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authorTrupti Kini2017-03-17 23:30:25 +0600
committerTrupti Kini2017-03-17 23:30:25 +0600
commit2a5f1f9f2af82c46fbdba902c9dfdaba56c136b0 (patch)
tree7ce76ec82cb74706a939781d9bf0c7c9afab53e5 /Introduction_to_Heat_Transfer_by_S._K._Som/Chapter5.ipynb
parentd93e64cd264d30ae87de69ab9ab7f377d6047361 (diff)
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Added(A)/Deleted(D) following books
M Introduction_to_Heat_Transfer_by_S._K._Som/Chapter1.ipynb M Introduction_to_Heat_Transfer_by_S._K._Som/Chapter10.ipynb M Introduction_to_Heat_Transfer_by_S._K._Som/Chapter11.ipynb M Introduction_to_Heat_Transfer_by_S._K._Som/Chapter2.ipynb M Introduction_to_Heat_Transfer_by_S._K._Som/Chapter3.ipynb M Introduction_to_Heat_Transfer_by_S._K._Som/Chapter4.ipynb M Introduction_to_Heat_Transfer_by_S._K._Som/Chapter5.ipynb M Introduction_to_Heat_Transfer_by_S._K._Som/Chapter6.ipynb M Introduction_to_Heat_Transfer_by_S._K._Som/Chapter7.ipynb M Introduction_to_Heat_Transfer_by_S._K._Som/Chapter8.ipynb M Introduction_to_Heat_Transfer_by_S._K._Som/Chapter9.ipynb M Introduction_to_Heat_Transfer_by_S._K._Som/chapter12.ipynb
Diffstat (limited to 'Introduction_to_Heat_Transfer_by_S._K._Som/Chapter5.ipynb')
-rw-r--r--Introduction_to_Heat_Transfer_by_S._K._Som/Chapter5.ipynb107
1 files changed, 9 insertions, 98 deletions
diff --git a/Introduction_to_Heat_Transfer_by_S._K._Som/Chapter5.ipynb b/Introduction_to_Heat_Transfer_by_S._K._Som/Chapter5.ipynb
index d3fc7380..5b3d46e7 100644
--- a/Introduction_to_Heat_Transfer_by_S._K._Som/Chapter5.ipynb
+++ b/Introduction_to_Heat_Transfer_by_S._K._Som/Chapter5.ipynb
@@ -38,7 +38,6 @@
}
],
"source": [
- " \n",
"import math \n",
"from scipy.integrate import quad\n",
" \n",
@@ -74,23 +73,7 @@
"#Q is the rate of heat transfer\n",
"print\"The rate of heat transfer in W/m of width is\"\n",
"Q=hbarL*L*(T2-T1)\n",
- "print\"Q=\",Q\n",
- "\n",
- "\n",
- "\n",
- "\n",
- "\n",
- "\n",
- "\n",
- "\n",
- "\n",
- "\n",
- "\n",
- "\n",
- "\n",
- "\n",
- "\n",
- "\n"
+ "print\"Q=\",Q"
]
},
{
@@ -102,7 +85,7 @@
},
{
"cell_type": "code",
- "execution_count": 2,
+ "execution_count": 27,
"metadata": {
"collapsed": false
},
@@ -119,7 +102,6 @@
}
],
"source": [
- " \n",
"import math\n",
" \n",
"print\"Introduction to heat transfer by S.K.Som, Chapter 5, Example 4\"\n",
@@ -144,18 +126,7 @@
"#from an enrgy balance we can write as E=27.063*U**0.85*L*B*(Ts-Tinf)\n",
"print\"The minimum flow velocity in m/s is\"\n",
"U=(E/(27.063*L*B*(Ts-Tinf)))**(1/0.85)\n",
- "print\"U=\",U\n",
- "\n",
- "\n",
- "\n",
- "\n",
- "\n",
- "\n",
- "\n",
- "\n",
- "\n",
- "\n",
- "\n"
+ "print\"U=\",U"
]
},
{
@@ -167,7 +138,7 @@
},
{
"cell_type": "code",
- "execution_count": 3,
+ "execution_count": 1,
"metadata": {
"collapsed": false
},
@@ -190,10 +161,8 @@
}
],
"source": [
- " \n",
"import math\n",
" \n",
- " \n",
"print\"Introduction to heat transfer by S.K.Som, Chapter 5, Example 6\"\n",
"#Air at 1atm pressure and temprature(Tin)=30°C enters a tube of 25mm diameter(D) with a velocity(U) of 10m/s\n",
"D=0.025;#in metre\n",
@@ -231,25 +200,7 @@
"k=0.0285;\n",
"print\"Overall Nusselt number is \"\n",
"NuL=hx*D/k\n",
- "print\"NuL=\",NuL\n",
- "\n",
- "\n",
- "\n",
- "\n",
- "\n",
- "\n",
- "\n",
- "\n",
- "\n",
- "\n",
- "\n",
- "\n",
- "\n",
- "\n",
- "\n",
- "\n",
- "\n",
- "\n"
+ "print\"NuL=\",NuL"
]
},
{
@@ -261,7 +212,7 @@
},
{
"cell_type": "code",
- "execution_count": 4,
+ "execution_count": 3,
"metadata": {
"collapsed": false
},
@@ -285,7 +236,6 @@
}
],
"source": [
- " \n",
"import math\n",
" \n",
"print\"Introduction to heat transfer by S.K.Som, Chapter 5, Example 7\"\n",
@@ -324,21 +274,7 @@
"#Q is the heat loss from the plate\n",
"print\"The heat loss from the plate in W is\"\n",
"Q=hbar*A*(Ts-Tinf)\n",
- "print\"Q=\",Q\n",
- "\n",
- "\n",
- "\n",
- "\n",
- "\n",
- "\n",
- "\n",
- "\n",
- "\n",
- "\n",
- "\n",
- "\n",
- "\n",
- "\n"
+ "print\"Q=\",Q"
]
},
{
@@ -370,11 +306,7 @@
}
],
"source": [
- " \n",
- " \n",
- " \n",
- " \n",
- " import math\n",
+ "import math\n",
" \n",
"print\"Introduction to heat transfer by S.K.Som, Chapter 5, Example 8\"\n",
"#Eletric current passes through a L=0.5m long horizontal wire of D=0.1mm diameter.\n",
@@ -401,28 +333,7 @@
"#I is the current flow.\n",
"print\"The current in Ampere is\"\n",
"I=(Q/(R*L))**0.5\n",
- "print\"I=\",I\n",
- "\n",
- "\n",
- "\n",
- "\n",
- "\n",
- "\n",
- "\n",
- "\n",
- "\n",
- "\n",
- "\n",
- "\n",
- "\n",
- "\n",
- "\n",
- "\n",
- "\n",
- "\n",
- "\n",
- "\n",
- "\n"
+ "print\"I=\",I"
]
}
],