Removed Problem Statements Completely

1 files changed, 70 insertions, 23 deletions

diff --git a/Introduction_To_Chemical_Engineering/ch5.ipynb b/Introduction_To_Chemical_Engineering/ch5.ipynb
index 6af51e50..24e997c2 100644
--- a/Introduction_To_Chemical_Engineering/ch5.ipynb
+++ b/Introduction_To_Chemical_Engineering/ch5.ipynb
@@ -1,6 +1,7 @@
 {
  "metadata": {
-  "name": ""
+  "name": "",
+  "signature": "sha256:a84d51472594c75f9afdf6cd721b95cb9d112fa36b409d534c3bc68aa928266a"
  },
  "nbformat": 3,
  "nbformat_minor": 0,
@@ -27,18 +28,21 @@
      "cell_type": "code",
      "collapsed": false,
      "input": [
-      "\n",
+      " \n",
       "import math \n",
+      "# Variables\n",
       "A=5.*4   #in m2\n",
       "T1=100.;   #in K\n",
       "T2=30.;    #in K\n",
       "\n",
+      "# Calculations\n",
       "delta_T=T1-T2;\n",
       "\n",
       "x=0.25   #in m\n",
       "k=0.70    #in W/mK\n",
       "Q=k*A*(delta_T/x);\n",
       "\n",
+      "# Results\n",
       "print \"rate of heat loss = %f W\"%(Q)\n"
      ],
      "language": "python",
@@ -66,12 +70,14 @@
      "cell_type": "code",
      "collapsed": false,
      "input": [
-      "\n",
+      " \n",
       "import math \n",
+      "# Variables\n",
       "d1=0.15   #in m\n",
       "d2=0.16   #in m\n",
       "l=1.   #in m\n",
       "\n",
+      "# Calculations\n",
       "A1=3.14*d1*l;\n",
       "A2=3.14*d2*l\n",
       "Am=(A1-A2)/math.log (A1/A2);\n",
@@ -84,6 +90,7 @@
       "k=50.   #in W/mK\n",
       "Q=k*Am*(delta_T/x);\n",
       "\n",
+      "# Results\n",
       "print \"rate of heat loss per unit length = %f W/m\"%(Q)\n"
      ],
      "language": "python",
@@ -111,13 +118,15 @@
      "cell_type": "code",
      "collapsed": false,
      "input": [
-      "\n",
+      " \n",
       "import math \n",
+      "# Variables\n",
       "ri=0.5   #in m\n",
       "ro=0.6;  #in m\n",
       "A1=4*3.14*ri**2;\n",
       "A2=4*3.14*ro**2;\n",
       "\n",
+      "# Calculations\n",
       "Am=(A1*A2)**0.5;\n",
       "\n",
       "Ti=140.;    #in K\n",
@@ -128,6 +137,7 @@
       "\n",
       "Q=k*Am*(delta_T/x);\n",
       "\n",
+      "# Results\n",
       "print \"Heat loss through sphere = %f W\"%(Q)\n"
      ],
      "language": "python",
@@ -155,13 +165,16 @@
      "cell_type": "code",
      "collapsed": false,
      "input": [
-      "\n",
+      " \n",
       "import math \n",
+      "# Variables\n",
       "x1=0.250;  #in m\n",
       "k1=0.7;  #in W/mK\n",
       "A1=1.;   #in m2\n",
       "R1=x1/(k1*A1);   #in K/W\n",
       "\n",
+      "# Calculations and Results\n",
+      "#for the felt layer\n",
       "x2=0.020;  #in m\n",
       "k2=0.046;  #in W/mK\n",
       "A2=1.;   #in m2\n",
@@ -201,8 +214,9 @@
      "cell_type": "code",
      "collapsed": false,
      "input": [
-      "\n",
+      " \n",
       "import math \n",
+      "# Variables\n",
       "d1=0.15   #in m\n",
       "d2=0.16   #in m\n",
       "l=1.   #in m\n",
@@ -213,6 +227,8 @@
       "k1=50.   #in W/mK\n",
       "R1=x1/(k1*Am1);\n",
       "\n",
+      "# Calculations and Results\n",
+      "#resistance by insulation\n",
       "d2=0.16   #in m\n",
       "d3=0.26   #in m\n",
       "l=1.   #in m\n",
@@ -259,8 +275,9 @@
      "cell_type": "code",
      "collapsed": false,
      "input": [
-      "\n",
+      " \n",
       "import math \n",
+      "# Variables\n",
       "x1=0.1;   #in m\n",
       "x2= 0.25;  #in m\n",
       "k_rb=0.93;   #in W/mK\n",
@@ -268,6 +285,8 @@
       "k_al=203.6    #in W/mK\n",
       "A=0.1   #in m2\n",
       "\n",
+      "# Calculations and Results\n",
+      "#to find resistance without rivets\n",
       "R=(1/A)*((x1/k_rb)+(x2/k_ib));\n",
       "T1=225   #in K\n",
       "T2=37    #in K\n",
@@ -275,6 +294,7 @@
       "Q=delta_T/R;\n",
       "print \"heat transfer rate = %f W\"%(Q)\n",
       "\n",
+      "#to find resistance with rivet\n",
       "d=0.03   #in m\n",
       "rivet_area= (3.14/4)*d**2;\n",
       "R_r=(x1+x2)/(k_al*rivet_area);\n",
@@ -314,20 +334,17 @@
      "cell_type": "code",
      "collapsed": false,
      "input": [
-      "'''\n",
-      "calculate the heat tranfer coefficient based on \n",
-      "i) the arithmetic mean difference between the temperatures of the water and the wall of the tube\n",
-      "ii) the logarithmic mean difference between the temperatures of the water and the wall of the tube.\n",
-      "'''\n",
-      "\n",
+      " \n",
       "import math\n",
       "\n",
+      "# variables\n",
       "Cp = 4.178          # kJ/kg K for water\n",
       "q = 1838.            # rate at which heat is transfered\n",
       "A = .1005           # heat transfer area\n",
       "dt1 = 80. - 24       # temperature diffference at hot end\n",
       "dt2 = 36.-24         # temperature difference at cold end\n",
       "\n",
+      "# Calculations and Results\n",
       "dtm = (56 + 12)/2.0\n",
       "h = q/(A*dtm)\n",
       "print \"Heat transfer coefficient, h  = %.0f W/m**2 K\"%h\n",
@@ -363,9 +380,10 @@
      "cell_type": "code",
      "collapsed": false,
      "input": [
-      "\n",
+      " \n",
       "import math \n",
       "\n",
+      "# Variables\n",
       "density=984.1     #in kg/cubic meter\n",
       "v=3.   #in m/s\n",
       "viscosity=485*10**-6;    #in Pa-s\n",
@@ -373,12 +391,15 @@
       "cp=4178.   #in J/kg K\n",
       "d=0.016    #in m\n",
       "\n",
+      "# Calculations and Results\n",
       "Re=(density*v*d)/viscosity;\n",
       "Pr=(cp*viscosity)/k;\n",
       "\n",
+      "#dittus boelter equation\n",
       "h=0.023*Re**0.8*Pr**0.3*(k/d);\n",
       "print \"heat transfer coefficient = %f W/sq meter K\"%(h)\n",
       "\n",
+      "#Sieder Tate equation\n",
       "viscosity_w=920*10**-6.\n",
       "h1=0.023*Re**0.8*Pr**(1./3)*(k/d)*(viscosity/viscosity_w)**0.14;\n",
       "print \"heat transfer coefficient = %f W/sq meter K\"%(h1)\n"
@@ -409,14 +430,17 @@
      "cell_type": "code",
      "collapsed": false,
      "input": [
-      "\n",
+      " \n",
       "import math \n",
+      "# Variables\n",
       "T_sun = 5973   #in degree C\n",
       "d = 1.5*10**13    #in cm\n",
       "R = 7.1*10**10;  #in cm\n",
       "\n",
+      "# Calculations\n",
       "T_earth = ((R/(2*d))**0.5)*T_sun;\n",
       "\n",
+      "# Results\n",
       "print \"Temperature of earth = %f C\"%(T_earth-273) \n"
      ],
      "language": "python",
@@ -444,14 +468,17 @@
      "cell_type": "code",
      "collapsed": false,
      "input": [
-      "\n",
+      " \n",
       "import math \n",
+      "# Variables\n",
       "R=7*10**10;   #in cm\n",
       "Ts=6000;   #in K\n",
       "\n",
+      "# Calculations\n",
       "l=1.5*10**13;   #in m\n",
       "To=((R**2/(4*l**2))**0.25)*Ts;\n",
       "\n",
+      "# Results\n",
       "print \"temperature of earth = %f K\"%(To)\n"
      ],
      "language": "python",
@@ -479,14 +506,17 @@
      "cell_type": "code",
      "collapsed": false,
      "input": [
-      "\n",
+      " \n",
       "import math \n",
+      "# Variables\n",
       "R=6.92*10**5    #in km\n",
       "l=14.97*10**7   #in km\n",
       "Ts=6200;    #in K\n",
       "\n",
+      "# Calculations\n",
       "To=(R**2/l**2)**0.25*Ts;\n",
       "\n",
+      "# Results\n",
       "print \"Equilibrium temperature = %f K\"%(To)\n"
      ],
      "language": "python",
@@ -514,15 +544,18 @@
      "cell_type": "code",
      "collapsed": false,
      "input": [
-      "\n",
+      " \n",
       "import math \n",
+      "# Variables\n",
       "view_factor=0.5;\n",
       "R=6.92*10**5    #in km\n",
       "l=14.97*10**7   #in km\n",
       "Ts=6200;    #in K\n",
       "\n",
+      "# Calculations\n",
       "To=(view_factor*(R**2/l**2))**0.25*Ts;\n",
       "\n",
+      "# Results\n",
       "print \"Equilibrium temperature = %f K\"%(To)\n",
       "\n",
       "\n"
@@ -552,8 +585,9 @@
      "cell_type": "code",
      "collapsed": false,
      "input": [
-      "\n",
+      " \n",
       "import math \n",
+      "# Variables\n",
       "view_factor=0.25;\n",
       "R=7.1*10**10    #in cm\n",
       "l=1.5*10**13   #in cm\n",
@@ -561,10 +595,12 @@
       "alpha=0.2;\n",
       "epsilon=0.1;\n",
       "\n",
+      "# Calculations\n",
       "ratio=alpha/epsilon;\n",
       "To=(ratio*view_factor*(R**2/l**2))**0.25*Ts;\n",
       "\n",
       "\n",
+      "# Results\n",
       "print \"Equilibrium temperature = %f K\"%(To)\n"
      ],
      "language": "python",
@@ -592,15 +628,18 @@
      "cell_type": "code",
      "collapsed": false,
      "input": [
-      "\n",
+      " \n",
       "import math \n",
+      "# Variables\n",
       "R=7*10**10;   #in cm\n",
       "l=1.5*10**13;  #in cm\n",
       "sigma=5.3*10**-5;   #in erd/s(cm2)(K)4\n",
       "T=6000;    #in K\n",
       "\n",
+      "# Calculations\n",
       "S=(R/l)**2*(sigma)*(T**4)*60;\n",
       "\n",
+      "# Results\n",
       "print \"solar constant = %f J/sq cm min\"%(S/10**7)\n"
      ],
      "language": "python",
@@ -628,12 +667,14 @@
      "cell_type": "code",
      "collapsed": false,
      "input": [
-      "\n",
+      " \n",
       "import math \n",
+      "# Variables\n",
       "F = 5000.   #in kg/hr\n",
       "xF = 0.01\n",
       "xL = 0.02;\n",
       "\n",
+      "# Calculations and Results\n",
       "L = F*xF/xL;\n",
       "V = F-L;\n",
       "print \"L = %f Kg/hr V = %f kg/hr\"%(L,V)\n",
@@ -682,15 +723,18 @@
      "cell_type": "code",
      "collapsed": false,
      "input": [
-      "\n",
+      " \n",
       "import math \n",
       "from numpy import *\n",
+      "# Variables\n",
       "b1 = 6000*125.79+3187.56*2691.5-3187.56*461.30;    #data from previous problem\n",
       "b2 = 6000;\n",
       "A = array([[419.04, 2676.1],[1, 1]])\n",
       "\n",
+      "# Calculations and Results\n",
       "b = array([[b1],[b2]]);\n",
       "x = linalg.solve(A,b)\n",
+      "#x = x*b\n",
       "L = x[0];\n",
       "V = x[1];\n",
       "\n",
@@ -727,11 +771,13 @@
      "cell_type": "code",
      "collapsed": false,
      "input": [
-      "\n",
+      " \n",
       "import math \n",
+      "# Variables\n",
       "Hv=2635.3    #kJ/kg\n",
       "hL=313.93    #in kJ/kg\n",
       "\n",
+      "# Calculations and Results\n",
       "S=(2500*313.93+2500*2635.3-5000*125.79)/(2691.5-461.30);\n",
       "print \"steam flow rate = %f kg steam/hr\"%(S)\n",
       "\n",
@@ -744,6 +790,7 @@
       "print \"Area = %f sq meter\"%(A)\n",
       "print \"in this case a condensor and vaccum pump should be used\"\n",
       "\n",
+      "# Note : there is mistake in calculation in Book. Please calculate manually."
      ],
      "language": "python",
      "metadata": {},