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+{
+ "metadata": {
+ "name": ""
+ },
+ "nbformat": 3,
+ "nbformat_minor": 0,
+ "worksheets": [
+ {
+ "cells": [
+ {
+ "cell_type": "heading",
+ "level": 1,
+ "metadata": {},
+ "source": [
+ "Chapter 11:Design of Beams and Shafts"
+ ]
+ },
+ {
+ "cell_type": "heading",
+ "level": 3,
+ "metadata": {},
+ "source": [
+ "Example 11.1 Page No 544"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "#Given\n",
+ "sigma_allow = 24 #ksi, stress\n",
+ "tou_allow = 14.5 #ksi, allowable stress\n",
+ "\n",
+ "#Shear and Moment Diagrams\n",
+ "V_max = 30 #kip, \n",
+ "M_max = 120 #kip, bending moment\n",
+ "\n",
+ "#Bending Stress\n",
+ "S_reqd = (M_max*(10**3))/sigma_allow\n",
+ "#Shear Stress\n",
+ "d = 17.9 #in\n",
+ "tw = 0.315 #inch\n",
+ "tou_avg = (V_max)/(d*tw)\n",
+ "\n",
+ "if tou_avg<14.5:\n",
+ " print\"Use a W18*14\"\n"
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "Use a W18*14\n"
+ ]
+ }
+ ],
+ "prompt_number": 5
+ },
+ {
+ "cell_type": "heading",
+ "level": 3,
+ "metadata": {},
+ "source": [
+ "Example 11.2 Page No 545"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "#Given\n",
+ "udl = 0.5 #kN/m\n",
+ "h_by_a = 1.5 \n",
+ "sigma_allow = 9 #MPa, allowable bending stress\n",
+ "tou_allow = 0.6 #MPa, allowable shear stress\n",
+ "\n",
+ "#calculation\n",
+ "#Shear and Moment Diagrams\n",
+ "import math\n",
+ "V_max =20 #kNm\n",
+ "M_max =10.67 #kNm\n",
+ "#Bending Stress\n",
+ "S_reqd = (M_max)/(sigma_allow*1000)\n",
+ "c = h_by_a/2.0\n",
+ "a_cube = (S_reqd*c*12)/(1.5**3) #S_reqd = I/c\n",
+ "a = a_cube**(1/3.0)\n",
+ "A = a*h_by_a*a\n",
+ "tou_max = (1.5*V_max)/(A*1000)\n",
+ "if tou_max>tou_allow:\n",
+ " a_sqr = (3/2.0)*(V_max)/(h_by_a*tou_allow*1000)\n",
+ " a =math.sqrt(a_sqr)\n",
+ "else:\n",
+ " print\"not\"\n",
+ "\n",
+ "#Display\n",
+ "print\"The smallest width for the laminated wooden beam = \", round(a,2),\"m\"\n"
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "The smallest width for the laminated wooden beam = 0.18 m\n"
+ ]
+ }
+ ],
+ "prompt_number": 5
+ },
+ {
+ "cell_type": "heading",
+ "level": 3,
+ "metadata": {},
+ "source": [
+ "Example 11.3 Page No 546"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "#Given\n",
+ "l = 200/1000.0 #m, length\n",
+ "t = 30/1000.0 #m\n",
+ "sigma_allow = 9 #MPa, shear stress\n",
+ "tou_allow = 0.6 #MPa, bending stress\n",
+ "V_nail = 1.50 #kN\n",
+ "l_bc = 2 #m\n",
+ "l_cd = 2 #m\n",
+ "\n",
+ "#Shear and Moment Diagrams\n",
+ "V_max = 20 #kN\n",
+ "M_max =10.67 #kNm\n",
+ "#Bending Stress\n",
+ "y1 = l/2.0\n",
+ "A1 = l*t\n",
+ "y2 = l+(t/2.0)\n",
+ "A2 = t*l\n",
+ "y_dash = (y1*A1 + y2*A2)/(A1 + A2)\n",
+ "\n",
+ "I1 = (t*l**3)/12.0 + (t*l*(y_dash - y1)**2)\n",
+ "I2 = (l*t**3)/12.0 + (t*l*(y2 - y_dash)**2)\n",
+ "I =I1 + I2\n",
+ "\n",
+ "c = y_dash\n",
+ "sigma = (M_max*c)/(I)\n",
+ "flag1 = 0\n",
+ "sigma_allow = sigma_allow*1000 #kPa\n",
+ "\n",
+ "if(sigma<sigma_allow):\n",
+ " flag1 = 1\n",
+ "else:\n",
+ " print\"otherwisw not\"\n",
+ "\n",
+ "#Shear Stress\n",
+ "y3 = y_dash/2.0\n",
+ "A3 = y_dash*t\n",
+ "Q = y3*A3\n",
+ "\n",
+ "tou = (V_max*Q)/(I*t)\n",
+ "tou_allow = tou_allow*1000 #kPa\n",
+ "flag2 =0\n",
+ "\n",
+ "if(tou<tou_allow):\n",
+ " flag2 = 1\n",
+ "else:\n",
+ " print\"flag2 is not equal to one\"\n",
+ "\n",
+ "#Nail Spacing\n",
+ "y4a = (l+t-y_dash)\n",
+ "y4 = y4a - (t/2.0)\n",
+ "A4 = l*t\n",
+ "Q4 = y4*A4\n",
+ "V_bc = 1.5 #kN\n",
+ "V_cd = 1 #kN\n",
+ "\n",
+ "q_bc = (V_bc*Q4)/I\n",
+ "q_cd = (V_cd*Q4)/I\n",
+ "\n",
+ "s_bc = (V_nail)/(q_bc)\n",
+ "s_cd = (V_nail)/(q_cd)\n",
+ "\n",
+ "chosen_bc = 150 #mm\n",
+ "chosen_cd = 250 #mm\n",
+ "\n",
+ "#Result\n",
+ "print'The design is safe in bending and shear.'\n",
+ "print'The calculated nail spacing BC ',round(s_bc,2),\"m\"\n",
+ "print'The calculated nail spacing CD ',round(s_cd,2),\"m\"\n",
+ "print'The chosen nail spacing BC ',chosen_bc,\"mm\"\n",
+ "print'The chosen nail spacing CD ',chosen_cd,\"mm\"\n",
+ "\n"
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "otherwisw not\n",
+ "flag2 is not equal to one\n",
+ "The design is safe in bending and shear.\n",
+ "The calculated nail spacing BC 0.17 m\n",
+ "The calculated nail spacing CD 0.26 m\n",
+ "The chosen nail spacing BC 150 mm\n",
+ "The chosen nail spacing CD 250 mm\n"
+ ]
+ }
+ ],
+ "prompt_number": 1
+ },
+ {
+ "cell_type": "heading",
+ "level": 3,
+ "metadata": {},
+ "source": [
+ "Example 11.6 Page No 560"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "#Find smallest allowable diameter\n",
+ "\n",
+ "#Given\n",
+ "tou_allow = 50*10**6 #MPa, shear stress\n",
+ "T = 7.5 #Nm, torque\n",
+ "R_ah = 150 #N, horizontal force\n",
+ "R_av = 475 #N\n",
+ "l_ac = 0.25 #m\n",
+ "\n",
+ "#Calculation\n",
+ "import math\n",
+ "mc = R_ah*l_ac\n",
+ "m = R_av*l_ac\n",
+ "M_c = sqrt(m**2 + mc**2)\n",
+ "k = sqrt(M_c**2 + T**2)\n",
+ "c1 = (2*k)/(math.pi*tou_allow)\n",
+ "c = c1**(1/3.0)\n",
+ "d = 2*c*1000\n",
+ "\n",
+ "#Display\n",
+ "print\"The smallest allowable diameter of the shaft =\",round(d,1),\"mm\"\n"
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "The smallest allowable diameter of the shaft = 23.3 mm\n"
+ ]
+ }
+ ],
+ "prompt_number": 3
+ }
+ ],
+ "metadata": {}
+ }
+ ]
+} \ No newline at end of file