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author | hardythe1 | 2015-04-07 15:58:05 +0530 |
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committer | hardythe1 | 2015-04-07 15:58:05 +0530 |
commit | c7fe425ef3c5e8804f2f5de3d8fffedf5e2f1131 (patch) | |
tree | 725a7d43dc1687edf95bc36d39bebc3000f1de8f /Modern_Physics_By_G.Aruldas/Chapter19_2.ipynb | |
parent | 62aa228e2519ac7b7f1aef53001f2f2e988a6eb1 (diff) | |
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diff --git a/Modern_Physics_By_G.Aruldas/Chapter19_2.ipynb b/Modern_Physics_By_G.Aruldas/Chapter19_2.ipynb new file mode 100755 index 00000000..c8745970 --- /dev/null +++ b/Modern_Physics_By_G.Aruldas/Chapter19_2.ipynb @@ -0,0 +1,291 @@ +{
+ "metadata": {
+ "name": "",
+ "signature": "sha256:9326f276d5dc99ce97d41c9ca0d5924dbd68f522091536657f41d8cfe038dc31"
+ },
+ "nbformat": 3,
+ "nbformat_minor": 0,
+ "worksheets": [
+ {
+ "cells": [
+ {
+ "cell_type": "heading",
+ "level": 1,
+ "metadata": {},
+ "source": [
+ "19: Nuclear reactions"
+ ]
+ },
+ {
+ "cell_type": "heading",
+ "level": 2,
+ "metadata": {},
+ "source": [
+ "Example number 19.1, Page number 368"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "#importing modules\n",
+ "import math\n",
+ "from __future__ import division\n",
+ "\n",
+ "#Variable declaration\n",
+ "m2H=2.014102; #atomic mass of 2H(u)\n",
+ "mn=1.008665; #mass of n(u)\n",
+ "m63Cu=62.929599; #mass of 63Cu(u)\n",
+ "m64Zn=63.929144; #mass of m64Zn(u)\n",
+ "E=931.5; #energy(MeV)\n",
+ "Kx=10; #energy of deutron(MeV)\n",
+ "Ky=15; #energy of neutron(MeV)\n",
+ "\n",
+ "#Calculation\n",
+ "Q=E*(m2H+m63Cu-mn-m64Zn); #Q-value(MeV)\n",
+ "KY=Q+Kx-Ky; #kinetic energy(MeV)\n",
+ "\n",
+ "#Result\n",
+ "print \"Q-value is\",round(Q,3),\"MeV\"\n",
+ "print \"kinetic energy is\",round(KY,3),\"MeV\""
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "Q-value is 5.488 MeV\n",
+ "kinetic energy is 0.488 MeV\n"
+ ]
+ }
+ ],
+ "prompt_number": 2
+ },
+ {
+ "cell_type": "heading",
+ "level": 2,
+ "metadata": {},
+ "source": [
+ "Example number 19.2, Page number 368"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "#importing modules\n",
+ "import math\n",
+ "from __future__ import division\n",
+ "\n",
+ "#Variable declaration\n",
+ "m19F=18.998404; #atomic mass of 19F(u)\n",
+ "mH=1.007825; #mass of H(u)\n",
+ "m19O=19.003577; #mass of 19O(u)\n",
+ "mn=1.008665; #mass of n(u)\n",
+ "E=931.5; #energy(MeV)\n",
+ "\n",
+ "#Calculation\n",
+ "Q=E*(m19F+mn-mH-m19O); #Q-value(MeV)\n",
+ "Kxmin=-Q*(1+(mn/m19F)); #threshold energy(MeV)\n",
+ "\n",
+ "#Result\n",
+ "print \"Q-value is\",round(Q,4),\"MeV\"\n",
+ "print \"threshold energy is\",round(Kxmin,2),\"MeV\""
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "Q-value is -4.0362 MeV\n",
+ "threshold energy is 4.25 MeV\n"
+ ]
+ }
+ ],
+ "prompt_number": 5
+ },
+ {
+ "cell_type": "heading",
+ "level": 2,
+ "metadata": {},
+ "source": [
+ "Example number 19.3, Page number 373"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "#importing modules\n",
+ "import math\n",
+ "from __future__ import division\n",
+ "\n",
+ "#Variable declaration\n",
+ "mn=1.008665; #mass of n(u)\n",
+ "mu=235.043924; #mass of 235U(u)\n",
+ "mBa=140.91440; #mass of 141Ba(u)\n",
+ "mKr=91.92630; #mass of Kr(u)\n",
+ "E=931.5; #energy(MeV)\n",
+ "\n",
+ "#Calculation\n",
+ "mr=mn+mu; #mass of reactants(u)\n",
+ "mp=mBa+mKr+(3*mn); #mass of products(u)\n",
+ "md=mr-mp; #mass difference(u)\n",
+ "E=md*E; #energy released(MeV)\n",
+ "\n",
+ "#Result\n",
+ "print \"energy released is\",round(E,1),\"MeV\""
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "energy released is 173.2 MeV\n"
+ ]
+ }
+ ],
+ "prompt_number": 19
+ },
+ {
+ "cell_type": "heading",
+ "level": 2,
+ "metadata": {},
+ "source": [
+ "Example number 19.4, Page number 373"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "#importing modules\n",
+ "import math\n",
+ "from __future__ import division\n",
+ "\n",
+ "#Variable declaration\n",
+ "E=200*10**6; #energy released(eV)\n",
+ "e=1.6*10**-19; #conversion factor from J to eV\n",
+ "P=300*10**6; #power(W)\n",
+ "t=1; #time(s)\n",
+ "\n",
+ "#Calculation\n",
+ "n=P*t/(E*e); #number of fissions per second\n",
+ "\n",
+ "#Result\n",
+ "print \"number of fissions per second is\",n"
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "number of fissions per second is 9.375e+18\n"
+ ]
+ }
+ ],
+ "prompt_number": 20
+ },
+ {
+ "cell_type": "heading",
+ "level": 2,
+ "metadata": {},
+ "source": [
+ "Example number 19.5, Page number 378"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "#importing modules\n",
+ "import math\n",
+ "from __future__ import division\n",
+ "\n",
+ "#Variable declaration\n",
+ "m2H1=2*1.66*10**-27; #mass of proton(kg)\n",
+ "E=931.5; #energy(MeV)\n",
+ "m1=2.014102;\n",
+ "m2=3.01609;\n",
+ "mH=1.007825; #mass of H(u)\n",
+ "\n",
+ "#Calculation\n",
+ "E=E*((2*m1)-m2-mH); #energy released(MeV)\n",
+ "n=0.001/m2H1; #number of nuclei\n",
+ "Eg=n*E/2; #energy released per gm(MeV)\n",
+ "\n",
+ "#Result\n",
+ "print \"energy released per gm is\",round(Eg/10**23,2),\"*10**23 MeV\"\n",
+ "print \"answer given in the book is wrong\""
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "energy released per gm is 6.02 *10**23 MeV\n",
+ "answer given in the book is wrong\n"
+ ]
+ }
+ ],
+ "prompt_number": 31
+ },
+ {
+ "cell_type": "heading",
+ "level": 2,
+ "metadata": {},
+ "source": [
+ "Example number 19.6, Page number 379"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "#importing modules\n",
+ "import math\n",
+ "from __future__ import division\n",
+ "\n",
+ "#Variable declaration\n",
+ "k=8.99*10**9; #value of k(Nm**2/C**2)\n",
+ "rd=1.5*10**-15; #radius of deuterium nucleus(m)\n",
+ "rt=1.7*10**-15; #radius of tritium nucleus(m)\n",
+ "e=1.6*10**-19; #conversion factor from J to eV\n",
+ "KE=0.225; #kinetic energy for 1 particle(MeV)\n",
+ "k=1.38*10**-23; #boltzmann constant(J/K)\n",
+ "\n",
+ "#Calculation\n",
+ "K_E=k*e**2/(e*(rd+rt)); #kinetic energy of 2 particles(MeV)\n",
+ "T=2*KE*e*10**6/(3*k); #temperature(K)\n",
+ "\n",
+ "#Result\n",
+ "print \"temperature is\",round(T/10**9),\"*10**9 K\""
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "temperature is 2.0 *10**9 K\n"
+ ]
+ }
+ ],
+ "prompt_number": 35
+ }
+ ],
+ "metadata": {}
+ }
+ ]
+}
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