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+{
+ "metadata": {
+  "name": ""
+ },
+ "nbformat": 3,
+ "nbformat_minor": 0,
+ "worksheets": [
+  {
+   "cells": [
+    {
+     "cell_type": "heading",
+     "level": 1,
+     "metadata": {},
+     "source": [
+      "Chapter : 10 - Non-linear Applications of IC Op-amps"
+     ]
+    },
+    {
+     "cell_type": "heading",
+     "level": 2,
+     "metadata": {},
+     "source": [
+      "Example 10.1 : Page No - 383\n"
+     ]
+    },
+    {
+     "cell_type": "code",
+     "collapsed": false,
+     "input": [
+      "from __future__ import division\n",
+      "#Given data\n",
+      "V_CC = 15 # in V\n",
+      "V_sat = V_CC # in V\n",
+      "R1 = 120 # in ohm\n",
+      "R2 = 51 # in k ohm\n",
+      "R2 = R2 * 10**3 # in ohm\n",
+      "V_in = 1 # in V\n",
+      "V_UT = (V_sat*R1)/(R1+R2) #in V\n",
+      "print \"When supply voltage is +15V then threshold voltage = %0.1f mV\" %(V_UT*10**3) \n",
+      "V_ULT = ((-V_sat)*R1)/(R1+R2) # in V\n",
+      "V_ULT = V_ULT # in V\n",
+      "print \"When supply voltage is -15V then threshold voltage = %0.1f mV\" %(V_ULT*10**3) \n",
+      "\n",
+      "\n"
+     ],
+     "language": "python",
+     "metadata": {},
+     "outputs": [
+      {
+       "output_type": "stream",
+       "stream": "stdout",
+       "text": [
+        "When supply voltage is +15V then threshold voltage = 35.2 mV\n",
+        "When supply voltage is -15V then threshold voltage = -35.2 mV\n"
+       ]
+      }
+     ],
+     "prompt_number": 2
+    },
+    {
+     "cell_type": "heading",
+     "level": 2,
+     "metadata": {},
+     "source": [
+      "Example 10.2 : Page No - 383\n"
+     ]
+    },
+    {
+     "cell_type": "code",
+     "collapsed": false,
+     "input": [
+      "from __future__ import division\n",
+      "#Given data\n",
+      "V_sat = 12 # in V\n",
+      "V_H = 6 # in V\n",
+      "R1 = 10 # in k ohm\n",
+      "R1 = R1 * 10**3 # in ohm\n",
+      "# Formula V_H= R1/(R1+R2)*(V_sat-(-V_sat)) and Let\n",
+      "V = V_H/(V_sat-(-V_sat)) # in V (assumed)\n",
+      "R2= (R1-V*R1)/V\n",
+      "print \"The value of R1 = %0.f k\u03a9\" %(R1*10**-3) \n",
+      "print \"The value of R2 = %0.f k\u03a9\" %(R2*10**-3) "
+     ],
+     "language": "python",
+     "metadata": {},
+     "outputs": [
+      {
+       "output_type": "stream",
+       "stream": "stdout",
+       "text": [
+        "The value of R1 = 10 k\u03a9\n",
+        "The value of R2 = 30 k\u03a9\n"
+       ]
+      }
+     ],
+     "prompt_number": 3
+    },
+    {
+     "cell_type": "heading",
+     "level": 2,
+     "metadata": {},
+     "source": [
+      "Example 10.3 : Page No - 384\n"
+     ]
+    },
+    {
+     "cell_type": "code",
+     "collapsed": false,
+     "input": [
+      "from numpy import pi\n",
+      "from math import asin\n",
+      "#Given data\n",
+      "V_P = 5 # in V\n",
+      "V_LT = -1.5 # in V\n",
+      "V_H = 2 # in V\n",
+      "f = 1 # in kHz\n",
+      "f = f * 10**3 # in Hz\n",
+      "V_UT = V_H-V_LT # in V\n",
+      "V_m = V_P/2 # in V\n",
+      "# Formula V_LT= V_m*sind(theta)\n",
+      "theta= asin(-V_LT/V_m) *180/pi\n",
+      "T = 1/f # in sec\n",
+      "theta1 = theta+180 # in degree\n",
+      "T1 = (T*theta1)/360 # in sec\n",
+      "T2 = T-T1 # in sec\n",
+      "print \"The value of T1 = %0.3f ms\" %(T1*10**3)\n",
+      "print \"The value of T2 = %0.3f ms\" %(T2*10**3)"
+     ],
+     "language": "python",
+     "metadata": {},
+     "outputs": [
+      {
+       "output_type": "stream",
+       "stream": "stdout",
+       "text": [
+        "The value of T1 = 0.602 ms\n",
+        "The value of T2 = 0.398 ms\n"
+       ]
+      }
+     ],
+     "prompt_number": 11
+    },
+    {
+     "cell_type": "heading",
+     "level": 2,
+     "metadata": {},
+     "source": [
+      "Example 10.4 : Page No - 384\n"
+     ]
+    },
+    {
+     "cell_type": "code",
+     "collapsed": false,
+     "input": [
+      "#Given data\n",
+      "V_H = 10 # in V\n",
+      "V_L = -10 # in V\n",
+      "I_max = 100 # in \u00b5A\n",
+      "I_max = I_max * 10**-6 # in A\n",
+      "V_HV = 0.1 # in V\n",
+      "V_sat = 10 # in V\n",
+      "R2 = 1 # in k ohm\n",
+      "R1 = 199 # in  k ohm\n",
+      "R = (R1*R2)/(R1+R2) # in k ohm\n",
+      "print \"The resistance = %0.f \u03a9\" %(R*10**3) \n",
+      "\n",
+      "# Note: The unit of the answer in the book is wrong"
+     ],
+     "language": "python",
+     "metadata": {},
+     "outputs": [
+      {
+       "output_type": "stream",
+       "stream": "stdout",
+       "text": [
+        "The resistance = 995 \u03a9\n"
+       ]
+      }
+     ],
+     "prompt_number": 12
+    },
+    {
+     "cell_type": "heading",
+     "level": 2,
+     "metadata": {},
+     "source": [
+      "Example 10.6 : Page No - 386\n"
+     ]
+    },
+    {
+     "cell_type": "code",
+     "collapsed": false,
+     "input": [
+      "#Given data\n",
+      "V_sat = 12 # in V\n",
+      "R1 = 1 # in k ohm\n",
+      "R2 = 3 # in k ohm\n",
+      "V_LT = ((-V_sat)*R1)/R2 # in V\n",
+      "print \"The value of V_LT = %0.f V\" %V_LT \n",
+      "V_UT = (-(-V_sat) * R1)/R2 # in V\n",
+      "print \"The value of V_UT = %0.f V\" %V_UT \n",
+      "V_H = (R1/R2)*(V_sat - (-V_sat)) # in V\n",
+      "print \"The value of V_H = %0.f V\" %V_H"
+     ],
+     "language": "python",
+     "metadata": {},
+     "outputs": [
+      {
+       "output_type": "stream",
+       "stream": "stdout",
+       "text": [
+        "The value of V_LT = -4 V\n",
+        "The value of V_UT = 4 V\n",
+        "The value of V_H = 8 V\n"
+       ]
+      }
+     ],
+     "prompt_number": 13
+    },
+    {
+     "cell_type": "heading",
+     "level": 2,
+     "metadata": {},
+     "source": [
+      "Example 10.7 : Page No - 387\n"
+     ]
+    },
+    {
+     "cell_type": "code",
+     "collapsed": false,
+     "input": [
+      "#Given data\n",
+      "R1 = 80 # in k ohm\n",
+      "R2 = 20 # in k ohm\n",
+      "V_sat = 12.5 # in V\n",
+      "V_UT = (R2/(R1+R2))*V_sat # in V\n",
+      "print \"Upper threshold voltage = %0.1f V\" %V_UT \n",
+      "V_LT = (R2/(R1+R2))*(-V_sat) # in V\n",
+      "print \"Lower threshold voltage = %0.1f V\" %V_LT \n",
+      "V_HV = (R2/(R1+R2))*(2*V_sat) # in V\n",
+      "print \"The hysteresis voltage = %0.f V\" %V_HV"
+     ],
+     "language": "python",
+     "metadata": {},
+     "outputs": [
+      {
+       "output_type": "stream",
+       "stream": "stdout",
+       "text": [
+        "Upper threshold voltage = 2.5 V\n",
+        "Lower threshold voltage = -2.5 V\n",
+        "The hysteresis voltage = 5 V\n"
+       ]
+      }
+     ],
+     "prompt_number": 15
+    },
+    {
+     "cell_type": "heading",
+     "level": 2,
+     "metadata": {},
+     "source": [
+      "Example 10.10 : Page No - 409\n"
+     ]
+    },
+    {
+     "cell_type": "code",
+     "collapsed": false,
+     "input": [
+      "from math import log\n",
+      "#Given data\n",
+      "R1 = 86 # in k ohm\n",
+      "V_sat = 15 # in V\n",
+      "R2 = 100 # in k ohm\n",
+      "V_UT = (R1/(R1+R2))*V_sat # in V\n",
+      "print \"The value of V_UT = %0.2f V\" %V_UT \n",
+      "V_LT = (R1/(R1+R2))*(-V_sat) # in V\n",
+      "print \"The value of V_LT = %0.2f V\" %V_LT \n",
+      "R_F = 100 # in k ohm\n",
+      "R_F= R_F*10**3 # in ohm\n",
+      "C = 0.1 # in \u00b5F\n",
+      "C = C * 10**-6 # in F\n",
+      "f_o = 1/(2*R_F*C*log( (V_sat-V_LT)/(V_sat-V_UT) )) # in Hz\n",
+      "print \"Frequency of oscillation = %0.f Hz\" %f_o"
+     ],
+     "language": "python",
+     "metadata": {},
+     "outputs": [
+      {
+       "output_type": "stream",
+       "stream": "stdout",
+       "text": [
+        "The value of V_UT = 6.94 V\n",
+        "The value of V_LT = -6.94 V\n",
+        "Frequency of oscillation = 50 Hz\n"
+       ]
+      }
+     ],
+     "prompt_number": 17
+    },
+    {
+     "cell_type": "heading",
+     "level": 2,
+     "metadata": {},
+     "source": [
+      "Example 10.12 : Page No - 421\n"
+     ]
+    },
+    {
+     "cell_type": "code",
+     "collapsed": false,
+     "input": [
+      "#Given data\n",
+      "del_Vin = 5 # in V\n",
+      "FRR = 80 # in dB\n",
+      "# Formula FRR= 20*log10(del_Vin/del_Vout)\n",
+      "del_Vout=del_Vin/(10**(FRR/20)) # in V\n",
+      "print \"Change in output voltage = %0.1f mV\" %(del_Vout*10**3)\n"
+     ],
+     "language": "python",
+     "metadata": {},
+     "outputs": [
+      {
+       "output_type": "stream",
+       "stream": "stdout",
+       "text": [
+        "Change in output voltage = 0.5 mV\n"
+       ]
+      }
+     ],
+     "prompt_number": 19
+    }
+   ],
+   "metadata": {}
+  }
+ ]
+}
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