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-{
- "metadata": {
- "name": "",
- "signature": "sha256:2335de0a1036d6583f9ddb709f27717d7dd705b5f69b2600b20c842c855e802b"
- },
- "nbformat": 3,
- "nbformat_minor": 0,
- "worksheets": [
- {
- "cells": [
- {
- "cell_type": "heading",
- "level": 1,
- "metadata": {},
- "source": [
- "Chapter 2 - Particles Atomic and subatomic"
- ]
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 2 - pg 40"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "#calculate the Increase in kinetic energy\n",
- "#Initialization of variables\n",
- "m1=1.008142\n",
- "m2=1.008982\n",
- "#calculations\n",
- "dm=m1-m2\n",
- "dt=abs(dm) *931\n",
- "#results\n",
- "print '%s %.3f %s' %(\"Increase in kinetic energy =\",dt,\"Mev\")\n"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "Increase in kinetic energy = 0.782 Mev\n"
- ]
- }
- ],
- "prompt_number": 1
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 3 - pg 44"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "#calculate the Thickness\n",
- "#Initialization of variables\n",
- "import math\n",
- "d=8.642 #g/cc\n",
- "M=112.41 #g/mol\n",
- "ratio=0.01/100\n",
- "nb=2400\n",
- "#calculations\n",
- "n=d*6.02*10**23 /M\n",
- "sigma=nb*10**-24\n",
- "x=-2.303*math.log10(ratio) /(sigma*n)\n",
- "#results\n",
- "print '%s %.3f %s' %(\"Thickness =\",x,\"cm\")\n"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "Thickness = 0.083 cm\n"
- ]
- }
- ],
- "prompt_number": 2
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 4 - pg 49"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "#calculate the Threshold\n",
- "#Initialization of variables\n",
- "M1=4\n",
- "M2=14\n",
- "E=-1.2 #Mev\n",
- "#calculations\n",
- "R1=1.5*10**-13 *(M1)**(1/3.)\n",
- "R2=1.5*10**-13 *(M2)**(1/3.)\n",
- "V1=2*7*(4.8*10**-10)**2 /(R1+R2)\n",
- "V2=V1/(1.6*10**-6)\n",
- "x=(M1+M2)*V2/M2\n",
- "#results\n",
- "print '%s %.1f %s' %(\"Threshold =\",x,\" Mev\")\n"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "Threshold = 4.3 Mev\n"
- ]
- }
- ],
- "prompt_number": 3
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 6 - pg 53"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "#calculate the Time taken\n",
- "#Initialization of variables\n",
- "import math\n",
- "t=1622. #years\n",
- "per=1. #percent\n",
- "#calculations\n",
- "Nratio=1-per/100.\n",
- "x=t*math.log10(Nratio) / math.log10(0.5)\n",
- "#results\n",
- "print '%s %.1f %s' %(\"Time taken =\",x,\" years\")\n"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "Time taken = 23.5 years\n"
- ]
- }
- ],
- "prompt_number": 4
- }
- ],
- "metadata": {}
- }
- ]
-} \ No newline at end of file