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Added(A)/Deleted(D) following books
A Grob's_Basic_Electronics_by_M._E._Schultz/Chapter1.ipynb A Grob's_Basic_Electronics_by_M._E._Schultz/Chapter11.ipynb A Grob's_Basic_Electronics_by_M._E._Schultz/Chapter12.ipynb A Grob's_Basic_Electronics_by_M._E._Schultz/Chapter13.ipynb A Grob's_Basic_Electronics_by_M._E._Schultz/Chapter14.ipynb A Grob's_Basic_Electronics_by_M._E._Schultz/Chapter15.ipynb A Grob's_Basic_Electronics_by_M._E._Schultz/Chapter16.ipynb A Grob's_Basic_Electronics_by_M._E._Schultz/Chapter17.ipynb A Grob's_Basic_Electronics_by_M._E._Schultz/Chapter18.ipynb A Grob's_Basic_Electronics_by_M._E._Schultz/Chapter19.ipynb A Grob's_Basic_Electronics_by_M._E._Schultz/Chapter20.ipynb A Grob's_Basic_Electronics_by_M._E._Schultz/Chapter21.ipynb A Grob's_Basic_Electronics_by_M._E._Schultz/Chapter22.ipynb A Grob's_Basic_Electronics_by_M._E._Schultz/Chapter23.ipynb A Grob's_Basic_Electronics_by_M._E._Schultz/Chapter25.ipynb A Grob's_Basic_Electronics_by_M._E._Schultz/Chapter26.ipynb A Grob's_Basic_Electronics_by_M._E._Schultz/Chapter27.ipynb A Grob's_Basic_Electronics_by_M._E._Schultz/Chapter28.ipynb A Grob's_Basic_Electronics_by_M._E._Schultz/Chapter29.ipynb A Grob's_Basic_Electronics_by_M._E._Schultz/Chapter3.ipynb A Grob's_Basic_Electronics_by_M._E._Schultz/Chapter30.ipynb A Grob's_Basic_Electronics_by_M._E._Schultz/Chapter31.ipynb A Grob's_Basic_Electronics_by_M._E._Schultz/Chapter32.ipynb A Grob's_Basic_Electronics_by_M._E._Schultz/Chapter33.ipynb A Grob's_Basic_Electronics_by_M._E._Schultz/Chapter4.ipynb A Grob's_Basic_Electronics_by_M._E._Schultz/Chapter5.ipynb A Grob's_Basic_Electronics_by_M._E._Schultz/Chapter6.ipynb A Grob's_Basic_Electronics_by_M._E._Schultz/Chapter7.ipynb A Grob's_Basic_Electronics_by_M._E._Schultz/Chapter8.ipynb A Grob's_Basic_Electronics_by_M._E._Schultz/Chapter9.ipynb A Grob's_Basic_Electronics_by_M._E._Schultz/ChapterI.ipynb A Grob's_Basic_Electronics_by_M._E._Schultz/screenshots/DCLoadLine.png A Grob's_Basic_Electronics_by_M._E._Schultz/screenshots/EmitterCurrent.png A Grob's_Basic_Electronics_by_M._E._Schultz/screenshots/freqNperiod.png A principle_of_physics_by_V.K.MEHTA_,_ROHIT_MEHTA_/Chapter10_3.ipynb A principle_of_physics_by_V.K.MEHTA_,_ROHIT_MEHTA_/Chapter28_3.ipynb A principle_of_physics_by_V.K.MEHTA_,_ROHIT_MEHTA_/Chapter29_3.ipynb A principle_of_physics_by_V.K.MEHTA_,_ROHIT_MEHTA_/chapter11_3.ipynb A principle_of_physics_by_V.K.MEHTA_,_ROHIT_MEHTA_/chapter12_3.ipynb A principle_of_physics_by_V.K.MEHTA_,_ROHIT_MEHTA_/chapter13_3.ipynb A principle_of_physics_by_V.K.MEHTA_,_ROHIT_MEHTA_/chapter14_3.ipynb A principle_of_physics_by_V.K.MEHTA_,_ROHIT_MEHTA_/chapter15_3.ipynb A principle_of_physics_by_V.K.MEHTA_,_ROHIT_MEHTA_/chapter16_3.ipynb A principle_of_physics_by_V.K.MEHTA_,_ROHIT_MEHTA_/chapter17_3.ipynb A principle_of_physics_by_V.K.MEHTA_,_ROHIT_MEHTA_/chapter18_3.ipynb A principle_of_physics_by_V.K.MEHTA_,_ROHIT_MEHTA_/chapter19_3.ipynb A principle_of_physics_by_V.K.MEHTA_,_ROHIT_MEHTA_/chapter1_3.ipynb A principle_of_physics_by_V.K.MEHTA_,_ROHIT_MEHTA_/chapter20_3.ipynb A principle_of_physics_by_V.K.MEHTA_,_ROHIT_MEHTA_/chapter21_3.ipynb A principle_of_physics_by_V.K.MEHTA_,_ROHIT_MEHTA_/chapter22_3.ipynb A principle_of_physics_by_V.K.MEHTA_,_ROHIT_MEHTA_/chapter23_3.ipynb A principle_of_physics_by_V.K.MEHTA_,_ROHIT_MEHTA_/chapter24_3.ipynb A principle_of_physics_by_V.K.MEHTA_,_ROHIT_MEHTA_/chapter25_3.ipynb A principle_of_physics_by_V.K.MEHTA_,_ROHIT_MEHTA_/chapter26_3.ipynb A principle_of_physics_by_V.K.MEHTA_,_ROHIT_MEHTA_/chapter27_3.ipynb A principle_of_physics_by_V.K.MEHTA_,_ROHIT_MEHTA_/chapter2_3.ipynb A principle_of_physics_by_V.K.MEHTA_,_ROHIT_MEHTA_/chapter3_3.ipynb A principle_of_physics_by_V.K.MEHTA_,_ROHIT_MEHTA_/chapter4_3.ipynb A principle_of_physics_by_V.K.MEHTA_,_ROHIT_MEHTA_/chapter5_3.ipynb A principle_of_physics_by_V.K.MEHTA_,_ROHIT_MEHTA_/chapter6_3.ipynb A principle_of_physics_by_V.K.MEHTA_,_ROHIT_MEHTA_/chapter7_3.ipynb A principle_of_physics_by_V.K.MEHTA_,_ROHIT_MEHTA_/chapter8_3.ipynb A principle_of_physics_by_V.K.MEHTA_,_ROHIT_MEHTA_/chapter9_3.ipynb A principle_of_physics_by_V.K.MEHTA_,_ROHIT_MEHTA_/screenshots/image11_2.png A principle_of_physics_by_V.K.MEHTA_,_ROHIT_MEHTA_/screenshots/image12_2.png A principle_of_physics_by_V.K.MEHTA_,_ROHIT_MEHTA_/screenshots/image13_2.png
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+{
+ "cells": [
+ {
+ "cell_type": "markdown",
+ "metadata": {},
+ "source": [
+ "# Chapter - I : Introduction to powers of 10"
+ ]
+ },
+ {
+ "cell_type": "markdown",
+ "metadata": {},
+ "source": [
+ "## Example No. I_9 Page No. 9"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "execution_count": 24,
+ "metadata": {
+ "collapsed": false
+ },
+ "outputs": [
+ {
+ "name": "stdout",
+ "output_type": "stream",
+ "text": [
+ "The addition of 170*10**3 and 23*10**4 =4.00E+05\n"
+ ]
+ }
+ ],
+ "source": [
+ "# Add 170*10**3 and 23*10**4. Express the final answer in scientific notation.\n",
+ "\n",
+ "# Given data\n",
+ "\n",
+ "A = 170*10**3# # Variable 1\n",
+ "B = 23*10**4# # Variable 2\n",
+ "\n",
+ "C = A+B#\n",
+ "print 'The addition of 170*10**3 and 23*10**4 =%0.2E'%C"
+ ]
+ },
+ {
+ "cell_type": "markdown",
+ "metadata": {},
+ "source": [
+ "## Example No. I_10 Page No. 9"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "execution_count": 25,
+ "metadata": {
+ "collapsed": false
+ },
+ "outputs": [
+ {
+ "name": "stdout",
+ "output_type": "stream",
+ "text": [
+ "The substraction of 250*10**3 and 1.5*10**6 =1.25E+06\n"
+ ]
+ }
+ ],
+ "source": [
+ "# Substract 250*10**3 and 1.5*10**6. Express the final answer in scientific notation.\n",
+ "\n",
+ "# Given data\n",
+ "\n",
+ "A = 1.5*10**6# # Variable 1\n",
+ "B = 250*10**3# # Variable 2\n",
+ "\n",
+ "C = A-B#\n",
+ "print 'The substraction of 250*10**3 and 1.5*10**6 =%0.2E'%C"
+ ]
+ },
+ {
+ "cell_type": "markdown",
+ "metadata": {},
+ "source": [
+ "## Example No. I_11 Page No. 10"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "execution_count": 26,
+ "metadata": {
+ "collapsed": false
+ },
+ "outputs": [
+ {
+ "name": "stdout",
+ "output_type": "stream",
+ "text": [
+ "The multiplication of 3*10**6 by 150*10**2 =4.50E+10\n"
+ ]
+ }
+ ],
+ "source": [
+ "# Multiply 3*10**6 by 150*10**2. Express the final answer in scientific notation.\n",
+ "\n",
+ "# Given data\n",
+ "\n",
+ "A = 3*10**6# # Variable 1\n",
+ "B = 150*10**2# # Variable 2\n",
+ "\n",
+ "C = A*B#\n",
+ "print 'The multiplication of 3*10**6 by 150*10**2 =%0.2E'%C"
+ ]
+ },
+ {
+ "cell_type": "markdown",
+ "metadata": {},
+ "source": [
+ "## Example No. I_12 Page No. 10"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "execution_count": 27,
+ "metadata": {
+ "collapsed": false
+ },
+ "outputs": [
+ {
+ "name": "stdout",
+ "output_type": "stream",
+ "text": [
+ "The division of 5.0*10**7 by 2.0*10**4 =2.50E+03\n"
+ ]
+ }
+ ],
+ "source": [
+ "# Divide 5.0*10**7 by 2.0*10**4. Express the final answer in scientific notation.\n",
+ "\n",
+ "# Given data\n",
+ "\n",
+ "A = 5.0*10**7# # Variable 1\n",
+ "B = 2.0*10**4# # Variable 2\n",
+ "\n",
+ "C = A/B#\n",
+ "print 'The division of 5.0*10**7 by 2.0*10**4 =%0.2E'%C"
+ ]
+ },
+ {
+ "cell_type": "markdown",
+ "metadata": {},
+ "source": [
+ "## Example No. I_13 Page No. 10"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "execution_count": 28,
+ "metadata": {
+ "collapsed": false
+ },
+ "outputs": [
+ {
+ "name": "stdout",
+ "output_type": "stream",
+ "text": [
+ "The reciprocal of 10**5 =1.00e-05\n",
+ "i.e 10**-5\n",
+ "The reciprocal of 10-3 = 1.00e+03\n",
+ "i.e 10**3\n"
+ ]
+ }
+ ],
+ "source": [
+ "# Find the reciprocals for the following powers of 10: (a) 10**5 (b) 10**-3.\n",
+ "\n",
+ "# Given data\n",
+ "\n",
+ "A = 10**5# # Variable 1\n",
+ "B = 10**-3# # Variable 2\n",
+ "\n",
+ "C = 1./A#\n",
+ "print 'The reciprocal of 10**5 =%0.2e'%C\n",
+ "print 'i.e 10**-5'\n",
+ "\n",
+ "D = 1./B#\n",
+ "print 'The reciprocal of 10-3 = %0.2e'%D\n",
+ "print 'i.e 10**3'"
+ ]
+ },
+ {
+ "cell_type": "markdown",
+ "metadata": {},
+ "source": [
+ "## Example No. I_14 Page No. 11"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "execution_count": 29,
+ "metadata": {
+ "collapsed": false
+ },
+ "outputs": [
+ {
+ "name": "stdout",
+ "output_type": "stream",
+ "text": [
+ "The square of 3.0*10**4 =9.00E+08\n"
+ ]
+ }
+ ],
+ "source": [
+ "# Square 3.0*10**4. Express the answer in scientific notation.\n",
+ "\n",
+ "# Given data\n",
+ "\n",
+ "A = 3.0*10**4# # Variable 1\n",
+ "\n",
+ "B = A*A#\n",
+ "print 'The square of 3.0*10**4 =%0.2E'%B"
+ ]
+ },
+ {
+ "cell_type": "markdown",
+ "metadata": {},
+ "source": [
+ "## Example No. I_15 Page No. 11"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "execution_count": 30,
+ "metadata": {
+ "collapsed": false
+ },
+ "outputs": [
+ {
+ "name": "stdout",
+ "output_type": "stream",
+ "text": [
+ "The squareroot of 4*10**6 = 2.00E+03\n"
+ ]
+ }
+ ],
+ "source": [
+ "from math import sqrt\n",
+ "# Find the squareroot of 4*10**6. Express the answer in scientific notation.\n",
+ "\n",
+ "# Given data\n",
+ "\n",
+ "A = 4*10**6# # Variable 1\n",
+ "\n",
+ "B = sqrt(A)#\n",
+ "print 'The squareroot of 4*10**6 = %0.2E'%B"
+ ]
+ },
+ {
+ "cell_type": "markdown",
+ "metadata": {},
+ "source": [
+ "## Example No. I_16 Page No. 12"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "execution_count": 31,
+ "metadata": {
+ "collapsed": false
+ },
+ "outputs": [
+ {
+ "name": "stdout",
+ "output_type": "stream",
+ "text": [
+ "The squareroot of 90*10**5 =3.00E+03\n"
+ ]
+ }
+ ],
+ "source": [
+ "from math import sqrt\n",
+ "# Find the squareroot of 90*10**5. Express the answer in scientific notation.\n",
+ "\n",
+ "# Given data\n",
+ "\n",
+ "A = 90*10**5# # Variable 1\n",
+ "\n",
+ "B = sqrt(A)#\n",
+ "print 'The squareroot of 90*10**5 =%0.2E'% B"
+ ]
+ },
+ {
+ "cell_type": "markdown",
+ "metadata": {},
+ "source": [
+ "## Example No. I_17 Page No. 12"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "execution_count": 32,
+ "metadata": {
+ "collapsed": false
+ },
+ "outputs": [
+ {
+ "name": "stdout",
+ "output_type": "stream",
+ "text": [
+ "The multiplication of 40*10**-3 by 5*10**6 =200000.00\n",
+ "i.e 200.000*10**03 OR 200E03\n"
+ ]
+ }
+ ],
+ "source": [
+ "# Show the keystrokes for multiplying 40*10**-3 by 5*10**6.\n",
+ "\n",
+ "# Given data\n",
+ "\n",
+ "A = 40*10**-3# # Variable 1\n",
+ "B = 5*10**6# # Variable 2\n",
+ "\n",
+ "C = A*B#\n",
+ "print 'The multiplication of 40*10**-3 by 5*10**6 =%0.2f'%C\n",
+ "print 'i.e 200.000*10**03 OR 200E03'"
+ ]
+ }
+ ],
+ "metadata": {
+ "kernelspec": {
+ "display_name": "Python 2",
+ "language": "python",
+ "name": "python2"
+ },
+ "language_info": {
+ "codemirror_mode": {
+ "name": "ipython",
+ "version": 2
+ },
+ "file_extension": ".py",
+ "mimetype": "text/x-python",
+ "name": "python",
+ "nbconvert_exporter": "python",
+ "pygments_lexer": "ipython2",
+ "version": "2.7.9"
+ }
+ },
+ "nbformat": 4,
+ "nbformat_minor": 0
+}