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| author | hardythe1 | 2015-05-05 14:21:39 +0530 |
|---|---|---|
| committer | hardythe1 | 2015-05-05 14:21:39 +0530 |
| commit | fba055ce5aa0955e22bac2413c33493b10ae6532 (patch) | |
| tree | be70ef4fccd07c9c88de778014219201b4ea971f /Physical_Chemsitry/Chapter1.ipynb | |
| parent | 67068710030ddd6b6c809518c34af2e04e0bf7ca (diff) | |
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Diffstat (limited to 'Physical_Chemsitry/Chapter1.ipynb')
| -rwxr-xr-x | Physical_Chemsitry/Chapter1.ipynb | 208 |
1 files changed, 0 insertions, 208 deletions
diff --git a/Physical_Chemsitry/Chapter1.ipynb b/Physical_Chemsitry/Chapter1.ipynb deleted file mode 100755 index f8eddd0e..00000000 --- a/Physical_Chemsitry/Chapter1.ipynb +++ /dev/null @@ -1,208 +0,0 @@ -{
- "metadata": {
- "name": "",
- "signature": "sha256:2d2c58ce752ea004ea6f79edf5332f8f357b96a3e81270455c238eb5e0794fa8"
- },
- "nbformat": 3,
- "nbformat_minor": 0,
- "worksheets": [
- {
- "cells": [
- {
- "cell_type": "heading",
- "level": 1,
- "metadata": {},
- "source": [
- "Chapter 1 - matter and its atomic nature"
- ]
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 1 - pg 3"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "#calculate the Angle required\n",
- "#Initialization of variables\n",
- "import math\n",
- "l=0.71 *10**-8 #cm\n",
- "n=200. #lines/cm\n",
- "v=0.00145 #radian\n",
- "#calculations\n",
- "d=1/n\n",
- "phi2=2*l/d +v**2\n",
- "phi=math.sqrt(phi2)\n",
- "#results\n",
- "print '%s %.2e %s' %('Angle required =',phi,'radian')\n"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "Angle required = 2.22e-03 radian\n"
- ]
- }
- ],
- "prompt_number": 1
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 2 - pg 6"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "#calculate the Interplanar distance\n",
- "#Initialization of variables\n",
- "import math\n",
- "angle=37.25 #degrees\n",
- "l=1.539 #A\n",
- "n=1. #order\n",
- "#calculations\n",
- "d=n*l/(2*math.sin(angle/180.*math.pi))\n",
- "#results\n",
- "print '%s %.3f %s' %(\"Interplanar distance =\",d,\"A\")\n"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "Interplanar distance = 1.271 A\n"
- ]
- }
- ],
- "prompt_number": 2
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 5 - pg 18"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "#calculate the ratio of radii\n",
- "#Initialization of variables\n",
- "import math\n",
- "r1=math.sqrt(3.)\n",
- "r2=1\n",
- "#calculations\n",
- "ratio=r1-r2\n",
- "#results\n",
- "print '%s %.3f' %('Ratio of radii =',ratio)\n"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "Ratio of radii = 0.732\n"
- ]
- }
- ],
- "prompt_number": 3
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 6 - pg 21"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "#calculate the Avagadro number\n",
- "#Initialization of variables\n",
- "d=2.64 #g/cc\n",
- "l=4.016*10**-8 #cm\n",
- "n=4\n",
- "M=25.94 #g/mol\n",
- "#calculations\n",
- "m=d*l**3 /n\n",
- "N0=M/m\n",
- "#results\n",
- "print '%s %.3e %s' %(\"Avagadro number =\",N0,\" molecule/mol\")\n"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "Avagadro number = 6.068e+23 molecule/mol\n"
- ]
- }
- ],
- "prompt_number": 4
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 10 - pg 28"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "#calculate the angle required\n",
- "#Initialization of variables\n",
- "import math\n",
- "import numpy\n",
- "A=numpy.array([-1, -1, -1 ])\n",
- "B=numpy.array([1, 1, -1])\n",
- "#calculations\n",
- "Ad=math.sqrt(1+1+1)\n",
- "Bd=math.sqrt(1+1+1)\n",
- "dot=numpy.dot(A,B) /(Ad*Bd) \n",
- "theta=math.acos(dot) *180./math.pi\n",
- "#results\n",
- "print '%s %.2f %s' %(\"Angle =\",theta,\" degrees\")\n"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "Angle = 109.47 degrees\n"
- ]
- }
- ],
- "prompt_number": 5
- }
- ],
- "metadata": {}
- }
- ]
-}
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