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| author | kinitrupti | 2017-05-12 18:53:46 +0530 |
|---|---|---|
| committer | kinitrupti | 2017-05-12 18:53:46 +0530 |
| commit | 6279fa19ac6e2a4087df2e6fe985430ecc2c2d5d (patch) | |
| tree | 22789c9dbe468dae6697dcd12d8e97de4bcf94a2 /Strength_of_Materials_by_Dr.R.K.Bansal/chapter16.ipynb | |
| parent | d36fc3b8f88cc3108ffff6151e376b619b9abb01 (diff) | |
| download | Python-Textbook-Companions-6279fa19ac6e2a4087df2e6fe985430ecc2c2d5d.tar.gz Python-Textbook-Companions-6279fa19ac6e2a4087df2e6fe985430ecc2c2d5d.tar.bz2 Python-Textbook-Companions-6279fa19ac6e2a4087df2e6fe985430ecc2c2d5d.zip | |
Removed duplicates
Diffstat (limited to 'Strength_of_Materials_by_Dr.R.K.Bansal/chapter16.ipynb')
| -rwxr-xr-x | Strength_of_Materials_by_Dr.R.K.Bansal/chapter16.ipynb | 319 |
1 files changed, 319 insertions, 0 deletions
diff --git a/Strength_of_Materials_by_Dr.R.K.Bansal/chapter16.ipynb b/Strength_of_Materials_by_Dr.R.K.Bansal/chapter16.ipynb new file mode 100755 index 00000000..05d4efe7 --- /dev/null +++ b/Strength_of_Materials_by_Dr.R.K.Bansal/chapter16.ipynb @@ -0,0 +1,319 @@ +{
+ "metadata": {
+ "name": "",
+ "signature": "sha256:5150ceeff814b37f327edfa239de19ec011af3bd135e00c577336409efc3a800"
+ },
+ "nbformat": 3,
+ "nbformat_minor": 0,
+ "worksheets": [
+ {
+ "cells": [
+ {
+ "cell_type": "heading",
+ "level": 1,
+ "metadata": {},
+ "source": [
+ "Chapter 16:Torsion of Shafts and Springs"
+ ]
+ },
+ {
+ "cell_type": "heading",
+ "level": 2,
+ "metadata": {},
+ "source": [
+ "Problem 16.1,page no.675"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "import math\n",
+ "#Given\n",
+ "#Variable declaration\n",
+ "D=150 #Diameter of the shaft in mm\n",
+ "tau=45 #Maximum shear stress in N/sq.mm\n",
+ "\n",
+ "#Calculation\n",
+ "T=int(math.pi/16*tau*D**3)*1e-3 #Maximum torque transmitted by the shaft in N-m\n",
+ "\n",
+ "#Result\n",
+ "print \"Maximum torque =\",T,\"N-m\""
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "Maximum torque = 29820.586 N-m\n"
+ ]
+ }
+ ],
+ "prompt_number": 1
+ },
+ {
+ "cell_type": "heading",
+ "level": 2,
+ "metadata": {},
+ "source": [
+ "Problem 16.3,page no.677"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "import math\n",
+ "\n",
+ "#Given\n",
+ "#Variable declaration\n",
+ "Do=200 #Outer diameter in mm\n",
+ "Di=100 #Inner diameter in mm\n",
+ "tau=40 #Maximum shear stress in N/sq.mm\n",
+ "\n",
+ "#Calculation\n",
+ "T=int(round((math.pi)/16*tau*((Do**4-Di**4)/Do),-1))*1e-3 #Maximum torque transmitted by the shaft in Nm\n",
+ "\n",
+ "#Result\n",
+ "print \"Maximum torque transmitted by the shaft =\",T,\"Nm\""
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "Maximum torque transmitted by the shaft = 58904.86 Nm\n"
+ ]
+ }
+ ],
+ "prompt_number": 2
+ },
+ {
+ "cell_type": "heading",
+ "level": 2,
+ "metadata": {},
+ "source": [
+ "Problem 16.7,page no.682"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "from __future__ import division\n",
+ "import math\n",
+ "\n",
+ "#Given\n",
+ "#Variable declaration\n",
+ "Do=120 #External diameter in mm\n",
+ "P=300*1000 #Power in W\n",
+ "N=200 #Speed in r.p.m\n",
+ "tau=60 #Maximum shear stress in N/sq.mm\n",
+ "\n",
+ "#Calculation\n",
+ "T=round((P*60)/(2*math.pi*N),1)*1e3 #Torque transmitted in Nmm \n",
+ "Di=round(((Do**4)-((T*16*Do)/(math.pi*tau)))**(1/4),1) #Maximum internal diameter in mm\n",
+ "\n",
+ "#Result\n",
+ "print \"Maximum Internal diameter =\",Di,\"mm\""
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "Maximum Internal diameter = 88.5 mm\n"
+ ]
+ }
+ ],
+ "prompt_number": 4
+ },
+ {
+ "cell_type": "heading",
+ "level": 2,
+ "metadata": {},
+ "source": [
+ "Problem 16.8,page no.683"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "import math\n",
+ "#Given\n",
+ "#Variable declaration\n",
+ "D=15*10 #Diameter of shaft in mm\n",
+ "P=150*1e3 #Power transmitted in W\n",
+ "N=180 #Speed of shaft in r.p.m\n",
+ "\n",
+ "#Calculation\n",
+ "T=(P*60)/(2*math.pi*N)*1e3 #Torque transmitted in Nmm\n",
+ "tau=int((16*T)/(math.pi*D**3)) #Maximum shear stress in N/sq.mm\n",
+ "\n",
+ "#Result\n",
+ "print \"Maximum shear stress =\",tau,\"N/mm^2\""
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "Maximum shear stress = 12 N/mm^2\n"
+ ]
+ }
+ ],
+ "prompt_number": 4
+ },
+ {
+ "cell_type": "heading",
+ "level": 2,
+ "metadata": {},
+ "source": [
+ "Problem 16.9,page no.683"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "from __future__ import division\n",
+ "import math\n",
+ "#Given\n",
+ "#Variable declaration\n",
+ "P=300*1000 #Power in W\n",
+ "N=100 #Speed in r.p.m\n",
+ "tau=80 #Maximum shear stress in N/sq.mm\n",
+ "\n",
+ "#Calculation\n",
+ "#case(a):\n",
+ "T=(P*60)/(2*math.pi*N)*1e3 #Torque transmitted in Nmm\n",
+ "D=round(((16*T)/(math.pi*tau))**(1/3),0) #Diameter of solid shaft in mm\n",
+ "#case(b):\n",
+ "Do=round(((T*16)/(math.pi*tau*(1-0.6**4)))**(1/3),0) #External diameter of hollow shaft in mm\n",
+ "Di=0.6*Do #Internal diameter of hollow shaft in mm\n",
+ "Per=(D**2-(Do**2-Di**2))/(D**2)*100 #Percentage saving in weight\n",
+ "\n",
+ "#Result\n",
+ "print \"Diameter of solid shaft =\",D,\"mm\"\n",
+ "print \"Percentage saving in weight = %.2f%%\"%Per"
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "Diameter of solid shaft = 122.0 mm\n",
+ "Percentage saving in weight = 29.55%\n"
+ ]
+ }
+ ],
+ "prompt_number": 5
+ },
+ {
+ "cell_type": "heading",
+ "level": 2,
+ "metadata": {},
+ "source": [
+ "Problem 16.10,page no.685"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "import math\n",
+ "#Given\n",
+ "#Variable declaration\n",
+ "P=75e3 #Power transmitted in W\n",
+ "N=200 #R.P.M of the shaft \n",
+ "tau=70 #Shear stress in N/sq.mm\n",
+ "\n",
+ "#Calculation\n",
+ "T=P*60/(math.pi*2*N)*1e3 #Mean Torque transmitted in Nmm\n",
+ "Tmax=1.3*T #Maximum Torque transmitted in Nmm\n",
+ "D=round((16*Tmax/(math.pi*tau))**(1/3),0) #Suitable diameter of the shaft in mm\n",
+ "\n",
+ "#Result\n",
+ "print \"Diameter of the shaft = %d mm\"%D"
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "Diameter of the shaft = 70 mm\n"
+ ]
+ }
+ ],
+ "prompt_number": 6
+ },
+ {
+ "cell_type": "heading",
+ "level": 2,
+ "metadata": {},
+ "source": [
+ "Problem 16.11,page no.685"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "import math\n",
+ "#Given\n",
+ "#Variable declaration\n",
+ "P=300e3 #Power transmitted in W\n",
+ "N=80 #speed of the shaft in r.p.m\n",
+ "tau=60 #Maximum shear stress in N/sq.mm\n",
+ "\n",
+ "#Calculation\n",
+ "T=P*60/(math.pi*2*N)*1e3 #Mean Torque transmitted in Nmm\n",
+ "Tmax=1.4*T #Maximum Torque transmitted in Nmm\n",
+ "D=round((16*Tmax/(math.pi*tau))**(1/3),0) #Suitable diameter of the shaft in mm\n",
+ "Do=round(((Tmax*16)/(math.pi*tau*(1-0.6**4)))**(1/3),0) #External diameter of hollow shaft in mm\n",
+ "Di=0.6*Do #Internal diameter of hollow shaft in mm\n",
+ "\n",
+ "#Result\n",
+ "print \"External diameter of hollow shaft = %d mm\"%Do\n",
+ "print \"Internal diameter of hollow shaft = %d mm\"%Di"
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "External diameter of hollow shaft = 170 mm\n",
+ "Internal diameter of hollow shaft = 102 mm\n"
+ ]
+ }
+ ],
+ "prompt_number": 7
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [],
+ "language": "python",
+ "metadata": {},
+ "outputs": []
+ }
+ ],
+ "metadata": {}
+ }
+ ]
+}
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