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| author | hardythe1 | 2015-01-28 14:31:21 +0530 |
|---|---|---|
| committer | hardythe1 | 2015-01-28 14:31:21 +0530 |
| commit | 9add422993fb2649287260bc91d429a07d1810d5 (patch) | |
| tree | ef48c2b2579e65b982d3f700c4fa76b81d2496c1 /Principles_of_physics/chapter5.ipynb | |
| parent | 6e3407ba85ae84e1cee1ae0c972fd32c5504d827 (diff) | |
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diff --git a/Principles_of_physics/chapter5.ipynb b/Principles_of_physics/chapter5.ipynb new file mode 100755 index 00000000..525b7c92 --- /dev/null +++ b/Principles_of_physics/chapter5.ipynb @@ -0,0 +1,332 @@ +{
+ "metadata": {
+ "name": "",
+ "signature": "sha256:8d1a6e24325b21ce86c3b6da78ff6614496eb66a81611477ea9a7b9f8a72ae03"
+ },
+ "nbformat": 3,
+ "nbformat_minor": 0,
+ "worksheets": [
+ {
+ "cells": [
+ {
+ "cell_type": "heading",
+ "level": 1,
+ "metadata": {},
+ "source": [
+ "Chapter 5 Properties of matter"
+ ]
+ },
+ {
+ "cell_type": "heading",
+ "level": 2,
+ "metadata": {},
+ "source": [
+ "Example 5.1 Page no 76"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "#given\n",
+ "m=1 #Mass of torsional pendulum in kg\n",
+ "R=0.06 #Radius of torsional pendulum in m\n",
+ "l=1.2 #Length of the wire in m\n",
+ "r=0.0008 #Radius of wire in m\n",
+ "S=(9*10**9) #Modulus of rigidity of the material in N/m^2\n",
+ "\n",
+ "#Calculations\n",
+ "import math\n",
+ "I=(1/2.0)*m*R**2\n",
+ "C=(3.14*S*r**4)/(2*l)\n",
+ "T=2*3.14*math.sqrt(I/C)\n",
+ "\n",
+ "#Output\n",
+ "print\"Period of pendulum is \",round(T,1),\"s\"\n"
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "Period of pendulum is 3.8 s\n"
+ ]
+ }
+ ],
+ "prompt_number": 1
+ },
+ {
+ "cell_type": "heading",
+ "level": 2,
+ "metadata": {},
+ "source": [
+ "Example 5.2 Page no 76"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "#given\n",
+ "l=0.8 #Length of the wire in m\n",
+ "d=(1.8*10**-3) #Diameter of the wire in m\n",
+ "a=1.5 #Angle of twist in degrees\n",
+ "S=(1.8*10**11) #Modulus of rigidity of the material in N/m^2\n",
+ "\n",
+ "#Calculations\n",
+ "r=(a*3.14)/180.0\n",
+ "W=((3.14*S*(d/2.0)**4*r**2)/(4*l))/10.0**-5\n",
+ "\n",
+ "#Output\n",
+ "print\"Work required to twist the wire is \",round(W,2),\"*10^-5 J\"\n"
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "Work required to twist the wire is 7.93 *10^-5 J\n"
+ ]
+ }
+ ],
+ "prompt_number": 4
+ },
+ {
+ "cell_type": "heading",
+ "level": 2,
+ "metadata": {},
+ "source": [
+ "Example 5.3 Page no 76"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "#given\n",
+ "l=2 #Length of wire in m\n",
+ "d=(0.4*10**-3) #Diameter of the wire in m\n",
+ "x=(1.03*10**-3) #Extension in length in m\n",
+ "L=2 #Load in kg\n",
+ "C=(4.52*10**-6) #Couple in N/m\n",
+ "a=0.03 #Twist angle in radians\n",
+ "\n",
+ "#Calculations\n",
+ "Y=((L*9.8*l)/(x*3.14*(d/2.0)**2))/10**11\n",
+ "S=((C*2*l)/(3.14*(d/2.0)**4*a))/10**11\n",
+ "s=(Y/(2*S))-1\n",
+ "\n",
+ "#Output\n",
+ "print\"Youngs modulus is \",round(Y,2),\"*10**11 N/m^2\"\n",
+ "print\"Modulus of rigidity is \",round(S,2),\"*10**11 N/m^2\"\n",
+ "print\"Poissons ratio is \",round(s,2)\n"
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "Youngs modulus is 3.03 *10**11 N/m^2\n",
+ "Modulus of rigidity is 1.2 *10**11 N/m^2\n",
+ "Poissons ratio is 0.26\n"
+ ]
+ }
+ ],
+ "prompt_number": 7
+ },
+ {
+ "cell_type": "heading",
+ "level": 2,
+ "metadata": {},
+ "source": [
+ "Example 5.4 Page no 76"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "#given\n",
+ "r=0.003 #Radius of drop of glycerine in m\n",
+ "T=(63.1*10**-3) #Surface tension of glycerine in N/m\n",
+ "\n",
+ "#Calculations\n",
+ "P=((2*T)/r)\n",
+ "\n",
+ "#Output\n",
+ "print\"Excess pressure inside the drop of glycerine is \",round(P,2),\"N/m^2\"\n"
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "Excess pressure inside the drop of glycerine is 42.07 N/m^2\n"
+ ]
+ }
+ ],
+ "prompt_number": 8
+ },
+ {
+ "cell_type": "heading",
+ "level": 2,
+ "metadata": {},
+ "source": [
+ "Example 5.5 Page no 76"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "#given\n",
+ "r1=0.001 #Initial radius in m\n",
+ "r2=0.004 #Final radius in m\n",
+ "t=2*10**-3 #Time in s\n",
+ "s=(7*10**-2) #Surface tension of water in N/m\n",
+ "\n",
+ "#Calculations\n",
+ "P=((2*s)*((1/r2)-(1/r1)))/(t*10**4)\n",
+ "\n",
+ "#Output\n",
+ "print\"Rate of change of pressure is \",P,\"*10**4 N/m**2 s\"\n"
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "Rate of change of pressure is -5.25 *10**4 N/m**2 s\n"
+ ]
+ }
+ ],
+ "prompt_number": 5
+ },
+ {
+ "cell_type": "heading",
+ "level": 2,
+ "metadata": {},
+ "source": [
+ "Example 5.6 Page no 77"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "#given\n",
+ "d=0.02 #Diamter of soap bubble in m\n",
+ "s=(25*10**-3) #Surface tension in N/m\n",
+ "#Initial surface area of the bubble is zero and final area is 2*4*pie*r^2 where r is the radius of the bubble\n",
+ "\n",
+ "#Calculations\n",
+ "W=(s*2*4*3.14*(d/2.0)**2)/10.0**-5\n",
+ "\n",
+ "#Output\n",
+ "print\"Work done in blowing a soap bubble is \",W,\"*10**-5 J\"\n"
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "Work done in blowing a soap bubble is 6.28 *10**-5 J\n"
+ ]
+ }
+ ],
+ "prompt_number": 9
+ },
+ {
+ "cell_type": "heading",
+ "level": 2,
+ "metadata": {},
+ "source": [
+ "Example 5.7 Page no 77"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "#given\n",
+ "r=0.01 #Radius of liquid drop in m\n",
+ "n=500 #Number of drops\n",
+ "s=(63*10**-3) #Surface tension in N/m\n",
+ "\n",
+ "#Calculations\n",
+ "r1=(((4*3.14*r**3)/3.0)/((n*4*3.14)/3.0))**(1/3.0)\n",
+ "As=(n*4*3.14*r1**2)\n",
+ "A=4*3.14*r**2\n",
+ "W=(s*(As-A))/10.0**-4\n",
+ "\n",
+ "#Output\n",
+ "print\"Energy required to break up a drop of a liquid is \",round(W,1),\"*10**-4 J\"\n"
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "Energy required to break up a drop of a liquid is 5.5 *10**-4 J\n"
+ ]
+ }
+ ],
+ "prompt_number": 8
+ },
+ {
+ "cell_type": "heading",
+ "level": 2,
+ "metadata": {},
+ "source": [
+ "Example 5.8 Page no 77"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "#given\n",
+ "d=0.04 #Inside diameter of garden hose in m\n",
+ "D=0.01 #Diamter of nozzle opening in m\n",
+ "v1=0.6 #speed of flow of water in the hose in m/s\n",
+ "\n",
+ "#calculations\n",
+ "a=3.14*(d/2.0)**2\n",
+ "A=3.14*(D/2.0)**2\n",
+ "v2=(v1*a)/A\n",
+ "\n",
+ "#Output\n",
+ "print\"Speed of flow through the nozzle is \",v2,\"m/s\"\n"
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "Speed of flow through the nozzle is 9.6 m/s\n"
+ ]
+ }
+ ],
+ "prompt_number": 10
+ }
+ ],
+ "metadata": {}
+ }
+ ]
+}
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