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author | Thomas Stephen Lee | 2015-09-07 17:46:06 +0530 |
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committer | Thomas Stephen Lee | 2015-09-07 17:46:06 +0530 |
commit | 78784b374b2d1a9be66eb4ad41470409e2bd4dfa (patch) | |
tree | 7b0144248a9d5c9b6c66065697177ee04a30f93e /Fundamental_of_Electronics_Devices/Ch3.ipynb | |
parent | 41f1f72e9502f5c3de6ca16b303803dfcf1df594 (diff) | |
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diff --git a/Fundamental_of_Electronics_Devices/Ch3.ipynb b/Fundamental_of_Electronics_Devices/Ch3.ipynb index d78715cf..19b5eab1 100755 --- a/Fundamental_of_Electronics_Devices/Ch3.ipynb +++ b/Fundamental_of_Electronics_Devices/Ch3.ipynb @@ -1,298 +1,341 @@ -{
- "metadata": {
- "name": ""
- },
- "nbformat": 3,
- "nbformat_minor": 0,
- "worksheets": [
- {
- "cells": [
- {
- "cell_type": "heading",
- "level": 1,
- "metadata": {},
- "source": [
- "Chapter3 : Excess Carriers in Semiconductor"
- ]
- },
- {
- "cell_type": "heading",
- "level": 3,
- "metadata": {},
- "source": [
- "Example 3.2 Page No 111"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "\n",
- "l=6000 #in Angstrum\n",
- "h=6.6*10**(-34) #Planks constant\n",
- "c=3*10**8 #speed of light in m/s\n",
- "e=1.602*10**(-19) #Constant\n",
- "\n",
- "phi=c*h/(e*l*10**(-10))\n",
- "\n",
- "print\"Minimum required energy is\",round(phi,2),\"eV \"\n"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "Minimum required energy is 2.06 eV \n"
- ]
- }
- ],
- "prompt_number": 3
- },
- {
- "cell_type": "heading",
- "level": 3,
- "metadata": {},
- "source": [
- "Example 3.3 Page No 112"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "\n",
- "Emax=2.5 #maximum energy of emitted electrons in eV \n",
- "l=2537.0 #in Angstrum\n",
- "\n",
- "EeV=12400.0/l #in eV\n",
- "phi=EeV-Emax #in eV\n",
- "\n",
- "print \"Work function of the cathode material is \",round(phi,2),\"eV\""
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "Work function of the cathode material is 2.39 eV\n"
- ]
- }
- ],
- "prompt_number": 6
- },
- {
- "cell_type": "heading",
- "level": 3,
- "metadata": {},
- "source": [
- "Example 3.4 Page No 115"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "\n",
- "t=0.46*10**-4 #in centi meters\n",
- "hf1=2 #in ev\n",
- "hf2=1.43\n",
- "Pin=10 #in mW\n",
- "alpha=50000 # in per cm\n",
- "e=1.6*10**-19 #constant\n",
- "Io=0.01 #in mW\n",
- "\n",
- "import math\n",
- "\n",
- "It=Io*math.exp(-alpha*t) #in mW\n",
- "Iabs=Io-It\n",
- "f=(hf1-hf2)/hf1\n",
- "E=f*Iabs\n",
- "N=Iabs/(e*hf1)\n",
- "\n",
- "print\"(i)Thus power absorbed is \",round(Iabs,3),\"J/s\"\n",
- "print\"(ii)Energy converted into heat is\",round(E,4),\"J/s\"\n",
- "print\"(iii)Number of photons per second given off from recombination events \",round(N,-14)\n",
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "(i)Thus power absorbed is 0.009 J/s\n",
- "(ii)Energy converted into heat is 0.0026 J/s\n",
- "(iii)Number of photons per second given off from recombination events 2.81e+16\n"
- ]
- }
- ],
- "prompt_number": 1
- },
- {
- "cell_type": "heading",
- "level": 3,
- "metadata": {},
- "source": [
- "Example 3.5 Page No 123"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "\n",
- "L=100 #in uM\n",
- "A=10&-7 #in cm**2\n",
- "th=10**-6 #in sec\n",
- "V=12 #in Volts\n",
- "ue=0.13 #in m**2/V-s\n",
- "uh=0.05 #in m**2/V-s\n",
- "\n",
- "E=V/(L*10**-6) #in V/m\n",
- "tn=(L*10**-6)/(ue*E)\n",
- "Gain=(1+uh/ue)*(th/tn)\n",
- "\n",
- "print\"Electron transit time in sec is \",round(tn,10),\"s\"\n",
- "print\"Photoconductor gain is \",Gain"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "Electron transit time in sec is 6.4e-09 s\n",
- "Photoconductor gain is 216.0\n"
- ]
- }
- ],
- "prompt_number": 29
- },
- {
- "cell_type": "heading",
- "level": 3,
- "metadata": {},
- "source": [
- "Example 3.6 Page No128"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "\n",
- "import math\n",
- "Io=0.15 #in uA\n",
- "V=0.12 #in mVolt\n",
- "Vt=26 #in mVolt\n",
- "\n",
- "I=Io*10**-6*(math.exp(V/(Vt*10**-3))-1) #in A\n",
- "\n",
- "print\"Current flowing through diode is \",round(I*10**6,2),\"micra A\""
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "Current flowing through diode is 15.0 micra A\n"
- ]
- }
- ],
- "prompt_number": 30
- },
- {
- "cell_type": "heading",
- "level": 3,
- "metadata": {},
- "source": [
- "Example 3.7 Page No 128"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "\n",
- "import math\n",
- "Io=2.5 #in uA\n",
- "I=10 #in mA\n",
- "Vt=26 #in mVolt\n",
- "n=2 #for silicon\n",
- "\n",
- "V=n*Vt*10**-3*math.log((I*10**-3)/(Io*10**-6))\n",
- "\n",
- "print \"Forward voltage is \",round(V,2),\"V\""
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "Forward voltage is 0.43 V\n"
- ]
- }
- ],
- "prompt_number": 31
- },
- {
- "cell_type": "heading",
- "level": 3,
- "metadata": {},
- "source": [
- "Example 3.8 Page No 128"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "\n",
- "ND=10**21 #in m**-3\n",
- "NA=10**22 #in m**-3\n",
- "De=3.4*10**-3 #in m**2-s**-1\n",
- "Dh=1.2*10**-3 #in m**2-s**-1\n",
- "Le=7.1*10**-4 #in meters\n",
- "Lh=3.5*10**-4 #in meters\n",
- "ni=1.6*10**16 #in m**-3\n",
- "e=1.602*10**-19 #constant\n",
- "\n",
- "IoA=e*ni**2*(Dh/(Lh*ND)+De/(Le*NA))\n",
- "\n",
- "print\"Reverse saturation current density is \",round(IoA*10**6,2),\"uA \""
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "Reverse saturation current density is 0.16 uA \n"
- ]
- }
- ],
- "prompt_number": 33
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [],
- "language": "python",
- "metadata": {},
- "outputs": []
- }
- ],
- "metadata": {}
- }
- ]
-}
\ No newline at end of file +{ + "cells": [ + { + "cell_type": "markdown", + "metadata": {}, + "source": [ + "# Chapter3 : Excess Carriers in Semiconductor" + ] + }, + { + "cell_type": "markdown", + "metadata": {}, + "source": [ + "### Example 3.2 Page No 111" + ] + }, + { + "cell_type": "code", + "execution_count": 3, + "metadata": { + "collapsed": false + }, + "outputs": [ + { + "name": "stdout", + "output_type": "stream", + "text": [ + "Minimum required energy is 2.06 eV \n" + ] + } + ], + "source": [ + "#Example 3.2\n", + "#What is Minimum required energy \n", + "\n", + "#given data\n", + "l=6000 #in Angstrum\n", + "h=6.6*10**(-34) #Planks constant\n", + "c=3*10**8 #speed of light in m/s\n", + "e=1.602*10**(-19) #Constant\n", + "\n", + "#calculation\n", + "phi=c*h/(e*l*10**(-10))\n", + "\n", + "#result\n", + "print\"Minimum required energy is\",round(phi,2),\"eV \"\n" + ] + }, + { + "cell_type": "markdown", + "metadata": {}, + "source": [ + "### Example 3.3 Page No 112" + ] + }, + { + "cell_type": "code", + "execution_count": 6, + "metadata": { + "collapsed": false + }, + "outputs": [ + { + "name": "stdout", + "output_type": "stream", + "text": [ + "Work function of the cathode material is 2.39 eV\n" + ] + } + ], + "source": [ + "#Exa 3.3\n", + "#calculate Work function of the cathode material\n", + "\n", + "#given data\n", + "Emax=2.5 #maximum energy of emitted electrons in eV \n", + "l=2537.0 #in Angstrum\n", + "\n", + "#Calculation\n", + "EeV=12400.0/l #in eV\n", + "phi=EeV-Emax #in eV\n", + "\n", + "#result\n", + "print \"Work function of the cathode material is \",round(phi,2),\"eV\"" + ] + }, + { + "cell_type": "markdown", + "metadata": {}, + "source": [ + "### Example 3.4 Page No 115" + ] + }, + { + "cell_type": "code", + "execution_count": 1, + "metadata": { + "collapsed": false + }, + "outputs": [ + { + "name": "stdout", + "output_type": "stream", + "text": [ + "(i)Thus power absorbed is 0.009 J/s\n", + "(ii)Energy converted into heat is 0.0026 J/s\n", + "(iii)Number of photons per second given off from recombination events 2.81e+16\n" + ] + } + ], + "source": [ + "#Example 3.4\n", + "#Find (i)The fraction of each photon energy unit which is converted into heat\",f\n", + "#(ii)Energy converted into heat in ,((2-1.43)/2)*0.009,\"J/s\"\n", + "#(iii)Number of photons per second given off from recombination events \",0.009/(e*2)\n", + "\n", + "#given data\n", + "t=0.46*10**-4 #in centi meters\n", + "hf1=2 #in ev\n", + "hf2=1.43\n", + "Pin=10 #in mW\n", + "alpha=50000 # in per cm\n", + "e=1.6*10**-19 #constant\n", + "Io=0.01 #in mW\n", + "\n", + "import math\n", + "\n", + "#Calculation\n", + "It=Io*math.exp(-alpha*t) #in mW\n", + "Iabs=Io-It\n", + "f=(hf1-hf2)/hf1\n", + "E=f*Iabs\n", + "N=Iabs/(e*hf1)\n", + "\n", + "#result\n", + "print\"(i)Thus power absorbed is \",round(Iabs,3),\"J/s\"\n", + "print\"(ii)Energy converted into heat is\",round(E,4),\"J/s\"\n", + "print\"(iii)Number of photons per second given off from recombination events \",round(N,-14)\n", + "#In book there is calculation mistake in Number of photons." + ] + }, + { + "cell_type": "markdown", + "metadata": {}, + "source": [ + "### Example 3.5 Page No 123" + ] + }, + { + "cell_type": "code", + "execution_count": 29, + "metadata": { + "collapsed": false + }, + "outputs": [ + { + "name": "stdout", + "output_type": "stream", + "text": [ + "Electron transit time in sec is 6.4e-09 s\n", + "Photoconductor gain is 216.0\n" + ] + } + ], + "source": [ + "#Example 3.5\n", + "#What is Photoconductor gain \n", + "#Electron transit time.\n", + "\n", + "#given data\n", + "L=100 #in uM\n", + "A=10&-7 #in cm**2\n", + "th=10**-6 #in sec\n", + "V=12 #in Volts\n", + "ue=0.13 #in m**2/V-s\n", + "uh=0.05 #in m**2/V-s\n", + "\n", + "#Calculation\n", + "E=V/(L*10**-6) #in V/m\n", + "tn=(L*10**-6)/(ue*E)\n", + "Gain=(1+uh/ue)*(th/tn)\n", + "\n", + "#result\n", + "print\"Electron transit time in sec is \",round(tn,10),\"s\"\n", + "print\"Photoconductor gain is \",Gain" + ] + }, + { + "cell_type": "markdown", + "metadata": {}, + "source": [ + "### Example 3.6 Page No128" + ] + }, + { + "cell_type": "code", + "execution_count": 30, + "metadata": { + "collapsed": false + }, + "outputs": [ + { + "name": "stdout", + "output_type": "stream", + "text": [ + "Current flowing through diode is 15.0 micra A\n" + ] + } + ], + "source": [ + "#Example3.6\n", + "#Calculate Current flowing through diode .\n", + "\n", + "#given datex\n", + "import math\n", + "Io=0.15 #in uA\n", + "V=0.12 #in mVolt\n", + "Vt=26 #in mVolt\n", + "\n", + "#calculation\n", + "I=Io*10**-6*(math.exp(V/(Vt*10**-3))-1) #in A\n", + "\n", + "#result\n", + "print\"Current flowing through diode is \",round(I*10**6,2),\"micra A\"" + ] + }, + { + "cell_type": "markdown", + "metadata": {}, + "source": [ + "### Example 3.7 Page No 128" + ] + }, + { + "cell_type": "code", + "execution_count": 31, + "metadata": { + "collapsed": false + }, + "outputs": [ + { + "name": "stdout", + "output_type": "stream", + "text": [ + "Forward voltage is 0.43 V\n" + ] + } + ], + "source": [ + "#Exa 3.7\n", + "#Determine the Forward voltage \n", + "\n", + "#given data\n", + "import math\n", + "Io=2.5 #in uA\n", + "I=10 #in mA\n", + "Vt=26 #in mVolt\n", + "n=2 #for silicon\n", + "\n", + "#Calculation\n", + "V=n*Vt*10**-3*math.log((I*10**-3)/(Io*10**-6))\n", + "\n", + "#Result\n", + "print \"Forward voltage is \",round(V,2),\"V\"" + ] + }, + { + "cell_type": "markdown", + "metadata": {}, + "source": [ + "### Example 3.8 Page No 128" + ] + }, + { + "cell_type": "code", + "execution_count": 33, + "metadata": { + "collapsed": false + }, + "outputs": [ + { + "name": "stdout", + "output_type": "stream", + "text": [ + "Reverse saturation current density is 0.16 uA \n" + ] + } + ], + "source": [ + "#Example 3.8\n", + "#What is Reverse saturation current density \n", + "\n", + "#given data\n", + "ND=10**21 #in m**-3\n", + "NA=10**22 #in m**-3\n", + "De=3.4*10**-3 #in m**2-s**-1\n", + "Dh=1.2*10**-3 #in m**2-s**-1\n", + "Le=7.1*10**-4 #in meters\n", + "Lh=3.5*10**-4 #in meters\n", + "ni=1.6*10**16 #in m**-3\n", + "e=1.602*10**-19 #constant\n", + "\n", + "#calculation\n", + "IoA=e*ni**2*(Dh/(Lh*ND)+De/(Le*NA))\n", + "\n", + "#Result\n", + "print\"Reverse saturation current density is \",round(IoA*10**6,2),\"uA \"" + ] + }, + { + "cell_type": "code", + "execution_count": null, + "metadata": { + "collapsed": false + }, + "outputs": [], + "source": [] + } + ], + "metadata": { + "kernelspec": { + "display_name": "Python 2", + "language": "python", + "name": "python2" + }, + "language_info": { + "codemirror_mode": { + "name": "ipython", + "version": 2 + }, + "file_extension": ".py", + "mimetype": "text/x-python", + "name": "python", + "nbconvert_exporter": "python", + "pygments_lexer": "ipython2", + "version": "2.7.3" + } + }, + "nbformat": 4, + "nbformat_minor": 0 +} |