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| author | hardythe1 | 2015-06-03 15:27:17 +0530 |
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| committer | hardythe1 | 2015-06-03 15:27:17 +0530 |
| commit | df60071cf1d1c18822d34f943ab8f412a8946b69 (patch) | |
| tree | ab059cf19bad4a1233a464ccf5d72cf8b3fb323c /Principles_Of_Electronic_Instrumentation/Pinciples_of_electronic_Instrumentation_Ch2.ipynb | |
| parent | fba055ce5aa0955e22bac2413c33493b10ae6532 (diff) | |
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diff --git a/Principles_Of_Electronic_Instrumentation/Pinciples_of_electronic_Instrumentation_Ch2.ipynb b/Principles_Of_Electronic_Instrumentation/Pinciples_of_electronic_Instrumentation_Ch2.ipynb new file mode 100755 index 00000000..26ecb8a9 --- /dev/null +++ b/Principles_Of_Electronic_Instrumentation/Pinciples_of_electronic_Instrumentation_Ch2.ipynb @@ -0,0 +1,547 @@ +{
+ "metadata": {
+ "name": ""
+ },
+ "nbformat": 3,
+ "nbformat_minor": 0,
+ "worksheets": [
+ {
+ "cells": [
+ {
+ "cell_type": "heading",
+ "level": 1,
+ "metadata": {},
+ "source": [
+ "Chapter 2: Measurement Of Electrical Quantities"
+ ]
+ },
+ {
+ "cell_type": "heading",
+ "level": 2,
+ "metadata": {},
+ "source": [
+ "Example2_1,pg 23"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "# output voltage \n",
+ "\n",
+ "import math\n",
+ "#Variable declaration\n",
+ "ic=1*10**-3 #constant current source\n",
+ "Rf=15*10**3 #feedback resistance\n",
+ "Rs=10*10**3 #input resistance\n",
+ "Rx=1.0*10**3 #unknown resistance\n",
+ "R1=10.0 #unknown resistance\n",
+ "R2=1*10**3 #input resistance\n",
+ "\n",
+ "#Calculations\n",
+ "\n",
+ "# for fig. 2.7\n",
+ "Vo1=ic*Rf*(Rx/(1+(Rx*Rs))) #output voltage case-1\n",
+ "#for fig. 2.8\n",
+ "Vo2=ic*Rx*(R1/(1+R1*R2)) #output voltage case-2\n",
+ "\n",
+ "#Result\n",
+ "print(\"output voltage for case-1:\")\n",
+ "print(\"Vo1 = %.4f V\\n\"%Vo1)\n",
+ "print(\"output voltage for case-2:\")\n",
+ "print(\"Vo2 = %.0f mV\\n\"%(Vo2*10**3))\n",
+ "#Answer for case-1 is different in the book"
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "output voltage for case-1:\n",
+ "Vo1 = 0.0015 V\n",
+ "\n",
+ "output voltage for case-2:\n",
+ "Vo2 = 1 mV\n",
+ "\n"
+ ]
+ }
+ ],
+ "prompt_number": 1
+ },
+ {
+ "cell_type": "heading",
+ "level": 2,
+ "metadata": {},
+ "source": [
+ "Example2_2,pg 27"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "# find Ad CMRR and Acm\n",
+ "\n",
+ "import math\n",
+ "#Variable declaration\n",
+ "V1=5.0 #input-1\n",
+ "V2=5.0 #input-2\n",
+ "V12=50*10**-3 #difference input\n",
+ "Vo=2.0 #output voltage\n",
+ "acc=0.01 #accuracy\n",
+ "\n",
+ "#Calculations\n",
+ "Ad=(Vo/V12) #diffrential gain\n",
+ "#error at the output should be less than (2/100)V or 20mV.if common mode gain is the only source of error then \n",
+ "err=Vo*acc #error\n",
+ "Acm=(err/V1) #common mode gain\n",
+ "CMRR=20*math.log10(Ad/Acm) #common mode rejection ratio in dB\n",
+ "\n",
+ "#Result\n",
+ "print(\"diffrential gain:\")\n",
+ "print(\"Ad=%.1f \\n\"%Ad)\n",
+ "print(\"common mode gain:\")\n",
+ "print(\"Acm=%.4f \"%Acm)\n",
+ "print(\"\\nCMRR=%.1f dB\\n\"%CMRR)"
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "diffrential gain:\n",
+ "Ad=40.0 \n",
+ "\n",
+ "common mode gain:\n",
+ "Acm=0.0040 \n",
+ "\n",
+ "CMRR=80.0 dB\n",
+ "\n"
+ ]
+ }
+ ],
+ "prompt_number": 3
+ },
+ {
+ "cell_type": "heading",
+ "level": 2,
+ "metadata": {},
+ "source": [
+ "Example2_3,pg 484"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "# find full scale output and minimum input\n",
+ "\n",
+ "import math\n",
+ "#Variable declaration\n",
+ "Aol=1.0*10**5 #open loop gain\n",
+ "R2=10.0*10**3 #Resistor R2\n",
+ "R3=10.0*10**3 #Resistor R3\n",
+ "R1=100*10**3 #input resistance\n",
+ "Vac=24.0 #maximum input\n",
+ "\n",
+ "#Calculations\n",
+ "Vo=(R2/R1)*Vac #output full scale\n",
+ "Vth=0.6 #threshold voltage\n",
+ "Vn=(Vth/Aol) #minimum input\n",
+ "\n",
+ "#Result\n",
+ "print(\"output FS voltage:\")\n",
+ "print(\"Vo = %.2f V\\n\"%Vo)\n",
+ "print(\"minimum input voltage:\")\n",
+ "print(\"Vn = %.1f micro-V\\n\"%(Vn*10**6))\n",
+ "#Answer for Vn is wrong in the book"
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "output FS voltage:\n",
+ "Vo = 2.40 V\n",
+ "\n",
+ "minimum input voltage:\n",
+ "Vn = 6.0 micro-V\n",
+ "\n"
+ ]
+ }
+ ],
+ "prompt_number": 8
+ },
+ {
+ "cell_type": "heading",
+ "level": 2,
+ "metadata": {},
+ "source": [
+ "Example2_4,pg 484"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "# output voltage\n",
+ "\n",
+ "import math\n",
+ "#Variable declaration\n",
+ "Vp=1.0 #peak input voltage\n",
+ "f=50.0 #frequency\n",
+ "#R1=R2\n",
+ "\n",
+ "#Calculations\n",
+ "#since halfwave rectification is done,integration gives the value\n",
+ "pi =math.floor(math.pi*100)/100\n",
+ "Vo=0.5*((2*Vp)/pi) #output voltage,pi=3.14 \n",
+ "\n",
+ "#Result\n",
+ "print(\"output voltage:\")\n",
+ "print(\"Vo = %.3f V\\n\"%Vo)"
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "output voltage:\n",
+ "Vo = 0.318 V\n",
+ "\n"
+ ]
+ }
+ ],
+ "prompt_number": 10
+ },
+ {
+ "cell_type": "heading",
+ "level": 2,
+ "metadata": {},
+ "source": [
+ "Example2_5,pg 484"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "# find unknown resistance\n",
+ "\n",
+ "import math\n",
+ "#VBariable declaration\n",
+ "ic=0.1*10**-3 #constant current source\n",
+ "Vo=2.0 #output voltage\n",
+ "Rf=22.0*10**3 #feedback resistance\n",
+ "Rs=10.0*10**3 #input resistance\n",
+ "\n",
+ "#Calculations\n",
+ "Rx=(1/(((ic*Rf)/(Vo*Rs))-(1/Rs)))\n",
+ "\n",
+ "#Result\n",
+ "print(\"unknown resistance:\")\n",
+ "print(\"Rx = %.0f k-ohm\\n\"%(Rx/1000))"
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "unknown resistance:\n",
+ "Rx = 100 k-ohm\n",
+ "\n"
+ ]
+ }
+ ],
+ "prompt_number": 12
+ },
+ {
+ "cell_type": "heading",
+ "level": 2,
+ "metadata": {},
+ "source": [
+ "Example2_6,pg 484"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "# find CMRR\n",
+ "\n",
+ "import math\n",
+ "#Variable declaration\n",
+ "a=0.9 #parameter of diff. amplr.\n",
+ "b=1.1 #parameter of diff. amplr.\n",
+ "\n",
+ "#Calculations\n",
+ "CMRR=0.5*(((1+a)*b+(1+b)*a))/((1+a)*b-(1+b)*a)\n",
+ "\n",
+ "#Results\n",
+ "print(\"CMRR = %.2f\"%CMRR)"
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "CMRR = 9.95\n"
+ ]
+ }
+ ],
+ "prompt_number": 13
+ },
+ {
+ "cell_type": "heading",
+ "level": 2,
+ "metadata": {},
+ "source": [
+ "Example2_7,pg 485"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "# tolerance in parameters\n",
+ "\n",
+ "import math\n",
+ "#Variable declaration\n",
+ "CMRR=10.0*10**4 #common mode rejection ratio\n",
+ "\n",
+ "\n",
+ "#Calculations\n",
+ "#set a=beta+k1*delbeta and b=beta(-/+)k2*delbeta\n",
+ "#CMRR=0.5*((4(+/-)3*delbeta*(k1-k2))/((+/-)delbeta*(k1-k2)))\n",
+ "#CMRR=0.5*((4(+/-)3*(a1-a2))/((+/-)(a1-a2)))\n",
+ "#a1->k1*delbeta, a2->k2*delbeta\n",
+ "\n",
+ "delalpha=(2/CMRR) #a1-a2=delalpha\n",
+ "\n",
+ "#Result\n",
+ "print(\"tolerance in parameters:\")\n",
+ "print(\"delalpha = %.0f * 10^-5 \"%(delalpha*10**5))\n",
+ "print(\"Therefore, if a varies by 1 percent, b should not vary more than 2*10^-3 percent of variation of a.\")"
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "tolerance in parameters:\n",
+ "delalpha = 2 * 10^-5 \n",
+ "Therefore, if a varies by 1 percent, b should not vary more than 2*10^-3 percent of variation of a.\n"
+ ]
+ }
+ ],
+ "prompt_number": 15
+ },
+ {
+ "cell_type": "heading",
+ "level": 2,
+ "metadata": {},
+ "source": [
+ "Example2_8,pg 485"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "# output voltage\n",
+ "\n",
+ "import math\n",
+ "#Variable declaration\n",
+ "R1=10*10**3 #resistor R1\n",
+ "R2=10*10**3 #resistor R2\n",
+ "V1=1.0 #input voltage-1\n",
+ "V2=1.0 #input voltage-2\n",
+ "R31=10.0*10**3 #Resistor R3,case-1\n",
+ "R32=100.0*10**3 #Resistor R3,case-2\n",
+ "R33=1000.0*10**3 #Resistor R3,case-3\n",
+ "\n",
+ "\n",
+ "#Calculations\n",
+ "Vo1=((1+(R2/R1)+(R2/R31))*V1)-(R2/R1)*V2\n",
+ "Vo2=((1+(R2/R1)+(R2/R32))*V1)-(R2/R1)*V2\n",
+ "Vo3=((1+(R2/R1)+(R2/R33))*V1)-(R2/R1)*V2\n",
+ "Vo4 = ((1+(R2/R1)+(0))*V1)-(R2/R1)*V2 #by substituting R3 = infinity in above equation abo\n",
+ "#Result\n",
+ "print(\"output voltage case-1:\")\n",
+ "print(\"Vo1 = %.2f V\\n\"%Vo1)\n",
+ "print(\"output voltage case-2:\")\n",
+ "print(\"Vo2 = %.2f V\\n\"%Vo2)\n",
+ "print(\"output voltage case-3:\")\n",
+ "print(\"Vo3 = %.2f V\\n\"%Vo3)\n",
+ "print(\"output voltage case-4:\")\n",
+ "print(\"Vo3 = %.2f V\"%Vo4)"
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "output voltage case-1:\n",
+ "Vo1 = 2.00 V\n",
+ "\n",
+ "output voltage case-2:\n",
+ "Vo2 = 1.10 V\n",
+ "\n",
+ "output voltage case-3:\n",
+ "Vo3 = 1.01 V\n",
+ "\n",
+ "output voltage case-4:\n",
+ "Vo3 = 1.00 V\n"
+ ]
+ }
+ ],
+ "prompt_number": 19
+ },
+ {
+ "cell_type": "heading",
+ "level": 2,
+ "metadata": {},
+ "source": [
+ "Example2_9,pg 486"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "# difference in output voltage\n",
+ "\n",
+ "import math\n",
+ "#Variable declaration\n",
+ "#(R3/R1)=0.98^-1(R2/R4)\n",
+ "R1=10.0*10**3 # Resistor R1\n",
+ "R3=10.0*10**3 # Resistor R3\n",
+ "I1=130.0*10**-6 # Current \n",
+ "\n",
+ "#Calculations\n",
+ "Vo1=R1*(1+0.98)*I1 #output for case-1, (R2/R4)=0.98\n",
+ "#(R1/R3)=(R4/R2)\n",
+ "Vo2=R1*(1+(R3/R1))*I1 #output for case-2\n",
+ "Vo12=((Vo2-Vo1)/Vo2)*100 #percent difference\n",
+ "\n",
+ "#Result\n",
+ "print(\"difference in output voltage:\")\n",
+ "print(\"%% difference = %.1f %%\"%Vo12)"
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "difference in output voltage:\n",
+ "% difference = 1.0 %\n"
+ ]
+ }
+ ],
+ "prompt_number": 5
+ },
+ {
+ "cell_type": "heading",
+ "level": 2,
+ "metadata": {},
+ "source": [
+ "Example2_10,pg 486"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "# find crest factor\n",
+ "\n",
+ "import math\n",
+ "#Variable declaration\n",
+ "dutcyc=0.4 #duty cycle\n",
+ "\n",
+ "#Calculations\n",
+ "CF=math.sqrt((1-dutcyc)/dutcyc) #crest factor\n",
+ "\n",
+ "#Result\n",
+ "print(\"crest factor:\")\n",
+ "print(\"CF = %.3f \"%(math.floor(CF*1000)/1000))"
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "crest factor:\n",
+ "CF = 1.224 \n"
+ ]
+ }
+ ],
+ "prompt_number": 6
+ },
+ {
+ "cell_type": "heading",
+ "level": 2,
+ "metadata": {},
+ "source": [
+ "Example2_11,pg 486"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "# Find unknown resisance\n",
+ "\n",
+ "import math\n",
+ "R1=10*10**3 #resistor R1\n",
+ "R4=10*10**3 #resistor R4\n",
+ "Idss=1*10**-3 #drain saturation current\n",
+ "Vp=2.2 #peak voltage\n",
+ "Vo=10.0 #output voltage\n",
+ "V2=2.0 #input-1\n",
+ "V1=-2.0 #input-2\n",
+ "\n",
+ "#Calculations\n",
+ "R5=((R1*R4)/Vo)*((-2*Idss/(Vp**2)))*V1*V2\n",
+ "\n",
+ "#Result\n",
+ "print(\"R5 = %.1f k-ohm\"%(R5/1000))\n",
+ "#R5 should satisfy the condition R5=((1+R1*(-2*Idss*Vp)/R2)*R3*R6) and with Vp negative it is obiviously possible"
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "R5 = 16.5 k-ohm\n"
+ ]
+ }
+ ],
+ "prompt_number": 9
+ }
+ ],
+ "metadata": {}
+ }
+ ]
+}
\ No newline at end of file |