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| author | Jovina Dsouza | 2014-06-18 12:43:07 +0530 |
|---|---|---|
| committer | Jovina Dsouza | 2014-06-18 12:43:07 +0530 |
| commit | 206d0358703aa05d5d7315900fe1d054c2817ddc (patch) | |
| tree | f2403e29f3aded0caf7a2434ea50dd507f6545e2 /Materials_science_and_engineering_an_introduction/CH12.ipynb | |
| parent | c6f0d6aeb95beaf41e4b679e78bb42c4ffe45a40 (diff) | |
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diff --git a/Materials_science_and_engineering_an_introduction/CH12.ipynb b/Materials_science_and_engineering_an_introduction/CH12.ipynb new file mode 100644 index 00000000..ee793447 --- /dev/null +++ b/Materials_science_and_engineering_an_introduction/CH12.ipynb @@ -0,0 +1,202 @@ +{
+ "metadata": {
+ "name": "CH12"
+ },
+ "nbformat": 3,
+ "nbformat_minor": 0,
+ "worksheets": [
+ {
+ "cells": [
+ {
+ "cell_type": "heading",
+ "level": 1,
+ "metadata": {},
+ "source": [
+ "Chapter 12: Structure and Properties of Ceramics"
+ ]
+ },
+ {
+ "cell_type": "heading",
+ "level": 3,
+ "metadata": {},
+ "source": [
+ "Example 12.1 Page no 418"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "#Computation of Minimum Caion-to-Anion Radius Ratio forCo-ordination No. of 3\n",
+ "\n",
+ "#For equilateral triangle after joining centres of the atoms Angle = 30\n",
+ "a=30\n",
+ "\n",
+ "#Calculation\n",
+ "import math\n",
+ "ratio=(1-math.cos(a*math.pi/180.0))/math.cos(a*math.pi/180.0)\n",
+ "\n",
+ "#Result\n",
+ "print\"Cation to anion raio is \",round(ratio,3)\n",
+ "\n"
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "Cation to anion raio is 0.155\n"
+ ]
+ }
+ ],
+ "prompt_number": 5
+ },
+ {
+ "cell_type": "heading",
+ "level": 3,
+ "metadata": {},
+ "source": [
+ "Example 12.2 Page no 423"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "#Ceramic Crystal structure prediction\n",
+ "\n",
+ "#Given\n",
+ "r_Fe=0.077 # in nm Radius of iron cation Fe++\n",
+ "r_O=0.140 #in nm Radius of Oxygen anion O--\n",
+ "\n",
+ "#Calculation\n",
+ "ratio=r_Fe/r_O\n",
+ "\n",
+ "#Result\n",
+ "print\"Ratio is \",ratio\n",
+ "if 0.414<ratio<0.732: \n",
+ " print\"Co-ordinaton no. is 6\"\n",
+ " print\"Structure is Rock Salt type\"\n",
+ "else:\n",
+ " print \"Coordination no is not 6\"\n",
+ " \n"
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "Ratio is 0.55\n",
+ "Co-ordinaton no. is 6\n",
+ "Structure is Rock Salt type\n"
+ ]
+ }
+ ],
+ "prompt_number": 16
+ },
+ {
+ "cell_type": "heading",
+ "level": 3,
+ "metadata": {},
+ "source": [
+ "Example 12.3 Page no 424"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "#Theoretical Density Determination for NaCl\n",
+ "\n",
+ "#Given\n",
+ "A_Na=22.99 # in g/mol\n",
+ "A_Cl=35.45 #in g/mol\n",
+ "r_Na=0.102*10**-7 #in cm Radius of Na+ ion\n",
+ "r_Cl=0.181*10**-7 #in cm Radius of Cl- ion\n",
+ "Na=6.023*10**23 #Avogadro number\n",
+ "\n",
+ "#Calculation\n",
+ "a=2*(r_Na+r_Cl)\n",
+ "V=a**3\n",
+ "n=4 #For FCC, no. of atoms are 4 per crystal\n",
+ "density=n*(A_Na+A_Cl)/(V*Na)\n",
+ "\n",
+ "#Result\n",
+ "print\"Density is \",round(density,2),\"gm/cm**3\"\n",
+ "\n"
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "Density is 2.14 gm/cm**3\n"
+ ]
+ }
+ ],
+ "prompt_number": 18
+ },
+ {
+ "cell_type": "heading",
+ "level": 3,
+ "metadata": {},
+ "source": [
+ "Example 12.4 Page no 436"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "#Computation of the No. of Schottky Defects in KCl\n",
+ "\n",
+ "#Given\n",
+ "Na=6.023*10**23 #Avogadro number\n",
+ "density=1.955 #in g/cm**3\n",
+ "A_K=39.1 #in g/mol\n",
+ "A_Cl=35.45 #in g/mol\n",
+ "\n",
+ "#calculation\n",
+ "import math\n",
+ "N=Na*density*10**6/(A_K+A_Cl)\n",
+ "Qs=2.6 # in eV\n",
+ "k=8.62*10**-5 # in eV/K Boltzmann Constant\n",
+ "T=500.0+273.0 # in K\n",
+ "Ns=N*math.exp(-Qs/(2*k*T))\n",
+ "\n",
+ "#result\n",
+ "print\"No. of Schottky Defects are \",round(Ns,-17),\"/m**3\"\n",
+ "\n"
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "No. of Schottky Defects are 5.31e+19 /m**3\n"
+ ]
+ }
+ ],
+ "prompt_number": 26
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [],
+ "language": "python",
+ "metadata": {},
+ "outputs": []
+ }
+ ],
+ "metadata": {}
+ }
+ ]
+}
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