adding book & removing unwanted files

1 files changed, 1100 insertions, 0 deletions

diff --git a/Textbook_of_Engineering_Chemistry/dChapter_3.ipynb b/Textbook_of_Engineering_Chemistry/dChapter_3.ipynb
new file mode 100755
index 00000000..5406df23
--- /dev/null
+++ b/Textbook_of_Engineering_Chemistry/dChapter_3.ipynb
@@ -0,0 +1,1100 @@
+{

+ "metadata": {

+  "name": ""

+ },

+ "nbformat": 3,

+ "nbformat_minor": 0,

+ "worksheets": [

+  {

+   "cells": [

+    {

+     "cell_type": "heading",

+     "level": 1,

+     "metadata": {},

+     "source": [

+      "Chapter 3:Chemical Kinetics & Catalysis"

+     ]

+    },

+    {

+     "cell_type": "heading",

+     "level": 2,

+     "metadata": {},

+     "source": [

+      "Example no:1,Page no:69"

+     ]

+    },

+    {

+     "cell_type": "code",

+     "collapsed": false,

+     "input": [

+      "import math\n",

+      "from scipy.optimize import fsolve\n",

+      "#Variable declaration\n",

+      "A0=0.25      #[M]\n",

+      "At=0.15      #[M]\n",

+      "k=6.7*10**-4\n",

+      "\n",

+      "#Calculation\n",

+      "def f(t):\n",

+      "    x=math.log10(A0/At)-(k*t)/2.303\n",

+      "    return(x)\n",

+      "t=fsolve(f,1)\n",

+      "\n",

+      "#Result\n",

+      "print\"Time taken to decrease concentration is%.3e\"%t[0],\"s (approx)\"\n",

+      "print\"NOTE: Approximate value taken in book\"\n",

+      "\n",

+      "    "

+     ],

+     "language": "python",

+     "metadata": {},

+     "outputs": [

+      {

+       "output_type": "stream",

+       "stream": "stdout",

+       "text": [

+        "Time taken to decrease concentration is7.626e+02 s (approx)\n",

+        "NOTE: Approximate value taken in book\n"

+       ]

+      }

+     ],

+     "prompt_number": 1

+    },

+    {

+     "cell_type": "heading",

+     "level": 2,

+     "metadata": {},

+     "source": [

+      "Example no:2,Page no:71"

+     ]

+    },

+    {

+     "cell_type": "code",

+     "collapsed": false,

+     "input": [

+      "#Variable declaration\n",

+      "#Initially:\n",

+      "A=0.1         #Concentration of A\n",

+      "B=0.1         #Concentration of B\n",

+      "rate=5.5*10**-6     #Rate of reaction initial in M/s\n",

+      "x=2             #exponent\n",

+      "y=1             #exponent\n",

+      "\n",

+      "#Calculation\n",

+      "order=x+y        #Reaction order\n",

+      "k=rate/((A**x)*(B**y))        #Rate law constant in [M**2/s]\n",

+      "\n",

+      "#Result\n",

+      "print\"The rate law is k=rate/(A**2)*(B)\"\n",

+      "print\"\\nRate constant is %.2e\"%k,\"M**2/s\"\n"

+     ],

+     "language": "python",

+     "metadata": {},

+     "outputs": [

+      {

+       "output_type": "stream",

+       "stream": "stdout",

+       "text": [

+        "The rate law is k=rate/(A**2)*(B)\n",

+        "\n",

+        "Rate constant is 5.50e-03 M**2/s\n"

+       ]

+      }

+     ],

+     "prompt_number": 2

+    },

+    {

+     "cell_type": "heading",

+     "level": 2,

+     "metadata": {},

+     "source": [

+      "Example no:3,Page no:76"

+     ]

+    },

+    {

+     "cell_type": "code",

+     "collapsed": false,

+     "input": [

+      "#Variable declaration\n",

+      "\n",

+      "T=[700.0,730.0,760.0,790.0]             #Temperature in [K]\n",

+      "k=[0.011,0.035,0.195,0.343]      #rate constants in [L/mol s]\n",

+      "import numpy \n",

+      "onebyT=numpy.reciprocal(T)      #Reciprocal of temperature\n",

+      "log_k=numpy.log10(k)             #log of k\n",

+      "R=8.30*10**-3       #[kJ/kmol]\n",

+      "\n",

+      "#Calculation\n",

+      "%pylab inline\n",

+      "import matplotlib.pyplot as plt\n",

+      "plt.plot(onebyT,log_k)\n",

+      "plt.ylabel('$log k$')\n",

+      "plt.xlabel('$1/T$')\n",

+      "plt.title('1/T vs log k\\n')\n",

+      "slope,intercept=np.polyfit(onebyT,log_k,1)\n",

+      "print\"Slope is\",slope\n",

+      "plt.show()\n",

+      "slope=-9.9*10**3       #Slope given in book [K]\n",

+      "E_star=slope*(-2.303*R)     #Activation energy in [kJ/mol]\n",

+      "\n",

+      "#Result\n",

+      "print\"Activation energy of reaction is\",round(E_star,1),\"kJ/mol\"\n",

+      "print\"NOTE that in book slope is approximated as 9.9*10**3 K\""

+     ],

+     "language": "python",

+     "metadata": {},

+     "outputs": [

+      {

+       "output_type": "stream",

+       "stream": "stdout",

+       "text": [

+        "Populating the interactive namespace from numpy and matplotlib\n",

+        "Slope is"

+       ]

+      },

+      {

+       "output_type": "stream",

+       "stream": "stdout",

+       "text": [

+        " -9663.82327366\n"

+       ]

+      },

+      {

+       "metadata": {},

+       "output_type": "display_data",

+       "png": "iVBORw0KGgoAAAANSUhEUgAAAYoAAAEuCAYAAACQ81XoAAAABHNCSVQICAgIfAhkiAAAAAlwSFlz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\nBgUREenEoCAiIp0YFEREpBODgoiIdPr//OMNiNnaocoAAAAASUVORK5CYII=\n",

+       "text": [

+        "<matplotlib.figure.Figure at 0x7a19438>"

+       ]

+      },

+      {

+       "output_type": "stream",

+       "stream": "stdout",

+       "text": [

+        "Activation energy of reaction is 189.2 kJ/mol\n",

+        "NOTE that in book slope is approximated as 9.9*10**3 K\n"

+       ]

+      }

+     ],

+     "prompt_number": 1

+    },

+    {

+     "cell_type": "heading",

+     "level": 2,

+     "metadata": {},

+     "source": [

+      "Example no:3.2,Page no:86"

+     ]

+    },

+    {

+     "cell_type": "code",

+     "collapsed": false,

+     "input": [

+      "#Variable declaration\n",

+      "T1=10.0 #in min\n",

+      "T2=20.0 #in min\n",

+      "a=25.0 #amount of KMnO4 in ml at t=0min#\n",

+      "a1=20.0 #amount of KMnO4 in ml at t=10min or a-x value at t=10#\n",

+      "a2=15.7 #a-x value at t=20min#\n",

+      "import math\n",

+      "\n",

+      "#Calculation\n",

+      "k1=(2.303/T1)*math.log10(a/a1) #formula of rate constant for first order reaction#\n",

+      "print\"At t=10min rate constant k=\",round(k1,5),\"/min\"\n",

+      "k2=(2.303/T2)*math.log10(a/a2) #rate constant formula#\n",

+      "\n",

+      "#Result\n",

+      "print\"\\nAt t=20min rate constant k=\",round(k2,5),\"/min\" \n",

+      "print\"\\nNOTE:Calculation mistake in book\"\n",

+      "print\"\\nIf we calculate the rate constant at other t values we will see that k values are almost constnat\""

+     ],

+     "language": "python",

+     "metadata": {},

+     "outputs": [

+      {

+       "output_type": "stream",

+       "stream": "stdout",

+       "text": [

+        "At t=10min rate constant k= 0.02232 /min\n",

+        "\n",

+        "At t=20min rate constant k= 0.02326 /min\n",

+        "\n",

+        "NOTE:Calculation mistake in book\n",

+        "\n",

+        "If we calculate the rate constant at other t values we will see that k values are almost constnat\n"

+       ]

+      }

+     ],

+     "prompt_number": 2

+    },

+    {

+     "cell_type": "heading",

+     "level": 2,

+     "metadata": {},

+     "source": [

+      "Example no:3.3,Page no:87"

+     ]

+    },

+    {

+     "cell_type": "code",

+     "collapsed": false,

+     "input": [

+      "#Variable declaration\n",

+      "T=40.5 #in min#\n",

+      "R1=25.0 #percentage of decomposed reactant#\n",

+      "import math\n",

+      "\n",

+      "#Calculation\n",

+      "R2=100.0-R1 #percentage of left out reactant which is a-x value#\n",

+      "R3=100.0/R2 #value of a/(a-x)#\n",

+      "K=(2.303/T)*math.log10(R3) #formula of rate constant for first order reaction#\n",

+      "\n",

+      "#Result\n",

+      "print\"The rate constant of the reaction is %.2e\"%K,\"/min\" \n"

+     ],

+     "language": "python",

+     "metadata": {},

+     "outputs": [

+      {

+       "output_type": "stream",

+       "stream": "stdout",

+       "text": [

+        "The rate constant of the reaction is 7.10e-03 /min\n"

+       ]

+      }

+     ],

+     "prompt_number": 3

+    },

+    {

+     "cell_type": "heading",

+     "level": 2,

+     "metadata": {},

+     "source": [

+      "Example no:3.4,Page no:87"

+     ]

+    },

+    {

+     "cell_type": "code",

+     "collapsed": false,

+     "input": [

+      "#Variable declaration\n",

+      "pi=0.0 #pressure of N2 at t=0#\n",

+      "t1=2.0 \n",

+      "t2=8.0 \n",

+      "t3=16.0 \n",

+      "t4=24.0 \n",

+      "t5=50.0 \n",

+      "pf=34.0 #pressure of N2 at infinity#\n",

+      "p1=1.6 #pressure of N2 at t=2min#\n",

+      "p2=6.2 #pressure of N2 at t=8min#\n",

+      "p3=11.2 #pressure Of N2 at t=16min#\n",

+      "p4=15.5 #pressure of N2 at t=24min#\n",

+      "p5=24.4 #pressure of N2 at t=50min#\n",

+      "import math\n",

+      "\n",

+      "#Calculation\n",

+      "a=pf-pi #value of a#\n",

+      "a1=pf-p1 #a-x value at t=2min#\n",

+      "a2=pf-p2 #a-x value at t=8min#\n",

+      "a3=pf-p3 #a-x value at t=16min#\n",

+      "a4=pf-p4 #a-x value at t=24min#\n",

+      "a5=pf-p5 #a-x value at t=50min#\n",

+      "k1=(1/t1)*math.log(a/a1) #rate constant at t=2min#\n",

+      "k2=(1/t2)*math.log(a/a2) #rate constant at t=8min#\n",

+      "k3=(1/t3)*math.log(a/a3) #rate constant at t=16min#\n",

+      "k4=(1/t4)*math.log(a/a4) #rate constant at t=24min#\n",

+      "k5=(1/t5)*math.log(a/a5) #rate constant at t=50min#\n",

+      "k=(k1+k2+k3+k4+k5)/5 \n",

+      "\n",

+      "#Result\n",

+      "print\"Time(min):   2\\t\\t8\\t\\t16\\t\\t24\\t\\t50\"\n",

+      "print\"k1 per min  %.2e\\t\"%k1,\"%.2e\\t\"%k2,\"%.2e\\t\"%k3,\"%.3e\\t\"%k4,\"%.2e\"%k5\n",

+      "print\"\\nAverage rate constant is %.3e\"%k,\"min^-1\""

+     ],

+     "language": "python",

+     "metadata": {},

+     "outputs": [

+      {

+       "output_type": "stream",

+       "stream": "stdout",

+       "text": [

+        "Time(min):   2\t\t8\t\t16\t\t24\t\t50\n",

+        "k1 per min  2.41e-02\t2.52e-02\t2.50e-02\t2.536e-02\t2.53e-02\n",

+        "\n",

+        "Average rate constant is 2.498e-02 min^-1\n"

+       ]

+      }

+     ],

+     "prompt_number": 4

+    },

+    {

+     "cell_type": "heading",

+     "level": 1,

+     "metadata": {},

+     "source": [

+      "Example no:3.5.,Page no:88"

+     ]

+    },

+    {

+     "cell_type": "code",

+     "collapsed": false,

+     "input": [

+      "#Variable declaration\n",

+      "t1=0 \n",

+      "t2=4.89 \n",

+      "t3=10.07 \n",

+      "t4=23.66 \n",

+      "v1=47.65 #ml of alkali used  at t=0min or a value#\n",

+      "v2=38.92 #ml of alkali used or a-x value at t=4.89min#\n",

+      "v3=32.62 #ml of alkali used or a-x value at t=10.07min#\n",

+      "v4=22.58 #ml of alkali used or a-x value at t=23.66min#\n",

+      "\n",

+      "#Calculation\n",

+      "x2=v1-v2 #x value at t=4.89min#\n",

+      "x3=v1-v3 #x value at t=10.07min#\n",

+      "x4=v1-v4 #x value at t=23.66min#\n",

+      "k22=(1/t2)*(x2/(v1*v2)) #rate constant for second order equation#\n",

+      "\n",

+      "#Result\n",

+      "print\"Rate constant k2 value at t=\",t2,\"min is \",round(k22,6),\"/min\"\n",

+      "k23=(1/t3)*(x3/(v1*v3)) #rate constant for second order equation#\n",

+      "print\"\\nRate constant k2 value at t=\",t3,\"min is \",round(k23,6),\"/min\"\n",

+      "k24=(1/t4)*(x4/(v1*v4)) #rate constant for second order equation#\n",

+      "print\"\\nRate constant k2 value at t=\",t4,\"min is\",round(k24,5),\"/min\" \n",

+      "print\"\\nAlmost constant values of k2 indicate that reaction is second order\""

+     ],

+     "language": "python",

+     "metadata": {},

+     "outputs": [

+      {

+       "output_type": "stream",

+       "stream": "stdout",

+       "text": [

+        "Rate constant k2 value at t= 4.89 min is  0.000963 /min\n",

+        "\n",

+        "Rate constant k2 value at t= 10.07 min is  0.00096 /min\n",

+        "\n",

+        "Rate constant k2 value at t= 23.66 min is 0.00098 /min\n",

+        "\n",

+        "Almost constant values of k2 indicate that reaction is second order\n"

+       ]

+      }

+     ],

+     "prompt_number": 5

+    },

+    {

+     "cell_type": "heading",

+     "level": 2,

+     "metadata": {},

+     "source": [

+      "Example no:3.6,Page no:88"

+     ]

+    },

+    {

+     "cell_type": "code",

+     "collapsed": false,

+     "input": [

+      "#Variable declaration\n",

+      "t=1590 #half life of given radio active element in years#\n",

+      "\n",

+      "#Calculation\n",

+      "k=0.693/t #formula of decay constant for first order reactions#\n",

+      "\n",

+      "#Result\n",

+      "print\"the value of decay constant is \",round(k,6),\"/year\""

+     ],

+     "language": "python",

+     "metadata": {},

+     "outputs": [

+      {

+       "output_type": "stream",

+       "stream": "stdout",

+       "text": [

+        "the value of decay constant is  0.000436 /year\n"

+       ]

+      }

+     ],

+     "prompt_number": 6

+    },

+    {

+     "cell_type": "heading",

+     "level": 2,

+     "metadata": {},

+     "source": [

+      "Example no:3.8,Page no:89"

+     ]

+    },

+    {

+     "cell_type": "code",

+     "collapsed": false,

+     "input": [

+      "#Variable declaration\n",

+      "t1=5.0 \n",

+      "t2=15.0 \n",

+      "t3=25.0 \n",

+      "t4=45.0 \n",

+      "a=37.0 #volume of KMnO4 in cm**3 at t=0 or value of a#\n",

+      "a1=29.8 #volume of KMnO4 in cm**3 or a-x value at t=5min#\n",

+      "a2=19.6 #volume of KMnO4 in cm**3 or a-x value at t=15min#\n",

+      "a3=12.3 #volume of KMnO4 in cm**3 or a-x value at t=25min#\n",

+      "a4=5.0 #volume of KMnO4 in cm**3 or a-x value at t=45min#\n",

+      "import math\n",

+      "\n",

+      "#Calculation\n",

+      "k1=(2.303/t1)*math.log10(a/a1) \n",

+      "print\"\\nRate constant value at t=5min is %.3e\"%k1,\"min**-1\"\n",

+      "k2=(2.303/t2)*math.log10(a/a2) \n",

+      "print\"\\nRate constant value at t=15min is %.3e\"%k2,\"min**-1\"\n",

+      "k3=(2.303/t3)*math.log10(a/a3) \n",

+      "print\"\\nRate constant value at t=25min is %.3e\"%k3,\"min**-1\"\n",

+      "k4=(2.303/t4)*math.log10(a/a4) \n",

+      "print\"\\nRate constant value at t=45min is %.3e\"%k4,\"min**-1\"\n",

+      "print\"\\nAs the different values of k are nearly same,the reaction is of first oredr.\"\n",

+      "k=(k1+k2+k3+k4)/4.0 \n",

+      "\n",

+      "#Result\n",

+      "print\"\\nThe average value of k is %.3e\"%k,\"min**-1\""

+     ],

+     "language": "python",

+     "metadata": {},

+     "outputs": [

+      {

+       "output_type": "stream",

+       "stream": "stdout",

+       "text": [

+        "\n",

+        "Rate constant value at t=5min is 4.329e-02 min**-1\n",

+        "\n",

+        "Rate constant value at t=15min is 4.237e-02 min**-1\n",

+        "\n",

+        "Rate constant value at t=25min is 4.406e-02 min**-1\n",

+        "\n",

+        "Rate constant value at t=45min is 4.449e-02 min**-1\n",

+        "\n",

+        "As the different values of k are nearly same,the reaction is of first oredr.\n",

+        "\n",

+        "The average value of k is 4.355e-02 min**-1\n"

+       ]

+      }

+     ],

+     "prompt_number": 7

+    },

+    {

+     "cell_type": "heading",

+     "level": 2,

+     "metadata": {},

+     "source": [

+      "Example no:3.9,Page no:89"

+     ]

+    },

+    {

+     "cell_type": "code",

+     "collapsed": false,

+     "input": [

+      "#Variable declaration\n",

+      "k=6.0*10**-4 #rate constant of first order decomposition of N2O5 in CCl4 in /min#\n",

+      "\n",

+      "#Calculation\n",

+      "#Part-a#\n",

+      "k1=k/60.0 \n",

+      "#Part-b#\n",

+      "t=0.693/k \n",

+      "\n",

+      "#Result\n",

+      "print\"(a) Rate constant in terms of seconds is \",k1,\"/s\"\n",

+      "print\"\\n(b) Half life of the reaction is %.2e\"%t,\"min\"\n",

+      "print\"NOTE:Slight rounding off in book in final answer\""

+     ],

+     "language": "python",

+     "metadata": {},

+     "outputs": [

+      {

+       "output_type": "stream",

+       "stream": "stdout",

+       "text": [

+        "(a) Rate constant in terms of seconds is  1e-05 /s\n",

+        "\n",

+        "(b) Half life of the reaction is 1.15e+03 min\n",

+        "NOTE:Slight rounding off in book in final answer\n"

+       ]

+      }

+     ],

+     "prompt_number": 8

+    },

+    {

+     "cell_type": "heading",

+     "level": 2,

+     "metadata": {},

+     "source": [

+      "Example no:3.10,Page no:90"

+     ]

+    },

+    {

+     "cell_type": "code",

+     "collapsed": false,

+     "input": [

+      "#Variable declaration\n",

+      "t1=40.0 \n",

+      "t2=80.0 \n",

+      "t3=120.0 \n",

+      "t4=160.0 \n",

+      "t5=240.0 \n",

+      "vi=0.0 #volume of oxygen collected at constant pressure in ml at t=0#\n",

+      "v1=15.6 #volume of oxygen collected at constant pressure in ml at t=40#\n",

+      "v2=27.6 #volume of oxygen collected at constant pressure in ml at t=80#\n",

+      "v3=37.7 #volume of oxygen collected at constant pressure in ml at t=120#\n",

+      "v4=45.8 #volume of oxygen collected at constant pressure in ml at t=160#\n",

+      "v5=58.3 #volume of oxygen collected at constant pressure in ml at t=200#\n",

+      "vf=84.6 #volume of oxygen collected at constant pressure in ml at t=infinity#\n",

+      "import math\n",

+      "\n",

+      "#Calculation\n",

+      "a=vf-vi #the initial concentration of N2O5 in solution i.e a#\n",

+      "a1=vf-v1 #a-x value at t=40min#\n",

+      "a2=vf-v2 #a-x value at t=80min#\n",

+      "a3=vf-v3 #a-x value at t=120min#\n",

+      "a4=vf-v4 #a-x value at t=160min#\n",

+      "a5=vf-v5 #a-x value at t=200min#\n",

+      "k1=(1.0/t1)*math.log(a/a1) \n",

+      "k2=(1.0/t2)*math.log(a/a2) \n",

+      "k3=(1.0/t3)*math.log(a/a3) \n",

+      "k4=(1.0/t4)*math.log(a/a4) \n",

+      "k5=(1.0/t5)*math.log(a/a5) \n",

+      "\n",

+      "#Result\n",

+      "print\"Time(min):   40\\t\\t80\\t\\t120\\t\\t160\\t\\t240\"\n",

+      "print\"k1 per min  %.2e\\t\"%k1,\"%.2e\\t\"%k2,\"%.2e\\t\"%k3,\"%.3e\\t\"%k4,\"%.2e\"%k5\n",

+      "print\"\\nNOTE:Calculation mistake in book in calculating a4,it should be 38.8\"\n",

+      "print\"\\nAs k value is fairly constant the reaction is first order\""

+     ],

+     "language": "python",

+     "metadata": {},

+     "outputs": [

+      {

+       "output_type": "stream",

+       "stream": "stdout",

+       "text": [

+        "Time(min):   40\t\t80\t\t120\t\t160\t\t240\n",

+        "k1 per min  5.10e-03\t4.94e-03\t4.92e-03\t4.872e-03\t4.87e-03\n",

+        "\n",

+        "NOTE:Calculation mistake in book in calculating a4,it should be 38.8\n",

+        "\n",

+        "As k value is fairly constant the reaction is first order\n"

+       ]

+      }

+     ],

+     "prompt_number": 9

+    },

+    {

+     "cell_type": "heading",

+     "level": 2,

+     "metadata": {},

+     "source": [

+      "Example no:3.11,Page no:90"

+     ]

+    },

+    {

+     "cell_type": "code",

+     "collapsed": false,

+     "input": [

+      "#Variable declaration\n",

+      "t1=120.0 #time in sec#\n",

+      "t2=240.0 \n",

+      "t3=530.0 \n",

+      "t4=600.0 \n",

+      "a=0.05 #initial concentration#\n",

+      "x1=32.95 #extent of reaction or x value at t=120sce#\n",

+      "x2=48.8 #extent of reaction or x value at t=240sce#\n",

+      "x3=69.0 #extent of reaction or x value at t=530sce#\n",

+      "x4=70.35 #extent of reaction or x value at t=600sce#\n",

+      "a1=100.0-x1 #extent of left out or a-x value at t=120sec#\n",

+      "a2=100.0-x2 #extent of left out or a-x value at t=240sec#\n",

+      "a3=100.0-x3 #extent of left out or a-x value at t=530sec#\n",

+      "a4=100.0-x4 #extent of left out or a-x value at t=600sec#\n",

+      "\n",

+      "#Calculation\n",

+      "k1=(1.0/(a*t1))*(x1/a1) \n",

+      "print\"Rate constant value at t=120sec is %.2e\"%k1,\"dm**3 mol**-1.s**-1\"\n",

+      "k2=(1.0/(a*t2))*(x2/a2) \n",

+      "print\"\\nRate constant value at t=240sec is %.2e\"%k2,\"dm**3 mol**-1.s**-1\"\n",

+      "k3=(1.0/(a*t3))*(x3/a3) \n",

+      "print\"\\nRate constant value at t=530sec is %.2e\"%k3,\"dm**3 mol**-1.s**-1\"\n",

+      "k4=(1.0/(a*t4))*(x4/a4) \n",

+      "print\"\\nRate constant value at t=600sec is %.2e\"%k4,\"dm**3 mol**-1.s**-1\"\n",

+      "k=(k1+k2+k3+k4)/4.0 \n",

+      "\n",

+      "#Result\n",

+      "print\"\\n\\nAverage value of rate constant is %.1e\"%k,\"dm**3 mol**-1.s**-1\"\n"

+     ],

+     "language": "python",

+     "metadata": {},

+     "outputs": [

+      {

+       "output_type": "stream",

+       "stream": "stdout",

+       "text": [

+        "Rate constant value at t=120sec is 8.19e-02 dm**3 mol**-1.s**-1\n",

+        "\n",

+        "Rate constant value at t=240sec is 7.94e-02 dm**3 mol**-1.s**-1\n",

+        "\n",

+        "Rate constant value at t=530sec is 8.40e-02 dm**3 mol**-1.s**-1\n",

+        "\n",

+        "Rate constant value at t=600sec is 7.91e-02 dm**3 mol**-1.s**-1\n",

+        "\n",

+        "\n",

+        "Average value of rate constant is 8.1e-02 dm**3 mol**-1.s**-1\n"

+       ]

+      }

+     ],

+     "prompt_number": 10

+    },

+    {

+     "cell_type": "heading",

+     "level": 2,

+     "metadata": {},

+     "source": [

+      "Example no:3.13,Page no:91"

+     ]

+    },

+    {

+     "cell_type": "code",

+     "collapsed": false,

+     "input": [

+      "#Variable declaration\n",

+      "t1=75.0 #time in min#\n",

+      "t2=119.0 \n",

+      "t3=183.0 \n",

+      "vi=9.62 #volume of alkali used in ml at t=0min#\n",

+      "v1=12.10 #volume of alkali used in ml at t=75min#\n",

+      "v2=13.10 #volume of alkali used in ml at t=119min#\n",

+      "v3=14.75 #volume of alkali used in ml at t=183min#\n",

+      "vf=21.05 #volume of alkali used in ml at t=infinity#\n",

+      "import math\n",

+      "\n",

+      "#Calculation\n",

+      "k1=(1.0/t1)*math.log((vf-vi)/(vf-v1)) #formula of rate constant for first order reactions#\n",

+      "k2=(1.0/t2)*math.log((vf-vi)/(vf-v2)) \n",

+      "k3=(1.0/t3)*math.log((vf-vi)/(vf-v3)) \n",

+      "\n",

+      "#Result\n",

+      "print\"\\nRate constant value at t=75min is \",round(k1,6),\"min**-1\"\n",

+      "print\"\\nRate constant value at t=119min is \",round(k2,6),\"min**-1\"\n",

+      "print\"\\nRate constant value at t=183min is \",round(k3,6),\"min**-1\"\n",

+      "\n",

+      "print\"\\nNOTE:Slight Calculation mistake in book in k calculation above\" \n",

+      "print\"\\nAn almost constant value of k shows that the hydrolysis of ethyl acetateis a first order reaction\"\n",

+      "\n"

+     ],

+     "language": "python",

+     "metadata": {},

+     "outputs": [

+      {

+       "output_type": "stream",

+       "stream": "stdout",

+       "text": [

+        "\n",

+        "Rate constant value at t=75min is  0.003261 min**-1\n",

+        "\n",

+        "Rate constant value at t=119min is  0.003051 min**-1\n",

+        "\n",

+        "Rate constant value at t=183min is  0.003255 min**-1\n",

+        "\n",

+        "NOTE:Slight Calculation mistake in book in k calculation above\n",

+        "\n",

+        "An almost constant value of k shows that the hydrolysis of ethyl acetateis a first order reaction\n"

+       ]

+      }

+     ],

+     "prompt_number": 11

+    },

+    {

+     "cell_type": "heading",

+     "level": 2,

+     "metadata": {},

+     "source": [

+      "Example no:3.14,Page no:92"

+     ]

+    },

+    {

+     "cell_type": "code",

+     "collapsed": false,

+     "input": [

+      "#Variable declaration\n",

+      "t=15 #the half time of given first order reaction in min#\n",

+      "k=0.693/t #formula of rate constant#\n",

+      "print\"The rate constant value of the given first order reaction is  is\",k,\"min**-1\"\n",

+      "a=100 #percentage of initial concentration#\n",

+      "x=80 #percentage of completed reaction#\n",

+      "import math\n",

+      "\n",

+      "#Calculation\n",

+      "a1=a-x #percentage of left out concentration#\n",

+      "t1=(2.303/k)*(math.log10(a/a1)) #formula to find time taken#\n",

+      "t2=t1*60 \n",

+      "\n",

+      "#Result\n",

+      "print\"\\nThe time taken to complete 80 percentage of the reaction is  \",round(t1,2),\"min or\",round(t2),\"sec\""

+     ],

+     "language": "python",

+     "metadata": {},

+     "outputs": [

+      {

+       "output_type": "stream",

+       "stream": "stdout",

+       "text": [

+        "The rate constant value of the given first order reaction is  is 0.0462 min**-1\n",

+        "\n",

+        "The time taken to complete 80 percentage of the reaction is   34.84 min or 2091.0 sec\n"

+       ]

+      }

+     ],

+     "prompt_number": 12

+    },

+    {

+     "cell_type": "heading",

+     "level": 2,

+     "metadata": {},

+     "source": [

+      "Example no:3.15,Page no:92"

+     ]

+    },

+    {

+     "cell_type": "code",

+     "collapsed": false,

+     "input": [

+      "#Variable declaration\n",

+      "t1=6.18 #time in min#\n",

+      "t2=18.0 \n",

+      "t3=27.05 \n",

+      "ri=24.09 #rotation in degrees when t=0min#\n",

+      "r1=21.4 #rotation in degrees when t=6.18min#\n",

+      "r2=17.7 #rotation in degrees when t=18min#\n",

+      "r3=15.0 #rotation in degrees when t=27.05min#\n",

+      "rf=-10.74 #rotation in degrees when t=infinity#\n",

+      "import math\n",

+      "\n",

+      "#Calculation\n",

+      "a=ri-rf #a value#\n",

+      "a1=r1-rf #a-x value at t=6.18min#\n",

+      "a2=r2-rf #a-x value at t=18min#\n",

+      "a3=r3-rf #a-x value at t=27.05min#\n",

+      "k1=(2.303/t1)*math.log10(a/a1) \n",

+      "k2=(2.303/t2)*math.log10(a/a2) \n",

+      "k3=(2.303/t3)*math.log10(a/a3) \n",

+      "\n",

+      "#Result\n",

+      "print\"Rate constant value at t=\",t1,\"min %.3e\"%k1,\"min**-1\"\n",

+      "print\"\\nRate constant value at t=\",t2,\"min %.3e\"%k2,\"min**-1\"\n",

+      "print\"\\nRate constant value at t=\",t3,\"min %.3e\"%k3,\"min**-1\"\n",

+      "\n",

+      "print\"\\nNOTE:Again,Calculation mistake in book\"\n",

+      "print\"\\nSince rate constant values are nearly same,hence reaction is of first order\"\n"

+     ],

+     "language": "python",

+     "metadata": {},

+     "outputs": [

+      {

+       "output_type": "stream",

+       "stream": "stdout",

+       "text": [

+        "Rate constant value at t= 6.18 min 1.301e-02 min**-1\n",

+        "\n",

+        "Rate constant value at t= 18.0 min 1.126e-02 min**-1\n",

+        "\n",

+        "Rate constant value at t= 27.05 min 1.118e-02 min**-1\n",

+        "\n",

+        "NOTE:Again,Calculation mistake in book\n",

+        "\n",

+        "Since rate constant values are nearly same,hence reaction is of first order\n"

+       ]

+      }

+     ],

+     "prompt_number": 13

+    },

+    {

+     "cell_type": "heading",

+     "level": 2,

+     "metadata": {},

+     "source": [

+      "Example no:3.16,Page no:93"

+     ]

+    },

+    {

+     "cell_type": "code",

+     "collapsed": false,

+     "input": [

+      "#Variable declaration\n",

+      "t1=10.0#time in min#\n",

+      "t2=20.0 \n",

+      "t3=30.0 \n",

+      "t4=40.0 \n",

+      "ri=32.4 #rotation in degrees when t=0min#\n",

+      "r1=28.8 #rotation in degrees when t=10min#\n",

+      "r2=25.5 #rotation in degrees when t=20min#\n",

+      "r3=22.4 #rotation in degrees when t=30min#\n",

+      "r4=19.6 #rotation in degrees when t=40min#\n",

+      "rf=-11.1 #rotation in degrees when t=0min#\n",

+      "import math\n",

+      "\n",

+      "#Calculation\n",

+      "a=ri-rf #a value#\n",

+      "a1=r1-rf #a-x value at t=10min#\n",

+      "a2=r2-rf #a-x value at t=20min#\n",

+      "a3=r3-rf #a-x value at t=30min#\n",

+      "a4=r4-rf #a-x value at t=40min#\n",

+      "k1=(1.0/t1)*math.log(a/a1) \n",

+      "k2=(1.0/t2)*math.log(a/a2) \n",

+      "k3=(1.0/t3)*math.log(a/a3) \n",

+      "k4=(1.0/t4)*math.log(a/a4) \n",

+      "\n",

+      "#Result\n",

+      "print\"Rate constant value at t=10min \",round(k1,6),\"min**-1\"\n",

+      "print\"\\nRate constant value at t=20min \",round(k2,6),\"min**-1\"\n",

+      "print\"\\nRate constant value at t=30min \",round(k3,6),\"min**-1\"\n",

+      "print\"\\nRate constant value at t=40min \",round(k4,6),\"min**-1\"\n",

+      "print\"\\nSince rate constant values are nearly same,hence inversion of sucrose is of first order\""

+     ],

+     "language": "python",

+     "metadata": {},

+     "outputs": [

+      {

+       "output_type": "stream",

+       "stream": "stdout",

+       "text": [

+        "Rate constant value at t=10min  0.008638 min**-1\n",

+        "\n",

+        "Rate constant value at t=20min  0.008636 min**-1\n",

+        "\n",

+        "Rate constant value at t=30min  0.008707 min**-1\n",

+        "\n",

+        "Rate constant value at t=40min  0.008712 min**-1\n",

+        "\n",

+        "Since rate constant values are nearly same,hence inversion of sucrose is of first order\n"

+       ]

+      }

+     ],

+     "prompt_number": 14

+    },

+    {

+     "cell_type": "heading",

+     "level": 2,

+     "metadata": {},

+     "source": [

+      "Example no:3.17,Page no:93"

+     ]

+    },

+    {

+     "cell_type": "code",

+     "collapsed": false,

+     "input": [

+      "#Variable declaration\n",

+      "T1=27.0 #initial temparature in C#\n",

+      "T1=T1+273 #in kelvin#\n",

+      "Tr=10.0 #rise in temparature#\n",

+      "T2=T1+Tr #final temparature in kelvin#\n",

+      "r=2.0 #ratio of final to initial rates of chemical reactions(k1/k2)#\n",

+      "R=8.314 #value of constant R in J/K.mol#\n",

+      "import math\n",

+      "\n",

+      "#Calculation\n",

+      "E=math.log(r)*R*305*295/Tr #from equation k=A*e**(-E/R*T)#\n",

+      "\n",

+      "#Result\n",

+      "print\"Activation energy of the reaction is \",round(E/1000,2),\"kJ/mol\"\n"

+     ],

+     "language": "python",

+     "metadata": {},

+     "outputs": [

+      {

+       "output_type": "stream",

+       "stream": "stdout",

+       "text": [

+        "Activation energy of the reaction is  51.85 kJ/mol\n"

+       ]

+      }

+     ],

+     "prompt_number": 15

+    },

+    {

+     "cell_type": "heading",

+     "level": 2,

+     "metadata": {},

+     "source": [

+      "Example no:3.18,Page no:94"

+     ]

+    },

+    {

+     "cell_type": "code",

+     "collapsed": false,

+     "input": [

+      "#Variable declaration\n",

+      "k=4.5*10**3 #value of k in /sec of a first order reaction at 1C#\n",

+      "E=58*10**3 #activation energy in J/mol#\n",

+      "T=1 #temperature in C#\n",

+      "T1=T+273 #in kelvin#\n",

+      "R=8.314 #value of constant R in J/K.mol#\n",

+      "import math\n",

+      "\n",

+      "#Calculation\n",

+      "lA=math.log10(k)+(E/(2.303*R*T1)) \n",

+      "k1=10**4 #value of k in /sec at some temperature#\n",

+      "a=math.log10(k1) \n",

+      "b=lA-a \n",

+      "T2=E/(2.303*R*b) \n",

+      "\n",

+      "#Result\n",

+      "print\"The temperature at which k=1*10**4/sec is\",round(T2),\"K\""

+     ],

+     "language": "python",

+     "metadata": {},

+     "outputs": [

+      {

+       "output_type": "stream",

+       "stream": "stdout",

+       "text": [

+        "The temperature at which k=1*10**4/sec is 283.0 K\n"

+       ]

+      }

+     ],

+     "prompt_number": 16

+    },

+    {

+     "cell_type": "heading",

+     "level": 2,

+     "metadata": {},

+     "source": [

+      "Example no:3.19,Page no:94"

+     ]

+    },

+    {

+     "cell_type": "code",

+     "collapsed": false,

+     "input": [

+      "#Variable declaration\n",

+      "T1=300.0 #temperature in kelvin#\n",

+      "t1=20.0 #half time of chemical reaction in min at T=300K#\n",

+      "T2=350.0 #temperature in kelvin#\n",

+      "t2=5.0 #half time of chemical reaction in min at T=350K#\n",

+      "import math\n",

+      "\n",

+      "#Calculation\n",

+      "k1=0.6932/t1 \n",

+      "k2=0.6932/t2 \n",

+      "l=math.log10(k2/k1) \n",

+      "R=8.314 #value of constant R in J/K.mol#\n",

+      "E=l*2.303*R*T1*T2/(T2-T1) \n",

+      "\n",

+      "#Result\n",

+      "print\"Rate constant of the reaction at T=300k is \",k1,\"/min\" \n",

+      "print\"\\nRate constant of the reaction at T=350k is \",k2,\"/min\"\n",

+      "print\"\\nActivation energy of the reaction is\",E,\"J/mol OR\",round(E/1000,1),\"kJ/mol\""

+     ],

+     "language": "python",

+     "metadata": {},

+     "outputs": [

+      {

+       "output_type": "stream",

+       "stream": "stdout",

+       "text": [

+        "Rate constant of the reaction at T=300k is  0.03466 /min\n",

+        "\n",

+        "Rate constant of the reaction at T=350k is  0.13864 /min\n",

+        "\n",

+        "Activation energy of the reaction is 24208.2291076 J/mol OR 24.2 kJ/mol\n"

+       ]

+      }

+     ],

+     "prompt_number": 17

+    },

+    {

+     "cell_type": "heading",

+     "level": 2,

+     "metadata": {},

+     "source": [

+      "Example no:3.20,Page no:94"

+     ]

+    },

+    {

+     "cell_type": "code",

+     "collapsed": false,

+     "input": [

+      "#Variable declaration\n",

+      "R=8.314 #value of constant R in J/K.mol#\n",

+      "H=1.25*10**4 #value of E/(2.303*R).It is given in the question#\n",

+      "\n",

+      "#Calculation\n",

+      "\n",

+      "#Part-i#\n",

+      "E=H*2.303*R \n",

+      "la=14.34 #value of math.log(a)#\n",

+      "T=670 #temperature in kelvin#\n",

+      "#Part-ii#\n",

+      "lk=la-(H/T) \n",

+      "k=10**lk \n",

+      "\n",

+      "#Result\n",

+      "print\"(i)  Activation energy is  %.2e\"%E,\"J mol**-1 or\",round(E/1000),\"kJ mol**-1\"\n",

+      "print\"\\n(ii)  Rate constant at 670K is %.1e\"%k,\"s**-1\""

+     ],

+     "language": "python",

+     "metadata": {},

+     "outputs": [

+      {

+       "output_type": "stream",

+       "stream": "stdout",

+       "text": [

+        "(i)  Activation energy is  2.39e+05 J mol**-1 or 239.0 kJ mol**-1\n",

+        "\n",

+        "(ii)  Rate constant at 670K is 4.8e-05 s**-1\n"

+       ]

+      }

+     ],

+     "prompt_number": 18

+    },

+    {

+     "cell_type": "heading",

+     "level": 2,

+     "metadata": {},

+     "source": [

+      "Example no:3.21,Page no:95"

+     ]

+    },

+    {

+     "cell_type": "code",

+     "collapsed": false,

+     "input": [

+      "#Variable declaration\n",

+      "Ti=27.0 #given temperature in C#\n",

+      "T1=Ti+273.0 #in kelvin#\n",

+      "t1=T1-5\n",

+      "Tr=10.0 #rise in temperature#\n",

+      "import math\n",

+      "\n",

+      "#Calculation\n",

+      "T2=T1+Tr \n",

+      "t2=T2-5\n",

+      "k=3.0 #value of k1/k2#\n",

+      "R=8.314 #value of constant R in J/K.mol#\n",

+      "E=math.log(k)*R*t1*t2/(T2-T1) \n",

+      "\n",

+      "#Result\n",

+      "print\"Activation energy of the reaction is\",round(E),\"J mol**-1 or\",round(E/1000,2),\"kJ mol**-1\""

+     ],

+     "language": "python",

+     "metadata": {},

+     "outputs": [

+      {

+       "output_type": "stream",

+       "stream": "stdout",

+       "text": [

+        "Activation energy of the reaction is 82182.0 J mol**-1 or 82.18 kJ mol**-1\n"

+       ]

+      }

+     ],

+     "prompt_number": 19

+    }

+   ],

+   "metadata": {}

+  }

+ ]

+}
\ No newline at end of file