Revised list of TBCs

1 files changed, 0 insertions, 217 deletions

diff --git a/Machine_Design_by_U.C._Jindal/Ch30_1.ipynb b/Machine_Design_by_U.C._Jindal/Ch30_1.ipynb
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--- a/Machine_Design_by_U.C._Jindal/Ch30_1.ipynb
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-{
- "cells": [
-  {
-   "cell_type": "markdown",
-   "metadata": {},
-   "source": [
-    "# Ch:30 Chain drive"
-   ]
-  },
-  {
-   "cell_type": "markdown",
-   "metadata": {},
-   "source": [
-    "## exa 30-1 - Page 778"
-   ]
-  },
-  {
-   "cell_type": "code",
-   "execution_count": 3,
-   "metadata": {
-    "collapsed": false
-   },
-   "outputs": [
-    {
-     "name": "stdout",
-     "output_type": "stream",
-     "text": [
-      "C is 300.00 mm \n"
-     ]
-    }
-   ],
-   "source": [
-    "from __future__ import division\n",
-    "from math import sqrt, pi\n",
-    "n1=17#\n",
-    "n2=51#\n",
-    "C=300#\n",
-    "p=9.52#\n",
-    "Ln=(2*C/p)+((n1+n2)/2)+((((n2-n1)/(2*pi))**2)*(p/C))#\n",
-    "x=(Ln-((n2+n1)/(2)))**2#\n",
-    "y=8*(((n2-n1)/(2*pi))**2)#\n",
-    "z=Ln-((n1+n2)/2)#\n",
-    "C=(p/4)*(z+(sqrt(x-y)))\n",
-    "\n",
-    "\n",
-    "  # printing data in scilab o/p window\n",
-    "print \"C is %0.2f mm \"%(C)#\n",
-    "  "
-   ]
-  },
-  {
-   "cell_type": "markdown",
-   "metadata": {},
-   "source": [
-    "## exa 30-2 - Page 778"
-   ]
-  },
-  {
-   "cell_type": "code",
-   "execution_count": 4,
-   "metadata": {
-    "collapsed": false
-   },
-   "outputs": [
-    {
-     "name": "stdout",
-     "output_type": "stream",
-     "text": [
-      "Ln is 80  \n"
-     ]
-    }
-   ],
-   "source": [
-    "from math import tan\n",
-    "G=4#\n",
-    "n1=17#\n",
-    "n2=n1*G#\n",
-    "N1=2300#\n",
-    "Kc=1.2# #from table 30-2\n",
-    "p=12.7# #fom table 30-1\n",
-    "D1=p*n1#\n",
-    "D2=p*n2#\n",
-    "phi=2*10.6#\n",
-    "x=tan(phi/2)# #phi/2 = 10.6deg, from table 30-3\n",
-    "Da1=(p/x)+(0.6*p)#\n",
-    "Da2=(p/x*4)+(0.6*p)#\n",
-    "Cmin=Kc*((Da1+Da2)/2)#\n",
-    "Ln1=(2*Cmin/p)+((n1+n2)/2)+((((n2-n1)/(2*pi))**2)*(p/Cmin))#\n",
-    "Ln1=80#\n",
-    "print \"Ln is %0.0f  \"%(Ln1)#"
-   ]
-  },
-  {
-   "cell_type": "markdown",
-   "metadata": {},
-   "source": [
-    "## exa 30-3 - Page 779"
-   ]
-  },
-  {
-   "cell_type": "code",
-   "execution_count": 5,
-   "metadata": {
-    "collapsed": false
-   },
-   "outputs": [
-    {
-     "name": "stdout",
-     "output_type": "stream",
-     "text": [
-      " Pc is 2.56 KW  \n",
-      "\n",
-      " V is 3.332 m/s  \n",
-      "\n",
-      " T is 767.6 N  \n",
-      "\n",
-      " FOS is 13.94   \n",
-      "\n",
-      " L is 1254.01 mm  \n"
-     ]
-    }
-   ],
-   "source": [
-    "from math import sqrt, pi\n",
-    "N1=1000#\n",
-    "N2=500#\n",
-    "P=2.03*10**3# #from table 30-8\n",
-    "K1=1.26#\n",
-    "Ks=1#\n",
-    "#let Pc be the power transmitting capacity of the chain\n",
-    "Pc=P*K1/Ks#\n",
-    "p=9.52#\n",
-    "n1=21#\n",
-    "n2=42#\n",
-    "V=n1*p*N1/(60*10**3)#\n",
-    "#Let the chain tension be T\n",
-    "T=Pc/V#\n",
-    "#Let the breaking load be BL\n",
-    "BL=10700#\n",
-    "FOS=BL/T#\n",
-    "C=50*p#\n",
-    "Ln=(2*C/p)+((n1+n2)/2)+((((n2-n1)/(2*pi))**2)*(p/C))#\n",
-    "L=Ln*p#\n",
-    "Pc=Pc*10**-3#\n",
-    "print \" Pc is %0.2f KW  \"%(Pc)#\n",
-    "print \"\\n V is %0.3f m/s  \"%(V)#\n",
-    "print \"\\n T is %0.1f N  \"%(T)#\n",
-    "print \"\\n FOS is %0.2f   \"%(FOS)#\n",
-    "print \"\\n L is %0.2f mm  \"%(L)#\n",
-    "\n",
-    "#The difference in the value of L and T is due to rounding-off the values."
-   ]
-  },
-  {
-   "cell_type": "markdown",
-   "metadata": {},
-   "source": [
-    "## exa 30-5 - Page 780"
-   ]
-  },
-  {
-   "cell_type": "code",
-   "execution_count": 6,
-   "metadata": {
-    "collapsed": false
-   },
-   "outputs": [
-    {
-     "name": "stdout",
-     "output_type": "stream",
-     "text": [
-      "L is 1678.25 mm  \n"
-     ]
-    }
-   ],
-   "source": [
-    "from math import sqrt, pi\n",
-    "G=2#\n",
-    "P=5000#\n",
-    "Ks=1.7#\n",
-    "Pd=P*Ks#\n",
-    "K2=1.7#\n",
-    "p=15.88#\n",
-    "n1=17#\n",
-    "n2=n1*G#\n",
-    "D1=n1*p#\n",
-    "D2=n2*p#\n",
-    "C=40*p#\n",
-    "Ln=(2*C/p)+((n1+n2)/2)+((((n2-n1)/(2*pi))**2)*(p/C))#\n",
-    "L=Ln*p#\n",
-    "print \"L is %0.2f mm  \"%(L)#\n",
-    "#The difference in the value of L is due to rounding-off the values."
-   ]
-  }
- ],
- "metadata": {
-  "kernelspec": {
-   "display_name": "Python 2",
-   "language": "python",
-   "name": "python2"
-  },
-  "language_info": {
-   "codemirror_mode": {
-    "name": "ipython",
-    "version": 2
-   },
-   "file_extension": ".py",
-   "mimetype": "text/x-python",
-   "name": "python",
-   "nbconvert_exporter": "python",
-   "pygments_lexer": "ipython2",
-   "version": "2.7.9"
-  }
- },
- "nbformat": 4,
- "nbformat_minor": 0
-}