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author | hardythe1 | 2015-04-07 15:58:05 +0530 |
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committer | hardythe1 | 2015-04-07 15:58:05 +0530 |
commit | 92cca121f959c6616e3da431c1e2d23c4fa5e886 (patch) | |
tree | 205e68d0ce598ac5caca7de839a2934d746cce86 /Modern_Physics/Chapter15_2.ipynb | |
parent | b14c13fcc6bb6d01c468805d612acb353ec168ac (diff) | |
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diff --git a/Modern_Physics/Chapter15_2.ipynb b/Modern_Physics/Chapter15_2.ipynb new file mode 100755 index 00000000..90c037a5 --- /dev/null +++ b/Modern_Physics/Chapter15_2.ipynb @@ -0,0 +1,62 @@ +{ + "metadata": { + "name": "MP-15" + }, + "nbformat": 3, + "nbformat_minor": 0, + "worksheets": [ + { + "cells": [ + { + "cell_type": "heading", + "level": 1, + "metadata": {}, + "source": "The General Theory of Relativity" + }, + { + "cell_type": "heading", + "level": 2, + "metadata": {}, + "source": "Example 15.1 Page 491" + }, + { + "cell_type": "code", + "collapsed": false, + "input": "#initiation of variable\nw=121.5; #lambeda\nG=6.67*10**-11; #Various given values and constants\nM= 1.99*10**30; \nR= 6.96*10**8;\nc=3*10**8;\n\n#calculation\nk= G*M/(R*c**2); #(delLambeda)/(lambeda)\ndelw=k*w; #del(lambeda)\n\n#result\nprint \"The change in wavelength due to gravitational shift in pm is\",round(delw*10**3,3);\n\n#part3\nk=5.5*10**-5;#due to thermal Doppler broadening effect\ndelw=k*w;\n\n#result\nprint \"The change in wavelength due to thermal Doppler broadening effect in pm is\",round(delw*10**3,3);", + "language": "python", + "metadata": {}, + "outputs": [ + { + "output_type": "stream", + "stream": "stdout", + "text": " The change in wavelength due to gravitational shift in pm is 0.257\nThe change in wavelength due to thermal Doppler broadening effect in pm is 6.683\n" + } + ], + "prompt_number": 2 + }, + { + "cell_type": "heading", + "level": 2, + "metadata": {}, + "source": "Example 15.2 Page 501" + }, + { + "cell_type": "code", + "collapsed": false, + "input": "#initiation of variable\nmp=938.280; #mass of various particles\nme=0.511;\nm2h=1875.628;\n\n#calculation\nmic2=2*mp; #mass energy on L.H.S\nmfc2=m2h+me; #mass energy on R.H.S\nQ=mic2-mfc2; #Q value of reation\npc=Q;\nmc2=1875.628;\nK=(pc**2)/(2*mc2); #kinetic threshold energy\nEmax=Q-K; #maximum energy \n\n#result\nprint \"The maximum neutrino energy in MeV is\",round(Emax,3);", + "language": "python", + "metadata": {}, + "outputs": [ + { + "output_type": "stream", + "stream": "stdout", + "text": "The maximum neutrino energy in MeV is 0.421\n" + } + ], + "prompt_number": 3 + } + ], + "metadata": {} + } + ] +}
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