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| author | hardythe1 | 2015-05-05 14:21:39 +0530 |
|---|---|---|
| committer | hardythe1 | 2015-05-05 14:21:39 +0530 |
| commit | 435840cef00c596d9e608f9eb2d96f522ea8505a (patch) | |
| tree | 4c783890c984c67022977ca98432e5e4bab30678 /Thermodynamics:_From_concepts_to_applications/Chapter13-.ipynb | |
| parent | aa1863f344766ca7f7c20a395e58d0fb23c52130 (diff) | |
| download | Python-Textbook-Companions-435840cef00c596d9e608f9eb2d96f522ea8505a.tar.gz Python-Textbook-Companions-435840cef00c596d9e608f9eb2d96f522ea8505a.tar.bz2 Python-Textbook-Companions-435840cef00c596d9e608f9eb2d96f522ea8505a.zip | |
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Diffstat (limited to 'Thermodynamics:_From_concepts_to_applications/Chapter13-.ipynb')
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diff --git a/Thermodynamics:_From_concepts_to_applications/Chapter13-.ipynb b/Thermodynamics:_From_concepts_to_applications/Chapter13-.ipynb deleted file mode 100755 index cb096e14..00000000 --- a/Thermodynamics:_From_concepts_to_applications/Chapter13-.ipynb +++ /dev/null @@ -1,217 +0,0 @@ -{
- "metadata": {
- "name": "",
- "signature": "sha256:8d95c094e950bc8cd1f4bbc97c09344d22cf81b1ba4d6101a144be7a5e1e83dc"
- },
- "nbformat": 3,
- "nbformat_minor": 0,
- "worksheets": [
- {
- "cells": [
- {
- "cell_type": "heading",
- "level": 1,
- "metadata": {},
- "source": [
- "Chapter13-thermodynamic relations"
- ]
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example2-pg284"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "#calculate entropy wrt pressures and volume wrt temerature\n",
- "##initialisation of variables\n",
- "S1= 6.539 ##kJ/kg K\n",
- "S2= 6.7664 ##kJ/kg K\n",
- "v1= 0.10976 ##m^3\n",
- "v2= 0.08700 ##m^3\n",
- "P= 3. ##Mpa\n",
- "P1= 2. ##Mpa\n",
- "T= 350. ##K\n",
- "T1= 250. ##K\n",
- "S3= 3.1741 ##kJ/kg K\n",
- "S4= 3.2071 ##kJ/kg K\n",
- "P2= 30. ##Mpa\n",
- "P3= 20. ##Mpa\n",
- "v3= 0.0014217 ##m^3\n",
- "v4= 0.0012860 ##m^3\n",
- "T2= 320. ##K\n",
- "T3= 280. ##K\n",
- "##CALCULATIONS\n",
- "r= (S1-S2)/(P*10*10*10-P1*10*10*10)\n",
- "r1= (v1-v2)/(T-T1)\n",
- "R= (S3-S4)/(P2*10*10*10-P3*10*10*10)\n",
- "R1= (v3-v4)/(T2-T3)\n",
- "##RESULTS\n",
- "print'%s %.7f %s'% ('entropy wrt pressre=',r,'kJ/kg K kpa')\n",
- "print'%s %.e %s'% ('entropy wrt pressre=',R,'kJ/kg K kpa')\n",
- "print'%s %.7f %s'% ('volume wrt temperature=',r1,'m^3/kg K ')\n",
- "print'%s %.2e %s'% ('volume wrt temperature=',R1,'m^3/kg K ')\n"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "entropy wrt pressre= -0.0002274 kJ/kg K kpa\n",
- "entropy wrt pressre= -3e-06 kJ/kg K kpa\n",
- "volume wrt temperature= 0.0002276 m^3/kg K \n",
- "volume wrt temperature= 3.39e-06 m^3/kg K \n"
- ]
- }
- ],
- "prompt_number": 6
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example3-pg286"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "#saturation pressure\n",
- "##initialisation of variables\n",
- "hfg= 2406.7 ##kJ/kg\n",
- "Psat40= 7.384 ##kPa\n",
- "R= 8.314 ##J/mol K\n",
- "T= 40. ##C\n",
- "T1= 50. ##C\n",
- "M= 18.##kg\n",
- "##CALCULATIONS\n",
- "Psat50= Psat40*math.e**((hfg*M/R)*((1/(273.15+T))-(1/(273.15+T1))))\n",
- "##RESULTS\n",
- "print'%s %.3f %s' %('Saturation pressure=',Psat50,'kPa')\n"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "Saturation pressure= 12.357 kPa\n"
- ]
- }
- ],
- "prompt_number": 2
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example4-pg287"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "#calcualte lowest temprature\n",
- "##initialisation of variables\n",
- "W= 800. ##N\n",
- "A= 0.4 ##cm^2\n",
- "p= 0.611 ##Mpa\n",
- "P1= 0.1 ##Mpa\n",
- "T= 0.01 ##C\n",
- "vs= 0.0010908 ##m^3/kg\n",
- "hs= -333.40 ##kJ/kg\n",
- "vf= 0.0010002 ##m^3/kg\n",
- "hf= 0 ##kJ/kg\n",
- "vg= 206.14 ##m^3/kg\n",
- "hg= 2501.4 ##kJ/kg\n",
- "##CALCULATIONS\n",
- "P2= P1+(W/A)*math.pow(10,(4-6))\n",
- "dT= (273.15++T)*(vf-vs)*(P2*10*10*10-p)/(0-hs)\n",
- "Tmin= dT+T\n",
- "##RESULTS\n",
- "print'%s %.2f %s'% ('lowest temperature=',Tmin,'C')\n"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "lowest temperature= -1.48 C\n"
- ]
- }
- ],
- "prompt_number": 3
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example7-pg292"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "import math\n",
- "#calculate volume exapansion coefficent and isothermal compressibilitiy and isotherma modulus of elasticity\n",
- "##initialisation of variables\n",
- "vi= 0.0009992 ##m^3\n",
- "T= 60. ##C\n",
- "T1= 20. ##C\n",
- "T2= 40. ##C\n",
- "vi1= 0.0010042 ##m^3\n",
- "vi2= 0.0009886 ##m^3\n",
- "v= 0.000951 ##m^3\n",
- "v1= 0.0009992 ##m^3\n",
- "v2= 0.0009956 ##m^3\n",
- "##CALCULATIONS\n",
- "B= (vi1-vi2)/(vi*(T-T1))\n",
- "Kt= (v1-v2)/(v*(T2-T1))\n",
- "Et= 1/Kt\n",
- "##RESULTS\n",
- "print'%s %.2e %s'% ('volume exapansion coefficient=',B,'L/s')\n",
- "print'%s %.3e %s'% ('isothermal compressibility=',Kt,'Mpa')\n",
- "print'%s %.f %s'% ('isothermal modulus of elasticity=',Et,'Mpa')\n",
- "\n",
- "\n",
- "##ANSWER FOR Et GIVEN IN THE TEXTBOOK IS WRONG\n"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "volume exapansion coefficient= 3.90e-04 L/s\n",
- "isothermal compressibility= 1.893e-04 Mpa\n",
- "isothermal modulus of elasticity= 5283 Mpa\n"
- ]
- }
- ],
- "prompt_number": 4
- }
- ],
- "metadata": {}
- }
- ]
-}
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