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+{
+ "metadata": {
+ "name": ""
+ },
+ "nbformat": 3,
+ "nbformat_minor": 0,
+ "worksheets": [
+ {
+ "cells": [
+ {
+ "cell_type": "heading",
+ "level": 1,
+ "metadata": {},
+ "source": [
+ "Chapter 03 : Junction diode characteristics"
+ ]
+ },
+ {
+ "cell_type": "heading",
+ "level": 2,
+ "metadata": {},
+ "source": [
+ "Example 3.1, Page No 62"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "import math\n",
+ "#initialisation of variables\n",
+ "Na=10.0**19 #Cm^3\n",
+ "q=1.6*10**-19\n",
+ "Vj=0.94 #V\n",
+ "Nd=10.0**17\n",
+ "e=11.9*8.85*10**-14\n",
+ "A=9.6*10**-8\n",
+ "\n",
+ "#Calculations\n",
+ "W=math.sqrt(((2*e)/(q*Nd))*Vj)\n",
+ "Ct=e*A/(W*10**-4)\n",
+ "\n",
+ "#Results\n",
+ "print(\"The transition capacitance is= %.2f fF \" %(Ct*10**11))"
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "The transition capacitance is= 9.09 fF \n"
+ ]
+ }
+ ],
+ "prompt_number": 1
+ },
+ {
+ "cell_type": "heading",
+ "level": 2,
+ "metadata": {},
+ "source": [
+ "Example 3.3, Page No 67"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "import math\n",
+ "#initialisation of variables\n",
+ "t=10 #ns lifetime of holes\n",
+ "I=0.1 #mA forward current\n",
+ "n=1\n",
+ "vt=0.026 #V\n",
+ "\n",
+ "#Calculations\n",
+ "Cd=(t*I)/(n*vt)\n",
+ "\n",
+ "#Results\n",
+ "print(\"The defusion capicitance is= %.2f pF \" %Cd)"
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "The defusion capicitance is= 38.46 pF \n"
+ ]
+ }
+ ],
+ "prompt_number": 2
+ },
+ {
+ "cell_type": "heading",
+ "level": 2,
+ "metadata": {},
+ "source": [
+ "Example 3.4, Page No 70"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "import math\n",
+ "#initialisation of variables\n",
+ "V=10.0\n",
+ "Vb=6.0 # breakdown voltage\n",
+ "\n",
+ "vz1=0.1/(0.1+1)*10 #v\n",
+ "vz2=9.0/(9+1)*10 #v\n",
+ "\n",
+ "#Calculations\n",
+ "Ir=(V-Vb)/vz1\n",
+ "Il=Vb/vz2\n",
+ "Iz=Ir-Il\n",
+ "\n",
+ "\n",
+ "#Results\n",
+ "print(\"The value of Iz is= %.2f mA \" %(Iz))"
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "The value of Iz is= 3.73 mA \n"
+ ]
+ }
+ ],
+ "prompt_number": 3
+ }
+ ],
+ "metadata": {}
+ }
+ ]
+} \ No newline at end of file