Added(A)/Deleted(D) following books

 A  1000_solved_Problems_in_Fluid_Mechanics_includes_Hydraulic_machines_by_K.Subramanya/chapter10_1.ipynb
A  1000_solved_Problems_in_Fluid_Mechanics_includes_Hydraulic_machines_by_K.Subramanya/chapter12_1.ipynb
A  1000_solved_Problems_in_Fluid_Mechanics_includes_Hydraulic_machines_by_K.Subramanya/chapter13_1.ipynb
A  1000_solved_Problems_in_Fluid_Mechanics_includes_Hydraulic_machines_by_K.Subramanya/chapter14_1.ipynb
A  1000_solved_Problems_in_Fluid_Mechanics_includes_Hydraulic_machines_by_K.Subramanya/chapter15_1.ipynb
A  1000_solved_Problems_in_Fluid_Mechanics_includes_Hydraulic_machines_by_K.Subramanya/chapter16_1.ipynb
A  1000_solved_Problems_in_Fluid_Mechanics_includes_Hydraulic_machines_by_K.Subramanya/chapter1_1.ipynb
A  1000_solved_Problems_in_Fluid_Mechanics_includes_Hydraulic_machines_by_K.Subramanya/chapter2_1.ipynb
A  1000_solved_Problems_in_Fluid_Mechanics_includes_Hydraulic_machines_by_K.Subramanya/chapter6_1.ipynb
A  1000_solved_Problems_in_Fluid_Mechanics_includes_Hydraulic_machines_by_K.Subramanya/chapter7_1.ipynb
A  1000_solved_Problems_in_Fluid_Mechanics_includes_Hydraulic_machines_by_K.Subramanya/chapter8_1.ipynb
A  1000_solved_Problems_in_Fluid_Mechanics_includes_Hydraulic_machines_by_K.Subramanya/chapter9_1.ipynb
A  1000_solved_Problems_in_Fluid_Mechanics_includes_Hydraulic_machines_by_K.Subramanya/screenshots/Screenshot_from_2016-01-14_17:01:00_1.png
A  1000_solved_Problems_in_Fluid_Mechanics_includes_Hydraulic_machines_by_K.Subramanya/screenshots/Screenshot_from_2016-01-14_17:01:25_1.png
A  1000_solved_Problems_in_Fluid_Mechanics_includes_Hydraulic_machines_by_K.Subramanya/screenshots/Screenshot_from_2016-01-14_17:02:44_1.png
A  Applied_Chemistry_by_Dr._Mrs.Trupti_Paradkar/chapter1.ipynb
A  Applied_Chemistry_by_Dr._Mrs.Trupti_Paradkar/chapter3.ipynb
A  Applied_Chemistry_by_Dr._Mrs.Trupti_Paradkar/screenshots/1.png
A  Applied_Chemistry_by_Dr._Mrs.Trupti_Paradkar/screenshots/2.png
A  Applied_Chemistry_by_Dr._Mrs.Trupti_Paradkar/screenshots/3.png
A  Basic_Mathematics_for_Electricity_and_Electronics_by_Arthur_Beiser/chapter10_1.ipynb
A  Basic_Mathematics_for_Electricity_and_Electronics_by_Arthur_Beiser/chapter11_1.ipynb
A  Basic_Mathematics_for_Electricity_and_Electronics_by_Arthur_Beiser/chapter12_1.ipynb
A  Basic_Mathematics_for_Electricity_and_Electronics_by_Arthur_Beiser/chapter13_1.ipynb
A  Basic_Mathematics_for_Electricity_and_Electronics_by_Arthur_Beiser/chapter14_1.ipynb
A  Basic_Mathematics_for_Electricity_and_Electronics_by_Arthur_Beiser/chapter15_1.ipynb
A  Basic_Mathematics_for_Electricity_and_Electronics_by_Arthur_Beiser/chapter1_1.ipynb
A  Basic_Mathematics_for_Electricity_and_Electronics_by_Arthur_Beiser/chapter2_1.ipynb
A  Basic_Mathematics_for_Electricity_and_Electronics_by_Arthur_Beiser/chapter3_1.ipynb
A  Basic_Mathematics_for_Electricity_and_Electronics_by_Arthur_Beiser/chapter4_1.ipynb
A  Basic_Mathematics_for_Electricity_and_Electronics_by_Arthur_Beiser/chapter5_1.ipynb
A  Basic_Mathematics_for_Electricity_and_Electronics_by_Arthur_Beiser/chapter6_1.ipynb
A  Basic_Mathematics_for_Electricity_and_Electronics_by_Arthur_Beiser/chapter7_1.ipynb
A  Basic_Mathematics_for_Electricity_and_Electronics_by_Arthur_Beiser/screenshots/Screenshot_from_2016-03-09_13:50:16.png
A  Basic_Mathematics_for_Electricity_and_Electronics_by_Arthur_Beiser/screenshots/Screenshot_from_2016-03-09_13:52:27.png
A  Basic_Mathematics_for_Electricity_and_Electronics_by_Arthur_Beiser/screenshots/Screenshot_from_2016-03-09_13:53:23.png
A  Introduction_To_Chemical_Engineering_Thermodynamics_by_G._Halder/Ch1.ipynb
A  Introduction_To_Chemical_Engineering_Thermodynamics_by_G._Halder/Ch10.ipynb
A  Introduction_To_Chemical_Engineering_Thermodynamics_by_G._Halder/Ch11.ipynb
A  Introduction_To_Chemical_Engineering_Thermodynamics_by_G._Halder/Ch12.ipynb
A  Introduction_To_Chemical_Engineering_Thermodynamics_by_G._Halder/Ch2.ipynb
A  Introduction_To_Chemical_Engineering_Thermodynamics_by_G._Halder/Ch3.ipynb
A  Introduction_To_Chemical_Engineering_Thermodynamics_by_G._Halder/Ch4.ipynb
A  Introduction_To_Chemical_Engineering_Thermodynamics_by_G._Halder/Ch5.ipynb
A  Introduction_To_Chemical_Engineering_Thermodynamics_by_G._Halder/Ch6.ipynb
A  Introduction_To_Chemical_Engineering_Thermodynamics_by_G._Halder/Ch7.ipynb
A  Introduction_To_Chemical_Engineering_Thermodynamics_by_G._Halder/Ch8.ipynb
A  Introduction_To_Chemical_Engineering_Thermodynamics_by_G._Halder/Ch9.ipynb
A  Introduction_To_Chemical_Engineering_Thermodynamics_by_G._Halder/screenshots/Ch9MolFracNMolVol.png
A  Introduction_To_Chemical_Engineering_Thermodynamics_by_G._Halder/screenshots/Ch9_molarFracNMolVol.png
A  Introduction_To_Chemical_Engineering_Thermodynamics_by_G._Halder/screenshots/ch10_consistency.png
A  Machine_Design_by_T._H._Wentzell,_P._E/README.txt
A  Microwaves_and_Radar_Principles_and_Applications_by_A._K._Maini/README.txt
A  Network_Analysis_and_Synthesis_by_B_R_Gupta/README.txt

1 files changed, 645 insertions, 0 deletions

diff --git a/Introduction_To_Chemical_Engineering_Thermodynamics_by_G._Halder/Ch1.ipynb b/Introduction_To_Chemical_Engineering_Thermodynamics_by_G._Halder/Ch1.ipynb
new file mode 100644
index 00000000..60cbc213
--- /dev/null
+++ b/Introduction_To_Chemical_Engineering_Thermodynamics_by_G._Halder/Ch1.ipynb
@@ -0,0 +1,645 @@
+{
+ "cells": [
+  {
+   "cell_type": "markdown",
+   "metadata": {},
+   "source": [
+    "# Chapter 1 - Introduction and basic concepts"
+   ]
+  },
+  {
+   "cell_type": "markdown",
+   "metadata": {},
+   "source": [
+    "## Example: 1.1 Page: 4"
+   ]
+  },
+  {
+   "cell_type": "code",
+   "execution_count": 22,
+   "metadata": {
+    "collapsed": false
+   },
+   "outputs": [
+    {
+     "name": "stdout",
+     "output_type": "stream",
+     "text": [
+      "Example: 1.1 - Page: 4\n",
+      "\n",
+      "\n",
+      "Weight of the man on the moon is 260.43 N\n",
+      "\n"
+     ]
+    }
+   ],
+   "source": [
+    "from __future__ import division\n",
+    "# Soltion\n",
+    "\n",
+    "print \"Example: 1.1 - Page: 4\\n\\n\"\n",
+    "\n",
+    "#*****Data*****#\n",
+    "g_Earth = 9.83 #  [m/square s]\n",
+    "F_Earth = 800 #  [N]\n",
+    "g_Moon = 3.2 #  [m/square s]\n",
+    "#************#\n",
+    "\n",
+    "# From the expression of force, the force on the man on the Eath's surface is given by:\n",
+    "# F = m*g_Earth\n",
+    "m = F_Earth/g_Earth #  [kg]\n",
+    "\n",
+    "# On the moon, the weight of the mass is equal to the force acting on the mass on the moon and is given by\n",
+    "F_Moon = m*g_Moon #  [N]\n",
+    "\n",
+    "print \"Weight of the man on the moon is %0.2f N\\n\"%(F_Moon)#"
+   ]
+  },
+  {
+   "cell_type": "markdown",
+   "metadata": {},
+   "source": [
+    "## Example: 1.2 Page: 5"
+   ]
+  },
+  {
+   "cell_type": "code",
+   "execution_count": 23,
+   "metadata": {
+    "collapsed": false
+   },
+   "outputs": [
+    {
+     "name": "stdout",
+     "output_type": "stream",
+     "text": [
+      "Example: 1.2 - Page: 5\n",
+      "\n",
+      "\n",
+      "Gravitational force on the body is 16.68 N\n",
+      "\n"
+     ]
+    }
+   ],
+   "source": [
+    "# Solution\n",
+    "\n",
+    "print \"Example: 1.2 - Page: 5\\n\\n\"\n",
+    "\n",
+    "#*****Data*****#\n",
+    "m1 = 1.5 #  [mass of the body, kg]\n",
+    "m2 = 6*10**(24) #  [mass of the Earth, kg]\n",
+    "G = 6.672*10**(-11) #  [N.square m/square.kg]\n",
+    "r = 6000*10**(3) #  [m]\n",
+    "#************#\n",
+    "\n",
+    "# According to Newton's universal law of gravity:\n",
+    "F = G*m1*m2/r**2 #  [N]\n",
+    "print \"Gravitational force on the body is %.2f N\\n\"%(F)#"
+   ]
+  },
+  {
+   "cell_type": "markdown",
+   "metadata": {},
+   "source": [
+    "## Example: 1.3 Page: 5"
+   ]
+  },
+  {
+   "cell_type": "code",
+   "execution_count": 24,
+   "metadata": {
+    "collapsed": false
+   },
+   "outputs": [
+    {
+     "name": "stdout",
+     "output_type": "stream",
+     "text": [
+      "Example: 1.3 - Page: 5\n",
+      "\n",
+      "\n",
+      "Mass of 1 kg will weigh 6.92 kg on moon\n",
+      "\n"
+     ]
+    }
+   ],
+   "source": [
+    "# Solution\n",
+    "\n",
+    "print \"Example: 1.3 - Page: 5\\n\\n\"\n",
+    "\n",
+    "#*****Data*****#\n",
+    "r_Moon = 0.3 #  [km]\n",
+    "r_Earth = 1 #  [km]\n",
+    "m2 = 1 #  [mass of body, kg]\n",
+    "mMoon_By_mEarth = 0.013 #  [kg/kg]\n",
+    "#***************#\n",
+    "\n",
+    "# According to the Newton's universal law of gravitation:\n",
+    "Fe_By_Fm = (1/mMoon_By_mEarth)*(r_Moon/r_Earth)**2#\n",
+    "print \"Mass of 1 kg will weigh %.2f kg on moon\\n\"%(Fe_By_Fm)#"
+   ]
+  },
+  {
+   "cell_type": "markdown",
+   "metadata": {},
+   "source": [
+    "## Example: 1.4 Page: 6"
+   ]
+  },
+  {
+   "cell_type": "code",
+   "execution_count": 25,
+   "metadata": {
+    "collapsed": false
+   },
+   "outputs": [
+    {
+     "name": "stdout",
+     "output_type": "stream",
+     "text": [
+      "Example: 1.4 - Page: 6\n",
+      "\n",
+      "\n",
+      "The absolute pressure is 54.914 kPa\n",
+      "\n"
+     ]
+    }
+   ],
+   "source": [
+    "# Solution\n",
+    "\n",
+    "print \"Example: 1.4 - Page: 6\\n\\n\"\n",
+    "\n",
+    "#*****Data*****#\n",
+    "h = 40 #  [cm]\n",
+    "density = 14.02 #  [g/cubic cm]\n",
+    "g = 9.792 #  [m/square s]\n",
+    "#*************#\n",
+    "\n",
+    "P = h*density*g/1000 #  [N/square cm]\n",
+    "P = P*10 #  [kPa]\n",
+    "\n",
+    "print \"The absolute pressure is %.3f kPa\\n\"%(P)#"
+   ]
+  },
+  {
+   "cell_type": "markdown",
+   "metadata": {},
+   "source": [
+    "## Example: 1.5 Page: 7"
+   ]
+  },
+  {
+   "cell_type": "code",
+   "execution_count": 26,
+   "metadata": {
+    "collapsed": false
+   },
+   "outputs": [
+    {
+     "name": "stdout",
+     "output_type": "stream",
+     "text": [
+      "Example: 1.5 - Page: 7\n",
+      "\n",
+      "\n",
+      "The absolute pressure within the container is 119.299 kPa\n",
+      "\n"
+     ]
+    }
+   ],
+   "source": [
+    "# Solution\n",
+    "\n",
+    "print \"Example: 1.5 - Page: 7\\n\\n\"\n",
+    "\n",
+    "#*****Data*****#\n",
+    "Patm = 112 #  [kPa]\n",
+    "density = 1200 #  [kg/cubic m]\n",
+    "g = 9.81 #  [m/sqaure s]\n",
+    "h = 0.62 #  [m]\n",
+    "#**************#\n",
+    "\n",
+    "P = Patm + (density*g*h/1000) #  [kPa]\n",
+    "\n",
+    "print \"The absolute pressure within the container is %.3f kPa\\n\"%(P)#"
+   ]
+  },
+  {
+   "cell_type": "markdown",
+   "metadata": {},
+   "source": [
+    "## Example: 1.6 Page: 9"
+   ]
+  },
+  {
+   "cell_type": "code",
+   "execution_count": 27,
+   "metadata": {
+    "collapsed": false
+   },
+   "outputs": [
+    {
+     "name": "stdout",
+     "output_type": "stream",
+     "text": [
+      "Example: 1.6 - Page: 9\n",
+      "\n",
+      "\n",
+      "Work done by the system is 1500 J\n",
+      "\n"
+     ]
+    }
+   ],
+   "source": [
+    "# Solution\n",
+    "\n",
+    "print \"Example: 1.6 - Page: 9\\n\\n\"\n",
+    "\n",
+    "#*****Data*****#\n",
+    "F = 150 #  [N]\n",
+    "Displacement = 10 #  [m]\n",
+    "#**************#\n",
+    "\n",
+    "W = F*Displacement #  [J]\n",
+    "\n",
+    "print \"Work done by the system is %d J\\n\"%(W)#"
+   ]
+  },
+  {
+   "cell_type": "markdown",
+   "metadata": {},
+   "source": [
+    "## Example: 1.7 Page: 9"
+   ]
+  },
+  {
+   "cell_type": "code",
+   "execution_count": 28,
+   "metadata": {
+    "collapsed": false
+   },
+   "outputs": [
+    {
+     "name": "stdout",
+     "output_type": "stream",
+     "text": [
+      "Example: 1.7 - Page: 9\n",
+      "\n",
+      "\n",
+      "Actual Work done by the system is 9.1e+05 J\n",
+      "\n"
+     ]
+    }
+   ],
+   "source": [
+    "# Solution\n",
+    "\n",
+    "print \"Example: 1.7 - Page: 9\\n\\n\"\n",
+    "\n",
+    "#*****Data*****#\n",
+    "P = 560*10**3 #  [Pa]\n",
+    "Vinit = 3 #  [cubic m]\n",
+    "Vfinal = 5 #  [cubic m]\n",
+    "Wext = 210*10**3 #  [J]\n",
+    "#*************#\n",
+    "\n",
+    "W = P*(Vfinal - Vinit) #  [J]\n",
+    "# Again the system receives 210 kJ of work from the external agent.\n",
+    "W = W - Wext #  [J]\n",
+    "\n",
+    "print \"Actual Work done by the system is %.1e J\\n\"%(W)#"
+   ]
+  },
+  {
+   "cell_type": "markdown",
+   "metadata": {},
+   "source": [
+    "## Example: 1.8 Page: 11"
+   ]
+  },
+  {
+   "cell_type": "code",
+   "execution_count": 29,
+   "metadata": {
+    "collapsed": false
+   },
+   "outputs": [
+    {
+     "name": "stdout",
+     "output_type": "stream",
+     "text": [
+      "Example: 1.8 - Page: 11\n",
+      "\n",
+      "\n",
+      "Change in potential Energy is 981 J\n",
+      "\n"
+     ]
+    }
+   ],
+   "source": [
+    "# Solution\n",
+    "\n",
+    "print \"Example: 1.8 - Page: 11\\n\\n\"\n",
+    "\n",
+    "#*****Data*****#\n",
+    "g = 9.81 #  [m/square s]\n",
+    "Z = 100 # [m]\n",
+    "#***************#\n",
+    "\n",
+    "# Basis: 1 kg of water\n",
+    "m = 1 #  [kg]\n",
+    "Ep = m*g*Z #  [J]\n",
+    "print \"Change in potential Energy is %d J\\n\"%(Ep)"
+   ]
+  },
+  {
+   "cell_type": "markdown",
+   "metadata": {},
+   "source": [
+    "## Example: 1.9 Page: 11"
+   ]
+  },
+  {
+   "cell_type": "code",
+   "execution_count": 30,
+   "metadata": {
+    "collapsed": false
+   },
+   "outputs": [
+    {
+     "name": "stdout",
+     "output_type": "stream",
+     "text": [
+      "Example: 1.9 - Page: 11\n",
+      "\n",
+      "\n",
+      "The velocity of the metal block is 15.34 m/s\n",
+      "\n",
+      "The final Kinetic Energy is 1765.8 J\n",
+      "\n"
+     ]
+    }
+   ],
+   "source": [
+    "from __future__ import division\n",
+    "# Solution\n",
+    "\n",
+    "print \"Example: 1.9 - Page: 11\\n\\n\"\n",
+    "\n",
+    "#*****Data*****#\n",
+    "m = 15# # [kg]\n",
+    "g = 9.81 #  [m/square s]\n",
+    "V1 = 0 #  [m/square s]\n",
+    "Z1 = 12 #  [m]\n",
+    "Z2 = 0 #  [m]\n",
+    "#***************#\n",
+    "\n",
+    "# At initial condition, V1 = 0, so kinetic energy is zero.\n",
+    "# At final condition, Z2 = 0, so potential energy is zero.\n",
+    "# Ep1 + Ek1 = Ep2 + Ek2\n",
+    "#deff('[y] = f(V2)','y = ((1/2)*m*V1**2) + (m*g*Z1) - (((1/2)*m*V2**2) + (m*g*Z2))')#\n",
+    "def f(V2):\n",
+    "    y = ((1/2)*m*V1**2) + (m*g*Z1) - (((1/2)*m*V2**2) + (m*g*Z2))\n",
+    "    return y\n",
+    "from scipy.optimize import fsolve\n",
+    "V2 = fsolve(f,7)#\n",
+    "\n",
+    "print \"The velocity of the metal block is %.2f m/s\\n\"%(V2)#\n",
+    "\n",
+    "Ek2 = (1/2)*m*V2**2 #  [J]\n",
+    "print \"The final Kinetic Energy is %.1f J\\n\"%(Ek2)#"
+   ]
+  },
+  {
+   "cell_type": "markdown",
+   "metadata": {},
+   "source": [
+    "## Example: 1.10 Page: 12"
+   ]
+  },
+  {
+   "cell_type": "code",
+   "execution_count": 31,
+   "metadata": {
+    "collapsed": false
+   },
+   "outputs": [
+    {
+     "name": "stdout",
+     "output_type": "stream",
+     "text": [
+      "Example: 1.10 - Page: 12\n",
+      "\n",
+      "\n",
+      "Power required is 7.64 kW\n",
+      "\n"
+     ]
+    }
+   ],
+   "source": [
+    "# Solution\n",
+    "\n",
+    "print \"Example: 1.10 - Page: 12\\n\\n\"\n",
+    "\n",
+    "#*****Data*****#\n",
+    "m = 1200 #  [kg]\n",
+    "v1 = 10 #  [km/h]\n",
+    "v2 = 100 #  [km/h]\n",
+    "time = 1 #  [min]\n",
+    "#***************#\n",
+    "\n",
+    "v1 = 10*1000/3600 #  [m/s]\n",
+    "v2 = 100*1000/3600 #  [m/s]\n",
+    "W = (1/2)*m*(v2**2 - v1**2) #  [J]\n",
+    "time = time*60 #  [s]\n",
+    "P = W/time #  [W]\n",
+    "print \"Power required is %.2f kW\\n\"%(P/1000)#"
+   ]
+  },
+  {
+   "cell_type": "markdown",
+   "metadata": {},
+   "source": [
+    "## Example: 1.11 Page: 13"
+   ]
+  },
+  {
+   "cell_type": "code",
+   "execution_count": 32,
+   "metadata": {
+    "collapsed": false
+   },
+   "outputs": [
+    {
+     "name": "stdout",
+     "output_type": "stream",
+     "text": [
+      "Example: 1.11 - Page: 13\n",
+      "\n",
+      "\n",
+      "Total Force eacting upon the gas is 8139.7 N\n",
+      "\n",
+      "Pressure exerted is 115.153 kPa\n",
+      "\n",
+      "\n",
+      "Work due to expansion by the gas is 4.070 kJ\n",
+      "\n",
+      "\n",
+      "Change in Potential Energy is 489.6 J\n",
+      "\n"
+     ]
+    }
+   ],
+   "source": [
+    "from math import pi\n",
+    "print \"Example: 1.11 - Page: 13\\n\\n\"\n",
+    "\n",
+    "#*****Data*****#\n",
+    "dia = 0.3 #  [m]\n",
+    "m = 100 #  [kg]\n",
+    "P_atm = 1.013*10**5 #  [N/square m]\n",
+    "g = 9.792 #  [m/square s]\n",
+    "#**************#\n",
+    "\n",
+    "Area = (pi/4)*dia**2 #  [square m]\n",
+    "#Solution (a)(i)\n",
+    "# Force exerted by the atmosphere:\n",
+    "F_atm = P_atm*Area #  [N]\n",
+    "# Force exerted by piston & metal block:\n",
+    "F_mass = m*g #  [N]\n",
+    "# Total force acting upon the gas:\n",
+    "F = F_atm + F_mass #  [N]\n",
+    "print \"Total Force eacting upon the gas is %.1f N\\n\"%(F)#\n",
+    "\n",
+    "# Solution (a)(ii)\n",
+    "Pressure = F/Area #  [N/square m]\n",
+    "print \"Pressure exerted is %.3f kPa\\n\\n\"%(Pressure/1000)#\n",
+    "\n",
+    "# Solution (b)\n",
+    "# The gas expands on application of heat, the volume of the gas goes on increasing and the piston moves upward.\n",
+    "Z = 0.5 #  [m]\n",
+    "# Work done due to expansion of gas:\n",
+    "W = F*Z #  [J]\n",
+    "print \"Work due to expansion by the gas is %.3f kJ\\n\\n\"%(W/1000)#\n",
+    "\n",
+    "# Solution (c)\n",
+    "# Change in potential energy of piston and weight after expansion process:\n",
+    "Ep = m*g*Z #  [J]\n",
+    "print \"Change in Potential Energy is %.1f J\\n\"%(Ep)#"
+   ]
+  },
+  {
+   "cell_type": "markdown",
+   "metadata": {},
+   "source": [
+    "## Example: 1.12 Page: 24"
+   ]
+  },
+  {
+   "cell_type": "code",
+   "execution_count": 33,
+   "metadata": {
+    "collapsed": false
+   },
+   "outputs": [
+    {
+     "name": "stdout",
+     "output_type": "stream",
+     "text": [
+      "Example: 1.12 - Page: 24\n",
+      "\n",
+      "\n",
+      "The temperature which has the same value on both the centigrade and Fahrenheit scales is -40 degree Celsius or -40 degree Fahrenheit\n",
+      "\n"
+     ]
+    }
+   ],
+   "source": [
+    "print \"Example: 1.12 - Page: 24\\n\\n\"\n",
+    "\n",
+    "# Solution\n",
+    "\n",
+    "# The relation is:\n",
+    "# (C/5) = ((F - 32)/9)\n",
+    "# For C = F\n",
+    "C = - (32*5/4)# # [degree Celsius]\n",
+    "print \"The temperature which has the same value on both the centigrade and Fahrenheit scales is %d degree Celsius or %d degree Fahrenheit\\n\"%(C,C)#"
+   ]
+  },
+  {
+   "cell_type": "markdown",
+   "metadata": {},
+   "source": [
+    "## Example: 1.13 Page: 24"
+   ]
+  },
+  {
+   "cell_type": "code",
+   "execution_count": 34,
+   "metadata": {
+    "collapsed": false
+   },
+   "outputs": [
+    {
+     "name": "stdout",
+     "output_type": "stream",
+     "text": [
+      "Example: 1.13 - Page: 24\n",
+      "\n",
+      "\n",
+      "The rise in temperature in the Kelvin scale is 30 K\n",
+      "\n",
+      "The rise in temperature in the Rankine scale is 54 R\n",
+      "\n",
+      "The rise in temperature in the Fahrenheit scale is 54 OF\n",
+      "\n"
+     ]
+    }
+   ],
+   "source": [
+    "print \"Example: 1.13 - Page: 24\\n\\n\"\n",
+    "\n",
+    "# Solution\n",
+    "\n",
+    "#*****Data*****#\n",
+    "delta_T_C = 30 #  [OC]\n",
+    "#*************#\n",
+    "\n",
+    "# The relation between the Kelvin temperature scale and the Celsius temperature scale:\n",
+    "# T(K) = T(OC) + 273.15\n",
+    "# Here, the temperature rise is to be expressed in terms of K, but the difference in temperature will be the same in the Kelvin and Celsius scales of temperature:\n",
+    "delta_T_K = delta_T_C #  [K]\n",
+    "print \"The rise in temperature in the Kelvin scale is %d K\\n\"%(delta_T_K)#\n",
+    "# The emperical relationship between the Rankine and Kelvin scales is given by:\n",
+    "delta_T_R = 1.8*delta_T_K #  [R]\n",
+    "print \"The rise in temperature in the Rankine scale is %d R\\n\"%(delta_T_R)#\n",
+    "delta_T_F = delta_T_R #  [OF]\n",
+    "print \"The rise in temperature in the Fahrenheit scale is %d OF\\n\"%(delta_T_F)#"
+   ]
+  }
+ ],
+ "metadata": {
+  "kernelspec": {
+   "display_name": "Python 2",
+   "language": "python",
+   "name": "python2"
+  },
+  "language_info": {
+   "codemirror_mode": {
+    "name": "ipython",
+    "version": 2
+   },
+   "file_extension": ".py",
+   "mimetype": "text/x-python",
+   "name": "python",
+   "nbconvert_exporter": "python",
+   "pygments_lexer": "ipython2",
+   "version": "2.7.9"
+  }
+ },
+ "nbformat": 4,
+ "nbformat_minor": 0
+}