Added(A)/Deleted(D) following books

 A  Electronics_Engineering_by_P._Raja/chapter_1_2.ipynb
A  Electronics_Engineering_by_P._Raja/chapter_2_2.ipynb
A  Electronics_Engineering_by_P._Raja/chapter_3_2.ipynb
A  Electronics_Engineering_by_P._Raja/chapter_4_2.ipynb
A  Electronics_Engineering_by_P._Raja/chapter_5_2.ipynb
A  Electronics_Engineering_by_P._Raja/chapter_6_2.ipynb
A  Electronics_Engineering_by_P._Raja/chapter_7_2.ipynb
A  Electronics_Engineering_by_P._Raja/chapter_8_2.ipynb
A  Electronics_Engineering_by_P._Raja/chapter_9_2.ipynb
A  Electronics_Engineering_by_P._Raja/screenshots/7_2.png
A  Electronics_Engineering_by_P._Raja/screenshots/snap-3_2.png
A  Electronics_Engineering_by_P._Raja/screenshots/snap-6_2.png
A  Machine_Design_by_U.C._Jindal/Ch10.ipynb
A  Machine_Design_by_U.C._Jindal/Ch11.ipynb
A  Machine_Design_by_U.C._Jindal/Ch12.ipynb
A  Machine_Design_by_U.C._Jindal/Ch13.ipynb
A  Machine_Design_by_U.C._Jindal/Ch14.ipynb
A  Machine_Design_by_U.C._Jindal/Ch15.ipynb
A  Machine_Design_by_U.C._Jindal/Ch16.ipynb
A  Machine_Design_by_U.C._Jindal/Ch17.ipynb
A  Machine_Design_by_U.C._Jindal/Ch18.ipynb
A  Machine_Design_by_U.C._Jindal/Ch19.ipynb
A  Machine_Design_by_U.C._Jindal/Ch20.ipynb
A  Machine_Design_by_U.C._Jindal/Ch21.ipynb
A  Machine_Design_by_U.C._Jindal/Ch22.ipynb
A  Machine_Design_by_U.C._Jindal/Ch23.ipynb
A  Machine_Design_by_U.C._Jindal/Ch24.ipynb
A  Machine_Design_by_U.C._Jindal/Ch25.ipynb
A  Machine_Design_by_U.C._Jindal/Ch26.ipynb
A  Machine_Design_by_U.C._Jindal/Ch27.ipynb
A  Machine_Design_by_U.C._Jindal/Ch28.ipynb
A  Machine_Design_by_U.C._Jindal/Ch29.ipynb
A  Machine_Design_by_U.C._Jindal/Ch3.ipynb
A  Machine_Design_by_U.C._Jindal/Ch30.ipynb
A  Machine_Design_by_U.C._Jindal/Ch31.ipynb
A  Machine_Design_by_U.C._Jindal/Ch4.ipynb
A  Machine_Design_by_U.C._Jindal/Ch5.ipynb
A  Machine_Design_by_U.C._Jindal/Ch6.ipynb
A  Machine_Design_by_U.C._Jindal/Ch7.ipynb
A  Machine_Design_by_U.C._Jindal/Ch8.ipynb
A  Machine_Design_by_U.C._Jindal/Ch9.ipynb
A  Machine_Design_by_U.C._Jindal/screenshots/Chapter-3stressgraph.png
A  Machine_Design_by_U.C._Jindal/screenshots/Chapter-_8AdditionalLoad.png
A  Machine_Design_by_U.C._Jindal/screenshots/Chapter11_-_strengthofrevet.png
A  Solid_State_Devices_and_Circuits___by_V._Chaudhary_and_H._K._Maity/Chapter02_2.ipynb
A  Solid_State_Devices_and_Circuits___by_V._Chaudhary_and_H._K._Maity/Chapter03_2.ipynb
A  Solid_State_Devices_and_Circuits___by_V._Chaudhary_and_H._K._Maity/Chapter04_2.ipynb
A  Solid_State_Devices_and_Circuits___by_V._Chaudhary_and_H._K._Maity/Chapter05_2.ipynb
A  Solid_State_Devices_and_Circuits___by_V._Chaudhary_and_H._K._Maity/Chapter06_2.ipynb
A  Solid_State_Devices_and_Circuits___by_V._Chaudhary_and_H._K._Maity/Chapter07_2.ipynb
A  Solid_State_Devices_and_Circuits___by_V._Chaudhary_and_H._K._Maity/Chapter08_2.ipynb
A  Solid_State_Devices_and_Circuits___by_V._Chaudhary_and_H._K._Maity/Chapter09_2.ipynb
A  Solid_State_Devices_and_Circuits___by_V._Chaudhary_and_H._K._Maity/Chapter10_2.ipynb
A  Solid_State_Devices_and_Circuits___by_V._Chaudhary_and_H._K._Maity/Chapter11_2.ipynb
A  Solid_State_Devices_and_Circuits___by_V._Chaudhary_and_H._K._Maity/screenshots/Screenshot_3.1.py.PNG
A  Solid_State_Devices_and_Circuits___by_V._Chaudhary_and_H._K._Maity/screenshots/Screenshot_6.1.py.PNG
A  Solid_State_Devices_and_Circuits___by_V._Chaudhary_and_H._K._Maity/screenshots/Screenshot_6.2.py.PNG
A  sample_notebooks/PriyankaSaini/Chapter3.ipynb
A  sample_notebooks/ebbygeorge/Chapter01.ipynb

1 files changed, 438 insertions, 0 deletions

diff --git a/Machine_Design_by_U.C._Jindal/Ch23.ipynb b/Machine_Design_by_U.C._Jindal/Ch23.ipynb
new file mode 100644
index 00000000..0ff4eb7a
--- /dev/null
+++ b/Machine_Design_by_U.C._Jindal/Ch23.ipynb
@@ -0,0 +1,438 @@
+{
+ "metadata": {
+  "name": "",
+  "signature": "sha256:75a895f6b6e2b52911a88eac6dae9689200eafdf77449669257c302ec104ee3c"
+ },
+ "nbformat": 3,
+ "nbformat_minor": 0,
+ "worksheets": [
+  {
+   "cells": [
+    {
+     "cell_type": "heading",
+     "level": 1,
+     "metadata": {},
+     "source": [
+      "Ch:23 Brakes"
+     ]
+    },
+    {
+     "cell_type": "heading",
+     "level": 2,
+     "metadata": {},
+     "source": [
+      "exa 23-1 - Page 618"
+     ]
+    },
+    {
+     "cell_type": "code",
+     "collapsed": false,
+     "input": [
+      "from __future__ import division\n",
+      "from math import asin, pi\n",
+      "W=20e3#\n",
+      "m=W/9.81#\n",
+      "#diameter of brake drum\n",
+      "Db=0.6#\n",
+      "p=1#\n",
+      "Vi=1#\n",
+      "Vf=0#\n",
+      "D=1#\n",
+      "R=0.5#\n",
+      "wi=Vi/R#\n",
+      "wf=0#\n",
+      "w=1#\n",
+      "Vav=0.5#\n",
+      "S=2#\n",
+      "t=S/Vav#\n",
+      "#angle turned by by hoist drum=theta\n",
+      "theta=0.5*wi*t#\n",
+      "K_E=0.5*m*Vi**2#\n",
+      "P_E=2*W#\n",
+      "T_E=K_E+P_E#\n",
+      "T=T_E/theta#\n",
+      "P=wi*T*10**-3#\n",
+      "Rb=Db/2#\n",
+      "Ft=0.5*T*p/Rb#\n",
+      "u=0.35#\n",
+      "N=Ft/u#\n",
+      "#contact area of brake lining=A\n",
+      "A=N/p#\n",
+      "b=0.3*Db#\n",
+      "L=A*10**-6/(b)#\n",
+      "#angle subtended at brake drum centre=theta2\n",
+      "theta2=2*(asin(L/Db))#\n",
+      "theta2=theta2*180/pi# # converting radian to degree\n",
+      "print \"T is %0.1f Nm \"%(T)#\n",
+      "print \"\\nP is %0.4f kW \"%(P)#\n",
+      "print \"\\nb is %0.2f m \"%(b)#\n",
+      "print \"\\nL is %0.3f m \"%(L)#\n",
+      "print \"\\ntheta2 is %0.0f deg \"%(theta2)#\n",
+      " "
+     ],
+     "language": "python",
+     "metadata": {},
+     "outputs": [
+      {
+       "output_type": "stream",
+       "stream": "stdout",
+       "text": [
+        "T is 10254.8 Nm \n",
+        "\n",
+        "P is 20.5097 kW \n",
+        "\n",
+        "b is 0.18 m \n",
+        "\n",
+        "L is 0.271 m \n",
+        "\n",
+        "theta2 is 54 deg \n"
+       ]
+      }
+     ],
+     "prompt_number": 9
+    },
+    {
+     "cell_type": "heading",
+     "level": 2,
+     "metadata": {},
+     "source": [
+      "exa 23-2 - Page 618"
+     ]
+    },
+    {
+     "cell_type": "code",
+     "collapsed": false,
+     "input": [
+      "from math import exp\n",
+      "b=80#\n",
+      "t=2#\n",
+      "theta=225*pi/180#\n",
+      "u=0.22#\n",
+      "#F1/F2=e**(u*theta)\n",
+      "#let F1/F2=x#\n",
+      "x=exp(u*theta)#\n",
+      "#maximum tensile stress in steel tape is siga\n",
+      "siga=60#\n",
+      "A=b*t#\n",
+      "F1=siga*A#\n",
+      "F2=F1/x#\n",
+      "r=0.2#\n",
+      "T=(F1-F2)*r#\n",
+      "OA=30#\n",
+      "OB=100#\n",
+      "OC=350#\n",
+      "P=((F2*OB)+(F1*OA))/OC#\n",
+      "OA=F2*OB/F1#\n",
+      "print \"F1 is %0.0f N \"%(F1)#\n",
+      "print \"\\nF2 is %0.1f N \"%(F2)#\n",
+      "print \"\\nT is %0.2f Nm \"%(T)#\n",
+      "print \"\\nOA is %0.2f mm \"%(OA)#"
+     ],
+     "language": "python",
+     "metadata": {},
+     "outputs": [
+      {
+       "output_type": "stream",
+       "stream": "stdout",
+       "text": [
+        "F1 is 9600 N \n",
+        "\n",
+        "F2 is 4046.4 N \n",
+        "\n",
+        "T is 1110.72 Nm \n",
+        "\n",
+        "OA is 42.15 mm \n"
+       ]
+      }
+     ],
+     "prompt_number": 10
+    },
+    {
+     "cell_type": "heading",
+     "level": 2,
+     "metadata": {},
+     "source": [
+      "exa 23-3 - Page 619"
+     ]
+    },
+    {
+     "cell_type": "code",
+     "collapsed": false,
+     "input": [
+      "from math import sin\n",
+      "theta=pi/3#\n",
+      "r=160#\n",
+      "u=0.3#\n",
+      "pmax=0.9#\n",
+      "b=40#\n",
+      "R=(4*r*sin(theta))/((2*theta)+sin(2*theta))#\n",
+      "#frictional torque is T\n",
+      "T=2*u*pmax*b*(r**2)*sin(theta)#\n",
+      "T=2*T*10**-3#\n",
+      "Rx=0.5*pmax*b*r*((2*theta)+(sin(2*theta)))*10**-3#\n",
+      "Ry=u*Rx#\n",
+      "print \"T is %0.2f Nmm \"%(T)#\n",
+      "print \"\\nR is %0.3f mm \"%(R)#\n",
+      "print \"\\nRx is %0.3f kN \"%(Rx)#\n",
+      "print \"\\nRy is %0.2f kN \"%(Ry)#"
+     ],
+     "language": "python",
+     "metadata": {},
+     "outputs": [
+      {
+       "output_type": "stream",
+       "stream": "stdout",
+       "text": [
+        "T is 957.75 Nmm \n",
+        "\n",
+        "R is 187.222 mm \n",
+        "\n",
+        "Rx is 8.526 kN \n",
+        "\n",
+        "Ry is 2.56 kN \n"
+       ]
+      }
+     ],
+     "prompt_number": 11
+    },
+    {
+     "cell_type": "heading",
+     "level": 2,
+     "metadata": {},
+     "source": [
+      "exa 23-4 - Page 620"
+     ]
+    },
+    {
+     "cell_type": "code",
+     "collapsed": false,
+     "input": [
+      "from math import sin, cos, pi, sqrt\n",
+      "d=320#\n",
+      "r=d/2#\n",
+      "b=50#\n",
+      "u=0.3#\n",
+      "pmax=1#\n",
+      "c=115*2#\n",
+      "# From to fig. 23-9, distance OA=R is calculated.\n",
+      "R=sqrt(115**2+66.4**2)#\n",
+      "C=115*2#\n",
+      "theta1=0#\n",
+      "theta2=120*pi/180#\n",
+      "theta0=120*pi/180#\n",
+      "thetamax=pi/2#\n",
+      "Tr=u*pmax*b*r**2*(cos(theta1)-cos(theta2))/sin(thetamax)*10**-3#\n",
+      "#the notation 'r' is used for moments of right hand shoe, similarly 'l' for the left shoe.\n",
+      "Mfr=u*pmax*b*r*(4*r*(cos(theta1)-cos(theta2))+(R*(cos(2*theta1)-cos(2*theta2))))/(4*sin(thetamax))*10**-3#\n",
+      "Mpr=pmax*b*r*R*((2*theta0)-(sin(2*theta2)-(sin(theta1))))/(4*sin(thetamax))*10**-3#\n",
+      "F=(Mpr-Mfr)/c*10**3#\n",
+      "#Mpl+Mfl=F*c#\n",
+      "x=F*c*10**-3#\n",
+      "y=(Mpr/pmax)+(Mfr/pmax)#\n",
+      "pmax2=x/y#\n",
+      "Tl=pmax2*Tr#\n",
+      "Mpl=pmax2*Mpr#\n",
+      "Mfl=pmax2*Mfr#\n",
+      "T=Tl+Tr#\n",
+      "print \"Tr is %0.0f Nm \"%(Tr)#\n",
+      "print \"\\nMf is %0.2f Nm \"%(Mfr)#\n",
+      "print \"\\nMp is %0.2f Nm \"%(Mpr)#\n",
+      "print \"\\nTl is %0.1f Nm \"%(Tl)# \n",
+      "print \"\\nMfl is %0.2f Nm \"%(Mfl)#\n",
+      "print \"\\nMpl is %0.2f Nm \"%(Mpl)#\n",
+      "print \"\\nF is %0.1f N \"%(F)#\n",
+      "print \"\\nT is %0.1f Nm \"%(T)#\n",
+      "  \n",
+      "  #The difference in the answers are due to rounding-off of values.\n",
+      "  "
+     ],
+     "language": "python",
+     "metadata": {},
+     "outputs": [
+      {
+       "output_type": "stream",
+       "stream": "stdout",
+       "text": [
+        "Tr is 576 Nm \n",
+        "\n",
+        "Mf is 695.51 Nm \n",
+        "\n",
+        "Mp is 1342.49 Nm \n",
+        "\n",
+        "Tl is 182.9 Nm \n",
+        "\n",
+        "Mfl is 220.79 Nm \n",
+        "\n",
+        "Mpl is 426.18 Nm \n",
+        "\n",
+        "F is 2812.9 N \n",
+        "\n",
+        "T is 758.9 Nm \n"
+       ]
+      }
+     ],
+     "prompt_number": 12
+    },
+    {
+     "cell_type": "heading",
+     "level": 2,
+     "metadata": {},
+     "source": [
+      "exa 23-5 - Page 621"
+     ]
+    },
+    {
+     "cell_type": "code",
+     "collapsed": false,
+     "input": [
+      "m=1100#\n",
+      "V=65*5/18#\n",
+      "t=4#\n",
+      "r=0.22#\n",
+      "mb=12#\n",
+      "C=460#\n",
+      "S=0.5*V*t#\n",
+      "#Total kinetic energy TE=K.E(vehicle)+K.E(rotating parts).\n",
+      "TE=((0.5*m*(V**2))+(0.1*0.5*m*(V**2)))#\n",
+      "E=TE/4#\n",
+      "w=V/r#\n",
+      "theta=S/r#\n",
+      "T=E/theta#\n",
+      "delT=E/(mb*C)#\n",
+      "print \"S is %0.2f m \"%(S)#\n",
+      "print \"\\nE is %0.2f Nm \"%(E)#\n",
+      "print \"\\nT is %0.2f Nm \"%(T)#\n",
+      "print \"\\ndelT is %0.2f \"%(delT)#\n",
+      "  \n",
+      "#The difference in the answers are due to rounding-off of values."
+     ],
+     "language": "python",
+     "metadata": {},
+     "outputs": [
+      {
+       "output_type": "stream",
+       "stream": "stdout",
+       "text": [
+        "S is 36.11 m \n",
+        "\n",
+        "E is 49307.97 Nm \n",
+        "\n",
+        "T is 300.40 Nm \n",
+        "\n",
+        "delT is 8.93 \n"
+       ]
+      }
+     ],
+     "prompt_number": 13
+    },
+    {
+     "cell_type": "heading",
+     "level": 2,
+     "metadata": {},
+     "source": [
+      "exa 23-6 - Page 621"
+     ]
+    },
+    {
+     "cell_type": "code",
+     "collapsed": false,
+     "input": [
+      "T=35000#\n",
+      "u=0.4#\n",
+      "p=0.7#\n",
+      "r=200#\n",
+      "N=T/(u*r)\n",
+      "b=sqrt(N/p)#\n",
+      "l=b#\n",
+      "#2theta = theta2\n",
+      "theta2=2*asin(l/(2*r))#\n",
+      "F=u*N#\n",
+      "P=((250*N)-(u*N*80))/550#\n",
+      "Ry=N-P#\n",
+      "Rx=u*N#\n",
+      "R=sqrt(Rx**2+Ry**2)#\n",
+      "w=2*pi*100/60#\n",
+      "# Rate of heat generated is Q\n",
+      "Q=u*N*w*r/1000#\n",
+      "print \"N is %0.1f N \"%(N)#\n",
+      "print \"\\nb is %0.0f mm \"%(b)#\n",
+      "print \"\\nP is %0.1f N \"%(P)#\n",
+      "print \"\\nR is %0.2f N \"%(R)#\n",
+      "print \"\\nQ is %0.2f J/s \"%(Q)#\n",
+      "\n",
+      "#The answer to Rate of heat generated 'Q' is calculated incorrectly in the book."
+     ],
+     "language": "python",
+     "metadata": {},
+     "outputs": [
+      {
+       "output_type": "stream",
+       "stream": "stdout",
+       "text": [
+        "N is 437.5 N \n",
+        "\n",
+        "b is 25 mm \n",
+        "\n",
+        "P is 173.4 N \n",
+        "\n",
+        "R is 316.81 N \n",
+        "\n",
+        "Q is 366.52 J/s \n"
+       ]
+      }
+     ],
+     "prompt_number": 14
+    },
+    {
+     "cell_type": "heading",
+     "level": 2,
+     "metadata": {},
+     "source": [
+      "exa 23-7 - Page 622"
+     ]
+    },
+    {
+     "cell_type": "code",
+     "collapsed": false,
+     "input": [
+      "Vi=20*5/18#\n",
+      "Vf=0#\n",
+      "m=80#\n",
+      "pmax=1#\n",
+      "u=0.1#\n",
+      "S=50#\n",
+      "KE=0.5*m*Vi**2#\n",
+      "N=KE/(u*S*2)#\n",
+      "t=sqrt(N/(pmax*3))#\n",
+      "b=3*t#\n",
+      "print \"KE is %0.1f Nm \"%(KE)#\n",
+      "print \"\\nN is %0.2f N \"%(N)#\n",
+      "print \"\\nt is %0.1f mm \"%(t)#\n",
+      "print \"\\nb is %0.1f mm \"%(b)#\n",
+      "\n",
+      "#The difference in the answers are due to rounding-off of values."
+     ],
+     "language": "python",
+     "metadata": {},
+     "outputs": [
+      {
+       "output_type": "stream",
+       "stream": "stdout",
+       "text": [
+        "KE is 1234.6 Nm \n",
+        "\n",
+        "N is 123.46 N \n",
+        "\n",
+        "t is 6.4 mm \n",
+        "\n",
+        "b is 19.2 mm \n"
+       ]
+      }
+     ],
+     "prompt_number": 15
+    }
+   ],
+   "metadata": {}
+  }
+ ]
+}
\ No newline at end of file