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+{
+ "metadata": {
+  "name": ""
+ },
+ "nbformat": 3,
+ "nbformat_minor": 0,
+ "worksheets": [
+  {
+   "cells": [
+    {
+     "cell_type": "heading",
+     "level": 1,
+     "metadata": {},
+     "source": [
+      " Chapter 2:Dynamics of Electric Drives"
+     ]
+    },
+    {
+     "cell_type": "heading",
+     "level": 2,
+     "metadata": {},
+     "source": [
+      "Example no:2.1,Page no:16"
+     ]
+    },
+    {
+     "cell_type": "code",
+     "collapsed": false,
+     "input": [
+      "import math\n",
+      "\n",
+      "#variable declaration\n",
+      "Jo=0.2     # inertia of the motor in kg-m2\n",
+      "a1=0.1     # reduction gear\n",
+      "J1=10      # inertia of the load in kg-m2\n",
+      "Tl1=10     # load torque\n",
+      "v=1.5      # speed of the translational load \n",
+      "M1=1000    # mass of the translational load\n",
+      "N=1420     # speed of the motor\n",
+      "n1=.9      # efficiency of the reduction gear\n",
+      "n1_=0.85   # efficiency of the translational load and the motor\n",
+      "F1=M1*9.81 # force of the translational load \n",
+      "\n",
+      "#Calculation\n",
+      "Wm=N*math.pi/30 #angular speed\n",
+      "J=Jo+a1**2*J1+ M1*(v/Wm)**2 # total equivalent moment of inertia\n",
+      "Tl= a1*Tl1/n1+F1/n1_*(v/Wm) # total equivalent torque\n",
+      "\n",
+      "#Result\n",
+      "print\"\\nEquivalent moment of inertia is :\",round(J,1),\"kg-m2\"\n",
+      "print\"\\nEquivalent load torque :\",round(Tl,2),\"N-m\"\n",
+      "\n"
+     ],
+     "language": "python",
+     "metadata": {},
+     "outputs": [
+      {
+       "output_type": "stream",
+       "stream": "stdout",
+       "text": [
+        "\n",
+        "Equivalent moment of inertia is: 0.4 kg-m2\n",
+        "\n",
+        "Equivalent load torque : 117.53 N-m\n"
+       ]
+      }
+     ],
+     "prompt_number": 4
+    },
+    {
+     "cell_type": "heading",
+     "level": 2,
+     "metadata": {},
+     "source": [
+      "Example no:2.2,Page no:22"
+     ]
+    },
+    {
+     "cell_type": "code",
+     "collapsed": false,
+     "input": [
+      "import scipy\n",
+      "from scipy import integrate\n",
+      "import math\n",
+      "\n",
+      "# variable declaration\n",
+      "J=10           #moment of inertia of the drive in kg-m2\n",
+      "print(\"Passive load torque during steady state is :Tl=0.05*N in N-m\")\n",
+      "print(\"And load torque : T=100-0.1*N in N-m \")\n",
+      "print(\"load torque  when the direction is reversed T=-100-0.1*N  in N-m\")\n",
+      "\n",
+      "#Calculation\n",
+      "print(\"T-Tl=0\")\n",
+      "print(\"100-0.1*N-0.05*N=0\")\n",
+      "N=100/0.15     #Required speed of the motor in rpm during steady state\n",
+      "N2=-100/0.15   #During reversal speed is in opposite direction\n",
+      "print(\"\\nJdWm/dt=-100-0.1*N-0.05*N during reversing\")\n",
+      "print(\"dN/dt=30/(J*pi)*(-100-0.15*N)\")\n",
+      "print(\"dN/dt=(-95.49-0.143*N)\")\n",
+      "N1=N\n",
+      "N2=N2*0.95 #for speed reversal \n",
+      "x2 = lambda N: 1/(-95.49-0.143*N)\n",
+      "t=integrate.quad(x2, round(N1), round(N2))\n",
+      "\n",
+      "#result\n",
+      "print\"\\nHence Time of reversal is :\",round(t[0],2),\"s\""
+     ],
+     "language": "python",
+     "metadata": {},
+     "outputs": [
+      {
+       "output_type": "stream",
+       "stream": "stdout",
+       "text": [
+        "Passive load torque during steady state is :Tl=0.05*N in N-m\n",
+        "And load torque : T=100-0.1*N in N-m \n",
+        "load torque  when the direction is reversed T=-100-0.1*N  in N-m\n",
+        "T-Tl=0\n",
+        "100-0.1*N-0.05*N=0\n",
+        "\n",
+        "JdWm/dt=-100-0.1*N-0.05*N during reversing\n",
+        "dN/dt=30/(J*pi)*(-100-0.15*N)\n",
+        "dN/dt=(-95.49-0.143*N)\n",
+        "\n",
+        "Hence Time of reversal is : 25.51 s\n"
+       ]
+      }
+     ],
+     "prompt_number": 7
+    },
+    {
+     "cell_type": "heading",
+     "level": 2,
+     "metadata": {},
+     "source": [
+      "Example no:2.3,Page no:27"
+     ]
+    },
+    {
+     "cell_type": "code",
+     "collapsed": false,
+     "input": [
+      "import math\n",
+      "from __future__ import division\n",
+      "\n",
+      "#variable declaration\n",
+      "Tlh=1000     # load torque in N-m\n",
+      "Tmax=700     # maximum motor torque\n",
+      "Tll=200      # light load for the motor to regain its steady state\n",
+      "Tmin=Tll     # minimum torque\n",
+      "t_h=10       # period for which a load torque of 1000 N-m is apllied in sec\n",
+      "Jm=10        # moment of inertia of the motor in Kg-m2\n",
+      "No=500       # no load speed in rpm\n",
+      "Tr=500       # torque at a given no load speed in N-m\n",
+      "\n",
+      "#Calculation\n",
+      "Wmo=No*2*math.pi/60 # angular no load speed in rad/sec\n",
+      "s=0.05              # slip at a torque of 500 N-m\n",
+      "Wmr=(1-s)*Wmo       # angular speed at a torque of 500 N-m in rad/sec\n",
+      "\n",
+      "y=math.log((Tlh-Tmin)/(Tlh-Tmax))\n",
+      "x=Tr/(Wmo-Wmr)\n",
+      "\n",
+      "J=x*t_h/y\n",
+      "Jf=J-Jm\n",
+      "\n",
+      "#Result \n",
+      "#answer in the book is wrong\n",
+      "print\"\\n\\nMoment of inertia of the flywheel : \", round(Jf,1),\"Kg-m2\""
+     ],
+     "language": "python",
+     "metadata": {},
+     "outputs": [
+      {
+       "output_type": "stream",
+       "stream": "stdout",
+       "text": [
+        "\n",
+        "\n",
+        "Moment of inertia of the flywheel :  1937.2 Kg-m2\n"
+       ]
+      }
+     ],
+     "prompt_number": 12
+    }
+   ],
+   "metadata": {}
+  }
+ ]
+}
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