Added(A)/Deleted(D) following books

 A  Principles_of_Physics_by_F.J.Bueche/Chapter1.ipynb
A  Principles_of_Physics_by_F.J.Bueche/Chapter10.ipynb
A  Principles_of_Physics_by_F.J.Bueche/Chapter11.ipynb
A  Principles_of_Physics_by_F.J.Bueche/Chapter13.ipynb
A  Principles_of_Physics_by_F.J.Bueche/Chapter14.ipynb
A  Principles_of_Physics_by_F.J.Bueche/Chapter15.ipynb
A  Principles_of_Physics_by_F.J.Bueche/Chapter16.ipynb
A  Principles_of_Physics_by_F.J.Bueche/Chapter17.ipynb
A  Principles_of_Physics_by_F.J.Bueche/Chapter18.ipynb
A  Principles_of_Physics_by_F.J.Bueche/Chapter19.ipynb
A  Principles_of_Physics_by_F.J.Bueche/Chapter2.ipynb
A  Principles_of_Physics_by_F.J.Bueche/Chapter20.ipynb
A  Principles_of_Physics_by_F.J.Bueche/Chapter21.ipynb
A  Principles_of_Physics_by_F.J.Bueche/Chapter22.ipynb
A  Principles_of_Physics_by_F.J.Bueche/Chapter23.ipynb
A  Principles_of_Physics_by_F.J.Bueche/Chapter24.ipynb
A  Principles_of_Physics_by_F.J.Bueche/Chapter25.ipynb
A  Principles_of_Physics_by_F.J.Bueche/Chapter26.ipynb
A  Principles_of_Physics_by_F.J.Bueche/Chapter27.ipynb
A  Principles_of_Physics_by_F.J.Bueche/Chapter3.ipynb
A  Principles_of_Physics_by_F.J.Bueche/Chapter4.ipynb
A  Principles_of_Physics_by_F.J.Bueche/Chapter5.ipynb
A  Principles_of_Physics_by_F.J.Bueche/Chapter6.ipynb
A  Principles_of_Physics_by_F.J.Bueche/Chapter7.ipynb
A  Principles_of_Physics_by_F.J.Bueche/Chapter8.ipynb
A  Principles_of_Physics_by_F.J.Bueche/Chapter9.ipynb
A  Principles_of_Physics_by_F.J.Bueche/chapter12.ipynb
A  Principles_of_Physics_by_F.J.Bueche/screenshots/11.2.png
A  Principles_of_Physics_by_F.J.Bueche/screenshots/24.4.png
A  Principles_of_Physics_by_F.J.Bueche/screenshots/8.4.png

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diff --git a/Principles_of_Physics_by_F.J.Bueche/Chapter15.ipynb b/Principles_of_Physics_by_F.J.Bueche/Chapter15.ipynb
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+{
+ "cells": [
+  {
+   "cell_type": "markdown",
+   "metadata": {},
+   "source": [
+    "# Chapter 15:Electric Forces and Fields"
+   ]
+  },
+  {
+   "cell_type": "markdown",
+   "metadata": {},
+   "source": [
+    "## Ex15.1:pg-719"
+   ]
+  },
+  {
+   "cell_type": "code",
+   "execution_count": 2,
+   "metadata": {
+    "collapsed": false
+   },
+   "outputs": [
+    {
+     "name": "stdout",
+     "output_type": "stream",
+     "text": [
+      "The value of q is= 3.61e-06  C\n",
+      "\n",
+      "Number of electrons to be removed is=\n",
+      "2.25625e+13\n",
+      "Fraction of atoms lost is=\n",
+      "7.52083333333e-10\n"
+     ]
+    }
+   ],
+   "source": [
+    "  #Example 15_1\n",
+    "import math \n",
+    "  #To find the value of q and how many electrons must be removed and fraction of atoms lost\n",
+    "dist=2       #Units in meters\n",
+    "f=0.0294     #Units in N\n",
+    "s=9*10**9   #Units in N meter**2/C**2\n",
+    "q=math.sqrt((dist**2*f)/s)    #Units in C\n",
+    "print \"The value of q is=\",round(q,8),\" C\\n\"\n",
+    "charge=3.61*10**-6   #Units in C\n",
+    "c_elec=1.6*10**-19       #Units in C\n",
+    "n=charge/c_elec     #Units in number\n",
+    "print \"Number of electrons to be removed is=\"\n",
+    "print n\n",
+    "f1=3*10.0**22     #Units in number\n",
+    "fraction=n/f1     #Units of number\n",
+    "print \"Fraction of atoms lost is=\"\n",
+    "print fraction\n"
+   ]
+  },
+  {
+   "cell_type": "markdown",
+   "metadata": {},
+   "source": [
+    "## Ex15.2:pg-721"
+   ]
+  },
+  {
+   "cell_type": "code",
+   "execution_count": 3,
+   "metadata": {
+    "collapsed": false
+   },
+   "outputs": [
+    {
+     "name": "stdout",
+     "output_type": "stream",
+     "text": [
+      "The force on the center charge is= 0.02813  N\n"
+     ]
+    }
+   ],
+   "source": [
+    "  #Example 15_2\n",
+    " \n",
+    "  \n",
+    "  #To find the force on the center charge\n",
+    "k=9*10**9      #Units in N meter**2/C**2\n",
+    "q1=4*10.0**-6      #Units in C\n",
+    "q2=5*10.0**-6     #Units in C\n",
+    "r1=2           #Units in meters\n",
+    "r2=4       #Units in meters\n",
+    "q3=6*10.0**-6       #Units in C\n",
+    "f1=(k*q1*q2)/r1**2         #Units in N\n",
+    "f2=(k*q2*q3)/r2**2         #Units in N\n",
+    "f=f1-f2         #Units in C\n",
+    "print \"The force on the center charge is=\",round(f,5),\" N\"\n"
+   ]
+  },
+  {
+   "cell_type": "markdown",
+   "metadata": {},
+   "source": [
+    "## Ex15.3:pg-722"
+   ]
+  },
+  {
+   "cell_type": "code",
+   "execution_count": 7,
+   "metadata": {
+    "collapsed": false
+   },
+   "outputs": [
+    {
+     "name": "stdout",
+     "output_type": "stream",
+     "text": [
+      "The resultant force is f= 19.0  N \n",
+      "The resultant angle is theta= 71.6  degrees\n"
+     ]
+    }
+   ],
+   "source": [
+    "  #Example 15_3\n",
+    "import math \n",
+    "  \n",
+    "  #To find the resultant force\n",
+    "f1=6   #Units in N\n",
+    "f2=18       #Units in N\n",
+    "f=math.sqrt(f1**2+f2**2)   #Units in N\n",
+    "theta=math.atan(f2/f1)*180/math.pi    #Units in degrees\n",
+    "print \"The resultant force is f=\",round(f),\" N \\nThe resultant angle is theta=\",round(theta,1),\" degrees\"\n",
+    "  #In text book answer printed wrong as f=19 N correct answer is f=18N \n"
+   ]
+  },
+  {
+   "cell_type": "markdown",
+   "metadata": {},
+   "source": [
+    "## Ex15.4:pg-724"
+   ]
+  },
+  {
+   "cell_type": "code",
+   "execution_count": 9,
+   "metadata": {
+    "collapsed": false
+   },
+   "outputs": [
+    {
+     "name": "stdout",
+     "output_type": "stream",
+     "text": [
+      "The resultant force is f= 3.4  N \n",
+      " The resultant angle is theta= 65.0  degrees\n"
+     ]
+    }
+   ],
+   "source": [
+    "  #Example 15_4\n",
+    " \n",
+    "import math\n",
+    "  #To find the resultant force on 20 micro C\n",
+    "f1=2   #Units in N\n",
+    "f2=1.8       #Units in N\n",
+    "theta=37.0         #Units in degrees\n",
+    "f2x=f2*math.cos(theta*math.pi/180)        #Units in N\n",
+    "f2y=f2*math.sin(theta*math.pi/180)        #Units in N\n",
+    "fy=f1+f2y       #Units in N\n",
+    "f=math.sqrt(fy**2+f2x**2)   #Units in N\n",
+    "theta=math.atan(fy/f2x)*180/math.pi    #Units in degrees\n",
+    "print \"The resultant force is f=\",round(f,1),\" N \\n The resultant angle is theta=\",round(theta,1),\" degrees\""
+   ]
+  },
+  {
+   "cell_type": "markdown",
+   "metadata": {},
+   "source": [
+    "## Ex15.6:pg-726 "
+   ]
+  },
+  {
+   "cell_type": "code",
+   "execution_count": 11,
+   "metadata": {
+    "collapsed": false
+   },
+   "outputs": [
+    {
+     "name": "stdout",
+     "output_type": "stream",
+     "text": [
+      "The magnitude of E is=\n",
+      "7198876.9\n",
+      "N/C\n"
+     ]
+    }
+   ],
+   "source": [
+    "  #Example 15_6\n",
+    " \n",
+    "  \n",
+    "  #To find the magnitude of E\n",
+    "k=9*10**9      #Units in N meter**2/C**2\n",
+    "q=3.6*10**-6        #Units in C\n",
+    "theta=37            #Units in degrees\n",
+    "r=10*math.sin(theta*math.pi/180)*10**-2      #Units in meters  \n",
+    "e1=(k*q)/r**2       #Units in N/C\n",
+    "q2=5*10**-6        #Units in C\n",
+    "theta=37            #Units in degrees\n",
+    "r1=10*10**-2   #Units in meters  \n",
+    "e2=(k*q2)/r1**2       #Units in N/C\n",
+    "e1y=e1           #Units in N/C\n",
+    "e2x=e2*math.cos(theta*math.pi/180)      #Units in N/C\n",
+    "e2y=-e2*math.sin(theta*math.pi/180)   #Units in N/C\n",
+    "ex=e2x         #Units in N/C\n",
+    "ey=e1y+e2y          #Units in N/C\n",
+    "e=math.sqrt(ex**2+ey**2)           #Units in N/C\n",
+    "print \"The magnitude of E is=\"\n",
+    "print round(e,2)\n",
+    "print \"N/C\"\n",
+    "  #In text book the answer isprinted wrong as E=7.26*10**6 N/C but the correct answer is E=7198876.9 N/C\n"
+   ]
+  },
+  {
+   "cell_type": "markdown",
+   "metadata": {},
+   "source": [
+    "## Ex15.7:pg-726"
+   ]
+  },
+  {
+   "cell_type": "code",
+   "execution_count": 12,
+   "metadata": {
+    "collapsed": false
+   },
+   "outputs": [
+    {
+     "name": "stdout",
+     "output_type": "stream",
+     "text": [
+      "The charge occured is q= 8.33e-07  C\n"
+     ]
+    }
+   ],
+   "source": [
+    "  #Example 15_7\n",
+    " \n",
+    "  \n",
+    "  #To find out how much charge occurs\n",
+    "e=3*10.0**6      #Units in N/C\n",
+    "r=0.050      #Units in meters\n",
+    "k=9*10.0**9   #Units in N meter**2/C**2\n",
+    "q=(e*r**2)/k       #Units in C\n",
+    "print \"The charge occured is q=\",round(q,9),\" C\"\n"
+   ]
+  },
+  {
+   "cell_type": "markdown",
+   "metadata": {},
+   "source": [
+    "## Ex15.8:pg-727"
+   ]
+  },
+  {
+   "cell_type": "code",
+   "execution_count": 13,
+   "metadata": {
+    "collapsed": false
+   },
+   "outputs": [
+    {
+     "name": "stdout",
+     "output_type": "stream",
+     "text": [
+      "Lines of force come out of positive charge q suspended in cavity.\n",
+      "Cavity \n",
+      "surface must possess a negative charge since lines of force go and terminate on q.\n",
+      "Therefore a charge +q must exist on outer portions.\n"
+     ]
+    }
+   ],
+   "source": [
+    "  #Example 15_8\n",
+    " \n",
+    "  \n",
+    "  #To show using lines of force that a charge suspended with in cavity induces an equal and opposite charge on surface\n",
+    "print \"Lines of force come out of positive charge q suspended in cavity.\\nCavity \\nsurface must possess a negative charge since lines of force go and terminate on q.\\nTherefore a charge +q must exist on outer portions.\"\n"
+   ]
+  },
+  {
+   "cell_type": "markdown",
+   "metadata": {},
+   "source": [
+    "## Ex15.9:pg-728"
+   ]
+  },
+  {
+   "cell_type": "code",
+   "execution_count": 15,
+   "metadata": {
+    "collapsed": false
+   },
+   "outputs": [
+    {
+     "name": "stdout",
+     "output_type": "stream",
+     "text": [
+      "The field goes by a speed of  47952.0  meters/sec\n"
+     ]
+    }
+   ],
+   "source": [
+    "  #Example 15_9\n",
+    "import math  \n",
+    "  #To find the speed just before the field strikes\n",
+    "e=6000     #Units in N/C\n",
+    "q=1.6*10**-19    #Units in C\n",
+    "f=e*q           #Units in N\n",
+    "m=1.67*10**-27          #Units in Kg\n",
+    "a=f/m        #Units in meters/sec**2\n",
+    "vo=0       #Units in meters/sec\n",
+    "x=2*10**-3        #Units in meters\n",
+    "v=math.sqrt(vo**2+(2*a*x))          #Units in meters/sec\n",
+    "print \"The field goes by a speed of \",round(v),\" meters/sec\"\n",
+    "  #In text book answer printed wrong as v=48000 meters/sec the correct answer is v=47952 meters/sec \n"
+   ]
+  }
+ ],
+ "metadata": {
+  "kernelspec": {
+   "display_name": "Python 2",
+   "language": "python",
+   "name": "python2"
+  },
+  "language_info": {
+   "codemirror_mode": {
+    "name": "ipython",
+    "version": 2
+   },
+   "file_extension": ".py",
+   "mimetype": "text/x-python",
+   "name": "python",
+   "nbconvert_exporter": "python",
+   "pygments_lexer": "ipython2",
+   "version": "2.7.11"
+  }
+ },
+ "nbformat": 4,
+ "nbformat_minor": 0
+}