Added(A)/Deleted(D) following books

 A  Electrical_&_Electronic_Systems_by_Neil_Storey/Chapter11.ipynb
A  Electrical_&_Electronic_Systems_by_Neil_Storey/Chapter12.ipynb
A  Electrical_&_Electronic_Systems_by_Neil_Storey/Chapter13.ipynb
A  Electrical_&_Electronic_Systems_by_Neil_Storey/Chapter14.ipynb
A  Electrical_&_Electronic_Systems_by_Neil_Storey/Chapter15.ipynb
A  Electrical_&_Electronic_Systems_by_Neil_Storey/Chapter16.ipynb
A  Electrical_&_Electronic_Systems_by_Neil_Storey/Chapter18.ipynb
A  Electrical_&_Electronic_Systems_by_Neil_Storey/Chapter19.ipynb
A  Electrical_&_Electronic_Systems_by_Neil_Storey/Chapter2.ipynb
A  Electrical_&_Electronic_Systems_by_Neil_Storey/Chapter20.ipynb
A  Electrical_&_Electronic_Systems_by_Neil_Storey/Chapter21.ipynb
A  Electrical_&_Electronic_Systems_by_Neil_Storey/Chapter22.ipynb
A  Electrical_&_Electronic_Systems_by_Neil_Storey/Chapter23.ipynb
A  Electrical_&_Electronic_Systems_by_Neil_Storey/Chapter5.ipynb
A  Electrical_&_Electronic_Systems_by_Neil_Storey/Chapter6.ipynb
A  Electrical_&_Electronic_Systems_by_Neil_Storey/Chapter8.ipynb
A  Electrical_&_Electronic_Systems_by_Neil_Storey/Chapter9.ipynb
A  Electrical_&_Electronic_Systems_by_Neil_Storey/screenshots/pic1.png
A  Electrical_&_Electronic_Systems_by_Neil_Storey/screenshots/pic2.png
A  Electrical_&_Electronic_Systems_by_Neil_Storey/screenshots/pic3.png
A  MECHANICS_OF_SOLIDS_by_S.S._Bhavikatti/Chapter10_67BmtXx.ipynb
A  MECHANICS_OF_SOLIDS_by_S.S._Bhavikatti/Chapter10_LGPoR7F.ipynb
A  MECHANICS_OF_SOLIDS_by_S.S._Bhavikatti/Chapter10_PDCS2qh.ipynb
A  MECHANICS_OF_SOLIDS_by_S.S._Bhavikatti/Chapter10_lNjLAte.ipynb
A  MECHANICS_OF_SOLIDS_by_S.S._Bhavikatti/Chapter10_n5s4jXl.ipynb
A  MECHANICS_OF_SOLIDS_by_S.S._Bhavikatti/Chapter10_npy5vv0.ipynb
A  MECHANICS_OF_SOLIDS_by_S.S._Bhavikatti/Chapter10_pjpRgex.ipynb
A  MECHANICS_OF_SOLIDS_by_S.S._Bhavikatti/Chapter11_IE4byFL.ipynb
A  MECHANICS_OF_SOLIDS_by_S.S._Bhavikatti/Chapter11_RAQoou9.ipynb
A  MECHANICS_OF_SOLIDS_by_S.S._Bhavikatti/Chapter11_VcicGy5.ipynb
A  MECHANICS_OF_SOLIDS_by_S.S._Bhavikatti/Chapter11_hoqMFBX.ipynb
A  MECHANICS_OF_SOLIDS_by_S.S._Bhavikatti/Chapter11_iBTGbp8.ipynb
A  MECHANICS_OF_SOLIDS_by_S.S._Bhavikatti/Chapter11_k1rTVhh.ipynb
A  MECHANICS_OF_SOLIDS_by_S.S._Bhavikatti/Chapter11_nGrFEGY.ipynb
A  MECHANICS_OF_SOLIDS_by_S.S._Bhavikatti/Chapter11_pfzLlc6.ipynb
A  MECHANICS_OF_SOLIDS_by_S.S._Bhavikatti/Chapter1_1FJHa67.ipynb
A  MECHANICS_OF_SOLIDS_by_S.S._Bhavikatti/Chapter1_2wryDDQ.ipynb
A  MECHANICS_OF_SOLIDS_by_S.S._Bhavikatti/Chapter1_BuZVTIP.ipynb
A  MECHANICS_OF_SOLIDS_by_S.S._Bhavikatti/Chapter1_UCsno1y.ipynb
A  MECHANICS_OF_SOLIDS_by_S.S._Bhavikatti/Chapter1_Yd7uN6t.ipynb
A  MECHANICS_OF_SOLIDS_by_S.S._Bhavikatti/Chapter1_bGP3Wsd.ipynb
A  MECHANICS_OF_SOLIDS_by_S.S._Bhavikatti/Chapter1_pFJzyF5.ipynb
A  MECHANICS_OF_SOLIDS_by_S.S._Bhavikatti/Chapter2_242icmu.ipynb
A  MECHANICS_OF_SOLIDS_by_S.S._Bhavikatti/Chapter2_Rcy1wii.ipynb
A  MECHANICS_OF_SOLIDS_by_S.S._Bhavikatti/Chapter2_TvxYpxT.ipynb
A  MECHANICS_OF_SOLIDS_by_S.S._Bhavikatti/Chapter2_VU0Vuul.ipynb
A  MECHANICS_OF_SOLIDS_by_S.S._Bhavikatti/Chapter2_Xiz19Ms.ipynb
A  MECHANICS_OF_SOLIDS_by_S.S._Bhavikatti/Chapter2_rAG8C10.ipynb
A  MECHANICS_OF_SOLIDS_by_S.S._Bhavikatti/Chapter2_xUN650b.ipynb
A  MECHANICS_OF_SOLIDS_by_S.S._Bhavikatti/Chapter3_0WKL8dM.ipynb
A  MECHANICS_OF_SOLIDS_by_S.S._Bhavikatti/Chapter3_BsRbQCe.ipynb
A  MECHANICS_OF_SOLIDS_by_S.S._Bhavikatti/Chapter3_IF7BAbT.ipynb
A  MECHANICS_OF_SOLIDS_by_S.S._Bhavikatti/Chapter3_Qh2uphO.ipynb
A  MECHANICS_OF_SOLIDS_by_S.S._Bhavikatti/Chapter3_WS64jkH.ipynb
A  MECHANICS_OF_SOLIDS_by_S.S._Bhavikatti/Chapter3_aM1BqRM.ipynb
A  MECHANICS_OF_SOLIDS_by_S.S._Bhavikatti/Chapter3_tEQK8Lr.ipynb
A  MECHANICS_OF_SOLIDS_by_S.S._Bhavikatti/Chapter4_0E18xYL.ipynb
A  MECHANICS_OF_SOLIDS_by_S.S._Bhavikatti/Chapter4_4P7HQZZ.ipynb
A  MECHANICS_OF_SOLIDS_by_S.S._Bhavikatti/Chapter4_8GR2j3i.ipynb
A  MECHANICS_OF_SOLIDS_by_S.S._Bhavikatti/Chapter4_KE5ki12.ipynb
A  MECHANICS_OF_SOLIDS_by_S.S._Bhavikatti/Chapter4_LmrwpIC.ipynb
A  MECHANICS_OF_SOLIDS_by_S.S._Bhavikatti/Chapter4_ZuWrQKN.ipynb
A  MECHANICS_OF_SOLIDS_by_S.S._Bhavikatti/Chapter4_wUtoaip.ipynb
A  MECHANICS_OF_SOLIDS_by_S.S._Bhavikatti/Chapter5_0Ke5Vhq.ipynb
A  MECHANICS_OF_SOLIDS_by_S.S._Bhavikatti/Chapter5_23aeJMe.ipynb
A  MECHANICS_OF_SOLIDS_by_S.S._Bhavikatti/Chapter5_4a14Khd.ipynb
A  MECHANICS_OF_SOLIDS_by_S.S._Bhavikatti/Chapter5_eftppGy.ipynb
A  MECHANICS_OF_SOLIDS_by_S.S._Bhavikatti/Chapter5_jOQv5Ua.ipynb
A  MECHANICS_OF_SOLIDS_by_S.S._Bhavikatti/Chapter5_m75AW4e.ipynb
A  MECHANICS_OF_SOLIDS_by_S.S._Bhavikatti/Chapter5_mZ9916M.ipynb
A  MECHANICS_OF_SOLIDS_by_S.S._Bhavikatti/Chapter6_2OboaPO.ipynb
A  MECHANICS_OF_SOLIDS_by_S.S._Bhavikatti/Chapter6_Cf1Ae70.ipynb
A  MECHANICS_OF_SOLIDS_by_S.S._Bhavikatti/Chapter6_IZI7GIy.ipynb
A  MECHANICS_OF_SOLIDS_by_S.S._Bhavikatti/Chapter6_TRm6El0.ipynb
A  MECHANICS_OF_SOLIDS_by_S.S._Bhavikatti/Chapter6_WfVJQIc.ipynb
A  MECHANICS_OF_SOLIDS_by_S.S._Bhavikatti/Chapter6_Z5dEk19.ipynb
A  MECHANICS_OF_SOLIDS_by_S.S._Bhavikatti/Chapter6_z9FlTqT.ipynb
A  MECHANICS_OF_SOLIDS_by_S.S._Bhavikatti/Chapter8_6BR5OK6.ipynb
A  MECHANICS_OF_SOLIDS_by_S.S._Bhavikatti/Chapter8_FV7Jgrb.ipynb
A  MECHANICS_OF_SOLIDS_by_S.S._Bhavikatti/Chapter8_Q79Sp1O.ipynb
A  MECHANICS_OF_SOLIDS_by_S.S._Bhavikatti/Chapter8_Qhj9HPA.ipynb
A  MECHANICS_OF_SOLIDS_by_S.S._Bhavikatti/Chapter8_fBoE3j3.ipynb
A  MECHANICS_OF_SOLIDS_by_S.S._Bhavikatti/Chapter8_mFOxHz2.ipynb
A  MECHANICS_OF_SOLIDS_by_S.S._Bhavikatti/Chapter8_zNY63b3.ipynb
A  MECHANICS_OF_SOLIDS_by_S.S._Bhavikatti/Chapter9_039FJN6.ipynb
A  MECHANICS_OF_SOLIDS_by_S.S._Bhavikatti/Chapter9_0AhnrOb.ipynb
A  MECHANICS_OF_SOLIDS_by_S.S._Bhavikatti/Chapter9_8K1gGKx.ipynb
A  MECHANICS_OF_SOLIDS_by_S.S._Bhavikatti/Chapter9_E4M5MRA.ipynb
A  MECHANICS_OF_SOLIDS_by_S.S._Bhavikatti/Chapter9_Ivqhz8T.ipynb
A  MECHANICS_OF_SOLIDS_by_S.S._Bhavikatti/Chapter9_ZSvbidk.ipynb
A  MECHANICS_OF_SOLIDS_by_S.S._Bhavikatti/Chapter9_u7ekl0N.ipynb
A  MECHANICS_OF_SOLIDS_by_S.S._Bhavikatti/screenshots/ch1_mHmqCLQ.png
A  MECHANICS_OF_SOLIDS_by_S.S._Bhavikatti/screenshots/ch_9_UicjBqW.png
A  MECHANICS_OF_SOLIDS_by_S.S._Bhavikatti/screenshots/ch_xk3ylh6.png
A  basic_electrical_engineering_by_nagsarkar_and_sukhija/Chapter2_eh02mMg.ipynb
A  basic_electrical_engineering_by_nagsarkar_and_sukhija/Chapter4_QnODdtI.ipynb
A  basic_electrical_engineering_by_nagsarkar_and_sukhija/Chapter5_IwMblyq.ipynb
A  basic_electrical_engineering_by_nagsarkar_and_sukhija/chapter11_nHcyQSN.ipynb
A  basic_electrical_engineering_by_nagsarkar_and_sukhija/chapter1_ivpTi0v.ipynb
A  basic_electrical_engineering_by_nagsarkar_and_sukhija/chapter3.ipynb
A  basic_electrical_engineering_by_nagsarkar_and_sukhija/chapter6_7Vcvq3x.ipynb
A  basic_electrical_engineering_by_nagsarkar_and_sukhija/chapter7_Iro5ijO.ipynb
A  basic_electrical_engineering_by_nagsarkar_and_sukhija/chapter8_dRxKPQv.ipynb
A  basic_electrical_engineering_by_nagsarkar_and_sukhija/chapter9_QP9exWK.ipynb
A  basic_electrical_engineering_by_nagsarkar_and_sukhija/screenshots/chap1_gG9EuuG.png
A  basic_electrical_engineering_by_nagsarkar_and_sukhija/screenshots/chapter2_RW9JXUw.png
A  basic_electrical_engineering_by_nagsarkar_and_sukhija/screenshots/chapter6_kNIRtlM.png

1 files changed, 466 insertions, 0 deletions

diff --git a/MECHANICS_OF_SOLIDS_by_S.S._Bhavikatti/Chapter9_u7ekl0N.ipynb b/MECHANICS_OF_SOLIDS_by_S.S._Bhavikatti/Chapter9_u7ekl0N.ipynb
new file mode 100644
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@@ -0,0 +1,466 @@
+{
+ "cells": [
+  {
+   "cell_type": "markdown",
+   "metadata": {},
+   "source": [
+    "# Chapter9-Beams"
+   ]
+  },
+  {
+   "cell_type": "markdown",
+   "metadata": {},
+   "source": [
+    "# example 9.1 page number 286"
+   ]
+  },
+  {
+   "cell_type": "code",
+   "execution_count": 1,
+   "metadata": {
+    "collapsed": false
+   },
+   "outputs": [
+    {
+     "name": "stdout",
+     "output_type": "stream",
+     "text": [
+      "RB= 18.8684 KN\n",
+      "RA= 29.989 KN\n",
+      "alpha= 25.21 °\n"
+     ]
+    }
+   ],
+   "source": [
+    "from math import pi,atan,sqrt,cos,sin\n",
+    "\n",
+    "#variable declaration\n",
+    "\n",
+    "#summation of all  horizontal forces is zero & vertical forces is zero.\n",
+    "P1=float(10)                                     #Vertical down Load at 4m from A,KN\n",
+    "P2=float(15)                                     #Inclined down Load at angle 30° at 6m from A,KN\n",
+    "P3=float(20)                                     #Inclined down Load at angle 45° at 10m from A,KN\n",
+    "theta2=30\n",
+    "theta3=45\n",
+    "#horizontal,vertical component at A  is Ha,Va respectively.\n",
+    "\n",
+    "Ha=P2*cos(theta2*pi/180)+P3*cos(theta3*pi/180)\n",
+    "Rb=(P1*4+P2*6*sin(theta2*pi/180)+P3*10*sin(theta3*pi/180))/12         #reaction at B point,KN\n",
+    "\n",
+    "print \"RB=\",round(Rb,4),\"KN\"\n",
+    "\n",
+    "#now vertical component\n",
+    "Va=P2*sin(theta2*pi/180)+P3*sin(theta3*pi/180)+P1-Rb\n",
+    "\n",
+    "Ra=sqrt(pow(Ha,2)+pow(Va,2))\n",
+    "\n",
+    "print \"RA=\",round(Ra,4),\"KN\"\n",
+    "\n",
+    "alpha=(atan(Va/Ha))*180/pi\n",
+    "\n",
+    "print \"alpha=\",round(alpha,2),\"°\""
+   ]
+  },
+  {
+   "cell_type": "markdown",
+   "metadata": {},
+   "source": [
+    "# example 9.2 page number 287"
+   ]
+  },
+  {
+   "cell_type": "code",
+   "execution_count": 2,
+   "metadata": {
+    "collapsed": false
+   },
+   "outputs": [
+    {
+     "name": "stdout",
+     "output_type": "stream",
+     "text": [
+      "RB= 100.4475 KN\n",
+      "RA= 87.0172 KN\n",
+      "alpha= 79.45 °\n"
+     ]
+    }
+   ],
+   "source": [
+    "from math import pi,atan,sqrt,cos,sin\n",
+    "\n",
+    "#variable declaration\n",
+    "\n",
+    "#summation of all  horizontal forces is zero & vertical forces is zero.\n",
+    "P1=float(60)                                     #inclined down to right Load at angle 60 at 1m from A,KN\n",
+    "P2=float(80)                                     #Inclined down to left Load at angle 75° at 3m from A,KN\n",
+    "P3=float(50)                                     #Inclined down to left Load at angle 60° at 5.5m from A,KN\n",
+    "theta1=60                                    \n",
+    "theta2=75\n",
+    "theta3=60\n",
+    "thetaRb=60\n",
+    "#horizontal,vertical component at A is Ha,Va  respectively.\n",
+    "\n",
+    "Rb=(P1*1*sin(theta1*pi/180)+P2*3*sin(theta2*pi/180)+P3*5.5*sin(theta3*pi/180))/(6*sin(thetaRb*pi/180))         #reaction at B point,KN\n",
+    "Ha=-P1*cos(theta1*pi/180)+P2*cos(theta2*pi/180)-P3*cos(theta3*pi/180)+Rb*cos(thetaRb*pi/180)\n",
+    "print \"RB=\",round(Rb,4),\"KN\"\n",
+    "\n",
+    "#now vertical component\n",
+    "Va=P1*sin(theta1*pi/180)+P2*sin(theta2*pi/180)+P3*sin(theta3*pi/180)-Rb*sin(thetaRb*pi/180)\n",
+    "\n",
+    "Ra=sqrt(pow(Ha,2)+pow(Va,2))\n",
+    "\n",
+    "print \"RA=\",round(Ra,4),\"KN\"\n",
+    "\n",
+    "alpha=(atan(Va/Ha))*180/pi\n",
+    "\n",
+    "print \"alpha=\",round(alpha,2),\"°\"\n"
+   ]
+  },
+  {
+   "cell_type": "markdown",
+   "metadata": {},
+   "source": [
+    "# example 9.3 page number 288\n"
+   ]
+  },
+  {
+   "cell_type": "code",
+   "execution_count": 3,
+   "metadata": {
+    "collapsed": false
+   },
+   "outputs": [
+    {
+     "name": "stdout",
+     "output_type": "stream",
+     "text": [
+      "RA= 91.6503 KN\n",
+      "HB= 42.4264 KN\n",
+      "VB= 90.7761 KN\n",
+      "RB= 100.2013 KN\n",
+      "alpha= 64.95 °\n"
+     ]
+    }
+   ],
+   "source": [
+    "from math import pi,atan,sqrt,cos,sin\n",
+    "\n",
+    "#variable declaration\n",
+    "\n",
+    "#summation of all  horizontal forces is zero & vertical forces is zero.\n",
+    "P1=float(20)                                     #vertical down  Load  at 2m from A,KN\n",
+    "P2=float(30)                                     #uniform distributed load from 2m to 6m from A,KN/m(in 4m of span)\n",
+    "P3=float(60)                                     #Inclined down to right Load at angle 45° at 7m from A,KN\n",
+    "\n",
+    "theta3=45\n",
+    "#horizontal,vertical component at  B is  Hb,Vb respectively.\n",
+    "\n",
+    "Ra=(P1*7+P2*4*5+P3*2*sin(theta3*pi/180))/(9)     #reaction at B point,KN\n",
+    "\n",
+    "print \"RA=\",round(Ra,4),\"KN\"\n",
+    "\n",
+    "Hb=P3*cos(theta3*pi/180)\n",
+    "print \"HB=\",round(Hb,4),\"KN\"\n",
+    "#now vertical component\n",
+    "Vb=P1+P2*4+P3*sin(theta3*pi/180)-Ra\n",
+    "print \"VB=\",round(Vb,4),\"KN\"\n",
+    "\n",
+    "Rb=sqrt(pow(Hb,2)+pow(Vb,2))\n",
+    "\n",
+    "print \"RB=\",round(Rb,4),\"KN\"\n",
+    "\n",
+    "alpha=(atan(Vb/Hb))*180/pi\n",
+    "\n",
+    "print \"alpha=\",round(alpha,2),\"°\""
+   ]
+  },
+  {
+   "cell_type": "markdown",
+   "metadata": {},
+   "source": [
+    "# example 9.4 page number 288"
+   ]
+  },
+  {
+   "cell_type": "code",
+   "execution_count": 4,
+   "metadata": {
+    "collapsed": false
+   },
+   "outputs": [
+    {
+     "name": "stdout",
+     "output_type": "stream",
+     "text": [
+      "no horizontal force  HA=0\n",
+      "VA= 74.0 KN\n",
+      "MA= 148.0 KN-m\n"
+     ]
+    }
+   ],
+   "source": [
+    "#variable declaration\n",
+    "#Let the reactions at A be Ha, Va and Ma\n",
+    "#summation of all  horizontal forces is zero & vertical forces is zero.\n",
+    "\n",
+    "P1=float(20)                                     #vertical down  Load  at 2m from A,KN\n",
+    "P2=float(12)                                     #vertical down  Load  at 3m from A,KN \n",
+    "P3=float(10)                                     #vertical down  Load  at 4m from A,KN\n",
+    "Pu=float(16)                                     #uniform distributed load from A to 2m from A,KN/m(in 2m of span)\n",
+    "##horizontal,vertical component at  A is  Ha,Va respectively.\n",
+    "print\"no horizontal force \",\"HA=0\"\n",
+    "Va=Pu*2+P1+P2+P3\n",
+    "print \"VA=\", round(Va,2),\"KN\"\n",
+    "Ma=Pu*2*1+P1*2+P2*3+P3*4\n",
+    "print \"MA=\", round(Ma,2),\"KN-m\"\n",
+    "\n"
+   ]
+  },
+  {
+   "cell_type": "markdown",
+   "metadata": {},
+   "source": [
+    "# example 9.5 page number 288\n"
+   ]
+  },
+  {
+   "cell_type": "code",
+   "execution_count": 5,
+   "metadata": {
+    "collapsed": false
+   },
+   "outputs": [
+    {
+     "name": "stdout",
+     "output_type": "stream",
+     "text": [
+      "no horizontal force  HA=0\n",
+      "VA= 65.0 KN\n",
+      "MA= 165.0 KN-m\n"
+     ]
+    }
+   ],
+   "source": [
+    "#variable declaration\n",
+    "#Let the reactions at A be  Va and Ma\n",
+    "#summation of all  horizontal forces is zero & vertical forces is zero.\n",
+    "\n",
+    "P1=float(15)                                     #vertical down  Load  at 3m from A,KN\n",
+    "P2=float(10)                                     #vertical down  Load  at 5m from A,KN \n",
+    "M=float(30)                                      #CW moment at 4m distance from A, KN-m\n",
+    "Pu=float(20)                                     #uniform distributed load from A to 2m from A,KN/m(in 2m of span)\n",
+    "##horizontal,vertical component at  A is  Ha,Va respectively.\n",
+    "print\"no horizontal force \",\"HA=0\"\n",
+    "Va=Pu*2+P1+P2\n",
+    "print \"VA=\", round(Va,2),\"KN\"\n",
+    "Ma=Pu*2*1+P1*3+P2*5+M\n",
+    "print \"MA=\", round(Ma,2),\"KN-m\"\n"
+   ]
+  },
+  {
+   "cell_type": "markdown",
+   "metadata": {},
+   "source": [
+    "# example 9.6 page number 289"
+   ]
+  },
+  {
+   "cell_type": "code",
+   "execution_count": 6,
+   "metadata": {
+    "collapsed": false
+   },
+   "outputs": [
+    {
+     "name": "stdout",
+     "output_type": "stream",
+     "text": [
+      "RB= 100.0 KN\n",
+      "RA= 30.0 KN\n"
+     ]
+    }
+   ],
+   "source": [
+    "#variable declaration\n",
+    "\n",
+    "#As supports A and B are simple supports and loading is only in vertical direction, the reactions RA and RB are in vertical directions only.\n",
+    "\n",
+    "#summation of all  horizontal forces is zero & vertical forces is zero.\n",
+    "\n",
+    "P1=float(30)                                     #vertical down  Load  at 1m from A,KN\n",
+    "P2=float(40)                                     #vertical down  Load  at 6.5m from A,KN                   \n",
+    "Pu=float(20)                                     #uniform distributed load from 2m to 5m from A,KN/m(in 3m of span).\n",
+    "\n",
+    "Rb=(Pu*3*3.5+P1*1+P2*6.5)/5\n",
+    "print \"RB=\", round(Rb,2),\"KN\"\n",
+    "Ra=Pu*3+P1+P2-Rb\n",
+    "print \"RA=\", round(Ra,2),\"KN\""
+   ]
+  },
+  {
+   "cell_type": "markdown",
+   "metadata": {},
+   "source": [
+    "# example 9.7 page number 289\n"
+   ]
+  },
+  {
+   "cell_type": "code",
+   "execution_count": 7,
+   "metadata": {
+    "collapsed": false
+   },
+   "outputs": [
+    {
+     "name": "stdout",
+     "output_type": "stream",
+     "text": [
+      "no horizontal force  HA=0\n",
+      "VB= 50.0 KN\n",
+      "VA= 70.0 KN\n"
+     ]
+    }
+   ],
+   "source": [
+    "#variable declaration\n",
+    "#Let the reactions at A be  Va and Ma.\n",
+    "#summation of all  horizontal forces is zero & vertical forces is zero.\n",
+    "\n",
+    "P1=float(60)                                     #vertical down  Load  at 4m from A to right,KN\n",
+    "P2=float(20)                                     #vertical down  Load  at 11m from A to right,KN \n",
+    "M=float(30)                                      #CW moment at 7m distance from A to right, KN-m\n",
+    "Pu=float(20)                                     #uniform distributed load from A to 2m from A to left ,KN/m(in 2m of span)\n",
+    "##horizontal,vertical component at  A is  Ha,Va respectively.\n",
+    "print\"no horizontal force \",\"HA=0\"\n",
+    "Vb=(-Pu*2*1+P1*4+P2*11+M)/9\n",
+    "print \"VB=\", round(Vb,2),\"KN\"\n",
+    "Va=Pu*2+P1+P2-Vb\n",
+    "print \"VA=\", round(Va,2),\"KN\"\n"
+   ]
+  },
+  {
+   "cell_type": "markdown",
+   "metadata": {},
+   "source": [
+    "# example 9.8 page number 290\n"
+   ]
+  },
+  {
+   "cell_type": "code",
+   "execution_count": 8,
+   "metadata": {
+    "collapsed": false
+   },
+   "outputs": [
+    {
+     "name": "stdout",
+     "output_type": "stream",
+     "text": [
+      "RB= 71.011 KN\n",
+      "(Negative sign show that the assumed direction of VA is wrong. In other words, VA is acting vertically downwards). \n",
+      "RA= 23.3666 KN\n",
+      "alpha= 24.79 °\n"
+     ]
+    }
+   ],
+   "source": [
+    "from math import pi,atan,sqrt,cos,sin\n",
+    "\n",
+    "#variable declaration\n",
+    "\n",
+    "#summation of all  horizontal forces is zero & vertical forces is zero.\n",
+    " \n",
+    "P1=float(30)                                     #Inclined down Load at angle 45° to left at 5m from A,KN\n",
+    "Pu=float(20)                                     #uniformly distributed load from 6m to 8m from A ,KN,(2m of span)\n",
+    "theta1=45\n",
+    "M=40                                             #ACW moment at 3m from A, KN-m\n",
+    "#horizontal,vertical component at A  is Ha,Va respectively.\n",
+    "\n",
+    "Rb=(M+P1*5*sin(theta1*pi/180)+Pu*2*7)/6         #reaction at B point,KN\n",
+    "\n",
+    "print \"RB=\",round(Rb,4),\"KN\"\n",
+    "\n",
+    "Ha=P1*cos(theta1*pi/180)\n",
+    "\n",
+    "#now vertical component\n",
+    "Va=P1*sin(theta1*pi/180)-Rb+Pu*2\n",
+    "\n",
+    "Ra=sqrt(pow(Ha,2)+pow(Va,2))\n",
+    "\n",
+    "print \"(Negative sign show that the assumed direction of VA is wrong. In other words, VA is acting vertically downwards). \"\n",
+    "\n",
+    "Va1=-1*Va\n",
+    "print \"RA=\",round(Ra,4),\"KN\"\n",
+    "\n",
+    "alpha=(atan(Va1/Ha))*180/pi\n",
+    "\n",
+    "print \"alpha=\",round(alpha,2),\"°\""
+   ]
+  },
+  {
+   "cell_type": "markdown",
+   "metadata": {},
+   "source": [
+    "# example 9.9 page number 290\n"
+   ]
+  },
+  {
+   "cell_type": "code",
+   "execution_count": 9,
+   "metadata": {
+    "collapsed": false
+   },
+   "outputs": [
+    {
+     "name": "stdout",
+     "output_type": "stream",
+     "text": [
+      "X= 5.0 m\n"
+     ]
+    }
+   ],
+   "source": [
+    "#variable declaration\n",
+    "\n",
+    "#summation of all  horizontal forces is zero & vertical forces is zero.\n",
+    " \n",
+    "#Let the left support C be at a distance x metres from A. \n",
+    "\n",
+    "P1=float(30)                        #vertical down load at A,KN\n",
+    "Pu=float(6)                         #uniform distributed load over whole span,KN/m,(20m of span)\n",
+    "P2=float(50)                        #vertical down load at B, KN\n",
+    "\n",
+    "#Rc=Rd(given) reaction at C & D is equal.\n",
+    "\n",
+    "Rc=(P1+P2+Pu*20)/2\n",
+    "Rd=Rc\n",
+    "\n",
+    "#taking moment at A \n",
+    "x=(((Pu*20*10+P2*20)/100)-12)/2\n",
+    "\n",
+    "print \"X=\", round(x,2),\"m\"\n"
+   ]
+  }
+ ],
+ "metadata": {
+  "kernelspec": {
+   "display_name": "Python [Root]",
+   "language": "python",
+   "name": "Python [Root]"
+  },
+  "language_info": {
+   "codemirror_mode": {
+    "name": "ipython",
+    "version": 2
+   },
+   "file_extension": ".py",
+   "mimetype": "text/x-python",
+   "name": "python",
+   "nbconvert_exporter": "python",
+   "pygments_lexer": "ipython2",
+   "version": "2.7.12"
+  }
+ },
+ "nbformat": 4,
+ "nbformat_minor": 0
+}