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| author | hardythe1 | 2015-06-11 17:31:11 +0530 |
|---|---|---|
| committer | hardythe1 | 2015-06-11 17:31:11 +0530 |
| commit | 79c59acc7af08ede23167b8455de4b716f77601f (patch) | |
| tree | 2d6ff34b6f131d2671e4c6b798f210b3cb1d4ac7 /Solid_Mechanics_by_S._M._A._Kazimi/Chapter9.ipynb | |
| parent | df60071cf1d1c18822d34f943ab8f412a8946b69 (diff) | |
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diff --git a/Solid_Mechanics_by_S._M._A._Kazimi/Chapter9.ipynb b/Solid_Mechanics_by_S._M._A._Kazimi/Chapter9.ipynb new file mode 100755 index 00000000..ff92969f --- /dev/null +++ b/Solid_Mechanics_by_S._M._A._Kazimi/Chapter9.ipynb @@ -0,0 +1,895 @@ +{
+ "metadata": {
+ "name": "",
+ "signature": "sha256:9a9db8433ab57f1254bcf525f290f9e1ef0d063ac15516708405e3ee93106db3"
+ },
+ "nbformat": 3,
+ "nbformat_minor": 0,
+ "worksheets": [
+ {
+ "cells": [
+ {
+ "cell_type": "heading",
+ "level": 1,
+ "metadata": {},
+ "source": [
+ "Chapter9-Combined Stresses"
+ ]
+ },
+ {
+ "cell_type": "heading",
+ "level": 2,
+ "metadata": {},
+ "source": [
+ "Ex1-pg361"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "#calculate values of R at A,B,C\n",
+ "##initialization of variables\n",
+ "import math\n",
+ "##case (a)\n",
+ "A=72.9 ##cm^2\n",
+ "Iy=633 ##cm^4\n",
+ "Ix=1199. ##cm^4\n",
+ "t=24./(5.*Ix)+13.5/(5.*Iy)\n",
+ "r=1/(A*t)\n",
+ "print'%s %.2f %s'%('case (a) \\n r = ',r,' cm')\n",
+ "## case (b)\n",
+ "t=24./(5.*Ix)-13.5/(5.*Iy)\n",
+ "r=1/(A*t)\n",
+ "print'%s %.2f %s'%('\\n case (b) \\n r = ',r,' cm')\n",
+ "##case (c)\n",
+ "t=-24./(5.*Ix)+13.5/(5.*Iy)\n",
+ "r=1./(A*t)\n",
+ "print'%s %.2f %s'%('\\n case (a) \\n r =',r,' cm')\n",
+ "print'%s %.2f %s'%('\\n So the load is to be placed on the leg OD, at a distance of ',r,' cm from O' )\n",
+ "\n"
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "case (a) \n",
+ " r = 1.66 cm\n",
+ "\n",
+ " case (b) \n",
+ " r = -52.34 cm\n",
+ "\n",
+ " case (a) \n",
+ " r = 52.34 cm\n",
+ "\n",
+ " So the load is to be placed on the leg OD, at a distance of 52.34 cm from O\n"
+ ]
+ }
+ ],
+ "prompt_number": 3
+ },
+ {
+ "cell_type": "heading",
+ "level": 2,
+ "metadata": {},
+ "source": [
+ "Ex3-pg365"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "#calculate steel height and Width\n",
+ "##initialization of variables\n",
+ "import math\n",
+ "b=14. ##cm\n",
+ "d=20. ##cm\n",
+ "rx=8.46 ##cm\n",
+ "ry=2.99 ##cm\n",
+ "## calculations\n",
+ "ex=2.*rx**2/d\n",
+ "ey=2*ry**2/b\n",
+ "h=2*ex\n",
+ "w=2*ey\n",
+ "## results\n",
+ "print'%s %.2f %s %.2f %s '%('for steel height=',h,' cm and width=',w,' cm')\n",
+ "## ISHB 225\n",
+ "b=22.5 ##cm\n",
+ "d=22.5 ##cm\n",
+ "rx=9.8 ##cm\n",
+ "ry=4.96 ##cm\n",
+ "## calculations\n",
+ "ex=2*rx**2/d\n",
+ "ey=2*ry**2/b\n",
+ "h=2*ex\n",
+ "w=2*ey\n",
+ "## results\n",
+ "print'%s %.2f %s %.2f %s '%('\\n for an ISHB height=',h,' cm and width=',w,' cm')\n"
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "for steel height= 14.31 cm and width= 2.55 cm \n",
+ "\n",
+ " for an ISHB height= 17.07 cm and width= 4.37 cm \n"
+ ]
+ }
+ ],
+ "prompt_number": 25
+ },
+ {
+ "cell_type": "heading",
+ "level": 2,
+ "metadata": {},
+ "source": [
+ "Ex4-pg366"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "#calculate Safe load\n",
+ "##initialization of variables\n",
+ "import math\n",
+ "t=280. ##kg/cm^2\n",
+ "c=840. ##kg/cm^2\n",
+ "xbar=7.5 ##cm from AB\n",
+ "A=210. ##cm^2\n",
+ "## calculations\n",
+ "e=50.+xbar ##cm\n",
+ "Iyy=7433. ##cm^2\n",
+ "k=(1./210.+e*xbar/Iyy)\n",
+ "P=t/k\n",
+ "k1=(-1./210.+e*(xbar+5.)/Iyy)\n",
+ "P1=c/k1\n",
+ "P_safe=min(P1,P)\n",
+ "## results\n",
+ "print'%s %.2f %s'%('The safe load is ',P_safe,' kg')\n"
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "The safe load is 4460.00 kg\n"
+ ]
+ }
+ ],
+ "prompt_number": 26
+ },
+ {
+ "cell_type": "heading",
+ "level": 2,
+ "metadata": {},
+ "source": [
+ "Ex5-pg367"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "#calcualte compression and tension\n",
+ "##initialization of the variables\n",
+ "import math\n",
+ "s=1.6 ##m\n",
+ "s1=4. ##m\n",
+ "pi=28. ##degrees\n",
+ "w=16. ##kg/m^2\n",
+ "p=100. ##kg/m^2\n",
+ "pl=20. ##cm\n",
+ "pb=10. ##cm\n",
+ "r=500. ##kg/m^3\n",
+ "## calculations\n",
+ "pi=pi*math.pi/180 ##radians\n",
+ "W=w*s+(r*pl*pb/(100.*100.))\n",
+ "P=p*s\n",
+ "L=P+W*math.cos(pi)\n",
+ "Mx=L*s1**2*100./8.\n",
+ "sigma_1=Mx*6./(pb*pl**2)\n",
+ "My=W*math.sin(pi)*s1**2*100./8.\n",
+ "sigma_2=My*6./(pl*pb**2)\n",
+ "sigma1=sigma_1+sigma_2\n",
+ "## results\n",
+ "print'%s %.2f %s %.2f %s '%('Due to bending in the noth the planes, D experiences maximum \\n compression of ',sigma1,' kg/cm^2 and B has maximum tension of ',sigma1,' kg/cm^2')\n"
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "Due to bending in the noth the planes, D experiences maximum \n",
+ " compression of 67.46 kg/cm^2 and B has maximum tension of 67.46 kg/cm^2 \n"
+ ]
+ }
+ ],
+ "prompt_number": 27
+ },
+ {
+ "cell_type": "heading",
+ "level": 2,
+ "metadata": {},
+ "source": [
+ "Ex6-pg369"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "#calculate maximum stresses\n",
+ "##initialization of the problems\n",
+ "import math\n",
+ "s=1.6 ##m\n",
+ "s1=4. ##m\n",
+ "pi=28. ##degrees\n",
+ "w=16. ##kg/m^2\n",
+ "p=100. ##kg/m^2\n",
+ "pl=20. ##cm\n",
+ "pb=10. ##cm\n",
+ "r=500. ##kg/m^3\n",
+ "Zx=54.8 ##cm^3\n",
+ "Zy=3.9 ##cm^3\n",
+ "## calculations\n",
+ "pi=pi*math.pi/180. ##radians\n",
+ "W=w*s+8.1\n",
+ "P=p*s\n",
+ "L=P+W*math.cos(pi)\n",
+ "Mx=L*s1**2*100./8.\n",
+ "sigma_1=Mx/Zx\n",
+ "My=W*math.sin(pi)*s1**2*100./8.\n",
+ "sigma_2=My/Zy\n",
+ "sigma=sigma_1+sigma_2\n",
+ "## results\n",
+ "print'%s %.2f %s'%('Maximum stresses are ',sigma,' kg/cm^2, tension or compression')\n"
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "Maximum stresses are 1503.88 kg/cm^2, tension or compression\n"
+ ]
+ }
+ ],
+ "prompt_number": 28
+ },
+ {
+ "cell_type": "heading",
+ "level": 2,
+ "metadata": {},
+ "source": [
+ "Ex7-pg369"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "#calculate strain gauge \n",
+ "##initialization of variables\n",
+ "import math\n",
+ "s=1.6 ##m\n",
+ "s1=4. ##m\n",
+ "pi=28. ##degrees\n",
+ "w=16. ##kg/m^2\n",
+ "p=100. ##kg/m^2\n",
+ "pl=20. ##cm\n",
+ "pb=10. ##cm\n",
+ "r=500. ##kg/m^3\n",
+ "sg=5. ##cm\n",
+ "E=12*10**4\n",
+ "pi=pi*math.pi/180 ##radians\n",
+ "## calculations\n",
+ "W=w*s+(r*pl*pb/(100.*100.))\n",
+ "P=p*s\n",
+ "L=P+W*math.cos(pi)\n",
+ "Mx=L*s1**2*100/8.\n",
+ "sigma_1=Mx*6./(pb*pl**2)\n",
+ "My=W*math.sin(pi)*s1**2*100/8.\n",
+ "sigma_2=My*6./(pl*pb**2)\n",
+ "st=sigma_1*sg/10.\n",
+ "Ts=st-sigma_2\n",
+ "ez=Ts/E\n",
+ "## results\n",
+ "print'%s %.2e %s'%('The strain gauge, aligned to the z axis will give compression strain of ',ez,'')\n"
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "The strain gauge, aligned to the z axis will give compression strain of 1.56e-04 \n"
+ ]
+ }
+ ],
+ "prompt_number": 13
+ },
+ {
+ "cell_type": "heading",
+ "level": 2,
+ "metadata": {},
+ "source": [
+ "Ex8-pg371"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "#calcualte bending stress and shearing stress\n",
+ "##initialization of variables\n",
+ "import math\n",
+ "P=3. ##tonne/m\n",
+ "s=6. ##m\n",
+ "l=50. ##cm\n",
+ "b=20. ##cm\n",
+ "k=0.5 ##m\n",
+ "##calculations\n",
+ "R=P*s/2.\n",
+ "sf=R-k*P\n",
+ "bm=R*k-P*k**2/2.\n",
+ "tau_xy=1.5*sf*1000./(l*b)\n",
+ "tau_max=tau_xy\n",
+ "str=bm*s*10**5/(b*l*l)\n",
+ "\n",
+ "## consider the line a-a\n",
+ "\n",
+ "sigma_x=str*12.5/25.\n",
+ "sigma_y=0.\n",
+ "tau_xy=tau_xy*(1.-(12.5/25.)**2)\n",
+ "\n",
+ "sigma_1=(sigma_x+sigma_y)/2.+math.sqrt((1/2*(sigma_x-sigma_y))**2+tau_xy**2)\n",
+ "sigma_2=(sigma_x+sigma_y)/2.-math.sqrt((1/2*(sigma_x-sigma_y))**2+tau_xy**2)\n",
+ "\n",
+ "print'%s %.2f %s %.2f %s '%('For the line a-a the bending stress and shearing stress are \\n respectively ',sigma_x,' kg/cm^2'and'',tau_xy,'kg/cm^2 ')\n",
+ "print'%s %.2f %s %.2f %s '%('\\n The principal stresses are ',sigma_1,' kg/cm^2 (tension)' and '',sigma_2,'kg/cm^2 (compression) ')\n",
+ "\n",
+ "##consider the line c-c\n",
+ "print'%s %.2f %s %.2f %s '%('\\n For the line c-c the bending stress and shearing stress are \\n respectively ',sigma_x,' kg/cm^2'and '',tau_xy,' kg/cm^2 ')\n",
+ "print'%s %.2f %s %.2f %s '%('\\n The principal stresses are ',sigma_2,' kg/cm^2 (compression)'and '',sigma_1,' kg/cm^2 (tension) ')\n",
+ "\n",
+ "##for the line b-b\n",
+ "tau_xy=tau_max\n",
+ "sigma_x=0.\n",
+ "sigma_y=0.\n",
+ "sigma_1=(sigma_x+sigma_y)/2.+math.sqrt((1./2.*(sigma_x-sigma_y))**2+tau_xy**2)\n",
+ "sigma_2=(sigma_x+sigma_y)/2.-math.sqrt((1./2.*(sigma_x-sigma_y))**2+tau_xy**2)\n",
+ "## results\n",
+ "print'%s %.7f %s %.2f %s '%('\\n For the line b-b the bending stress and shearing stress are \\n respectively ',sigma_x,' kg/cm^2'and '',tau_xy,' kg/cm^2 ')\n",
+ "print'%s %.2f %s %.2f %s '%('\\n The principal stresses are ',sigma_1,' kg/cm^2 (tension)'and'',sigma_2,' kg/cm^2 (compression) ')\n"
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "For the line a-a the bending stress and shearing stress are \n",
+ " respectively 24.75 8.44 kg/cm^2 \n",
+ "\n",
+ " The principal stresses are 20.81 3.94 kg/cm^2 (compression) \n",
+ "\n",
+ " For the line c-c the bending stress and shearing stress are \n",
+ " respectively 24.75 8.44 kg/cm^2 \n",
+ "\n",
+ " The principal stresses are 3.94 20.81 kg/cm^2 (tension) \n",
+ "\n",
+ " For the line b-b the bending stress and shearing stress are \n",
+ " respectively 0.0000000 11.25 kg/cm^2 \n",
+ "\n",
+ " The principal stresses are 11.25 -11.25 kg/cm^2 (compression) \n"
+ ]
+ }
+ ],
+ "prompt_number": 29
+ },
+ {
+ "cell_type": "heading",
+ "level": 2,
+ "metadata": {},
+ "source": [
+ "Ex9-pg372"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "#calculate tension and principal stress\n",
+ "##initialization of variables\n",
+ "import math\n",
+ "P=3. ##tonne/m\n",
+ "s=6. ##m\n",
+ "l=50. ##cm\n",
+ "b=20. ##cm\n",
+ "k=0.5 ##m\n",
+ "##calculations\n",
+ "R=P*s/2.\n",
+ "sf=R-k*P\n",
+ "bm=R*k-P*k**2/2.\n",
+ "tau_xy=1.5*sf*1000./(l*b) ##max shear stress\n",
+ "tau_max=tau_xy \n",
+ "str=bm*s*10**5/(b*l*l) ##max bending stress\n",
+ "\n",
+ "## consider the line a-a\n",
+ "\n",
+ "sigma_x=str*12.5/25.\n",
+ "sigma_y=0.\n",
+ "tau_xy=tau_xy*(1.-(12.5/25.)**2)\n",
+ "\n",
+ "sigma_1=(sigma_x+sigma_y)/2.+math.sqrt((1/2.*(sigma_x-sigma_y))**2+tau_xy**2)\n",
+ "sigma_2=(sigma_x+sigma_y)/2-math.sqrt((1/2.*(sigma_x-sigma_y))**2+tau_xy**2)\n",
+ "\n",
+ "theta=1/2.*math.atan(2.*tau_xy/(sigma_x-sigma_y))*57.3\n",
+ "sigma_p=sigma_1/math.cos(theta)\n",
+ "P=sigma_p*2.*l*b/(3.*1000.)\n",
+ "print'%s %.2f %s'%('A prestressing force of ',P,' Tonne must be applied to balance the tension at a-a')\n",
+ "\n",
+ "##At bottom point D or C\n",
+ "pre_str=P*2.*1000./(l*b)\n",
+ "net=str-pre_str\n",
+ "print('\\n At bottom point D or C')\n",
+ "print'%s %.2f %s'%('\\n Net tension = ',net,' kg/cm^2 ')\n",
+ "\n",
+ "##consider the line b-b\n",
+ "pre_str=P\n",
+ "sigma_x=pre_str\n",
+ "sigma_y=0.\n",
+ "tau_xy=tau_max\n",
+ "sigma_1=(sigma_x+sigma_y)/2.+math.sqrt((1./2.*(sigma_x-sigma_y))**2+tau_xy**2)\n",
+ "sigma_2=(sigma_x+sigma_y)/2.-math.sqrt((1./2.*(sigma_x-sigma_y))**2+tau_xy**2)\n",
+ "print('\\n At section b-b')\n",
+ "print'%s %.2f %s '%('\\n pre-stress=',pre_str,' kg/cm^2')\n",
+ "print'%s %.2f %s %.2f %s '%('\\n principal stresses are ',sigma_1,''and'',sigma_2,' kg/cm^2 ')\n",
+ "\n",
+ "##for the line c-c\n",
+ "sigma_x=str*12.5/25.\n",
+ "sigma_y=0.\n",
+ "tau_xy=tau_xy*(1-(12.5/25.)**2)\n",
+ "sigma_1=(sigma_x+sigma_y)/2.+math.sqrt((1./2.*(sigma_x-sigma_y))**2+tau_xy**2)\n",
+ "sigma_2=(sigma_x+sigma_y)/2.-math.sqrt((1./2.*(sigma_x-sigma_y))**2+tau_xy**2)\n",
+ "pre_str=pre_str/2.\n",
+ "net=sigma_1+pre_str\n",
+ "sigma_x=net\n",
+ "sigma_y=0.\n",
+ "sigma_1=(sigma_x+sigma_y)/2.+math.sqrt((1./2.*(sigma_x-sigma_y))**2+tau_xy**2)\n",
+ "sigma_2=(sigma_x+sigma_y)/2.-math.sqrt((1./2.*(sigma_x-sigma_y))**2+tau_xy**2)\n",
+ "## results\n",
+ "print('\\n At section c-c')\n",
+ "print'%s %.2f %s'%('\\n the direct stress is ',net,' kg/cm^2')\n",
+ "print'%s %.2f %s'%('\\n pre-stress =',pre_str,' kg/cm^2')\n",
+ "print'%s %.2f %s %.2f %s '%('\\n principal stresses are',sigma_1,'kg/cm^2'and '',sigma_2,'kg/cm^2')\n",
+ "print('wrong calculations in the thext for some parts')\n",
+ "\n"
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "A prestressing force of -136.43 Tonne must be applied to balance the tension at a-a\n",
+ "\n",
+ " At bottom point D or C\n",
+ "\n",
+ " Net tension = 322.36 kg/cm^2 \n",
+ "\n",
+ " At section b-b\n",
+ "\n",
+ " pre-stress= -136.43 kg/cm^2 \n",
+ "\n",
+ " principal stresses are 0.92 -137.35 kg/cm^2 \n",
+ "\n",
+ " At section c-c\n",
+ "\n",
+ " the direct stress is -40.86 kg/cm^2\n",
+ "\n",
+ " pre-stress = -68.22 kg/cm^2\n",
+ "\n",
+ " principal stresses are 1.67 -42.54 kg/cm^2 \n",
+ "wrong calculations in the thext for some parts\n"
+ ]
+ }
+ ],
+ "prompt_number": 30
+ },
+ {
+ "cell_type": "heading",
+ "level": 2,
+ "metadata": {},
+ "source": [
+ "Ex10-pg373"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "#calculate sigma and Tau\n",
+ "##initialization of variables\n",
+ "import math\n",
+ "b=2. ##cm\n",
+ "h=2. ##cm\n",
+ "T=2000. ##kg-cm\n",
+ "V=250. ##kg\n",
+ "M=2000. ##kg-cm\n",
+ "## calculations\n",
+ "Mmax=M*6./(b*h*b)\n",
+ "Vmax=3.*V/(2.*b*h)\n",
+ "Zt=0.208*b**2*h\n",
+ "Tmax=T/(Zt)\n",
+ "\n",
+ "sigma=Mmax\n",
+ "print('points A,B,')\n",
+ "print'%s %.2f %s'%('\\n sigma=',sigma,' kg/cm^2 (tension)')\n",
+ "print('\\n points C,D,')\n",
+ "print'%s %.2f %s'%('\\n sigma=',sigma,' kg/cm^2 (cmpression)')\n",
+ "tau=Vmax+Tmax\n",
+ "print('\\n point E')\n",
+ "print'%s %.2f %s'%('\\n tau=',tau,'kg/cm^2 shear')\n",
+ "tau=Vmax-Tmax\n",
+ "print'%s %.2f %s'%('\\n tau=',tau,' kg/cm^2 shear')\n",
+ "## at G\n",
+ "sigma_x=sigma\n",
+ "sigma_y=0.\n",
+ "tau_xy=Tmax\n",
+ "sigma_1=(sigma_x+sigma_y)/2.+math.sqrt((1./2.*(sigma_x-sigma_y))**2+tau_xy**2)\n",
+ "sigma_2=(sigma_x+sigma_y)/2.-math.sqrt((1./2.*(sigma_x-sigma_y))**2+tau_xy**2)\n",
+ "## results\n",
+ "print('\\n at point G')\n",
+ "print'%s %.2f %s'%('\\n sigma_1 = ',sigma_1,' kg/cm^2 (tension)')\n",
+ "print'%s %.2f %s'%('\\n sigma_2 = ',sigma_2,' kg/cm^2 (compression)')\n",
+ "\n",
+ "print('Question was asked only to find out at A,B,C,D,E,F and G')\n",
+ "print(' And in book Ans worng')\n"
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "points A,B,\n",
+ "\n",
+ " sigma= 1500.00 kg/cm^2 (tension)\n",
+ "\n",
+ " points C,D,\n",
+ "\n",
+ " sigma= 1500.00 kg/cm^2 (cmpression)\n",
+ "\n",
+ " point E\n",
+ "\n",
+ " tau= 1295.67 kg/cm^2 shear\n",
+ "\n",
+ " tau= -1108.17 kg/cm^2 shear\n",
+ "\n",
+ " at point G\n",
+ "\n",
+ " sigma_1 = 2166.73 kg/cm^2 (tension)\n",
+ "\n",
+ " sigma_2 = -666.73 kg/cm^2 (compression)\n",
+ "Question was asked only to find out at A,B,C,D,E,F and G\n",
+ " And in book Ans worng\n"
+ ]
+ }
+ ],
+ "prompt_number": 31
+ },
+ {
+ "cell_type": "heading",
+ "level": 2,
+ "metadata": {},
+ "source": [
+ "Ex11-pg374"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "#calculate total shear and bending stress and principal stress\n",
+ "##initialization of variables\n",
+ "import math\n",
+ "w=10. ##cm\n",
+ "s=2.8 ##m\n",
+ "P=1. ##tonne\n",
+ "Ft=1.4 ##cm\n",
+ "Wt=0.8 ##cm\n",
+ "Ix=13989.5 ##cm^4\n",
+ "Z=699.5 ##cm^3\n",
+ "## calculations\n",
+ "BM= 2.8 \n",
+ "T=P*1000*8.21\n",
+ "SF=P*1000.\n",
+ "BS=BM*10**5/(Z)\n",
+ "sigmaXA=BS*18.6/20.\n",
+ "K=w*Ft*19.3+18.6*Wt*9.3\n",
+ "tau_xy_C=SF/(Ix*Wt)*K\n",
+ "tau_xy_A=tau_xy_C*(w*Ft*19.3)/K \n",
+ "tau_xy_B=tau_xy_A*0.5*Wt/w\n",
+ "sigmaXB=sigmaXA*19.3/20.\n",
+ "\n",
+ "tau_max=3*Ft*8210./(w*Ft**3+37.2*Wt**3)\n",
+ "tau_A=3*Wt*8210./(w*Ft**3+37.2*Wt**3)\n",
+ "\n",
+ "##For point A\n",
+ "Shear=tau_xy_A-tau_A\n",
+ "sigma_x=sigmaXA\n",
+ "sigma_y=0.\n",
+ "tau_xy=Shear\n",
+ "sigma_1=(sigma_x+sigma_y)/2.+math.sqrt((1./2.*(sigma_x-sigma_y))**2+tau_xy**2)\n",
+ "sigma_2=(sigma_x+sigma_y)/2.-math.sqrt((1./2.*(sigma_x-sigma_y))**2+tau_xy**2)\n",
+ "\n",
+ "print('For point A')\n",
+ "print'%s %.2f %s'%('\\n Total shear= ',Shear,' kg/cm^2 ')\n",
+ "print'%s %.2f %s'%('\\n Bending stress = ',sigma_x,' kg/cm^2 (Compr.)')\n",
+ "print'%s %.2f %s %.2f %s '%('\\n Principal stresses are ',sigma_1,'(tension)kg/cm^2 'and'' ,sigma_2,'(comp.) kg/cm^2 ')\n",
+ "\n",
+ "##For point B\n",
+ "print('\\n FOr point B')\n",
+ "print'%s %.2f %s'%('\\n Bending shear stress is ',tau_xy_B,' k/cm^2')\n",
+ "sigmaXB=BS*19.3/20.\n",
+ "sigma_x=sigmaXB\n",
+ "sigma_y=0.\n",
+ "tau_xy=tau_max\n",
+ "sigma_1=(sigma_x+sigma_y)/2.+math.sqrt((1./2.*(sigma_x-sigma_y))**2+tau_xy**2)\n",
+ "sigma_2=(sigma_x+sigma_y)/2.-math.sqrt((1./2.*(sigma_x-sigma_y))**2+tau_xy**2)\n",
+ "print'%s %.2f %s %.2f %s '%('\\n Principal stresses are ',sigma_1,' (tension) kg/cm^2'and'',sigma_2,' (comp.) kg/cm^2 ')\n",
+ "print('Answers in the text are approximations')\n"
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "For point A\n",
+ "\n",
+ " Total shear= -399.72 kg/cm^2 \n",
+ "\n",
+ " Bending stress = 372.27 kg/cm^2 (Compr.)\n",
+ "\n",
+ " Principal stresses are 627.07 -254.80 (comp.) kg/cm^2 \n",
+ "\n",
+ " FOr point B\n",
+ "\n",
+ " Bending shear stress is 0.97 k/cm^2\n",
+ "\n",
+ " Principal stresses are 959.64 -573.36 (comp.) kg/cm^2 \n",
+ "Answers in the text are approximations\n"
+ ]
+ }
+ ],
+ "prompt_number": 2
+ },
+ {
+ "cell_type": "heading",
+ "level": 2,
+ "metadata": {},
+ "source": [
+ "Ex12-pg380"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "#calcualte permissible stress and developed stress\n",
+ "##initialization of variables\n",
+ "import math\n",
+ "b=10. ##cm\n",
+ "h=10. ##cm\n",
+ "P=5. ##tonne\n",
+ "e=1. ##cm\n",
+ "E=12*10**4 ##kg/cm^2\n",
+ "str=130. ## kg/cm^2\n",
+ "n=3.\n",
+ "L=2. ##m\n",
+ "## calculations\n",
+ "L=L*100. ##cm\n",
+ "Pcr=math.pi**2*E*b*h**3/(12.*L**2.)\n",
+ "Pcr=Pcr/1000.\n",
+ "Smax=-P*1000./(b*h)-(P*1000.*1.*5.*12./10**4)*1./(1.-(n*P/Pcr))\n",
+ "## results\n",
+ "print'%s %.2f %s'%('permissible stress = ',str,' kg/cm^2')\n",
+ "print'%s %.2f %s'%('\\n develoed stress = ',Smax,' kg/cm^2')\n",
+ "print('\\n Since it is below the permissible stress, the design is safe')\n",
+ "\n"
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "permissible stress = 130.00 kg/cm^2\n",
+ "\n",
+ " develoed stress = -126.52 kg/cm^2\n",
+ "\n",
+ " Since it is below the permissible stress, the design is safe\n"
+ ]
+ }
+ ],
+ "prompt_number": 33
+ },
+ {
+ "cell_type": "heading",
+ "level": 2,
+ "metadata": {},
+ "source": [
+ "Ex13-pg381"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "import math\n",
+ "##initializatio of variables\n",
+ "#calculate Smax and percentage error\n",
+ "## linked to 9.13\n",
+ "b=10. ##cm\n",
+ "h=10. ##cm\n",
+ "P=5. ##tonne\n",
+ "e=1. ##cm\n",
+ "E=12.*10**4 ##kg/cm^2\n",
+ "str=130. ## kg/cm^2\n",
+ "n=3.\n",
+ "L=2. ##m\n",
+ "## calculations\n",
+ "L=L*100. ##cm\n",
+ "Pcr=math.pi**2*E*b*h**3/(12*L**2)\n",
+ "Pcr=Pcr/1000.\n",
+ "Smax=-P*1000./(b*h)-(P*1000.*1.*5.*12./10**4)*1./(1.-(n*P/Pcr))\n",
+ "Smax=abs(Smax)\n",
+ "\n",
+ "rr=b*h**3/(12.*100.)\n",
+ "Smax_se=P*1000./(b*h)*(1+e*5/rr*(1./math.cos(math.pi/2.*math.sqrt(n*P/Pcr))))\n",
+ "Perror=(Smax-Smax_se)/Smax\n",
+ "Perror=Perror*100.\n",
+ "Perror=abs(Perror)\n",
+ "## results\n",
+ "print'%s %.2f %s'%('Using secent formula, stress obtained is ',Smax_se,' kg/cm^2')\n",
+ "print'%s %.2f %s'%('\\n hence, the percentage error ',Perror,'')\n",
+ "## approximate answees in the text\n"
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "Using secent formula, stress obtained is 138.45 kg/cm^2\n",
+ "\n",
+ " hence, the percentage error 9.43 \n"
+ ]
+ }
+ ],
+ "prompt_number": 3
+ },
+ {
+ "cell_type": "heading",
+ "level": 2,
+ "metadata": {},
+ "source": [
+ "Ex14-pg382"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "import math\n",
+ "##initialization of variables\n",
+ "#calculate maximum stress developed\n",
+ "P=400. ##kg/m\n",
+ "L=10. ##m\n",
+ "F=10. ##tonne\n",
+ "n=3.\n",
+ "Ixx=5943.1 ##cm^4\n",
+ "A=52.03 ##cm^2\n",
+ "rx=10.69 ##cm\n",
+ "E=2*10**6 ##kg/cm^2\n",
+ "## calculations\n",
+ "Pcr=math.pi**2*E*Ixx/((L*100.)**2.)\n",
+ "Pcr=Pcr/1000.\n",
+ "e=P*L**2/(8*F*1000.)\n",
+ "g=e*12.5*100./rx**2\n",
+ "Smax=F*1000./A*(1.+g*1./(1-n*(F/Pcr)))\n",
+ "## results\n",
+ "print'%s %.2f %s'%('The maximum stress developed is ',Smax,' kg/cm^2')\n",
+ "\n",
+ "print('approximate calculations involved in the text book')\n"
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "The maximum stress developed is 1604.54 kg/cm^2\n",
+ "approximate calculations involved in the text book\n"
+ ]
+ }
+ ],
+ "prompt_number": 35
+ },
+ {
+ "cell_type": "heading",
+ "level": 2,
+ "metadata": {},
+ "source": [
+ "Ex15-pg383"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "#calculate maximum stress developed\n",
+ "##initialization of variables\n",
+ "import math\n",
+ "## linked to 9_14\n",
+ "## calculations\n",
+ "P=400. ##kg/m\n",
+ "L=10. ##m\n",
+ "F=10. ##tonne\n",
+ "n=3.\n",
+ "Ixx=5943.1 ##cm^4\n",
+ "A=52.03 ##cm^2\n",
+ "rx=10.69 ##cm\n",
+ "E=2*10**6 ##kg/cm^2\n",
+ "Pcr=math.pi**2.*E*Ixx/((L*100.)**2)\n",
+ "Pcr=Pcr/1000.\n",
+ "e=P*L**2./(8.*F*1000.)\n",
+ "g=e*12.5*100./rx**2.\n",
+ "Smax=F*1000./A*(1+g*1./(1.+n*(F/Pcr)))\n",
+ "## results\n",
+ "print'%s %.2f %s'%('The maximum stress developed is ',Smax,' kg/cm^2')\n",
+ "\n",
+ "print('approximate answer in the text')\n"
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "The maximum stress developed is 1029.29 kg/cm^2\n",
+ "approximate answer in the text\n"
+ ]
+ }
+ ],
+ "prompt_number": 36
+ }
+ ],
+ "metadata": {}
+ }
+ ]
+}
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