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| author | hardythe1 | 2015-06-03 15:27:17 +0530 |
|---|---|---|
| committer | hardythe1 | 2015-06-03 15:27:17 +0530 |
| commit | df60071cf1d1c18822d34f943ab8f412a8946b69 (patch) | |
| tree | ab059cf19bad4a1233a464ccf5d72cf8b3fb323c /Integrated_Electronics/Chapter12.ipynb | |
| parent | fba055ce5aa0955e22bac2413c33493b10ae6532 (diff) | |
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Diffstat (limited to 'Integrated_Electronics/Chapter12.ipynb')
| -rwxr-xr-x | Integrated_Electronics/Chapter12.ipynb | 108 |
1 files changed, 108 insertions, 0 deletions
diff --git a/Integrated_Electronics/Chapter12.ipynb b/Integrated_Electronics/Chapter12.ipynb new file mode 100755 index 00000000..e66f53de --- /dev/null +++ b/Integrated_Electronics/Chapter12.ipynb @@ -0,0 +1,108 @@ +{
+ "metadata": {
+ "name": ""
+ },
+ "nbformat": 3,
+ "nbformat_minor": 0,
+ "worksheets": [
+ {
+ "cells": [
+ {
+ "cell_type": "heading",
+ "level": 1,
+ "metadata": {},
+ "source": [
+ "Chapter 12 : MultiStage Amplifiers"
+ ]
+ },
+ {
+ "cell_type": "heading",
+ "level": 2,
+ "metadata": {},
+ "source": [
+ "Example 12.1a, Page No 433"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "import math\n",
+ "#initialisation of variables\n",
+ "Ry=1 #in K\n",
+ "Rg=1 #in M\n",
+ "Ri=1 #in K\n",
+ "hOE=1.0/40 #in K^-1\n",
+ "\n",
+ "#fL=1/(2*%pi*(ro+ri)*Cb)<=10\n",
+ "#Since ri=1M , ro<Ry=1K , then ro+ri=1M\n",
+ "\n",
+ "#Calculations\n",
+ "Cb=1/(2*math.pi*1*10)\n",
+ "\n",
+ "#Results\n",
+ "print(\"Minimum Value of coupling Capacitance for given FET = %.3f \" %Cb)\n"
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "Minimum Value of coupling Capacitance for given FET = 0.016 \n"
+ ]
+ }
+ ],
+ "prompt_number": 1
+ },
+ {
+ "cell_type": "heading",
+ "level": 2,
+ "metadata": {},
+ "source": [
+ "Example 12.1b, Page No 433"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "import math\n",
+ "\n",
+ "#initialisation of variables\n",
+ "Ry=1#in K\n",
+ "Rg=1#in M\n",
+ "Ri=1#in K\n",
+ "hOE=1.0/40 #in K^-1\n",
+ "\n",
+ "#fL=1/(2*math.pi*(ro+ri)*Cb)<=10\n",
+ "\n",
+ "#Ro>1/hOE=40K ro=Rc=1K. Rb>Ri=1K then ri=1K\n",
+ "\n",
+ "#Calculations\n",
+ "ro=1000.0 #in ohm\n",
+ "ri=1000.0 #in ohm\n",
+ "Cb=1.0/(2*math.pi*10*(ro+ri))\n",
+ "\n",
+ "#Results\n",
+ "print(\"Coupling Capacitance for given transistor = %.2f v \" %(Cb*(10**6)))"
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "Coupling Capacitance for given transistor = 7.96 v \n"
+ ]
+ }
+ ],
+ "prompt_number": 2
+ }
+ ],
+ "metadata": {}
+ }
+ ]
+}
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