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+{
+ "metadata": {
+  "name": "",
+  "signature": "sha256:76799d83bd91128bf807e32787abef19090d6630d45c16a130eb1ab2178963ed"
+ },
+ "nbformat": 3,
+ "nbformat_minor": 0,
+ "worksheets": [
+  {
+   "cells": [
+    {
+     "cell_type": "heading",
+     "level": 1,
+     "metadata": {},
+     "source": [
+      "Chapter 5 : Flow of Water Over Weirs"
+     ]
+    },
+    {
+     "cell_type": "heading",
+     "level": 2,
+     "metadata": {},
+     "source": [
+      "Example 5.1 Page No : 141"
+     ]
+    },
+    {
+     "cell_type": "code",
+     "collapsed": false,
+     "input": [
+      "import math \n",
+      "\t\t\n",
+      "#initialisation of variables\n",
+      "L = 6. \t\t#ft\n",
+      "H = 15. \t\t#in\n",
+      "Cd = 0.62\n",
+      "g = 32.2 \t\t#ft/sec**2\n",
+      "\n",
+      "#CALCULAIONS\n",
+      "Q = 2*Cd*L*math.sqrt(2*g)*(H/12)**1.5/3\n",
+      "\t\t\n",
+      "#RESULTS\n",
+      "print  'Total Discharge = %.1f cuses'%(Q)\n"
+     ],
+     "language": "python",
+     "metadata": {},
+     "outputs": [
+      {
+       "output_type": "stream",
+       "stream": "stdout",
+       "text": [
+        "Total Discharge = 27.8 cuses\n"
+       ]
+      }
+     ],
+     "prompt_number": 1
+    },
+    {
+     "cell_type": "heading",
+     "level": 2,
+     "metadata": {},
+     "source": [
+      "Example 5.2 Page No : 143"
+     ]
+    },
+    {
+     "cell_type": "code",
+     "collapsed": false,
+     "input": [
+      "import math \n",
+      "\t\t\n",
+      "#initialisation of variables\n",
+      "o = 90. \t\t#degrees\n",
+      "H = 15.5 \t\t#in\n",
+      "Cd = 0.6\n",
+      "g = 32.2 \t\t#ft/sec**2\n",
+      "\t\t\n",
+      "#CALCULATIONS\n",
+      "Q = 8*Cd*math.tan(math.radians(o/2))*math.sqrt(2*g)*(H/12)**2.5/15\n",
+      "\t\t\n",
+      "#RESULTS\n",
+      "print  'Total Discharge = %.2f cuses'%(Q)\n"
+     ],
+     "language": "python",
+     "metadata": {},
+     "outputs": [
+      {
+       "output_type": "stream",
+       "stream": "stdout",
+       "text": [
+        "Total Discharge = 4.87 cuses\n"
+       ]
+      }
+     ],
+     "prompt_number": 2
+    },
+    {
+     "cell_type": "heading",
+     "level": 2,
+     "metadata": {},
+     "source": [
+      "Example 5.3 Page No : 143"
+     ]
+    },
+    {
+     "cell_type": "code",
+     "collapsed": false,
+     "input": [
+      "import math \n",
+      "\t\t\n",
+      "#initialisation of variables\n",
+      "Cd = 0.62\n",
+      "L = 4. \t\t#ft\n",
+      "g = 32.2 \t\t#ft/sec**2\n",
+      "H = 6. \t\t#in\n",
+      "o = 90. \t\t#degrees\n",
+      "\t\t\n",
+      "#CALCULATIONS\n",
+      "Q = Cd*L*math.sqrt(2*g)*(H/12)**1.5*(2./3)\n",
+      "H1 = (Q*15/(8*Cd*math.tan(math.radians(o/2))*math.sqrt(2*g)))**(2./5)\n",
+      "\t\t\n",
+      "#RESULTS\n",
+      "print  'depth of water = %.2f ft'%(H1)\n"
+     ],
+     "language": "python",
+     "metadata": {},
+     "outputs": [
+      {
+       "output_type": "stream",
+       "stream": "stdout",
+       "text": [
+        "depth of water = 1.26 ft\n"
+       ]
+      }
+     ],
+     "prompt_number": 3
+    },
+    {
+     "cell_type": "heading",
+     "level": 2,
+     "metadata": {},
+     "source": [
+      "Example 5.4 Page No : 144"
+     ]
+    },
+    {
+     "cell_type": "code",
+     "collapsed": false,
+     "input": [
+      "import math \n",
+      "\t\t\n",
+      "#initialisation of variables\n",
+      "Cd = 0.62\n",
+      "L = 3. \t\t#ft\n",
+      "g = 32.2 \t\t#ft/sec**2\n",
+      "H = 1. \t\t#ft\n",
+      "L1 = 2. \t\t#ft\n",
+      "h = 0.5 \t\t#ft\n",
+      "L2 = 1. \t\t#ft\n",
+      "h1 = 0.25 \t\t#ft\n",
+      "\t\t\n",
+      "#CALCULATIONS\n",
+      "Q = 2*Cd*L*math.sqrt(2*g)*H**1.5/3\n",
+      "Q1 =2*Cd*L1*math.sqrt(2*g)*((H+h)**1.5- H**1.5)/3\n",
+      "Q2 = 2*Cd*L2*math.sqrt(2*g)*((H+h+h1)**1.5- (H+h)**1.5)/3\n",
+      "Q3 = Q1+Q2+Q\n",
+      "\t\t\n",
+      "#RESULTS\n",
+      "print  'Total Discharge = %.2f cuses'%(Q3)\n"
+     ],
+     "language": "python",
+     "metadata": {},
+     "outputs": [
+      {
+       "output_type": "stream",
+       "stream": "stdout",
+       "text": [
+        "Total Discharge = 17.09 cuses\n"
+       ]
+      }
+     ],
+     "prompt_number": 4
+    },
+    {
+     "cell_type": "heading",
+     "level": 2,
+     "metadata": {},
+     "source": [
+      "Example 5.5 Page No : 149"
+     ]
+    },
+    {
+     "cell_type": "code",
+     "collapsed": false,
+     "input": [
+      "import math \n",
+      "\t\t\n",
+      "#initialisation of variables\n",
+      "h = 9. \t\t#in\n",
+      "l = 6. \t\t#ft\n",
+      "g = 32.2 \t\t#ft/sec**2\n",
+      "\t\t\n",
+      "#CALCULATIONS\n",
+      "H = h/12\n",
+      "Q = math.sqrt(2*g)*l*(H/12)**1.5*(0.405+(0.00984/0.75))\n",
+      "Q1 = 3.33*l*H**1.5\n",
+      "\t\t\n",
+      "#RESULTS\n",
+      "print  'Discharge by francis formula = %.2f cuses'%(Q1)\n"
+     ],
+     "language": "python",
+     "metadata": {},
+     "outputs": [
+      {
+       "output_type": "stream",
+       "stream": "stdout",
+       "text": [
+        "Discharge by francis formula = 12.98 cuses\n"
+       ]
+      }
+     ],
+     "prompt_number": 5
+    },
+    {
+     "cell_type": "heading",
+     "level": 2,
+     "metadata": {},
+     "source": [
+      "Example 5.6 Page No : 149"
+     ]
+    },
+    {
+     "cell_type": "code",
+     "collapsed": false,
+     "input": [
+      "\t\t\n",
+      "#initialisation of variables\n",
+      "l = 24. \t\t#ft\n",
+      "n = 5. \t\t#parts\n",
+      "h = 2. \t\t#ft\n",
+      "w = 1.\t\t#ft\n",
+      "n1 = 4.\n",
+      "c = 10.\n",
+      "\t\t\n",
+      "#CALCULATIONS\n",
+      "Q = 3.33*((l-n1)-0.1*c*h)*h**1.5\n",
+      "\t\t\n",
+      "#RESULTS\n",
+      "print  'Discharge = %.1f cuses'%(Q)\n"
+     ],
+     "language": "python",
+     "metadata": {},
+     "outputs": [
+      {
+       "output_type": "stream",
+       "stream": "stdout",
+       "text": [
+        "Discharge = 169.5 cuses\n"
+       ]
+      }
+     ],
+     "prompt_number": 6
+    },
+    {
+     "cell_type": "heading",
+     "level": 2,
+     "metadata": {},
+     "source": [
+      "Example 5.7 Page No : 150"
+     ]
+    },
+    {
+     "cell_type": "code",
+     "collapsed": false,
+     "input": [
+      "\t\t\n",
+      "#initialisation of variables\n",
+      "A = 25. \t\t#miles**2\n",
+      "t = 24. \t\t#hr\n",
+      "p = 50. \t\t#per cent\n",
+      "l = 3. \t\t#in\n",
+      "h = 4. \t\t#ft\n",
+      "\t\t\n",
+      "#CALCULATIONS\n",
+      "A1 = 5280**2*A\n",
+      "V = A1*l/12\n",
+      "V1 = V/(t*60*60)\n",
+      "V2 = V1/2\n",
+      "L = (V2/(3.33*h*2))+0.2*4\n",
+      "\t\t\n",
+      "#RESULTS\n",
+      "print  'length of weir = %.1f ft'%(L)\n"
+     ],
+     "language": "python",
+     "metadata": {},
+     "outputs": [
+      {
+       "output_type": "stream",
+       "stream": "stdout",
+       "text": [
+        "length of weir = 38.7 ft\n"
+       ]
+      }
+     ],
+     "prompt_number": 7
+    },
+    {
+     "cell_type": "heading",
+     "level": 2,
+     "metadata": {},
+     "source": [
+      "Example 5.8 Page No : 151"
+     ]
+    },
+    {
+     "cell_type": "code",
+     "collapsed": false,
+     "input": [
+      "\t\t\n",
+      "#initialisation of variables\n",
+      "h = 4. \t\t#ft\n",
+      "w = 5. \t\t#ft\n",
+      "l = 2. \t\t#ft\n",
+      "Q1 = 1008.5 \t\t#cuses\n",
+      "n = 8. \t\t#piers\n",
+      "\t\t\n",
+      "#CALCULATIONS\n",
+      "Q = 3.33*(w-0.2*h)*h**1.5\n",
+      "n1 = Q1/Q\n",
+      "L = n*l+w*n1\n",
+      "\t\t\n",
+      "#RESULTS\n",
+      "print  'length of weir = %.f ft'%(L)\n"
+     ],
+     "language": "python",
+     "metadata": {},
+     "outputs": [
+      {
+       "output_type": "stream",
+       "stream": "stdout",
+       "text": [
+        "length of weir = 61 ft\n"
+       ]
+      }
+     ],
+     "prompt_number": 8
+    },
+    {
+     "cell_type": "heading",
+     "level": 2,
+     "metadata": {},
+     "source": [
+      "Example 5.9 Page No : 153"
+     ]
+    },
+    {
+     "cell_type": "code",
+     "collapsed": false,
+     "input": [
+      "\n",
+      "import math \n",
+      "\t\t\n",
+      "#initialisation of variables\n",
+      "k = 3.33\n",
+      "l = 10. \t\t#ft\n",
+      "x = 2. \t\t#ft\n",
+      "A = 30. \t\t#ft**2\n",
+      "g = 32.2 \t\t#ft/sec**2\n",
+      "\t\t\n",
+      "#CALCULATIONS\n",
+      "Q = k*(l-0.2*x)*x**1.5\n",
+      "V = Q/A\n",
+      "h = V**2/(2*g)\n",
+      "Q1 = k*(l-0.2*(x+h))*((x+h)**1.5-h**1.5)\n",
+      "va = Q1/A\n",
+      "ha = va**2/(2*g)\n",
+      "Q2 =  k*(l-0.2*(x+ha))*((x+ha)**1.5-ha**1.5)\n",
+      "\t\t\n",
+      "#RESULTS\n",
+      "\t\t\n",
+      "#RESULTS\n",
+      "print  'Discharge in franccis formula = %.2f cusecs'%(Q1)\n",
+      "print  ' Discharge in corrected franccis formula = %.2f cusecs'%(Q2)\n"
+     ],
+     "language": "python",
+     "metadata": {},
+     "outputs": [
+      {
+       "output_type": "stream",
+       "stream": "stdout",
+       "text": [
+        "Discharge in franccis formula = 98.17 cusecs\n",
+        " Discharge in corrected franccis formula = 99.41 cusecs\n"
+       ]
+      }
+     ],
+     "prompt_number": 9
+    },
+    {
+     "cell_type": "heading",
+     "level": 2,
+     "metadata": {},
+     "source": [
+      "Example 5.10 Page No : 154"
+     ]
+    },
+    {
+     "cell_type": "code",
+     "collapsed": false,
+     "input": [
+      "import math \n",
+      "\t\t\n",
+      "#initialisation of variables\n",
+      "Cd = 0.6\n",
+      "g = 32.2 \t\t#ft/sec**2\n",
+      "o = 90. \t\t#degrees\n",
+      "H = 2.   \t\t#ft\n",
+      "A = 15.2 \t\t#ft**2\n",
+      "\t\t\n",
+      "#CALCULATIONS\n",
+      "Q = 8*Cd*math.sqrt(2*g)*math.tan(math.radians(o/2))*H**2.5/15\n",
+      "va = Q/A\n",
+      "ha = va**2/(2*g)\n",
+      "Q1 = 8*Cd*math.sqrt(2*g)*((H+ha)**2.5-ha**2.5)/15\n",
+      "\t\t\n",
+      "#RESULTS\n",
+      "print  'Discharge of stream = %.1f cuses'%(Q1)\n"
+     ],
+     "language": "python",
+     "metadata": {},
+     "outputs": [
+      {
+       "output_type": "stream",
+       "stream": "stdout",
+       "text": [
+        "Discharge of stream = 14.8 cuses\n"
+       ]
+      }
+     ],
+     "prompt_number": 4
+    },
+    {
+     "cell_type": "heading",
+     "level": 2,
+     "metadata": {},
+     "source": [
+      "Example 5.11 Page No : 155"
+     ]
+    },
+    {
+     "cell_type": "code",
+     "collapsed": false,
+     "input": [
+      "\t\t\n",
+      "#initialisation of variables\n",
+      "va = 4. \t\t#ft/sec\n",
+      "g = 32.2 \t\t#ft/sec**2\n",
+      "H = 1.25 \n",
+      "l = 10. \t\t#ft\n",
+      "w = 62.4 \t\t#lbs/ft**3\n",
+      "p = 60. \t\t#per cent\n",
+      "l1 = 90. \t\t#ft\n",
+      "\t\t\n",
+      "#CALCULATIONS\n",
+      "ha = va**2/(2*g)\n",
+      "Q = 3.333*(l-0.1*2*(H+ha))*((H+ha)**1.5-ha**1.5)*w\n",
+      "E = Q*l1\n",
+      "HP = E*60/(100*550)\n",
+      "\t\t\n",
+      "#RESULTS\n",
+      "print  'H.P available = %.1f H.P'%(HP)\n"
+     ],
+     "language": "python",
+     "metadata": {},
+     "outputs": [
+      {
+       "output_type": "stream",
+       "stream": "stdout",
+       "text": [
+        "H.P available = 338.8 H.P\n"
+       ]
+      }
+     ],
+     "prompt_number": 11
+    },
+    {
+     "cell_type": "heading",
+     "level": 2,
+     "metadata": {},
+     "source": [
+      "Example 5.12 Page No : 157"
+     ]
+    },
+    {
+     "cell_type": "code",
+     "collapsed": false,
+     "input": [
+      "import math \n",
+      "\t\t\n",
+      "#initialisation of variables\n",
+      "L = 8. \t\t#ft\n",
+      "d = 9. \t\t#in\n",
+      "h = 3. \t\t#in\n",
+      "Cd1 = 0.62\n",
+      "Cd2 = 0.62\n",
+      "g = 32.2 \t\t#ft/sec**2\n",
+      "\t\t\n",
+      "#CALCULATIONS\n",
+      "Q1 = (2./3)*Cd1*L*math.sqrt(2*g)*(h/12)**1.5\n",
+      "Q2 = Cd2*L*d*math.sqrt(2*g*h/12)/12\n",
+      "Q = Q1+Q2\n",
+      "\t\t\n",
+      "#RESULTS\n",
+      "print  'Discharge = %.2f cuses'%(Q)\n"
+     ],
+     "language": "python",
+     "metadata": {},
+     "outputs": [
+      {
+       "output_type": "stream",
+       "stream": "stdout",
+       "text": [
+        "Discharge = 18.24 cuses\n"
+       ]
+      }
+     ],
+     "prompt_number": 12
+    },
+    {
+     "cell_type": "heading",
+     "level": 2,
+     "metadata": {},
+     "source": [
+      "Example 5.13 Page No : 158"
+     ]
+    },
+    {
+     "cell_type": "code",
+     "collapsed": false,
+     "input": [
+      "import math \n",
+      "\t\t\n",
+      "#initialisation of variables\n",
+      "L = 50. \t\t#ft\n",
+      "d = 2. \t\t#ft\n",
+      "h = 4. \t\t#ft\n",
+      "Cd1 = 0.58\n",
+      "Cd2 = 0.8\n",
+      "g = 32.2 \t\t#ft/sec**2\n",
+      "\t\t\n",
+      "#CALCULATIONS\n",
+      "ha = h/(2*g)\n",
+      "Q1 = (2./3)*Cd1*L*math.sqrt(2*g)*((h+ha)**1.5-ha**1.5)\n",
+      "Q2 = Cd2*L*d*math.sqrt(2*g*(h+ha))\n",
+      "Q = Q1+Q2\n",
+      "\n",
+      "\n",
+      "#RESULTS\n",
+      "print  'Discharge = %d cuses'%(Q)\n",
+      "\n",
+      "# note : value of ha is calculated wrongly. please check."
+     ],
+     "language": "python",
+     "metadata": {},
+     "outputs": [
+      {
+       "output_type": "stream",
+       "stream": "stdout",
+       "text": [
+        "Discharge = 2561 cuses\n"
+       ]
+      }
+     ],
+     "prompt_number": 4
+    },
+    {
+     "cell_type": "heading",
+     "level": 2,
+     "metadata": {},
+     "source": [
+      "Example 5.14 Page No : 158"
+     ]
+    },
+    {
+     "cell_type": "code",
+     "collapsed": false,
+     "input": [
+      "import math \n",
+      "\t\t\n",
+      "#initialisation of variables\n",
+      "M = 60.\n",
+      "k = 500.\n",
+      "v = 8. \t\t#ft/sec\n",
+      "w = 100. \t\t#ft\n",
+      "h1 = 5. \t\t#ft\n",
+      "g = 32.2 \t\t#ft/sec**2\n",
+      "x = 1.95 \t\t#ft\n",
+      "\t\t\n",
+      "#CALCULATIONS\n",
+      "Q = k*M**(2./3)\n",
+      "A = Q/v\n",
+      "md = A/w\n",
+      "h = md-h1\n",
+      "ha = v**2/(2*g)\n",
+      "H = h+x**2-1+h1-1\n",
+      "\t\t\n",
+      "#RESULTS\n",
+      "print  'height above the crest of the air  = %.2f ft of water'%(H)\n"
+     ],
+     "language": "python",
+     "metadata": {},
+     "outputs": [
+      {
+       "output_type": "stream",
+       "stream": "stdout",
+       "text": [
+        "height above the crest of the air  = 11.38 ft of water\n"
+       ]
+      }
+     ],
+     "prompt_number": 14
+    },
+    {
+     "cell_type": "heading",
+     "level": 2,
+     "metadata": {},
+     "source": [
+      "Example 5.16 Page No : 163"
+     ]
+    },
+    {
+     "cell_type": "code",
+     "collapsed": false,
+     "input": [
+      "import math \n",
+      "\t\t\n",
+      "#initialisation of variables\n",
+      "H2 = 1.5 \t\t#ft\n",
+      "H1 = 1. \t\t#ft\n",
+      "A = 100. \t\t#yards**2\n",
+      "Cd = 0.6\n",
+      "g = 32.2 \t\t#ft/sec**2\n",
+      "\t\t\n",
+      "#CALCULATIONS\n",
+      "A1 = A*9\n",
+      "T = (1.25*A1/(Cd*math.sqrt(2*g)))*(H1-(1/H2)**1.5)\n",
+      "\t\t\n",
+      "#RESULTS\n",
+      "print  'time of lowering the surface = %.1f sec'%(T)\n"
+     ],
+     "language": "python",
+     "metadata": {},
+     "outputs": [
+      {
+       "output_type": "stream",
+       "stream": "stdout",
+       "text": [
+        "time of lowering the surface = 106.5 sec\n"
+       ]
+      }
+     ],
+     "prompt_number": 15
+    }
+   ],
+   "metadata": {}
+  }
+ ]
+}
\ No newline at end of file