Added(A)/Deleted(D) following books

 A  Principles_of_Physics_by_F.J.Bueche/Chapter10_1.ipynb
A  Principles_of_Physics_by_F.J.Bueche/Chapter10_2.ipynb
A  Principles_of_Physics_by_F.J.Bueche/Chapter11_1.ipynb
A  Principles_of_Physics_by_F.J.Bueche/Chapter13_1.ipynb
A  Principles_of_Physics_by_F.J.Bueche/Chapter14_1.ipynb
A  Principles_of_Physics_by_F.J.Bueche/Chapter15_1.ipynb
A  Principles_of_Physics_by_F.J.Bueche/Chapter16_1.ipynb
A  Principles_of_Physics_by_F.J.Bueche/Chapter17_1.ipynb
A  Principles_of_Physics_by_F.J.Bueche/Chapter18_1.ipynb
A  Principles_of_Physics_by_F.J.Bueche/Chapter19_1.ipynb
A  Principles_of_Physics_by_F.J.Bueche/Chapter1_1.ipynb
A  Principles_of_Physics_by_F.J.Bueche/Chapter1_2.ipynb
A  Principles_of_Physics_by_F.J.Bueche/Chapter20_1.ipynb
A  Principles_of_Physics_by_F.J.Bueche/Chapter21_1.ipynb
A  Principles_of_Physics_by_F.J.Bueche/Chapter22_1.ipynb
A  Principles_of_Physics_by_F.J.Bueche/Chapter23_1.ipynb
A  Principles_of_Physics_by_F.J.Bueche/Chapter24_1.ipynb
A  Principles_of_Physics_by_F.J.Bueche/Chapter25_1.ipynb
A  Principles_of_Physics_by_F.J.Bueche/Chapter26_1.ipynb
A  Principles_of_Physics_by_F.J.Bueche/Chapter27_1.ipynb
A  Principles_of_Physics_by_F.J.Bueche/Chapter2_1.ipynb
A  Principles_of_Physics_by_F.J.Bueche/Chapter2_2.ipynb
A  Principles_of_Physics_by_F.J.Bueche/Chapter3_1.ipynb
A  Principles_of_Physics_by_F.J.Bueche/Chapter3_2.ipynb
A  Principles_of_Physics_by_F.J.Bueche/Chapter4_1.ipynb
A  Principles_of_Physics_by_F.J.Bueche/Chapter4_2.ipynb
A  Principles_of_Physics_by_F.J.Bueche/Chapter5_1.ipynb
A  Principles_of_Physics_by_F.J.Bueche/Chapter5_2.ipynb
A  Principles_of_Physics_by_F.J.Bueche/Chapter6_1.ipynb
A  Principles_of_Physics_by_F.J.Bueche/Chapter6_2.ipynb
A  Principles_of_Physics_by_F.J.Bueche/Chapter7_1.ipynb
A  Principles_of_Physics_by_F.J.Bueche/Chapter7_2.ipynb
A  Principles_of_Physics_by_F.J.Bueche/Chapter8_1.ipynb
A  Principles_of_Physics_by_F.J.Bueche/Chapter9_1.ipynb
A  Principles_of_Physics_by_F.J.Bueche/Chapter9_2.ipynb
A  Principles_of_Physics_by_F.J.Bueche/chapter12_1.ipynb
A  Principles_of_Physics_by_F.J.Bueche/screenshots/11.2_1.png
A  Principles_of_Physics_by_F.J.Bueche/screenshots/24.4_1.png
A  Principles_of_Physics_by_F.J.Bueche/screenshots/8.4_1.png

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diff --git a/Principles_of_Physics_by_F.J.Bueche/Chapter16_1.ipynb b/Principles_of_Physics_by_F.J.Bueche/Chapter16_1.ipynb
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+{
+ "cells": [
+  {
+   "cell_type": "markdown",
+   "metadata": {},
+   "source": [
+    "# Chapter 16:Electric Potential"
+   ]
+  },
+  {
+   "cell_type": "markdown",
+   "metadata": {},
+   "source": [
+    "## Ex16.1:pg-731"
+   ]
+  },
+  {
+   "cell_type": "code",
+   "execution_count": 1,
+   "metadata": {
+    "collapsed": false
+   },
+   "outputs": [
+    {
+     "name": "stdout",
+     "output_type": "stream",
+     "text": [
+      "The magnitude of electric field is E= 2400.0  V/meters\n"
+     ]
+    }
+   ],
+   "source": [
+    "  import math   #Example16_1\n",
+    " \n",
+    "  \n",
+    "#To find the magnitude of the electric field\n",
+    "v=12.0        #Units in V\n",
+    "d=5.0*10**-3        #units in Meters\n",
+    "e=v/d           #Units in V/meter\n",
+    "print \"The magnitude of electric field is E=\",round(e),\" V/meters\"\n"
+   ]
+  },
+  {
+   "cell_type": "markdown",
+   "metadata": {},
+   "source": [
+    "## Ex16.2:pg-731"
+   ]
+  },
+  {
+   "cell_type": "code",
+   "execution_count": 2,
+   "metadata": {
+    "collapsed": false
+   },
+   "outputs": [
+    {
+     "name": "stdout",
+     "output_type": "stream",
+     "text": [
+      "The speed of the proton is Vab= 92858.79  meters/sec\n"
+     ]
+    }
+   ],
+   "source": [
+    "  import math   #Example16_2\n",
+    " \n",
+    "  \n",
+    "#To calculate the speed of the proton\n",
+    "q=1.6*10**-19      #Units in C\n",
+    "vab=45      #Units in V\n",
+    "m=1.67*10**-27        #Units in Kg\n",
+    "va=math.sqrt((2*q*vab)/m)       #Units in meters/sec\n",
+    "print \"The speed of the proton is Vab=\",round(va,2),\" meters/sec\"\n"
+   ]
+  },
+  {
+   "cell_type": "markdown",
+   "metadata": {},
+   "source": [
+    "## Ex16.3:pg-733"
+   ]
+  },
+  {
+   "cell_type": "code",
+   "execution_count": 3,
+   "metadata": {
+    "collapsed": false
+   },
+   "outputs": [
+    {
+     "name": "stdout",
+     "output_type": "stream",
+     "text": [
+      "The speed of the electron is Vab= 3975777.37  meters/sec\n"
+     ]
+    }
+   ],
+   "source": [
+    "  import math   #Example16_3\n",
+    "  \n",
+    "#To find the sped of an electron\n",
+    "e=1.6*10**-19      #Units in C\n",
+    "vab=45      #Units in V\n",
+    "m=9.11*10**-31        #Units in Kg\n",
+    "va=math.sqrt((2*e*vab)/m)       #Units in meters/sec\n",
+    "print \"The speed of the electron is Vab=\",round(va,2),\" meters/sec\"\n"
+   ]
+  },
+  {
+   "cell_type": "markdown",
+   "metadata": {},
+   "source": [
+    "## Ex16.4:pg-735"
+   ]
+  },
+  {
+   "cell_type": "code",
+   "execution_count": 4,
+   "metadata": {
+    "collapsed": false
+   },
+   "outputs": [
+    {
+     "name": "stdout",
+     "output_type": "stream",
+     "text": [
+      "Charged metal object have an equi potential volume so its surface is am equi potential volume\n",
+      "Because lines of force must be perpendiculat ro equipotential lines and surfaces.\n"
+     ]
+    }
+   ],
+   "source": [
+    "  import math   #Example16_4\n",
+    " \n",
+    "  \n",
+    "  #To sketch the equipotentials and electric field lines near a charged metal object\n",
+    "print \"Charged metal object have an equi potential volume so its surface is am equi potential volume\\nBecause lines of force must be perpendiculat ro equipotential lines and surfaces.\"\n"
+   ]
+  },
+  {
+   "cell_type": "markdown",
+   "metadata": {},
+   "source": [
+    "## Ex16.5:pg-735"
+   ]
+  },
+  {
+   "cell_type": "code",
+   "execution_count": 5,
+   "metadata": {
+    "collapsed": false
+   },
+   "outputs": [
+    {
+     "name": "stdout",
+     "output_type": "stream",
+     "text": [
+      "The work done in carrying proton is=\n",
+      "1.44e-18\n",
+      "Joules\n",
+      "\n",
+      "The work done in carrying electron is=\n",
+      "-1.44e-18\n",
+      "Joules\n",
+      "\n"
+     ]
+    }
+   ],
+   "source": [
+    "  import math   #Example16_5\n",
+    " \n",
+    "  \n",
+    "#To find the work done in carrying a proton and for an electron\n",
+    "q=1.6*10**-19   #Units in C\n",
+    "vab=9.0            #Units in V\n",
+    "work=q*vab        #Units in J\n",
+    "print \"The work done in carrying proton is=\"\n",
+    "print work\n",
+    "print \"Joules\\n\"\n",
+    "q=-1.6*10**-19   #Units in C\n",
+    "work=q*vab        #Units in J\n",
+    "print \"The work done in carrying electron is=\"\n",
+    "print work\n",
+    "print \"Joules\\n\"\n"
+   ]
+  },
+  {
+   "cell_type": "markdown",
+   "metadata": {},
+   "source": [
+    "## Ex16.6:pg-736"
+   ]
+  },
+  {
+   "cell_type": "code",
+   "execution_count": 6,
+   "metadata": {
+    "collapsed": false
+   },
+   "outputs": [
+    {
+     "name": "stdout",
+     "output_type": "stream",
+     "text": [
+      "The speed of proton before it strikes is Vb= 7756781.9  meters/sec\n"
+     ]
+    }
+   ],
+   "source": [
+    "  import math   #Example16_6\n",
+    "  \n",
+    "  #To calculate the speed just befor it strikes it\n",
+    "va=8*10**6         #Units in meters/sec\n",
+    "q=1.6*10**-19         #Units in C\n",
+    "m=1.67*10**-27        #Units in Kg\n",
+    "vab=20000   #Units in V\n",
+    "vb=math.sqrt(va**2-((2*q*vab)/m))        #Units in meters/sec\n",
+    "print \"The speed of proton before it strikes is Vb=\",round(vb,1),\" meters/sec\"\n"
+   ]
+  },
+  {
+   "cell_type": "markdown",
+   "metadata": {},
+   "source": [
+    "## Ex16.7:pg-737"
+   ]
+  },
+  {
+   "cell_type": "code",
+   "execution_count": 7,
+   "metadata": {
+    "collapsed": false
+   },
+   "outputs": [
+    {
+     "name": "stdout",
+     "output_type": "stream",
+     "text": [
+      "Since each proton has a minimum energy of 13.6 eV and a charge of 1.602*10**-19 C\n",
+      " The required potential difference is=13.6 eV\n"
+     ]
+    }
+   ],
+   "source": [
+    "  import math   #Example16_7\n",
+    " \n",
+    "  \n",
+    "  #To calculate the minimum value of Vab needed\n",
+    "print \"Since each proton has a minimum energy of 13.6 eV and a charge of 1.602*10**-19 C\\n The required potential difference is=13.6 eV\"\n"
+   ]
+  },
+  {
+   "cell_type": "markdown",
+   "metadata": {},
+   "source": [
+    "## Ex16.8:pg-737"
+   ]
+  },
+  {
+   "cell_type": "code",
+   "execution_count": 8,
+   "metadata": {
+    "collapsed": false
+   },
+   "outputs": [
+    {
+     "name": "stdout",
+     "output_type": "stream",
+     "text": [
+      "The speed of electron is v= 4150286.78  meters/sec\n"
+     ]
+    }
+   ],
+   "source": [
+    "  import math   #Example16_8\n",
+    "  \n",
+    "  #To find out the speed of the proton\n",
+    "k=9*10**9         #Units in N meter**2/C**2\n",
+    "q=5*10.0**-6   #Units in C\n",
+    "r=0.5         #Units in meters\n",
+    "v1=(k*q)/r     #Units in V\n",
+    "q=1.6*10**-19           #Units in V\n",
+    "m=1.672*10**-27           #Units in Kg\n",
+    "v=math.sqrt((v1*q*2)/m)     #Units in V\n",
+    "print \"The speed of electron is v=\",round(v,2),\" meters/sec\"\n"
+   ]
+  },
+  {
+   "cell_type": "markdown",
+   "metadata": {},
+   "source": [
+    "## Ex16.9:pg-739"
+   ]
+  },
+  {
+   "cell_type": "code",
+   "execution_count": 9,
+   "metadata": {
+    "collapsed": false
+   },
+   "outputs": [
+    {
+     "name": "stdout",
+     "output_type": "stream",
+     "text": [
+      "Due to 5*10**-8 C V1= 4500.0  V\n",
+      "Due to 8*10**-8 C V2= 7200.0  V\n",
+      "Due to 40*10**-8 C V3= -18000.0  V\n",
+      " Absolute potential at B is Vb= -6300.0  V\n"
+     ]
+    }
+   ],
+   "source": [
+    "  import math   #Example16_9\n",
+    " \n",
+    "  \n",
+    "  #To compute the absolute potential at B\n",
+    "k=9*10**9         #Units in N meter**2/C**2\n",
+    "q=5*10.0**-8   #Units in C\n",
+    "r=0.1         #Units in meters\n",
+    "v1=(k*q)/r     #Units in V\n",
+    "q=8*10**-8   #Units in C\n",
+    "r=0.1         #Units in meters\n",
+    "v2=(k*q)/r     #Units in V\n",
+    "q=40*10**-8   #Units in C\n",
+    "r=0.2         #Units in meters\n",
+    "v3=-(k*q)/r     #Units in V\n",
+    "vb=v1+v2+v3            #Units in V        \n",
+    "print \"Due to 5*10**-8 C V1=\",round(v1),\" V\\nDue to 8*10**-8 C V2=\",round(v2),\" V\\nDue to 40*10**-8 C V3=\",round(v3),\" V\\n Absolute potential at B is Vb=\",round(vb),\" V\"\n",
+    "      \n"
+   ]
+  },
+  {
+   "cell_type": "markdown",
+   "metadata": {},
+   "source": [
+    "## Ex16.10:pg-739"
+   ]
+  },
+  {
+   "cell_type": "code",
+   "execution_count": 10,
+   "metadata": {
+    "collapsed": false
+   },
+   "outputs": [
+    {
+     "name": "stdout",
+     "output_type": "stream",
+     "text": [
+      "The absolute potential is V= 27.2  V\n",
+      "\n",
+      "The energy that is required is W=\n",
+      "4.35e-18 J\n"
+     ]
+    }
+   ],
+   "source": [
+    "  import math   #Example16_10\n",
+    " \n",
+    "  \n",
+    "  #To find the absolute potential and how much energy is needed to pull the electrons from atom\n",
+    "k=9*10**9         #Units in N meter**2/C**2\n",
+    "q=1.6*10**-19   #Units in C\n",
+    "r=5.3*10**-11         #Units in meters\n",
+    "v=(k*q)/r     #Units in V\n",
+    "print \"The absolute potential is V=\",round(v,1),\" V\\n\"\n",
+    "Vinfinity=0              #Units in V\n",
+    "deltaV=Vinfinity-v           #Units in V\n",
+    "work=-q*deltaV             #Units in J\n",
+    "print \"The energy that is required is W=\"\n",
+    "print round(work,20),\"J\"  \n"
+   ]
+  }
+ ],
+ "metadata": {
+  "kernelspec": {
+   "display_name": "Python 2",
+   "language": "python",
+   "name": "python2"
+  },
+  "language_info": {
+   "codemirror_mode": {
+    "name": "ipython",
+    "version": 2
+   },
+   "file_extension": ".py",
+   "mimetype": "text/x-python",
+   "name": "python",
+   "nbconvert_exporter": "python",
+   "pygments_lexer": "ipython2",
+   "version": "2.7.11"
+  }
+ },
+ "nbformat": 4,
+ "nbformat_minor": 0
+}