diff options
author | kinitrupti | 2017-05-12 18:53:46 +0530 |
---|---|---|
committer | kinitrupti | 2017-05-12 18:53:46 +0530 |
commit | 6279fa19ac6e2a4087df2e6fe985430ecc2c2d5d (patch) | |
tree | 22789c9dbe468dae6697dcd12d8e97de4bcf94a2 /Fluid_Mechanics_by_John_F._Douglas/Chapter_14.ipynb | |
parent | d36fc3b8f88cc3108ffff6151e376b619b9abb01 (diff) | |
download | Python-Textbook-Companions-6279fa19ac6e2a4087df2e6fe985430ecc2c2d5d.tar.gz Python-Textbook-Companions-6279fa19ac6e2a4087df2e6fe985430ecc2c2d5d.tar.bz2 Python-Textbook-Companions-6279fa19ac6e2a4087df2e6fe985430ecc2c2d5d.zip |
Removed duplicates
Diffstat (limited to 'Fluid_Mechanics_by_John_F._Douglas/Chapter_14.ipynb')
-rwxr-xr-x | Fluid_Mechanics_by_John_F._Douglas/Chapter_14.ipynb | 365 |
1 files changed, 365 insertions, 0 deletions
diff --git a/Fluid_Mechanics_by_John_F._Douglas/Chapter_14.ipynb b/Fluid_Mechanics_by_John_F._Douglas/Chapter_14.ipynb new file mode 100755 index 00000000..2e55c7c8 --- /dev/null +++ b/Fluid_Mechanics_by_John_F._Douglas/Chapter_14.ipynb @@ -0,0 +1,365 @@ +{ + "metadata": { + "name": "", + "signature": "sha256:75785fe7e68940de5df81a115443b8d5c78793053ae837735e58f86a072c05cc" + }, + "nbformat": 3, + "nbformat_minor": 0, + "worksheets": [ + { + "cells": [ + { + "cell_type": "heading", + "level": 1, + "metadata": {}, + "source": [ + "Chapter 14: Steady Incompressible Flow in Pipe and Duct System" + ] + }, + { + "cell_type": "heading", + "level": 2, + "metadata": {}, + "source": [ + "Example 14.1, Page 468" + ] + }, + { + "cell_type": "code", + "collapsed": false, + "input": [ + "from __future__ import division\n", + "import math\n", + "\n", + "\n", + " #Initializing the variables\n", + "L1 = 5;\n", + "L2 = 10;\n", + "d = 0.1;\n", + "f = 0.08;\n", + "Za_Zc = 4; #difference in height between A and C \n", + "g = 9.81 ;\n", + "Pa = 0;\n", + "Va = 0; \n", + "Za_Zb = -1.5;\n", + "V = 1.26;\n", + "rho = 1000;\n", + "\n", + " #Calculations\n", + "D = 1.5 + 4*f*(L1+L2)/d ; # Denominator in case of v**2 \n", + "v = (2*g*Za_Zc/D)**0.5;\n", + "Pb = rho*g*Za_Zb - rho*V**2/2*(1.5+4*f*L1/d);\n", + "print \"Pressure in the pipe at B (kN/m2):\",round(Pb/1000,2)\n", + "print \"Mean Velocity at C (m/s) :\",round(v,2)\n", + "\n" + ], + "language": "python", + "metadata": {}, + "outputs": [ + { + "output_type": "stream", + "stream": "stdout", + "text": [ + "Pressure in the pipe at B (kN/m2): -28.61\n", + "Mean Velocity at C (m/s) : 1.26\n" + ] + } + ], + "prompt_number": 1 + }, + { + "cell_type": "heading", + "level": 2, + "metadata": {}, + "source": [ + "Example 14.3, Page 473" + ] + }, + { + "cell_type": "code", + "collapsed": false, + "input": [ + "from __future__ import division\n", + "import math\n", + "from sympy import symbols,solve\n", + "import sympy\n", + "\n", + "\n", + " #Initializing the variables\n", + "Za_Zb = 10;\n", + "f = 0.008;\n", + "L = 100;\n", + "d1 = 0.05;\n", + "g = 9.81;\n", + "d2 = 0.1;\n", + "\n", + " #Calculations\n", + "\n", + "def flowRate(d):\n", + " D = 1.5 + 4*f*L/d ; # Denominator in case of v1**2\n", + " A = math.pi*d**2/4;\n", + " v = (2*g*Za_Zb/D)**0.5;\n", + " z = A*v;\n", + " return z \n", + "Q1 = flowRate(d1);\n", + "Q2 = flowRate(d2);\n", + "Q=round(Q1+Q2,4)\n", + "\n", + "\n", + "D=symbols('D')\n", + "roots=solve(241212*D**5 -3.2, D)\n", + "dia=roots[0]\n", + "\n", + "print \"Rate flow for pipe 1 (m^3/s) :\",round(Q1,4)\n", + "print \"Rate flow for pipe 2 (m^3/s) :\",round(Q2,4)\n", + "print \"Combined Rate flow (m^3/s) :\",round(Q,4)\n", + "print \"Diameter of single equivalent pipe (mm) :\",round(dia,3)*1000\n" + ], + "language": "python", + "metadata": {}, + "outputs": [ + { + "output_type": "stream", + "stream": "stdout", + "text": [ + "Rate flow for pipe 1 (m^3/s) : 0.0034\n", + "Rate flow for pipe 2 (m^3/s) : 0.019\n", + "Combined Rate flow (m^3/s) : 0.0224\n", + "Diameter of single equivalent pipe (mm) : 106.0\n" + ] + } + ], + "prompt_number": 1 + }, + { + "cell_type": "heading", + "level": 2, + "metadata": {}, + "source": [ + "Example 14.4, Page 476" + ] + }, + { + "cell_type": "code", + "collapsed": false, + "input": [ + "from __future__ import division\n", + "import math\n", + "import sympy\n", + "from sympy import solve,symbols\n", + "\n", + " #Initializing the variables\n", + "Za_Zb = 16;\n", + "Za_Zc = 24;\n", + "f = 0.01;\n", + "l1 = 120;\n", + "l2 = 60;\n", + "l3 = 40;\n", + "d1 = 0.12;\n", + "d2 = 0.075;\n", + "d3 = 0.060;\n", + "g = 9.81;\n", + " #Calculations\n", + "\n", + "v1=symbols('v1')\n", + "ash=solve(v1-0.3906*(g-1.25*v1**2)**0.5-0.25*(17.657-1.5*v1**2)**0.5,v1)\n", + "v1=round(abs(ash[0]),2)\n", + "Q1=math.pi/4*d1**2*v1\n", + "\n", + "v2=(g-1.25*v1**2)**0.5\n", + "Q2=math.pi/4*d2**2*v2\n", + "\n", + "v3=(17.657-1.5*v1**2)**0.5\n", + "Q3=math.pi/4*d3**2*v3\n", + "\n", + "print \"Flow rate in pipe 1 (m^3/s):\",round(Q1,4)\n", + "print \"Flow rate in pipe 2 (m^3/s):\",round(Q2,4)\n", + "print \"Flow rate in pipe 3 (m^3/s):\",round(Q3,4)\n", + "print \"continuity condition satisfied as Q1=Q2+Q3\"" + ], + "language": "python", + "metadata": {}, + "outputs": [ + { + "output_type": "stream", + "stream": "stdout", + "text": [ + "Flow rate in pipe 1 (m^3/s): 0.0206\n", + "Flow rate in pipe 2 (m^3/s): 0.0105\n", + "Flow rate in pipe 3 (m^3/s): 0.0101\n", + "continuity condition satisfied as Q1=Q2+Q3\n" + ] + } + ], + "prompt_number": 2 + }, + { + "cell_type": "heading", + "level": 2, + "metadata": {}, + "source": [ + "Example 14.5, Page 480" + ] + }, + { + "cell_type": "code", + "collapsed": false, + "input": [ + "from __future__ import division\n", + "import math\n", + "\n", + "\n", + " #Initializing the variables\n", + "D = 0.3;\n", + "Q = 0.8;\n", + "rho = 1.2;\n", + "f = 0.008;\n", + "L_entry = 10;\n", + "L_exit = 30;\n", + "Lt = 20*D #Transition may be represented by a separation loss equivalent length of 20 * the approach duct diameter\n", + "K_entry = 4;\n", + "K_exit = 10\n", + "l = 0.4; # length of cross section\n", + "b = 0.2; # width of cross section\n", + "\n", + " #Calculations\n", + "A = math.pi*D**2/4;\n", + "Dp1 = 0.5*rho*Q**2/A**2*(K_entry + 4*f*(L_entry+Lt)/D);\n", + "area = l*b;\n", + "perimeter =2*(l+b);\n", + "m = area/perimeter;\n", + "Dp2 = 0.5*rho*Q**2/area**2*(K_exit + f*L_exit/m);\n", + "Dfan = Dp1+Dp2;\n", + "\n", + "print \"fan Pressure input (N/m2) :\",round(Dfan,1)" + ], + "language": "python", + "metadata": {}, + "outputs": [ + { + "output_type": "stream", + "stream": "stdout", + "text": [ + "fan Pressure input (N/m2) : 1254.6\n" + ] + } + ], + "prompt_number": 6 + }, + { + "cell_type": "heading", + "level": 2, + "metadata": {}, + "source": [ + "Example 14.6, Page 482" + ] + }, + { + "cell_type": "code", + "collapsed": false, + "input": [ + "from __future__ import division\n", + "import math\n", + "\n", + "\n", + " #Initializing the variables\n", + "D = [0.15 , 0.3];\n", + "rho = 1.2;\n", + "f = 0.008;\n", + "L_entry = 10;\n", + "L_exit = 20;\n", + "Lt = 20*D[1] \n", + "K = 4;\n", + "Q1 = 0.2;\n", + "\n", + " #Calculations\n", + "Q2 = 4*Q1;\n", + "A=[0.0,0.0]\n", + "A[0] = math.pi*D[0]**2/4;\n", + "A[1] = math.pi*D[1]**2/4;\n", + "Dp1 = 0.5*rho*Q1**2/A[0]**2*(K + 4*f*L_entry/D[0]);\n", + "Dp2 = 0.5*rho*Q2**2/A[1]**2*(4*f*(L_exit + Lt)/D[1]);\n", + "Dfan = Dp1+Dp2;\n", + "\n", + "print \"fan Pressure input (N/m2) :\",round(Dfan,2)" + ], + "language": "python", + "metadata": {}, + "outputs": [ + { + "output_type": "stream", + "stream": "stdout", + "text": [ + "fan Pressure input (N/m2) : 684.51\n" + ] + } + ], + "prompt_number": 7 + }, + { + "cell_type": "heading", + "level": 2, + "metadata": {}, + "source": [ + "Example 14.7, Page 487" + ] + }, + { + "cell_type": "code", + "collapsed": false, + "input": [ + "from __future__ import division\n", + "import math\n", + "from scipy.optimize import fsolve\n", + " \n", + " \n", + " \n", + " #Initializing the variables\n", + "d = [0.1 , 0.125, 0.15, 0.1, 0.1 ]; # Corrosponding to AA1B AA2B BC CD CF\n", + "l = [30 , 30 , 60, 15, 30]; # Corrosponding to AA1B AA2B BC CD CF\n", + "rho = 1.2;\n", + "f = 0.006;\n", + "Ha = 100;\n", + "Hf = 60;\n", + "He = 40;\n", + "K = [0.0, 0.0, 0.0, 0.0, 0.0]\n", + " #Calculations\n", + "for i in range(0,len(l)):\n", + " K[i] = f*l[i]/(3*d[i]**5);\n", + "\n", + "\n", + "K_ab = K[0]*K[1]/((K[0])**0.5+(K[1])**0.5)**2;\n", + "K_ac = K_ab + K[2];\n", + "Hc = (K_ac*Hf +K[4]*Ha/4)/(K_ac+K[4]/4);\n", + "Q = ((Ha - Hc)/K_ac)**0.5;\n", + "\n", + "def f(n):\n", + " z = He - Hc + (0.5*Q)**2 *(K[3]+(4000/n)**2);\n", + " return z\n", + "\n", + "n = fsolve(f,1);\n", + "\n", + "print \"total Volume flow rate (m3/s):\",round(Q, 4)\n", + "print \"Head at C (m) :\",round(Hc,2) \n", + "print \"Percentage valve opening (%) :\",round(n,2)" + ], + "language": "python", + "metadata": {}, + "outputs": [ + { + "output_type": "stream", + "stream": "stdout", + "text": [ + "total Volume flow rate (m3/s): 0.1016\n", + "Head at C (m) : 75.48\n", + "Percentage valve opening (%) : 38.58\n" + ] + } + ], + "prompt_number": 8 + } + ], + "metadata": {} + } + ] +}
\ No newline at end of file |