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authordebashisdeb2014-06-20 15:42:42 +0530
committerdebashisdeb2014-06-20 15:42:42 +0530
commit83c1bfceb1b681b4bb7253b47491be2d8b2014a1 (patch)
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parenta78126bbe4443e9526a64df9d8245c4af8843044 (diff)
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removing problem statements
Diffstat (limited to 'Fundamental_of_Electronics_Devices/Ch3.ipynb')
-rw-r--r--Fundamental_of_Electronics_Devices/Ch3.ipynb39
1 files changed, 0 insertions, 39 deletions
diff --git a/Fundamental_of_Electronics_Devices/Ch3.ipynb b/Fundamental_of_Electronics_Devices/Ch3.ipynb
index fcc2f572..d78715cf 100644
--- a/Fundamental_of_Electronics_Devices/Ch3.ipynb
+++ b/Fundamental_of_Electronics_Devices/Ch3.ipynb
@@ -27,19 +27,14 @@
"cell_type": "code",
"collapsed": false,
"input": [
- "#Example 3.2\n",
- "#What is Minimum required energy \n",
"\n",
- "#given data\n",
"l=6000 #in Angstrum\n",
"h=6.6*10**(-34) #Planks constant\n",
"c=3*10**8 #speed of light in m/s\n",
"e=1.602*10**(-19) #Constant\n",
"\n",
- "#calculation\n",
"phi=c*h/(e*l*10**(-10))\n",
"\n",
- "#result\n",
"print\"Minimum required energy is\",round(phi,2),\"eV \"\n"
],
"language": "python",
@@ -67,18 +62,13 @@
"cell_type": "code",
"collapsed": false,
"input": [
- "#Exa 3.3\n",
- "#calculate Work function of the cathode material\n",
"\n",
- "#given data\n",
"Emax=2.5 #maximum energy of emitted electrons in eV \n",
"l=2537.0 #in Angstrum\n",
"\n",
- "#Calculation\n",
"EeV=12400.0/l #in eV\n",
"phi=EeV-Emax #in eV\n",
"\n",
- "#result\n",
"print \"Work function of the cathode material is \",round(phi,2),\"eV\""
],
"language": "python",
@@ -106,12 +96,7 @@
"cell_type": "code",
"collapsed": false,
"input": [
- "#Example 3.4\n",
- "#Find (i)The fraction of each photon energy unit which is converted into heat\",f\n",
- "#(ii)Energy converted into heat in ,((2-1.43)/2)*0.009,\"J/s\"\n",
- "#(iii)Number of photons per second given off from recombination events \",0.009/(e*2)\n",
"\n",
- "#given data\n",
"t=0.46*10**-4 #in centi meters\n",
"hf1=2 #in ev\n",
"hf2=1.43\n",
@@ -122,18 +107,15 @@
"\n",
"import math\n",
"\n",
- "#Calculation\n",
"It=Io*math.exp(-alpha*t) #in mW\n",
"Iabs=Io-It\n",
"f=(hf1-hf2)/hf1\n",
"E=f*Iabs\n",
"N=Iabs/(e*hf1)\n",
"\n",
- "#result\n",
"print\"(i)Thus power absorbed is \",round(Iabs,3),\"J/s\"\n",
"print\"(ii)Energy converted into heat is\",round(E,4),\"J/s\"\n",
"print\"(iii)Number of photons per second given off from recombination events \",round(N,-14)\n",
- "#In book there is calculation mistake in Number of photons."
],
"language": "python",
"metadata": {},
@@ -162,11 +144,7 @@
"cell_type": "code",
"collapsed": false,
"input": [
- "#Example 3.5\n",
- "#What is Photoconductor gain \n",
- "#Electron transit time.\n",
"\n",
- "#given data\n",
"L=100 #in uM\n",
"A=10&-7 #in cm**2\n",
"th=10**-6 #in sec\n",
@@ -174,12 +152,10 @@
"ue=0.13 #in m**2/V-s\n",
"uh=0.05 #in m**2/V-s\n",
"\n",
- "#Calculation\n",
"E=V/(L*10**-6) #in V/m\n",
"tn=(L*10**-6)/(ue*E)\n",
"Gain=(1+uh/ue)*(th/tn)\n",
"\n",
- "#result\n",
"print\"Electron transit time in sec is \",round(tn,10),\"s\"\n",
"print\"Photoconductor gain is \",Gain"
],
@@ -209,19 +185,14 @@
"cell_type": "code",
"collapsed": false,
"input": [
- "#Example3.6\n",
- "#Calculate Current flowing through diode .\n",
"\n",
- "#given datex\n",
"import math\n",
"Io=0.15 #in uA\n",
"V=0.12 #in mVolt\n",
"Vt=26 #in mVolt\n",
"\n",
- "#calculation\n",
"I=Io*10**-6*(math.exp(V/(Vt*10**-3))-1) #in A\n",
"\n",
- "#result\n",
"print\"Current flowing through diode is \",round(I*10**6,2),\"micra A\""
],
"language": "python",
@@ -249,20 +220,15 @@
"cell_type": "code",
"collapsed": false,
"input": [
- "#Exa 3.7\n",
- "#Determine the Forward voltage \n",
"\n",
- "#given data\n",
"import math\n",
"Io=2.5 #in uA\n",
"I=10 #in mA\n",
"Vt=26 #in mVolt\n",
"n=2 #for silicon\n",
"\n",
- "#Calculation\n",
"V=n*Vt*10**-3*math.log((I*10**-3)/(Io*10**-6))\n",
"\n",
- "#Result\n",
"print \"Forward voltage is \",round(V,2),\"V\""
],
"language": "python",
@@ -290,10 +256,7 @@
"cell_type": "code",
"collapsed": false,
"input": [
- "#Example 3.8\n",
- "#What is Reverse saturation current density \n",
"\n",
- "#given data\n",
"ND=10**21 #in m**-3\n",
"NA=10**22 #in m**-3\n",
"De=3.4*10**-3 #in m**2-s**-1\n",
@@ -303,10 +266,8 @@
"ni=1.6*10**16 #in m**-3\n",
"e=1.602*10**-19 #constant\n",
"\n",
- "#calculation\n",
"IoA=e*ni**2*(Dh/(Lh*ND)+De/(Le*NA))\n",
"\n",
- "#Result\n",
"print\"Reverse saturation current density is \",round(IoA*10**6,2),\"uA \""
],
"language": "python",