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| author | tslee | 2014-11-27 17:17:59 +0530 |
|---|---|---|
| committer | tslee | 2014-11-27 17:17:59 +0530 |
| commit | 7b78be04fe05bf240417e22f74b3fc22e7a77d19 (patch) | |
| tree | 1875acbe01f3225bbfcc1024266dc96e515f3ea0 /Operational_Amplifiers_and_Linear_Integrated_Circuit/C14_1.ipynb | |
| parent | 8048392490bd2efe0fdfa001945f663cba969841 (diff) | |
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diff --git a/Operational_Amplifiers_and_Linear_Integrated_Circuit/C14_1.ipynb b/Operational_Amplifiers_and_Linear_Integrated_Circuit/C14_1.ipynb new file mode 100644 index 00000000..5eaa01c3 --- /dev/null +++ b/Operational_Amplifiers_and_Linear_Integrated_Circuit/C14_1.ipynb @@ -0,0 +1,509 @@ +{
+ "metadata": {
+ "name": ""
+ },
+ "nbformat": 3,
+ "nbformat_minor": 0,
+ "worksheets": [
+ {
+ "cells": [
+ {
+ "cell_type": "heading",
+ "level": 1,
+ "metadata": {},
+ "source": [
+ "Chapter 14:Digital to analog Converters"
+ ]
+ },
+ {
+ "cell_type": "heading",
+ "level": 3,
+ "metadata": {},
+ "source": [
+ "Example 14.1 Page no 403"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "#Given\n",
+ "n=8 #An 8-bit DAC wire\n",
+ "V1=0 #Voltage range\n",
+ "V2=5.12\n",
+ "\n",
+ "#Calculation\n",
+ "R=2**n\n",
+ "dvo=V2/R\n",
+ "Vfs=V2*(1-1/R)\n",
+ "\n",
+ "#Result\n",
+ "print\"(a)The resolution is\",R\n",
+ "print\"(b)The output change per bit is\",dvo*1000,\"mV/bit\"\n",
+ "print\"(c)the ideal full scale output voltage is\",Vfs,\"V\"\n"
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "(a)The resolution is 256\n",
+ "(b)The output change per bit is 20.0 mV/bit\n",
+ "(c)the ideal full scale output voltage is 5.12 V\n"
+ ]
+ }
+ ],
+ "prompt_number": 3
+ },
+ {
+ "cell_type": "heading",
+ "level": 3,
+ "metadata": {},
+ "source": [
+ "Example 14.2 Page no 404"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "#Given\n",
+ "Res=20 #mV/bit\n",
+ "#From the given code 00010110 and 10000000\n",
+ "#The binary weighted code for unipolar operation\n",
+ "b7=0\n",
+ "b6=0\n",
+ "b5=0\n",
+ "b4=1\n",
+ "b3=0\n",
+ "b2=1\n",
+ "b1=1\n",
+ "b0=0\n",
+ "#For part (b)\n",
+ "b7_=1\n",
+ "b6_=0\n",
+ "b5_=0\n",
+ "b4_=0\n",
+ "b3_=0\n",
+ "b2_=0\n",
+ "b1_=0\n",
+ "b0_=0\n",
+ "\n",
+ "#Calculation\n",
+ "D=b7*2**7+b6*2**6+b5*2**5+b4*2**4+b3*2**3+b2*2**2+b1*2**1+b0*2**0\n",
+ "Vo=D*Res*10**-3\n",
+ "D_=b7_*2**7+b6_*2**6+b5_*2**5+b4_*2**4+b3_*2**3+b2_*2**2+b1_*2**1+b0_*2**0\n",
+ "Vo_=D_*Res*10**-3\n",
+ "\n",
+ "#Resul\n",
+ "print\"(a)The output voltage is\",Vo,\"V\"\n",
+ "print\"(b)The output voltage is\",Vo_,\"V\"\n"
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "(a)The output voltage is 0.44 V\n",
+ "(b)The output voltage is 2.56 V\n"
+ ]
+ }
+ ],
+ "prompt_number": 4
+ },
+ {
+ "cell_type": "heading",
+ "level": 3,
+ "metadata": {},
+ "source": [
+ "Example 14.3 Page no 404"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "#Given\n",
+ "#From Example 14.1\n",
+ "n=8 #An 8-bit DAC wire\n",
+ "V1=0 #Voltage range\n",
+ "V2=5.12\n",
+ "\n",
+ "#Calculation\n",
+ "dvo=2*V2/2**n \n",
+ "\n",
+ "#Result\n",
+ "print\"The full scale output voltage range\",dvo*1000,\"V\"\n"
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "The full scale output voltage range 40.0 V\n"
+ ]
+ }
+ ],
+ "prompt_number": 6
+ },
+ {
+ "cell_type": "heading",
+ "level": 3,
+ "metadata": {},
+ "source": [
+ "Example 14.4 Page no 405"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "#Given\n",
+ "Vref=10.24 #V, input ref voltage\n",
+ "p=0.05 #Percentage error\n",
+ "n=12 #12 bit unipolar DAC\n",
+ "\n",
+ "#Calculation\n",
+ "Voff=0.05/100*Vref\n",
+ "dvo=Vref/(2**n)\n",
+ "a=Voff/dvo\n",
+ "\n",
+ "#REsult\n",
+ "print\"The offset voltage is\",Voff*1000,\"mV\"\n",
+ "print\"Interms of least significant bit(s) it is\",dvo*1000,\"mV/bit\"\n"
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "The offset voltage is 5.12 mV\n",
+ "Interms of least significant bit(s) it is 2.5 mV/bit\n"
+ ]
+ }
+ ],
+ "prompt_number": 9
+ },
+ {
+ "cell_type": "heading",
+ "level": 3,
+ "metadata": {},
+ "source": [
+ "Example 14.5 Page no 407"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "#Given\n",
+ "n=8.0 #8-bit DAC\n",
+ "error=0.2 #percent\n",
+ "Vref=5.12 #V\n",
+ "Vos=0\n",
+ "\n",
+ "#Calculation\n",
+ "V11=(((-error/100.0))+1)*(Vref)+Vos\n",
+ "\n",
+ "#REsult\n",
+ "print\"The minimum output voltage is\",round(V11,1),\"V\"\n"
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "The minimum output voltage is 5.1 V\n"
+ ]
+ }
+ ],
+ "prompt_number": 7
+ },
+ {
+ "cell_type": "heading",
+ "level": 3,
+ "metadata": {},
+ "source": [
+ "Example 14.6 Page no 411"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "#Given\n",
+ "n=4.0 #4 bit resistance ladder\n",
+ "R=10.0 #kohm\n",
+ "Vref=10.0 #V\n",
+ "\n",
+ "#Calculation\n",
+ "Res=Vref/(2**n*R*10**3)\n",
+ "\n",
+ "#From dicimal value of binary 1111\n",
+ "D=15\n",
+ "Iout=Res*D\n",
+ "\n",
+ "#Result\n",
+ "print\"The resolution of 1 LSB is\",Res*10**6,\"microA\"\n",
+ "print\"output current is\",Iout*1000,\"microA\"\n"
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "The resolution of 1 LSB is 62.5 microA\n",
+ "output current is 0.9375 microA\n"
+ ]
+ }
+ ],
+ "prompt_number": 2
+ },
+ {
+ "cell_type": "heading",
+ "level": 3,
+ "metadata": {},
+ "source": [
+ "Example 14.7 Page no 412"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "#Given\n",
+ "Io=62.5 #microA, from ex. 14.6\n",
+ "Rf=10 #kohm , from fig.14.7\n",
+ "Vref=10 #V, reference voltage\n",
+ "R=Rf\n",
+ "n=4 #no of bits\n",
+ "\n",
+ "#Calculation\n",
+ "VR=Io*Rf*10**-3\n",
+ "D=15 #For a digital input of 1111\n",
+ "Vo=-VR*D\n",
+ "\n",
+ "#REsult\n",
+ "print\"The voltage resolution of 1 LSB is\",VR,\"V\"\n",
+ "print\"When digital input is 1111 , Vo is\",Vo,\"V\"\n"
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "The voltage resolution of 1 LSB is 0.625 V\n",
+ "When digital input is 1111 , Vo is -9.375 V\n"
+ ]
+ }
+ ],
+ "prompt_number": 23
+ },
+ {
+ "cell_type": "heading",
+ "level": 3,
+ "metadata": {},
+ "source": [
+ "Example 14.8 Page no 416"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "#Given\n",
+ "Vref=10.0 #V, from fig. 14.8. reference voltage\n",
+ "Rref=5.0 #kohm\n",
+ "n=8.0 #no of bits\n",
+ "\n",
+ "#Calculation\n",
+ "Iref=Vref/Rref\n",
+ "I=Vref/(Rref*2**n)\n",
+ "\n",
+ "#Result\n",
+ "print\"The ladder input current is\",Iref,\"mA\"\n",
+ "print\"Current value of 1 LSB is\",round(I*1000,3),\"microA\"\n"
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "The ladder input current is 2.0 mA\n",
+ "Current value of 1 LSB is 7.813 microA\n"
+ ]
+ }
+ ],
+ "prompt_number": 30
+ },
+ {
+ "cell_type": "heading",
+ "level": 3,
+ "metadata": {},
+ "source": [
+ "Example 14.9 Page no 417"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "#Given\n",
+ "I=7.812 #Current resolution from ex 14.8\n",
+ "\n",
+ "\n",
+ "#Calculation\n",
+ "Ifs=I*10**-3*255 #From eq. 14-15(a)\n",
+ "#The value of D for part (a),(b),(c)\n",
+ "D1=1 #for digital input 00000001\n",
+ "D2=128\t\t#for digital input 10000000\n",
+ "D3=255\t\t#for digital input 11111111\n",
+ "Iout1=I*D1\n",
+ "Iout2=I*D2\n",
+ "Iout3=I*D3\n",
+ "Iout_1=Ifs-Iout1*10**-3\n",
+ "Iout_2=Ifs-Iout2*10**-3\n",
+ "Iout_3=Ifs-Iout3*10**-3\n",
+ "\n",
+ "#Result\n",
+ "print\"(a) The Iout is\",Iout1,\"mA and Iout_ is\",round(Iout_1,3),\"mA\"\n",
+ "print\"(b) The Iout is\",Iout2,\"mA and Iout_ is\",round(Iout_2,3),\"mA\"\n",
+ "print\"(c) The Iout is\",Iout3,\"mA and Iout_ is\",Iout_3,\"mA\"\n"
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "(a) The Iout is 7.812 mA and Iout_ is 1.984 mA\n",
+ "(b) The Iout is 999.936 mA and Iout_ is 0.992 mA\n",
+ "(c) The Iout is 1992.06 mA and Iout_ is 0.0 mA\n"
+ ]
+ }
+ ],
+ "prompt_number": 35
+ },
+ {
+ "cell_type": "heading",
+ "level": 3,
+ "metadata": {},
+ "source": [
+ "Example 14.10 Page no 417"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "#Given\n",
+ "#From fig 14.8 (a)\n",
+ "Vref=10 #V\n",
+ "Rf=5\t\t#kohm\n",
+ "Rref=5.0\t\t#kohm\n",
+ "n=8\t\t#\n",
+ "\n",
+ "#Calculation\n",
+ "VR=Vref*Rf/(Rref*2**n)\n",
+ "D1=1\t\t#Value of D for 00000001\n",
+ "D2=255\t\t#Value of D for 11111111\n",
+ "Vo1=VR*1000*D1\n",
+ "Vo2=VR*1000*D2\n",
+ "\n",
+ "#Result\n",
+ "print\"(a) Vo is \",round(Vo1,0),\"V\"\n",
+ "print\"(b) Vo is \",round(Vo2/1000,3),\"V\"\n"
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "(a) Vo is 39.0 V\n",
+ "(b) Vo is 9.961 V\n"
+ ]
+ }
+ ],
+ "prompt_number": 43
+ },
+ {
+ "cell_type": "heading",
+ "level": 3,
+ "metadata": {},
+ "source": [
+ "Example 14.11 Page no 418"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "#Given\n",
+ "#From fig 14.9(a)\n",
+ "I=8 #microA, value of 1 LSB\n",
+ "Rf=5\t\t# kohm\n",
+ "\n",
+ "#Calculation\n",
+ "#from eq 14-15(a)\n",
+ "Ifs=I*10**-3*255\n",
+ "D1=0 \t\t#Value of D for 00000000\n",
+ "Iout1=I*D1\n",
+ "Iout_1=Ifs-Iout1\n",
+ "Vo1=(Iout1-Iout_1)*Rf\n",
+ "\n",
+ "D2=127 #From digital value(b)\n",
+ "Iout2=I*D2\n",
+ "Iout_2=Ifs-Iout2/1000.0\n",
+ "Vo2=(Iout2/1000.0-Iout_2)*Rf\n",
+ "\n",
+ "D3=128 \t\t#Value of D for 00000000\n",
+ "Iout3=I*D3\n",
+ "Iout_3=Ifs-Iout3/1000.0\n",
+ "Vo3=(Iout3/1000.0-Iout_3)*Rf\n",
+ "\n",
+ "D4=255 \t\t#Value of D for 00000000\n",
+ "Iout4=I*D4\n",
+ "Iout_4=Ifs-Iout4/1000\n",
+ "Vo4=(Iout4/1000-Iout_4)*Rf\n",
+ "\n",
+ "#Result\n",
+ "print\"(a)Vo is \",Vo1,\"V . (b)Vo is \",round(Vo2,3),\"V. (c)Vo is \",Vo3,\"V .(d)Vo is \",round(Vo4,0),\"V\""
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ " 2.04\n",
+ "(a)Vo is -10.2 V . (b)Vo is -0.04 V. (c)Vo is 0.04 V .(d)Vo is 10.0 V\n"
+ ]
+ }
+ ],
+ "prompt_number": 35
+ }
+ ],
+ "metadata": {}
+ }
+ ]
+}
\ No newline at end of file |