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+{
+ "cells": [
+ {
+ "cell_type": "markdown",
+ "metadata": {},
+ "source": [
+ "# Chapter 8 :Hydraulic Valves"
+ ]
+ },
+ {
+ "cell_type": "markdown",
+ "metadata": {},
+ "source": [
+ "## Example 8.1 pgno:293"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "execution_count": 1,
+ "metadata": {
+ "collapsed": false
+ },
+ "outputs": [
+ {
+ "name": "stdout",
+ "output_type": "stream",
+ "text": [
+ "\n",
+ " Results: \n",
+ "\n",
+ " The Cracking pressure is psi. 667.0\n",
+ "\n",
+ " The Full pump flow pressure is psi. 1000.0\n"
+ ]
+ }
+ ],
+ "source": [
+ "# Aim:Refer Example 8-1 for Problem Description \n",
+ "# Given:\n",
+ "# area of relief valve:\n",
+ "A=0.75; #in**2\n",
+ "# spring constant:\n",
+ "k=2500.0; #lb/in\n",
+ "# initial compressed length of spring:\n",
+ "S=0.20; #in\n",
+ "# poppet displacement to pass full pump flow:\n",
+ "L=0.10; #in\n",
+ "\n",
+ "\n",
+ "\n",
+ "\n",
+ "\n",
+ "\n",
+ "# Solution:\n",
+ "# spring force excerted on poppet when it is fully closed,\n",
+ "F=k*S; #lb\n",
+ "# Cracking pressure,\n",
+ "p_crack=F/A; #psi\n",
+ "# spring force when poppet moves 0.10 in from its fully closed position,\n",
+ "F_new=k*(L+S); #lb\n",
+ "# Full pump flow pressure,\n",
+ "p_ful_pump_flow=F_new/A; #psi\n",
+ " \n",
+ "# Results:\n",
+ "print\"\\n Results: \" \n",
+ "print\"\\n The Cracking pressure is psi.\",round(p_crack)\n",
+ "print\"\\n The Full pump flow pressure is psi.\",p_ful_pump_flow\n",
+ "\n",
+ "\n",
+ "\n",
+ "\n"
+ ]
+ },
+ {
+ "cell_type": "markdown",
+ "metadata": {},
+ "source": [
+ "## Example 8.2 pgno:299"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "execution_count": 2,
+ "metadata": {
+ "collapsed": false
+ },
+ "outputs": [
+ {
+ "name": "stdout",
+ "output_type": "stream",
+ "text": [
+ "\n",
+ " Results: \n",
+ "\n",
+ " The Horsepower across the pressure relief valve is HP. 11.7\n"
+ ]
+ }
+ ],
+ "source": [
+ "# Aim:To compute horsepower across the pressure relief valve\n",
+ "# Given:\n",
+ "# pressure relief valve setting:\n",
+ "p=1000.0; #psi\n",
+ "# pump flow to the tank:\n",
+ "Q=20.0; #gpm\n",
+ "\n",
+ "\n",
+ "\n",
+ "# Solution:\n",
+ "# Horsepower across the valve,\n",
+ "HP=((p*Q)/1714); #HP\n",
+ " \n",
+ "# Results:\n",
+ "print\"\\n Results: \" \n",
+ "print\"\\n The Horsepower across the pressure relief valve is HP.\",round(HP,1)\n",
+ "\n"
+ ]
+ },
+ {
+ "cell_type": "markdown",
+ "metadata": {},
+ "source": [
+ "## Example 8.3 pgno:299"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "execution_count": 3,
+ "metadata": {
+ "collapsed": false
+ },
+ "outputs": [
+ {
+ "name": "stdout",
+ "output_type": "stream",
+ "text": [
+ "\n",
+ " Results: \n",
+ "\n",
+ " The Horsepower across the unloading valve is HP. 0.29\n"
+ ]
+ }
+ ],
+ "source": [
+ "# Aim:To compute horsepower across the unloading valve\n",
+ "# Given:\n",
+ "# pump pressure during unloading:\n",
+ "p=25.0; #psi\n",
+ "# pump flow to the tank:\n",
+ "Q=20.0; #gpm\n",
+ "\n",
+ "\n",
+ "\n",
+ "\n",
+ "# Solution:\n",
+ "# Horsepower across the valve,\n",
+ "HP=((p*Q)/1714); #HP\n",
+ " \n",
+ "# Results:\n",
+ "print\"\\n Results: \" \n",
+ "print\"\\n The Horsepower across the unloading valve is HP.\",round(HP,2)\n",
+ "\n",
+ "\n"
+ ]
+ },
+ {
+ "cell_type": "markdown",
+ "metadata": {},
+ "source": [
+ "## Example 8.4 pgno:302"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "execution_count": 4,
+ "metadata": {
+ "collapsed": false
+ },
+ "outputs": [
+ {
+ "name": "stdout",
+ "output_type": "stream",
+ "text": [
+ "\n",
+ " Results: \n",
+ "\n",
+ " The flow-rate through orifice is gpm. 252.0\n"
+ ]
+ }
+ ],
+ "source": [
+ "# Aim:To find flow-rate through given orifice\n",
+ "# Given:\n",
+ "# pressure drop across orifice:\n",
+ "del_p=100.0; #psi\n",
+ "# orifice diameter:\n",
+ "D=1.0; #in\n",
+ "# specific gravity of oil:\n",
+ "SG_oil=0.9;\n",
+ "# flow coefficient for sharp edge orifice:\n",
+ "C=0.80;\n",
+ "import math \n",
+ "from math import pi\n",
+ "\n",
+ "# Solution:\n",
+ "# flow-rate through orifice,\n",
+ "Q=38.1*C*((pi*(D**2))/4)*(del_p/SG_oil)**0.5; #gpm\n",
+ "\n",
+ "# Results:\n",
+ "print\"\\n Results: \" \n",
+ "print\"\\n The flow-rate through orifice is gpm.\",round(Q)\n"
+ ]
+ },
+ {
+ "cell_type": "markdown",
+ "metadata": {},
+ "source": [
+ "## Example 8.5 pgno:304"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "execution_count": 5,
+ "metadata": {
+ "collapsed": false
+ },
+ "outputs": [
+ {
+ "name": "stdout",
+ "output_type": "stream",
+ "text": [
+ "\n",
+ " Results: \n",
+ "\n",
+ " The capacity coefficient in English unit is gpm/sqrt(psi). 2.37\n",
+ "\n",
+ " The capacity coefficient in Metric unit is Lpm/sqrt(kPa). 3.43\n"
+ ]
+ }
+ ],
+ "source": [
+ "# Aim:To determine the capacity coefficient of flow control valve \n",
+ "# Given:\n",
+ "# pressure drop across flow control valve:\n",
+ "del_p=100.0; #psi\n",
+ "del_p1=687.0; #kPa\n",
+ "# flow-rate across valve:\n",
+ "Q=25.0; #gpm\n",
+ "Q1=94.8; #Lpm\n",
+ "# specific gravity of oil:\n",
+ "SG_oil=0.9; \n",
+ "\n",
+ "\n",
+ "\n",
+ "\n",
+ "\n",
+ "# Solution:\n",
+ "# capacity coefficient in English Units,\n",
+ "Cv=Q/((del_p/SG_oil)**0.5); #gpm/sqrt(psi)\n",
+ "# capacity coefficient in Metric Units,\n",
+ "Cv1=Q1/((del_p1/SG_oil)**0.5); #Lpm/sqrt(kPA)\n",
+ "\n",
+ "# Results:\n",
+ "print\"\\n Results: \" \n",
+ "print\"\\n The capacity coefficient in English unit is gpm/sqrt(psi).\",round(Cv,2)\n",
+ "print\"\\n The capacity coefficient in Metric unit is Lpm/sqrt(kPa).\",round(Cv1,2)\n",
+ "\n",
+ "\n",
+ "\n"
+ ]
+ },
+ {
+ "cell_type": "markdown",
+ "metadata": {},
+ "source": [
+ "## Example 8.6 pgno:304"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "execution_count": 6,
+ "metadata": {
+ "collapsed": false
+ },
+ "outputs": [
+ {
+ "name": "stdout",
+ "output_type": "stream",
+ "text": [
+ "\n",
+ " Results: \n",
+ "\n",
+ " The capacity coefficient of needle valve is gpm/sqrt(psi). 0.37\n"
+ ]
+ }
+ ],
+ "source": [
+ "# Aim:To determine the capacity coefficient of needle valve \n",
+ "# Given:\n",
+ "# Desired cylinder speed:\n",
+ "v2=10.0; #in/s\n",
+ "# Cylinder piston area:\n",
+ "A1=3.14; #in^2\n",
+ "# Cylinder rod area:\n",
+ "Ar=0.79; #in^2\n",
+ "# Cylinder load:\n",
+ "F_load=1000.0; #lb\n",
+ "# Specific gravity of oil:\n",
+ "SG_oil=0.9;\n",
+ "# Pressure relief valve setting:\n",
+ "p1=500.0; #psi\n",
+ "\n",
+ "\n",
+ "\n",
+ "\n",
+ "\n",
+ "# Solution:\n",
+ "# annular area of cylinder,\n",
+ "A2=A1-Ar; #in^2\n",
+ "# back pressure in the rod end,\n",
+ "p2=((p1*A1)-F_load)/A2; #psi\n",
+ "# flow rate through needle valve based on desired cylinder speed,\n",
+ "Q=(A2*v2*60)/231; #gpm\n",
+ "# capacity coefficient of needle valve,\n",
+ "Cv=Q/((p2/SG_oil)**0.5); #gpm/sqrt(psi)\n",
+ "\n",
+ "# Results:\n",
+ "print\"\\n Results: \"\n",
+ "print\"\\n The capacity coefficient of needle valve is gpm/sqrt(psi).\",round(Cv,2)\n",
+ "\n"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "execution_count": null,
+ "metadata": {
+ "collapsed": true
+ },
+ "outputs": [],
+ "source": []
+ }
+ ],
+ "metadata": {
+ "kernelspec": {
+ "display_name": "Python 2",
+ "language": "python",
+ "name": "python2"
+ },
+ "language_info": {
+ "codemirror_mode": {
+ "name": "ipython",
+ "version": 2
+ },
+ "file_extension": ".py",
+ "mimetype": "text/x-python",
+ "name": "python",
+ "nbconvert_exporter": "python",
+ "pygments_lexer": "ipython2",
+ "version": "2.7.9"
+ }
+ },
+ "nbformat": 4,
+ "nbformat_minor": 0
+}