m= 5000 ##kg\n",
       "cp= 1.4 ##kJ/kg K\n",
       "T2= 27.6 ##K\n",
-      "T1= 22. ##K\n",
-      "t= 40. ##min\n",
-      "P= 20. ##kW\n",
+      "T1= 22 ##K\n",
+      "t= 40 ##min\n",
+      "P= 20 ##kW\n",
       "##CALCULATIONS\n",
       "H= m*cp*(T2-T1)\n",
       "W= -P*t*60\n",
       "Q= H+W\n",
       "dT= -W/(m*cp)\n",
       "##RESULTS\n",
-      "print'%s %.f %s'%('heat interaction =',Q,'kJ')\n",
-      "print'%s %.2f %s'%('Temperature rise = ',dT,'C')\n"
+      "print'%s %.2f %s'% ('heat interaction = ',Q,' kJ')\n",
+      "print'%s %.2f %s'% ('\\n temperature rise = ',dT,' C')\n"
      ],
      "language": "python",
      "metadata": {},
@@ -140,19 +142,20 @@
        "output_type": "stream",
        "stream": "stdout",
        "text": [
-        "heat interaction = -8800 kJ\n",
-        "Temperature rise =  6.86 C\n"
+        "heat interaction =  -8800.00  kJ\n",
+        "\n",
+        " temperature rise =  6.86  C\n"
        ]
       }
      ],
-     "prompt_number": 15
+     "prompt_number": 16
     },
     {
      "cell_type": "heading",
      "level": 2,
      "metadata": {},
      "source": [
-      "example 4-pg 59\n"
+      "Ex4-pg59"
      ]
     },
     {
@@ -160,12 +163,12 @@
      "collapsed": false,
      "input": [
       "import math\n",
-      "#caluclate the volumes and internal energy and enthaply\n",
       "##initialisation of variables\n",
+      "#calculate volume and internal energy and enthalpy\n",
       "T= 300. ##C\n",
       "p= 2. ##Mpa\n",
       "T1= 300. ##C\n",
-      "p1= 20.##Mpa\n",
+      "p1= 20. ##Mpa\n",
       "T2= 300. ##C\n",
       "p2= 8.501 ##Mpa\n",
       "##CALCULATIONS\n",
@@ -176,12 +179,12 @@
       "h= 3023.5\n",
       "h1= 1333.3\n",
       "##RESULTS\n",
-      "print'%s %.5f %s'%('volume =',v,'m^3/kg')\n",
-      "print'%s %.5f %s'%('volume =',v1,'m^3/kg')\n",
-      "print'%s %.1f %s'%('internal energy = ',u,'kJ/kg')\n",
-      "print'%s %.1f %s'%('internal energy =',u1,'kJ/kg')\n",
-      "print'%s %.1f %s'%('enthalpy =',h,'kJ/kg')\n",
-      "print'%s %.f %s'%('enthalpy = ',h1,'kJ/kg')\n"
+      "print'%s %.2f %s'% ('volume = ',v,' m^3/kg')\n",
+      "print'%s %.2f %s'% ('\\n volume =',v1,' m^3/kg')\n",
+      "print'%s %.2f %s'% ('\\n internal energy = ',u,' kJ/kg')\n",
+      "print'%s %.2f %s'% ('\\n internal energy = ',u1,' kJ/kg')\n",
+      "print'%s %.2f %s'% ('\\n enthalpy = ',h,' kJ/kg')\n",
+      "print'%s %.2f %s'% ('\\n enthalpy = ',h1,' kJ/kg')\n"
      ],
      "language": "python",
      "metadata": {},
@@ -190,12 +193,17 @@
        "output_type": "stream",
        "stream": "stdout",
        "text": [
-        "volume = 0.12547 m^3/kg\n",
-        "volume = 0.00136 m^3/kg\n",
-        "internal energy =  2772.6 kJ/kg\n",
-        "internal energy = 1306.1 kJ/kg\n",
-        "enthalpy = 3023.5 kJ/kg\n",
-        "enthalpy =  1333 kJ/kg\n"
+        "volume =  0.13  m^3/kg\n",
+        "\n",
+        " volume = 0.00  m^3/kg\n",
+        "\n",
+        " internal energy =  2772.60  kJ/kg\n",
+        "\n",
+        " internal energy =  1306.10  kJ/kg\n",
+        "\n",
+        " enthalpy =  3023.50  kJ/kg\n",
+        "\n",
+        " enthalpy =  1333.30  kJ/kg\n"
        ]
       }
      ],
@@ -206,7 +214,7 @@
      "level": 2,
      "metadata": {},
      "source": [
-      "example5-pg60\n"
+      "Ex5-pg60"
      ]
     },
     {
@@ -214,7 +222,7 @@
      "collapsed": false,
      "input": [
       "import math\n",
-      "#calculate the volume and internal energy and enthalpy\n",
+      "#calculate volume and internal energy\n",
       "##initialisation of variables\n",
       "vf= 0.001404 ##m^3/kg\n",
       "x= 0.8\n",
@@ -228,9 +236,9 @@
       "u= uf+x*ug\n",
       "h= hf+x*hg\n",
       "##RESULTS\n",
-      "print'%s %.5f %s'%('volume =',v,'m^3/kg')\n",
-      "print'%s %.1f %s'%('internal energy =',u,'kJ/kg')\n",
-      "print'%s %.1f %s'%('enthalpy =',h, 'kJ/kg')\n"
+      "print'%s %.2f %s'% ('volume = ',v,' m^3/kg')\n",
+      "print'%s %.2f %s'% ('\\n internal energy = ',u,' kJ/kg')\n",
+      "print'%s %.2f %s'% ('\\n enthalpy = ',h,' kJ/kg')\n"
      ],
      "language": "python",
      "metadata": {},
@@ -239,20 +247,22 @@
        "output_type": "stream",
        "stream": "stdout",
        "text": [
-        "volume = 0.01762 m^3/kg\n",
-        "internal energy = 2316.8 kJ/kg\n",
-        "enthalpy = 2467.9 kJ/kg\n"
+        "volume =  0.02  m^3/kg\n",
+        "\n",
+        " internal energy =  2316.80  kJ/kg\n",
+        "\n",
+        " enthalpy =  2467.92  kJ/kg\n"
        ]
       }
      ],
-     "prompt_number": 5
+     "prompt_number": 18
     },
     {
      "cell_type": "heading",
      "level": 2,
      "metadata": {},
      "source": [
-      "Example6-pg 61"
+      "Ex6-pg61"
      ]
     },
     {
@@ -260,7 +270,7 @@
      "collapsed": false,
      "input": [
       "import math\n",
-      "#calculate the specific volume and internal energy and enthalpy and entropy\n",
+      "#calculate specific volume and internal energy and enthalpy and entropy\n",
       "##initialisation of variables\n",
       "T= 296. ##K\n",
       "T1= 250. ##K\n",
@@ -275,17 +285,17 @@
       "s2= 6.5433 ##kJ/kg K\n",
       "##CALCULATIONS\n",
       "a1= (T-T1)/(T2-T1)\n",
-      "a2= 1-a1\n",
+      "a2= 1.-a1\n",
       "V= a1*v+a2*v1\n",
       "U= a1*u1+a2*u2\n",
       "H= a1*h1+a2*h2\n",
       "S= a1*s1+a2*s2\n",
       "##RESULTS\n",
-      "print'%s %.3f %s'%('a2 = ',a2,'')\n",
-      "print'%s %.5f %s'%('specific volume =',V,'m^3/kg')\n",
-      "print'%s %.1f %s'%('internal energy =',U,'kJ/kg')\n",
-      "print'%s %.1f %s'%('enthalpy =',H,'kJ/kg')\n",
-      "print'%s %.1f %s'%('Entropy =',S,'kJ/kg')\n"
+      "print'%s %.2f %s'% ('a2 =  ',a2,'')\n",
+      "print'%s %.2f %s'% ('\\n specific volume = ',V,' m^3/kg')\n",
+      "print'%s %.2f %s'% ('\\n internal energy = ',U,' kJ/kg')\n",
+      "print'%s %.2f %s'% ('\\n enthalpy = ',H,' kJ/kg')\n",
+      "print'%s %.2f %s'% ('\\n Entropy = ',S,' kJ/kg')\n"
      ],
      "language": "python",
      "metadata": {},
@@ -294,22 +304,26 @@
        "output_type": "stream",
        "stream": "stdout",
        "text": [
-        "a2 =  0.080 \n",
-        "specific volume = 0.12456 m^3/kg\n",
-        "internal energy = 25765.2 kJ/kg\n",
-        "enthalpy = 3013.8 kJ/kg\n",
-        "Entropy = 6.7 kJ/kg\n"
+        "a2 =   0.08 \n",
+        "\n",
+        " specific volume =  0.12  m^3/kg\n",
+        "\n",
+        " internal energy =  25765.16  kJ/kg\n",
+        "\n",
+        " enthalpy =  3013.82  kJ/kg\n",
+        "\n",
+        " Entropy =  6.75  kJ/kg\n"
        ]
       }
      ],
-     "prompt_number": 6
+     "prompt_number": 19
     },
     {
      "cell_type": "heading",
      "level": 2,
      "metadata": {},
      "source": [
-      "Exapmle7-pg62"
+      "Ex7-pg62"
      ]
     },
     {
@@ -317,7 +331,7 @@
      "collapsed": false,
      "input": [
       "import math\n",
-      "#calculate a2 and internal enerjy\n",
+      "#calculate a2 and internal energy\n",
       "##initialisation of variables\n",
       "v= 0.15 ##m^3/kg\n",
       "v1= 0.13857 ##m^3/kg\n",
@@ -333,8 +347,8 @@
       "x= (v3-vf)/(vg-vf)\n",
       "u= uf+x*ufg\n",
       "##RESULTS\n",
-      "print'%s %.3f %s'%('a2 =',a2,'')\n",
-      "print'%s %.1f %s'%('internal energy =',u,'kJ/kg')\n"
+      "print'%s %.2f %s'% ('a2 =  ',a2,'')\n",
+      "print'%s %.2f %s'% ('\\n internal energy = ',u,' kJ/kg')\n"
      ],
      "language": "python",
      "metadata": {},
@@ -343,19 +357,20 @@
        "output_type": "stream",
        "stream": "stdout",
        "text": [
-        "a2 = 0.095 \n",
-        "internal energy = 1746.4 kJ/kg\n"
+        "a2 =   0.10 \n",
+        "\n",
+        " internal energy =  1746.40  kJ/kg\n"
        ]
       }
      ],
-     "prompt_number": 7
+     "prompt_number": 20
     },
     {
      "cell_type": "heading",
      "level": 2,
      "metadata": {},
      "source": [
-      "Example8-pg63"
+      "Ex8-pg63"
      ]
     },
     {
@@ -365,8 +380,8 @@
       "import math\n",
       "#calculate pressure and temperature\n",
       "##initialisation of variables\n",
-      "T= 250.##C\n",
-      "T1= 300. ##C\n",
+      "T= 250. ##C\n",
+      "T2= 300. ##C\n",
       "v300= 0.6548 ##m^3/kg\n",
       "v250= 0.591 ##m^3/kg\n",
       "v= 0.6 ##m^3/kg\n",
@@ -378,13 +393,13 @@
       "p= 0.4 ##Mpa\n",
       "p2= 0.2 ##Mpa\n",
       "##CALCULATIONS\n",
-      "T1= T1+((v-v250)/(v300-v250))*(T2-T)\n",
+      "T1= T+((v-v250)/(v300-v250))*(T2-T)\n",
       "u1= u250+((v-v250)/(v300-v250))*(u300-u250)\n",
       "du= u1-u\n",
       "p1= p+((u-u1)/(u2-u1))*p2\n",
       "##RESULTS\n",
-      "print'%s %.3f %s'%('pressure =',p1,'Mpa')\n",
-      "print'%s %.f %s'%('temperature =',T2,'C')\n"
+      "print'%s %.2f %s'% ('pressure = ',p1,' Mpa')\n",
+      "print'%s %.2f %s'% ('\\n temperature = ',T2,' C')\n"
      ],
      "language": "python",
      "metadata": {},
@@ -393,36 +408,38 @@
        "output_type": "stream",
        "stream": "stdout",
        "text": [
-        "pressure = 0.529 Mpa\n",
-        "temperature = 510 C\n"
+        "pressure =  0.53  Mpa\n",
+        "\n",
+        " temperature =  510.30  C\n"
        ]
       }
      ],
-     "prompt_number": 8
+     "prompt_number": 21
     },
     {
      "cell_type": "heading",
      "level": 2,
      "metadata": {},
      "source": [
-      "Ex10-pg64"
+      "Ex9-pg64"
      ]
     },
     {
      "cell_type": "code",
      "collapsed": false,
      "input": [
-      "\n",
+      "import math\n",
+      "#calculate mass and specific volume\n",
       "##initialisation of variables\n",
       "n= 1.5 ##kmol\n",
-      "V= 0.5 ##m**3\n",
+      "V= 0.5 ##m^3\n",
       "M= 18.02 ##kg\n",
       "##CALCULATIONS\n",
       "m= n*M\n",
       "v= V/m\n",
       "##RESULTS\n",
       "print'%s %.2f %s'% ('mass = ',m,' kg')\n",
-      "print'%s %.2f %s'% (' sepcific volume = ',v,' m^3/kg')\n"
+      "print'%s %.2f %s'% ('\\n sepcific volume = ',v,' m^3/kg')\n"
      ],
      "language": "python",
      "metadata": {},
@@ -432,18 +449,19 @@
        "stream": "stdout",
        "text": [
         "mass =  27.03  kg\n",
+        "\n",
         " sepcific volume =  0.02  m^3/kg\n"
        ]
       }
      ],
-     "prompt_number": 5
+     "prompt_number": 22
     },
     {
      "cell_type": "heading",
      "level": 2,
      "metadata": {},
      "source": [
-      "Example 12-pg66"
+      "Ex12-pg66"
      ]
     },
     {
@@ -459,18 +477,18 @@
       "u1= 2747.7 ##kJ/kg\n",
       "h2= 3092.5 ##kJ/kg\n",
       "h1= 2987.3 ##kJ/kg\n",
-      "p= 4 ##Mpa\n",
+      "p= 4. ##Mpa\n",
       "v2= 0.06645 ##m^3/kg\n",
       "v1= 0.02995 ##m^3/kg\n",
       "##CALCULATIONS\n",
       "m= V/v1\n",
       "U= m*(u2-u1)\n",
       "H= m*(h2-h1)\n",
-      "W= m*p*10*10*10*(v2-v1)\n",
+      "W= m*p*10**3*(v2-v1)\n",
       "Q= U+W\n",
       "##RESULTS\n",
-      "print'%s %.1f %s'%('work =',W,'kJ') \n",
-      "print'%s %.1f %s'%('heat interaction =',Q,'kJ')\n"
+      "print'%s %.2f %s'% (' work = ',W,' kJ') \n",
+      "print'%s %.2f %s'% ('\\n heat interaction = ',Q,' kJ') \n"
      ],
      "language": "python",
      "metadata": {},
@@ -479,19 +497,20 @@
        "output_type": "stream",
        "stream": "stdout",
        "text": [
-        "work = 975.0 kJ\n",
-        "heat interaction = 1502.5 kJ\n"
+        " work =  974.96  kJ\n",
+        "\n",
+        " heat interaction =  1502.50  kJ\n"
        ]
       }
      ],
-     "prompt_number": 10
+     "prompt_number": 23
     },
     {
      "cell_type": "heading",
      "level": 2,
      "metadata": {},
      "source": [
-      "Example13-pg 67"
+      "Ex13-pg67"
      ]
     },
     {
@@ -519,8 +538,8 @@
       "W= m*0.5*((p1+p2)*(v2-v1)+(p2+p3)*(v3-v2)+(p3+p4)*(v4-v3)+(p4+p5)*(v5-v4))\n",
       "Q=U+W\n",
       "##RESULTS\n",
-      "print'%s %.1f %s'%('work =',W,'kJ') \n",
-      "print'%s %.f %s'%('heat interaction =',Q,'kJ') \n"
+      "print'%s %.2f %s'% (' work = ',W,' kJ') \n",
+      "print'%s %.2f %s'% ('\\n heat interaction = ',Q,' kJ') \n"
      ],
      "language": "python",
      "metadata": {},
@@ -529,19 +548,20 @@
        "output_type": "stream",
        "stream": "stdout",
        "text": [
-        "work = 1361.0 kJ\n",
-        "heat interaction = 1889 kJ\n"
+        " work =  1361.04  kJ\n",
+        "\n",
+        " heat interaction =  1888.61  kJ\n"
        ]
       }
      ],
-     "prompt_number": 12
+     "prompt_number": 24
     },
     {
      "cell_type": "heading",
      "level": 2,
      "metadata": {},
      "source": [
-      "Example 14-pg68\n"
+      "Ex14-pg68"
      ]
     },
     {
@@ -549,7 +569,7 @@
      "collapsed": false,
      "input": [
       "import math\n",
-      "#calculate final pressure and enthalpy and etropy\n",
+      "#calculate final pressure and enthalpy and piston rise\n",
       "##initialisation of variables\n",
       "p0= 100. ##kpa\n",
       "A= 0.1 ##m^2\n",
@@ -561,13 +581,13 @@
       "u2= 2728.7 ##kJ/kg\n",
       "v3= 0.9942 ##m^3/kg\n",
       "##CALCULATIONS\n",
-      "pe= (p0+(F/A))/1000\n",
+      "pe= (p0+(F/A))/1000.\n",
       "h3= (m1*u1-m2*u2)/m3\n",
       "z3= m3*v3/A\n",
       "##RESULTS\n",
-      "print'%s %.1f %s'%('final pressure =',pe,'Mpa') \n",
-      "print'%s %.1f %s'%('enthalpy = ',h3,'kJ/kg') \n",
-      "print'%s %.2f %s'%('piston rise =',z3,'m') \n"
+      "print'%s %.2f %s'% (' final pressure = ',pe,' Mpa') \n",
+      "print'%s %.2f %s'% (' \\n enthalpy = ',h3,' kJ/kg') \n",
+      "print'%s %.2f %s'% ('\\n piston rise = ',z3,' m') \n"
      ],
      "language": "python",
      "metadata": {},
@@ -576,13 +596,15 @@
        "output_type": "stream",
        "stream": "stdout",
        "text": [
-        "final pressure = 0.3 Mpa\n",
-        "enthalpy =  3225.9 kJ/kg\n",
-        "piston rise = 8.82 m\n"
+        " final pressure =  0.30  Mpa\n",
+        " \n",
+        " enthalpy =  3225.86  kJ/kg\n",
+        "\n",
+        " piston rise =  8.82  m\n"
        ]
       }
      ],
-     "prompt_number": 14
+     "prompt_number": 25
     }
    ],
    "metadata": {}
diff --git a/Thermodynamics:_From_concepts_to_applications/chapter12.ipynb b/Thermodynamics:_From_concepts_to_applications/chapter12.ipynb
deleted file mode 100755
index aea962e5..00000000
--- a/Thermodynamics:_From_concepts_to_applications/chapter12.ipynb
+++ /dev/null
@@ -1,314 +0,0 @@
-{
- "metadata": {
-  "name": "",
-  "signature": "sha256:2837d214113f06819e10997f047a7eaa67f457e584a6b0f4db06b83606bfd8b8"
- },
- "nbformat": 3,
- "nbformat_minor": 0,
- "worksheets": [
-  {
-   "cells": [
-    {
-     "cell_type": "heading",
-     "level": 1,
-     "metadata": {},
-     "source": [
-      "Chapter12-ideal gas mixtures and humid air"
-     ]
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Example1-pg 251"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "#calculate molecular weight of air\n",
-      "##initialisation of variables\n",
-      "x= 0.78\n",
-      "x1= 0.21\n",
-      "x2= 0.008\n",
-      "x3= 0.002\n",
-      "MN2= 28.013 ##gms\n",
-      "MO2= 32. ##gms\n",
-      "MAr= 39.948 ##gms\n",
-      "MH2O= 18.016 ##gms\n",
-      "##CALCULATIONS\n",
-      "M= x*MN2+x1*MO2+x2*MAr+x3*MH2O\n",
-      "##RESULTS\n",
-      "print'%s %.3f %s'% ('molecular wight of air=',M,'kg/kmol')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "molecular wight of air= 28.926 kg/kmol\n"
-       ]
-      }
-     ],
-     "prompt_number": 1
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Example2-pg254"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "#calculate average value and mass\n",
-      "##initialisation of variables\n",
-      "M= 30.04 ##kg/kmol\n",
-      "R= 8.3143 ##J/mol K\n",
-      "p= 100. ##kPa\n",
-      "V= 0.2 ##m^3\n",
-      "T= 25. ##C\n",
-      "##CALCULATIONS\n",
-      "R1= R/M\n",
-      "m= p*V/(R1*(273.15+T))\n",
-      "##RESULTS\n",
-      "print'%s %.4f %s'% ('average value of R=',R1,'kJ/kg K')\n",
-      "print'%s %.3f %s'% ('mass=',m,'kg')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "average value of R= 0.2768 kJ/kg K\n",
-        "mass= 0.242 kg\n"
-       ]
-      }
-     ],
-     "prompt_number": 2
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Example3-pg256"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "#calculate final temperature and final pressure and change in entropy\n",
-      "##initialisation of variables\n",
-      "m1= 0.5 ##kg\n",
-      "cv1= 0.6496 ##kJ/kg K\n",
-      "T1= 80. ##C\n",
-      "m2= 1. ##kg\n",
-      "cv2= 0.6299 ##kJ/kg K\n",
-      "T2= 150. ##C\n",
-      "M= 32. ##kg\n",
-      "M1= 44. ##kg\n",
-      "V1= 0.11437 ##m^3\n",
-      "V2= 0.1 ##m^2\n",
-      "R= 8.314 ##J/mol K\n",
-      "##CALCULATIONS\n",
-      "T= (m1*cv1*(273.15+T1)+m2*cv2*(273.15+T2))/(m1*cv1+m2*cv2)\n",
-      "p= ((m1/M)+(m2/M1))*R*T/(V1+V2)\n",
-      "S= m1*(cv1*math.log(T/(273.15+T1))+(R/M)*math.log((V1+V2)/V1))+m2*(cv2*math.log(T/(273.15+T2))+(R/M1)*math.log((V1+V2)/V2))\n",
-      "##RESULTS\n",
-      "print'%s %.1f %s'% ('final temperature=',T,'kPa')\n",
-      "print'%s %.1f %s'% ('final pressure=',p,'kPa')\n",
-      "print'%s %.4f %s'% ('change in entropy=',S,'kJ/K')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "final temperature= 399.3 kPa\n",
-        "final pressure= 594.0 kPa\n",
-        "change in entropy= 0.2291 kJ/K\n"
-       ]
-      }
-     ],
-     "prompt_number": 3
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Example4-pg268\n"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "#calculate wet-bulb temoerature and minimum temperature and amount of water injected\n",
-      "##initialisation of variables\n",
-      "Twb= 22. ##C\n",
-      "Tmin= 22.3 ##C\n",
-      "w2= 0.0170 ##kg/kg dry air\n",
-      "w1= 0.0093 ##kg/kg dry air\n",
-      "##CALCULATIONS\n",
-      "m= w2-w1\n",
-      "##RESULTS\n",
-      "print'%s %.f %s'% (' wet-bulb temperature=',Twb,'C')\n",
-      "print'%s %.f %s'% ('minimum temperature=',Tmin,'1C')\n",
-      "print'%s %.4f %s'% ('amount of water injected=',m,'kg/kg dry air')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        " wet-bulb temperature= 22 C\n",
-        "minimum temperature= 22 1C\n",
-        "amount of water injected= 0.0077 kg/kg dry air\n"
-       ]
-      }
-     ],
-     "prompt_number": 4
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Example5-pg269"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "#calculate state after mixing\n",
-      "##initialisation of variables\n",
-      "w3= 0.0178 ##kg/kgair\n",
-      "w4= 0.0172 ##kg/kgair\n",
-      "##CALCULATIONS\n",
-      "dw= w3-w4\n",
-      "##RESULTS\n",
-      "print'%s %.4f %s'% (' state after mixing=',dw,'kg/kgair')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        " state after mixing= 0.0006 kg/kgair\n"
-       ]
-      }
-     ],
-     "prompt_number": 5
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Example6-pg271"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "#calculate air mass flow rate and amount of water to be added\n",
-      "##initialisation of variables\n",
-      "m= 20000. ##kg/h\n",
-      "T1= 42. ##C\n",
-      "T2= 22. ##C\n",
-      "J= 4.186 ##cal\n",
-      "h1= 54. ##kJ/kg\n",
-      "h2= 94.8 ##kJ/kg\n",
-      "w1= 0.0105 ##kg/h kg\n",
-      "w2= 0.0244 ##kg/h kg\n",
-      "##CALCULATIONS\n",
-      "ma= m*(T1-T2)*J/((h2-h1-J*T2*(w2-w1)))\n",
-      "mw= ma*(w2-w1)\n",
-      "m4= m-mw\n",
-      "##RESULTS\n",
-      "print'%s %.1f %s'%('air mass flow rate=',ma,'kg/hr')\n",
-      "print'%s %.f %s'%('amount of water to be added=',m4,'kg/hr')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "air mass flow rate= 42368.5 kg/hr\n",
-        "amount of water to be added= 19411 kg/hr\n"
-       ]
-      }
-     ],
-     "prompt_number": 6
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Example7-pg272"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "#calculate maximum useful work\n",
-      "##initialisation of variables\n",
-      "x= 0.79\n",
-      "P0= 101 ##kPa\n",
-      "P= 20 ##Mpa\n",
-      "V= 0.032 ##m^3\n",
-      "##CALCULATIONS\n",
-      "p= x*P0\n",
-      "Wrev= P*10*10*10*V*(math.log(P/(p*math.pow(10,-3)))+((p*math.pow(10,-3))/P)-1)\n",
-      "##RESULTS\n",
-      "print'%s %.1f %s'% (' maximum useful work=',Wrev,'kJ')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        " maximum useful work= 2898.0 kJ\n"
-       ]
-      }
-     ],
-     "prompt_number": 7
-    }
-   ],
-   "metadata": {}
-  }
- ]
-}
-\ No newline at end of file
diff --git a/Thermodynamics:_From_concepts_to_applications/chapter12_1.ipynb b/Thermodynamics:_From_concepts_to_applications/chapter12_1.ipynb
deleted file mode 100755
index aea962e5..00000000
--- a/Thermodynamics:_From_concepts_to_applications/chapter12_1.ipynb
+++ /dev/null
@@ -1,314 +0,0 @@
-{
- "metadata": {
-  "name": "",
-  "signature": "sha256:2837d214113f06819e10997f047a7eaa67f457e584a6b0f4db06b83606bfd8b8"
- },
- "nbformat": 3,
- "nbformat_minor": 0,
- "worksheets": [
-  {
-   "cells": [
-    {
-     "cell_type": "heading",
-     "level": 1,
-     "metadata": {},
-     "source": [
-      "Chapter12-ideal gas mixtures and humid air"
-     ]
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Example1-pg 251"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "#calculate molecular weight of air\n",
-      "##initialisation of variables\n",
-      "x= 0.78\n",
-      "x1= 0.21\n",
-      "x2= 0.008\n",
-      "x3= 0.002\n",
-      "MN2= 28.013 ##gms\n",
-      "MO2= 32. ##gms\n",
-      "MAr= 39.948 ##gms\n",
-      "MH2O= 18.016 ##gms\n",
-      "##CALCULATIONS\n",
-      "M= x*MN2+x1*MO2+x2*MAr+x3*MH2O\n",
-      "##RESULTS\n",
-      "print'%s %.3f %s'% ('molecular wight of air=',M,'kg/kmol')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "molecular wight of air= 28.926 kg/kmol\n"
-       ]
-      }
-     ],
-     "prompt_number": 1
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Example2-pg254"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "#calculate average value and mass\n",
-      "##initialisation of variables\n",
-      "M= 30.04 ##kg/kmol\n",
-      "R= 8.3143 ##J/mol K\n",
-      "p= 100. ##kPa\n",
-      "V= 0.2 ##m^3\n",
-      "T= 25. ##C\n",
-      "##CALCULATIONS\n",
-      "R1= R/M\n",
-      "m= p*V/(R1*(273.15+T))\n",
-      "##RESULTS\n",
-      "print'%s %.4f %s'% ('average value of R=',R1,'kJ/kg K')\n",
-      "print'%s %.3f %s'% ('mass=',m,'kg')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "average value of R= 0.2768 kJ/kg K\n",
-        "mass= 0.242 kg\n"
-       ]
-      }
-     ],
-     "prompt_number": 2
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Example3-pg256"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "#calculate final temperature and final pressure and change in entropy\n",
-      "##initialisation of variables\n",
-      "m1= 0.5 ##kg\n",
-      "cv1= 0.6496 ##kJ/kg K\n",
-      "T1= 80. ##C\n",
-      "m2= 1. ##kg\n",
-      "cv2= 0.6299 ##kJ/kg K\n",
-      "T2= 150. ##C\n",
-      "M= 32. ##kg\n",
-      "M1= 44. ##kg\n",
-      "V1= 0.11437 ##m^3\n",
-      "V2= 0.1 ##m^2\n",
-      "R= 8.314 ##J/mol K\n",
-      "##CALCULATIONS\n",
-      "T= (m1*cv1*(273.15+T1)+m2*cv2*(273.15+T2))/(m1*cv1+m2*cv2)\n",
-      "p= ((m1/M)+(m2/M1))*R*T/(V1+V2)\n",
-      "S= m1*(cv1*math.log(T/(273.15+T1))+(R/M)*math.log((V1+V2)/V1))+m2*(cv2*math.log(T/(273.15+T2))+(R/M1)*math.log((V1+V2)/V2))\n",
-      "##RESULTS\n",
-      "print'%s %.1f %s'% ('final temperature=',T,'kPa')\n",
-      "print'%s %.1f %s'% ('final pressure=',p,'kPa')\n",
-      "print'%s %.4f %s'% ('change in entropy=',S,'kJ/K')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "final temperature= 399.3 kPa\n",
-        "final pressure= 594.0 kPa\n",
-        "change in entropy= 0.2291 kJ/K\n"
-       ]
-      }
-     ],
-     "prompt_number": 3
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Example4-pg268\n"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "#calculate wet-bulb temoerature and minimum temperature and amount of water injected\n",
-      "##initialisation of variables\n",
-      "Twb= 22. ##C\n",
-      "Tmin= 22.3 ##C\n",
-      "w2= 0.0170 ##kg/kg dry air\n",
-      "w1= 0.0093 ##kg/kg dry air\n",
-      "##CALCULATIONS\n",
-      "m= w2-w1\n",
-      "##RESULTS\n",
-      "print'%s %.f %s'% (' wet-bulb temperature=',Twb,'C')\n",
-      "print'%s %.f %s'% ('minimum temperature=',Tmin,'1C')\n",
-      "print'%s %.4f %s'% ('amount of water injected=',m,'kg/kg dry air')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        " wet-bulb temperature= 22 C\n",
-        "minimum temperature= 22 1C\n",
-        "amount of water injected= 0.0077 kg/kg dry air\n"
-       ]
-      }
-     ],
-     "prompt_number": 4
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Example5-pg269"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "#calculate state after mixing\n",
-      "##initialisation of variables\n",
-      "w3= 0.0178 ##kg/kgair\n",
-      "w4= 0.0172 ##kg/kgair\n",
-      "##CALCULATIONS\n",
-      "dw= w3-w4\n",
-      "##RESULTS\n",
-      "print'%s %.4f %s'% (' state after mixing=',dw,'kg/kgair')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        " state after mixing= 0.0006 kg/kgair\n"
-       ]
-      }
-     ],
-     "prompt_number": 5
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Example6-pg271"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "#calculate air mass flow rate and amount of water to be added\n",
-      "##initialisation of variables\n",
-      "m= 20000. ##kg/h\n",
-      "T1= 42. ##C\n",
-      "T2= 22. ##C\n",
-      "J= 4.186 ##cal\n",
-      "h1= 54. ##kJ/kg\n",
-      "h2= 94.8 ##kJ/kg\n",
-      "w1= 0.0105 ##kg/h kg\n",
-      "w2= 0.0244 ##kg/h kg\n",
-      "##CALCULATIONS\n",
-      "ma= m*(T1-T2)*J/((h2-h1-J*T2*(w2-w1)))\n",
-      "mw= ma*(w2-w1)\n",
-      "m4= m-mw\n",
-      "##RESULTS\n",
-      "print'%s %.1f %s'%('air mass flow rate=',ma,'kg/hr')\n",
-      "print'%s %.f %s'%('amount of water to be added=',m4,'kg/hr')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "air mass flow rate= 42368.5 kg/hr\n",
-        "amount of water to be added= 19411 kg/hr\n"
-       ]
-      }
-     ],
-     "prompt_number": 6
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Example7-pg272"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "#calculate maximum useful work\n",
-      "##initialisation of variables\n",
-      "x= 0.79\n",
-      "P0= 101 ##kPa\n",
-      "P= 20 ##Mpa\n",
-      "V= 0.032 ##m^3\n",
-      "##CALCULATIONS\n",
-      "p= x*P0\n",
-      "Wrev= P*10*10*10*V*(math.log(P/(p*math.pow(10,-3)))+((p*math.pow(10,-3))/P)-1)\n",
-      "##RESULTS\n",
-      "print'%s %.1f %s'% (' maximum useful work=',Wrev,'kJ')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        " maximum useful work= 2898.0 kJ\n"
-       ]
-      }
-     ],
-     "prompt_number": 7
-    }
-   ],
-   "metadata": {}
-  }
- ]
-}
-\ No newline at end of file
diff --git a/Thermodynamics:_From_concepts_to_applications/chapter12_2.ipynb b/Thermodynamics:_From_concepts_to_applications/chapter12_2.ipynb
deleted file mode 100755
index aea962e5..00000000
--- a/Thermodynamics:_From_concepts_to_applications/chapter12_2.ipynb
+++ /dev/null
@@ -1,314 +0,0 @@
-{
- "metadata": {
-  "name": "",
-  "signature": "sha256:2837d214113f06819e10997f047a7eaa67f457e584a6b0f4db06b83606bfd8b8"
- },
- "nbformat": 3,
- "nbformat_minor": 0,
- "worksheets": [
-  {
-   "cells": [
-    {
-     "cell_type": "heading",
-     "level": 1,
-     "metadata": {},
-     "source": [
-      "Chapter12-ideal gas mixtures and humid air"
-     ]
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Example1-pg 251"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "#calculate molecular weight of air\n",
-      "##initialisation of variables\n",
-      "x= 0.78\n",
-      "x1= 0.21\n",
-      "x2= 0.008\n",
-      "x3= 0.002\n",
-      "MN2= 28.013 ##gms\n",
-      "MO2= 32. ##gms\n",
-      "MAr= 39.948 ##gms\n",
-      "MH2O= 18.016 ##gms\n",
-      "##CALCULATIONS\n",
-      "M= x*MN2+x1*MO2+x2*MAr+x3*MH2O\n",
-      "##RESULTS\n",
-      "print'%s %.3f %s'% ('molecular wight of air=',M,'kg/kmol')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "molecular wight of air= 28.926 kg/kmol\n"
-       ]
-      }
-     ],
-     "prompt_number": 1
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Example2-pg254"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "#calculate average value and mass\n",
-      "##initialisation of variables\n",
-      "M= 30.04 ##kg/kmol\n",
-      "R= 8.3143 ##J/mol K\n",
-      "p= 100. ##kPa\n",
-      "V= 0.2 ##m^3\n",
-      "T= 25. ##C\n",
-      "##CALCULATIONS\n",
-      "R1= R/M\n",
-      "m= p*V/(R1*(273.15+T))\n",
-      "##RESULTS\n",
-      "print'%s %.4f %s'% ('average value of R=',R1,'kJ/kg K')\n",
-      "print'%s %.3f %s'% ('mass=',m,'kg')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "average value of R= 0.2768 kJ/kg K\n",
-        "mass= 0.242 kg\n"
-       ]
-      }
-     ],
-     "prompt_number": 2
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Example3-pg256"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "#calculate final temperature and final pressure and change in entropy\n",
-      "##initialisation of variables\n",
-      "m1= 0.5 ##kg\n",
-      "cv1= 0.6496 ##kJ/kg K\n",
-      "T1= 80. ##C\n",
-      "m2= 1. ##kg\n",
-      "cv2= 0.6299 ##kJ/kg K\n",
-      "T2= 150. ##C\n",
-      "M= 32. ##kg\n",
-      "M1= 44. ##kg\n",
-      "V1= 0.11437 ##m^3\n",
-      "V2= 0.1 ##m^2\n",
-      "R= 8.314 ##J/mol K\n",
-      "##CALCULATIONS\n",
-      "T= (m1*cv1*(273.15+T1)+m2*cv2*(273.15+T2))/(m1*cv1+m2*cv2)\n",
-      "p= ((m1/M)+(m2/M1))*R*T/(V1+V2)\n",
-      "S= m1*(cv1*math.log(T/(273.15+T1))+(R/M)*math.log((V1+V2)/V1))+m2*(cv2*math.log(T/(273.15+T2))+(R/M1)*math.log((V1+V2)/V2))\n",
-      "##RESULTS\n",
-      "print'%s %.1f %s'% ('final temperature=',T,'kPa')\n",
-      "print'%s %.1f %s'% ('final pressure=',p,'kPa')\n",
-      "print'%s %.4f %s'% ('change in entropy=',S,'kJ/K')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "final temperature= 399.3 kPa\n",
-        "final pressure= 594.0 kPa\n",
-        "change in entropy= 0.2291 kJ/K\n"
-       ]
-      }
-     ],
-     "prompt_number": 3
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Example4-pg268\n"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "#calculate wet-bulb temoerature and minimum temperature and amount of water injected\n",
-      "##initialisation of variables\n",
-      "Twb= 22. ##C\n",
-      "Tmin= 22.3 ##C\n",
-      "w2= 0.0170 ##kg/kg dry air\n",
-      "w1= 0.0093 ##kg/kg dry air\n",
-      "##CALCULATIONS\n",
-      "m= w2-w1\n",
-      "##RESULTS\n",
-      "print'%s %.f %s'% (' wet-bulb temperature=',Twb,'C')\n",
-      "print'%s %.f %s'% ('minimum temperature=',Tmin,'1C')\n",
-      "print'%s %.4f %s'% ('amount of water injected=',m,'kg/kg dry air')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        " wet-bulb temperature= 22 C\n",
-        "minimum temperature= 22 1C\n",
-        "amount of water injected= 0.0077 kg/kg dry air\n"
-       ]
-      }
-     ],
-     "prompt_number": 4
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Example5-pg269"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "#calculate state after mixing\n",
-      "##initialisation of variables\n",
-      "w3= 0.0178 ##kg/kgair\n",
-      "w4= 0.0172 ##kg/kgair\n",
-      "##CALCULATIONS\n",
-      "dw= w3-w4\n",
-      "##RESULTS\n",
-      "print'%s %.4f %s'% (' state after mixing=',dw,'kg/kgair')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        " state after mixing= 0.0006 kg/kgair\n"
-       ]
-      }
-     ],
-     "prompt_number": 5
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Example6-pg271"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "#calculate air mass flow rate and amount of water to be added\n",
-      "##initialisation of variables\n",
-      "m= 20000. ##kg/h\n",
-      "T1= 42. ##C\n",
-      "T2= 22. ##C\n",
-      "J= 4.186 ##cal\n",
-      "h1= 54. ##kJ/kg\n",
-      "h2= 94.8 ##kJ/kg\n",
-      "w1= 0.0105 ##kg/h kg\n",
-      "w2= 0.0244 ##kg/h kg\n",
-      "##CALCULATIONS\n",
-      "ma= m*(T1-T2)*J/((h2-h1-J*T2*(w2-w1)))\n",
-      "mw= ma*(w2-w1)\n",
-      "m4= m-mw\n",
-      "##RESULTS\n",
-      "print'%s %.1f %s'%('air mass flow rate=',ma,'kg/hr')\n",
-      "print'%s %.f %s'%('amount of water to be added=',m4,'kg/hr')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "air mass flow rate= 42368.5 kg/hr\n",
-        "amount of water to be added= 19411 kg/hr\n"
-       ]
-      }
-     ],
-     "prompt_number": 6
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Example7-pg272"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "#calculate maximum useful work\n",
-      "##initialisation of variables\n",
-      "x= 0.79\n",
-      "P0= 101 ##kPa\n",
-      "P= 20 ##Mpa\n",
-      "V= 0.032 ##m^3\n",
-      "##CALCULATIONS\n",
-      "p= x*P0\n",
-      "Wrev= P*10*10*10*V*(math.log(P/(p*math.pow(10,-3)))+((p*math.pow(10,-3))/P)-1)\n",
-      "##RESULTS\n",
-      "print'%s %.1f %s'% (' maximum useful work=',Wrev,'kJ')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        " maximum useful work= 2898.0 kJ\n"
-       ]
-      }
-     ],
-     "prompt_number": 7
-    }
-   ],
-   "metadata": {}
-  }
- ]
-}
-\ No newline at end of file
diff --git a/Thermodynamics:_From_concepts_to_applications/chapter12_ideal_gas_mixtures_and_humid_air.ipynb b/Thermodynamics:_From_concepts_to_applications/chapter12_ideal_gas_mixtures_and_humid_air.ipynb
deleted file mode 100755
index aea962e5..00000000
--- a/Thermodynamics:_From_concepts_to_applications/chapter12_ideal_gas_mixtures_and_humid_air.ipynb
+++ /dev/null
@@ -1,314 +0,0 @@
-{
- "metadata": {
-  "name": "",
-  "signature": "sha256:2837d214113f06819e10997f047a7eaa67f457e584a6b0f4db06b83606bfd8b8"
- },
- "nbformat": 3,
- "nbformat_minor": 0,
- "worksheets": [
-  {
-   "cells": [
-    {
-     "cell_type": "heading",
-     "level": 1,
-     "metadata": {},
-     "source": [
-      "Chapter12-ideal gas mixtures and humid air"
-     ]
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Example1-pg 251"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "#calculate molecular weight of air\n",
-      "##initialisation of variables\n",
-      "x= 0.78\n",
-      "x1= 0.21\n",
-      "x2= 0.008\n",
-      "x3= 0.002\n",
-      "MN2= 28.013 ##gms\n",
-      "MO2= 32. ##gms\n",
-      "MAr= 39.948 ##gms\n",
-      "MH2O= 18.016 ##gms\n",
-      "##CALCULATIONS\n",
-      "M= x*MN2+x1*MO2+x2*MAr+x3*MH2O\n",
-      "##RESULTS\n",
-      "print'%s %.3f %s'% ('molecular wight of air=',M,'kg/kmol')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "molecular wight of air= 28.926 kg/kmol\n"
-       ]
-      }
-     ],
-     "prompt_number": 1
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Example2-pg254"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "#calculate average value and mass\n",
-      "##initialisation of variables\n",
-      "M= 30.04 ##kg/kmol\n",
-      "R= 8.3143 ##J/mol K\n",
-      "p= 100. ##kPa\n",
-      "V= 0.2 ##m^3\n",
-      "T= 25. ##C\n",
-      "##CALCULATIONS\n",
-      "R1= R/M\n",
-      "m= p*V/(R1*(273.15+T))\n",
-      "##RESULTS\n",
-      "print'%s %.4f %s'% ('average value of R=',R1,'kJ/kg K')\n",
-      "print'%s %.3f %s'% ('mass=',m,'kg')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "average value of R= 0.2768 kJ/kg K\n",
-        "mass= 0.242 kg\n"
-       ]
-      }
-     ],
-     "prompt_number": 2
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Example3-pg256"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "#calculate final temperature and final pressure and change in entropy\n",
-      "##initialisation of variables\n",
-      "m1= 0.5 ##kg\n",
-      "cv1= 0.6496 ##kJ/kg K\n",
-      "T1= 80. ##C\n",
-      "m2= 1. ##kg\n",
-      "cv2= 0.6299 ##kJ/kg K\n",
-      "T2= 150. ##C\n",
-      "M= 32. ##kg\n",
-      "M1= 44. ##kg\n",
-      "V1= 0.11437 ##m^3\n",
-      "V2= 0.1 ##m^2\n",
-      "R= 8.314 ##J/mol K\n",
-      "##CALCULATIONS\n",
-      "T= (m1*cv1*(273.15+T1)+m2*cv2*(273.15+T2))/(m1*cv1+m2*cv2)\n",
-      "p= ((m1/M)+(m2/M1))*R*T/(V1+V2)\n",
-      "S= m1*(cv1*math.log(T/(273.15+T1))+(R/M)*math.log((V1+V2)/V1))+m2*(cv2*math.log(T/(273.15+T2))+(R/M1)*math.log((V1+V2)/V2))\n",
-      "##RESULTS\n",
-      "print'%s %.1f %s'% ('final temperature=',T,'kPa')\n",
-      "print'%s %.1f %s'% ('final pressure=',p,'kPa')\n",
-      "print'%s %.4f %s'% ('change in entropy=',S,'kJ/K')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "final temperature= 399.3 kPa\n",
-        "final pressure= 594.0 kPa\n",
-        "change in entropy= 0.2291 kJ/K\n"
-       ]
-      }
-     ],
-     "prompt_number": 3
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Example4-pg268\n"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "#calculate wet-bulb temoerature and minimum temperature and amount of water injected\n",
-      "##initialisation of variables\n",
-      "Twb= 22. ##C\n",
-      "Tmin= 22.3 ##C\n",
-      "w2= 0.0170 ##kg/kg dry air\n",
-      "w1= 0.0093 ##kg/kg dry air\n",
-      "##CALCULATIONS\n",
-      "m= w2-w1\n",
-      "##RESULTS\n",
-      "print'%s %.f %s'% (' wet-bulb temperature=',Twb,'C')\n",
-      "print'%s %.f %s'% ('minimum temperature=',Tmin,'1C')\n",
-      "print'%s %.4f %s'% ('amount of water injected=',m,'kg/kg dry air')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        " wet-bulb temperature= 22 C\n",
-        "minimum temperature= 22 1C\n",
-        "amount of water injected= 0.0077 kg/kg dry air\n"
-       ]
-      }
-     ],
-     "prompt_number": 4
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Example5-pg269"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "#calculate state after mixing\n",
-      "##initialisation of variables\n",
-      "w3= 0.0178 ##kg/kgair\n",
-      "w4= 0.0172 ##kg/kgair\n",
-      "##CALCULATIONS\n",
-      "dw= w3-w4\n",
-      "##RESULTS\n",
-      "print'%s %.4f %s'% (' state after mixing=',dw,'kg/kgair')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        " state after mixing= 0.0006 kg/kgair\n"
-       ]
-      }
-     ],
-     "prompt_number": 5
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Example6-pg271"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "#calculate air mass flow rate and amount of water to be added\n",
-      "##initialisation of variables\n",
-      "m= 20000. ##kg/h\n",
-      "T1= 42. ##C\n",
-      "T2= 22. ##C\n",
-      "J= 4.186 ##cal\n",
-      "h1= 54. ##kJ/kg\n",
-      "h2= 94.8 ##kJ/kg\n",
-      "w1= 0.0105 ##kg/h kg\n",
-      "w2= 0.0244 ##kg/h kg\n",
-      "##CALCULATIONS\n",
-      "ma= m*(T1-T2)*J/((h2-h1-J*T2*(w2-w1)))\n",
-      "mw= ma*(w2-w1)\n",
-      "m4= m-mw\n",
-      "##RESULTS\n",
-      "print'%s %.1f %s'%('air mass flow rate=',ma,'kg/hr')\n",
-      "print'%s %.f %s'%('amount of water to be added=',m4,'kg/hr')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "air mass flow rate= 42368.5 kg/hr\n",
-        "amount of water to be added= 19411 kg/hr\n"
-       ]
-      }
-     ],
-     "prompt_number": 6
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Example7-pg272"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "#calculate maximum useful work\n",
-      "##initialisation of variables\n",
-      "x= 0.79\n",
-      "P0= 101 ##kPa\n",
-      "P= 20 ##Mpa\n",
-      "V= 0.032 ##m^3\n",
-      "##CALCULATIONS\n",
-      "p= x*P0\n",
-      "Wrev= P*10*10*10*V*(math.log(P/(p*math.pow(10,-3)))+((p*math.pow(10,-3))/P)-1)\n",
-      "##RESULTS\n",
-      "print'%s %.1f %s'% (' maximum useful work=',Wrev,'kJ')\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        " maximum useful work= 2898.0 kJ\n"
-       ]
-      }
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-     "prompt_number": 7
-    }
-   ],
-   "metadata": {}
-  }
- ]
-}
-\ No newline at end of file
author	hardythe1	2015-05-05 14:21:39 +0530
committer	hardythe1	2015-05-05 14:21:39 +0530
commit	fba055ce5aa0955e22bac2413c33493b10ae6532 (patch)
tree	be70ef4fccd07c9c88de778014219201b4ea971f /Thermodynamics:_From_concepts_to_applications
parent	67068710030ddd6b6c809518c34af2e04e0bf7ca (diff)
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