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| author | nice | 2014-10-09 18:07:00 +0530 |
|---|---|---|
| committer | nice | 2014-10-09 18:07:00 +0530 |
| commit | 8048392490bd2efe0fdfa001945f663cba969841 (patch) | |
| tree | c298682dfb22073b17d86791c5e7a756f4aa1a92 /Modern_Electronics_Communication/Chapter5.ipynb | |
| parent | b9ebc3adfe1cd0b17f061dd639a5c76329e09afa (diff) | |
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diff --git a/Modern_Electronics_Communication/Chapter5.ipynb b/Modern_Electronics_Communication/Chapter5.ipynb new file mode 100755 index 00000000..5e894199 --- /dev/null +++ b/Modern_Electronics_Communication/Chapter5.ipynb @@ -0,0 +1,360 @@ +{
+ "metadata": {
+ "name": ""
+ },
+ "nbformat": 3,
+ "nbformat_minor": 0,
+ "worksheets": [
+ {
+ "cells": [
+ {
+ "cell_type": "heading",
+ "level": 1,
+ "metadata": {},
+ "source": [
+ "Chapter 5 Frequency Modulation : Transmission"
+ ]
+ },
+ {
+ "cell_type": "heading",
+ "level": 2,
+ "metadata": {},
+ "source": [
+ "Example 5.1 Page no 209"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "#given\n",
+ "v=25*10**-3\n",
+ "f=750 #deviation constant\n",
+ "vg=10.0*10**-3 #deviation constant\n",
+ "\n",
+ "#calculation\n",
+ "pfd=v*(f/vg) #positive frequency deviation\n",
+ "nfd=-v*(f/vg) #negative frequency deviation\n",
+ "\n",
+ "#result\n",
+ "print\"(a) positive frequency deviation = \",pfd,\"Hz\"\n",
+ "print\"negative frequency deviation = \",nfd,\"Hz\"\n",
+ "print\"The total deviation is written as +-2.25kHz for the given input signal level\"\n",
+ "print\"(b) The carrier wil deviate \",pfd,\"Hz\",\"&\",nfd,\"Hz\",\"at 400 Hz\"\n"
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "(a) positive frequency deviation = 1875.0 Hz\n",
+ "negative frequency deviation = -1875.0 Hz\n",
+ "The total deviation is written as +-2.25kHz for the given input signal level\n",
+ "(b) The carrier wil deviate 1875.0 Hz & -1875.0 Hz at 400 Hz\n"
+ ]
+ }
+ ],
+ "prompt_number": 5
+ },
+ {
+ "cell_type": "heading",
+ "level": 2,
+ "metadata": {},
+ "source": [
+ "Example 5.3 Page no 214"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "#given\n",
+ "d=20*10**3 #maximum deviation\n",
+ "fi=10.0*10**3 #input frequency\n",
+ "\n",
+ "#calculation\n",
+ "mf=d/fi\n",
+ "a=mf*40\n",
+ "\n",
+ "#result\n",
+ "print\"total required bandwidth is \",a,\"KHz\"\n"
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "total required bandwidth is 80.0 KHz\n"
+ ]
+ }
+ ],
+ "prompt_number": 6
+ },
+ {
+ "cell_type": "heading",
+ "level": 2,
+ "metadata": {},
+ "source": [
+ "Example 5.4 Page no 214"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "#given\n",
+ "d=20*10**3 #maximum deviation\n",
+ "fi=5.0*10**3 #input frequency\n",
+ "\n",
+ "#calculation\n",
+ "mf=d/fi\n",
+ "a=2*35\n",
+ "\n",
+ "#print\n",
+ "print\"the required bandwidth is \",mf\n"
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "the required bandwidth is 4.0\n"
+ ]
+ }
+ ],
+ "prompt_number": 2
+ },
+ {
+ "cell_type": "heading",
+ "level": 2,
+ "metadata": {},
+ "source": [
+ "Example 5.5 Page no 215"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "#given\n",
+ "Vm=2000\n",
+ "R=50.0 #resistance, ohm\n",
+ "\n",
+ "#calcultion\n",
+ "import math\n",
+ "fc=(2*math.pi*(10**8))/2.0*math.pi\n",
+ "P=(2000/math.sqrt(2))**2/R\n",
+ "mf=2 #by inspection of FM equation\n",
+ "fi=(math.pi*10**4)/(2.0*math.pi)\n",
+ "d=(mf*fi)\n",
+ "BW=mf*40\n",
+ "bw=2*(d+fi)\n",
+ "P1=((0.58*2000/math.sqrt(2))**2)/R\n",
+ "P2=((0.03*2000/math.sqrt(2))**2)/R\n",
+ "\n",
+ "#result\n",
+ "print\"(a) carrier frequency = \",round(fc,-9),\"Hz\" #by inspection of FM equation\n",
+ "print\"(b) the peak voltage is 2000V P thus= \",P,\"W\"\n",
+ "print\"(c) mf = 2\" #by inspection of FM equation\n",
+ "print\"(d) the intelligence frequency fi = \",fi,\"Hz\"\n",
+ "print\"(e) BW = \",bw ,\"Hz\" #using carson's rule \n",
+ "print\"(f) The smallest sideband J4 is 0.03 times the carrier = \",P2,\"W\""
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "(a) carrier frequency = 1000000000.0 Hz\n",
+ "(b) the peak voltage is 2000V P thus= 40000.0 W\n",
+ "(c) mf = 2\n",
+ "(d) the intelligence frequency fi = 5000.0 Hz\n",
+ "(e) BW = 30000.0 Hz\n",
+ "(f) The smallest sideband J4 is 0.03 times the carrier = 36.0 W\n"
+ ]
+ }
+ ],
+ "prompt_number": 6
+ },
+ {
+ "cell_type": "heading",
+ "level": 2,
+ "metadata": {},
+ "source": [
+ "Example 5.6 Page no 218"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "#given\n",
+ "d=75*10**3 #maximum deviation\n",
+ "fi=30.0 #modulating frequency, Hz\n",
+ "fi1=15.0*10**3 \n",
+ "d1=1*10**3\n",
+ "fi2=100 #Hz\n",
+ "fi3=2.0*10**3\n",
+ "\n",
+ "#calculation\n",
+ "mf1=d/fi\n",
+ "mf2=d/fi1\n",
+ "mf3=d1/fi2\n",
+ "mf4=d1/fi3\n",
+ "DR=d1/fi3\n",
+ "\n",
+ "#result\n",
+ "print\"(a)maximum deviation at 30 Hz = \",mf1 \n",
+ "print\"maximum deviation at 15kHz= \",mf2\n",
+ "print\"(b) maximum deviation at 100Hz = \",mf3\n",
+ "print\"maximum deviation at 2KHz= \",mf4\n",
+ "print \"(c)Deviation Ratio \",DR #deviation ratio"
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "(a)maximum deviation at 30 Hz = 2500.0\n",
+ "maximum deviation at 15kHz= 5.0\n",
+ "(b) maximum deviation at 100Hz = 10\n",
+ "maximum deviation at 2KHz= 0.5\n",
+ "(c)Deviation Ratio 0.5\n"
+ ]
+ }
+ ],
+ "prompt_number": 1
+ },
+ {
+ "cell_type": "heading",
+ "level": 2,
+ "metadata": {},
+ "source": [
+ "Example 5.7 Page no 218"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "#given\n",
+ "mf=0.25\n",
+ "a=0.98\n",
+ "b=0.12\n",
+ "x=10*10**3 #power, watt\n",
+ "\n",
+ "#calculation\n",
+ "P=(a**2)*x\n",
+ "P1=(b**2)*x\n",
+ "t=P+2*P1\n",
+ "\n",
+ "#result\n",
+ "print\"power of each sideband = \",P1,\"W\"\n",
+ "print\"total power = \",round(t,-4),\"W\"\n"
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "power of each sideband = 144.0 W\n",
+ "total power = 10000.0 W\n"
+ ]
+ }
+ ],
+ "prompt_number": 31
+ },
+ {
+ "cell_type": "heading",
+ "level": 2,
+ "metadata": {},
+ "source": [
+ "Example 5.8 Page no 222"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "#given\n",
+ "phi=0.5 #maximum intelligence frequency\n",
+ "fi=5.0*10**3\n",
+ "x=75*10**3\n",
+ "\n",
+ "#calculation\n",
+ "d=phi*fi\n",
+ "y=x/d\n",
+ "\n",
+ "#result\n",
+ "print\"o/p S/N = \",y\n"
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "o/p S/N = 30.0\n"
+ ]
+ }
+ ],
+ "prompt_number": 34
+ },
+ {
+ "cell_type": "heading",
+ "level": 2,
+ "metadata": {},
+ "source": [
+ "Example 5.9 Page no 222"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "#given\n",
+ "dm=10*10**3\n",
+ "x=(1/3.0) #N/S input ratio\n",
+ "\n",
+ "#calculation\n",
+ "import math\n",
+ "phi=math.asin(x)\n",
+ "phi1=math.asin(x)\n",
+ "fi=3*10**3\n",
+ "d=phi1*fi\n",
+ "a=dm/d\n",
+ "\n",
+ "#result\n",
+ "print\"The S/N output will be \",round(a,0)\n"
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "The S/N output will be 10.0\n"
+ ]
+ }
+ ],
+ "prompt_number": 36
+ }
+ ],
+ "metadata": {}
+ }
+ ]
+}
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